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30951.

The degree of dissociation (alpha) of CH_(3)COOHsolution having 0.1M concentration and pKa as 6, in presence of strong acid HCl having concentration 0.1M is 10^(-x). Then what is the value of x?

Answer»


Solution :
`{:(t=0,0.1,0,0),(t=t,0.1- 0.1 alpha,0.1 alpha,(0.1 alpha + 0.1)):}`
`HCL rarr underset(0.1)(H^(+)) + underset(0.1)(Cl^(-))`
`K_(a)= (0.1 (1+ alpha) xx alpha xx 0.1)/(0.1 (1 - alpha))`
Since `alpha lt lt 1` therefore
`10^(-6) = (alpha xx 0.1)/(1)`
`alpha= (10^(-6))/(10^(-1))= 10^(-5)`
So the VALUE of x=5
Discussion
30952.

The degree of dissociation (alpha) of a weak electrolyteA_(x)B_(y) is related to Van't Hoff factor (i) by the expression ______________.

Answer»

`ALPHA =(i-1)/((x-y-1))`
`alpha=(i-1)/((x+y+1))`
`alpha=((x+y-1))/(i-1)`
`alpha=(x+y+1)/(i-1)`

ANSWER :A
Discussion
30953.

The degree of dissociation (alpha) of a weak electrolyte A_x B_y is related to Van't Hoff factor (i) by the expression

Answer»

`ALPHA=(i-1)/((x+y-1))`
`alpha=(i-1)/(x+y+1)`
`alpha=(x+y-1)/(i-1)`
`alpha=(x+y+1)/(i-1)`

ANSWER :A
Discussion
30954.

The degree of dissociation (alpha) of a weak electrolyte, A_(x)B_(y) is related to van't Hoff factor (i) by the expression

Answer»

`ALPHA=(i-1)/((X+y-1))`
`alpha=(i-1)/(x+y+1)`
`alpha=(x+y-1)/(i-1)`
`alpha=(x+y+1)/(i-1)`

Solution :`{:(A_(x)B_(y),RARR,XA^(y+),+,yB^(x-)),(1-alpha,,x alpha,,y alpha):}`
`i=1-alpha+x alpha+ y alpha`
`i=1+alpha(x+y-1)`
`alpha=(i-1)/((x+y-1))`
Discussion
30955.

The degree of dissociation (alpha) of a weak electrolyte, A_(x)B_(y) is related to van't Hoff factor (i) by the expression :

Answer»

`alpha=(x+y-1)/(i-1)`
`alpha=(x+y+1)/(i-1)`
`alpha=(i-1)/((x+y-1))`
`alpha=(i-1)/(x+y+1)`

Solution :`{:(,A_(x)B_(y),hArr,XA^(y+),+,yB^(x-)),("MOLES at EQUILIBRIUM",1-alpha,,x alpha,,yalpha):}`
TOTAL no. of moles `=1-alpha+x alpha+y alpha`
`i=(1-alpha+x alpha+y alpha)/(1)`
`:.(i-1)=alpha(x+y-1)`
`:.alpha=(i-1)/((x+y-1))`
Discussion
30956.

The degree of dissociation (alpha) can be calculated using the formula, alpha=(dt-d_(0))/((n-1)d_(0)) This formula is applicable at

Answer»

CONSTANT VOLUME and constant temperature
constant volume and VARIABLE temperature
constant PRESSURE and constant temperature
all the above conditions

Answer :C
Discussion
30957.

The degree of dissociation (alpha)of a weak electrolyte A_(x)B_(y) is related to van't Hoff factor(i) by the expression

Answer»

`ALPHA=((i-1))/((X+y-1))`
`alpha=((i-1))/((x+y+1))`
`alpha=((x+y-1))/((i-1))`
`alpha=((x+y+1))/((i-1))`

SOLUTION :`AxBy=xA^(Y+)+YB^(x-)`
`(1-alpha)=xalpha, yalpha`
`i=("No.of particles after dissociation")/("No. of particles originally present")`
`=((1-alpha)+xalpha+yalpha)/1=(1+alpha(x+y)-1)/1`
`alpha=-((1-i))/((x+y-1))`
Discussion
30958.

The degeneracy of d-orbitals is lost under: (I) Strong field ligand (II) Weak field ligand (III) Mixed field lagand (IV) Chelated Ligand field Choose the correct code:

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I, II and IV
I and II
I, II, III and IV
I, II and III

Solution :Degenerate d-orbitals undergo SPLITTING under lignd field created by STRONG, weak or MIXED LIGANDS.
Discussion
30959.

The deficiency of which vitmain causes the disease pernicious anaemia ?

Answer»
Discussion
30960.

The deficiency of which vitamin causes the disease 'pernicious anaemia' ?

Answer»

Solution :Deficiency of vitamin `B_(12)` CAUSES PERNICIOUS ANAEMIA.
Discussion
30961.

The deficiency of vitamin C causes

Answer»

scurvy
RICKETS
PYORRHEA
pernicious ANAEMIA.

Answer :A
Discussion
30962.

The deficiency of vitamin K causes

Answer»

Haemorrhage
Lengthening TIME of BLOOD clotting
Inflammation of tung
Both (1) & (2)

ANSWER :D
Discussion
30963.

The deficiency of which of the following vitamins adversely affects eye sight?

Answer»

A
D
`B_(12)`
E

Answer :A
Discussion
30964.

The deficiency of vitamin C causes………..

Answer»

SCURVY
RICKETS
pyrrohea
PELLAGRA

ANSWER :A
Discussion
30965.

The deficiencyof Vitamin B_(12)leads to Hair loss, muscle pain ?

Answer»

CONVULSIONS
BERIBERI
PERNICIOUS anaemia
pellagram

Answer :D
Discussion
30966.

The deficiency of vitamin B_1 causes which diseaes ?

Answer»

Beri-Beri
Rickets
Anaemia
Xerosis

Answer :A
Discussion
30967.

Write the chemical name of vitamin B_1 and the disease caused by its deficiency.

Answer»

Ber-Beri
Ricket
Acaemine
Xerosis

Answer :A
Discussion
30968.

The defect due to which crystal of NaCl shows yellow colour is

Answer»

FRENKEL DEFECT 
IMPURITY defect 
Schottky defect 
Metal excess defect DUE to vacancy by anion

Answer :D
Discussion
30969.

The deep green colour of compound (C ) is due to the formation of:

Answer»

a.
b.
c.
d.Both `(a)` and `(b)`.

Solution :It is an EXAMPLE of Liebermann's NITROSO REACTION (test for nitroso group or test for PHENOL).
Discussion
30970.

The deep colour produced when iodine is dissolved in a solution of potassium iodide is caused by the presence of

Answer»

`I^(+)`
`I^(-)`
`I_(3)^(-)`
`I_(2)^(-)`

Solution :`I_(2)` is more soluble in 10% AG KI solution this is due to the FORMATION of a COMPLEX tri-Iodide ion `I_(3)^(-)`is CALLED poly halide. `KI + I_(2) rarr KI_(3)^(-)`
Discussion
30971.

The deep red colour of Fe(SCN)_3 or Fe(SCN)_4^- is destroyed by addition of:

Answer»

`F^-`
`CN^-`
`SCN^-`
`FE^+`

ANSWER :A
Discussion
30972.

The deep blue complex produced by adding excess of Ammonia to CuSO_(4) solution is

Answer»

`[CU(NH_3)_2]^(2+)`
`[Cu(NH_3)_4]^(2+)`
`[Cu(NH_3)_6]^(2+)`
`[Cu(NH_3)_4]^(+)`

ANSWER :B
Discussion
30973.

The deep blue colour obtained on adding K Fe(CN), to ferrous sulphate is due to the formation of

Answer»

`FE[Fe(CN)_(6)]`
`Fe[Fe(CN)_(6)l]_2`
 `Fe_3 [Fe(CN)_(6)]_(4)`
 `Fe_4 [Fe(CN)_6]_3`

ANSWER :B
Discussion
30974.

The deep blue colour produced on adding excess of ammonia to copper sulphate solution is due to the presence of:

Answer»

`Cu^(2+)`
`Cu(NH_3)_2^(2+)`
`Cu(NH_3)_4^(2+)`
`Cu(NH_3)_6^(+2)`

ANSWER :C
Discussion
30975.

The deecreasing leaving group order of the following compounds is: i. overset(o-)(C)H_(3), ii. overset(o-)(N)H_(2), iii. overset(o-)(O)H, iv. F^(o-)

Answer»

`(i) GT (ii) gt (iii) gt (iv)`
`(iv) gt (iii) gt (ii) gt (i)`
`(ii) gt (i) gt (iii) gt (iv)`
`(ii) gt (i) gt (iv) gt (iii)`

Solution :Weaker the BASE or stonger the ACID, stonger is the leaving grouop.
`F^(o-) gt OVERSET(o-)(O)H gt overset(o-)(N) H_(2) gt C overset(H)_(3)`
Discussion
30976.

The decresing nuclephilic order of the following is: i. F_(3)CSO_(3)^(o-), ii. Cl_(3)C-COO^(o-) iii. PhSO_(3)^(o-), iv. MeSO_(3)^(o-)

Answer»

`(i) gt (II) gt (III) gt (IV)`
`(iv) gt (iii) gt (ii) gt (i)`
`(ii) gt (iv) gt (iii) gt (i)`
`(iv) gt (ii) gt (i) gt (iii)`

Solution :Same nucleophilc CENTRE, basically and nucelphilicity are same:
Nucleophilicity:
`Cl_(3)CCOO^(o-) gt MeSO_(3)^(o-) gt PhSO_(3)^(o-) gt F_(3)CSO_(3_^(o-)`
Discussion
30977.

The decresing fugacity order of the following is: i. Me_(2)N - Nme_(2), ii. MeNH-NHMe iii. H_(2)N - NH_(2), iv. NH_(3)

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`(i) GT (II) gt (III) gt (iv)`
`(iv) gt (iii) gt (ii) gt (i)`
`(iv) gt (iii) gt (i) gt (ii)`
`(iii) gt (iv) gt (ii) gt (i)`

SOLUTION :Basically and FUGACITY are reversed.
Discussion
30978.

The decreasing values of bond angles from NH_(3) to SbH_(3) down the group 15 of the periodic table is due to

Answer»

increasing bp - bp repulsion
increasing p - ORBITAL character in `sp^3`
decreasing LP - bp repulsion
decreasing ELECTRONEGATIVITY of central ATOM

ANSWER :D
Discussion
30979.

The decreasing tendency to exist in puckered 8 - membered ring structure is

Answer»

`S GT SE gt TE gt Po`
`Se gt S gt Te gt Po`
`S gt Te gt Se gt Po`
`TR gt Se gt S gt Po`

Answer :A
Discussion
30980.

The decreasing order of the first ionization energy (in kJ mol^(-1)) of He, Mg and Na is HegtMggtNa. The increasing order of the 2^(nd) ionization energy (in kJ mol^(-1)) of these elements will be

Answer»

`NaltMgltHe`
`MgltNaltHe`
`MgltHeltNa`
`NaltHeltMg`

Solution :`He : 1s^(2)underset(-1e^(-))overset(DeltaH_(1))rarr1s^(1)`
`Na:1s^(2), 2s^(2)2p^(6),3s^(1)underset(-1e^(-))overset(DeltaH_(1))rarr1s^(2), 2s^(2)2p^(6)`
`MG: 1s^(2), 2s^(2)2p^(6),3s^(2)underset(-1e^(-))overset(DeltaH_(1))rarr1s^(2),2s^(2)2p^(6),3s^(1)`
He has highest value of II IONIZATION energy due to smallest size. After removal of one electron from Na, the `Na^(+)` ion has inert GAS configuration. To remove the electron from this configuration, a very high energy than Mg.
So, the order of II ionization energy is :
`MgltNaltHe`
Discussion
30981.

Thedecreasingorderof thesizeofvoidis______.

Answer»

CUBIC GT OCTAHEDRAL gt TETRAHEDRAL gt TRIGONAL
trigonal gt tetrahedral gt octahedral gt cubic
trigonal gt octahedral gt tetrahedral gt cubic
cubic gt tetrahedral gt octahedral gt trigonal

Answer :A
Discussion
30982.

The decreasing order of the bond moment of E-H bond in NH_(3), PH_(3), AsH_(3) and SbH_(3) is given by

Answer»

`NH_(3) GT PH_(3) gt AsH_(3) gt SbH_(3)`
`SbH_(3) gt AsH_(3) gt PH_(3) gt NH_(3)`
`NH_(3) gt AsH_(3) gt PH_(3) gt SbH_(3)`
`NH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3)`

Answer :D
Discussion
30983.

The decreasing order of the basic chracter of three amines and ammonia is :

Answer»

`NH_3 GT CH_3NH_2 gtC_2H_5NH_2 gtC_6H_5NH_2`
`C_2H_5NH_2 gtCH_3NH_2 gtNH_3 gtC_6H_5NH_2`
`C_6H_5NH_2 gt C_2H_5NH_2 gtCH_3NH_2 gtNH_3`
`CH_3NH_2 gt C_2H_5NH_2 gt C_6H_5NH_2 gt NH_3`

ANSWER :B
Discussion
30984.

The decreasing order of stability of the following alkene is :

Answer»

a GT b gt c gt d
c gt d gt a gt b
a gt d gt b gt c
c gt d gt b gt a

Solution :Stability of alkene µ no. of ALPHA Hydrogen atom
Discussion
30985.

The decreasing order of strengthh of following bases is :

Answer»

`CL^-3, CH_3COO^-, NH_2^-`
`CH_3COO^- , NH_2^- , Cl^-`
`CH_3COO^- , Cl^- , NH_2^-`
`NH_2^-, CH_3COO^_ , Cl^-`

ANSWER :D
Discussion
30986.

The decreasing order of stability of oxides of halogens is :

Answer»

`"FLUORINE"gt"Chlorine"gt"IODINE"gt"BROMINE"`
`"Fluorine"gt"Chlorine"gt"Bromine"gt"Iodine"`
`"Iodine" gt"Bromine"gt"Chlorine"gt"Fluorine"`
`"Iodine"gt"Chlorine"gt"Bromine"gt"Fluorine."`

Answer :D
Discussion
30987.

The decreasing order of S_(N^(2)) reaction for the given compounds is .

Answer»

IgtIIgtIIIgtIV
IIgtIgtIIIgtIV
IVgtIIIgtIIgtI
IVgtIIIgtIgtII

Solution :The order of reactivity in `S_(N^(2))` REACTIONS is directly proportional to the magnitude of `-I` effect and INVERSELY proportional to the magnitude of steric HINDRANCE. Based UPON this, the correct order is IIgtIgtIIIgtIV
Discussion
30988.

The decreasing order of solubility of methanal (A), propanaldehyde (B), benzaldehyde ( C ) and acetophenone (D) :

Answer»

`AgtBgtCgtD`
`DgtCgtBgtA`
`DgtAgtBgtC`
`BgtAgtCgtD`

ANSWER :A
Discussion
30989.

The decreasing order of size of ions is :-

Answer»

`Br^(-) GT S^(-2) gt CL^(-) gt N^(-3)`
`N^(3-) gt S^(-2) gt Cl^(-) gt Br^(-)`
`Br^(-) gt Cl^(-) gt S^(-2) gt N^(-3)`
`N^(-3) gt Cl^(-) gt S^(-2) gt Br^(-)`

ANSWER :A
Discussion
30990.

The decreasing order of second ionisation enthalpy of K, Ca and Ba is:

Answer»

`CagtBagtK`
`BagtKgtCa`
`KgtCagtBa`
`KgtBagtCa`

ANSWER :C
Discussion
30991.

The decreasing order of rate of reaction for the following compounds towards S_(N)2Th (bimolecular nucleophilic substitution with tetrahedral intermediate) reaction is (i) CH_(3)-CH_(2)-overset(O)overset(||)C-NH_(2) (ii) CH_(3)-CH_(2)-overset(O)overset(||)C-Br (iii) CH_(3)-CH_(2)-overset(O)overset(||)C-O-overset(O)overset(||)C-CH_(2)-CH_(3) (iv) CH_(3)-CH_(2)-overset(O)overset(||)C-O-C_(2)H_(5)

Answer»

`I GT II gt III gt IV`
`II gt III gt I gt IV`
`III gt II gt IV gt I`
`II gt III gt IV gt I`

ANSWER :D
Discussion
30992.

The decreasing order of reactivity towards electrophilic substitution of the following compound is :

Answer»

`1 GT 3 gt 4 gt 2`
`4 gt 1 gt 3 gt 2`
`4 gt 1 gt 2 gt 3`
`1 gt 3 gt 4 gt 2`

Answer :C
Discussion
30993.

The decreasing order of IE_2 values in K, Ca and Ba is:

Answer»

`KgtCagtBa`
`CagtBagtK`
`BagtKgtCa`
`KgtBagtCa`

ANSWER :A
Discussion
30994.

The decreasing order offor the following compound will be

Answer»

`BltAltC`
`ALTCLTB`
`AltBltC`
`BltCltA`

SOLUTION :`BltAltC`
Discussion
30995.

The decreasing order of b.pt. or m.pt of halogens is:

Answer»

`I_2gtBr_2gtCl_2gtF_2`
`F_2gtCl_2gtI_2gtBr_2`
`Cl_2gtBr_2gtI_2gtF_2`
`F_2gtI_2gtCl_2gtBr_2`

ANSWER :A
Discussion
30996.

The decreasing order of dipole moment of the folliwng is: I. CH_(3)Cl, II. CH_(3)Br, III. CH_(3)F

Answer»

`(I) GT (II) gt (III)`
`(I) gt (III) gt (II)`
`(II) gt (I) gt (III)`
`(II) gt (III) gt (I)`

SOLUTION :NA
Discussion
30997.

The decreasing order of density of different crystals is

Answer»

f.c.c. `GT` b.c.c. `gt` SIMPLE CUBE
b.c.c. `gt` f.c.c. `gt` simple cube
simple cube `gt` f.c.c. `gt` b.c.c.
h.c.p. `gt` f.c.c. `gt` simple cube

Answer :A
Discussion
30998.

The decreasing order of bond dissociation energies of C-C,C-H and H-H bonds is

Answer»

`H-H gt -C-H gt -C-C-`
`-C-C-gt-C-HgtH-H`
`-C-Hgt-C-C-gtH-H`
`-C-C-gtH-Hgt-C-H`

Solution :The decreasing ORDER of bond DISSOCIATION ENERGIES of C-C, C-H and H-H bonds is as follows
`H-H gt-C-H gt-C-C-`
Discussion
30999.

The decreasing order of bond energies of halogens

Answer»

`F_(2) GT Cl_(2) gt Br_(2) gt I_(2)`
`Cl_(2) gt I_(2) gt Br_(2) gt F_(2)`
`Cl_(2) gtBr_(2) gt F_(2) gt I_(2)`
`Cl_(2) gt Br_(2) gt F_(2) gt I_(2)`

SOLUTION :Bond ENERGIES decreasing order `Cl_(2) gt Br_(2) gt F_(2) gt I_(2)`.
Discussion
31000.

The decreasing order of bond dissociation energy among halogens is

Answer»

`F-F GT CL -Cl gt BR gt Br gt I-I`
`Cl - Cl gt Br- Br gt I-I gt F-F`
`Cl-Cl gt Br- Br gt I-I gt F-F`
`I-I gtF-F gt Cl- Cl gt Br- Br`

ANSWER :B
Discussion