This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 24301. |
The reaction between H_(2)(g)" and "O_(2)(g) is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain. |
| Answer» Solution :This is because activation ENERGY of the REACTION is very HIGH at room temperature. | |
| 24302. |
The reaction between H_(2(g)) and O_(2(g)) is highly feasible yet allowing the gases to satnd at room temperature in the same vessel does not lead to the formation of water .Explain. |
| Answer» SOLUTION :This is because ACTIVATION energy for the REACTION is very high at room temperatue .So due to lack of energy bonds of `H_(2)` and `O_(2)` will bot break and inspite of collision product will not FORM. | |
| 24303. |
The reaction between H_(2(g)) and Icl_((g)) occurns in thefollowing steps : (i) H_(2)+ICl rarr HI+HCl (ii) HI+ICl rarr I_(2)+HCl The reaction intermediate in the reaction is |
| Answer» ANSWER :B | |
| 24304. |
The reaction between H_(2(g)) and ICI_((g)) occurs in the following steps : i) H_2+ ICl to HI +HCl ii) HI + IClto I_2+ HCl The reaction intermediate in the reaction is |
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Answer» HCl |
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| 24305. |
The reaction between gaseous NH_(3) and HBr produces the white solid NH_(4)Br. Suppose that NH_(3) and HBr are introduced simultaneously into the opposite ends of an open tube that is 1 metre long. Where would you expect the white solid to form ? |
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Answer» Solution :Suppose the two gases meet to form a white solid `NH_(4)Br` at a will of `r_(1)`cm from the `NH_(3)` END. Thus from the HBR end, the distance will be `(100 - r_(1)) cm`. We have, `(r_(NH_(3)))/(r_(HBr)) = SQRT((M_(HBr))/(M_(NH_(3)))) = sqrt((81)/(17))` Since the rate of diffusion is proportional to the distance, the molecules travel. `therefore (r_(NH_(3)))/(r_(HBr)) = (r_(1))/(100 - r_(1)) = sqrt((81)/(17)) = 2.18` `therefore r_(1) = 65.55 cm`. |
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| 24306. |
The reaction between Ferric chloride and potassium thio cyanate solution gives a blood red coloured coordination compound as …………… |
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Answer» |
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| 24307. |
The reaction between excesss of C_2H_5OH and H_2 SO_4 at 140^@C gives |
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Answer» `C_2H_5 HSO_4` |
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| 24308. |
The reaction between ethyl bromide and sodium in dry ether to form butane is called: |
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Answer» Friedel-crafts REACTION |
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| 24309. |
the reaction between cyanamide NH_(2)CH(s) and oxygen was allowed to complete and DeltaU at 300 K was observed to be -743 kJ mol ^(-1) . The value of DeltaHat 300 K for the combustion reaction NH_(2) CN(s)+3/2 O_(2)(g) to N_(2)(g) + CO_(2)(g) + H_(2)O(l)would be |
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Answer» `-741. 75 kJ mol ^(-1) ` `=-743 + 1/2 xx8.314 xx300xx10^(-3)kJ mol^(-1)` `741.75 kJ mol^(-1)` |
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| 24310. |
The reaction between chloral and chlorobenzene in H_(2)SO_(4) yields: |
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Answer» <P>CHLORETONE |
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| 24312. |
The reaction between CH_3 COCl and KCN followed by hydrolysis yields |
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Answer» ACETAMIDE |
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| 24313. |
The reaction between C_(6)H_(5)NH_(2) and chloroform and a few drops of alcoholic KOH is known as: |
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Answer» CANNIZZARO's REACTION |
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| 24314. |
The reaction between C_2H_5ONa + C_2H_5Ito give C_2H_5OC_2H_5 is called |
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Answer» WURTZ REACTION |
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| 24315. |
The reaction between Benzaldehyde and methyl amine takes place in a very narrow pH range. For the above reaction optimum pH is |
| Answer» Solution :OPTIMUM pH for the above reaction =4-5 | |
| 24316. |
The reaction between benzene diazonium chloride and benzene in the presence of NaOH is……….. |
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Answer» PERKIN's reaction |
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| 24317. |
The reaction between Aniline and Nitrous acid at very low temp (0 ^(@)C) gives which product ? |
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Answer» ACETANILIDE
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| 24318. |
The reaction between an alcoholand an acid with the elimination of water molecules is called |
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Answer» Esterfication |
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| 24319. |
The reaction between an alcohol and an acid with the elimination of water molecule is called |
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Answer» ESTERIFICATION |
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| 24320. |
The reaction between an alcohol and an acid is known as : |
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Answer» SAPONIFICATION |
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| 24321. |
The reaction between alkyl halides and sodium metal is called : |
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Answer» WURTZ reaction |
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| 24322. |
The reaction between alcohol and conc. H_2SO_4 at 413 K gives |
| Answer» Answer :A | |
| 24323. |
The reaction between A to B is not feasible but on changing entropy through a series of steps : A to C to D to B DeltaS (A to C) = 50 eu DeltaS (C to D) = 30 eu DeltaS(B to D) = 20 eu. The entropy change for A to B would be : |
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Answer» 100 EU |
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| 24324. |
The reaction between A and B is first order w.r.t. A and zero order w.r.t. B. Fill in the blanks in the following table : {:("Experiment",,,[A]//"mol L"^(-1),,,[B]//"mol L"^(-1),,,"Initialrate"//"mol L"^(-1)min^(-1)),(I,,,0.1,,,0.1,,,2.0xx10^(-2)),(II,,,-,,,0.2,,,4.0xx10^(-2)),(III,,,0.4,,,0.4,,,""-),(IV,,,-,,,0.2,,,2.0xx10^(-2)):} |
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Answer» Solution :The rate expression will be : Rate `=k[A]^(1)[B]^(0)=k[A]` For EXPT. I, `2.0xx10^(-2)=MOLL^(-1)" min"^(-1)=k(0.1" M")" or "k=0.2" min"^(-1)` For expt. II, `4.0xx10^(-2)mol L^(-1)" min"^(-1)=0.2" min"^(-1)[A]" or "[A]=0.2" mol L"^(-1)` For expt. III, Rate `=(0.2" min"^(-1))(0.4" mol L"^(-1))=0.08" mol L"^(-1)" min"^(-1)` For expt. IV, `2.0xx10^(-2)" mol L"^(-1)" min"^(-1)=0.2" min"^(-1)[A]" or "[A]=0.1" mol L"^(-1)` |
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| 24325. |
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table. |
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Answer» Solution :the rate EQUATION for the reaction is : r`=k[A]^(1)[B]^(0)` i) Comparing EXPERIMENTS I and II. `2.0 xx 10^(-2) = k[0.1]^(1)[0.1]^(0)` `4.0 xx 10^(-2) = k[x]^(1)[0.2]^(0)` Dividing eqn.(ii) by eqn. (i), `(4.0 xx 10^(-2))/(2.0 xx 10^(-2)) = (k[x]^(1)[0.2]^(0))/(k[0.1]^(1)[0.1]^(0)) , 2 = x/0.1 or x = 2xx 0.1= 0.2 M` Thus, concentration of A in experiment II is 0.2 M ii) Comparing experiments II and III. When the concentration of A is made double, the reaction rate will also becomes twice. `therefore` Rate of reaction in experiment III is `8.0 xx 10^(-2)` iii) Comparing experiments I and IV, Since, the reaction rates are the same in both the experiments, the molar concentration of A in experiment IV must be the same as in experiment I. i.e., it must be 0.1 M. |
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| 24326. |
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table : |
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Answer» Solution :The RATE expression will be : `""` Rate `=K[A]^(1)[B]^(0)=k[A]` From experiment I,`""2.0xx10^(-2)"mol L"^(-1)"min"^(-1)= k(0.1m) or k=0.2 "min"^(-1)` From experiment II, `""4.0xx10^(-2)"mol"^(-1)L^(-1)"min"^(-1)=(0.2 "min"^(-1))[A] or [A]=0.2 "mol L"^(-1)` From experiment III, `"Rate"=(0.2"min"^(-1))(0.4"mol L"^(-1)) or " Rate"=0.08"mol L"^(-1)"min"^(-1)` From Experiment IV, `""2.0xx10^(-2)"mol L"^(-1) "min"^(-1)=0.2"min"^(-1)[A] or [A]-0.1"mol L"^(-1)` |
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| 24327. |
The reaction AsH_(3) (g) rarr As(s) +(3)/(2) H_(2)(g) was followed at constant volume at 310°C by measuring the gas pressure at intervals Show from the following figures that reaction is of first order. Time (in hrs) 057.510 Total pressure (in mm) 758827856882 |
| Answer» SOLUTION :FIRST ORDER | |
| 24328. |
The reaction at cathode during the electrolysis of aqueous solution of NaCI in Nelson cell is : |
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Answer» `2CI^-rarrCI_2 + 2E` |
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| 24329. |
The reaction at anode in NICAD cell is |
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Answer» `NiO_(2) + 2 OH^(-) to Ni(OH)_(2) + 2e^(-) + H_(2)O` |
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| 24330. |
The reaction at anode in a fuel cell is |
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Answer» `PB + SO_(4)^(2-) to Pb SO_(4) + 2 e^(-)` |
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| 24331. |
The reaction A+B toC has zero order. Write its rate equatons. |
| Answer» SOLUTION :RATE = `K[A]^(0)[B]^(0)`. | |
| 24332. |
The reaction, Aroverset(+)(N_(2))Cl^(-) overset(Cu//HCl)to ArCl+N_(2)+CuCl is names as_____ |
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Answer» SANDMEYER reaction |
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| 24333. |
The reactionAroverset(+)N_(2)Cl^(-)overset(Cu//HCl)to ArCl +N_(2) + CuClis named as _____ |
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Answer» SANDMEYER REACTION |
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| 24334. |
The reaction Aroverset(+)N_(2)Cl^(-)overset(Cu//HCl)rarr ArCl+N_(2)+CuCl is named as : |
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Answer» SANDMEYER reaction |
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| 24335. |
The reaction A +B to C has zero order. What is the rate equation ? |
| Answer» SOLUTION :`(dx)/(dt)=k[A]^(0)[B]^(0)` | |
| 24336. |
The reaction ArN_(2)^(+)Cl^(-) overset(Cu//HCl)(rarr)ArCl+N_(2)+CuCl is named as ……………. |
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Answer» SANDMEYER reaction |
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| 24337. |
The reaction A+2Bto product, is first order in A and second order in B. If t_(1//2) w.r.t. A is same as the t_(1//2) of the reaction. |
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Answer» `[A]_("INITIAL")GT[B]_("Initial")` |
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| 24338. |
The reactionAlcohol +HCl hArr lakyl halide +H_(2)O for completion of reaction is used |
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Answer» anhy `ZnCl_(2)` |
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| 24339. |
The reaction A + B rarr C follows first order kinetics with respect to A and second order kinetics with respect to B. What is the overall order of the reaction ? |
| Answer» SOLUTION :THREE or 3. | |
| 24340. |
The reaction and mechanism involved in the formation of the compound (I) form (H), respectively, are: |
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Answer» Clasisen REARRANGEMENT REACTION, FREE RADICAL mechanism
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| 24341. |
The reaction A+B rarr C +DDeltaH =30 kJ mol^(-1) should have activation energy |
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Answer» a) 30 kJ `MOL^(-1)` |
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| 24342. |
The reaction A(g)toB(g)+2C(g) is a first order reaction with rate constant 2.772xx10^(-3)s^(-1), Starting with 0.1 mole of A in 2 litre vessel, find the concentration of A after 250 secwhen the reaction is allowed to take place at constant pressure and at 300 K? |
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Answer» `0.0125 M` |
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| 24343. |
The reaction A(g) to 2B(g) + C(g) follows first order kinetics. The reaction is started with pure 'A' in a rigid closed vessel maintained at constant temperature. After 10 s, a pin hole is developed in the vessel. If the molar ratio of gases 'A' and 'B' coming out initially is 1 : 2, the rate constant of reaction (in s^(-1) ) is (Molar masses of A, B and C are 16, 4 and 8 g/mol, respectively, ln 2 = 0.7, ln 3 = 1.1) |
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Answer» Now, `(r_A)/(r_B) = (P_A)/(P_B) sqrt((M_B)/(M_A)) implies 1/2 = (a-x)/(2x) cdot sqrt(4/16)` `implies x = a/3` Now, `K = 1/t cdot 1N a/(a-x) = 1/(10 "sec")cdot 1n(a)/((2a)/(3))`. |
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| 24344. |
The reaction ._(5)B^(8) rarr ._(4)Be^(8) + ._(1)e^(0) is due to |
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Answer» Loss of `ALPHA`-particles |
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| 24345. |
The reaction A_((g)) + B_((g))hArrC_((g)) + D_((g)) proceeds to right hand side upto 99.9%. The equilibrium constant K for the reaction will be - |
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Answer» `10^(4)` |
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| 24346. |
The reaction A+2B hArr 2C+Dwas situated using an initial concentration of B which was 1.5 times that of A But the equilibrium concentration ofA and C were found to be equal . Then what is the K_c for the equilibrium? |
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Answer» 4 |
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| 24347. |
The reaction, A(g)+2B(g) to C(g)+D(g) is an elementary process. In an experiment, the initial partial pressure of A and B are P_(A)=0.60 and P_(B)=0.80 atm. When P_(C )=0.2 atm, the rate of reaction relative to the initial rate is |
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Answer» `1//48` |
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| 24348. |
The reaction : A(aq) rarr Products, occur 0.01% in 20 milliseconds when the initial concentration of 'A' was 0.4 M and 80 milliseconds when the initial concentration of 'A' was 0.2 M. The order of reaction is : |
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Answer» 0 |
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| 24349. |
The reaction: |
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Answer» `CH_2Br-CH_2Br` |
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| 24350. |
The reaction A to B follows first order kinetics . The time taken for 0.8 mole of A to produce 0.8 mole of A to produce 0.6 mole of B is 1 hour . What is the time taken for conversion of 0.9 mole of A to produce to 0.675 mole of B |
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Answer» 2HOURS `t = (2.303)/(k)` log `(0.9)/(0.675) = (2.303)/(k) "log" (4)/(3) ` , t = 1 hour . |
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