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27451.

The number of sigmaand pi-bonds in a molecule of benzene is

Answer»

`6 sigma and 9 pi` BONDS
`12 sigma and 3 pi` bonds
`9 sigma and 3 pi` bonds
`6 sigma and 6 pi` bonds

Answer :B
Discussion
27452.

The number of 3d-electrons in Cu^+ ion is :

Answer»

8
10
6
12

Answer :B
Discussion
27453.

The number of 2p electrons having spm quantum number s = - 1/2 are

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6
0
2
3

Solution :There are three 2P ORBITALS containing 3 electrons with SPIN + 1/2 and 3 with spin - 1/2.
Discussion
27454.

The number of 2 p electrons having spin quantum number S = -1//2 are

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6
0
2
3

Solution :i.e., the NUMBER of 2p electrons having spin quantum number, 3 = -1/2 are 3.
Discussion
27455.

The number of 1^(0), 2^(0) and 3^(0) alcoholic groups in Mannitol or Sorbitol are respectively

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2, 4 and 0
1, 4 and 0
2, 2 and 0
2, 1 and 1

Answer :A
Discussion
27456.

The number of 1^@ alcoholic groups in glycol

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1
2
3
zero

Answer :B
Discussion
27457.

The number 'n' of repeating unit in polymer molecule is called ………………...

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DEGREE of POLYMERIZATION
oligomer
heavy polymer
REPEATING UNIT

Solution :degree of polymerization
Discussion
27458.

The number of 1^@, 2^@ and 3^@ carbon atoms present in isopentane are respectively:

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3,2,1
2,3,1
3,1,1
2,2,1

Answer :C
Discussion
27459.

The number and type of bonds between two carbon atoms in calcium carbide are:

Answer»

one `SIGMA`, one `PI`
one `sigma`, two `pi`
two `sigma`, one `pi`
one `sigma` ,`1 1/2 pi`

ANSWER :B
Discussion
27460.

The numbe of moles of oxygen obtained by the electrolytic decomposition of 108 g water is

Answer»

2.5
3
5
7.5

Solution :`{:(2H_(2)O overset("electrolysis")(rarr)2H_(2)+O_(2)),("2 mole1 mole"),(2xx18),(=36 G):}`
`:'` 36 g of `H_(2)O` PRODUCE 1 mole of oxygen
`:.` 108 g of water will produce oxygen `=108/36=3` mol.
Discussion
27461.

The number 32.392800 may be written upto three significant figures as:

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32.4
`0.323 XX 10^2`
`34.2`
`32.393`

SOLUTION :APPLYING ROUNDING off procedure 32.392800 `rArr` 32.4
Discussion
27462.

The numbe of hydrogen atoms in 0.9 gm glucose, C_(6)H_(12)O_(6), is same as

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0.048 gm hydrazine.`N_(2)H_(4)`
0.17 gm AMMONIA, `NH_(3)`
0.30 gm of ETHANE ,`C_(2)H_(6)`
0.03 gm pentene, `H_(2)`

ANSWER :C
Discussion
27463.

The number of atoms present in one molecule of rhombic sulphur is

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2
4
6
8

Answer :D
Discussion
27464.

The nuclide X undergoes alpha-decay and other nuclide Y, beta^(-) decay. Which of the following statements are correct? 1. The beta^(-1) particles emitted by Y may have widely different speeds. 2. The alpha-particles emitted by X may have widely different speeds 3. The alpha-particles emitted X will have almost same speed. 4. The beta-particles emitted by Y will have the same speed.

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1 and 3 are correct
2 and 3 are correct
2 and 4 are correct
1 and 4 are correct

Answer :a
Discussion
27465.

The number of points at the centre of the primitive unit cell is

Answer»

1
2
3
0

Answer :D
Discussion
27466.

The nuclides with Z > 20 lying below the stability belt decay by

Answer»

`BETA^(+)`-emission
K-electron CAPTURE
both (a) and (B)
`beta^(-)`-emission

Solution :By `beta^(+)` emission and K- electron capture, n/p RATIO increases to LIE within the stability belt.
Discussion
27467.

The nuclide ratio, ""_1^3H to ""_1^1Hin a sample of water is 8.0 xx 10^(-18): 1. Tritium undergoes decay with a half-life period of 12.3 years. How many tritium atoms would 10.0 g of such a sample contain 40 years after the original sample is collected?

Answer»

Solution :Given that , `("MOL of " T_2O "molecules")/("mol of " H_2O" molecules") = (8 xx 10^(-18))/(1)`
` THEREFORE 10g` of SAMPLE contains `(2 xx 8 xx 10^(-18)) xx 10/18` mole tritium atoms`
`5.62 xx 10^5`
Discussion
27468.

The nuclides ""_(18)^(40)Ar and ""_(19)^(41)K are

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isotopes
isobars
isotones
none of these

Answer :C
Discussion
27469.

The nuclide ""^227Acundergoes betaemission (98.6%) or a emission (1.4%) with a half-life of 21.6 years. Determine lamda(alpha) and lamda(beta) .

Answer»

SOLUTION :`4.5 XX 10^(-4) YR^(-1) , 0.0317 yr^(-1)`
Discussion
27470.

The nucleus resulting from ""_(92)^(238)U after successive loss of two alpha and four beta particles is

Answer»

`""_(90)^(234)Th`
`""_(94)^(230)PU`
`""_(88)^(230)Ra`
`""_(92)^(230)U`

SOLUTION :`""_(92)^(238)U overset(-2 alpha)(rarr) ""_(88)^(230)X overset(-4 beta)(rarr) ""_(92)^(230)U`.
Discussion
27471.

The nucleus of an atom X is supposed to be a sphere with a radius of 5xx10^(-13)cm. find the density of the matter in the atomic nucleus if the atomic weight of X is 19.

Answer»


ANSWER :`6.02xx10^(13)`g/mL
Discussion
27472.

The nucleus of radioactive element possesses

Answer»

LOW BINDING ENERGY
High binding energy
Zero binding energy
High POTENTIAL energy

Solution :Low binding energy causes radioactivity
Discussion
27473.

The nucleus of an element contains 17 protons and 18 neutrons. What is its (a) atomic number and (b) mass number? Write the complete symbol for the element.

Answer»

SOLUTION :`Z=17m A=35," SYMBOL"=""_(17)^(35)CL`
Discussion
27474.

The nucleus of an atom is located at x=yx=z=0. If the probability of finding an electron in d_(x^(2)-y^(2)) orbital in a tiny volume around x=a, y=0, z=0 is 1xx10^(-5), what is the probability of finding the electron in the same size volume around x=0, y=a, z=0 ?

Answer»

`1 xx10^(-5)`
`1XX10^(-5)XXA`
`-1xx10^(-5)xxa`
zero

Solution :It would be same in `X` and `y` axis for `d_(x)^(2)-y^(2)`
Discussion
27475.

The nucleus of an atom is made up of X protons and Y neutrons. For the most stable and abundant nuclei

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X and Y are both EVEN
X and Y are both ODD
X is even and Y is odd
X is odd and Y is even

Solution :Ever-Ever are most STABLE
Odd -Odd are most UNSTABLE
Discussion
27476.

The nucleus of an atom can be assumed to be spherical. The radius of the nucleus of mass number A is given by 1.25 xx 10^(-13) xx A^(1//3) cm. Radius of atom is one A. If the mass number is 64, then the fraction of the atomic volume that is occupied by the nucleus is

Answer»

`1.0xx10^(-3)`
`5.0xx10^(-5)`
`2.5xx10^(-2)`
`1.25xx10^(-13)`

Solution :Radius of nucleus = `1.25xx10^(-13)XXA^(1//3)cm`
`=1.25xx10^(-13)xx64^(1//3)` cm
`=1.25xx10^(-13)xx4cm=5xx10^(-13)cm`
Radius of atom = `1Å=10^(-8)cm`
Volume of nucleus/volume of atom
`=((4//3)PI(5xx10^(-13))^(3))/((4//3)pi(10^(-8))^(3))=(125xx10^(-39))/(10^(-24))`
`=125xx10^(-15)=1.25xx10^(-13)`
Discussion
27477.

The nucleus of an atom can be asssumed to be spherical. The radius of the nucleus of mass number A is given by 1.25xx10^(-13)xxA^(1/3)cm. Radius of atom is one Å. If the mass number is 64, then the fraction of the atomic volume that is occupied by the nucleus is

Answer»

`1.0xx10^(-3)`
`5.0xx10^(-5)`
`2.5xx10^(-2)`
`1.25xx10^(-13)`

ANSWER :D
Discussion
27478.

The nucleus emits beta-particles though it does't contain any electrons in it. (R ) The nucleus shows the transformation ._(0)n^(1) to p + beta+ antineutrino for beta-emission.

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If both (A) and (R ) are CORRECT and (R ) is the correct EXPLANATION for (A).
If both (A) and (R ) are correct but (R ) is not the correct explanation for (A )
If both (A) and (R ) are incorrect.
If both (A) and (R ) are incorrect.

Answer :A
Discussion
27479.

The nucleus""_(29)^(64)Cu accepts an orbital electron to yield

Answer»

`""_(28)^(65)Ni`
`""_(30)^(64)Zn`
`""_(28)^(64)Ni`
`""_(30)^(65)Zn`

SOLUTION :`""_(29)^(64)Cu + e^(-)` (K-electron capture) `to ""_(28)^(64)Ni`
Discussion
27480.

The nucleophilic substitution reactions taking place in aromatic system are designated as SN ArIn fact aryl halides do not easily undergo nucleophilic substitution under ordinary conditions. However, introduction of electron- withdrawing groups in o, p – positions makes the reaction to go faster. Keeping these general points in view answer the following questionsWhich of the following undergo nucleophilic substitution at a faster rate with a given nucleophilic

Answer»




SOLUTION :As it CONTAINS two EWG - `S_(N) Ar` is faster than others
Discussion
27481.

The nucleophilicity of F^(-) is higher in case of

Answer»

water
ethanol
DMSO
acetone

Answer :C
Discussion
27482.

The nucleotides are joined by …………………….

Answer»

GLYCOSIDIC LINKAGE
PHOSPHODIESTER linkage
Peptide linkage
H-bonds

SOLUTION :Phosphodiester linkage
Discussion
27483.

The nucleotides of one polynucleotide chain are joined together by

Answer»

WEAK HYDROGEN bonds
Disulphide bonds
Phospho-diester bonds
Glycosidic bonds

Answer :C
Discussion
27484.

The nucleidic ratio of ""_(1)^(3)H to _(1)^(1)H in a sample of water is 8.0xx10^(-18) : 1. Tritium undergoes decay with half-life period of 12.3 years. How many tritium atoms would 10.0g of such a sample contains 40 years after the original sample is collected ?

Answer»


ANSWER :`5.624xx10^(5)` ATOMS
Discussion
27485.

The nucleides X and Y are isotonic to each other with mass numbers 70 and 72 respectively. If the atomic number of X is 34, then that of Y would be

Answer»

32
34
36
38

Solution :the ISOTONIC SPECIES have same NUMBER of neutrons.
Neutrons in X=70-34=36
Neutrons in Y=36
Protons in Y=72-3=36 (atomic number).
Discussion
27486.

The nucleicacid base havingtwo possiblebindingsitesis ……….. .

Answer»

THYMINE
cytosine
guanine
ADENINE

ANSWER :C
Discussion
27487.

The nuclear reaction ._(29)^(63)Cu + ._(2)^(4)He rarr ._(17)^(37)Cl + 14 ._(1)^(1)H + 16 ._(0)^(1)n is referred to as

Answer»

Spallation reaction
Fusion reaction
FISSION reaction
Chain reaction

Solution :Spallation REACTIONS are similar to fission reactions. They BROUGHT about by HIGH ENERGY bombarding particles or photons
Discussion
27488.

The nuclei which are not identical but have same number of nucleons represent :

Answer»

isobars
isotopes
isomers
isotones.

Answer :A
Discussion
27489.

The nuclear binding energy for Ar (39.962384 amu) is : (given mass of proton and neuron are 1.007825 amu and 1.008665amu respectively)

Answer»

<P>343.62 MEV
0.369096 MeV
931 MeV
None of these

Solution :`._(18)Ar^(40)`
Total no. of protons = 18
Total no. of neutrons = 22
Mass DEFECT `= [m xx p + m xx n] = 39.962384`
`= [1.007825 xx 18 + 1.008665 xx 22] - 39.962384`
`=[18.14085 + 22.19063] - 39.962384 = 0.369`
Binding ENERGY = mass defect `xx 931`
`= 0.369 xx 931 = 343.62 MeV`
Discussion
27490.

The nuclear activity of a neutral atom and its ion is always the same.

Answer»


ANSWER :T
Discussion
27491.

The normality of orthophosphoric acid having purity of 70% by weight and specific gravity 1.54 is :

Answer»

11N
22N
33N
44N

SOLUTION :Equivalent weight of orthophosphoric acid`(H_3PO_4)`
`=(3+31+64)/3 = 98/3`
Now 100 G solution contains 70 g `H_3PO_4`
`100/(1000 xx1.54)` litre of solution contains `70/(98//3) g`
equivalent of `H_3PO_4`
Normality of solution
`=((70 xx3)/98)/(1/(10xx1.54))=(70xx3)/98xx10xx1.54 =33N`
Discussion
27492.

The normality of a mixture of HCI and H_2 SO_4 solution is N/5 Now, 0.287 g of AgCI is obtained when 20 ml of the solution is treated with excess of AgNO_3.The percentage of both acids in the mixture will be?

Answer»

`HCI = 32.44%, H_2 SO_4 = 67.56%`
`HCI = 42.69%, H_2 SO_4= 57.31%`
`HCI= 48.75%, H_2 SO_4 = 51.25%`
`HCI=92.51%, H_2 SO_4 = 7.49%`

ANSWER :B
Discussion
27493.

The normality of a solution of sodium hydroxide 100 ml of which contains 4 grams of NAOH is

Answer»

`0.1`
40
`1.0`
`0.4`

Solution :`N=(W xx 1000)/(eq.wt. xx "VOLUME in ml.") = (4xx1000)/(40xx100)=1.0 N`.
Discussion
27494.

The normality of a solution containing 60 g of CH_3COOH per litre is

Answer»

`1.5 N`
`2N`
`0.5N`
1N

Answer :D
Discussion
27495.

The normality of '30 volume H_(2)O_(2)is

Answer»

2.678 N
5.336 N
8.0334 N
6.685 N

Solution :VOLUME strength `=5.6xx` normality
`30=5.6xx` normality
`"Normality "=(30)/(5.6)=5.3`
Discussion
27496.

Thenormality of 10% (weight/volume) acetic acid is

Answer»

1 N
10 N
1.66 N
0.83 N

Solution :Normality `= (w)/(E.V) = (10G)/(100 mL)xx(1)/(60)`
`= (10g)/((100)/(1000)xx60) = 1.66 N`
Discussion
27497.

The molal freezing point constant for water is 1.86 K.kg "mole"^(-1). The freezing point of 0.1m NaCl solution is

Answer»

`-1.86^@C`
`-0.372^@C`
`-0.186^@C`
`0.372^@C`

ANSWER :B
Discussion
27498.

The normalityof 2.3 MH_(2)SO_(4) solution is

Answer»

2.3 N
4.6 N
0.46 N
0.23 N

Solution :NORMALITY of `2.3 M H_(2)SO_(4)=M XX` Valency
`=2.3xx2=4.6 N`
Discussion
27499.

The normality of 2% H_(2)SO_(4) (wt/vol) is nearly

Answer»

0.02 N
0.04 N
0.2 N
0.4 N

Solution :AMOUNT of `H_(2)SO_(4)=2G`.
Equivalents of `H_(2)SO_(4)=2/49`
Normality `=(2)/(49)xx(1000)/(100)=0.408=0.4N`
Discussion
27500.

The molal elevation/depression constant depends upon :

Answer»

NATURE of SOLVENT
Nature of solute
Temperature
`DELTAH` solution

Answer :A
Discussion