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2051.

Explain the effect of the addition of inert gas to the following equilibria : (i) at constant pressure and (ii) at constant volume . (a) H_(2(g))+Cl_(2(g)) hArr 2HCl_((g)) (b) CO_((g))+Cl_(2(g)) hArr COCl_(2(g)) (c ) N_(2)O_(4(g)) hArr 2NO_(2(g))

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Solution :(i) Le Chatelier's principle
(ii) FACTORS affecting equilibria
(iii) CHANGE in CONCENTRATION on the addition of inert gas at constant pressure
(iv) change in concentration on the addition of inert gas at constant VOLUME
(v) EFFECT of change in concentration on the equilibrium
2052.

Explain the effect of temperature on rate of reaction on the basis of collision theory.

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2053.

Alkaline earth metals are denser than corresponding alkali metsl .Comment on the statement

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Solution :(i) compariosn of nuclear CHARGE in alkaliand akaline earth metals
(ii) RELATION and comparion between nuclear chage and atomic sizeof alkali and ALKALINE earth metals
(iii) comparison of atomic mass of corresponding elements of IA and IIA
(iv) relation between mass size and DENSITY
2054.

Explain the effect of temperature and concentration on the rate of reaction by an experiment.

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2055.

Alka was making tea in a kettle. Suddenly she felt intense heat from the puff of stream gushing out of the spout of the kettle. She woundered whether the temperature of the stream was higher than that of the water boiling in the kettle . Comment.

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Solution :The temperature of both boiling WATER and steam are the same. However, steam has extra ENERGY in the form of latent heat of vaporisation. That is why, a PUFF of steam RELEASES more energy than that of boiling water.
2056.

Explain the effect of concentration on rate of reaction on the basis of collision theory.

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2057.

Explain the effect of catalyst on the rate of a reaction.

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2058.

Alcohol can be separated from water by ___________

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ANSWER :distullation
2059.

Explain the earlier attempt of classification by Lavoiser?

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Answer :Antoine Lavoiser classified the known ELEMENTS into METALS and non metals. But he was not ABLE to DULY classify metalloids.
2060.

Akshay and Sauranh are the students of class IX. They have recently studied the chapter on structure of atom in the class. Both Akshy and Saurabh were performing some activities in the science laboratory. Akshy took a plastic comb and rubbed it in his dry hair. When he brought this plastic comb (rubbed in dry hair) near tiny pieces of paper, the comb attracted the pieces of paper towards it. Mean while, Saurabh took a glass rod and rubbed it with a piece of silk cloth. When he brought this glass rod (rubbed with silk cloth) near the tiny pieces of paper, the glass rod also attracted the pieces of paper towards it (just like the plastic comb). Akshy and Saurabh had studied an instrument called electroscope in class VIII. So, they decided to make use of a positively charged electroscope having diverged leaves (or opened up leaves) in their activity. Akshy took the plastic comb (rubbed in dry hair) and touched the metal top of positively charged electroscope with it. This made the diverged leaves of electroscope to fold up. Saurabh then tool the glass rod (rubbed with silk cloth) and touched the metal top of another positively charged electroscope with it. This made the diverged leaves of the electroscope to diverge (or open up) even more. Askshy did not understand the various conclusions which could be drawn from all these observations. Saurabh explained him everthing very clearly. (a) What conclusion can be drawn from the observation that a plastic comb rubbed in dry hair and a glass rod rubbed with silk cloth, both attract tiny pieces of paper ? (b) What do the above observations tell us about the atoms present on plastic comb and glass rod ? (c) (i) What conclusion do you get from the observation that when a plastic comb rubbed in dry hair is touched with the metal top of a positively charged electroscope, then its diverged leaves fold up ? (ii) What conclusion do you get form the observation that when a glass rod rubbed with silk cloth is touched with the metal top of a positvely charged electrosope, then its leaves diverage even more ? (d) What are the two types of electric charges present in atoms as shown by the above observations ? Name the subatomic particles which carry these charges. (e) (i) Which electric charges are agained by a plastic comb on rubbing in dry hair ? (ii) Which electric charge are lost by a glass rod on rubbing with silk cloth ? (f) What values are displayed by Saurabh in this episode ?

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Solution :(a) It is a known fact that an electrically charged object can attract an uncharged object. So, both a plastic comb rubbed in dry hair and a glass rod rubbed with silk cloth are electrically charged (having ELECTRIC charges on them) due to which they attract the uncharged pieces of paper.
(b) These observations tell us that some charged particles are present in the atoms of plastic comb as well as glass rod
(c) (i) This observation shows that the charge on plastic comb is opposite to that of positively charged ELECTROSCOPE. In other words, the plastic comb rubbed in dry hair carries negative electric charge.
(ii) This observation shows that the charge on glass rod is of the same type as that of positively charged electroscope. In other words, the glass rod rubbed with silk cloth carries positive electric charge
(d) The atoms contain negative electric charges as well as positive electric charges. The subatomic particles having negative charge are electrons whereas the subatomic particles having POSITVE charge are protons. (A neutral atom contains an equal number of electrons and protons)
(e) (i) The plastic comb gain negative charges (electrons) from dry hair on rubbing
(ii) The glass rod loses negative charges (electrons) to silk cloth on rubbing
(F) The various values DISPLAYED by Saurabh are (i) Awareness that atoms contain two types of electric charges : negative (electrons), and positive (protons), and (ii) Knowledge that only loosely held negative charges (electrons) can be transferred from atoms of one substance to another by friction during rubbing (the strongly held positive charges or protons cannot be transferred by friction during rubbing).
2061.

Explain the dynamic nature of chemical equilibrium.

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2062.

Ajay and Rakesh live in Rajgarh town of Churu districk of Rajasthan. As usual, the summer in this area of Rajasthan in extremely hot. Ajay's sister is getting engaged in the month of May, Ajay's family and relatives were waiting for the guests to arrive for the engagement ceremony. They had brought a slab of ice and put it in a tub of water for cooling the warm bottles of soft drinks. Just when they had finished drinking all the cold soft drink bottles, the gruests (including would-be bridegroom) arrive. Ajay and Rakesh were in a fix because they had only warm bottles of soft drinks left with them. Ajay suggested that they should put the warm soft drink bottles in the ice cold water which they already had in the tub but Rakesh did not agree with him Rakesh quickly brought a big slab of ice from the nearby shop crushed it well. He then put the warm soft drink bottles in an empty tub and surrounded them well with crushed ice. These warm soft drink bottles got colled in a short time and were served to the guests. All the guests enjoyed cold soft drinks on a very hot day and felt refreshed. (a) What is the temperature of water formed from freshly melted ice ? (b) What is the temperature of melting ice ? (c) A person holds some ice-old water in his left hand palm and a piece of ice in his right hand palm. Which of the two will appear to be more cold and why ? (d) Explain why, the warm drink bottles could be cooled more quickly by placing them in a tub of crushed ice than in a tub of ice cold water. (e) Can you suggest another way in which the warm soft drinks can be cooled even more quickly by using ice (than by keeping the bottles in crushed ice) ? (f) What type of change of state takes place when ice is used for cooling purposes ? What is the special name of this change of state ? (g) What values are displayed by Rakesh in the episode ?

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Solution :(a) The temperature of WATER formed from the freshly melted ice is `0^(@)C`
(b) The temperature of melting ice is also `0^(@)C`
(c)The piece of ice held on the right hand palm will appear to be more cold to the person. This is because when the piece of ice held on the right hand palm starts melting, it takes the latent heat (required for melting) from the right hand palm of the person. The right hand palm loses more heat to the melting ice and hence the person feels it to be more cold. The ice cold water held in the left hand palm, however, cannot take away any latent heat (because no change in state is involved).
(d) The warm soft drink BOTTLES can be cooled more quickly by placed in crushed ice because, when the ice melts, it will take the latent heat required for melting from the soft drink bottles and the liquid contained in them. And by losing this heat, the warm soft drink bottles and the liquid contained in them. And by losing this heat, the warm soft drink bottles will get colled more quickly. But ice cold water cannot take away any latent heat of melting from warm solf drink bottles
(e) The warm solt drinks can be colled even more quickly by opening the bottles, pouring the soft drinks in jugs and placing pieces of ice in them
(f) When ice is used for cooling PURPOSES, it melts to form water. So, the change of state is from solid to liquid. The special NAME of this change of state is fusion (of ice)
(g) The values displayed by Rakesh in this episode are (i) Knowledge of latent heat of fusion of ice (ii) Application of knowledge in solving everyday problems, and (iii) Desire to prevent embarrassment to his FRIEND's family.
2063.

Explain the chemical reaction of chloride with hydrogen sulphide.

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SOLUTION :N/A
2064.

Explain the acidic nature of sulphur dioxide based on its reactivity with water.

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SOLUTION :N/A
2065.

Air shows the property of

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`N_(2)`
`O_(2)`
Both a and b
None of these

Answer :C
2066.

ExplainSuspension with example ?

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SOLUTION :HeterogenousMixture in which the soluteParticlesare BIG ENOUGHTO settledown . Example :-Paints, Dosa batter
2067.

Air is a mixture, not a compound.

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Solution :Each components present in air RETAIN their fundament PROPERTIES.
These components can be separated fairly easily by physical METHODS.
The COMPOSITION of components present in air is not FIXED.
The above properties are possessed by the mixture only. Hence, an air is a mixture, not a compound.
2068.

ExplainSaturated Solution ?

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SOLUTION :MAXIMUM QuantityofDissolvesin a givenvolumeof solventat a GIVEN TEMPERATURE .
2069.

Air is _____ .

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ANSWER :a MIXTURE
2070.

Explain representative elements?

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Answer :Elements of GROUP 1 and 2 ALSO those in groups of 13-18 are CALLED REPRESENTATIVE elements it BELONGS to metals, nonmetals and metalloids.
2071.

Air can be filled in more proportion in tyres.

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Solution :Air is a gaseous SUBSTANCE. The INTERMOLECULAR forces between the particles in gaseous FORM isnegligible. Thus, the distance between the molecules of air is very high. Air being gaseous is compressible. Thus, by APPLYING PRESSURE the molecules of air can be forced to get closer. So they can be compressed. Thus air can be filled in more proportion in tyres.
2072.

ExplainPureSubstances with example ?

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Solution : Contains ONLYONE typeof PARTICLES . Examples : PureMetals like GOLD .
2073.

(a)How many moles are present in 11.5g of sodium? (b)The mass of an atom of element (X) is 2.0xx10^(-23)g. Calculate its atomic mass.

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Solution :Gram atomic mass of Na=23g
23g of Na REPRESENT =1 MOL
11.5g of Na represent=`((1"mol")xx(11.5g))/((23.0g))=0.5"mol"`
(B) One atom of element (X) has mass=`2.0xx10^(-23)G`
`=12.044gcong12.0g`
2074.

Explain Octet rule with an example.

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Solution :The tendency of atoms to have EIGHT electrons in the VALENCE shell is known as the "Octet rule or the .Rule of eight..
Example: Sodium with atomic number 11 will readily LOOSE onc electron to attain Neon.s STABLE electronic configuration.
2075.

(a)Give one point of difference betweeen an atoms and an ion. (b)Give one example of each of polyatomic cation and a polyatomic anion. (c )Identify the correct name of FeSO_(3) from the given names-Ferrous sulphate, Ferrous sulphide, Ferrous sulphite. (d)Write the chemical formulae for the chloride the magnesium.

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Solution :(a)An atom is always NEUTRAL in the SENSE that it does not carry any charge. An ion carries either POSITIVE charge (cations) or negative charge (anion).
(b)Ammonium `(NH_(4))^(-)` ion is a polytomic cation while sulphate `(SO_(4))^(2-)` ion is a polyatomic anion.
(c)Correct CHEMICAL name of `FeSO_(3)` is ferrous sulphite.
(d)Chemical formula for the chloride of magnesium is `MgCl_(2)`.
2076.

Explain limitations of Mendelev's periodic table and why is the modern period considered an extension of Mendelev's periodic table.

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SOLUTION :Limitations of Mendelev.s periodic table-
(i) Elements with large difference in properties were included in the same group. EG. Hard metals like copper (Cu) and silver (AG) were included along with soft metals like sodium and potassium.
(ii) No proper position COULD be given to the element hydrogen. Non-metallic Hydrogen was placed along with metals like lithium, sodium and potassium.
(iii) The increasing order of atomic mass was not strictly followed throughout. Eg - Co & Ni, te & I.
(iv) No place for ISOTOPES in the periodic table.
The modern periodic table is an extension of the original mendeleev.s periodic table and is known as the long form of periodic table. Mendeleev.s initial table had 63 elements, modern table has 109 elements. It is also known important to note how the modern periodic table is arranged. Although the columns which reflect a natural order have been retained, the row.s of the modern table show elements in the order of Mendeleev.s columns. In other words the elements of what we now oall .a period. were listed vertically by Mendeleev. .Groups are now shown vertically in contrast to their horizontal format in Mendeleev.s table.
2077.

(a)Explain with the help of a labelled diagram an acitivity for the verification of law of conservation of mass. (b)Find the number of atoms present in 100g of sodium and 100g of iron. (Given that Na=23u, Fe=56u,N_(0)=6.022xx10^(23) per mole)

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Solution :(a) For ANSWER, CONSULT of sodium =3.1
(b)Gram atomic mass of sodium=23g
No. of atoms in 23g of sodium=`N_(A)=6.022xx10^(23)`
`"No. of atoms in 100g of sodium"=6.022xx10^(23)XX((100g))/((23g))=2.618xx10"atoms"`
Gram atomic mass of iron=100g
No. of atoms in 56G of iron= `N_(A)=6.022xx10^(23)`
No. of atoms in 100g of iron `=6.022xx10^(23)xx((100g))/((56g))=1.075xx10^(24)"atoms"`
2078.

Explain Le Chatelier's principle. Apply it to the following equilibria : (a) 2SO_(2(g))+O hArr 2SO_(3(g))+"Heat" (b) N_(2)O_(4(g)) hArr 2NO_(2(g))- "Heat"

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2079.

(a)Explain the disadvantage of P_2O_5 as a drying agent though it is known to be a good desiccant. (b)How can P_2O_5 be used in the preparation of SO_3 ?

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Solution :(a) `P_2O_5` is a solid and is a good desiccant since it can absorb moisture form other SUBSTANCES. However, on absorbing moisture, `P_2O_5` forms `H_3PO_4` which forms a layer on the surface. As a result of this desiccating ability decreases and hence, its use for dryiny in limited.
(b) `P_2O` is a STRONG dehydrating agent and hence, REMOVES water moleucles form inorganic COMPOUNDS. `H_2SO_4` and `HNO_3` are CONVERTED into their corresponding anhydride :
`2H_2SO_4+P_4O_10to 2SO_3+4HPO_3`
2080.

(a)Define atomic mass unit. How is it linked with relative atomic mass? (b) How do you know the presence of atoms if they do not exist independently for most of the elements?

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Solution :Atomic mass unit (u) is 1/12 of the mass of one ATOM o of C-12. Relative atomic mass of the atom of an element is the average mass of the atoms as compared to 1//12th of the mass of C-12 atom
`"Relative atomic mass of an element"=("Average mass of 1 atom of the element")/("1/12th of mass of 1 atom of C-12")`
(B)Atoms of most of the elements do not exist independently. However, they combine in specific NUMBER to form molecules or IONS which we can feel and KNOW about their presence. For example.
A molecules of `H_(2)SO_(4)`, consists of 2 atoms of H+1 atom of S+4 atoms of O
A molecules of `C_(12)H_(22)O_(11)` consists of 12 atoms of C+22 atoms of H+11 atoms of O.
Ammonium ion `(NH_(4)^(+))` consists of 1 atom of N+4 atoms of H.
2081.

Explain interconversion in the states of amtter with reference to (i) force of attraction (ii) kinetic energy of particles.

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Solution :The force of attraction among the PARTICLES of matter is called intermolecular force. The force of attraction is maximum in the solid state of amter and negligible in the GASEOUS state.
The particles of solid remain quite close to each other. This makes the solid rigid and incompressible. This makes the solid rigid and incompressible. The kinetic energy of the particles in solid is negligible. So the solid has a definite SHAPE.
In the liquid state, the intermolecular force of attraction is less as compared to solid. So the liquid does not have a definite shape but the force is strong enough to keep the liquid in BULK.
The less kinetic energ of the particles is not enough to overcome theforce of attraction.
In GAS, intermolecular force of attraction is negligible. So the particles more freely and occuyp the available space. The particles of gas have high kinetic energy. So gas does not have a definite shape nor volume.
2082.

Additon of an electrons to a uninegative ion (except to VI A group elements) is an endotherimic process whereas the formation of uninegative ion from its neutral atom is an exothermic process comment

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Solution :Addition of an electron to unine gative ioninvolveds repulsion between the electron and negatively chargedion so energy is REQUIRED to add and ELECTON to a uninegative ion hence it is endothemic process when an electorn is aded to a NEUTRAL aotm it workd towards the force of attraction exertied by the nucleus of the neutral atom and hence energy is releaaed during this process
2083.

Explain in detail the effects of changes in temperature and pressure on the states of matter.

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Solution :The effect of change of temperature on states of matter are as follows:
With the increase in temperature the kinetic energy of PARTICLES increases. The particles starts vibrating with greater speed. The energy supplied by heatovercomes the force of attraction betwen the particles.
In solids the particles leave their fixed positions and start moving more freely. A stage is reached when solid gets converted into liquid.
In liquids the particles move freely. The force of attractionbetween the particles is less as compared to solid. With the increase in teperature the particles starts moving even faster. At a certain temperature, the particles have enough energy to break FREE from the force of attraction and the liquid CHANGES in gas.
Gases on heating expands very fast. They OCCUPY all the available space. The particles have high kinetic energy and the force of attraction is negligible.
The effect of change of pressure on states of matter are as follows:
Teh effect FO change of pressure on solids and liquids is negligible.
The effect of change of pressure ongases is noticeable The particles of gas come closer.
With increase in pressue and reducing temperature, the particles of gas come closer and closer.The force of attraction increases and gas converts into liquid and then into solid.
2084.

Activated charcoal is essentially , used in water purifiers, Justify ?

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Solution :Activated charcoal is essentially used for water purification because of its adsorbing nature which is OBTAINED form destructive distillation of COCONUT charcoal. Water CONTAINS dissolved gases and suspended impurities which may IMPART foul smell to water.
Activated charcoal has high porosity and can adsorb these substances therby helping in purification process.
2085.

Explain in detail about the different peiods of the modern perioidic table

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2086.

Acids turn blue litmus paper to (a) Green (b) Red (c) Orange

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ANSWER :B
2087.

Explain how three states of matter arise due to the variation in the characteristics of the particles.

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SOLUTION :The three states of MATTER arise because of two characteristics
(i) Interparticle spaces : These are minimum in the SOLID state and maximum in the GASEOUS state.
(ii) Interparticles forces of attraction : These are maximum in the solid state and minimum in the gaseous state.
2088.

Acids in plants and animals are organic acids. Whereas Acids inrocks and minerals are.......... (a) Inorganic acids (b) Weak acids

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ANSWER :A
2089.

Explain how the denisty changes across a period from k to ni and compare it with the change down the group from k to Cs respecitively

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SOLUTION :(i) comparision between different electronentering different SHELLS
(ii) variation of nuclear charge on the SIZE of the elements from k to Ni
(III) variation of he nuclear charge on elements k to cs down the GROUP
(iv) effect of nuclear charge on size
(v) relation between mass size density
2090.

Acetone present in water can be separated by ..............

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ANSWER :DISTILLATION
2091.

Explain how it is possible to show the dynamic nature of chemical equilibrium by an experiment.

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2092.

Account for the following : (a) The temperature of water remains constant during boiling. (b) Evaporation is a surface phenomenon. (c ) The spaces between constituent particles is maximum in the gaseous state.

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Solution :(a) Once a liquid starts boiling, there is no increase in average KINETIC energy upon further heating. The heat now supplied is USED to overcome intermolecular forces only. Therefore, the temperature of water remains constant during boiling.
(b) Molecules or particles of a liquid present on the surface have an urge or desire to escape from the surface as vapours in order to increase their free movement or randomness. This is known as evaporation. THUS, evaporation is a surface phenomenon. More the surface area available more will be the RATE of evaporation.
(c ) In the gaseous state of matter the interparticle forces are the least. Therefore, interparticle spaces are the maximum.
2093.

Explain how individual gases can be separated from a gaseous mixture of O_2, H_2 and CO_2.

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Solution :When a MIXTURE of `O_2, H_2 and CO_2` is present, the mixture can FIRST be passed through KOH as it will dissolve the `CO_2`. This `CO_2` can be obtained BACK from KOH by adding dilute HCl.The left over mixture contains `O_2 and H_2`. As the molucular weight difference is HIGH, therefore, they can be separated by DIFFUSION, where `H_2`will come out first.
2094.

Account for the following : (a) When sugar crystals dissolve in water, the level of water does not rise appreciable. (b) Dogs generally hang out their tongue in summer.

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Solution :(a) Since water is a liquid, there are intermolecular spaces. Sugar particles occupy these spaces. As a RESULT, water level does not rise appreciable.
(B) For answer, consult Q. 3 (N.C.E.R.T. End Exercise). (c ) For answer, consult Q. 10 (N.C.E.R.T. In text Problems). (d) In summer, DOGS GET exahusted due to the loss of persipiration from their body. Since they are always running most of the time, they hang out their tongue.
2095.

Explain how dioxins are formed? Which plastic type they are linked to and why they are harmful to humans?

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Solution :Burning PVC PLASTIC releases dioxins which are ONE of the most dangerous CHEMICALS known to humans.
2096.

According to Newland's classification the properties of the 3rdelement will find similarity with those of the ___________element

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ANSWER :10TH
2097.

Explain gram molecular mass. How is it related to the molc and Avogadro number?

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Solution :Gram MOLECULAR mass : The molecular mass of a SUBSTANCE expressed in GRAMS is called the gram molecular mass.
Ionic COMPOUNDS do not contain molecules, therefore molecular mass of an ionic compound is its formula unit mass.
A gram molecular mass of a compound is equal to the mass of `6.022 xx 10^(23)` molecules, i.e., 1 mole of the substance.
2098.

Abhinav is a student of class IX. One day all the students were performing experiments in the science laboratory. Just then, the chemistry teacher, Mrs. Prasad, came to the laboratory. She had three beaker in her hands labelled A, B and C. All the beakers contained colourless liquids which looked exactly the same. Mrs. Prasad turned to the students and said that one of the beakers contained a pure substance whereasthe other two beakers contained solutions of the same solute in the same solvent but different concentrations. She also told the students that the weight one of the three beakers A, B and C were 110g, 120g and 100g respectively. Mrs. Prasad wanted one of the students to find out experiementally which beaker contained a pure substance and which two beakers contained solutions. She also wanted them to show experimentally two properties which could tell why the solutions are considered mixtures, even though they are homogeneous substances. Mrs. Prasad wanted one of the the students to find out experimentally which beaker contained a pure substance and which two beakers contained solutions. She also wanted them to show experimentally two properties which could tell why the solutions are considered mixtures, even though they are homogeneous substances. Mrs. Prasad allowed them to use any required apparatus from the laboratory for the purpose. Abhinav offered to perform the experiements to distinguish between the pure substance and solutions and also to show experimentally why solutions are considered mixtures. (a) What did Abhinav do to find out which of the given liquids is a pure substances and which liquids are solutions ? What were the observations made by Abhinav ? (b) Whay did Abhinav conclude form the above observations ? (c) Which property of the pure substance is exhibited by this experiment ? (d) Which properties of a solution are exhibited in this experiement ? (e) What values are displayed by Abhinav in this episode ?

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Solution :(a) Abhinav took the three liquids A,B,C and D in three different china dishes and evaporated them by heating. Abhinav observed that :
(i) The liquid in beaker A evaporated evaporated leaving behind a white 'solid' residue.
(ii) The liquid in beaker B evaporated leaving behind MUCH more quantity of white solid residue.
(iii) The liquid in beaker C evaporated completely, without leaving behind behind any residue
(b) Abhinav CONCLUDED that :
(i) Liquids A and B are solutions or mixtures (becuase they leave behind residue on evaporation)
(ii) Liquid C is a pure substance (because it EVAPORATES completely, without leaving behind any residue)
(c) The property of a pure substance exhibited by this experiement is that is pure substance cannot be separated
(c) The property of a pure substance exhibited by this experiement is that a pure substance cannot be separated into its constituents by physical methods (here evaporation)
(d) The properties of a solution exhibited in this EXPERIMENT are that :
(i) a solution can be separated into its components by physical methods (here evaporation)
(ii) a solution has a variable composition (here the two solutions contain different amounts of dissolved solids)
(e) The values displayed by Abhinav in this episode are (i) Knowledge, of pure substances and solution
(ii) APPLICATION of knowledge in solving problems, and
(iii) Boldness (to accept challenge)
2099.

Explain froth flotation process for concentrating sulpide ores.

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Solution :Froth floatation process is generally used for concentrating SULPHIDE ORES. The powered ore is taken is a tank with pine oil and water, and mixed thoroughly by blowing air. BUBBLES. Of pine oil are FORMED. The one STICKS to these bubbles and rises up while the gangue sticks to the water and settles at the bottom. The froth along with the ore is separated.
2100.

Explain froth floation process for concentrating sulphide ores.

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SOLUTION :N/A