InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4051. |
How can a karate player break a pile of tiles or a slab of ice with a single blow of his hand? |
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Answer» As tiles are solids. Therefore,its particles are tightly packed. Due to which we need large amount of force to break them which is applied by karate player |
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| 4052. |
We can easily move our hand in cist, but to dothrough a solid block of wood, we need a Karate expertolish have space |
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Answer» we can move our hand in air. Howeverwecannotmove our handin a solid block because there are strong forces of attractions between particles in a solid and thereisno empty space between them. The molecules of a gas (air) have very large intermolecular spaces and negligible intermolecular forces . Hence we can easily move our hand in air , whereas the intermolecular spaces between the molecules of a solid are very small and intermolecular forces are very large . Hence , a lot of force is needed to separate the molecules of a solid and we need karate expert to break a block of wood we can move our hand in air. However we can't move our hand in a solid block because there are strong forces of attraction between them |
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| 4053. |
uestion1. What are canal rays? |
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| 4054. |
uestion1. How will you find the valencyof chlorine, sulphur andmagnesium? |
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| 4055. |
uestion 1.Why are solids rigid?The thrpp states of mattor diffor in intern |
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Answer» Solidsarerigidbecause the intermolecular forces of attraction that are present insolidsare very strong. The constituent particles ofsolidscannot move from their positions they can only vibrate from their mean positive. |
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| 4056. |
why is Chandigarh unlikely to be affected by cyclone |
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| 4057. |
From the following solid which isamorphous ?(Sodium Chloride, diamond, metals,glass) |
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Answer» glass is an example of an amorphous solid. others are examples of crystalline solids. |
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| 4058. |
Define the term 'amorphous'. |
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Answer» Ans :- Amorphous solids are the solids whose constituent particles have a completely random arrangement. Amorphous solids do not have a sharp melting point and melt over a range of temperature. These solids are isotropic in nature. Amorphous solid have elasticity, electric conductance, reflective index and rate of dissociation are the same throughout all the direction. Amorphous solid always flow very slowly therefore, amorphous solids are sometimes called pseudo solids or super cooled liquids. Amorphous solid do not have definite heat of fusion. When we cut a piece of amorphous solid cut with a sharp–edged tool, they cut into two pieces with irregular surfaces. Examples :– glass, rubber, and plastic. |
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| 4059. |
uses of amorphous solids |
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Answer» Amorphous solids such as glass and plastic are very important materials and are widely used in construction, houseware, laboratory ware etc.., Amorphous silica is likely to be the best material for converting sunlight into electricity (photovoltaic). Another well known amorphous solid is rubber which is used in making tyres shoe soles etc.., |
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| 4060. |
(i) Define the term amorphous solid. |
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Answer» An amorphous solid is any noncrystalline solid in which the atoms and molecules are not organized in a definite lattice pattern. Such solids include glass, plastic, and gel. Solids and liquids are both forms of condensed matter; both are composed of atoms in close proximity to each other. |
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| 4061. |
3. An amorphous allotrope of carbon which floats on water |
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Answer» Charcoal is an amorphous allotrope of carbon which floats on water. Please hit the like button if this helped you |
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| 4062. |
Difference between crystalline and amorphous solids |
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| 4063. |
What is the name of the compound Na2so4 |
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Answer» Ans :- Sodium sulfate is the inorganic compound with formula Na₂SO₄ as well as several related hydrates. Ty |
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| 4064. |
The crystalline salt Na2SO4 XH2O on heating loses55.9% of its mass and becomes anhydrous. Theformula of crystalline salt is(1) Na2SO45H2O(3) Na2SO4 2H20(2) Na2SO4.7H2O(4) Na2SO410H2O |
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Answer» option 4 |
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| 4065. |
66. Mno2(s)+4HCl(aq)-HeatMnCl2 (aq)+2H2+Cl2(g)The equivalent weight of MnO, in the above reaction is:(a) 23.4 (b) 33.6 (c) 43.5 (d) 53.6 |
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Answer» The oxidation state of Mn changes from (+4) to (+2) so, its valancy factor is 2 and molar mass of MnO2 is = 87g so, Equivalent weight = 87/2 = 43.5 |
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| 4066. |
Define the pajeand cla sification01 proiect |
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Answer» A problem scheduled for solution is called project. The gap between the current position and the desired position is referred to as problem and there may present some hindrance that precludes the convenient movement to fill the gap. Project is composed of set of activities that should be carried out to obtain certain objectives in a certain time and certain locality. In other words the temporary effort made to develop a unique product, service or results is said to be project. Project is referred as an investment on which resources are employed to make assets that will generate benefits over a wide period of time. Project is unique process that contains group of coordinated and controlled activities having beginning & ending dates and these activities are performed to accomplish certain objective in the light of some requirement including time, resources and cost constraints. |
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| 4067. |
100. In which of the following ores, calcinations process is not applicable?1. Caco,2. A1,0,.2H20 3. Cuco, Cu(OH), 4. ZnsTAN |
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Answer» (zns) is the following ores , calcination process is not applicable. ZnS tq |
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| 4068. |
calculate the osidation number of Mn in MnO2 |
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Answer» +4 is the correct answer of the given question oxidation number of Mn is +4 let oxidation of Mn be awe know oxidation no of Oxygen is -2 so O2= (-2)×2= -4(MnO2)=0 a+(-4)=0a= +4so oxidation no ofMn in MnO2 is +4 +4 is the correct answer |
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| 4069. |
1. Name the substance oxidised and reduced in the given reaction:MnO2 + 4HCI Heat MnCle 2H20 Cla |
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Answer» Here MnO2 is reduced to MnCl2. ie., the oxidation no.of Mn is decreased from +4 to -2. HCl is oxidised to chlorine molecule. ie.,the OXIDATION-NUMBER of chlorine is increased from -2 to 0. So MnO2 is reduced to MnCl2. HCl is oxidised to chlorine. |
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| 4070. |
8. Identify the substance oxidised and reduced in the chemical reaction:Mno2MnCl2Cl2+ Cl2 2H2O4HCI |
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Answer» In the reactionMnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O , Cl (chlorine) is the substance which is oxidized from the HCl, and it is the reducing agent for the MnO2 as well. As Cl is the oxidized substance in HCl, thus it is the oxidizing agent in the reaction. |
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| 4071. |
Identify the type of reaction in 2H2 +022H20. |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 4072. |
In which of the forwhich of the following physical state, weak Vanderwaal forces and hydrogen bonds playrole for molecular attractionsb) Liquidsc) Gasesd) Bose Einstein state10a) Solidsforro |
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Answer» iska answer (b) liquids. hoga in liquid is the right answer...... iska answer (b) liquids. hoga option B is the correct answer Liquids is the correct answer (b)liquids is the correct answer right answer is liquid Liquid is the right answer baya option b is correct answer that question In liquid is the correct answer liquids is correct answer |
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| 4073. |
Right the name of reactants and product of the following reaction. SO2+2H2S-35+2H20Tve the following any five |
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Answer» PrepSolution: The reaction SO2(g) + 2H2S(g) ⇌ 3S(s) + 2H2O(g) is the basis of a suggested method for removal of SO2 from power-plant gases. Reactants = Sulphur dioxide and Hydrogen sulphide Products = Sulphur and Water |
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| 4074. |
7. In the reaction SO, +2H,S3S +2H20 the substance oxidised is(b) SO2H2o |
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Answer» (a) H2S |
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| 4075. |
The equ e reaction SO2(3) + NO208) sO3(8) +NO(g) is 16. If1mole of each of all the four gases is taken in 1 dm3 vessel, the equilibrium concentration of NOwocld be:(a) 0.4 Mlibrium constant K. for th(b) 0.6 M(c) 1.4 M(d) 1.6 M |
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Answer» NO=1-3/5=2/5=0.4 |
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| 4076. |
14. The radii of two concentric circles are 17 cm and 10 cm. A line segment PQRS cuts the largercircle at P and S and the smaller circle at Q and R. If QR 12 cm, find the length PQ |
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Answer» Given OP = 17 cm and OR =OQ = 10 cm QR = 12 cm(We have interpreted R=12 cm as QR=12cm) To find PQ: Drop OM perpendicular to QR. Since perpendicular from center to chord bisects the chord MQ = 6 cm In triangle OMQ, MQ = 6 cm, OQ = 10cm Using Pythagoras theorem OM = square root (100 – 36) = square root (64) = 8 In triangle OMP, OM = 8 cm, OP = 17 cm using Pythagoras theorem PM = square root (289 – 64) = square root (225) = 15 cm Clearly PQ = PM – QM = 15 cm – 6 cm = 9 cm |
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| 4077. |
At 100°C and 1 atm, if the density of liquid water is 1.0 g cm-3 and that of water vapouris0.0006 g cm and that of water vapour is 0.0006 g cm 9, then the volume occupied by watermolecules in 1 litre of steam at that temperature is:(A) 6 cm3[2000](B) 60 cm(C) 0.6 cm3(D) 0.06 cm3 |
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| 4078. |
b) Discuss the kinetics of complex reaction and side reaction. |
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Answer» Aside reactionis also referred to as competingreactionwhen different compounds (B, C) compete for another reactant (A). If theside reactionoccurs about as often as the mainreaction, it is spoken of parallelreactions(especially in thekinetics, see below). |
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| 4079. |
1. (a) Derive the rate(b) Discuss the kinetics of complex reaction and side reaction.ny two of the following |
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| 4080. |
TULUIThe value of enthalpy change (AH) for the reactionC,H,OH(T) + 30,(g) →2C0,(g) + 3H,O(1),at 27°C is - 1366.5 kJ mol-! The value of internal energychange for the above reaction at this temperature will be |
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Answer» plz mark it best if it helps u |
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| 4081. |
Electron ny B65. Calculate the enthalpy change for the reaction Fe,O, + 3CO2Fe+ 3codata.2 3CO; AH 137 k]226 |
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Answer» A dash of simultaneous equationy stuff to begin, so we have 6 Fe in each of the first equations. (Fe2O3(s) + 3CO(g) => 2Fe(s) + 3CO2(g) ; Δ H = –28.0kJ) x33Fe2O3(s) + 9CO(g) => 6Fe(s) + 9CO2(g) and Δ H = –84.0kJ (Fe3O4(s) + 4CO(g) => 3Fe(s) + 4CO2(g) ; Δ H = –12.5kJ) x2 so2Fe3O4(s) + 8CO(g) => 6Fe(s) + 8CO2(g) and Δ H = –25.0kJ We know 3Fe2O3(s) is our starting product so the top reaction occurs in its original direction, and the other is reversed. 3Fe2O3(s) + 9CO(g) => 6Fe(s) + 9CO2(g)6Fe(s) + 8CO2(g) => 2Fe3O4(s) + 8CO(g) which is the same as the 3rd equation in the question. but now we know the directions. As the top equation keeps its original direction, Δ H keeps its sign. the other is reversed. it's essentially one reaction followed by the other, so -84 + 25 = -59kJ/mol |
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| 4082. |
is breaking and making of bonds in chemicalCBSE 2009hataction called? |
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Answer» The chemical reaction is a process in which two or more elements react with each other. There are two types of elements, that are reactants and products. There is also formation of bonds. The process of making of bonds is called chemical bonding and the process of breaking of bond is called chemical disassociation. please like the solution 👍 ✔️ |
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| 4083. |
68. The relationofΔΗ and Δυisrepresentedas :(CPMT 2002) |
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Answer» b... U=H-PV |
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| 4084. |
47. The enthalpy change (AH) in an endothermic reaction is:(CPMT 1998)(a) -ve(c) 0(b) + ve(d) none of these |
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Answer» B option is the correct answer. |
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| 4085. |
69. NH4CI(NH3 (g)+ HClg)when the above ronction occurs, the entropy: (CPMT 2002)(a) remains eame(c) increaseb) decrease(d) none of these |
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Answer» entropy increases as gases have more entropy than solids. option (c) |
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| 4086. |
Give reason why a paper by itself catches fire easily whereas a paper wrapped in a aluminium pipe doesn't. |
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Answer» The ignition temperature of paper is less, so it catches fire easily. It does not catch fire when wrapped around aluminium pipe because aluminium absorbs the heat, so paper does not attain its ignition temperature. |
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| 4087. |
Wavelength ofparticle A is 1A.1 fit the mass of B is 25% of that of A and velocity 75% of that of Ain comparison, what will be the wavelength of particle B?(a) 1 A(b) 3 A(c) 5.33 A(d) 0.2 A |
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| 4088. |
Which one property can be used to separate a mixture of common salt and ammoniumchloride? |
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Answer» We can separate a mixture of salt and ammonium chloride with the process called 'sublimation'. In this we take a China dish in which there is the mixture of salt and ammonium chloride. Now we have to take the funnel and invert it over the dish to cover the mixture. And now keep this China dish in a stand and heat it with the Bunsen burner. Now we can see that the ammonium chloride will be sticking onto the walls of the funnel and salt remains in the funnel. By this salt and ammonium chloride are separated. |
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| 4089. |
119 How does pressure helps en eeport,229 Gine one property of solid which liquid does not possessand one property of liquid which solid does not possess. |
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Answer» a )solid have fixed shape but liquid don't have shape they shape of vessel in which it is kept. b) liquids can flow but solid cannot flow 1)solid has the highest intermolecular force of attraction2)but liquid has a less intermolecular force of attraction compared to liquid |
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| 4090. |
11. What volume of propane is burnt for every 500 cm3 ofair used in the reaction under the same conditions?(Assuming oxygen is 1/5th of air)C3H8 + 50,- 3CO, + 4H20(2017) |
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Answer» C3H8 + 5 O2 ----> 3 CO2 propane = 1v , oxygen = 5v therefore volume of propane required = 100 cm3 |
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| 4091. |
Q18 Who deserves the main credit ofclassifying elements? |
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Answer» Earlier attempts of classification of Elements Johann Dobereiner Triad model The first attempt on classification of elements have no definite proof as early man started to classify elements based on his needs. But a scientific method of classification was first introduced by the German chemist Johann Dobereiner in 1829. He classified the elements to groups of three. It should be noticed that there was only less number of elements at that time and many were not discovered. A classification method at that time therefore really deserve appreciation. Dobereiner thus created a law based on his classification and was called Law of Triads.The name triads came as his classification included elements in a group of three. He also noticed that there was relation in the classified group. The middle element, ie, the second element was having somewhat an atomic mass which was equal to the average mass of other two elements in the group. This was the basis of Law of Triads. After the long list of classifications the works of this two scientists caused an impact on scientific world. Both came up with same work but Mendeleev was the one with dominance. These 2 personalities are given great respect in chemical world for their contributions. They worked independently and was working on the same method of classification. Dmitri Mendeleev, the German chemist was the first to publish. So the credit goes to him. The basis of their classification was increasing order of atomic weights itself. The difference was the consideration of other physical properties like melting point etc. Mendeleev published the his Law in 1869 and was followed for long time.Mendeleev's periodic lawThe properties of elements are periodic functions of their atomic weights.But this model also had its own limitations. Still all respect the hard work behind the classification method. Later this classification model which had 8 groups was replaced by modern table with 18 groups prepared by Moseley. |
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| 4092. |
In some of the reactions thallium resembles aluminium, whereas in othersit resembles with group I metals. Support this statement by giving someevidences.27 |
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Answer» ty |
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| 4093. |
cnteutatstops aballromngon the ground.Which will cause more severe burns at the same temperature steam or boiling water and why |
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Answer» Steamproducesmore severe burnsthanboiling waterbecause the LATENT HEAT ofsteamis greater thanwater. It means thatsteamhas greater heat energy thanboiling waterwhichcauses more severe burns. |
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| 4094. |
निम्नलिखित यौगिकों के 1.ए.?ह.0 नाम लिखिए.(i) CH;COOH (i) CH;—C =CH(iii) CH , OH ~(iv)HCHO |
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Answer» पहले का है ethanoic acidदूसरे का propyne 3.methanoic acid4. methanol |
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| 4095. |
WWUL conan boiling water6. Howrasedcan the boiling point of a liquid belwithout adding any impurity ? |
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Answer» Boiling point of a liquidincreases with increase in pressure. Since aliquid vaporises when molecules moves faster and farther apart but while increasing pressure, you are applying an external force o hold molecules closer to each other. The boiling point of a liquid can be increased by increasing the pressure around the liquid. This would increase the attraction and would overcome the dissipation. Pressure is directly proportional to the Temperature (the boiling point in this case). |
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| 4096. |
the boiling point of heavy water is |
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Answer» slightly more than normal water. it is equal to 101.4°C |
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| 4097. |
5. Boiling point of hard water is more than that of distilled water at the sameatmospheric pressure. Why? |
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Answer» This is because hard water contains sulphates, carbonates or bicarbonates of calcium and magnesium in it in the form of impurities. hit like if you find it useful Hello you are girl |
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| 4098. |
3.Which of the following is not the consequence of hydrogen bonding?(A) HCl is water soluble due to H-bonding(B) Glycerol is more soluble in water than in ethanol.(C) Boiling point of C,H,OH is higher than CH,-0-CH,(D) p-nitrophenol has higher boiling point than o-nitrophenol |
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Answer» option a is correct beacuse HCl has no hydrogen bonding with water as all other molecules gives in other options have H bonding |
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| 4099. |
3. Ravi wants to buy a few shirts for summer. What kind of shirts arfor summer? Cotton or Synthetic. Give reason.hat kind of shirts are bestSynthetic Fibres and Plastics |
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Answer» Cotton is best suited. We should wear cotton clothes in summer because during summers we tend to sweat a lot and cotton fabric absorbs this sweat and helps the body to cool down. Cotton clothes provide better air circulation leading to more absorption of sweat and thus gives a cooling effect to us. |
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| 4100. |
5)Identify the functional group in the followingcompounds.i) n-Propyl alcoholii) Acetyleneii) Acetone.iv) Ethyl alcohol |
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Answer» i) -OH group (alcohol) ii) >C=O group (ketone) iii) C≡C group (alkyne) iv) -OH group (alcohol) |
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