94420 + Interview Questions in Chemistry in Class 12 Page 530 InterviewSolution

26451.	The outermost electronic configuration of the most electronegative element is
Answer» `3s^(2)3p^(5)` `6s^(1)` `2S^(2)2P^(5)` `2s^(2)2p^(4)` ANSWER :C

Discussion

26452.	The outer electronic configuration of 15 group
Answer» `ns^2 np^1` `ns^2 np^2` `ns^2 np^3` `ns^2 np^4` ANSWER :C

Discussion

26453.	The outermost electronic confi-guration of transition metal is
Answer» `ns^2np^3` `ns^2np^6` `ns^2np^5` `(n-1)d^(1-10)ns^2` ANSWER :D

Discussion

26454.	The outer shell of an egg was dissolved in hydrochloric acid and than placed in concentrated NaCI solution. Which one of the following will happen ?
Answer» The egg will swell The egg will shrink Nothing will happen to the egg The INSIDE of the egg will BECOME SALTISH . SOLUTION :Endoosmosis

Discussion

26455.	The outermost electron is most loosely held in:
Answer» Li Na K Cs Answer :D

Discussion

26456.	The outer shell electronic configuration of palladium (Z=46) is
Answer» `4d^(8)5s^(2)` `4d^(9)5s^(2)` `4d^(10) 5s^(0)` `4d^(2)5s^(2)5P^(6)` Solution :`15200cm^(-1)(Z^(2))=15200xx(3)^(2) ` `=136800cm^(-1)`

Discussion

26457.	The outermost elecronic configuration of most electronegative element is :
Answer» `ns^2np^3` `ns^2np^4` `ns^2np^5` `ns^2np^6` ANSWER :C

Discussion

26458.	The outer electronic configurations of two transition metals are (i) 3d^(5)4s^(2) and (ii) 3d^(6)4s^(2) respectively. Based on this information predict the relative stability of +2 and +3 oxidation state of these metals. Which of the two exhibits larger number of oxidation states ?
Answer» Solution :Metal with configuration `3d^(5)4s^(2)` will show oxidation state (+2) more readily because of greater STABILITY of half-filled d-orbitals. Metal with configuration `3d^(6)4s^(2)` will be more stable in +3 oxidation state than +2 due because after losing two ELECTRONS the configuration of the metal ION will be `3d^(5)`, which is a stable configuration.

Discussion

26459.	The outer electronic configuration of two members of the lanthanoid series are as follows : 4f^(1) 5d^(1) 6s^(2) and 4f^(7) 5d^(-) 6s^(2) What are their atomic numbers ? Predict the oxidation states exhibited by these elements in their compounds.
Answer» Solution :Complte E.C. of 1ST lanthanoid `= [Xe]^(54) 4f^(1) 5d^(1) 6 s^(1) `. Atomic No. ` = 58 (C e) ` COMPLETE E.C. of 2nd lanthanoid `= [ Xe]^(54) 4f^(7) 5d^(0) 6s^(2)` . Atomic No. `=63 (E u)` OXIDATIO states of 1st lanthanoid `= + 2 ( 4f^(2)) , + 3( 4f^(1)) , + 4 ( 4f^(0))` Oxidation states of 2nd lanthanoid ` = +2 (4f^(7)) ` and `+ 3 ( 4f^(6))`

Discussion

26460.	The outer shell configuration of a halide ion is
Answer» `ns^2` `ns^2 np^6` `ns^2 np^5` `ns^2 np^4` ANSWER :B

Discussion

26461.	The outer electronic structure of lawrencium (atomic number 103) is:
Answer» `Rn5f^(13)7S^(2)7p^(2)` `Rnf^(13)6d^(1)7s^(1)7p^(2)` `Rn5f^(14)7s^(1)7p^(1)` `Rn5f^(14)6d^(1)7s^(2)` Answer :D

Discussion

26462.	The outer electronic configuration of Gd (Atomic No:64) is :
Answer» `4F^(4) 5D^(4) 6s^(2)` `4f^(7) 5d^(1) 6s^(2)` `4f^(3) 5d^(5) 6s^(2)` `4f^(6)5d^(0) 6s^(2)` Solution :`Gd : [Xe] 4f^(7) 5d^(1) 6s^(2)`

Discussion

26463.	The outer electronic configuration of Gd (Atomic no. 64) is…..
Answer» `4f^(3) 5D^(5) 6s^(2)` `4f^(6) 5d^(0) 6s^(2)` `4f^(4) 5d^(4) 6s^(2)` `4f^(7) 5d^(1) 6s^(2)` ANSWER :D

Discussion

26464.	The outer electronic configuration of alkaline earth metal is
Answer» `ns^(2)` `ns^(1)` `NP^(6)` `ND^(10)` ANSWER :A

Discussion

26465.	The outer elecftronic configuration of plutonium in +6 oxidatino state is
Answer» `7S^(0), 5F^(5), 6d^(0)` `7s^(0), 5f^(1), 6d^(0)` `7s^(0), 5f^(2), 6d^(0)` `7s^(0), 5f^(4), 6d^(0)` ANSWER :C

Discussion

26466.	The other name of 1, 2, 3-trihydroxy benzene is …………………….. .
Answer» SOLUTION :PYROGALLOL

Discussion

26467.	The Ostwald process is the main method for the manufacture of nitric acid. In the first step in this process
Answer» nitrogen and HYDROGEN REACT to FORM `NH3` ammonia is BURNED in `O_2` to generate `N_2 and H_2O` nitrogen and OXYGEN react to form `NO_2` ammonia is burned with `O_2` to generate `NO and H_(2)O` Answer :D

Discussion

26468.	The othernameof glucose is ………. .
Answer» DEXTROSE BLOOD sugar aldohexoe all the above ANSWER :D

Discussion

26469.	The other name of fructoseis ………… .
Answer» KETOHEXOSE FRUIT SUGAR LEVULOSE all the above ANSWER :D

Discussion

26470.	The number of signiicant figures in piare
Answer» 1 2 3 infinite Answer :D

Discussion

26471.	The other name of 3,5-dihydroxy toluene is known as …………………. .
Answer» ORCINOL QUINOL PYROGALLOL RESORCINOL SOLUTION :Orcinol

Discussion

26472.	The other name of 1,2,3-trihydroxy benzene is called ……………………. .
Answer» Pholoroglucinol QUINOL PYROGALLOL HYDROXY quinol SOLUTION :Pyrogallol

Discussion

26473.	The number of silver atoms present in a 90% pure silver wire weighing 10 g is :
Answer» `5.57 xx 10^22` `0.62 xx 10^23` `5.0 xx 10^22` `6.2 xx 10^29` Solution :Amount of PURE SILVER in 10g wire ` = 10 xx 90/100 = 9g ` 108 g of Ag contain ATOMS =`6 xx 10^23` 9g of Ag contain atoms ` = (6 xx 10^23)/(108) xx 9= 5 xx 10^22`

Discussion

26474.	The osmotic presure of a urea solution is 500 mm of Hg at 10^(@)C. The solution is diluted and its temperature is reised to 25^(@)C. It is now found that the osmotic pressure of the solution is reduced to 105.3 mm. Detyermine the extrant of dilution of the solution.
Answer» Solution :According to Van't Hoff equation for dilute solution. `piV=n_(B)RT or pi=(n_(B)RT)/V` `At 10^(@)C:""pi=((500MM))/((750mm))xx(1"atm")=500/760"atm",T=10+273=233=283 K` `(500/760"atm")=(n_(B)xxRxx283K)/V` `At20^(@)C:""pi=(10.5.3mm)/(760mm)xx1(atm)=105.3/760("atm"),T=20+273=293K` `((105.3)/760"atm")=(n_(B)xxRxx293K)/V'` `"Dividing eqn. (i) by eqn.(II),"(500/760"atm")xx(760/105.3"atm"^(-1))=((283K))/Vxx(V')/((293K)` `(V')/V=500/105.3xx((293K))/((283K))=4.92~~5.` V'=5V This means that the solution has been diluted five times.

Discussion

26475.	The number of significant zeros in 0.001010 is :
Answer» two three four one ANSWER :A

Discussion

26476.	The osmotic pressure (pi) of a solution is given by reation
Answer» <P>`pi = (RT)/C` `pi = (CT)/R` `pi = (RC)/T` `pi/C =RT` Solution :PV = N RT `:. P = n/v RT = CRT.`

Discussion

26477.	The number of significant figures present in 0.0200 is ………………whereas number of significant figures in a dozen (12) is………………… .
Answer» SOLUTION :3, INFINITE

Discussion

26478.	The osmotic pressure (P) of a solution is given by relation:
Answer» <P>`P= (RT)/( C ) ` `P= (CT)/( R ) ` `P= (RC)/( T ) ` `(P) / ( C )= RT` Answer :D

Discussion

26479.	The osmotic pressure of which solution is maximum (consider that deci-molar solution of each 90% dissociated)
Answer» Aluminium sulphate Barium chloride Sodium sulphate A MIXTURE of equal VOLUMES of (b) and (c ) Solution :`Al_(2)(SO_(4))_(3)` gives maximum osmotic PRESSURE because it gives 5 IONS.

Discussion

26480.	The number of significant figures in piare:
Answer» three Infinite number zero one Answer :B

Discussion

26481.	The osmotic pressure of which solution is maximum ( consider that deci-molar solution of each 90% dissociated )
Answer» Aluminium sulphate Barium chloride Sodium Sulphate A MIXTURE of equal volumes of ( B ) and ( c ) Solution :`Al_(2)(SO_(4))_(3) rarr2Al^(+++) +3SO_(4)^(--) ` ( 5 particles ) `BaCl_(2) rarr BA^(++) +2Cl^(-) ` ( 3 particles ) `Na_(2) SO(4) rarr 2Na^(+) +SO_(4)^(--) ` ( 3 particles ) A mixture of equal volumes.

Discussion

26482.	The number of significant figures in the final answer of : (( 16.8 -14.2) ( 6.023 xx 10^(23)))/(2.76)is :
Answer» 2 3 1 4 Answer :A

Discussion

26483.	The osmotic pressure of the solution obtained by mixing 200 "cm"^3 of 2% (mass-volume) solution of urea with 200 "cm"^3 of 3.42% solution of sucrose at 20^@C is
Answer» 4 BAR 1.2 bar 5.2 bar 2.60 bar ANSWER :C

Discussion

26484.	The number of significant figures in 6.02xx10^(23) is
Answer» 23 3 4 26 Answer :B

Discussion

26485.	The Osmotic pressure of solution containing 4.0g of solute (molar mass 246) per litre at 27^@C is (R = 0.082L atm "k"^(-1) "mol"^(-1))
Answer» `0.1 ATM` `0.2 atm` `0.4 atm` `0.8 atm` ANSWER :C

Discussion

26486.	The osmotic pressure of equimolar solutions of glucose, KCI, MgC12 follows the order
Answer» `MgCl_2 GT KCI gt GLUCOSE` `Glucose gt KCI gt MgCl_2` `KCI gt MgCl_2 gt Glucose` `MgCl_2 gt Glucose gtKCl` ANSWER :A

Discussion

26487.	The number of significant figures for the three numbers 161 cm, 0.161 cm, 0.0161 cm are
Answer» 3, 4 and 5 respectively 3, 4 and 4 respectively 3, 3 and 4 respectively 3, 3 and 3 respectively Solution :We know that all non-zero digits are significant and the ZEROS at the beginning of a number are not significant. THEREFORE number 161 cm, 0.161 cm and 0.0161 cm have 3, 3 and 3 significant FIGURES respectively.

Discussion

26488.	The osmotic pressure of equimolar solutions of glucose, sodium chloride and barium chloride will be in the order :
Answer» `BaCl_(2) GT NaCl gt ` glucose `BaCl_(2) gt` glucose `gt` NaCl Glucose `gt BaCl_(2) gt NaCl` `NaCl gt BaCl_(2) gt` glucose Solution :Osmotic PRESSURE DEPENDS upon the number of particles given by solute. Glucose remains undissociated, SODIUM chloride gives `(NA^(+)+Cl^(-))^(2)` mole particlesper mole and barium chloride gives `(Ba^(2+), 2Cl^(-))`3 mole particles pre mole. Therefore, correct order is A.

Discussion

26489.	The osmotic pressure of equimolar solutions of following solutes have been measured. Which of these show minimum osmotic pressure ?
Answer» `MgCl_(2)` KCL `(NH_(4))_(3)PO_(4)` Sucrose SOLUTION :Sucrose does not ionize in solution.

Discussion

26490.	The number of significant figures in 1.00 xx 10^6 is:
Answer» one three eight eleven ANSWER :B

Discussion

26491.	The osmotic pressure of equimolar solutions of BaCl_2, NaCl and glucose follow the order:
Answer» `BaCl_2` > NACL > GLUCOSE Glucose > NaCl > `BaCl_2` NaCl > `BaCl_2` > glucose NaCl > glucose > `BaCl_2` ANSWER :A

Discussion

26492.	The number of significant figures in (0.04)^2 + (0.25)^2is :
Answer» one two three four Solution :`(0.04)^2+ (0.25)^2 = 0.0016 + 0.0625 = 2 XX 10^(-3) + 62 + 10^(-3)` (up to correct significant figures) ` = 64 xx 10^(-3)` Number of significant figures = 2

Discussion

26493.	The osmotic pressure of decimolar solution of glucose at 30^(@)C is :
Answer» 24.88 atm 2.488 atm 248.8 atm 2488 atm Solution :`C.RT = 0.1 XX 0.082 xx 303 = 2.488`

Discussion

26494.	The osmotic pressure of decimolar solution of glucose at 30^@C is:
Answer» 24.88 atm 2.488 atm 248.8 atm None Answer :B

Discussion

26495.	The number of significant figures in 0.0230 is :
Answer» 2 3 4 5 Answer :B

Discussion

26496.	The osmotic pressure of an aqueous solution containing 45g of sucrose (343) per litre of solution is 2.97 atm at 0^(@)C. Find the value of the gas constant and compare the result with the accepted value.
Answer» ANSWER :`0.086`lit.atm/K/mole

Discussion

26497.	The number of significant figure in 60.001 are
Answer» 5 6 3 2 Solution :All the ZEROES between two non ZERO digit are SIGNIFICANT. Hence in 60.0001 significant figures is 6.

Discussion

26498.	The osmotic pressure of blood is 8.21 atm at 37^(@)C. How much glucose would be used for an injection that is at the same osmotic pressure as blood?
Answer» Solution :`"MOLAR conc. of GLYCERINE "=10.2//M" (M = mol. mass)"` `"Molar conc. of GLUCOSE "=(2)/(180)xx(1)/(100)xx1000="0.111 mol L"^(-1)""THEREFORE""(10.2)/(M_(2))=0.111"or"M_(2)=91.9"g mol"^(-1)`.

Discussion

26499.	The number of sigma bonds in Zeise's salt is :
Answer» 4 6 7 none of these Solution :In `C_(2)H_(4)` itself 5 `delta`-bonds are PRESENT. Apart from this, metal has `delta`-co-ordination from 3`CL^(-)` ligands and `delta`-co-ordination from `pi-C_(2)H_(4)`. `K[PtCl_(3)(C_(2)H_(4))]`

Discussion

26500.	The osmotic pressure of an aqueous solution of sucrose is 2.47 atm at 303 K and the molar volume of the water present in solution is 18.10cm^(3). Calculate the elevation of boiling point of this solution. Given Delta H_("vap") = 540 cal//g. Assume volume solvent equal to volume of solution.
Answer» ANSWER :`5.145 XX 10^(-2)` ;

Discussion

Explore topic-wise InterviewSolutions in .

The outermost electronic configuration of the most electronegative element is

The outer electronic configuration of 15 group

The outermost electronic confi-guration of transition metal is

The outer shell of an egg was dissolved in hydrochloric acid and than placed in concentrated NaCI solution. Which one of the following will happen ?

The outermost electron is most loosely held in:

The outer shell electronic configuration of palladium (Z=46) is

The outermost elecronic configuration of most electronegative element is :

The outer electronic configurations of two transition metals are (i) 3d^(5)4s^(2) and (ii) 3d^(6)4s^(2) respectively. Based on this information predict the relative stability of +2 and +3 oxidation state of these metals. Which of the two exhibits larger number of oxidation states ?

The outer electronic configuration of two members of the lanthanoid series are as follows : 4f^(1) 5d^(1) 6s^(2) and 4f^(7) 5d^(-) 6s^(2) What are their atomic numbers ? Predict the oxidation states exhibited by these elements in their compounds.

The outer shell configuration of a halide ion is

The outer electronic structure of lawrencium (atomic number 103) is:

The outer electronic configuration of Gd (Atomic No:64) is :

The outer electronic configuration of Gd (Atomic no. 64) is…..

The outer electronic configuration of alkaline earth metal is

The outer elecftronic configuration of plutonium in +6 oxidatino state is

The other name of 1, 2, 3-trihydroxy benzene is …………………….. .

The Ostwald process is the main method for the manufacture of nitric acid. In the first step in this process

The othernameof glucose is ………. .

The other name of fructoseis ………… .

The number of signiicant figures in piare

The other name of 3,5-dihydroxy toluene is known as …………………. .

The other name of 1,2,3-trihydroxy benzene is called ……………………. .

The number of silver atoms present in a 90% pure silver wire weighing 10 g is :

The osmotic presure of a urea solution is 500 mm of Hg at 10^(@)C. The solution is diluted and its temperature is reised to 25^(@)C. It is now found that the osmotic pressure of the solution is reduced to 105.3 mm. Detyermine the extrant of dilution of the solution.

The number of significant zeros in 0.001010 is :

The osmotic pressure (pi) of a solution is given by reation

The number of significant figures present in 0.0200 is ………………whereas number of significant figures in a dozen (12) is………………… .

The osmotic pressure (P) of a solution is given by relation:

The osmotic pressure of which solution is maximum (consider that deci-molar solution of each 90% dissociated)

The number of significant figures in piare:

The osmotic pressure of which solution is maximum ( consider that deci-molar solution of each 90% dissociated )

The number of significant figures in the final answer of : (( 16.8 -14.2) ( 6.023 xx 10^(23)))/(2.76)is :

The osmotic pressure of the solution obtained by mixing 200 "cm"^3 of 2% (mass-volume) solution of urea with 200 "cm"^3 of 3.42% solution of sucrose at 20^@C is

The number of significant figures in 6.02xx10^(23) is

The Osmotic pressure of solution containing 4.0g of solute (molar mass 246) per litre at 27^@C is (R = 0.082L atm "k"^(-1) "mol"^(-1))

The osmotic pressure of equimolar solutions of glucose, KCI, MgC12 follows the order

The number of significant figures for the three numbers﻿ 161 cm, 0.161 cm, 0.0161 cm are﻿

The osmotic pressure of equimolar solutions of glucose, sodium chloride and barium chloride will be in the order :

The osmotic pressure of equimolar solutions of following solutes have been measured. Which of these show minimum osmotic pressure ?

The number of significant figures in 1.00 xx 10^6 is:

The osmotic pressure of equimolar solutions of BaCl_2, NaCl and glucose follow the order:

The number of significant figures in (0.04)^2 + (0.25)^2is :

The osmotic pressure of decimolar solution of glucose at 30^(@)C is :

The osmotic pressure of decimolar solution of glucose at 30^@C is:

The number of significant figures in 0.0230 is :

The osmotic pressure of an aqueous solution containing 45g of sucrose (343) per litre of solution is 2.97 atm at 0^(@)C. Find the value of the gas constant and compare the result with the accepted value.

The number of significant figure in 60.001 are

The osmotic pressure of blood is 8.21 atm at 37^(@)C. How much glucose would be used for an injection that is at the same osmotic pressure as blood?

The number of sigma bonds in Zeise's salt is :

The osmotic pressure of an aqueous solution of sucrose is 2.47 atm at 303 K and the molar volume of the water present in solution is 18.10cm^(3). Calculate the elevation of boiling point of this solution. Given Delta H_("vap") = 540 cal//g. Assume volume solvent equal to volume of solution.

The number of significant figures for the three numbers 161 cm, 0.161 cm, 0.0161 cm are