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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 26401. |
The oxidation number of Mn in the product of alkaline oxidative fusion ofMnO_2 is ..... |
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Answer» |
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| 26402. |
The oxidation number of metal atom is (are)zero in : |
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Answer» `[Ni(CO)_(4)]` |
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| 26404. |
The oxidation number of iorn in [Fe(CO_(3))(pi-C_(4)H_(4)] is: |
| Answer» Solution :`[OVERSET(+2)Fe(Coverset(0)O)_(3)(pi-C_(4)overset(-2)H_(4))]` | |
| 26407. |
The oxidation number of Fe in [Fe(CN)_6]^(4-)Cr in [Cr(NH_3)_3(NO_2)_3] and Ni in Ni(CO)_4 are respectively |
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Answer» 0,+3,+2 |
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| 26408. |
The oxidation number of Fe in brown ring [Fe(H_(2)O)_(5)NO]^(2+) is |
| Answer» Answer :B | |
| 26409. |
The oxidation state of Cr in the complex [Cr(H_2O)_4Cl_2]^+ is _____ |
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Answer» 1 |
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| 26410. |
The oxidation number of cobalt in the complex:(i) K[Co(CO)_(4)] (ii)[Co(C_(2)O_(4))_(3)]^(-3) |
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Answer» SOLUTION :(i) -1 (II)+3 |
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| 26411. |
The oxidation number of cobalt in K[Co(CO)_(4)] is |
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Answer» `+1` x + 0 = - 1 or x = -1 Hence, (III) is the CORRECT option. |
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| 26412. |
The oxidation number of cobalt in K[Co(CO)_4] is : (i) + 1 (ii) + 3 (iii)-1 (vi) - 3 |
| Answer» SOLUTION :`+1+X+4xx0=0 "" THEREFORE x = -1`. | |
| 26415. |
The oxidation number of 'Co' in the complex K[Co(CO)4] is _____ |
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Answer» 1 |
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| 26417. |
The oxidation number of Ba in barium peroxide is |
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Answer» `+6` |
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| 26418. |
the oxidation number of C in CO_(2) is |
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Answer» `-2` `x+2(-2)=0, x-4=0, x=+4`. |
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| 26421. |
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Whichof the following rules is not correct in this respect? |
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Answer» 1. The oxidation number of hydrogen is always +1. |
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| 26422. |
The oxidation number is changed in which of the following case? |
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Answer» `SO_(2)` GAS is passed into `Cr_(2)O_(7)^(2-)//H^(+)` |
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| 26423. |
The oxidation number and the electronic configuration of sulphur in H_(2)SO_(4) is |
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Answer» `+3, 1S^(2) 2s^(2) 2P^(6) 3s^(2) 3p^(1)` `2 + x -2 xx 4= 0 rArr 2 + x - 8 = 0 rArr x6 " " :.` Oxidation No. 6, Electronic configuration is `2s^(2) 2p^(6)` Oxidation state = +6 |
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| 26424. |
The oxidation number and covalency of sup,phur in the sulphur molecule (S_8) are respectively : |
| Answer» Answer :A | |
| 26427. |
The oxidation number of cobalt in K[Co(CO)_4] is |
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Answer» 1 |
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| 26429. |
The oxidation electrode potential E, of a 0.1 M solution ofM^(+) ions (E_(RP)^(o) = - 2.36 V) is : |
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Answer» `-2.41`V |
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| 26430. |
The oxidant which is used as an antiseptic is |
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Answer» `KBrO_3` |
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| 26432. |
The overlapping of orbitals in benzene is of the type |
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Answer» `SP^(2)-sp^(2)`  Each `p_(z)` orbital interacts equally with its two neighbours procucing a circular double - doughnut shaped molecular orbital embracing all six carbon atoms and thus six `pi` - electrons are delocalized. |
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| 26433. |
The overlapping in benzene involves: |
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Answer» sp-p |
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| 26434. |
The overlapping involved in HF molecule is |
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Answer» s-s |
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| 26435. |
The overall reaction that takes place in an electrochemical cell is |
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Answer» oxidation |
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| 26436. |
The overlapping ability is maximum in case of : |
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Answer» `sp^3` -HYBRID ORBITAL |
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| 26437. |
The overall reaction taking place at anode duringelectrolysis of fused sodiumusing suitable electrode is |
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Answer» OXIDATION of CHLORIDE `NaCI rarr Na^(+) +CI^(-)` oxidation`Na rarr Na^(+) +e^(-)` Reduction`CI rarr CI^(-) - e^(-)` and oxidation takes place at anode |
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| 26438. |
The overall order of the reaction 2NO_((g))+O_(2(g))rarr2NO_(2(g)) is .......... |
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Answer» 2 |
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| 26439. |
The overall reaction taking place at anode during electrolysis of fused sodium chloride using suitable electrode is |
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Answer» Oxidation of Chlorineions `NaCl to Na^(+)+ Cl^(-)` At CATHODE `(-Ve)` `2Na + 2e^(-) to 2Na` (Reduction) At anode `(+Ve)`: `2Cl^(-) to Cl_(2) + 2e^(-)` (Oxidation) |
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| 26440. |
The overall order of the reaction 5Br^(-)+BrO_3^(-)+6H^(+) is .......... |
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Answer» 4 |
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| 26441. |
The overall order of decomposition of acetaldehyde to methane and carbon monoxide rate law is called........... |
| Answer» SOLUTION :3/2 or 1.5 | |
| 26442. |
The overall molecularity of the reaction 2H_2O_(2(aq))overset(I^-)rarr2H_2Ol_((l))+O_(2(g)) is ............. |
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Answer» UNIMOLECULAR |
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| 26443. |
The overall formation constant of the following reaction is 1 xx 10^(19) Co^(+2) +6CN^(-) Leftrightarrow [Co(CN)_(6)]^(-3) Calculate formation constant of following comples Co^(+3) +6CN^(-) Leftrightarrow[Co(CN)_(6)]^(-3) Given that [Co(CN)_(6)]^(-4) to [Co(CN)_(6)]^(-3) +e^(-), E^(0)=-0.83V Co^(+3) +e^(-) to Co^(+2), E^(0)=1.82 V |
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Answer» SOLUTION :`CO^(+2) +6CN^(-) Leftrightarrow [Co(CN)_(6)]^(-4)` `K_(1)=([Co(CN)_(6)]^(-4))/([Co^(+2)][CN^(-)]^(6))` And `Co^(+#) +6CN^(-) Leftrightarrow [Co(CN)_(6)]^(-3)` `K_(2)=([Co(CN)_(6)]^(-3))/([Co^(+3)] [CN^(-6)]^(6))` `K_(2)/K_(1) =([Co(CN)_(6)]^(-3) [Co^(+2)])/([Co(CN)_(6)]^(-4) [Co^(+3)])` `[Co(CN)_(6)]^(-4) to [Co(CN)_(6)]^(-3)+e^(-)""E^(@)=-0.83V` `Co^(+3)+e^(-) to Co^(+2) ""E^(@)=1.82V` Net cell REACTION `Co^(+3) +[Co(CN)_(6)]^(-4) to Co^(+2) +[Co(CN)_(6)]^(-3)""E_("Cell")^(@)=0.99V` at equilibrium `E_("cell")=0` `E_("cell")^(@)=(0.0591)/(N) log K_(EQ)` `0.99=(0.0591)/(1) log ([Co^(2+)] [Co(CN)_(6)]^(-3))/([Co^(+3)] [Co(CN)_(6)]^(-4))=(0.059)/(1) log ""K_(2)/K_(1)` `K_(2)/K_(1)=5.64 xx 10^(16)=K_(2)/10^(19) =8.23 xx 10^(44)` `K_(2)=8.23 xx 10^(63)` |
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| 26444. |
The overall equation for the reaction between sodium carbonate solution and dilute hydrochloric acid is Na_(2)CO_(3)(aq.)+2HCl(aq.)rarrNaCl(aq)+CO_(2)(g)H_(2)O(l) If you had the two solutions of the same concentration, you would have to use double volume of HCl to reach the equivalence point. Indicators change their colours at the end point of the reaction and hence we are able to know the end points (equivalence points of reactions). 25 ml of Na_(2)CO_(3) solution requires 100 ml of 0.1 M HCl to reach end point with phenolphthaleinindicator. Molarity of HCO_(3^(-)) ions in the resulting solution is |
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Answer» 0.008 M EQUIVALENTS of HCl = Equivalent of `Na_(2)CO_(3)` `N_(1)V_(1)=N_(2)V_(2)` For HCl `N_(1)=M_(1) ` and `Na_(2)CO_(3)N_(2)=N_(2)M_(1)V_(1)=M_(2)V_(2)` `0.1 xx 100 = N_(2)xx25` `M_(2)=0.4` Reaction is `Na_(2)CO_(3) +HCl rarrNaHCO_(3)+NaCl` in moles of `Na_(2)CO_(3)=MV` `0.4 018xx25xx10^(-3)` =moles of `NaCHO_(3)` molarity of `HCO_(3)^(-)=("Moles of " NaHCO_(3))/("Volume")=(0.4xx25xx10^(-3)xx1000)/(125)=0.08` |
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| 26445. |
The overall equation for the reaction between sodium carbonate solution and dilute hydrochloric acid is Na_(2)CO_(3)(aq.)+2HCl(aq.)rarrNaCl(aq)+CO_(2)(g)H_(2)O(l) If you had the two solutions of the same concentration, you would have to use double volume of HCl to reach the equivalence point. Indicators change their colours at the end point of the reaction and hence we are able to know the end points (equivalence points of reactions). How many ml of 1N HCl are required for X milimoles of NaOH + Y milimoles of Na_(2)CO_(3)+Z milimoles of NaHCO_(3)with methyl orange indicator |
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Answer» (2X+Y+Z)ML `1xxV=[x xx10^(-3)xx1]+[Yxx10^(-3)xx2]+[Zxx10^(-3)xx1]` `V=[x +2Y+Z]xx10^(-3)L` `V=[X+2Y+Z]ml` |
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| 26446. |
The overall formaion constant for the reaction of 6 mole of CN^(-) with cobalt (II) is 1xx10^(19) the standard reduction potential constant of [Co(CN)_(6)]^(3-)+e^(-)toCo(CN)_(6)^(4-) is -0.83V Calcualte the formation constant of [Co(CN)_(6)]^(3-). Given Co^(3+)+e^(-)toCo^(2+),E^(@)=1.82V |
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Answer» cathode: `Co^(3+)+e^(-)toCO^(2+)""E_(SRP)^(0)=1.82V` so overall cell reaction is `Co^(3+)+[Co(CN)_(6)]^(4-)toCO^(2+)+[Co(CN)_(6)]^(3-)` `E_(cell)^(0)=E_(C)^(0)-E_(a)^(0)=1.82-(-0.83)=2.65V` `E_(cell)=E_(cell)^(0)-(0.059)/(1)log(([Co^(2+)][Co(CN)_(6)]^(3-))/([Co^(3+)][Co(CN)_(6)]^(4-)))` Now, `Co^(2+)+6CN^(-)hArr[Co(CN)_(6)]^(4-)""K_(f_(1))=1xx10^(19)` `Co^(3+)+6CN^(-)hArr[Co(CN)_(6)]^(3-)""K_(f_(2))` At equilibrium `E_(cell)=0` `E_(cell)^(0)=(0.059)/(1)log((k_(f_(2)))/(K_(f_(1)))`, solving we get `K_(1)=10^(63.915)` |
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| 26447. |
The overall formation constant for the reacction of 6 mol of CN^- with cobalt (II) is 1xx10^(19). The stadard reduction potential for the reaction. [Co(CN)_6]^(3-)+e^-to Co(CN)_6^(4-) is -0.83V. Calculate the formation constant of [Co(CN)_6]^(3+) Given Co^(3+)+e^-to Co^(2+),E^0=1.82V |
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Answer» |
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| 26448. |
The overall equation for the reaction between sodium carbonate solution and dilute hydrochloric acid is Na_(2)CO_(3)(aq.)+2HCl(aq.)rarrNaCl(aq)+CO_(2)(g)H_(2)O(l) If you had the two solutions of the same concentration, you would have to use double volume of HCl to reach the equivalence point. Indicators change their colours at the end point of the reaction and hence we are able to know the end points (equivalence points of reactions). How many ml of 1N HCl are requiredfor X milimoles of Na_(2)CO_(3) with methyl orange indicator |
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Answer» X ml Equivalent of HCl = Equivalent of `Na_(2)CO_(3)` NV=mole `xx`V.F 1 V `=x xx10^(-3)xx2` `V=2x xx10^(-3)L=2x ml` |
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| 26449. |
The outermost shell electronic configuration 3d^5,4s^2 represents : |
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Answer» CA |
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| 26450. |
The outermost shell electronic configuration 3d^(5), 4s^(2) represents |
| Answer» Answer :B | |