94420 + Interview Questions in Chemistry in Class 12 Page 551 InterviewSolution

27501.	The normality of 10% (weight/volume) acetic acid is
Answer» 1 N 10 N 1.7 N 0.83 N Solution :`N=(w xx1000)/(Eq.wt. XX "VOLUME")=(10xx1000)/(60xx100)=1.66 N`.

Discussion

27502.	The molal elevation/depression constant depends on
Answer» NATURE of SOLVENT nature of solute temperature Delta H solution Solution :It is a CHARACTERISTICS of GIVEN solvent.

Discussion

27503.	The normality of 10 mL of a 20 V H_(2)O_(2) is
Answer» `1.79` `3.58` `60.86` `6.086` ANSWER :B

Discussion

27504.	The molal elevation constant of water is …………… while that of benzene is ………………. .
Answer» SOLUTION :`"0.52 K KG MOL"^(-1)," 2.53 K kg mol"^(-1)`

Discussion

27505.	The normality of 10% ( weight/volume) acetic acid is :
Answer» 1 N 1.7 N 0.83 N 10 N SOLUTION :Wt. of ACETIC ACID `=10G`. Equivalents of acetic acid `=10/60`, Vol. of solution `=100 ml` Molarity `=(10xx1000)/(60xx100)=1.7` N

Discussion

27506.	The molal elevation constant of water is 0.51. The boiling point of 0.1 molal aqueous NaCl solution is nearly:
Answer» `100.05^@C` `100.1^@C` `100.2^@C` `101.0^@C` ANSWER :A

Discussion

27507.	The Normality of 0.98% (w/v) H_2SO_4 solution is
Answer» `0.1MN` `0.2N` `0.4N` 1N Answer :B

Discussion

27508.	The normality of 10 lit. volume hydrogen peroxide is
Answer» `0.176` `3.52` `1.78` `0.88` SOLUTION :`H_(2)O_(2)to H_(2)O+(1)/(2)O_(2)` `1 M H_(2)O_(2)` solution = 2N = 34 gm/litre = 11.2 So Normality `=(2XX10)/(11.2)=17.8`

Discussion

27509.	The normality of 0.3 M phosphorus acid (H_(3)PO_(3)) is
Answer» 0.1 0.9 0.3 0.6 Answer :D

Discussion

27510.	The molal elevation constant of water = 0.52^(@)C kg mol^(-1). The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), therefore, should be
Answer» `100.52^(@)C` `101.04^(@)C` `99.48^(@)C` `98.96^(@)C` Solution :`Delta T_(B) =imk_(b)=0.52xx1xx2=1.04`. `THEREFORE T_(b)=100+1.04=101.04^(@)C`.

Discussion

27511.	The normal boiling point of watr is 373 K (at 760 mm), vapour pressure of water at 298 K is 23 mm. If entyalpyof vaporization is 40.656 kj//mol.the boiling point of water at 23 mm pressure will be :
Answer» <P>250 K `294.4 K` `51.6 K` `12.5 K` Solution :From Clausius- CLAPEYRON equation. `"log" (P_(2))/(P_(1))=(DeltaH_(v))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]` `rArr"log" (760)/(23)=(40656)/(2.303xx8.314)[(373-T_(1))/(373xxT_(1))]` `:.T_(1)=294.4K`. Hence, (B) is the correct answer.

Discussion

27512.	The molal elevation constant of water = 0.52 K, molality^-1. The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), should be:
Answer» `100.52^@C` `101.04^@C` `99.48^@C` `98.96^@C` ANSWER :B

Discussion

27513.	The normal K_a for carboxylic acids is of the order of:
Answer» `10^-5` `10^-8` `10^-3` `10^-2` ANSWER :A

Discussion

27514.	The molal elevation constant is the ratio of the elevation in B.P. to
Answer» MOLARITY MOLALITY does not CHANGE with TEMPERATURE Mole fraction of solute Mole fraction of solvent Solution :`Delta T_(B)=K_(b)xx m` or `K_(b) = Delta T_(b)//m`

Discussion

27515.	The normal boiling point of water is 373K . Vapour pressure of water at temperature T is 19 mmHg . If enthalpy of vaporization is 40.67 kJ//"mol", then temperature T would be
Answer» 250 K 291.4 K 230 K 290 K ANSWER :B

Discussion

27516.	The molal elevation constant is the ratio of the elevation in boliing point to
Answer» Lmolarity MOLALITY MOLE FREACTION of solute Mole FRACTION of solvent Answer :B

Discussion

27517.	Thenormalboilingpointofpurewateris373 K. Calculatetheboilingpoint ofthe solutioncontaining2.0 xx 10^(-2)kg ofglucosein 0.5 kg of water(K_(3) for wateris 0.52 k kg mol^(-1))
Answer» SOLUTION :373 .0116K

Discussion

27518.	The normal boiling point of a liquid 'X' is 400 K.Which of the following statement is true about the process X(l)toX(g) ?
Answer» At 400 K, and 1 atm pressure `DeltaG=0` At 400 K, and 2 atm pressure `DeltaG=+ve` At 400 K, and 1 atm pressure `DeltaG=0` At 400 K, and 1 atm pressure `DeltaG=0` Solution :Boiling of a liquid at normal boiling point is a equilibrium process and on decreasing the pressure equilibrium will go FORWARD and `DeltaG` will be NEGATIVE and vice-versa.

Discussion

27519.	The molal elevation constant for water is 0.52 K. "molality"^(-). The elevation caused in the boiling point of water by dissolving 0.25 mole of a non volatile solute in 250 g of water will be :
Answer» `52^(@)` `5.2 ^(@)C` `0.52^(@)C` `0.052 ^(@)C` Solution :`(Delta T_(f)=1000 XX K_(f))/W_(1) xx W_(2)/M_(2)=(1000 xx K_(f))/W_(1)xx n` `Delta T_(f) = (1000 xx 0.52)/250 xx 0.25 =0.52^(@)C`

Discussion

27520.	The molal depression constant of water is …………….while that of benzene is ……………… .
Answer» SOLUTION :`"1.86 K KG MOL"^(-1),"5.12 K kg mol"^(-1)`

Discussion

27521.	The normalboilingpoint of a liquild'A' is350 K.DeltaH_(vap) to benormal pointis35kJ//mole. Pick outthe correctstatement(s).(Assume DeltaH_(vap) to beindependentof pressure ).
Answer» `DeltaS_("vaporisation")gt 10 J//K "MOLE" "at350 K and 0.5 atm"` `DeltaS_("vaporisation")lt 10 J//K "mole" "at350 K and 0.5 atm"` `DeltaS_("vaporisation")lt 10 J//K "mole" "at350 K and 2 atm"` `DeltaS_("vaporisation")=10 J//K "mole" "at350 K and 2 atm"` Solution :N//A

Discussion

27522.	The molal elevation constant for water is 0.52 K.molality^-1. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be:
Answer» `52^@C` `5.2^@C` `0.52^@C` `0.052^@C` ANSWER :C

Discussion

27523.	The normal boiling point of a liquid ‘A’ is 350 K. DeltaH_("vap") at normal boiling point is 35 kJ/mole. Pick out the correct statement (s). (Assume DeltaH_("vap") to be independent of pressure).
Answer» `DeltaS_("VAPORISATION")gt100` mole at 350 K and 0.5 atm `DeltaS_("vaporisation")lt100` J/K mole at 350 K and 0.5 atm `DeltaS_("vaporisation")lt100` J/K mole at 350 K and 2 atm `DeltaS_("vaporisation")=100` J/K mole at 350 K and 2 atm Answer :A::C

Discussion

27524.	The molal depreesion constant of water is 1.86^(@)C//m. Then find out the freezing point of 0.1 m NaCl solution.
Answer» `-1.86^(@)C` `0.372^(@)C` `-0.372^(@)C` `-0.186^(@)C` SOLUTION :For NACL, i = 2 `Delta T_(f)=2K_(f).m` `= 2xx1.86xx0.1=0.372` `T_(s)=T-Delta T_(f)=0-0.372=-0.372^(@)C`.

Discussion

27525.	The molal depression constant for a solvent is 4.9. The depression in freezing point for a millimolal solution of a non-electrolyte in the solvent is
Answer» 0.49 4.9 4.9 + 0.001 0.0049. Solution :`DELTA T_(f) = K_(f) XX m=4.9 xx 10^(-3)=0.0049`

Discussion

27526.	The normal amount of glucose in 100 mL of blood (8-12hours after a meal) is:
Answer» 8 mg 80 mg 200 mg 800 mg Answer :B

Discussion

27527.	The no.of statements is// are correct ?
Answer» SOLUTION :a ,b , d are correct . In C species can be inside or outside the COORDINATION sphere to satisfy the oxidation STATE .

Discussion

27528.	The no.of chloride ions co-ordinated to Fe^(+3) ion is hydrated FeCl_3. 6H_2O
Answer» SOLUTION :`[FE(H_2O)_4Cl_2]Cl.2H_2O`

Discussion

27529.	The molal cryoscopic for water is 1.86 "K mol"^(-1). When 3.42 g of sugar ( molar mass = 342) is dissolved in 100 g of water, the solution will freeze at
Answer» `1.86^(@)C` `0.186^(@)C` `-0.186^(@)C` `0.914^(@)C` Solution :`DeltaT_(F)=(K_(f)xx W_(B)xx1000)/(W_(A)xxM_(B))` `=(1.86xx3.42xx1000)/(100xx342)=0.186` Freezing point of solution `=0-0.186` `=-0.186^(@)C`

Discussion

27530.	The molal cryoscopic constant for water is:
Answer» 1.86 K `molality_(-1)` 5.26 K `molality_(-1)` 55.5 K `molality_(-1)` 0.52 K `molality_(-1)` ANSWER :A

Discussion

27531.	The molal cryoscopic constant for water is
Answer» `1.86 K "molality"^(-1)` 5.26 K `molality_(-1)` `55.5 K "molality"^(-1)` `0.52 K "molality"^(1)` Solution :It is the numerical VALUE of molal CRYOSCOPIC constant for WATER. It CHANGES with change of solvent.

Discussion

27532.	The non-fusible impurities of ores are removed by adding :
Answer» Flux Slag Gangue None Answer :A

Discussion

27533.	The molal boiling point constant for water is0.513^(@)C kgmol^(-1). When 0.1mole of sugar is dissolved in 200ml of water , the solution boils under a pressure of one atmosphere at
Answer» `100.513^(@)C` `100.0513^(@)C` `100.256^(@)C` `101.025^(@)C` Solution :`DELTA T_(B)=K_(b)xx m =0.513xx((0.1)/(200)xx1000)` `=0.2565^(@)C, T_(b)=100.256^(@)C`

Discussion

27534.	The non - stoichiometric iron oxide has a composition Fe_(0.94) O. Find the ratio of ferrous and ferric ions present in it.
Answer» Solution :SAY one hundred ions of each `Fe^(2+) and O^(2-)` present in the stoichiometric `FEO`. Some of `Fe^(2+)`ions (x) are REPLACED by `Fe^(3+)`ions (y). In view of the conservation of ions in an ionic crystal, `x+y=94 ""…(1)` In view of the conservation of positive charge of cations in a crystal, `2x+3y = 200""...(2)` Solving, for .x. and for .y., `y=12 and x=82` The ration of `Fe^(2+) and Fe^(3+)` ions present in `Fe_(0.94) O =82 : 12` `= 41:6`

Discussion

27535.	The non-viable particulate among the following is
Answer» DUST bacteria moulds fungi Solution :Dust

Discussion

27536.	The molal boiling point constant of water is 0.53^@C. When 2 mole of glucose are dissolved in 4000 g of water, the solution will boil at:
Answer» `100.53^@C` `101.06^@C` `100.265^@C` `99.47^@C` ANSWER :C

Discussion

27537.	The non-proteinaceous substances which certain enzymes require for their activity are called:
Answer» Catalysts Inhibitors Co-enzymes Epimers Answer :C

Discussion

27538.	The Mn_3O_4formed on strong heating of a sample of MnSO_4 . 4H_2Owas dissolvedin 100 cm of 0.1 N FeSO_4containing dilute H_2SO_4 . The resulting solution reacted completely with 50 cm^3of KMnO_4solution. 25 cm^3of this KMnO_4solution required 30 cm^3of 0.1 N FeSO_4solution for complete reaction. Calculate the amount of MnSO_4 . 4H_2Oin the sample.
Answer» SOLUTION :1.338 G

Discussion

27539.	The non-protein component in enzymes which is necessary for its biological activity is :
Answer» LIPIDS COENZYMES Nucleic acid Phosphoric acid. Answer :B

Discussion

27540.	The modern basis of atomic weight is
Answer» Isotope `H^(1) = 1.000` Oxygen `= 16.000` Isotope `O^(16) = 16.000` Isotope `C^(12) = 12.000` Solution :Isotope `C^(12)` is the MODERN basis of atomic weight.

Discussion

27541.	The MnO_(4)^(-) ion is coloured though Mn(+7) has a d^(0) configuration due to the _________ of electrons from __________ to __________.
Answer» SOLUTION :TRANSFER, OXYGEN, MANGANESE

Discussion

27542.	The non-nutritive sweetener is
Answer» saccharine sucrose fructose glucose Answer :A

Discussion

27543.	The non-metallic element whose molecules contain maximum number of its atom is:
Answer» O Si As P Answer :D

Discussion

27544.	The non-metal whose oxide is a good dehydrating agent is:
Answer» S Cl N P Answer :D

Discussion

27545.	The mixtureof n-hexane and n-heptane is an example of :
Answer» IDEAL SOLUTION None-ideal solution Dilute solution Real solution Answer :A

Discussion

27546.	The non-metal which is not affected ny NaOH:
Answer» C Si P S Answer :A

Discussion

27547.	The mixture that forms maximum boiling azeotrope is :
Answer» HEPTANE + Octane WATER + Nitric acid Ethanol + Water Acetone + Carbon disulphide SOLUTION :Negative DEVIATED mixture from IDEAL behaviour can form maximum boiling azeotrope. Water + Nitric acid shows negative deviation.

Discussion

27548.	The non-metal that usually occupies tetrahedral voids in the formation of interstetial compounds
Answer» HYDROGEN Boron Carbon Sulphur Answer :A

Discussion

27549.	The mixture of which of the following is called "Matte"?
Answer» `FeO and SiO_2` `PbS and Zns` `Cu_2S and FeS` `Cu_2S and SO_2` ANSWER :C

Discussion

27550.	The non metal which exists in liquid state at room temperature is:
Answer» Na Br Mg Ga Solution :Bromine is non METAL which EXISTS in liquid STATE at room TEMPERATURE.

Discussion

Explore topic-wise InterviewSolutions in .

The normality of 10% (weight/volume) acetic acid is

The molal elevation/depression constant depends on

The normality of 10 mL of a 20 V H_(2)O_(2) is

The molal elevation constant of water is …………… while that of benzene is ………………. .

The normality of 10% ( weight/volume) acetic acid is :

The molal elevation constant of water is 0.51. The boiling point of 0.1 molal aqueous NaCl solution is nearly:

The Normality of 0.98% (w/v) H_2SO_4 solution is

The normality of 10 lit. volume hydrogen peroxide is

The normality of 0.3 M phosphorus acid (H_(3)PO_(3)) is

The molal elevation constant of water = 0.52^(@)C kg mol^(-1). The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), therefore, should be

The normal boiling point of watr is 373 K (at 760 mm), vapour pressure of water at 298 K is 23 mm. If entyalpyof vaporization is 40.656 kj//mol.the boiling point of water at 23 mm pressure will be :

The molal elevation constant of water = 0.52 K, molality^-1. The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), should be:

The normal K_a for carboxylic acids is of the order of:

The molal elevation constant is the ratio of the elevation in B.P. to

The normal boiling point of water is 373K . Vapour pressure of water at temperature T is 19 mmHg . If enthalpy of vaporization is 40.67 kJ//"mol", then temperature T would be

The molal elevation constant is the ratio of the elevation in boliing point to

Thenormalboilingpointofpurewateris373 K. Calculatetheboilingpoint ofthe solutioncontaining2.0 xx 10^(-2)kg ofglucosein 0.5 kg of water(K_(3) for wateris 0.52 k kg mol^(-1))

The normal boiling point of a liquid 'X' is 400 K.Which of the following statement is true about the process X(l)toX(g) ?

The molal elevation constant for water is 0.52 K. "molality"^(-). The elevation caused in the boiling point of water by dissolving 0.25 mole of a non volatile solute in 250 g of water will be :

The molal depression constant of water is …………….while that of benzene is ……………… .

The normalboilingpoint of a liquild'A' is350 K.DeltaH_(vap) to benormal pointis35kJ//mole. Pick outthe correctstatement(s).(Assume DeltaH_(vap) to beindependentof pressure ).

The molal elevation constant for water is 0.52 K.molality^-1. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be:

The normal boiling point of a liquid ‘A’ is 350 K. DeltaH_("vap") at normal boiling point is 35 kJ/mole. Pick out the correct statement (s). (Assume DeltaH_("vap") to be independent of pressure).

The molal depreesion constant of water is 1.86^(@)C//m. Then find out the freezing point of 0.1 m NaCl solution.

The molal depression constant for a solvent is 4.9. The depression in freezing point for a millimolal solution of a non-electrolyte in the solvent is

The normal amount of glucose in 100 mL of blood (8-12hours after a meal) is:

The no.of statements is// are correct ?

The no.of chloride ions co-ordinated to Fe^(+3) ion is hydrated FeCl_3. 6H_2O

The molal cryoscopic for water is 1.86 "K mol"^(-1). When 3.42 g of sugar ( molar mass = 342) is dissolved in 100 g of water, the solution will freeze at

The molal cryoscopic constant for water is:

The molal cryoscopic constant for water is

The non-fusible impurities of ores are removed by adding :

The molal boiling point constant for water is0.513^(@)C kgmol^(-1). When 0.1mole of sugar is dissolved in 200ml of water , the solution boils under a pressure of one atmosphere at

The non - stoichiometric iron oxide has a composition Fe_(0.94) O. Find the ratio of ferrous and ferric ions present in it.

The non-viable particulate among the following is

The molal boiling point constant of water is 0.53^@C. When 2 mole of glucose are dissolved in 4000 g of water, the solution will boil at:

The non-proteinaceous substances which certain enzymes require for their activity are called:

The non-protein component in enzymes which is necessary for its biological activity is :

The modern basis of atomic weight is

The MnO_(4)^(-) ion is coloured though Mn(+7) has a d^(0) configuration due to the _________ of electrons from __________ to __________.

The non-nutritive sweetener is

The non-metallic element whose molecules contain maximum number of its atom is:

The non-metal whose oxide is a good dehydrating agent is:

The mixtureof n-hexane and n-heptane is an example of :

The non-metal which is not affected ny NaOH:

The mixture that forms maximum boiling azeotrope is :

The non-metal that usually occupies tetrahedral voids in the formation of interstetial compounds

The mixture of which of the following is called "Matte"?

The non metal which exists in liquid state at room temperature is:

The MnO_(4)^(-) ion is coloured though Mn(+7) has a d^(0) configuration due to the _ of electrons from to ____.