This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 29801. |
The IIUPAC name of C_(17)H_(35)COOH is : |
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Answer» Heptadecanoic ACID |
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| 29802. |
The I.E_(1). And the I.E_(2) in kJ mol^(-1) of a few elements designated by P,Q,R,S are shown below: Based on the above information, answer the following questions. Q. Which of the above elements forms a stable binary halide of the formula MX_(2)? |
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Answer» P |
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| 29803. |
The I.E_(1). And the I.E_(2) in kJ mol^(-1) of a few elements designated by P,Q,R,S are shown below: Based on the above information, answer the following questions. Q. Which represents a noble gas? |
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Answer» P |
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| 29804. |
The I.E_(1). And the I.E_(2) in kJ mol^(-1) of a few elements designated by P,Q,R,S are shown below: Based on the above information, answer the following questions. Q. Which of the elements is likely to be reactive non-metal? |
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Answer» P |
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| 29805. |
The I.E_(1). And the I.E_(2) in kJ mol^(-1) of a few elements designated by P,Q,R,S are shown below: Based on the above information, answer the following questions. Q. Which of the element is likely to be reactive metal? |
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Answer» P |
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| 29806. |
The I.E_(1) among group 13 members follows as |
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Answer» `BgtAlltGaltTl` |
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| 29807. |
The idea which prompted bartlett to prepare first ever compound of noble gas was: |
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Answer» High BOND energy of Xe-F |
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| 29808. |
The O-O bond length in ozone is: |
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Answer» Resonance |
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| 29809. |
The value of C-O-C angle in ether molecule is : |
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Answer» Resonance |
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| 29811. |
The +I effect is shown by: |
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Answer» `-CH_3` |
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| 29812. |
The hypothetical complex triamminediaquachloridocobalt(III) chloride can be represented as: |
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Answer» `[CoCl(NH_(3))_(3)(H_(2)O_(2))]` |
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| 29813. |
The hypothetical complex chloro-diaquatriamminecobalt (III) chloride can be represented as |
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Answer» `[COCL(NH_(3))_(3)(H_(2)O)_(2)]Cl_(2)` |
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| 29814. |
The hypothetical complex chlorodiaquatriam minecobalt (III) chloride can be presented as |
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Answer» `[CO(NH_3)_3(H_2O)_2Cl]Cl_2` |
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| 29815. |
The hydroxyl compound that gives a precipitate immediately when treated with concentrated HCl and anhydrous ZnCl_(2) is : |
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Answer» 3-methyl-2-butanol Mechanism of this reaction involves the formation of CARBOCATION and the `3^(@)` carbocation is most stable. In the above reaction `3^(@)` carbocationis formed.Hence, when hydrozyl compound is treated with conc. HCl, the precipitate of 2-chloro-2-methylbutane is formed IMMEDIATELY. |
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| 29816. |
The hydroxide with least ksp value at room temperature is: |
| Answer» Answer :D | |
| 29817. |
The hydroxide which is max. soluble in water is ? |
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Answer» `BA(OH)_2` |
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| 29818. |
The hydroxide of which metal is soluble in excess of ammonia: |
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Answer» Cr |
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| 29819. |
The hydrophobic end of lauryl sulphate is |
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Answer» `C_(17)H_(35)` |
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| 29820. |
The hydronium ion concentration in 5xx10^(-4) M aqueous solution of NaOH at 25^@C, is : |
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Answer» zero |
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| 29821. |
The hydrolysisof whichof the followinglakesthe longest time ? |
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Answer» `CH_(3) COCl` |
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| 29822. |
The hydrolysis of which compound is an example of disproportionating reaction? |
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Answer» `SCl_(4)` |
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| 29823. |
The hydrolysis of XeF_6is not a redox reaction(R) XeF_6on complete hydrolysis will give XeO_3 |
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Answer» Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A) |
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| 29824. |
The hydrolysis of TiCl_(4) in the presenceof HCl gives : |
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Answer» `TiCl_(2)` |
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| 29825. |
The hydrolysis of the salt of weak acid and strong base is known as: |
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Answer» ANIONIC hydrolysis |
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| 29826. |
The hydrolysis of the salt of strong acid and weak base is called: |
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Answer» INCREASES with concentration |
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| 29827. |
The hydrolysis of sucrose produce a mixture which is |
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Answer» Laevorotatory |
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| 29828. |
The hydrolysis of the salt of strong acid and weak base is called |
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Answer» AMPHOTERIC hydrolysis |
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| 29829. |
The hydrolysis of starchy foods begins in the mouth by enzymes present in saliva . The enzymes are |
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Answer» Amylase |
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| 29830. |
The hydrolysis of sodium carbonate involves the reaction betweem: |
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Answer» `Na^+` and water |
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| 29831. |
The hydrolysis of PCl_3 produces |
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Answer» `H_(3)PO_(3)+HCLO` |
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| 29832. |
The hydrolysis of PCl_3 produces: |
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Answer» `H_3PO_3 + HCLO` |
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| 29833. |
The hydrolysis of optically active 2- bromobutane with aqueous NaOH result in the formation of |
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Answer» `(pm)` butan - 2- ol The reaction between 2- tromobutonewith equal NaOH follows first order kinetic, i.e.,the rate of reaction depends upon the concentration of 2-brombutane (`S_N 1` MECHANISM). ![]() Since, the 2-bromobutane is OPTICALLY active than the produt is a receive mixture. This is because carbocations are as intermadiate in `S_N1` REACTIONS. Since, carbonation being `Sp^2`-HYBRIDIZED is planar species, the attack of the nucleotide on it can occur from both the face with almost case giving a 50 : 50 mixture of two enantiomes. |
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| 29834. |
The hydrolysis of optically active 2-bromobutane with aqueous NaOH results in the formation of: |
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Answer» (-)butane-2-ol RACEMIC `(+-)` butan-2-ol is FORMED. |
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| 29835. |
The hydrolysis of NCl_3 by water produces : |
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Answer» `NH_3 and HOCL` |
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| 29836. |
The hydrolysis of NCl_(3) by H_(2)O produces |
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Answer» `NH_(2)OH and HOCl` |
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| 29837. |
The hydrolysis of methyl formate in acid solution has rate expression, rete =k [HCOOCH_3][H]^+ the balanced equation being, HCOOCH_3+H_2O to HCOOH +CH_3OH. The rate law contains [H^+] though the balanced equation does not ontain [H^+] because |
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Answer» of convenience to express the rate law |
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| 29838. |
The hydrolysis of methyl formate in acid solution has rate expression : rate =k[HCOOCH_3][H^+], the balanced equation being HCOOCH_3 +H_2O to HCOOH +CH_3OH The rate law contains [H^+]though the balanced equation does not contain [H^+] though the balanced equation does not contain [H^+] because |
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Answer» more for convenience to express the rate law |
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| 29839. |
The hydrolysis of methyl cyanide in presence of acid gives : |
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Answer» Methanoic ACID |
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| 29840. |
The hydrolysis of ethyle acetate in dilute aqueous solution in the presence of a mineral acid is represented by the equation : CH_(3) COOC_(2) H_(5)+H_(2)O overset(H^(+))(rarr) CH_(3) COOH+C_(2)H_(5)OH The reaction is : |
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Answer» trimolecular |
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| 29841. |
The hydrolysis of ethyl acetate,CH_3COOC_2H_5+H_2Ooverset(H^+)rarrCH_3COOH+C_2H_5OH is: |
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Answer» FIRST order |
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| 29842. |
The hydrolysis of ethyl acetate, R-COOR^1 + H_2O overset(H^+)to RCOOH+R^1-OH is |
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Answer» first ORDER `R prop [ R COOR'] "" because [H_(2)O]` = constant `THEREFORE ` It is first order reaction |
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| 29843. |
The hydrolysis of ethyl acetat CH_3COOC_2H_5+H_2O overset(H^(+))to CH_3COOH + C_2H_5OH is a reaction of |
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Answer» FIRST order |
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| 29844. |
The hydrolysis of ester to carboxylic acid and alcohol takes place easily in presence of enzyme ………………….. |
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Answer» Esterase |
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| 29845. |
The hydrolysis of ester was carried out separately with 0.05 N HCl and 0.05 N H_2SO_4. Which of the following will be true: |
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Answer» `K_(HCI)gtK_(H_2SO_4)` |
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| 29846. |
The hydrolysis of ester in the presence of alklai solution is a ………………………………………order reaction |
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Answer» 1 |
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| 29847. |
The hydrolysis of an underline ("alkyl cyanide ")always yields formic acid. |
| Answer» SOLUTION :The HYDROLYSIS of an alkyl isocyanide alwaysyields FORMIC acid | |
| 29848. |
The hydrolysis of an ester in acid medium is first order reaction. Half life period of a first order reaction is 20 seconds. How much time will it take to complete 90% of the reaction? |
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Answer» Solution :`k=(0.693)/t_(1/2)=0.693/20=0.3465s^(-1)` If INITIAL CONCENTRATION`[R]_0`=100,[R]=100-90=10 `thereforet=2.303/k LOG ([R]_0)/([R])2.303/0.03465 log 100/10=(2.303xx1)/0.03465=66.46`SECONDS |
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| 29849. |
The hydrolysis of an ester in acid medium is first order reaction. What do you mean by a first order reaction ? |
| Answer» SOLUTION :If the RATE ofa reaction is proportional to the first power of the concentration of only one rectant,it is CALLED a first order reaction `r=K[A]^1` | |
| 29850. |
Write the relation between half lifet_(1/2)and rate constant (k)of a first order reaction . |
| Answer» SOLUTION :For a first ORDER reaction,`t_(1/2)=0.693/k`where k is the RATE constant. | |