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Water is a compound , so its composition will be fixed whether the oxygen supply is excess or not.

Since, molar mass of water (H2O) =2x1 + 16 = 18 gm

So, 2 gm of hydrogen reacts with 18 gm of water

Hence, 15 gm of hydrogen will form = (18/2 )x15=135 gm of water.

(a) The Bayer process is the principal industrial means of refining bauxite to produce alumina (aluminium oxide).

(b) Al3+ + 3e- ----> Al

(c) The equation for the action of heat on aluminium hydroxide is as follows. 2 Al (OH) ₃ → Al₂O₃ + 3H₂O

(a) The Bayer process is the principal industrial means of refining bauxite to produce alumina (aluminium oxide).

(b) Al3+ + 3e- ----> Al

(c) The equation for the action of heat on aluminium hydroxide is as follows. 2 Al (OH) ₃ → Al₂O₃ + 3H₂O

o bai questions c nahi dek raha hai Sodium k aage

option 3.

the question has asked for Au3+ /Au , so it is +ve.

mixture of ethane,propane and butane is formed.

sir I can't understand the c alpha in [H+]

KI will produce HI in presence of Sulphuric acid..

2KI + H2SO4→ 2KHSO4 + 2HI

Since H2SO4is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).

2HI + H2SO4 → I2 + SO2 + H2O

As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4is used.

A => 2B + C

p 0 0 (initial) (at t=0)

P-Po 2Po Po (final) (at t =10)

initial total pressure = P = 90mm

final total pressure = 180mm

from eq adding all presures we get total pressure = P + 2Po

P + 2Po= 180

90 + 2Po= 180

Po= 45

for A , initially pressure = P= 90

final pressure = P-Po= 90-45 = 45

rate constant (k) = 2.303 log(Pi/Pf) / t

= 2.303 log90/45 / t

=(2.303)log2/10

k = 0.069 min-1

this value of rate constant is in min-1, 1min = 60sec so

K = 0.069/60 sec-1

2 will be the correct answer....because the the negative charge can make resonance with the remaining compound and as NO2 is an electron loving group,so the charge get more stability by this group....

What number will be multiplied by itself will give 1296

Mixing solid lead nitrate and solid potassium iodide results in a change of state.

A cloudy yellow precipitate – an insoluble solid that comes from a liquid solution – forms.

thanks

1)The origin of the charge on the sol particles in most cases is due to the preferential adsorption of either positive or negative ions on their surface. The sol particles acquire electrical charge in any one or more of the following ways.

(1) Due to the dissociation of the surface molecules : Some colloidal particles develope electrical charge due to the dissociation / ionisation of the surface molecules. The charge on the colloidal particles is balanced by the oppositely charged ions in the sol. For example, an aqueous solution of soap (sodium palmitate) which dissociates into ions as,

The cations (Na+) pass into the solution while the anions have a tendency to form aggregates due to weak attractive forces present in the hydrocarbon chains.

(2) Due to frictional electrification (i) It is believed that the frictional electrification due to the rubbing of the dispersed phase particles with that of dispersion medium results in some charge on the colloidal particles.

(ii) The dispersion medium must also get some charge, because of the friction. Since it does not carry any charge, the theory does not seem to be correct.

(3) Due to selective adsorption of ions

(i) The particles constituting the dispersed phase adsorb only those ions preferentially which are common with their own lattice ions.

(ii) For example, when a small quantity of silver nitrate solution is added to a large quantity of potassium iodide solution, the colloidal particles of silver iodide adsorb from the solution to become negatively charged, (at this stage is in excess, and being common to )

But, when a small quantity of potassium iodide solution is added to a large quantity of silver nitrate solution ; the colloidal silver iodide particles adsorb from the solution to become positively charged, (at this stage is in excess and is common to ),

(iii) Depending upon the nature of charge on the particles of the dispersed phase, the colloidal solutions are classified into positively charged and negatively charged colloids.

M is iron. Its ore is rich in Fe2O3. It forms chlorides like FeCl2 and FeCl3

plz answer other ques also i need it right now

2 sigma bond and 1 pi bond

2 sigma bond and 1 pi bond

2 sigma bond and 1 pi bond

2 sigma bond and 1 pi bond

2 sigma bond and 1 pi bond

2 sigma bond 1 pi bond

2 sigma bond and 1 pi bond

2 sigma bond 1pi bond

3 sigma bond and 2 pie bond

here the answerthere all over the reaction (3 sigma bond are thereand 2 pie bond )because the single bond is always sigmaand the next bond it's pie.hope this will help you

X→443Kconc.H2SO4Y ( unsaturated compound)Z is hydrogen (Colourless gas)

X, Y and Z are alcohol, alkene and hydrogen respectively.

Suppose X is ethanol, it gives alkene on reacting with conc. H2SO4

C2H5OH (X)→443Kconc.H2SO4 C2H4(Y)

2C2H5OH→Na2C2H5O-Na++ H2(Z)

Role of sulphuric acid: It is used as a dehydrating agent in the above reaction.

Ethanoic acidreacts withethanolin the presence of concentratedsulphuric acidas a catalyst toproducethe ester, ethyl acetate.

1)Lead nitrateonheatingdecomposes toleadmonoxide, nitrogen dioxide and oxygen. NO2 is liberated, along with oxygen, as a reddish brown gas. The residue left isleadmonoxide. ... Whenheated,lead(II)nitratecrystals decompose tolead(II) oxide, oxygen and nitrogen dioxide.

2)When ferrous sulphate crystals[FeSO4.7H2O] are heated, water of crystallization is lost. And then the anhydrous salt decomposes to formred brownferric oxide [Iron(III)] , sulphur dioxide (SO2) and sulphur trioxide (SO3) gases

3)Thermal decomposition occurs.Calcium Carbonatebreaks down into Calcium Oxide and Carbon Dioxide. ...CaCO3upon heating breaks down into CO2 gas and CaO. The CO2 gas can be checked by passing it through lime water , CO2 gas will turn it milky

it is best for all student

Zinc displacescopper metal, which acts as a catalyst. (copper, silver,goldand platinum) will not react with dilute acid. They cannot displace hydrogen from the non-metal anion

sorry I didn't know

1.this is an exothermic reaction. Hence one will be able to observe a rise in temperature. 2 . there will be an evolution of hydrogen gas along with the formation of zinc sulphate

Correct answer:11.2 cc (STP) of nitrogen and 0.015 g of nitric oxide

Nitric oxide is a gas that is found naturally in the human body. This gas is important in cell signalling, by helping cells in different parts of the body talk to one another. It can prevent infections and is also important to heart health. It can increase the amount of blood pumping through your heart and the blood flow to your muscles among other things. Some bodybuilders take supplements to help their bodies increase nitric oxide levels and believe that it will improve their strength and muscle gain.

Nitrous oxide is also known as "laughing gas" because it gives some people the giggles when they inhale it. It is used by dentists to calm patients who may be anxious or nervous before a minor dental procedure. It is also used in rockets or race cars to give them more power.

1) 11.2 cc = 11.2 cm³ = 11.2 ml

so, no..of moles of N2 = 11.2 ×10-³ L/22.4 L = 0.0005 moles

in 0.015g of nitric oxide ( M = 30g) , the no. of moles will be 0.015/30 = 0.0005 moles since both the compounds have same moles

so , option 1 is correct...

1) 11.2 cm³ is 11.2/1000L, so moles will be 1/2000= 0.005moles of N2 and for nitric oxides the formula is NO(molecular mass = 30) is 0.015/30 = 0.005moles...

so, option 1 matches.. the same no. of moles for both the compound.. having 2 atoms each.

Thesea wateris first collected and it is keptforevaporation.When thewateris fully evaporated thesaltremains.By this waysaltisobtainedfromsea water.Sea water containsa large amountofcommonsaltand thesalts ofother metals dissolved in it.

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding cloud of electrons.

weight of Na2CO3=106gm/molhence moles =5.3/106=0.05moleshence molarity=moles/volume of solventhence 0.05/1=0.05M

6+3+1+5= 15.

Logic and Solution:

The reported radii of noble gas elements are "van der Waals radii", which are 40% more than the actual atomic radii. Hence neon's atomic radius must be much more than that of fluorine.

Note: It is not possible to get covalent and metallic radii for noble gases since they do not form bonds.

fluorine= 0.72A°neon= 1.60A°

At neutralisation,

25 ml N/10 NaOH≡25 ml N/10 acid

Now,

25 ml N/10 acid = 0.16 gm

So,

1000 ml N/10 acid = (0.16/25) x 1000

= 6.4 g

Therefore,

1000 ml N acid = 6.4 x 10 = 64 g

Thus, the equivalent weight of acid = 64 g

Since the acid is dibasic,

The molecular weight of acid

= 64 x 2 = 128 g

Rutherford, in this experiment, bombarded fast moving alpha (α)-particles on a thin gold foil. He observed that-

(i) Most of the fast moving α-particles passed straight through the gold foil.

(ii) Some of the α-particles were deflected by the foil by small angles.

(iii) Only one out of every 12000 particles appeared to rebound.

From the observations, Rutherford concluded that:

(i) Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected.

(ii) Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.

(iii) A very small fraction of α-particles were deflected by 1800 ,indicating that all the positive charge and mass of an atom were concentrated in a very small volume within the atom.

When sugar dissolve on water the particles of sugar are very small then the particles of water and these particles of sugar get adjusted completely this cause no rise in the level of water.

Volume bof NaOH=20 ml.

Strength of NaOH= 0.4 N

Volume of dibasic acid=40 ml.

Strength of dibasic acid= ?

So strength of dibasic acid=20x 0.4/40=0.2N

Molarity of the dibasic acid = Normality /2.

So Molarity=0.2/2=0.1 M

pH = 14 - pKb - log [(B+)/(BOH)]

V = 30 ml as answer.

eye lens- the lens focus light on the buck of retina

pupil- the size of pupil change when the light enters in the eye

cones and rods - cones are sensitive to bright light to sense colour , rods are sensitive to dim light and sense black and white