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26301.

The oxidation state of iron in Fe(CO)_(5) is :

Answer»

`+1`
0
`+3`
`+4`.

Answer :B
26302.

The oxidation state of I in IPO_(4) is

Answer»

`+1`
`+3`
`+5`
`+7`

Solution :Let the OXIDATION number of I in `IPO_(4)=X`
Oxidation number of `PO_(4)=-3`
`x+(-3)=0 IMPLIES x=+3`
26303.

The oxidation state of I inH_4IO_6^- is:

Answer»

`+7
`-1`
`+5`
`+1`

ANSWER :A
26304.

The oxidation state of fluorine can also be + 2. The given statement is true or false?

Answer»

SOLUTION :The OXIDATION state of fluorine cannot also be +2.
26305.

The oxidation state of hydrogen in CaH_2 is :

Answer»

`+1`
`-1`
ZERO
`+2`

ANSWER :B
26306.

The oxidation state of fluorine can also be + 2.

Answer»

Solution :The OXIDATION state of FLUORINE cannot also be +2.
26307.

The oxidation state of final product formed by the reaction between Kl and acidifed potassium dichromate solution is :

Answer»

`+4`
`+6`
`+2`
`+3`

Solution :`Cr_(2)O_(7)^(2-) + 14H^(+) + 6I^(-) to 2Cr^(3+) + 3I_(2) + 7H_(2)O`
oxidation of Cr is + 3 in the final product.
`underset("Calomel")Hg_(2)Cl_(2) + 2NH_(3) to Hg + Hg(NH_(2)) Cl + NH_(4)Cl`
26308.

The oxidation state of Fe in the brown ring complex [Fe(H_(2)O)_5No]SO_(4) is

Answer»

0
`+2`
`+1`
`+3`

Solution :Let the oxidation of Fe in `[Fe(H_(2)O)_(5)NO]^(2+)`be x.
CHARGE of `H_(2)O` and NO is ZERO as both are neutral ligands.
`:.x+0+0=2impliesx=+2`
`:.` Oxidation state of `Fe=+2`.
26309.

The oxidation state of Fe in the brown ring complex [Fe(H_(2)O)_(5)NO]SO_(4) is

Answer»


SOLUTION :`[overset(X)(Fe)overset(0)((H_(2)O)_(5))overset(+1)(NO)]^(2+),x+0+1=+2orx=+1`
26310.

The oxidation state of Cu in [Cu(NH_3)_4]SO_4 is:

Answer»

`-1`
`+1`
`+2`
Zero

Answer :C
26311.

The oxidation state of Fe in Na_3[Fe(NH_3)(CN) _5]2H_2O is:

Answer»

`-1`
`+1`
`+2`
`+3`

ANSWER :C
26312.

The oxidation state of Fe in iron penta carbonyl is:

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ZERO
1
2
2.5

Answer :A
26313.

The oxidation state of Fe in [Fe(CN)_(6)]^(4+) is…………………..

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`II`
`III`
`VI`
`IV`

ANSWER :A
26314.

The oxidation state of Fe in [Fe(NO)(H_(2)O)_(5)]SO_(4) is

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`+1`
`+2`
`+3`
`+4`.

SOLUTION :`x+0+5xx0-2=0 therefore x=+2`
26315.

The oxidation state of Fe in Fe_3O_4 is:

Answer»

`+3`
`+6`
`+8//3`
`+2`

ANSWER :C
26316.

The oxidation state of CrO_(3)

Answer»


SOLUTION :
26317.

The oxidation state of Cr is K_3CrO_8

Answer»


Solution :`K_4CrO_8` contain all oxygens in PEROXIDE LINKAGE, Cr= +5
26318.

Write IUPAC name of [Cr (H_2O)_6]Cl_3.

Answer»


ANSWER :1
26319.

What is the oxidation state of Cr in CrO_5 and why?

Answer»

`+4`
`+5`
`+6`
`+10`

Answer :C
26320.

The oxidation state of Cr in CrO_5 is

Answer»

`+4`
`+6`
`+8`
`+10`

ANSWER :B
26321.

The oxidation state of Cr in [Cr(H_(2)O)_(6)]Cl_(3), [Cr(C_(6)H_(6))_(2)], and K_(2)[Cr(CN)_(2)(O)_(2)(O_(2))(NH_(3))] respectively are :

Answer»

`+3,0 and +6`
`+3,0 and +4`
`+3,+4 and +6`
`+3,+2 and +4`

ANSWER :A
26322.

The oxidation state of Cr in [Cr(NH_(3))_(4)Cl_(2)]^(+) is:

Answer»

0
`+1`
`+2`
`+3`

SOLUTION :`[overset(+3)Cr(NH_(3))_(4)Coverset(-2)l_(2)]^(+)`
26323.

The oxidation state of Cr in Cr(CO)_(6)is

Answer»

0
`+2`
`-2`
`+6`.

ANSWER :A
26324.

The oxidation state of copper changes when aqueous copper (II) ions react with: (I)NaOH(aq)(II)Fe(s)(III)KI(aq)

Answer»

I, II, III
II only
II, III
I only

Answer :C
26325.

The oxidation state of copper is:

Answer»

`+1`
`+1 and +2`
`+2`
`+1, +2 and +3`

ANSWER :B
26326.

The oxidation state of cobalt in [Co(NH_(3))_(5)Cl]^(2+) is…….. .

Answer»


ANSWER :`+3`
26327.

The oxidation state of chromium in the final product obtained when H_(2)O_(2) is treated with acidified K_(2)Cr_(2)O_(7) is …..

Answer»

`+2`
`+3`
`+5`
`+6`

Solution :`K_(2)Cr_(2)O_(7) + 4H_(2)O_(2) + H_(2)SO_(4) rarr UNDERSET((+6))(2CrO_(5)) + K_(2)SO_(4) + 5H_(2)O`
26328.

The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is

Answer»

`+4`
`+6`
`+2`
`+3`

ANSWER :D
26329.

The oxidation state of Chromium in the complex, [Cr(NH_3)_4Cl_2]Cl is

Answer»

`+3`
`+2`
`+1`
`0`

ANSWER :A
26330.

The oxidation state of Cr in [Cr(NH_(3))_(4)Cl_(2)]Cl

Answer»

`+3`
`+2`
`+1`
0

Answer :A
26331.

The oxidation state of chromium in [Cr(PPh_3)_3(CO)] is

Answer»

`+3`
`+8`
5
6

Solution :Sinceboththe ligandsi.e.,`P PH_3`( triphenylphosphine ) andVO areneutraland the complexdoes notcarryanychargethereforeoxidation NUMBEROF Cris ZERO
26332.

The oxidation state of Chromium in CrO_(4)^(2-) and in Cr_(2)O_(7)^(2-) are .................... .

Answer»

`+3, +6`
`+7, +4`
`+6, +6`
`+4, +6`

SOLUTION :`+6, +6`
26333.

The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be. . . . . . . ..

Answer»

`+3`
`+5`
`+1`
`-3`

Solution :OXIDATION state of CENTRAL ATOM (P) in `(H_2PO_2^(-))` is + 1
26334.

The oxidation state of chlorine is highest in the compound

Answer»

`Cl_(2)O_(7)`
HCL
`Cl_(2)O`
`Cl_(2)O_6`

ANSWER :A
26335.

The oxidation state of central atom in the anion of compound NaH_2PO_2 will be

Answer»

`+3`
`+5`
`+1`
`-3`

Solution :Oxidation STATE of CENTRAL atom (P) in `(H_2PO_2^(-))` is + 1
26336.

The oxidation state of central atom in the anion of compound NaH_2PO_2 will be ...........

Answer»

`+3`
`+5`
`+1`
`-3`

ANSWER :C
26337.

The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be _________.

Answer»

`+3`
`+5`
`+1`
`-3`

SOLUTION :`NaH_(2)PO_(2)`
`+1+2xx(+1)+x+2(-2)=0 ""therefore""x=+1`
26338.

The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be ......... .

Answer»

`+3`
`+5`
`+1`
`-3`

Solution :`overset(+1)(NA)overset(+1)((H))_(2)overset(X)(P)overset(-2)(O)_(2)"Here", (+1) + 2(+1) + x + 2(-2) = 0, i.e., x = + 1`
26339.

The oxidation state of bromine inBrO_2 and HBrO_3 are ....... and ...... respectively.

Answer»

SOLUTION :`+4,+5`,
26340.

The oxidation state of Al in cryolite

Answer»


Solution :CRYOLITE is `Na_(3)AlF_(6)` . In Cryolite Oxidation state of AL is +3
26341.

The oxidation state of Ag in Tollen’s reagent is:

Answer»

ZERO
`+1`
`+2`
`+1.5`

ANSWER :B
26342.

The oxidation state of +3 for phosphorous is in :

Answer»

Hyprophosporous acid
Meta-Phosphoric acid
Ortho-phosphoric acid
Phosphorous acid

Answer :D
26343.

The oxidation product of 2-propanol with hot conc. HNO_(3) is

Answer»

ETHANOIC acid
Propanone
Propanal
None of these

Answer :B
26344.

The oxidation potential of Zn, Mg , Ni and Cu are -0.76 V, 2.37V, 0.25V and -0.34V respectively. What will not be liberating H_(2) from HCl /

Answer»

Zn
Ni
Mg
Cu

Answer :D
26345.

The oxidation potentials of A and B are +2.37 and +1.66 V respectively . In chemical reactions

Answer»

A will be replaced by B
A will REPLACE B
A will not replace B
A and B will not replace each other .

Solution :Greater the oxidation POTENTIAL , more is the REACTIVITY .
26346.

The oxidationpotential values of A,B,C and D are -0.03 V + 0.18 V-0.07and +0.1 v respecitively thenon spontaneous cell reaction takes place between

Answer»

A and B
B an D
D and A
B and C

Solution :(i) The electrodewith higheroxidation potential acts as anodeand electrode withloweroxidationpitentialacts as cathode
(ii) CELL REACTION is spontaneous when `E_(Cell)` is POSTIVE
`E_(Cell)=E_(C )-E_(A)`
Givenoxidation potentialof A =- 0.03 V
oxidation potential of B= + 0.108 V
oxidation potential of C= 0.07 V
oxidation potentialof D =+ 0.1 V
`because` oxidationpotentialof Bis more than A
`therefore` oxidation of A is not possible
`therefore` Thus CEL having A as andoe and B as cathode is not possible
26347.

The oxidation potential of two metals X and Y are +2.37 and +1.66 V respectively. In a chemical reaction:

Answer»

X will be REPLACED by Y
X will REPLACE Y
X will not replace Y
X and Y will not replace each other

Answer :B
26348.

The oxidation potential of Mg and Al are +2.37 and +1.66 volts respectively . The Mg in chemical reactions

Answer»

will be REPLACED by Al
will replace Al
will not be able to replace Al
NONE of these

SOLUTION :Mg is more reaction than Al.
26349.

The oxidation potential of Mg and Al are +2.37 and +1.66 volt respectively. The Mg in chemical reactions :

Answer»

Will be REPLACED by Al
Will REPLACE Al
Will not be ABLE to replace Al
None of these

Answer :B
26350.

The oxidation potential of hydrogen half-cell will be negative if :

Answer»

`p(H_2) =1 ATM and [H^+] = 1M`
`p(H_2)= 1 atmand [H^(+)] = 2M`
`p(H_2) = 0.2 atm and [H^(+)] = 1M`
`p(H_2) = 0.2 atm and [H^(+)]=0.2 M`

SOLUTION :`E_(RP) = E_(0)^(0) -(0.0591)/(2) log""(PH_2)/((H^(oplus))^(2)) , 2H^(oplus) + 2e^(-) IMPLIES H_2`
` -E _(OP)= + (0.0591)/(2) log""((H^(oplus))/(P_(H_2)))`
a) `E_(RP )= -E(OP) = 0 ` b) `E_(RP) = -E_(OP) = +ve ` c) `E_(RP) = -E_(OP) = +ve` d) `E_(RP) = -E_(OP) = -ve`