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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
What is the magnetic moment ( spin only) and hybridisation of the brown ring complex `[Fe(H_(2)O)_(5)NO]SO_(4)` ?A. `sqrt(3)BM,sp^(3)d^(2)`B. `sqrt(3)BM,d^(2)sp^(3)`C. `sqrt(15)BM,sp^(3)d^(2)`D. `sqrt(15)BM,d^(2)sp^(3)` |
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Answer» Correct Answer - 3 Number of unpaired electrons `=3` `mu_(ef f)=3.9BM` type of hybridisation `=2p^(3)d^(2)` |
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| 52. |
`[Fe(CN)_(6)]^(4-)` and `[Fe(H_(2)O)_(6)]^(2+)` are of different colours in dilute solutions why?A. `CN^(-)` is a strong field ligand and `H_(2)O` is a weak field ligand hence magnitude of CFSE is differentB. both `CN^(-)` and `H_(2)O` absorb same wavelength of energyC. complexes of weak field ligands are generally colourlessD. the sizes of `CN^(-)` and `H_(2)O` are different hence their colours are also different . |
| Answer» Correct Answer - B | |
| 53. |
`[Fe(H_(2)O)_(6)]^(3+) and [Fe(CN)_(6)]^(3-)` differ inA. Oxidation numberB. Coordination numberC. StructureD. Magnetic nature |
| Answer» Correct Answer - D | |
| 54. |
Assertion`Cu^(o+)` ion is unstable in aqueous solution, whereas `Fe^(2+)` ion is stable `Cu^(o+)` disproportionate in aqueous solution .A. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .B. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .C. If`(A)` is correct, but `( R )` is incorrect .D. Both `(A)` and `(R ) ` are incorrect . |
| Answer» Correct Answer - A | |
| 55. |
The most stable ion is .A. (a) `[Fe(C_2O_4)_3]^(2-)`B. (b) `[Fe(Cl)_6]^(3-)`C. (c) `[Fe(CN)_6]^(3-)`D. (d) `[Fe(H_2O)_6]^(3+)` |
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Answer» Correct Answer - A A more basic ligand and bidenate ligand forms a stable bond with metal ion due to chelation. |
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| 56. |
STATEMENT-1: Fe-CN bond length is smaller in `Fe(CN)_(6)^(-4)` than `Fe(CN)_(6)^(-3)` and STATEMENT-2: `Fe(CN)_(6)^(-3)` is more stable than `Fe(CN)_(6)^(-4)`A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True , Statement-2 is FalseD. Statement-1 is False , Statement-2 is True |
| Answer» Correct Answer - B | |
| 57. |
The most stable ion is .A. `[Fe(C_(2)O_(4))_(3)]^(3-)`B. `[Fe(CI)_(6)]^(3-)`C. `[Fe(H_(2)O)_(6)]^(3+)`D. `[Fe(SCN)_(6)]^(3-)` |
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Answer» Correct Answer - A A more basic ligand and bidentate ligand form stable bond with metal ion due to chelation . |
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| 58. |
Among the following, the most stable complex is (i). `[Fe(H_2O)_6]^(3+)` (ii). `[Fe(NH_3)_6]^(3+)` (iii). `[Fe(C_2O_4)_3]^(3-)` (iv). `[FeCl_6]^(3-)` |
| Answer» In each of the given complex Fe is in +3 oxidation state As `C_(2)O_(4)^(2-)` is didentate chelating ligand it forms chelate rings and hence (iii) out of complexes given above is the most stable complex. | |
| 59. |
The number of sigma and `pi`-bonds in `Fe_(2)(CO)_(9)`` respectively are .A. `22sigma` and `15pi`B. `22sigma` and `16pi`C. `23sigma` and `15pi`D. `15sigma` and `8pi` |
| Answer» Correct Answer - A | |
| 60. |
The effective atomic number of cobalt in the complex `[Co(NH_3)_6]^(3+)` isA. (a) `36`B. (b) `33`C. (c) `24`D. (d) `30` |
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Answer» Correct Answer - A EAN=at. no. of central atom - oxidation state + 2 x (no. of ligands) `=27-3+2xx6=36`. |
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| 61. |
Select the correct statementA. Potassium ferrocyanide and potassium ferricyanide can be differentiated by measuring the solid state magnetic moment.B. The complex `[Co(NH)_(3)_(5)Br]SO_(4) and [Co(NH_(3))_(5)SO_(4)]Br` can be differentiated by adding aqueous solution of barium chlorideC. The complex `[Co(NH)_(3)_(5)Cl]Br and [Co(NH_(3))_(5)Br]Cl ` can be differentiated by adding aqueous solution of silver nitrate .D. the complex `[co(NH_(3))_(6)Cl_(3)] and [Co(NH_(3))_(5)Cl]Cl_(2)` can be differentiated by measuring molar conductance. |
| Answer» Correct Answer - A::B::C::D | |
| 62. |
Effective atomic number of Fe in `Fe_(2)(CO)_(9)` isA. 35B. 36C. 37D. Cannot be calculated |
| Answer» Correct Answer - B | |
| 63. |
The effective atomic number of `Co(CO)_(4)` is 35 and hence is less stable. It attains stability byA. oxidation of CoB. reduction of CoC. dimerizationD. none |
| Answer» Correct Answer - B::C | |
| 64. |
Name the type of isomerism when ambidentate ligands are attched to central metal ion. Give two examples of ambidentate ligands. |
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Answer» Ligand having more than one different binding position are known as ambidentate ligand. E.g., SCN has two different binding positions S and N. Coordination compound containing ambidentate ligands are considered to show linkage isomerism due to presence of two different binding positions. e.g., (i) `[CO(NH_(3))_(5) SCN]^(3+)` and (ii) `[Fe(NH_(3))_(5)(NO_(2))]^(3+)` |
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| 65. |
Match the compounds given In column I with oxidation state of cabalt present in it (given in column II) and assign the correct code. A. `{:(A,B,C,D),(1,2,4,3):}`B. `{:(A,B,C,D),(4,3,2,1):}`C. `{:(A,B,C,D),(3,1,4,2):}`D. `{:(A,B,C,D),(4,1,3,2):}` |
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Answer» Correct Answer - A::B::C::D Oxidation state of CMI (central metal ion) can be calculated by considering the oxidation state of whole molecule is equal to charge present on coordination sphere. A. `[Co(NCS)(NH_(3))_(5)]SO_(3)`. Let oxidation state of `Co` is x. `x-1+5xx0= +2` `x= +2 +1= + 3` B. `[Co(NH_(3))_(4)Cl_(2)]SO_(4)` Let oxidation state of `Co=x` `rArr" "x+4xx0+2xx(-1)=+2` `rArr" "x-2=+2` `x=4` C. `Na_(4)[Co(S_(2)O_(3))_(3)]` Let oxidation state of `Co=x` `x+3xx(-2)=-4` `x-6= -4` `x=-4 +6=+2` D. `[Co(CO)_(8)]` Let oxidation state of `Co=x` `x-8xx0=0` `x=0` Hence, correct choice is (d). |
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| 66. |
Primary and secondary valencies of Cu in `[Cu(NH_(3))_(4)]SO_(4)` isA. 4,4B. 2,4C. 4,1D. 4,2 |
| Answer» Correct Answer - B | |
| 67. |
Which of the following primary and secondary valencies are not correctly marked against the compound ?A. `[Cr(NH_(3))_(6)]Cl_(3) , p = 3 , s = 6`B. `K_(2) [PtCl_(4)] , p = 2 , s = 4`C. `[Pt(NH_(3))_(2) Cl_(2)], p = 2 , s = 4 `D. `[Cu(NH_(3))_(4)]SO_(4), p = 4 , s = 4 ` |
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Answer» Correct Answer - D In `[Cu(NH_(3))_(4)]SO_(4)` primary valency is 2 and secondary valency is 4 . |
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| 68. |
On the basis of the following observations made with aqueous solutions, assign secondary valences to metals in the following compounds: |
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Answer» (i) Secondary 4 (ii) Secondary 6 (iii) Secondary 6 (iv) Secondary 6 (v) Secondary 4 |
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| 69. |
On the basis of the following observations made with aqueous solutions , assign primary and secondary valencies to metals in the following compounds . |
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Answer» Primary valency = ionizable Secondary valency = non- ionizable `PdCl_(2).4NH_(3)`, mole of AgCl precipitated =2, so it is `[Pd(NH_(3))_(4)]Cl_(2)` `NiCl_(2). 6H_(2)O`, moles of AgCl precipated = 2, so it is `[Ni(H_(2)O)_(6)]Cl_(2)` `PtCl_(4).2HCl`, mole of AgCl precipitated =0, so it is `H_(2)[PtCl_(6)]` `CoCl_(3).4NH_(3)`, mole of AgCl precipitated =1, so it is `[Co(NH_(3))_(4)Cl_(2)]Cl` `PtCl_(2).2NH_(3)`, moles of AgCl precipated =0, so it is `[Pt(NH_(3))_(2)Cl_(2)]` |
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| 70. |
A d-block element forms octahedral complex but its spin magnetic moment remains same either in strong field or in weak field ligand Which pf the following is//are correct ?A. a.Element always forms colourless comoundB. b.Number of electrons in `t_(2g)` orbitals are higher than in `e_(g)` orbitalsC. c.It can have either `d^(3)` or `d^(8)` configuration.D. d.It can have either `d^(7)` or `d^(8)` configuration |
| Answer» Correct Answer - B::C | |
| 71. |
`d_(x)2-_(y)2` orbital is involved in which of the following hybridisation ?A. `a.sp^(3)d^(3)`B. `b.dsp^(2)`C. `c.sp^(3)d^(2)`D. `d.sp^(3)d` |
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Answer» Correct Answer - B::C `sp^(3)d or dsp^(3)impliess p_(x) p_(y) p_(z) d_(z2)` `dsp^(2)implies d_(x2) -_(y2) s p_(x) p_(y) p_(z)` `sp^(3) d^(2) implies s p_(x) p_(y) p_(z) d_(x)2-y_(2) d_(z2)` `sp^(3)d^(3)implies s p_(x) p_(y) p_(z) d_(xy) d_(yz) d_(xz)` . |
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| 72. |
Give the ration of geometrical isomers in `[M(A A)_(2)b_(2)]` and optical isomers of `[M(A A)_(3)]` . |
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Answer» Correct Answer - 1 `GI=2,OI =2` Rtation `=(2)/(2) =1` . |
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| 73. |
Neither optical nor geometrical isomers can be distinguished by mass spectroscopy. Why (ii) Select the pairs of (a) Geometrical isomers,(b) Optical isomers ( c ) Identical structures (III) Which one of followig will show optical activity Identifly the type of insomerisum in (if no isomerism then indicate none |
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Answer» Since all atoms in each isomers are attached to the same other types of atoms the same fragments are expected when the molecules are split Therefore ultraviolet (UV) nuclear magnetic resonance `(NMR)` and `X` ray diffraction conductance method electrolysis method chemical method dipole magnetic and magnetic properties menthod are used to distinguish isomers (II) a Geometrical isomers are 1 and 3 4 with 6 and 8 (b) Optical isomers are 6 and 8 (c) Identical stures are 1and 2, 4, 5 and 7 (III) Optical active isomers are 2 and 3 Optical inactive isomers are (i) I it is trans and has mirror plane i. e, plane of symmetry thrugh (en) groups (ii) 5,it has plane of symmetry through the two CI atoms (iii) 4 it has centre of symmetry (iv A) Geometrical isomers (B) None (C) None (D) None (E) Optical active isomers . |
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| 74. |
Hexaammineplatinum (IV ) tetracloridoplatinate (II ) isA. `[Pt(NH_(3))_(6)[PtCl_(4)]`B. `[Pt(NH_(3))_(6)]_(2)[PtCl_(4)]`C. `[Pt(NH_(3))_(6)][PtCl_(4)]_(2)`D. `[Pt(NH_(3))_(6)]_(3)[PtCl_(4)]_(2)` |
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Answer» Correct Answer - C `[Pt(NH_(3))_(6)]^(4+)[PtCl_(4)]^(2-).` thus `[Pt(NH_(3))_(6)][PtCl_(4)]_(2).` |
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| 75. |
Backbonding involes the fomation ofA. (a) `sigma`-bondB. (b) coordinate bondC. (c) `pi`-bondD. (d) none of these |
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Answer» Correct Answer - B Backbonding involves coordinate bond formation. |
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| 76. |
Match the quantity of Column I with the quantity of Column II |
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Answer» Correct Answer - A `rarr` q, r, s; B `rarr` r, s; C `rarr` p, q, r; D `rarr` p, q |
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| 77. |
How many stereoisomers exist for the complex `[Co (en)_(2) ClNO_(2)] Br` ? |
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Answer» Correct Answer - 3 |
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| 78. |
Of the following complex ions, the one that probably has the largest overall formation constant , `K_(f)`, isA. `[Co(NH_(3))_(6)]^(3+)`B. `[Co(H_(2)O)_(6)]^(3+)`C. `[Co(NH_(3))_(2)(H_(2)O)_(4)]^(3+)`D. `[Co(en)_(3)]^(3+)` |
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Answer» Correct Answer - D (4) Chelate complex has higher stability than the similar complexes having monodentate ligands and an higher stability means higher overall formation constant. |
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| 79. |
For the complex `ML_(2) ` stepwise formation constants for `M+L hArr ML ` `M+L hArr ML_(2)` are 4 and 3 . Hence overcell stability constant for ` M +2L hArr ML_(2)` isA. 12B. 7C. `1.33`D. `0.75` |
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Answer» Correct Answer - A `M+L hArr ML, k _(1) =([ML])/([M][L])=4` `ML+L hArr ML _(2 ),K _(2)=([ML_(2)])/([ML][L])=3` `M+2L hArr ML_(2), K_(3)` `K_(3)=([ML_(2)])/([M][L]^(2))=K_(1)k_(2)=12` |
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| 80. |
`M + 4 L hArr ML_(4)` For this reaction overall stability constant `(beta _(4))` is expressed asA. `beta_(4) =[ML]//[ML_(3)][L]`B. `beta _(4) =[ML_(4)]//[ML_(3)][L]`C. `beta _(4)= [ML_(4)]//[ML_(3)][L]^(4)`D. `beta _(4) =[ML]//[M][L]` |
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Answer» Correct Answer - C For `M +4L hArr ML _(4).` the overall stability constant `(beta _(4))` is expressed as ` beta _(4) =[ML_(4)]//[M][L]^(4)` |
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| 81. |
Give the number of `3d` electrons occupied in `t_(2g)` orbitals of hydrated `Cr^(3+)` ion (octahedral) . |
| Answer» Correct Answer - 3 | |
| 82. |
Statement I `[Fe(H_(2)O)_(5)NO]SO_(4)` is paramagnetic Statement II The Fe in `[Fe(H_(2)O)_(5)NO]SO_(4)` has three unpaired electrons .A. Statement-1 is true, statement-2 is true,statement-2 is a correct explanation for statement-2B. Statement-1 is true, statement-2 is true,statement-2 is NOT a correct explanation for statement-2C. Statement-1 is true, statement-2 is falseD. Statement-1 is false, statement-2 is true. |
| Answer» Correct Answer - A | |
| 83. |
Number of unpaired electrons present in `[Ni(H_(2)O)_(6)]^(2+)`A. TwoB. OneC. FourD. Three |
| Answer» Correct Answer - A | |
| 84. |
Assertion: The number of unpaired electrons in `[Ni(CO)_(4)]` is zero Reason: In this compounds 4s-electrons of Ni atom enter the inner d-orbitals to facilitate the `sp^(3)` hybridisation in Ni atom .A. (a) zeroB. (b) oneC. (c) threeD. (d) five |
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Answer» Correct Answer - A Due to presence of strong ligand all the `e^(-)` get paired. So number of unpaired electrons is 0. |
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| 85. |
The C-O bond length is the shortest in:A. `[Cr(CO)_(6)]`B. `[Mo(CO)_(6)]`C. `[Mn(CO)_(6)]^(+)`D. `[V(CO)_(6)]^(-)` |
| Answer» Correct Answer - C | |
| 86. |
An appropriate reagent for the conversion of 1-propanol to 1-propanal isA. acidified potassium dichromateB. alkaline potassium permaganateC. pyrindium chlorochromateD. acidified `CrO_(3)` |
| Answer» Correct Answer - C | |
| 87. |
The IUPAC name of the complex `[PT(en)(NH_(3))(cl)_(2)(ONO)][Ag(CN)_(2)]` is :A. monoamminedichlorido(ethane-1,2-diammine)nitritioplatinum(IV)dicyanoargentate(I)B. monoaminebischlorido (ethane-1,2-diammine)nitritioplatinate(IV) dicyanoanosilver(I)C. monoaminebischlorido(ethane-1,2-diammine ) nitritioplatinate (IV) dicyanoargentate (I)D. monoamminebischlorido (ethane-1,2-diammine) nitritioplatinum(IV) dicyanoargentate (I) |
| Answer» Correct Answer - D | |
| 88. |
The complex ion that does not have d electrons in the metal atom isA. `[MnO_(4)]^(-)`B. `[Co(NH_(3))_(6)]^(3+)`C. `[Fe(CN)_(6)]^(3-)`D. `[Cr(H_(2)O)_(6)]^(3+)` |
| Answer» Correct Answer - A | |
| 89. |
The complex ion . `[M(en)Br_(2)I_(2)]^(-1)`, has two optical isomers. Their correct configurations are:A. B. C. D. |
| Answer» Correct Answer - D | |
| 90. |
Which of the following is/are inner orbital complex ?A. `[Fe(CN)_(6)]^(4-)`B. `[Cr(NH_(3))_(6)]^(3+)`C. `[Mn(CN)_(6)]^(3-)`D. All of these |
| Answer» Correct Answer - D | |
| 91. |
How many isomers are possible in `[Cr(en)_(2)Br_(2)]` ?A. 2B. 3C. 6D. 1 |
| Answer» Correct Answer - B | |
| 92. |
Which one of the following has a square planar geometry? `(Co=27, Ni=28, Fe=26, Pt=78)`A. (a) `[CoCl_4]^(2-)`B. (b) `[FeCl_4]^(2-)`C. (c) `[NiCl_4]^(2-)`D. (d) `[PtCl_4]^(2-)` |
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Answer» Correct Answer - D `Cl^(-)` is weak field ligand and so chloride complexes are mostly high spin, but CFSE for transition metals is in the order `3dlt4dlt5d`, so the metal belonging to higher series will prefer low spin complex. Among the given complexes, `Pt` forms low spin complex while others form high spin complex. Square planar geometry of `[PtCl_4]^(2-)` is also supported by its diamagnetic nature. Note: All the complexes of Pd (II) ad Pt (II) are square planar. |
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| 93. |
The hybridisation of Ni in `[Ni(CO)_(4)]` isA. `sp^(3)`B. `dsp^(3)`C. `sp^(2)`D. `sp^(3)d` |
| Answer» Correct Answer - A | |
| 94. |
For the correct assignment of electronic configuration of a complex, the valence bond theory often requires the measurement ofA. molar conductanceB. optical activityC. magnetic momentD. dipole moment |
| Answer» Correct Answer - C | |
| 95. |
According to valence bond theory the geometry of `[Ni(CO)_(4)]` is________ . |
| Answer» Correct Answer - Tetrahedral | |
| 96. |
Which of the following statement is incorrect ?A. Potassium amminetetracyanidonitrosoniumchromate(I) having `mu=1.73 BM` has `ds^(2)sp^(3)` hybridisation.B. `K_(3)[AlF_(6)]+BF_(3) to AlF_(3)+3K[BF_(4)]`C. `[Cr(NH_(3))_(6)]Cl_(6) and [Cu(NC CH_(3))_(4)][BF_(4)]` both are coloured.D. `[Cr(NH_(3))_(4)Cl_(2)]Br` can show ionisation isomerism with `[Cr(NH_(3))_(4)ClBr]Cl` |
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Answer» Correct Answer - C ( C) `[Cr(NH_(3))_(6)]Cl_(3)` is coloured as it has three unpaired electrons while `[Cu(NC CH_(3))_(4)][BF_(4)]` is colourless as Cu(I) i.e `3d^(10)` electron configuration has all electrons paired, so there is no d-d transition of electrons. |
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| 97. |
Which of the following statements is not true ?A. `MnCl_(4)^(-)` ion has tetrahedral geometry and is paramagnetic .B. `[Mn(CN)_(6)]^(2-)` ioh has octahedral geometry and is paramagnetic.C. `[Cu(CN)_(4)]^(3-)` has square planar geometry and is diamagnetic.D. `[Ni(Ph_(3)P)_(2)Br_(3)]` has trigonal bipyramidal geometry and is paramagnetic. |
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Answer» Correct Answer - C (C ) `[Cu(CN)_(4)]^(3-),[Ar]^(18)3d^(10),` As there is no empty d-orbital for `dsp^(2)` hybridization. So it has `sp^(3)` hybridisation and is tetrahedral, and diamagnetic. |
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| 98. |
The complexes given below show: A. optical isomerismB. co-ordination isomerismC. geometrical isomerismD. bridged isomerism. |
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Answer» Correct Answer - C Geometrical isomerism arises in heteroleptic complexes due to different possible geometric arrangements of the ligands. When two `(C_(2)H_(5))_(3)P` groups are on same side it is cis- and when those are on opposite side it is trans- |
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| 99. |
Which of the following statement(s) is/are correct ?A. `cis-[Pt(NH_(3))_(2)Cl_(2)]` is used as an anticancer species.B. Carboxypeptidase-A is an enzyme and contains zinc.C. In the silver electroplating of copper, `K[Ag(CN)_(2)]` is used in place of `AgNO_(3)`.D. `CN^(-)` ions show the reducing as well as complexing properties towards metal species. |
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Answer» Correct Answer - A::B::C::D All statement are correct. |
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| 100. |
Which of the following statement is correct with respect to the metal carbonyls of `I^(st)` transition series ?A. As `M-Cpi` bonding increasing, the C-O bond length increases.B. As positive charge on the central metal atom increases, the C-O bond length increases.C. As electron density on the central metal atom increases, the C-O bond length increases.D. (A) and ( C) both. |
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Answer» Correct Answer - D Order of C-O bond strength: `[Mn(CO)_(6)^(+) gt [Cr(CO)_(6)] gt [V(CO)_(6)]^(-) gt [Ti(CO)_(6)]^(2-) and [NI(CO)_(4)] gt [Co(CO)_(4)]^(-) gt [Fe)CO)_(4)]^(2-)`. (A) True statement. (B)As+ve charge on the central metal atom increases, the less readily the metal can donate electron density into the `pi^(***)` orbitals CO ligand to weaken the C-O bond. ( C) In the carbonylate anions, the metal has a greater electron density to be dispersed, with the result that `M-Cpi` bonding is enhanced and the C-O bond is diminished in strength. |
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