Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

27601.

The no of moles of lead nitrate needed to coagulate 2 moles of colloidal [AgI]I^(-) is

Answer»


SOLUTION :`[AgI]I^(-) "" Pb(NO_3)_2`
2 MOLES REQUIRED for 1 mole of `Pb(NO_3)_2`
27602.

The minimum ionisation enthalpy from the isoelectric species Ca^(2+), K^(+), Ar and Cl^(-)is of

Answer»

`CL^(-)`
`Ar`
`Ca^(2+)`
`K^(+)`

Answer :A
27603.

The no. of polypeptide chains present in a molecule of haemoglobin is

Answer»

One
Two
Three
Four

Answer :D
27604.

The no of lone pairs of electrons present in the central atom of CIF_(3)

Answer»


SOLUTION :`ClF_(3)`
27605.

The no. of isomeric pair with correct relationship specified are:

Answer»


SOLUTION :N//A
27606.

The minimum energy required for molecules to enter into the reaction is called

Answer»

Potential energy
Kinetic energy
Nuclear energy
Activation energy

Solution :The energy necessary for MOLECULES to UNDERGO chemical REACTION is known as Activation energy .
27607.

The no. of ions given by [Pt(NH_3)_4CL_2]cl_2in aquieous solution is :

Answer»

2
3
4
5

Answer :B
27608.

The minimum energy required for the photo emission of electrons from the surface of a metal is 4.95xx10^(-19)J. Calculate the critical frequency and the corresponding wave length of the photon required to eject the electron.

Answer»

SOLUTION :`v=7.5xx10^(14)HZ, lambda=400nm`
27609.

The no of halogen (s) donot form oxy acids

Answer»


SOLUTION :At-(ASTATINE) do not FORM OXY ACIDS.
27610.

The no. of Hg atoms in Iodideof millions base is "______"

Answer»


Solution :IODIDE of million.s BASE is `:. ` 2 Hg ATOMS.
27611.

The minimum energy, required for molecules to enter into chemical reaction is called:

Answer»

KINETIC energy
Potential energy
Threshold energy
Activation energy

Answer :C
27612.

The no. of geometrical isomers of[Co(NH_(3))_(3) (NO_(3))_(3)]are :-

Answer»

0
2
3
4

Solution :`[Ma_(3)b_(3)]` - TWO G.I.
27613.

The no. of coulombs required to liberate 0.224 dm^(3) of chlorine at 0^(@)C and 1 atm passed are :

Answer»

`2 XX 965`
96500
96.5
965/2

Solution :`22.4 dm^3 of Cl_2=1" MOLE of "Cl_2=2F`
`THEREFORE 22.4 dm^3 =2F`
Then 0.224 =0.02F
`therefore` Coulombs =`0.02xx96500 or 2xx965`
27614.

The minimum energy which molecules need to acquire before they can react by collision is known as what ?

Answer»

KINETIC energy
Potential energy
Threshold energy
Activation energy

Answer :C
27615.

The no of faradays of electricity required for the deposition of 0.9g of Alluninum is 10 F 'x' is

Answer»


Solution :EWQ AL is `(27)/(3)=9`
to deposite 9 GM of al 1 Farady is required for 0.9 gm of Al `10^(-1)F` is required `:. X=1`
27616.

The minimum energy of a molecule would posses in order to enter into a fruitful collision is known as ........

Answer»

REACTION ENERGY
COLLISION energy
Activation energy
Threshold energy

Answer :D
27617.

The no. of complexes showing and mer isomerism (A) [Co(NH_(3))_(3)Cl_(3)](B) [Co(en)_(3)]^(+3) [Co(gly)_(3)] (D) [Co(NH_(3))_(2)(H_(2)O)_(2)Cl_(2)] (E) [Fe(dipy)_(3)]^(+2)(F)[Fe(o-phen)_(3)]^(+2)

Answer»


SOLUTION :`[Ma_(3)b_(3)]^(n pm)` and `[M (AB)_(3)]^(n pm)` show FAC and mer isomerism .
27618.

The no. of compound with correct IUPAC name is/are:

Answer»


SOLUTION :`F` and `G` are CORRECT
27619.

The minimum energy required for molecules to enter into chemical reaction is called

Answer»

kinetic energy
potential energy
threshold energy
ACTIVATION energy

SOLUTION :MOLECULES undergoing reaction should CROSS over the minimum energy reaction should cross over the minimum energy, barrier or energy level known as thershold energy.
27620.

The no. of comlexes showing hepticity 5

Answer»

FERROCENE
zeise's salt
ruthenocene
chromocene

Solution :Ferrocene and osmocene are LINKED to CYCLO pentadienylion.
27621.

The minimum energy necessary of overcome the attractive force between the electron and the surface of silver metal is 7.52xx10^(-19) J. What will be the maximum kinetic energy of the electronsejected from silver which is being irradiated with ultraviolet light having a wavelength 360Å?

Answer»


ANSWER :`47.68xx10^(-19)` JOULE
27622.

The no. Of amines having pkb less than C_(6)H_(5)NH_(2) among the following (##DBT_SM_CHE_XII_U_12_E01_025_Q01.png" width="80%">

Answer»


ANSWER :7
27623.

The no. of chiral carbon present in beta-D-(+)-glucose is:

Answer»
27624.

The minimum energy required for molecules to enter into chemical reactionn is called

Answer»

Kinetic ENERGY
Potential energy
Threshold energy
ACTIVATION energy

ANSWER :C
27625.

The no. of amine(s) with correct IUPAC name is/are

Answer»


SOLUTION :`B,c,f,G` are CORRECT
27626.

The nitrosation of N, N-dimethylaniline takes place through the attack of electrophile

Answer»

NITRONIUM ion
protonated NITROUS acid
nitrous acid
nitrosonium ion

Answer :D
27627.

The minimum energy a molecule should possess in order to enter into a fruitful collision is known as

Answer»

REACTION ENERGY
Collision energy
ACTIVATION energy
THRESHOLD energy

Solution :The definition of threshold energy.
27628.

The nitrogen oxide (s) that contains N-N bond (s) is (are)

Answer»

`N_(2)O`
`N_(2)O_(3)`
`N_(2)O_(4)`
`N_(2)O_(5)`

SOLUTION :`N_(2)O, N_(2)O_(3) and N_(2) O_(4)` CONTAIN N-N bonds.
27629.

The minimum energy a molecule should posses in order to enter into a fruitful collision is known as….

Answer»

REACTION energy
collision energy
activation energy
threshold energy

Answer :D
27630.

The nitrogen oides that contain(s) N-N bond(s) is / are (i) N_(2)O "" (ii) N_(2)O_(3) "" (iii) N_(2)O_(4) "" (iv) N_(2)O_(5)

Answer»

(i), (II)
(ii),(III),(IV)
(iii),(iv)
(i),(ii) and (iii)

SOLUTION :
27631.

The minimum energy level necessary to permit a reaction to occur is :

Answer»

INTERNAL energy
Threshold energy
Activation energy
Free energy

Answer :B
27632.

The nitrogen content in the proteins can be quantitatively estimated by :

Answer»

CARIUS method
Kjeldahl's method
Victor MEYER's method
Rast method

Answer :B
27633.

The minimum distance between two tetrahedral voids in NaCl type crystal structure is(a is edge lenth)

Answer»

`(sqrt3 a)/4`
`a/2`
`a/(2xxsqrt2)`
`(SQRT2 a)/2`

ANSWER :B
27634.

The nitrogen containing compound produced in the reaction of HNO_(3) with P_(4)O_(10) ?

Answer»

can be PREPARED by reaction of `P_(4) and HNO_(3)`
is diamagnetic
contains N-N bond
reacts with Na-metal producing brown gas

Solution :`4 HNO_(3) + P_(4) O_(10) rarr 4 HPO_(3) + 2N_(2)O_(5)`
`N_(2)O_(5)` cannot be prepared by action of `HNO_(3)`on `P_(4)` but gives `H_(3)PO_(4)`
`P_(4) + 10 HNO_(3) rarr 4 H_(3)PO_(4) + 20 NO_(2) + 4 H_(2)O`
`N_(2)O_(5)` has 54 electrons `(2 xx 7 + 5 xx 8)` and hence is diamagnetic
`N_(2)O_(5)` does not contain N-N bond.
`N_(2)O_(5)` reacts with Na producing `NO_(2)`
`Na + N_(2)O_(5) rarr NaNO_(3) + NO_(2)` (brown gas)
THUS, option (b) and (d) are correct.
27635.

The minimum distance between an octahedral and a tetrahedral void in fcc lattice is

Answer»

`a SQRT3`
`(a sqrt3)/2`
`(a sqrt3)/3`
`(a sqrt3)/4`

ANSWER :D
27636.

The minimum concentration of an electrolyte required to cause coagulation of a sol is called its flocculation value. It is expressed in millimoles per litre. If the flocculation value of MgSO_(4) for standard As_(2)S_(3) sol is 3.33. How many milligrams of MgSO_(4) is to be added to 20 ml standard As_(2)S_(3) sol so that flocculation just starts ?

Answer»


ANSWER :`8`
27637.

The nitrogen atom may complete its octet in several ways. Which one is incorrect ?

Answer»

ELECTRON gain to form the NITRIDE Ion, `N^(3-)` e.g., `Li_(3)N`
Formation of electron pair BONDS e.g. `NH_(3) " or " NF_(3)` Azo compounds `(-N = N -)`
Formation of electron - pair bonds with electron gain e.g., Amide ion `NH_(2^(-))` and imide ion `NH^(2-)`
Formation of electron pair bonds with electron gain : `NH_(4^(+)), N_(2)H_(5)^(+), (C_(2)H_(5))_(4) N^(+)`

ANSWER :D
27638.

The nitrogen atom in the following cyclic compounds can be removed as trimethylamine by successive Hoffmann eliminations (involving exhaustive methylation followed by heating with AgOH). The amine which will require a greater number of Hofmann eliminations is

Answer»




ANSWER :B
27639.

The minimum conductance in fused state is shown by

Answer»

`MgCl_2`
`CaCl_2`
`BaCl_2`
`SrCl_2`

ANSWER :C
27640.

The nitrogen atom in the following cyclic compounds can be removed as trimethylamine by successive Hoffmann eliminations (involving exhaustive methylation followed by heating with AgOH). The amine which will require a greater number of Hoffmann elimination is :

Answer»




ANSWER :B
27641.

The minimum concentration of an electrolyte required to cause coagulation of a solis called its:

Answer»

FLOCCULATION value
PROTECTIVE value
GOLD number
COAGULATION number.

Answer :A
27642.

The nitrogen atom in each of the following tertiary amines may be removed as trimethyl amine by repeated Hofmann elimination. Which of the following amines requires the greater number of Hoffmann sequence to accomplish this ?

Answer»




SOLUTION :
`to` REQUIRED more no of HOFFMANN SEQUENCE
27643.

The minimum bond angle in the hydrides of group 16 elements is in :

Answer»

`H_(2)O`
`H_(2)Te`
`H_(2)Se`
`H_(2)S.`

Answer :B
27644.

The nitrogen atom in each of the following tertiary amines may be removed as trimethyl amine by repeated Hofmann eliminations (exhaustive methylation followed by heating with AgOH). Which of the amines requires the greater number of Hofmann sequences to accomplish this ?

Answer»




ANSWER :A
27645.

The minimum amount of energy which is required to remove an outermost electron from anyisolated neutral gaseous atom is known as first iosiation energy. These are the following factors which other ionisation energy. (i) Ionisation energy alpha (1)/("principal quantum number") (ii) Ionisation Energy alphaZ_(eff) (iii) If orbitals are fully filled or half filled so stability will be more and ionisation energy will be high (iv) If penultimate electron will effectively shield the mucleus ionisation energy wiill be less and vise versa. 1E_(1) and IE_(2) of Mg are 178 kcal/mol and 348 kcal/mol. The enthalpy required for the reaction MgrarrMg^(2+)+2e is:

Answer»

`+170` kcal/mol
`+526 kcal/mol`
`-170` kcal/mol
`-526` kcal/mol

Solution :
27646.

The nitrogen atom in amine is …………. Hybridised.

Answer»


ANSWER :`SP^(3)`
27647.

The minimum amount of energy which is required to remove an outermost electron from anyisolated neutral gaseous atom is known as first iosiation energy. These are the following factors which other ionisation energy. (i) Ionisation energy alpha (1)/("principal quantum number") (ii) Ionisation Energy alphaZ_(eff) (iii) If orbitals are fully filled or half filled so stability will be more and ionisation energy will be high (iv) If penultimate electron will effectively shield the mucleus ionisation energy wiill be less and vise versa. Choose the correct order of I^(st) ionisation energy

Answer»

`NeltF`
`OgtN`
`NagtAl`
`MggtAl`

Solution :`Ne=1s^(2)2S^(2)2p^(6)`
`F=1s^(2)2s^(2)2p^(5)`
Due to the stable configuration of Ne, 1ST ionisation energy of Ne is greater than Fluorine
`MG=[Ne]3s^(2)`
`Al=[Ne]3s^(2)3p^(1)`
Due to stable configuration of Mg its ionisation energy is greater than Al
27648.

The nitro group can be reduced to primary amino group by……………

Answer»

`SN"/ CON."HCl`
Zn DUST
`Zn"/"NH_4Cl`
`Zn"/"NAOH`

Answer :A
27649.

The minimum amount of energy required to remove the most loosely bound electron form an isolated atom in the gaseous state is known as ionization energy or first ionization energy or inonization enthalpy (IE_(1)) of the element. The energy required to remove the second electron from the monovalent cation is called second ionization enthalpy (IE_(2)). Simllarly, we have third, fourth .................... fonization enthalpies. The values of ionization energy depends on a number of factors such as (i) size of the atom (ii) screening effect (iii) nuclear charge (iv) half filled and fuly filled orbitals (v) shape of orbital. In a group, the ionization energy decreases from top to bottom. In a period, the valup of ionisation energy increases from left to right with breaks where atoms have somewhat stable configurations. The electronic configuration of some netural elemtns are given below :

Answer»

`1s _(1), 2s^(2)`
`1s^(2), 2s^(2), 2P^(1)`
`1s ^(2), 2s ^(2), 2p ^(4)`
`1s ^(2), 2s ^(2), 2p ^(3)`

Answer :C
27650.

The minimum amount of energy required to remove the most loosely bound electron form an isolated atom in the gaseous state is known as ionization energy or first ionization energy or inonization enthalpy (IE_(1)) of the element. The energy required to remove the second electron from the monovalent cation is called second ionization enthalpy (IE_(2)). Simllarly, we have third, fourth .................... fonization enthalpies. The values of ionization energy depends on a number of factors such as (i) size of the atom (ii) screening effect (iii) nuclear charge (iv) half filled and fuly filled orbitals (v) shape of orbital. In a group, the ionization energy decreases from top to bottom. In a period, the valup of ionisation energy increases from left to right with breaks where atoms have somewhat stable configurations. Compared to the second ionization energy (IE_(2)) of an atom the third ionization energy(IE_(2)) is

Answer»

the same
greater
smaller
HALF

ANSWER :B