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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 24201. |
The reaction H_(2)(g) + AgCl(s) rarr H^(+) (aq) + Cl^(-)(aq)+Ag(s)can be represented b y the galvanic cell representation as: |
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Answer» `Agabs(AgCl(s))KCl("soln")abs(AgNO_(3)("soln"))Ag(s)` |
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| 24202. |
The reaction H_(2) C= CH_(2) +H_(2) underset(523-573K) overset(Ni) to CH_(3) -CH_(3)is called : |
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Answer» Wutrz'sreaction |
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| 24203. |
The reaction given, RNH_2+S=C=S overset(HgCl_2)underset(-H_2S)rarrunderset(Alkylisothiocynate)R-N=C=S constitutes: |
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Answer» MUSTARD OIL reaction |
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| 24204. |
The reaction given below is observed to be first order with rate constant 7.48xx10^(-3) sec^(-1). Calculate the time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm and also find the total pressure after 100sec. 2A(g)+4B(g)+C(g) |
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Answer» Solution :`{:(,,2A_((g)),,to,,4B_((g)),,+,,C_((g))),("Initial",,P_(0),,,,0,,,,0),("At time t",,P_(0)-P.,,,,2P.,,,,P.//2):}` `P_("total")=P_(0)-P.+2P.+P.//2=P_(0)+(3P.)/(2)` `P.=(2)/(3)(0.145-0.1)=0.03atm` `K=(2.303)/(t)LOG.(P_(0))/(P_(0)-P.)` `t=(2.303)/(7.48xx10^(-3))log((0.1)/(0.07))=47.7sec` ALSO, `k=(2.303)/(t)log((0.1)/(0.1-P.))` `7.48xx10^(-3)=(2.303)/(100)log((0.1)/(0.1-P.))` `0.1-P.=0.047` `P.=0.053` `P_("total")=0.1+(3)/(2)(0.053)~~0.180atm`. |
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| 24205. |
The reaction given below,C_2H_5ONa+IC_2H_5rarrC_2H_5OC_2H_5 +NaI is : |
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Answer» WURTZ synthesis |
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| 24206. |
Identify A & B in the following reaction. CH_3 COOH overset(SOCl_2)rarr (A) overset(NH_3)rarr (B) |
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Answer» Hoffmann.s bromamide REACTION |
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| 24207. |
The reaction given below is known as C_(2)H_(5)O"N"a+IC_(2)H_(5) to C_(2)H_(5)OC_(2)H_(5) + NaI |
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Answer» KOLBE synthesis |
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| 24208. |
The reaction given below is known as C_6H_5I + 2Na + ICH_3 rarrC_6H_5 -CH_3+2NaI |
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Answer» WURTZ REACTION |
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| 24209. |
The reaction given below is known as C_2H_5ONa + IC_2H_5 to C_2H_5OC_2H_5 + NaI |
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Answer» KOLBE's synthesis |
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| 24210. |
The reaction given below is 2H - CHO overset(OH^(-)) to H - COONa + CH_(3) OH The slowest step is |
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Answer» Wurtz's REACTION |
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| 24211. |
ThereactionF_(2(g))+ 2C1O_(2(g))to 2FC1O_(2(g)) if firstorderin eachof thereactants . Therateof thethereaction is4.88 xx 10^(-4)M//swhen[F_(2)] =0.015 M and [C1O_(2) =0 .025 M Calculatethe rateconstantof the reaction . |
| Answer» SOLUTION :RATECONSTANT = `K =1.3 M^(-1) s^(-1)` | |
| 24213. |
The reaction, C(s)+H_2O(g)toCO(g)+H_2(g) is allowed to occur with 0.1 mol of H_2O(g) at 700^(@)C in a closed vessel of volume 1L at equilibrium. If the partial pressure of H_2O(g) is found to decrease by 5.6 atm, then find the value of K_P for the reaction. What would be the minimum amount of C( s) so that the above equilibrium can establish? |
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Answer» SOLUTION :INITIAL PRESSURE of `H_2O(g)=(nRT)/(V)=(0.1xx0.0821xx973)/1` =7.98 atm Partial pressure`C(s)+H_2O(g) =2.38atm `K_p=(p_(CO)xxp_(H_2))/(p_(H_2O))=(5.6xx5.6)/(2.38)atm=13.18atm` NUMBER of moles of `CO_2` at equilibrium: `=(p_(CO_2)V)/(RT)=(5.6xx1)/(0.0821xx973)=0.7mol` `0.07 mol CO_2-=0.07molC(s)-=0.07xx12g-=0.84g` |
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| 24215. |
The reaction, Cu^(2+)(aq) +2CI^- (aq) rarr Cu(s) +CI_2(g) has E_(cell)^@=1.03V.This reaction : |
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Answer» Can be MADE to produce electricity in voltaic cell |
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| 24216. |
The reaction described, below is (CH_3)_3CBr + KOH rarr(CH_3)_3COH + KBr |
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Answer» `S_E1` |
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| 24217. |
The reaction , C(s)+CO_2(g)hArr2CO(g) is at equilibrium in a closed vessel under a given set of conditions. If the degree of dissociation of CO_2 at equilibrium is alpha and the total pressure of the equilibrium mixture and the value of equilibrium constant are P and K_p respectively, then alpha |
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Answer» <P>`(K_p)/sqrt(2P)` |
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| 24218. |
The reaction, Cr_2O_3 + 2Al to Al_2O_3 + 2Cr , (Delta_rG^(0) = - 421 kJ) is thermodynamically feasible as is apparent from the Gibb's energy value. Why does it not take place at room temperature ? |
| Answer» Solution :The reaction does not takes place at ROOM temperature because of high activation ENERGY through reaction is thermodynamically feasible. Thus, heating is requied to overcome activation energy. | |
| 24219. |
The reaction, C(s)+H_2O(g)hArrCO(g)+H_2(g), /_\H>0, is in equilibrium. At equilibrium- |
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Answer» if temperature is increased, the partial PRESSURE of `H_2O(g)` will DECREASE |
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| 24220. |
The reaction, Cr_(2)O_(3(s)) + 2Al_((s)) rarr Al_(2)O_(3) + 2Cr Delta G^(@) = -421 kJis thermodynamically feasible why does it not take place at room temperature? |
| Answer» Solution :The CHANGE in Gibbs energy is related to the equilibrium constant K as `DeltaG = -RT` Ink. At room temperature allreactants and PRODUCTS of the given REACTION are in solid state. As a result, equilibrium does not take place at room exist between the reactants and the products. Hence the reaction does not take place at room temperature. Certain amount of activation energy is essential even for reactions which are thermodynamically feasible. | |
| 24221. |
The reaction : Cr_(2)O_(3)+2Al to Al_(2)O_(3)+2Cr(triangleG^(0)= -421 kJ). is thermodynamically feasible as is apparent from the gibbs energy value. Why does it not take place at room temperature ? |
| Answer» Solution :In the given redox reaction, all the reactants and the products are solids at room temperature, therefore, there does not exist any equilibrium between the recatants and the products and hence the reaction does not OCCUR at room temperature. The interpretation of `triangleG` is based on `K(triangleG^(0)= -RT LN K)` where K is the equilibrium constant. When there is no equilibrium in the solid stateand the value of K becomes insignificant. However, at high temperature, when chromium melts, the value of `T TRIANGLE S` increases. As a result, the value of `triangle_(r )G^(0)` becomes more `-ve` and hence the reaction proceeds rapidly. | |
| 24222. |
The reaction,[Co(NH_(3))_(5)Br]^(2+)+H_(2)Orarr[Co(NH_(3))_(5)(H_(2)O)]^(3+)+Br^(-) is folllowed by measuring a property of the solution known as the optical density of which may be taken to be linearly related to the concentration of the reactant. The values of optical density are 0.80,0.35 and 0.20 at the end of 20 minutes, 40 minutes and infinite time after the start of the reaction which is first order. Calculate the rate constant. |
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Answer» `6.93xx10^(-3)MIN^(-1)` |
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| 24223. |
Thereaction,Cr_2 O _3 + 2 Al toAl_2O _ 3+2Cr (Delta G ^(@)= -421 kJ )isthethermodynamicallyfeasibleasisapparent from theGibbs energyvalue. Why doesit not take placeat roomtemperature ? |
| Answer» Solution :The interpretationof`Delta G^(@)`isbaseduponon K` (DeltaG^(@) =- RT `LN K ),theequilibriumconstant. Sincein the givenredoxreaction, all THEREACTANTS andtheproductsare solidsat roomtemperature, therefore, theredoesnot existanyequilibriumbetweenthereactantsandthe productsand hencethereactiondoes notoccur at roomtemperature. HOWEVER, athightemperature,whenchromiummelts, thevalueof` T DeltaS `increases. AAA result ,thevalueof` Delta _rG^(@)`becomes more-veandhencethereactionproceeds rapidly. | |
| 24224. |
The reaction conditions used for converting 1,2-dibromopropane to propylene are |
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Answer» KOH, alcohol/`Delta`<BR>KOH,water/`Delta` |
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| 24225. |
The reaction conditions leadint to the best yield of C_(2)H_(5)Cl are |
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Answer» `C_(2)H_(6)("EXCESS")+Cl_(2)overset("UV light")to` |
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| 24226. |
The reaction conditions leading to the best yield of C_(2)H_(5)Cl are : |
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Answer» `C_(2)H_(6)("excess")+Cl_(2)OVERSET("UV light")rarr` |
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| 24227. |
Thereactionconditionsleadingto bestyieldsof C_(2) H_(5)Clare : |
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Answer» `C_(2)H_(6)("EXCESS") +Cl_(2) overset("UV light ")to` |
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| 24228. |
The reaction condition leading to the best yields of C_2H_5Cl are : |
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Answer» `C_2H_6`(EXCESS) + `Cl_2` ` overset(UVLIGHT)RARR` |
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| 24229. |
The reaction condition leading to the best yields of C_2H_5Cl are - |
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Answer» `C_2H_6(excess)+Cl_2underset(LIGHT)OVERSET(UV)rarr` |
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| 24230. |
The reaction conditions leading to the best yield of C_(2)H_(5)Cl are |
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Answer» `C_(2)H_(6)"(excess)"+CL+(2)OVERSET("UV light")rarr` |
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| 24231. |
The reactionCl_2(g) + S_2O_3^(2-) to SO_4^(2-) +Cl^(-)is to be carried out in alkaline solution.Starting with 0.15 mole of Cl_2, 0.01 mole of S_2O_3^(2-)and 0.30 mole of OH^- . How many mole of O^-will be left in the solution after the reaction is complete? Assume that no other reaction takes place. |
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Answer» SOLUTION :`4Cl_2 + S_2O_3^(2-) + 10OH^(-) to 2SO_4^(2-) + 8Cl^(-) + 5H_2O` 0.2mole |
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| 24232. |
The reaction: ClO_(3)^(-) +I_(2) to IO_(3)^(-)+Cl_(2) |
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Answer» is possible Note: The reaction : `I_(2) + 2KCL` is not possible because Cl cannot be replaced by more electropositive `I_(2)`. |
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| 24233. |
The reaction Cl_(2(g)) + 2 I_((aq))^(-) to 2 Cl_((aq))^(-) + I_(2(s)) In this anode reaction is - |
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Answer» `Cl_(2) + 2E^(-) to 2 Cl^(-)` At cathode `"" Cl_(2) + 2 e^(-) to 2 Cl^(-)` |
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| 24234. |
The reactioncis-Xcis-Xunderset(k_(b))overset(k_(f))ltimplies trans-X is first order in both direction At 25^(@)C, the equilibrium constant is 0.10 and the rate constant k_(f)=3xx10^(-4)s^(-1) In an experiment starting with the pure cis- from , how long would it take for half of the equilibrium amount of the trans-iomer to be fromed? |
| Answer» Answer :D | |
| 24235. |
The reaction Cis-XhArr trans -X 1st order in both directions .At 25^(@)C , the equlibrium constant is 0.10andthe constant k_(f)=3xx10^(-4)sec^(-1) In an experiment starting with the cis form , How long will it take for half of the equilibrium amount of the trans to be formed? |
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Answer» 150 sec. |
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| 24236. |
The reaction CH_(4) (g) + Cl_2 (g) to CH_(3) Cl (g) to HCl (g) has Delta H = -25 kCal . From the given data , what is the bond energy of Cl – Cl bond |
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Answer» 70 KCAL |
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| 24237. |
The reaction CH_(4)Cl_(2) overset("U.V. light") to CH_(3)Cl+HCl is an example of |
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Answer» addition reaction |
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| 24238. |
The reaction CH_4+Cl_2underset(Light)overset (UV)rarr CH_3Cl+HClis an example of : |
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Answer» ADDITION reaction |
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| 24239. |
The reaction CH_3OC_2H_5 with cold HI gives |
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Answer» `CH_3OH+C_2H_5I` The NUCLEOPHILE `I^-` attacks `-CH_3` group and not `-CH_2` group of ethyl group , because the POSITIVE CHARGE on `-CH_2` is reduced by electron -donating effect of `-CH_3` in ethyl is more than on `-CH_2` of ethyl group . |
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| 24240. |
The reactionCH_3COOH_3+H_2Ooverset(H^(+))rarrCH_3COOH+CH_3OHis found to be |
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Answer» a reaction of the SECOND ORDER |
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| 24241. |
The reaction, CH_3COOC_2H_5+NaOHrarrCH_3COONa+C_2H_5OH is: |
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Answer» Bimolecular reaction |
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| 24242. |
The reaction CH_3COOC_2H_5 + NaOH to CH_3COONa+C_2H_5OH |
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Answer» bimolecular REACTION Hence the order of reaction is 2 . And TWO molecules involved so it is bimolecular . |
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| 24243. |
The reaction CH_(3)COOC_(2)H_(5)+H_(2)O+H_(2)O overset(H^(+))to CH_(3)COOH+C_(2)H_(5)OH is of |
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Answer» first ORDER. |
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| 24244. |
The reaction CH_3COOC_2H_5+H_2Oundersetrarr(H^(+))CH_3COOH+C_2H_5-OH is an example of |
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Answer» ZERO ORDER reaction |
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| 24245. |
The reaction CH_(3)COOAg+Br_(2)rarrCH_(3)Br+CO_(2)+AgBr is known as : |
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Answer» Hunsdiecker REACTION |
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| 24246. |
The reaction :CH_(3)COOAg+Br_(2)overset(C Cl_(4))rarr CH_(3)Br+CO_(2)+AgBris known as …. |
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Answer» Finkelstin REACTION |
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| 24247. |
The reaction CH_(3)CHO + CH_(3)CHO overset("Dil. alkali")rarr CH_(3)CH (OH)CH_(2)CHO isknown as |
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Answer» CANNIZZARO's reaction |
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| 24248. |
The reaction, CH_3CHO+H_2N-NH_2rarrCH_3CH=N-NH_2 is: |
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Answer» Elimination |
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| 24249. |
The reaction , CH_(3)CHO + CH_(3)CHO overset("alkali") to CH_(3)CH(OH) CH_(2)CHO represents |
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Answer» CANNIZZARO REACTION |
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| 24250. |
The reaction CH_3CH=CH_2underset(H^+)overset((CO+H_2))to CH_3-underset"COOH"underset|CH-CH_3 is known as |
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Answer» Wurtz reaction |
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