Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

27801.

The name chloromethyl acetylene implies:

Answer»

`CH_(3)-CH=CHCl`
`CICH_(2)-CH=CH_(2)`
`CH_(3)-C-=C-CI`
`CICH_(2)-C-=CH`

Answer :c,d
27802.

The name 'Blue gas' is given to :

Answer»

NATURAL gas
coal gas
producer gas
water gas

Answer :D
27803.

The n-propyl iodide is heated with aq. KOH the product obtained is

Answer»

2-propanol
1-propanol
porpene
cyclopropane

Answer :B
27804.

The name aquadag is given to the colloidal solution of

Answer»

graphite in water
platinum in water
copper in water
none of these.

Solution : AQUADAG is water BASED colloidal graphite suspension, and MAY be painted on items to avoid build up STATIC or provide electrical screening
27805.

The n+l value for the 3-p energy level is:

Answer»

4
7
3
1

Answer :A
27806.

The N-H bond in NH_3 is:

Answer»

Covalent
Ionic
Dative
Hydrogen

Answer :A
27807.

The mutual heat of neutralization of 40gm of NaOH and 60 gm CH_(3)COOH will be

Answer»

56.1 KCAL
Less than 56.1 kcal
More than 56.1 kcal
13.7 kcal

Solution :Heat of NEUTRALIZATION is less than 56.1 Kcal when a STRONG BASE and a WEAK acid reacts.
27808.

The metal which does not form ammonium nitrate by reaction with dilute nitric acid is

Answer»

Al
Fe
Pb
Mg

SOLUTION :Lead from nitric OXIDE with dil. `HNO_(3)`
`3Pb+ 8NHNO_(3) to 3Pb(NO_(3))_(2) +2NO +4 H_(2)O`
27809.

The (n+1) value for 4f-electron is:

Answer»

6
4
7
8

Answer :C
27810.

the mutual heat ofneutralusation of 40 g NaOH and 60 g CH_(3) COOH will be

Answer»

57.1 kJ
less than 57.1 kJ
more than 57.1 kJ
13.7 kJ

Solution :`40 g NaOH = 4/40` = 1 mol NaOH
` 60 g CH_(3)COOH=60/60=1 mol CH_(3) COOH`
SINCE , acetic acid a weak acid , some of the HEAT is utilised to ionsie it . Os enthalpy of neutralisation of 1 mole of NaOH by `1 mole CH_(3)` COOH is less than 57.1 KJ.
Enthalpy of neutralisation of a strang acid by a STRONG base is always 57.1 KJ.
27811.

The mutual heat of neutralisation of 40 grams NaOH and 60 grams CH_3COOH will be

Answer»

56.1 kJ
less than 56.1 kJ
more than 56.1 kJ
13.7 kJ

Answer :B
27812.

The mutarotation of glucose is characterised by

Answer»

a CHANGE from an ALDEHYDE to ketone structure
a change of specific rotation from a positive to a negative value
the PRESENCE of an intramolecular bridge structure
the IRREVERSIBLE change form `alpha`-D to the `BETA`-D form.

Answer :C
27813.

The metal which does not for a polynuclear carbonyl is

Answer»

Mn
Co
Cr
Fe

Answer :C
27814.

The muon (mu) is a subatomic particle of the lepton family which has same charge and magnetic behavioue as the electron, but has a different mass and is unstable, i.e. it disintegrates into other particles within microseconds after its creation. Here you will attempt to determine the mass of the muon using two rather different approaches. (a) the most common spontaneous disintegration reaction for the muon is: mu rarr e+bar(v)_(e)+v mu where bar(v)_(e) is the electron antineutrino and v_(mu) the muon neutrino. In a given experiment using a stationary muon, bar(v)_(e)+v mu, carried away a total energy of 2.000xx10^(-12) J, while the electron was moveing with a kinetic energy of 1.4846xx10^(-11) J. Determine the mass of the muon. (b) Many experiments have studied the spectroscopy of atoms that have captured a muon in place of an electron. These exotic atoms are formed in a variety of excited states. The transition from the third excited state to the first excited state of an atom consisiting of a ^(1)H nucleus and a muon attached it was observed at a wavelength of 2.615 nm. Determine the mass of the muon.

Answer»


Answer :{:a) Energy of a stationary muon:
`E_(mu)=m muc^(2)E_(E)+E_(V .V)`
`m_(mu)c^(2)=m_(e)c^(2)+(T_(e)+E_(v. v))`
`m_(mu)=(Me+(T_(e)+e_(V.V)))/(C^(2))=(9.109xx10^(-31)+(1.4846xx10^(-11)+2.000xx10^(-12)))/((2.998xx10^(8))^(2))`
`=1.883xx10^(-23) kg`
{:b) From Bohr theory:
`E_(n)=(me^(4))/(2n^(2)h^(2))=-109700 cm^(-)xx1/n^(2)xx(m/m_(e))`
`m=(m_(mu)m_(H))/(m_(mu)+m_(H))`
`lambda=(1)/(E_(4)-E_(2))=(1)/(109700(m/m_(e))(1/4-1/16))=2.615xx10^(-7) cm`
`m/m_(e)=185.9`
`m=185.9xx9.109xx10^(-31)=1.693xx10^(-28) kg`
The mass of a proton from Tables ATTACHED
`m_(H)=1.673xx10^(-27) kg`
`m_(mu)=(mm_(H))/(m_(H)-m)=(1.693xx10^(-28)xx1.673xx10^(-27))/(1.673xx10^(-27)-1.693xx10^(-28))=1.884xx10^(-28) kg`
27815.

The M.P. is highest for primary amides, why ?

Answer»

SOLUTION :DUE to the PRESENCE of HYDROGEN BOND.
27816.

The metal which can not displace hydrogen from dil. H_(2)SO_(4) solution is

Answer»

Zn
Al
Fe
Ag

Answer :D
27817.

The multiple 10^12has the prefix :

Answer»

peta
pico
giga
tera

ANSWER :D
27818.

The m.pt. and b.pt. is lowest for

Answer»

He
Ne
Xe
Ar

Answer :A
27819.

Themetalwhichcanbeusedtoobtainmetallic Cu fromaqueousCuSO _4solution is

Answer»

Na
AG
Hg
FE

Solution :AlthroughbothNaand FEARE moreelectropositivethatCubutNareactswith` H_2 O`and henceFeis usedtoextractCu from ` CU SO_4`
` Cu SO_4 (aq)+ Cu (s)`
27820.

The movement of dispersion medium under the influence of electric potential is called .............

Answer»

ELECTROPHORESIS
Cataphoresis
ELECTRO OSMOSIS
Electro dialysis

Solution : Electro osmosis
27821.

The movement of the molecules of the dispersion medium under the influence of an electric field and not allowing the colloidal particles to move is called………..

Answer»

SOLUTION :electro-osmosis
27822.

The movement of colloidal particles under the influence of applied electric field is called:

Answer»

DIALYSIS
TYNDALL EFFECT
Electrophoresis
Emulsion.

ANSWER :C
27823.

The most widely used antipyretic is

Answer»

SALICYLIC acid
phenacetin
PARACETAMOL
aspirin.

Solution :Most WIDELY USED ANTIPYRETIC is paracetamol.
27824.

The movement of colloidal particles under the influence of an electric field is called…………

Answer»

SOLUTION :ELECTROPHORESIS
27825.

The motion of particles in Brownian movement .........

Answer»

LINEAR
IRREGULAR curve
CONTINUOUS zig-zag
circular 

SOLUTION :continuous zig-zag
27826.

The metal which can be used to obtain metallic copper from aqueous CuSO_(4) is :

Answer»

Na
Ag
Hg
Fe

Solution :(d) SODIUM reacts with WATER violently. Both silver and mercury are weaker reducing agents than copper. Therefore, metal iron can reduce `Cu^(2+)` ions to Cu.
`Fe(s)+CuSO_(4)(aq) to FeSO_(4)(aq)+Cu(s)`
27827.

The most volatile of the following compounds is :

Answer»

n-Pentane
ISOBUTANE
2, 2-Dimethylbutane
2, 2-Dimethylpropane

ANSWER :D
27828.

The most volatile compound is :

Answer»




Solution :Most VOLATILE compound is DUE to intramolecular HYDROGEN bond.
27829.

The most volatile compound is

Answer»

2,2-dimethyl propane
2-methyl butane
Isobutane
n-pentane

Answer :A
27830.

The most useful classification of drugs for medicinal chemists is

Answer»

on the BASIS of CHEMICAL structure.
on the basis of drug action.
on the basis of molecular TARGETS.
on the basis of pharmacological effect. 

SOLUTION :on the basis of molecular targets.
27831.

The metal which can be used to obtain metallic Cu from aqueous CuSO_(4) solution is

Answer»

Na
Ag
Hg
Fe

SOLUTION :IRON DISPLACES Cu from `CuSO_(4)`.
`Fe+CuSO_(4)rarr FeSO_(4)+Cu`
27832.

The most useful classification of drugs for medicinal chemists is ______

Answer»

on the basis of chemical structure
on the basis of DRUG action
on the basis of MOLECULAR targets
on the basis of pharmacological effect

Answer :C
27833.

The most useful classification of drugs for medicinal chemists is:on the basis of chemical structure,on the basis of drug action,on the basis of molecular targets,on the basis of pharmacological effect.

Answer»

on the BASIS of chemical structure
on the basis of DRUG action
on the basis of molecular targets
on the basis of PHARMACOLOGICAL effect.

Answer :C
27834.

The most useful classification of drugs for medicinal chemists is ___ _

Answer»

on the BASIS of chemical STURCTURE
on the basis of drug action
on the basis of MOLECULAR targets
on the basis of PHARMACOLOGICAL EFFECT

Solution :The classification based on molecular targets is the most useful classification for medicinal chemists.
27835.

The most useful classification of drugfor medicinal chemistsis "……"

Answer»

on the basis of chemical structure
on the basis of drug action
on the basis of molecular targets
on the basis of pharmacological effect

Solution :Drugs can be calssified in the following ways
(a) On the basis of chemical structureDrugs have beenclassified on the basis of their chemical structurebecause drugs having common structural features often have similar pharmacological activity e.g., all SULPHONAMIDES having the common structural feature as given below are mostly antibacterial .

(b) On the basis of drug action This classification is based on the action of a drug ona particular biochemical process.
(c ) On the basis of molecular target Drugs usually interact with the biomolecules or biological macromoleules such as proteins, nucleic acid and lipids. These are called drug targets.
Drugs possessing some common strucutral features may have the same MECHANISM of action on a specific drug target. this classification is most useful for the medicinal chemists.
(d) On the basis of pharmacological effect. This classification is based upon the pharmacological effects of the drugs. It is more useful for the doctors because it provides them the whole range of drugs available for the treatment of a particular DISEASE e.g., analgesics reduce or kill pain while antiseptic either killor ARREST the growth of microorganisms.
27836.

The metal used to recover copper from a solution of copper sulphate is......

Answer»

Na
Fe
Hg
Ag

Answer :B
27837.

The most unsymmetrical and symmetrical systems are respectively.

Answer»

TETRAGONAL, cubic
triclinic, cubic
rhombohedral, hexagonal
orthorhombic, cubic

Answer :B
27838.

The most unsymmetrical crystal system is :

Answer»

cubic
hexagonal
TRICLINIC
orthorhombic

Solution :Triclinic is most UNSYMMETRICAL CRYSTAL SYSTEM.
27839.

The most unstable compound is

Answer»

2-oxobutanoic ACID
3-oxobutanoic acid
3-amino-2-butanone
2-hydroxybutanal

Answer :B
27840.

The most unlikely representation of resonance structuresof nitrophenoxide ion is

Answer»




Solution :In STRUCTURE (C) `&` N ATOMS FIVE BONDS `&` (+) CHARGED, so the structure in (c) option is not possible.
27841.

The most unlikely representation of resonance structure of p-nitrophenoxide ion is:

Answer»




ANSWER :C
27842.

Themostunlikely representation ofresonancestructuresof p- nitrophenoxideion is

Answer»




SOLUTION :INCASE of NITROGENATOM thevalenceshellcannothave more than8 electronsbecauseof ABSENCE of d- orbitalsin it.
27843.

The most unlikely representation of resonance structure of p-nitrophenoxide ion is :-

Answer»




ANSWER :D
27844.

The most unlikely repersentation of resonance structures of p-nitro phenoxide ion is ________

Answer»




ANSWER :C
27845.

The metal which can be obtained from anode mud is

Answer»

Cu
Fe
Ag
ZN

Solution :Zn
27846.

The most thermally unstable carbonate among thefollowing is

Answer»

`CaCO_3`
`MgCO_3`
`BeCO_3`
`BaCO_3`

ANSWER :C
27847.

The most suitable reagont for the following onversion is "Benzamide "overset("Reagent")to Benzylamine

Answer»

`Br_(2)+KOH`
`LiAlH_(4)`
`Conc.HNO_(3)`
`AQUEOUS KOH`

Answer :1
27848.

The metal used to recover copper from a solution of copper sulphate is

Answer»

Na
Fe
Hg
Ag

Solution :Iron can DISPLACE from `CuSO_4` solution and hence CU can be recovered from the solution by ADDING iron.
27849.

The most suitable reagent to convert primary alcohol to aldehyde

Answer»

ACIDIFIED `K_2Cr_2O_7`
ALKALINE `KMnO_4 `
`CrO_3`
PYRIDINIUM chlorochromate (PCC)

Answer :D
27850.

The metal used in storage batteries is :

Answer»

Cu
Sn
Pb
Ni

Answer :C