94420 + Interview Questions in Chemistry in Class 12 Page 598 InterviewSolution

29851.	The hydrolysis of Adienosine triphisphate [ATP] to give adienosine diphosphate [ADP] is represented by ATP hArr ADP. This reaction is expthermic zero[K] . The entropy change for the reaction is 982 J/K at 310 K . The free energy for the reaction is:
Answer» `31.01` KJ `9.188`KJ `-9.188` KJ `31.012`KJ Solution :N//A

Discussion

29852.	The hydrolysis constants of two salts M_(1)X and M_(2)X formed from strong acid and week base are 10^(-6) and 10^(-3) respectively. If K_(b) = 10^(-3) OH then base strength:
Answer» `M_(1) OH LT M_(2) OH lt M_(3)OH` `M_(1) OH gt M_(2)OH gt M_(3)OH` `M_(2)OH gt M_(1)OH gt M_(2)OH` None of these Answer :C

Discussion

29853.	The hydrolysis of alkyl halides by aqueous NaOH is best termed as:
Answer» ELECTROPHILIC SUBSTITUTION reaction Electrophilic ADDITION reaction Nucleophilic addition reaction Nucleophilic substitution reaction Answer :D

Discussion

29854.	The hydrolysis constant of the salt with NO_(2)^(-) ion (K_(a) = 4.5 xx 10^(-10) for HNO_(2))
Answer» `2.22 xx 10^(-5)` `4.44 xx 10^(-5)` `2.22 xx 10^(-6)` `4.44 xx 10^(-2)` Solution :The HYDROLYSIS CONSTANT of the hydrolysis of SALT of weak acid and strong base `K_(b) = (K_(w))/(K_(a))` Hence, hydrolysis constant of salt with `NO_(2)^(-)` ion. `K_(h) = (1 xx 10^(-14))/(4.5 xx 10^(-10)) = 2.22 xx 10^(-5)`.

Discussion

29855.	The hydrolysis constant of a salt of weak acid and weak base is inversely propertional to:
Answer» DISSOCIATION CONSTANT of WEAK ACID Dissociation constant of weak base Ionic PRODUCT of water Dissociation constant of both weak acid and weak base Answer :D

Discussion

29856.	The hydrolsed of in aqueous acetone gives.
Answer» K and L Only K L and M Only M Answer :A

Discussion

29857.	The hydrogen phosphate of certain metal has formula MHPO_(4). The formula of metal chloride wouble be
Answer» `MCL` `MCl_(2)` `M_(2)Cl_(2)` `MCl_(3)` Solution :As the valency of METAL is 2 `:.` Metal CHLORINE `= MCl_(2)`

Discussion

29858.	The hydrogen phosphate of a metal has the formula M_2(HPO_4)_3, the formula of metal nitrate will be
Answer» `MNO_3` `M(NO_3)_2` `M(NO_3)_3` `M_2(NO_3)_2` ANSWER :C

Discussion

29859.	The hydrogen line spectrum does not provide evidence for the
Answer» Heisenberg's UNCERTAINTY principle Wave like properties of light diatomic nature of `H_(2)` quantized nature of ATOMIC ENERGY states. Answer :A::B::C

Discussion

29860.	The hydrogen ion concentration of a solution is 3 xx 10^-6 g ion/litre. Find its pH value
Answer» 5.523 6.523 6.477 6.3 Answer :A

Discussion

29861.	The hydrogen ion concentration of a fruit juice is 3.3xx 10^(-2) M. What is the pH of the juice ? Is it acidic or basic ?
Answer» Solution :The DEFINITION of pH is We are GIVEN `[H^(+)]=3.3xx10^(-2)` Substituting into the definition of pH, we get `pH=-log(3.3xx10^(-2))` `=-(-1.48)=1.48` SINCE the pH is LESS than 7.00, the solution is acidic.

Discussion

29862.	The hydrogen ion concentration of a buffer solution consisting of a weak acid and its salts is given by……
Answer» `[H^+]=(K_a[ACID])/([sal t])` `[H^+]=K_a[sal t]` `[H^+]=K_a[acid]` `[H^+]=(K_a[sal t])/([acid])` Solution :ACCORDING to Henderson equation `pH=pK_a+LOG""([sal t])/([acid])` i.e., `-log[H^+]=-log K_a+log""([Sal t])/([acid])` `-log[H^+]=log""([Sal t])/([acid]) times 1/K_a` `-log""1/([H^+])=log""([Sal t])/([acid]) times 1/K_a` `therefore[H^+]=K_a([sal t])/([acid])`

Discussion

29863.	The hydrogen ion concentration of a buffer solution consisting of a week acid and its salts is given by
Answer» `[H^(+)]=(K_(a)["acid"])/(["SALT"])` `[H^(+)]=K_(a)["salt"]` `[H^(+)]=K_(a)["acid"]` `[H^(+)]=(K_(a)["salt"])/(["acid"])` Solution :According to Henderson equation `pH=pK_(a)+"LOG"(["Salt"])/(["Acid"])` `i.e. -log[H^(+)]=-logK_(a)+"log"(["Salt"])/(["Acid"])` `-log[H^(+)]="log"(["salt"])/(["acid"])XX(1)/(K_(a))` `"log"(1)/([H^(+)])="log"(["salt"])/(["acid"])xx(1)/(K_(3))` `therefore [H^(+)]=K_(a)(["salt"])/(["acid"])`

Discussion

29864.	The hydrogen ion concentration of a 10^(-8)M HCl aqueous solution at 298 K (K_(w) = 10^(-14)) is
Answer» `9.525 XX 10^(-8) M` `1.0 xx 10^(-8) M` `1.0 xx 10^(-6) M` `1.0525 xx 10^(-7) M` Answer :D

Discussion

29865.	The hydrogen ion concentration of a 10^(-8) M HCl aqueous solution at 298 K (K_(w)=10^(-14)) is :
Answer» `1.05xx10^(-7)M` `9.525xx10^(-8)M` `1.0xx10^(-8)M` `1.0xx10^(-6)M` Solution :`[H^(+)]_("Total")=[H^(+)]_("ACID")+[H^(+)]_("water")` `[H^(+)]_(HCl)=10^(-8)M` Let conc. of `H^(+)` from ionisation of water `[H^(+)]_(H_(2)O)=[OH^(-)]_(H_(2)O)=X` But `[H^(+)][OH^(-)=1xx10^(-14)` `(1.0xx10^(-8)+x)(x)=1xx10^(-14)` `x^(2)+10^(-8)x - 10^(-14)=0` SOLVING for x, we get `x = 9.5xx10^(-8)` `THEREFORE [H^(+)]_("total")=1xxx10^(-8)+9.5xx10^(-8)` `=1.05xx10^(-7)M`.

Discussion

29866.	The hydrogen ion concentration of 0.1 N solution of CH_(3)COOH, which is 30% dissociated, is
Answer» 0.03 `3.0` 0.3 `30.0` Solution :`[H^(+)] = c XX alpha = 0.1 xx (30)/(100) = 0.03 M`.

Discussion

29867.	The hydrogen ion concentration of 0.1 M solution of acetic acid, which is 20% dissociated, is
Answer» 0.02 M 2 M 0.2 M 0.002 M Answer :A

Discussion

29868.	The hydrogen ion concentration of 0.001 N NaOH solution is:
Answer» `1.0xx10^(-2)` M `1.0xx10^(-11)` M `1.0xx10^(-14)` M `1.0xx10^(-12)` M Answer :B

Discussion

29869.	The hydrogen ion concentration of 0.001 M NaOH solution is
Answer» `1 xx 10^(-2)` mole/litre `1 xx 10^(-11)` mole/litre `1 xx 10^(-14)` mole/litre `1 xx 10^(-12)` mole/litre Solution :0.001 M NaOH means `[OH^(-)] = 10^(-3) , POH = 3` `PH + pOH = 14, pH = 14-3` `pH = 11, [H^(+)] = 10^(-11) "mole-litre"^(-1)`.

Discussion

29870.	The hydrogen ion concentration in weak acid of dissociation constant K_(a) and concentration c is nearly equal to (1)
Answer» `sqrt(K_(a)//c)` `c//K_(a)` `K_(a)c` `sqrt(K_(a)c)` Solution :`{:(HA,RARR,H^(+),+,A^(-)),(C(1-alpha),,C alpha,,C alpha):}` Hydrogen ion CONCENTRATION `[H^(+)] = C alpha` ....(i) By the ostwald's law `alpha= sqrt((K_(a))/(C))` ...(II) By putting this value in equation (i) we GET `rArr c xx sqrt((K_(a))/(C)) = sqrt(K_(a)C)`.

Discussion

29871.	The hydrogen ion concentration in a given solution is 6 xx 10^-4. Its pH will be:
Answer» 6 4 3.22 2 Answer :C

Discussion

29872.	The hydrogen ion concentration in a solution of weak acid of dissociation constant K_a and concentration C is nearly equal to :
Answer» `SQRT(k_c/C)` `C/K_a` `K_aC` `sqrt(K_aC)` ANSWER :D

Discussion

29873.	The hydrogen fluoride is liquid unlike the other hydrogen halides, because:
Answer» FLUORINE is smaller atom HF is weakest acid HF molecules are ASSOCIATED due to hydrogen BONDING. `F_2` is highly reactive Answer :C

Discussion

29874.	The hydrogen electrode when placed in a buffer solution of CH_3COONa and CH_3COOH in the ratio x:y and y: x has oxidation electrode potential E_ and E_ volts respectively at25^(@) C(pH_2 =1 atm) . pK_a for CH_3COOH will be :
Answer» `E_1 + E_2 ` `E_1 - E_2 ` ` (E_ 1+ E_2)/(0.0591 xx 2) ` `(E_1- E_2)/( 0.0591 xx 2)` Solution :`E =E^(0)-(0.0591)/(1) LOG""(1)/([H^(+)]) , ((-E_(RP))/(0.0591)) = log (H^(oplus)) = pt ` ` (+E_1)/(0.0591) = P^(KA) + log""(x)/(y)` .......... (1) , ` (+E_2)/(0.0591) =P^(Ka) + log""(y)/(x) ` ......... (2) from (1) & (2) `(+E_1 + E_2)/(0.0591) = 2P^(Ka) + log((x)/(y)) + log((y)/(x)) + ((E_1 + E_2)/(0.0591)) = 2P^(Ka) + log""((x)/(y) xx (y)/(x)) , P^(Ka) = + ((E_1 + E_2)/(2 xx 0.0591))`

Discussion

29875.	The hydrogen electrode is dpped in a solution of pH=3 at 25^(@)C. The potential of the cell would be (the value of 2.303RT/F is 0.059V)
Answer» 0.177V `-0.177V` `0.087V` `0.059V` SOLUTION :REDUCTION POTENTIAL of hydrogen electrode. `E_(H)=(-2.303RT)/(F)"log"(1)/([H^(+)])` `=-0.059pH=-0.059xx3=-0.177V`.

Discussion

29876.	The hydrogen electrode is dipped in solution of pH =3 at 25^@C.The reduction potential of the cell would be:
Answer» `0.177V` `-0.177V` `0.087V` `0.059V` ANSWER :B

Discussion

29877.	The electrode potential of normal hydrogen electrode is
Answer» `0.177V` `-0.177V` `0.087V` `0.059V` ANSWER :B

Discussion

29878.	The hydrogen electrode is dipped in a solution of pH=3 at 25^(@)C. The potential of the cell would be (the value of 2.303 RT/F is 0.059 V)
Answer» 0.177 V 0.087 V `-0.177`V 0.059 V Answer :C

Discussion

29879.	The hydrogen electrode is dipped in a solution of pH 3 at 25^@C. The potential of the cell would be(2.303 RT//F = 0.059V) :
Answer» 0.177 V `-0.177V` `0.87 V` `0.059 V` ANSWER :B

Discussion

29880.	The hydrogen electrdoe is dipped in a solution of pH=3 at 25^(@)C the potential of the cell would be (the value of 2.303 RT/F is 0.059 V)
Answer» 0.177V 0.087V `-0.177V` `0.059V` Solution :`pH=3` `therefore [H^(+)]=10^(-3)` `H^(+)+e^(-)rarr(1)/(2)H_(2)` `E=E^(@)-(0.059)/(n)"LOG" (1)/([H^(+)])=0-(0.059)/(1)"log"10^(3)` ` E=-0.177V`

Discussion

29881.	The hydrogen electrode is dipped in a solution of pH 3 at 25^(@) C. The reduction potential of half cell would be :
Answer» `0.177V` `-0.177V` `0.087V` `0.059V` ANSWER :B

Discussion

29882.	The hydrogen bonds are encountered in HF, H_2 O, NH_3 and HF_2^-. The relative order of energies of hydrogen bonds is
Answer» `HF gt H_(2)O gt H_(3)N gt HF_(2)^(-)` `H_(2)O gt HF_(2)^(-) gt HF gt NH_(3)` `HF gt HF_(2)^(-) gt H_(2)O gt NH_(3)` `HF_(2)^(-) gt HF gt H_(2)O gt NH_(3)` Solution :Higher is the electronegativity, stronger is the H-bond. Fluorine has more electronegativity among the GIVEN compound. In `HF_(2)^(-)` there are TWO fluorine atoms that results into EVEN stronger H-bonding.

Discussion

29883.	The hydrogen bonding is strongest in :
Answer» O-H---S S-H---O F-H---F F-H---O Answer :C

Discussion

29884.	The hydrogen bonding ability of 1^@, 2^@ and 3^@ alcohols is of the order
Answer» `3^@ GT 2^@ gt 1^@` `1^@ gt 2^@ gt 3^@` `3^@ gt 1^@ gt 2^@` `1^@ gt 3^@ gt 2^@` ANSWER :B

Discussion

29885.	The hydrogen atom in chloroform is
Answer» ACIDIC Basic Neutral None of the above Solution :Acidic.

Discussion

29886.	The hydrogen atom in chloroform is :
Answer» Acidic Basic Neutral None Answer :A

Discussion

29887.	The hydrochlorides of amines form double salt with :
Answer» `PtCl_4` `AuCl_3` BOTH (A) AND (B) None Answer :C

Discussion

29888.	Explain, why hydrogen atom of chloroform is definitely acidic but that of methane is not?
Answer» Acidic Basic Neutral None Answer :A

Discussion

29889.	The hydrocarbon which decolorizes alkaline KMnO_4 solution ,but does not give any precipitate with ammoniacal silver nitrate is :
Answer» Benzene Acetylene Propyne BUTYNE -2 Answer :D

Discussion

29890.	The hydrocarbon styrene (C_(6)H_(5)CH=CH_(2)) can be prepared by the dehydrohalogenation of either 1-Bromo-2-phenylethane or 1-bromo-1-phenylethane using alcoholic KOH. Which alkyl halide will take part in the reaction?
Answer» Solution : 1-Bromo-1-pehnylethane is a secondary alkyl halide while the other is of primary NATURE. The alkene is expected to be formed by `E_(2)` elimination reaction. In this reaction, secondary alkyl halide is expected to give the desired alkene. `underset("1-Bromo-1-phenylethane")(H_(5)C_(6)-underset(Br)underset(\|)(C)H-CH_(3))+KOH(alc)tounderset("Styrene")(C_(6)H_(5)-CH=CH_(2)+KBr+H_(2)O`

Discussion

29891.	The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is
Answer» pentane 2 - methylbutane 2, 2- dimethylpropane none of the above Answer :C

Discussion

29892.	The hydrocarbon (molecular mass = 70) after reduction and chlorination gives a single monochloride . The hydrocarbon is
Answer» PENT - 1- ENE pent - 2- ene 1,1 - dimethylcycloprop -1 - ene cyclopentane Answer :A

Discussion

29893.	The hydrocarbon containing continuous chain which is isomeric with 2-methyl-3 ethylhexane is :
Answer» Hexane Octane Nonane Decane Answer :C

Discussion

29894.	The hydrides of the first elements in groups 15-17, namely NH_3, H_2O and HF respectively show abnormally high values for melting and boiling points. This is due to
Answer» Small size of N, O and F the ability to form extentsive intermolecular H-BONDING the ability to form EXTENSIVE INTRAMOLECULAR H - bonding effectiv van der Waals'interaction. Solution :`{:("ATOM","Electronegativity in Pauling scale"),(F,4.0),(O,3.5),(N,3.0):}` Thus, `NH_3, H_2O` and HF can form extensive intermolecular H-bonding.

Discussion

29895.	The hydride with more basic nature is
Answer» `PH_3` `NH_3` `BiH_3` `AsH_3` ANSWER :B

Discussion

29896.	The hydride of group 16 elements which shows greater Lewis base character
Answer» `H_2O` `H_2Te` `H_2S` `H_2Se` ANSWER :A

Discussion

29897.	The hydride of goup 16 elements showing maximum tendency for complex formation is
Answer» `H_(2)O` `H_(2)S` `H_(2)Se` `H_(2)Te` Solution :Oxygen due to its SMALLER size has more ELECTRON DENSITY in `H_(2)O` and thus has more tendency to donate its LONE pair for complex FORMATION.

Discussion

29898.	The hydration of ionic compounds involves :
Answer» Evolution of heat Weakening of ATTRACTIVE FORCES of IONS Dissociation into ions All of these Answer :D

Discussion

29899.	The hydration energy of Mg^(2+) is greater than that of :
Answer» `Al^(3+)` `NA^(+)` `Be^(2+)` `MG^(3+)` ANSWER :B

Discussion

29900.	The hydration energy of Mg^(2+) ions is lesser than that of:
Answer» `AL^(3+)` `Ba^(2+)` `Na` NONE of these Answer :A

Discussion

Explore topic-wise InterviewSolutions in .

The hydrolysis of Adienosine triphisphate [ATP] to give adienosine diphosphate [ADP] is represented by ATP hArr ADP. This reaction is expthermic zero[K] . The entropy change for the reaction is 982 J/K at 310 K . The free energy for the reaction is:

The hydrolysis constants of two salts M_(1)X and M_(2)X formed from strong acid and week base are 10^(-6) and 10^(-3) respectively. If K_(b) = 10^(-3) OH then base strength:

The hydrolysis of alkyl halides by aqueous NaOH is best termed as:

The hydrolysis constant of the salt with NO_(2)^(-) ion (K_(a) = 4.5 xx 10^(-10) for HNO_(2))

The hydrolysis constant of a salt of weak acid and weak base is inversely propertional to:

The hydrolsed of in aqueous acetone gives.

The hydrogen phosphate of certain metal has formula MHPO_(4). The formula of metal chloride wouble be

The hydrogen phosphate of a metal has the formula M_2(HPO_4)_3, the formula of metal nitrate will be

The hydrogen line spectrum does not provide evidence for the

The hydrogen ion concentration of a solution is 3 xx 10^-6 g ion/litre. Find its pH value

The hydrogen ion concentration of a fruit juice is 3.3xx 10^(-2) M. What is the pH of the juice ? Is it acidic or basic ?

The hydrogen ion concentration of a buffer solution consisting of a weak acid and its salts is given by……

The hydrogen ion concentration of a buffer solution consisting of a week acid and its salts is given by

The hydrogen ion concentration of a 10^(-8)M HCl aqueous solution at 298 K (K_(w) = 10^(-14)) is

The hydrogen ion concentration of a 10^(-8) M HCl aqueous solution at 298 K (K_(w)=10^(-14)) is :

The hydrogen ion concentration of 0.1 N solution of CH_(3)COOH, which is 30% dissociated, is

The hydrogen ion concentration of 0.1 M solution of acetic acid, which is 20% dissociated, is

The hydrogen ion concentration of 0.001 N NaOH solution is:

The hydrogen ion concentration of 0.001 M NaOH solution is

The hydrogen ion concentration in weak acid of dissociation constant K_(a) and concentration c is nearly equal to (1)

The hydrogen ion concentration in a given solution is 6 xx 10^-4. Its pH will be:

The hydrogen ion concentration in a solution of weak acid of dissociation constant K_a and concentration C is nearly equal to :

The hydrogen fluoride is liquid unlike the other hydrogen halides, because:

The hydrogen electrode when placed in a buffer solution of CH_3COONa and CH_3COOH in the ratio x:y and y: x has oxidation electrode potential E_ and E_ volts respectively at25^(@) C(pH_2 =1 atm) . pK_a for CH_3COOH will be :

The hydrogen electrode is dpped in a solution of pH=3 at 25^(@)C. The potential of the cell would be (the value of 2.303RT/F is 0.059V)

The hydrogen electrode is dipped in solution of pH =3 at 25^@C.The reduction potential of the cell would be:

The electrode potential of normal hydrogen electrode is

The hydrogen electrode is dipped in a solution of pH=3 at 25^(@)C. The potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

The hydrogen electrode is dipped in a solution of pH 3 at 25^@C. The potential of the cell would be(2.303 RT//F = 0.059V) :

The hydrogen electrdoe is dipped in a solution of pH=3 at 25^(@)C the potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

The hydrogen electrode is dipped in a solution of pH 3 at 25^(@) C. The reduction potential of half cell would be :

The hydrogen bonds are encountered in HF, H_2 O, NH_3 and HF_2^-. The relative order of energies of hydrogen bonds is

The hydrogen bonding is strongest in :

The hydrogen bonding ability of 1^@, 2^@ and 3^@ alcohols is of the order

The hydrogen atom in chloroform is

The hydrogen atom in chloroform is :

The hydrochlorides of amines form double salt with :

Explain, why hydrogen atom of chloroform is definitely acidic but that of methane is not?

The hydrocarbon which decolorizes alkaline KMnO_4 solution ,but does not give any precipitate with ammoniacal silver nitrate is :

The hydrocarbon styrene (C_(6)H_(5)CH=CH_(2)) can be prepared by the dehydrohalogenation of either 1-Bromo-2-phenylethane or 1-bromo-1-phenylethane using alcoholic KOH. Which alkyl halide will take part in the reaction?

The hydrocarbon of molecular mass 72 gives a single monochloride and two dichlorides on photochlorination is

The hydrocarbon (molecular mass = 70) after reduction and chlorination gives a single monochloride . The hydrocarbon is

The hydrocarbon containing continuous chain which is isomeric with 2-methyl-3 ethylhexane is :

The hydrides of the first elements in groups 15-17, namely NH_3, H_2O and HF respectively show abnormally high values for melting and boiling points. This is due to

The hydride with more basic nature is

The hydride of group 16 elements which shows greater Lewis base character

The hydride of goup 16 elements showing maximum tendency for complex formation is

The hydration of ionic compounds involves :

The hydration energy of Mg^(2+) is greater than that of :

The hydration energy of Mg^(2+) ions is lesser than that of: