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24301.

The reaction between H_(2)(g)" and "O_(2)(g) is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain.

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Solution :This is because activation ENERGY of the REACTION is very HIGH at room temperature.
24302.

The reaction between H_(2(g)) and O_(2(g)) is highly feasible yet allowing the gases to satnd at room temperature in the same vessel does not lead to the formation of water .Explain.

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SOLUTION :This is because ACTIVATION energy for the REACTION is very high at room temperatue .So due to lack of energy bonds of `H_(2)` and `O_(2)` will bot break and inspite of collision product will not FORM.
24303.

The reaction between H_(2(g)) and Icl_((g)) occurns in thefollowing steps : (i) H_(2)+ICl rarr HI+HCl (ii) HI+ICl rarr I_(2)+HCl The reaction intermediate in the reaction is

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HCl
HI
`I_(2)`
`I CL`

ANSWER :B
24304.

The reaction between H_(2(g)) and ICI_((g)) occurs in the following steps : i) H_2+ ICl to HI +HCl ii) HI + IClto I_2+ HCl The reaction intermediate in the reaction is

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HCl
ICl
`I_2`
HI

Solution :Reaction intermediate is FORMED in one step and CONSUMED in second step.
24305.

The reaction between gaseous NH_(3) and HBr produces the white solid NH_(4)Br. Suppose that NH_(3) and HBr are introduced simultaneously into the opposite ends of an open tube that is 1 metre long. Where would you expect the white solid to form ?

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Solution :Suppose the two gases meet to form a white solid `NH_(4)Br` at a will of `r_(1)`cm from the `NH_(3)` END. Thus from the HBR end, the distance will be `(100 - r_(1)) cm`.
We have,
`(r_(NH_(3)))/(r_(HBr)) = SQRT((M_(HBr))/(M_(NH_(3)))) = sqrt((81)/(17))`
Since the rate of diffusion is proportional to the distance, the molecules travel.
`therefore (r_(NH_(3)))/(r_(HBr)) = (r_(1))/(100 - r_(1)) = sqrt((81)/(17)) = 2.18`
`therefore r_(1) = 65.55 cm`.
24306.

The reaction between Ferric chloride and potassium thio cyanate solution gives a blood red coloured coordination compound as ……………

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Answer :`K_(3)[FE(SCN)_(6)]` Potassium ferrithio CYANATE
24307.

The reaction between excesss of C_2H_5OH and H_2 SO_4 at 140^@C gives

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`C_2H_5 HSO_4`
`CH_3OH`
`C_2 H_5-O-C_2 H_5`
`C_2H_5`

ANSWER :C
24308.

The reaction between ethyl bromide and sodium in dry ether to form butane is called:

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Friedel-crafts REACTION
WURTZ reaction
Cannizzaro.s reaction
Williamson.s reaction

ANSWER :B
24309.

the reaction between cyanamide NH_(2)CH(s) and oxygen was allowed to complete and DeltaU at 300 K was observed to be -743 kJ mol ^(-1) . The value of DeltaHat 300 K for the combustion reaction NH_(2) CN(s)+3/2 O_(2)(g) to N_(2)(g) + CO_(2)(g) + H_(2)O(l)would be

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`-741. 75 kJ mol ^(-1) `
`-743 KJ mol ^(-1)`
`-744 .25 kJ mol ^(-1)`
`- 740 . 5 kJ mol ^(-1)`

Solution :`DeltaH=DeltaU+(Deltan_(g))RT`
`=-743 + 1/2 xx8.314 xx300xx10^(-3)kJ mol^(-1)`
`741.75 kJ mol^(-1)`
24310.

The reaction between chloral and chlorobenzene in H_(2)SO_(4) yields:

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<P>CHLORETONE
`p,p-` DICHLORODIPHENYL trichloroenthane
`o-` Chlorobenzaldichloride
Chloralphenylchloride

Solution :PREPARATION of `D.D.T`
24311.

The reaction between copper and hot conc H_2SO_4 gives:

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`SO_3`
`SO_2`
`CU(OH)_2`
`H_2`

ANSWER :B
24312.

The reaction between CH_3 COCl and KCN followed by hydrolysis yields

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ACETAMIDE
acetic ACID
Pyruvic acid (2-oxopropanoic acid)
METHYL isocyanate

Answer :C
24313.

The reaction between C_(6)H_(5)NH_(2) and chloroform and a few drops of alcoholic KOH is known as:

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CANNIZZARO's REACTION
Carbylamine reaction
Frankland reaction
Wurtz reaction

Answer :B
24314.

The reaction between C_2H_5ONa + C_2H_5Ito give C_2H_5OC_2H_5 is called

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WURTZ REACTION
Kobles synthesis
Williamson's synthesis
Hoffman reaction

Answer :C
24315.

The reaction between Benzaldehyde and methyl amine takes place in a very narrow pH range. For the above reaction optimum pH is

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2 to 3
4 to 5
5 to 9
12 to 13

Solution :OPTIMUM pH for the above reaction =4-5
24316.

The reaction between benzene diazonium chloride and benzene in the presence of NaOH is………..

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PERKIN's reaction
Gattermann's reaction
Sandmeyer reaction
Gomberg-Bachmann reaction

Answer :D
24317.

The reaction between Aniline and Nitrous acid at very low temp (0 ^(@)C) gives which product ?

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ACETANILIDE
BENZENE DIAZONIUM chloride
Sodium phenoxide
Diphenyl ether

Solution :
24318.

The reaction between an alcoholand an acid with the elimination of water molecules is called

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Esterfication
Saponification
Etherification
Elimination

Solution :`(CH_(3)COOH+CH_(3)OH UNDERSET("ESTERIFICATION")to CH_(3)COOCH_(3)+H_(2)O`
24319.

The reaction between an alcohol and an acid with the elimination of water molecule is called

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ESTERIFICATION
SAPONIFICATION
Etherification
ELIMINATION

ANSWER :A
24320.

The reaction between an alcohol and an acid is known as :

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SAPONIFICATION
Esterification
Hydrolysis
HYDROGENATION

Answer :B
24321.

The reaction between alkyl halides and sodium metal is called :

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WURTZ reaction
kolbe's reaction
clemensen's reaction
Finkelstein reaction

Answer :A
24322.

The reaction between alcohol and conc. H_2SO_4 at 413 K gives

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DIETHYL ether
isopropyl ALCOHOL
diethyl alcohol
ethene

Answer :A
24323.

The reaction between A to B is not feasible but on changing entropy through a series of steps : A to C to D to B DeltaS (A to C) = 50 eu DeltaS (C to D) = 30 eu DeltaS(B to D) = 20 eu. The entropy change for A to B would be :

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100 EU
60 eu
`-60eu `
`-100 eu`

ANSWER :B
24324.

The reaction between A and B is first order w.r.t. A and zero order w.r.t. B. Fill in the blanks in the following table : {:("Experiment",,,[A]//"mol L"^(-1),,,[B]//"mol L"^(-1),,,"Initialrate"//"mol L"^(-1)min^(-1)),(I,,,0.1,,,0.1,,,2.0xx10^(-2)),(II,,,-,,,0.2,,,4.0xx10^(-2)),(III,,,0.4,,,0.4,,,""-),(IV,,,-,,,0.2,,,2.0xx10^(-2)):}

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Solution :The rate expression will be : Rate `=k[A]^(1)[B]^(0)=k[A]`
For EXPT. I, `2.0xx10^(-2)=MOLL^(-1)" min"^(-1)=k(0.1" M")" or "k=0.2" min"^(-1)`
For expt. II, `4.0xx10^(-2)mol L^(-1)" min"^(-1)=0.2" min"^(-1)[A]" or "[A]=0.2" mol L"^(-1)`
For expt. III, Rate `=(0.2" min"^(-1))(0.4" mol L"^(-1))=0.08" mol L"^(-1)" min"^(-1)`
For expt. IV, `2.0xx10^(-2)" mol L"^(-1)" min"^(-1)=0.2" min"^(-1)[A]" or "[A]=0.1" mol L"^(-1)`
24325.

The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table.

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Solution :the rate EQUATION for the reaction is : r`=k[A]^(1)[B]^(0)`
i) Comparing EXPERIMENTS I and II.
`2.0 xx 10^(-2) = k[0.1]^(1)[0.1]^(0)`
`4.0 xx 10^(-2) = k[x]^(1)[0.2]^(0)`
Dividing eqn.(ii) by eqn. (i),
`(4.0 xx 10^(-2))/(2.0 xx 10^(-2)) = (k[x]^(1)[0.2]^(0))/(k[0.1]^(1)[0.1]^(0)) , 2 = x/0.1 or x = 2xx 0.1= 0.2 M`
Thus, concentration of A in experiment II is 0.2 M
ii) Comparing experiments II and III.
When the concentration of A is made double, the reaction rate will also becomes twice.
`therefore` Rate of reaction in experiment III is `8.0 xx 10^(-2)`
iii) Comparing experiments I and IV,
Since, the reaction rates are the same in both the experiments, the molar concentration of A in experiment IV must be the same as in experiment I. i.e., it must be 0.1 M.
24326.

The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table :

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Solution :The RATE expression will be :
`""` Rate `=K[A]^(1)[B]^(0)=k[A]`
From experiment I,`""2.0xx10^(-2)"mol L"^(-1)"min"^(-1)= k(0.1m) or k=0.2 "min"^(-1)`
From experiment II, `""4.0xx10^(-2)"mol"^(-1)L^(-1)"min"^(-1)=(0.2 "min"^(-1))[A] or [A]=0.2 "mol L"^(-1)`
From experiment III, `"Rate"=(0.2"min"^(-1))(0.4"mol L"^(-1)) or " Rate"=0.08"mol L"^(-1)"min"^(-1)`
From Experiment IV, `""2.0xx10^(-2)"mol L"^(-1) "min"^(-1)=0.2"min"^(-1)[A] or [A]-0.1"mol L"^(-1)`
24327.

The reaction AsH_(3) (g) rarr As(s) +(3)/(2) H_(2)(g) was followed at constant volume at 310°C by measuring the gas pressure at intervals Show from the following figures that reaction is of first order. Time (in hrs) 057.510 Total pressure (in mm) 758827856882

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SOLUTION :FIRST ORDER
24328.

The reaction at cathode during the electrolysis of aqueous solution of NaCI in Nelson cell is :

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`2CI^-rarrCI_2 + 2E`
`2H^+ +2e rarrH_2`
`2OH^- rarrH_2+O_2+2e`
`NA^+ +erarrNa`

ANSWER :B
24329.

The reaction at anode in NICAD cell is

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`NiO_(2) + 2 OH^(-) to Ni(OH)_(2) + 2e^(-) + H_(2)O`
`Cd to Cd^(2+) + 2e^(-)`
`Cd + 2OH^(-) to Cd (OH)_(2) + 2e^(-)`
`Ni to Ni^(2+)+ 2e^(-)`

Solution :At anode in NICAD CELL, REACTION is `Cd to Cd^(2+)+ 2e^(-)`
24330.

The reaction at anode in a fuel cell is

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`PB + SO_(4)^(2-) to Pb SO_(4) + 2 e^(-)`
`2H_(2) + 4 OH^(-) to 4 H_(2)O +4e^(-)`
`O_(2) + 2 H_(2)O + 4e^(-) to 4OH^(-)`
`2H_(2) + O_(2) to 2H_(2)O`

Solution :It is a FACT .
24331.

The reaction A+B toC has zero order. Write its rate equatons.

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SOLUTION :RATE = `K[A]^(0)[B]^(0)`.
24332.

The reaction, Aroverset(+)(N_(2))Cl^(-) overset(Cu//HCl)to ArCl+N_(2)+CuCl is names as_____

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SANDMEYER reaction
Gattermann reaction
Claisen reaction
Carbylamine reaction

Answer :B
24333.

The reactionAroverset(+)N_(2)Cl^(-)overset(Cu//HCl)to ArCl +N_(2) + CuClis named as _____

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SANDMEYER REACTION
Gatterman reaction
Hofmann bromamie degradation reaction
CARBYLAMINE reaction

ANSWER :B
24334.

The reaction Aroverset(+)N_(2)Cl^(-)overset(Cu//HCl)rarr ArCl+N_(2)+CuCl is named as :

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SANDMEYER reaction
Gattermann reaction
Claisen reaction
Carbylamine reaction.

Answer :B
24335.

The reaction A +B to C has zero order. What is the rate equation ?

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SOLUTION :`(dx)/(dt)=k[A]^(0)[B]^(0)`
24336.

The reaction ArN_(2)^(+)Cl^(-) overset(Cu//HCl)(rarr)ArCl+N_(2)+CuCl is named as …………….

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SANDMEYER reaction
Gatterman reaction
Claisen reaction
Carbylamine reaction

Answer :B
24337.

The reaction A+2Bto product, is first order in A and second order in B. If t_(1//2) w.r.t. A is same as the t_(1//2) of the reaction.

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`[A]_("INITIAL")GT[B]_("Initial")`
`[A]_("Initial")=[B]_("Initial")`
A is the limiting reactant
B is the limiting reactant

Answer :C
24338.

The reactionAlcohol +HCl hArr lakyl halide +H_(2)O for completion of reaction is used

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anhy `ZnCl_(2)`
conc. `H_(2)SO_(4)`
EXCESS of water
`CaCl_(2)`

Answer :A
24339.

The reaction A + B rarr C follows first order kinetics with respect to A and second order kinetics with respect to B. What is the overall order of the reaction ?

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SOLUTION :THREE or 3.
24340.

The reaction and mechanism involved in the formation of the compound (I) form (H), respectively, are:

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Clasisen REARRANGEMENT REACTION, FREE RADICAL mechanism
Claisen rerrangement reaction, CONCERTED mechanism
Clasien-Schmide reaction, free radical mechanism
Claisen-Schmidt reaction, concerted mechanism

Solution :
24341.

The reaction A+B rarr C +DDeltaH =30 kJ mol^(-1) should have activation energy

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a) 30 kJ `MOL^(-1)`
B) `-30 "kJ mole"^(-1)`
c) ` gt 30 "kJ mole"^(-1)`
d) `le 30 "kJ mol"^(-1)`

Answer :C
24342.

The reaction A(g)toB(g)+2C(g) is a first order reaction with rate constant 2.772xx10^(-3)s^(-1), Starting with 0.1 mole of A in 2 litre vessel, find the concentration of A after 250 secwhen the reaction is allowed to take place at constant pressure and at 300 K?

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`0.0125 M`
`0.025 M`
`0.05 M`
NONE of these

Answer :A
24343.

The reaction A(g) to 2B(g) + C(g) follows first order kinetics. The reaction is started with pure 'A' in a rigid closed vessel maintained at constant temperature. After 10 s, a pin hole is developed in the vessel. If the molar ratio of gases 'A' and 'B' coming out initially is 1 : 2, the rate constant of reaction (in s^(-1) ) is (Molar masses of A, B and C are 16, 4 and 8 g/mol, respectively, ln 2 = 0.7, ln 3 = 1.1)

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SOLUTION :`{:(,A,to,2B,+,C),(t=0,a mol, ,0, ,0),(t=10"sec",(a-x) mol, ,2x mol, ,x mol):}`
Now, `(r_A)/(r_B) = (P_A)/(P_B) sqrt((M_B)/(M_A)) implies 1/2 = (a-x)/(2x) cdot sqrt(4/16)`
`implies x = a/3`
Now, `K = 1/t cdot 1N a/(a-x) = 1/(10 "sec")cdot 1n(a)/((2a)/(3))`.
24344.

The reaction ._(5)B^(8) rarr ._(4)Be^(8) + ._(1)e^(0) is due to

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Loss of `ALPHA`-particles
Loss of `beta-`particles
Loss of positron
Electron loss

Solution :The emission of positron TAKES PLACES
24345.

The reaction A_((g)) + B_((g))hArrC_((g)) + D_((g)) proceeds to right hand side upto 99.9%. The equilibrium constant K for the reaction will be -

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`10^(4)`
`10^(5)`
`10^(6)`
`10^(8)`

ANSWER :C
24346.

The reaction A+2B hArr 2C+Dwas situated using an initial concentration of B which was 1.5 times that of A But the equilibrium concentration ofA and C were found to be equal . Then what is the K_c for the equilibrium?

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4
8
6
0.632

Answer :A
24347.

The reaction, A(g)+2B(g) to C(g)+D(g) is an elementary process. In an experiment, the initial partial pressure of A and B are P_(A)=0.60 and P_(B)=0.80 atm. When P_(C )=0.2 atm, the rate of reaction relative to the initial rate is

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`1//48`
`1//24`
`9//16`
`1//6`

ANSWER :D
24348.

The reaction : A(aq) rarr Products, occur 0.01% in 20 milliseconds when the initial concentration of 'A' was 0.4 M and 80 milliseconds when the initial concentration of 'A' was 0.2 M. The order of reaction is :

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0
1
2
3

Answer :D
24349.

The reaction:

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`CH_2Br-CH_2Br`
`CHBr_2-CHBr_2`
`CHBr-CHBr`
None

Answer :D
24350.

The reaction A to B follows first order kinetics . The time taken for 0.8 mole of A to produce 0.8 mole of A to produce 0.6 mole of B is 1 hour . What is the time taken for conversion of 0.9 mole of A to produce to 0.675 mole of B

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2HOURS
1 hour
0.5 hour
0.25 hour

SOLUTION :`k = (2.303)/(t)` log `(0.8)/(0.6) = 2.303` log `(4)/(3)`
`t = (2.303)/(k)` log `(0.9)/(0.675) = (2.303)/(k) "log" (4)/(3) ` , t = 1 hour .