This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 27701. |
The Nernst equation for the reduction potential of a non metal A when [A^(n-)] = C is given by |
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Answer» `E^(0) + (0.059)/(n) log C ` |
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| 27702. |
The method used to distinguish optical isomers is |
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Answer» polarimetry |
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| 27703. |
The nernst equation,E = E ^(o) - (RT)/(nF) ln Q indicates that the equilibrium constant K_(C) will be equal to Q when: |
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Answer» `E= E^(o)` |
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| 27704. |
The method used for prepare steel is |
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Answer» Bessemer's convertor method |
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| 27705. |
The Nernst equation , E = E^(0) -(RT)/(nF) . In Q indicatesthat the equilibrium constant K_(c) will be equal to Q when : |
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Answer» `E=E^(0)` |
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| 27706. |
The negative value of electron gain enthalpy is less for fluorine than for chlorine. |
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Answer» SOLUTION :Due to small size the electron-electron repulsions in the relatively compact (small) 2p-subshell of F are comparatively LARGE and hence the incoming electron is not ACCEPTED with the same ease as is the case with the relatively bigger 3p subshell of CI atom. Consequently, the energy released during FORMATION of `F^(-)`(G) form F(g) is little less than during the formation of `CI^(-)`(g) from CI (g) `F(g) + e^(-) rarr F^(-)(g), Delta_(eg) = -333 kJ mol^(-1) and CI(g) + e^(-) rarr CI^(-)(g), Delta_(eg) = -349 kJ mol^(-1)` Thus, negative electron gain enthalpy of F is lower than that of Cl. |
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| 27707. |
The method of zone refining of metals is based on the principle of: |
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Answer» GREATER mobility of the pure metal than that of impurity |
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| 27708. |
The negative value for slope of the graph of concentration of reactant [R]tot indicates……. |
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Answer» ZERO ORDER REACTION |
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| 27709. |
The method of zone refining of metals is based on the priniciple of |
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Answer» GREATER solubility of the impurities in the molten state than in the solid |
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| 27710. |
The negative part of the addendum (the molecule to be added adds on to the carbon atom of the double bond containing the least number of hydrogen atoms. This rule is known as |
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Answer» SAYTZEFF's rule |
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| 27711. |
The methodof zonerefining ofmetals is basedon the principleof |
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Answer» greater mobilityof the puremetalthan that ofthe impurity. |
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| 27712. |
"The negative part of addenda adds on to the carbon atom linked with least number of hydrogen atoms" This statement is called |
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Answer» Thiele's principle<BR>Baeyer's STRAIN theory |
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| 27713. |
The method of zone refining of metals is based on the principle of |
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Answer» greater mobility of pure metal than that of impurity |
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| 27714. |
"The negative part of the addendum adds on the carbon atom joined to the least number of hydrogen atoms." This statement is called: |
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Answer» MARKOWNIKOFF's rule |
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| 27715. |
The negative part of an addendum adds on to that carbon atoms which is joined to the least number of hydrogen atoms. This statement is called |
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Answer» Thiele's THEORY |
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| 27716. |
The method of zone refining of metals is based on the principle of :- |
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Answer» GREATER mobility of the pure METAL than that of IMPURITY |
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| 27717. |
The negative part of an addendum adds on to the carbon atom joined to the least number of hydrogen atoms. This statement is called |
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Answer» Thiele's theory Markownifoff's rule is based on the STABILITY of CARBOCATIONS `(3^(@) gt 2^(@) gt 1^(@) gt ` methyl). |
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| 27718. |
The negative inductive effect is shown by : |
| Answer» Answer :B | |
| 27719. |
The method of zonc refining of metals is based on the principle of |
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Answer» GREATER mobility of the pure metal than that of the impurity |
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| 27720. |
The negative electron gain enthalpy values of N, O, S and Cl are in the order: |
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Answer» O < CL < N < S |
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| 27721. |
The negative E^(@) values shows that the reactoins are ....................... . |
| Answer» SOLUTION :Non-spontaneous | |
| 27722. |
The method of preparing an optically active compound from symmetric molecules under the influence of some optically active substance is called : |
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Answer» Resolution |
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| 27723. |
The negative electron gain enthalpy values of halogens follows the order: |
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Answer» 1.F,CL,BR, I |
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| 27724. |
The necessary condition for halogenation are |
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Answer» LOW temperature |
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| 27725. |
The negative catalyst in the decomposition of H_2O_2 is .............. |
| Answer» Solution :Ethanol | |
| 27726. |
The method of choice for determining the molecular weight of polymer is: |
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Answer» Osmotic pressre |
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| 27727. |
The necessary condition for a compound to form fibre is |
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Answer» its moleculesmust be linear |
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| 27728. |
The method of choice for determining the molecular weight of a polymer is |
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Answer» OSMOTIC pressure |
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| 27729. |
The necessary and sufficient condition for a molecule to exhibit optical activity is _________. |
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Answer» molecular symmetry |
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| 27730. |
The method not used in metallurgy to refine the impure metal is ....... |
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Answer» MOND's PROCESS |
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| 27731. |
The nearest neighbouring silver atoms in the silver crystals are 2.87 xx 10^(-10) m apart. What is the density of silver ? Silver crystallises in fcc form. [Atomic mass of Ag = 108] |
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Answer» Solution :Nearest neighbours if fcc crystal `=(1)/(2)XX" FACE diagonal"=(1)/(2)(sqrt2a)` `"or"2.87xx10^(-10)m=(a)/(sqrt2)` `"or"a=2.87xx1.414xx10^(-10)=4.05xx10^(-10)m=4.05xx10^(-8)cm` `"orVolume "=a^(3)=(4.05)^(3)xx10^(-24)` Use the following equation to CALCULATE d `d=(zxxM)/(a^(3)xxN_(A))=(4xx108)/((4.05)^(3)xx10^(-24)xx6.023xx10^(23))=(108)/(1.008xx10)=(108)/(10.08)="10.7 G cm"^(-3)` |
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| 27732. |
The method for the purification of impure metals which I based upon the phenomenon of electrolysis is called |
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Answer» ELECTROREFINING |
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| 27733. |
The methodfor the purification of impure metals which is based upon the phenomenon of electrolysis is called : |
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Answer» ELECTROREFINING |
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| 27734. |
The natures of the oxides CrO and CrO_3, respectively |
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Answer» ACIDIC and basic |
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| 27735. |
The method for converting precipitates in to colloidal particles by stirring them in a dispersion medium in presence of electrolyte is called ........... |
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Answer» FLOCCULATION |
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| 27736. |
The nature of pi-bond present in oxy acids of Cl is |
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Answer» `ppi-ppi` BOND |
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| 27737. |
The method by which aniline cannot be prepared is ………………………………….. |
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Answer» degradation of benzamide with `Br_(2)//NaOH`<BR>potassium SALT of phthalimide treated wit chlorobenzene FOLLOWED by HYDROLYSIS with AQUEOUS NaOH solution. |
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| 27738. |
The nature of phosphine is |
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Answer» acidic |
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| 27739. |
The method commonly employed for the destruction of colloidal solution is: |
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Answer» ADDITION of electrolytes |
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| 27740. |
The nature of PbO is: |
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Answer» Basic |
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| 27741. |
The method by which aniline cannot be prepared is |
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Answer» degradation of benzamide with `Br_(2)//NaOH` |
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| 27742. |
The nature of CrO and Cr_2O_3 is respectively |
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Answer» BASIC, Amphoteric |
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| 27743. |
The metals which produce hydrogen only with very dilute nitric acid are |
| Answer» Solution :`Mg, Mn` | |
| 27744. |
The nature of foces involved in physical adsorption are ……….. |
| Answer» SOLUTION :VAN DER WALLS ISOTHERM | |
| 27745. |
The metals which cannot be obtained by electrolysis of aqueous solution of their salts are |
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Answer» Ag |
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| 27746. |
The metals which produce hydrogen only with very dilute nitric acid are: |
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Answer» Zn |
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| 27747. |
The nature of forces operating between the adsorbate and the adsorbent in the adsorption occuring at high temperature is |
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Answer» VAN DER WAALS forces |
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| 27749. |
The nature of CsAuCl_(3) is (this compound contains Au in two oxidation states and there is no Au-Au bond) : |
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Answer» diamagnetic ACCORDING to the question Au exists two oxidation STATES, i.e., Au exists in `+1" and "+3` `Au^(+)=d^(10)` `Au^(+++)=d^(8)` Both CASES exist in diamagnetic form. |
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| 27750. |
The metals near the bottom of the electro chemicals series are |
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Answer» STRONG REDUCING agents |
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