This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 26302. |
The oxidation state of I in IPO_(4) is |
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Answer» `+1` Oxidation number of `PO_(4)=-3` `x+(-3)=0 IMPLIES x=+3` |
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| 26304. |
The oxidation state of fluorine can also be + 2. The given statement is true or false? |
| Answer» SOLUTION :The OXIDATION state of fluorine cannot also be +2. | |
| 26306. |
The oxidation state of fluorine can also be + 2. |
| Answer» Solution :The OXIDATION state of FLUORINE cannot also be +2. | |
| 26307. |
The oxidation state of final product formed by the reaction between Kl and acidifed potassium dichromate solution is : |
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Answer» Solution :`Cr_(2)O_(7)^(2-) + 14H^(+) + 6I^(-) to 2Cr^(3+) + 3I_(2) + 7H_(2)O` oxidation of Cr is + 3 in the final product. `underset("Calomel")Hg_(2)Cl_(2) + 2NH_(3) to Hg + Hg(NH_(2)) Cl + NH_(4)Cl` |
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| 26308. |
The oxidation state of Fe in the brown ring complex [Fe(H_(2)O)_5No]SO_(4) is |
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Answer» 0 CHARGE of `H_(2)O` and NO is ZERO as both are neutral ligands. `:.x+0+0=2impliesx=+2` `:.` Oxidation state of `Fe=+2`. |
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| 26309. |
The oxidation state of Fe in the brown ring complex [Fe(H_(2)O)_(5)NO]SO_(4) is |
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Answer» |
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| 26312. |
The oxidation state of Fe in iron penta carbonyl is: |
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Answer» ZERO |
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| 26313. |
The oxidation state of Fe in [Fe(CN)_(6)]^(4+) is………………….. |
| Answer» ANSWER :A | |
| 26314. |
The oxidation state of Fe in [Fe(NO)(H_(2)O)_(5)]SO_(4) is |
| Answer» SOLUTION :`x+0+5xx0-2=0 therefore x=+2` | |
| 26316. |
The oxidation state of CrO_(3) |
Answer»
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| 26317. |
The oxidation state of Cr is K_3CrO_8 |
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Answer» |
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| 26321. |
The oxidation state of Cr in [Cr(H_(2)O)_(6)]Cl_(3), [Cr(C_(6)H_(6))_(2)], and K_(2)[Cr(CN)_(2)(O)_(2)(O_(2))(NH_(3))] respectively are : |
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Answer» `+3,0 and +6` |
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| 26322. |
The oxidation state of Cr in [Cr(NH_(3))_(4)Cl_(2)]^(+) is: |
| Answer» SOLUTION :`[overset(+3)Cr(NH_(3))_(4)Coverset(-2)l_(2)]^(+)` | |
| 26324. |
The oxidation state of copper changes when aqueous copper (II) ions react with: (I)NaOH(aq)(II)Fe(s)(III)KI(aq) |
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Answer» I, II, III |
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| 26327. |
The oxidation state of chromium in the final product obtained when H_(2)O_(2) is treated with acidified K_(2)Cr_(2)O_(7) is ….. |
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Answer» `+2` |
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| 26328. |
The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is |
| Answer» ANSWER :D | |
| 26329. |
The oxidation state of Chromium in the complex, [Cr(NH_3)_4Cl_2]Cl is |
| Answer» ANSWER :A | |
| 26331. |
The oxidation state of chromium in [Cr(PPh_3)_3(CO)] is |
| Answer» Solution :Sinceboththe ligandsi.e.,`P PH_3`( triphenylphosphine ) andVO areneutraland the complexdoes notcarryanychargethereforeoxidation NUMBEROF Cris ZERO | |
| 26332. |
The oxidation state of Chromium in CrO_(4)^(2-) and in Cr_(2)O_(7)^(2-) are .................... . |
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Answer» `+3, +6` |
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| 26333. |
The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be. . . . . . . .. |
| Answer» Solution :OXIDATION state of CENTRAL ATOM (P) in `(H_2PO_2^(-))` is + 1 | |
| 26334. |
The oxidation state of chlorine is highest in the compound |
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Answer» `Cl_(2)O_(7)` |
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| 26335. |
The oxidation state of central atom in the anion of compound NaH_2PO_2 will be |
| Answer» Solution :Oxidation STATE of CENTRAL atom (P) in `(H_2PO_2^(-))` is + 1 | |
| 26336. |
The oxidation state of central atom in the anion of compound NaH_2PO_2 will be ........... |
| Answer» ANSWER :C | |
| 26337. |
The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be _________. |
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Answer» SOLUTION :`NaH_(2)PO_(2)` `+1+2xx(+1)+x+2(-2)=0 ""therefore""x=+1` |
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| 26338. |
The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be ......... . |
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Answer» `+3` |
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| 26339. |
The oxidation state of bromine inBrO_2 and HBrO_3 are ....... and ...... respectively. |
| Answer» SOLUTION :`+4,+5`, | |
| 26340. |
The oxidation state of Al in cryolite |
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Answer» |
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| 26342. |
The oxidation state of +3 for phosphorous is in : |
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Answer» Hyprophosporous acid |
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| 26343. |
The oxidation product of 2-propanol with hot conc. HNO_(3) is |
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Answer» ETHANOIC acid |
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| 26344. |
The oxidation potential of Zn, Mg , Ni and Cu are -0.76 V, 2.37V, 0.25V and -0.34V respectively. What will not be liberating H_(2) from HCl / |
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Answer» Zn |
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| 26345. |
The oxidation potentials of A and B are +2.37 and +1.66 V respectively . In chemical reactions |
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Answer» A will be replaced by B |
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| 26346. |
The oxidationpotential values of A,B,C and D are -0.03 V + 0.18 V-0.07and +0.1 v respecitively thenon spontaneous cell reaction takes place between |
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Answer» A and B (ii) CELL REACTION is spontaneous when `E_(Cell)` is POSTIVE `E_(Cell)=E_(C )-E_(A)` Givenoxidation potentialof A =- 0.03 V oxidation potential of B= + 0.108 V oxidation potential of C= 0.07 V oxidation potentialof D =+ 0.1 V `because` oxidationpotentialof Bis more than A `therefore` oxidation of A is not possible `therefore` Thus CEL having A as andoe and B as cathode is not possible |
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| 26347. |
The oxidation potential of two metals X and Y are +2.37 and +1.66 V respectively. In a chemical reaction: |
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Answer» X will be REPLACED by Y |
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| 26348. |
The oxidation potential of Mg and Al are +2.37 and +1.66 volts respectively . The Mg in chemical reactions |
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Answer» will be REPLACED by Al |
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| 26349. |
The oxidation potential of Mg and Al are +2.37 and +1.66 volt respectively. The Mg in chemical reactions : |
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Answer» Will be REPLACED by Al |
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| 26350. |
The oxidation potential of hydrogen half-cell will be negative if : |
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Answer» `p(H_2) =1 ATM and [H^+] = 1M` ` -E _(OP)= + (0.0591)/(2) log""((H^(oplus))/(P_(H_2)))` a) `E_(RP )= -E(OP) = 0 ` b) `E_(RP) = -E_(OP) = +ve ` c) `E_(RP) = -E_(OP) = +ve` d) `E_(RP) = -E_(OP) = -ve` |
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