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24401.

The reaction, (1//2)Hg(g) + AgCl(s)=H^+(aq)+Cl^-(aq)+Ag(s) occurs in the gal vanic cell:

Answer»

`AgIAgCI(s)IKCI(SOLN.)AgNO_3(soln.)IAg`
`PtIH_2(G)|HCI(slon.)|AgNO_3(slon.)Iag`
`PtH_2(g)|HCI(slon.)|AGCI(s)|Ag`
`Pt|H_2(g)|KCI(slon.)|AgCI(s)|Ag`

ANSWER :C
Discussion
24402.

The reactioin of HBr with CH_(3)C-unde

Answer»

`CH_(3)underset(CH_(3))underset(|)(CBr)-CH_(3)`<BR>`CH_(3)CH_(2)CH_(2)CH_(2)-Br`
`CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)Br`
`CH_()CH_(2)-underset(Br)underset(|)(C)-H-CH_(3)`

ANSWER :C
Discussion
24403.

The reaction, 1//2 H_(2) (g) + AgCl(s) = H^(+) (aq) + Cl^(-) (aq) + Ag(s) occurs in the galvanic cell . The anode is

Answer»

AGCL
Ag
`H_(2)`
`H^(+)`

Solution :Anode is `H_(2) | H^(+)` , Cathode is `Ag^(+) |Ag`.
Discussion
24404.

The reactio is spontaneous if the cell potential is

Answer»

POSITIVE
Negative
Zero
Infinite

Solution :EMF=[s.r.p. of cathode-s.r.p. of anode]
Where s.r.p.=Standard reduction potential
IF EMF is positive then the reaction is spontaneous
For e.g. in Galvanic CELL
(a) EMF=1.1 VOLT
(b) Cathode is MADE of copper
(c) Anode is made of Zinc
EMF=0.34 (-0.76)=1.1 volt
Discussion
24405.

The reactant which is entirely consumed in reactions is known as limiting reagent. In the reaction 2A+4B rarr 3C+4D, when 5 moles of A react with 6 moles of B, then (i) which is the limiting reagent ? (ii) calculate the amount of C formed ?

Answer»

Solution :According to the GIVEN equation, 2 moles of A react with 4 moles of B.
`therefore` 5 moles of A will react with 10 moles of B, But we have only 6 moles of B.
6 moles of will react 3 moles of A and 2 moles of A will unreacted. THUS,
(i) B is limiting a A is the excess reactant.
(II) The AMOUNT of C formed will depend upon the limiting reactant i.e., 6 moles of B
4 moles of B FORM C = 3 moles
`therefore"6 moles of B will form C"=(3)/(4)xx6="4.5 moles."`
Discussion
24406.

the reactant (A) will be

Answer»




Solution :In presence of NAOH intramolecular aldol CONDENSATION TAKE place.
Discussion
24407.

The reactant (A) will be :

Answer»




ANSWER :B
Discussion
24408.

The RBC deficient Haemoglobin is a sign of………………….

Answer»

VITAMIN `B_(12)` DEFICIENCY
Vitamin `B_(6)` deficiency
Vitamin K deficiency
Vitamin D deficiency

Answer :A
Discussion
24409.

The raw meterial for nylon-66 is

Answer»

adipic acid
tertraflouroethylene
hexamethylene diamine
both a and C

Solution :We know that, Nylon -66 is formed by the REACTION between adipic acid and hexamethylene diamine . Both monomwr UNITS consist of 6 -carbon atoms. Therefore it is called nylon -66 and is the raw material of nylon -66 .
Discussion
24410.

The raw materials required for the manufacture of Buna-N are ..

Answer»

acrylonitrile + BUTA - 1,3 - DIENE
chloro prene + buta - 1,3 - diene
terephthalic acid + ETHANE 1,2 - diol
phenol + methanal

Solution :acrylonitrile + Buta - 1,3 - diene
Discussion
24411.

The raw materials used in Nylon-6 is

Answer»

ADIPIC ACID
PHTHALIC acid
ETHYLENE GLYCOL
Caprolactam

Answer :D
Discussion
24412.

The raw materials required for the manufacture of Na_2CO_3 by solvay process are

Answer»

`CaCl_2,(NH_4)_2CO_3, NH_3`
`NH_4Cl, NaCl, CA(OH)_2`
`NaCl, (NH_4)_2CO_3,NH_3`
`NaCl, NH_3,CaCO_3`

Solution :In Solvay PROCESS, the RAW materials required are `NaCl, NH_3`and `CaCO_3` (lime STONE).
Discussion
24413.

The raw materials fed into the blast furnace for making iron are :

Answer»

FeO , `CaCO_3` and coke
`Fe_2O_3` , CaO and coke
`Fe_2O_3 , CaCO_3` and coke
`Fe_3O_4 , CA(HO)_2` and coke

Answer :C
Discussion
24414.

The rawmaterialusedin Fischer Tropschprocessfor the manufactureos synthetic petroleum is :

Answer»

Watergas
Watergas +EXCESS HYDROGEN
Coalgas +hydrogen
Water gas +COAL gas

ANSWER :B
Discussion
24415.

The raw materials is Solvay process are:

Answer»

NAOH, CAO and `NH_3`
`Na_2CO_3 , CaCO_3 and NH_3`
`Na_2SO_4 , CaCO_3 and NH_3`
`NACL, NH_3, CaCO_3`

ANSWER :D
Discussion
24416.

The raw material is used in the manufacture of neoprene?

Answer»

isoprene
CHLOROPRENE
1,3 - BUTA DIENE
VINYL chloride

Solution :chloroprene
Discussion
24417.

The raw material used in Fischer Tropsch process for synthetic pertroleum is

Answer»

WATER gas
Water gas+Excess of hydrogen
Producer gas
Coal gas

Solution :N/A
Discussion
24418.

The ration of weights of Ag and Al deposited at the cathode respectively, when the same current is passed for the same period thorugh molten Al_(2)(SO_(4))_(3) and aqueous AgNO_(3)is

Answer»

`1:4`
`12:1`
`1:12`
`4:1`

ANSWER :B
Discussion
24419.

The ration of the time required for 3/4 of the reaction and half ofthe reaction is :

Answer»

`4:3 `
`3:2`
`2:1`
`1:2`

Solution :(C ) TIME required for 3/4 of reaction
`t_(3//4) = (2.303)/(k) "log" (a)/(1//4a) = (2.303)/(k) log 4 `
Time required for half of reaction
`t_(1//2) = (2.303)/(k ) "log" (a)/((1)/(2)a)=(2.303)/(k)"log"2`
`(t_(3//4))/(t_(1//2))=("log"4)/("log"2)=(2"log"2)/("LOG2)=2:1`
Discussion
24420.

The ration of the value of any colligative property for KCI solution to that for sugar solution is nearly ………...times

Answer»

1
0.5
2
2.5

Answer :C
Discussion
24421.

The ratio of weights of hydrogen and magnesium deposited by the same amount of electricity from H_(2)SO_(4) and MgSO_(4) in aqueous solution are

Answer»

`1:12`
`1:8`
`1:16`
NONE of the above

Answer :D
Discussion
24422.

The ratio of wavelength for II line of Balmer series and I line of Lyman series is .

Answer»


ANSWER :4
Discussion
24423.

The ratio of weight of hydrogen and magnesium deposited by the same amonut of electrcity from H_2SO_4 and MgSO_4 in aqueous solution are :

Answer»

`1:8`
`1:12`
`1:16`
None

Answer :D
Discussion
24424.

The ratio of volumes occupied by 1 mole O_(2) and 1 mole CO_(2) under identical conditions of temperature and pressure is:

Answer»

`1:1`
`1:2`
`1:3`
`2:1`

ANSWER :A
Discussion
24425.

The ratio of two extensive properties is equal to___________ .

Answer»

EXTENSIVE property
intensive property
internal energy
external energy

Answer :B
Discussion
24426.

The ratio of volumes of CH_3 COOH 0.1 (N) to CH_3 COONa 0.1 (N) required to prepare a buffer solution of pH 5.74 is (given : pK_aof CH_3 COOH is 4.74)

Answer»

`10 :1`
`5 :1`
`1 :5`
`1 :10`

Solution :`pH = pK_a+log_(10)("Activityofsalt ")/("ACTIVITYOF acid ")`
` 5.74 =4.74 + log_(10) "concentration" xx "Volume "_(("SALT"))/( "concentration" xx"volume"_("acid"))`
[Concentrationgivenare same ]
` 1= log_(10)(v_("salt"))/( V_("acid ")) impliesV_("salt ") : V_("acid")= 10 :1 `
`thereforeV_("acid") :V_("salt")= 1: 10`
Discussion
24427.

The ratio of their molecular weights of thomas slag and limestone is nearly.

Answer»


SOLUTION :Thomos SLOG is `Ca_(3)(PO_(4))_(2) ` & Mwt =310
Discussion
24428.

The ratio of the value of any colligative property for KCl solution to that of sugar solution is:

Answer»

1
0.5
2
4

Answer :C
Discussion
24429.

The ratio of the uncomplexed to the complexed Zn^(2+) ion in a solution of 10 M NH_(3) is (Given that the stability constant of [Zn(NH_(3))_(4)]^(2+) is 3xx10^(9))

Answer»

`3.3xx10^(-9)`
`3.3xx10^(-11)`
`3.3xx10^(-13)`
`3.3xx10^(-14)`

Solution :`Zn^(2+)+4NH_(3)iff[Zn(NH_(3))_(4)]^(2+)`
`K=([Zn(NH_(3))_(4)]^(2+))/([Zn^(2+)][NH_(3)]^(4))therefore 3xx10^(9)=([Zn(NH_(3))_(4)]^(2+))/([Zn^(2+)](10)^(4))`
`or ([Zn^(2+)])/([Zn(NH_(3))_(4)]^(2+))=(1)/(3xx10^(9)xx10^(4))=3.33xx10^(-14)`
Discussion
24430.

The ratio of the value of any colligative property of KCl solution to that of sugar solution is

Answer»


Solution :Van't HOFF factor (i) `=("EXP. C.P.")/("Cal. C.P.")=1-ALPHA+x alpha+y alpha` ,
For KCl it is = 2 and for sugar it is EQUAL to 1.
`therefore (C.P._(KCl))/(C.O._("Sugar"))=2`
Discussion
24431.

The ratio of the value of any colligative property for KCl solution to that for sugar is nearly ___ times

Answer»


ANSWER :2
Discussion
24432.

The ratio of the value of any colligative property for KCl solution to that for sugar solution is nearly

Answer»

`1.0`
`0.5`
`2.0`
`2.5`

SOLUTION :Colligative property `PROP` No. of PARTICLES
`("Colligative property(KCl)")/("Colligative property(sugar)")=2/1=2`
Discussion
24433.

The ratio of the rate of diffusion of helium and methane under identical condition of pressure and temperature will be

Answer»

4
2
1
`0.5`

ANSWER :B
Discussion
24434.

The ratio of the time taken for 99.9% reaction and half life of the reaction is :

Answer»

100
49.95
10
1000

Solution :( C) For 99.9% completion
`R = [R]_(0)-(99.9)/(100) [R]_(0) = 0.001 [R]_(0)`
` t(99.9%) = (2.303) /(k) "log " ([R]_(0))/(0.001[R]_(0))`
`= (2.303)/(k) "log" 10^(3)`
`= (2.303xx3)/(k)`
`t_(1//2) = (2.303)/(k) "log" ([R]_(0))/(0.5[R]_(0)) `
`= (2.303"log"2)/(k)`
`=(2.303xx0.3010)/(k)`
Dividing EQ . (i ) by eq (ii) we GET
`(t(99.9%))/(t_(1//2))= (3)/(0.3010) ~~ 10`
Discussion
24435.

The ratio of the rates of diffusion of SO_(2), O_(2) and CH_(4) is :

Answer»

`1: sqrt(2) : 2 `
`1:2:4`
`sqrt( 2) : 1 : 2 `
`1:2: 2 sqrt(2)`

SOLUTION :RATE of diffusion `PROP sqrt((1) /( "Mol. wt. "))`
`{:(R(SO_(2)) ,:,r(O_(2)) ,:, r(CH_(4))),(sqrt((1)/( 64)),:,sqrt((1)/(32)),:,sqrt((1)/(16))),((1)/(8),:,(1)/(4sqrt(2)),:,(1)/(4)),(1,:,(2)/(sqrt(2)),:,2):}`
or `1: sqrt(2) : 2`
Discussion
24436.

The ratio of the rate of diffusion of a sample of N_2O_4 partially dissociated into NO_2 with pure hydrogen was found to be 1:5. Calculate (a) the vapour density of the mixture (b) the degree of dissociation of N_2O_4 (c) % by volume of N_2O_4 in the mixture.

Answer»

SOLUTION :(a)25 , (B)21/25 , (C) 200/23%
Discussion
24437.

The ratio of the radius of Bohr first orbit for the electron orbiting the hydrogen nucleus to that of the electron orbiting the deuterium nucleus (mass nearly twice that of H nucleus) is approximately

Answer»

`1:1`
`1:2`
`2:1`
`1:4`

ANSWER :A
Discussion
24438.

The ratio of the numer of moles of AgNO_(3), Pb(NO_(3))_(2) and Fe(NO_(3))_(3) required for coagulation of a difinite amount of a colloidal sol of silver iodide prepared by maxing Ag NO_(3) with excess of KI will be

Answer»

`1:2:3`
`3:2:1`
`6:3:2`
`2:3:6`

Solution :With excess of KI, colloidal particles will be `[AgI] I^(-)`
`{:([AgI]I^(-)+AgNo_(3)to AgI darr+ AgI darr + NO_(3)^(-)),("1 mol""""1 mol"):}`
`2[AgI]I^(-)+Pb(NO_(3)_(2)to AgI darr+ PbI _(2) darrNO_(3)^(-)`
`{:("2 mol","1 mol"),("1 mol", 1/2"mol"):}`
`3[AgI]I^(-)Fe(NO_(3))_(3)to 3 AgL darr+FeI _(3)darr+3NO_(3)^(-)`
`{:("3 mol", "1 mol"),("1 mol", 1/3 "mol"):}`
`therefore` MOLAR ratio required for coagulation of same
amount of `[AgI]I^(-)is 1:1/2:1/3=6:3:2.`
Discussion
24439.

The ratio of the radii of the first three Bohr orbit in H atom is

Answer»

`1: 5: 33`
`1: 2: 3`
`1: 4: 9`
`1: 8:27`

ANSWER :C
Discussion
24440.

The ratio of the number of moles of AgNO_(3), Pb(NO_(3))_(2) and Fe(NO_(3))_(3) required for coagulation of a definite amount of a colloidal sol of silver iodide prepared by mixing AgNO_(3) with excess of KI will be

Answer»

`1:2:3`
`3:2:1`
`6:3:2`
`2:3:6`

Solution :With excess of KI, colloidal particles will be `[AgI]I^(-)`
`underset(1 "mol")([AgI]I^(-)) + underset("1 mol")(AgNO_(3)) to AgI darr + AgI darr + NO_(3)^(-)`
`underset("2 mol")underset("2 mol")(2[AgI]I^(-)) + underset("1/2 mol")underset(1"mol")(Pb(NO_(3))_(2)) to 2AgI darr + PbI_(2) darr + 2NO_(3)^(-)`
`underset(1 "mol")underset(2 "mol")(3[AgI]I^(-)) + underset(1/3 "mol")underset( 1 "mol")(Fe(NO_(3))_(3)) to 3AgI darr + FeI_(3) darr + 3NO_(3)^(+)`
`therefore ` Molar ratio REQUIRED for COAGULATION of same AMOUNTOF `[AgI]I^(-)` is `=1 :1/3 :1/3=6:3:2`
Discussion
24441.

The ratio of the number of atoms of two radioactive elements A and B, in equilibrium with each other, is 3.1 xx 10^(9): 1. If t_((1)/(2)) of element B is 6.45 yrs, calculate that of element A.

Answer»

SOLUTION :`2 XX 10^(10)`
Discussion
24442.

The ratio of the number of hydrogen atoms required to get 1 mole of azobenzene and 1 mole of hydrazobenzene

Answer»

`4:5`
`5:4`
`1:1`
`2:3`

ANSWER :A
Discussion
24443.

The ratio of the gases obtained on dehydration of HCOOH and H_2C_2O_4 by conc. H_2SO_4 is:

Answer»

1:2
2:1
1:3
3:1

Answer :A
Discussion
24444.

The ratio of the energy ofthe electron in the ground state of H to the electron in the first excited state of Be^(3+)is ,

Answer»

`1:4`
`1:8`
`1:16`
`16:1`

Solution :`E_(n)=-(1311.8Z^(2))/(n^(2))kJ"MOL"^(-1)`
`E_(1)(H)=-1311.8`
first excitedstate of `Be^(3+)` is n=2
`E_(2)(Be^(+))=(-1311.8xx16)/4(n=2,z=4)`
`(E_(1)(H))/(E_(2)(Be^(3+)))=1/4`
Discussion
24445.

The ratio of the energy of a photon of 2000overset@A wavelength radiation to that of 4000 overset@Aradiation is:

Answer»

1/4
1/2
2
4

Answer :C
Discussion
24446.

The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is

Answer»

`1/2`
`1/3`
`4/9`
`27/5`

Solution :`E_(1)-E_(2)=1312/(L^(2))=1312/(2^(2))=1312(3/4)`
`E_(2)-E_(3)=1312/(2^(2))=1312/(3^(2))=1312(5/36)`
`therefore(E_(1)-E_(2)):(E_(2)-E_(3))=3/4:5/36=27:5`
Discussion
24447.

The ratio of the difference in energy between the first and second Bohr orbits to that between the second and third Bohr orbit is

Answer»

`1//2`
`1//3`
`4//9`
`27//5`

ANSWER :D
Discussion
24448.

The ratio of the difference between the first and second Bohr orbit energies to that between second and third Bohr orbit energies is :-

Answer»

`1/2`
`1/3`
`(27)/(5)`
`(5)/(27)`

ANSWER :C
Discussion
24449.

The ratio of the average speed of an oxygen molecle to the rms speed of a nitrogen molecule at the same temperature is :

Answer»

`((3PI)/(7))^(1/2)`
`((7)/(3pi))^(1/2)`
`((3)/(7pi))^(1/2)`
`((7pi)/(3))^(1/2)`

ANSWER :B
Discussion
24450.

The ratio of the average molecular kinetic energy of UF_6 to that of H_2, both at 300 K is :

Answer»

1:1
7:2
176:1
2:7

Answer :A
Discussion