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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
What are the values of m and n in the anionic species `[V(CO)_(m)]^(n-)` if it is fllowing Sidwick `EAN` rule and having octahedral shape ? . |
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Answer» Correct Answer - 6,1 `[V(CO)_(m)]^(n-) , V(Z =22) = 3d^(3) 4s^(2)` For octedral shape of complex `m =6` `EAN` of `V =Z +(-ve "charge") +2r m =36)` `= (22 + n + 2 xx 6)= 36implies n =1` . |
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| 102. |
Shape of `Fe(CO)_(5)` isA. octahedralB. square planarC. trigonal bipyramidalD. square bipyramidal |
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Answer» Correct Answer - C In `[Fe(CO)_(5)]` the oxidation number of Fe is zero `Fe^(0) (3d^(6) 4d^(2))` Since CO is a strong field ligand, the electron configuration is resuffled so as to provide one vacant d orbital for `dsp^(3)` hybrization leaging to trigonal bipyramidal geometry as well as shape. |
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| 103. |
A solution containing `2.675g` of `COCl_(3).6NH_(3)` (molar mass `=267.5gmol^(-1)`) is passed through a cation exchanger, The chloride ions obtined in solution were treated with excess of `AgNO_(3)` to give`4.78g` of `AgCl ("molar mass" =143.5gmol^(-1)`.The formula of the complex is (Atomic mass of `Ag=108 u`)A. (a) `[Co(NH_3)_6]Cl_3`B. (b) `[Co(NH_3)_3Cl_3]_3NH_3`C. (c) `[Co(NH_3)_4Cl_2]Cl_2NH_3`D. (d) `[Co(NH_3)_5Cl]Cl_2NH_3` |
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Answer» Correct Answer - A No. of moles complex `=(2.675)/(267.5)=0.01` No. of moles of `AgCl=(4.78)/(143.5)=0.03` This shows that three `Cl^-` ions are precipitated. Thus, formula of the complex is `[Co(NH_3)_6]Cl_3`. |
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| 104. |
A solution containing 2.675 g of `CoCl_(3).6NH_(3)` (molar mass `= 267.5 g mol^(-1)`) is passed through a cation exchanger. The chloride ions obtained is solution were treated with excess of `AgNO_(3)` to give 4.73 g of `AgCl` (molar mass = `143.5 g mol^(-1)`). The formula of the complex is (At. mass of Ag = 108 u)A. `[Co(NH_(3))_(6)]Cl_(3)`B. `[CoCl_(2)(NH_(3))_(4)]Cl`C. `[CoCl_(3)(NH_(3))_(3)]`D. `[CoCl(NH_(3))_(5)]Cl_(2)` |
| Answer» Correct Answer - A | |
| 105. |
Which one of the following forms with an excess of `CN^(-)` (Cyanide) a complex having coordination number twoA. (a) `Cu^(+)`B. (b) `Ag^(+)`C. (c) `Ni^(2+)`D. (d) `Fe^(2+)` |
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Answer» Correct Answer - B `Ag^(+)` has two coordination number forms complex with excess of `CN^(-)Ag(CN)_2`. |
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| 106. |
The number of ions given by `[Pt(NH_(3))_(6)]Cl_(4)` in aqueous solution will beA. twoB. threeC. fiveD. eleven . |
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Answer» Correct Answer - C `[Pt(NH_(3))_(6)]Cl_(4) hArr [Pt(NH_(3))_(6)]^(4+) + 4 Cl^(-)` Total number of ions given in aqueous solution = 5 |
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| 107. |
A coordination compound X gives pale yellow colour with `AgNO_(3)` solution while its isomer Y gives white precipitate with `BaCl_(2)` . Two compounds are isomers of `CoBrSO_(4)* 5NH_(3)` . What could be the possible formula of X and Y ?A. X = `[Co(NH_(3))_(5)SO_(4)] Br, Y = [Co(NH_(3))_(5) Br]SO_(4)`B. `X = [Co(NH_(3))_(5)Br]SO_(4) , Y = [Co(NH_(3))_(5)SO_(4)]Br`C. `X = [Co(NH_(3))_(5)Br(SO_(4))] , Y = [CoBr(SO_(4))(NH_(3))_(5)]`D. `X = [Co(Br_(5) NH_(3)]SO_(4) , Y = [CoBr(SO_(4))]NH_(3)` |
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Answer» Correct Answer - A `[Counderset(X)((NH_(3))_(5)) SO_(4) ]Br to [Co(NH_(3))_(5) SO_(4)]^(+) + Br^(-)` `AgNO_(3) + Br^(-) to underset("pale yellow") (AgBr) + NO_(3)^(-)` `[Co(NH_(3))_(5)Br]SO_(4) to [Co(NH_(3))_(5)Br]^(2+) + SO_(4)^(2-)` `BaCl_(2) + SO_(4)^(2-) to underset("white ppt.")(BaSO_(4)) + 2 Cl^(-)` |
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| 108. |
A complex anion is formed by Osmium ( in some oxidation state ) with ligands ( in proper number so that coordination number of osmium becomes six ). Which of the following can be its correct IUPAC name ?A. pentachloridonitridoosmium(VI)B. pentachloridonitridoosmate(VI)C. azidopentachloridoosmate(VI)D. None of these |
| Answer» Correct Answer - B | |
| 109. |
In Which of the following compunds the metal is in the lowest oxidation state?A. `[Co(NH_(3))_(5)Br]SO_(4)`B. `Fe_(3)[Fe(CN)_(6)]_(2)`C. `[Mn_(2)(CO)_(10)]`D. `K[PtCI_(3)(C_(2)H_(4))]` |
| Answer» Correct Answer - C | |
| 110. |
Which of the following is nonionisable?A. `[Co(NH_(3))_(3)CI_(3)]`B. `[Co(NH_(3))_(4)CI_(2)]CI`C. `[Co(Nh_(3))_(5)CI]CI_(2)`D. `[Co(NH_(3))_(6)]CI_(3)` |
| Answer» Correct Answer - A | |
| 111. |
Bidentate ligands areA. `C_(2)O_(4)^(2-)`(oxalate)B. en(ethylenediamine)C. `DMG`(dimethyl glyoxime)D. Gly (glycine) |
| Answer» Correct Answer - A::B::C::D | |
| 112. |
Complex salt can be made by the combination of `[Co^(III)(NH_3)_5Cl]^(x)` withA. (a) `PO_4^(3-)`B. (b) `Cl^(-)`C. (c) `2Cl^(-)`D. (d) `2K^(+)` |
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Answer» Correct Answer - C `[Co(NH_3)_5Cl]^(x)+2Cl^(-)rarr[Co(NH_3)_5Cl]Cl_2`. |
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| 113. |
Which of the following pair contains complex salt and double salt respectively?A. `FeSO_(4),K_(4)[Fe(CN)_(6)]`B. `[Cu(NH_(3))_(4)]SO_(4),FeSO_(4).7H_(2)O`C. `[Cu(NH_(3))_(4)]SO_(4),K_(2)SO_(4)AI_(2)(SO_(4))_(3).24H_(2)O`D. `MgSO_(4).7H_(2)O,CuSO_(4).5H_(2)O` |
| Answer» Correct Answer - C | |
| 114. |
Ligands in a complex salt are:A. (a) ions or molecules linked by coordinate bonds to a central metal atom or ion.B. (b) molecules linked by coordinate bonds to a central metal atom or ion.C. (c) cations linked by coordinate bonds to a central metal atom or ion.D. (d) anions linked by coordinate bonds to a central metal atom or ion. |
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Answer» Correct Answer - A Ligands from coordinate bond with central atom or ion and donate electron pair. |
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| 115. |
Select the correct `IUPA` name for `[CoCI_(2)(en)_(2)]_(2)(CIO_(3))_(2)` .A. Dichloridobis (ethylenediamine)cobalt(III)chlorate .B. Dichloridobis (ethane-1,2-diamine)cobalt(III)chlorate .C. bis{dichloridoethylenediaminecobalt(III)}chlorateD. bis{di(chlorido)ethylenediaminecobalt(III)}chlorate |
| Answer» Correct Answer - A::B | |
| 116. |
The pair in which both species have same ( spin only ) magnetic moment is `:`A. `[CrCl_(4)]^(-),[FeCl_(4)]^(-)`B. `[Ni(NH_(3))_(6)]^(2+),[Zn(NH_(3))_(6)]^(2+)`C. `[MnCl_(6)]^(3-),[FeF_(5)]^(3-)`D. `[Co(CN)_(6)]^(3-),[Co(C_(2)O_(4))_(2)]^(3-)` |
| Answer» Correct Answer - D | |
| 117. |
The pair in which both species have same magnetic moment (spin only value) is .A. a.`I[Cr(H_(2)O)_(6)]^(2+),[CoCI_(4)]^(2-)`B. b.`[Cr(H_(2)O)]^(2+),[Fe(H_(2)O)_(6)]^(2+)`C. c.`[Mn(H_(2)O)]^(2+),[Cr(H_(2)O)_(6)]^(2+)`D. d.`[CoCI_(4)]^(2-),[Fe(H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - B Same magnetic moment =Same number of unpaired electrons `mu=sqrt(n(n+2))` where `n=` number of unpaired electrons `Co^(2+) = 3d^(7), 3` unpaired electrons `Cr^(2+) = 3d^(4), 4` unpaired electrons, `Mn^(2+) = 3d^(5),5` unpaired electrons `Fe^(2+) =3d^(6),4` unpaired electrons. |
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| 118. |
Selcet the correct statement`(s)` for double salt .A. Double salts are stable in solid state but lose their identity in aqueous solution .B. In double salt the properties of constituent ions are not changed in their aqueous solution .C. Double salts are stable in solid state and do not lose their identity in aqueous solution .D. In double salt the properties of constituent ions are changed in their aqueous solution . |
| Answer» Correct Answer - A::B | |
| 119. |
Which of the following ligand `(s)` is/are ambidentate ?A. `NOS^(Θ)`B. `SCN^(Θ)`C. `NO_(2)^(Θ)`D. `CH_(3)COO^(Θ)` |
| Answer» Correct Answer - A::B::C | |
| 120. |
The pair in which both spacies have the same magnetic moment ( spin only) value is `:`A. `[Cr(NH_(3))_(6)]^(3+),[Co[H_(2)O)_(6)]^(3)`B. `[Cr(NH_(3))_(6)]^(3+),[Fe(H_(2)O)_(6)]^(2+)`C. `[Co(NH_(3))_(6)]^(2+),[Cr(NH_(3))_(6)]^(3+)`D. `[Mn(H_(2)O)_(6)]^(2+),[Fe(H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - C `mu=sqrt(n(n+2))` No. of unpaired electrons are `:` `(i)[Cr(NH_(3))_(6)]^(3+)Cr^(3+)(3d^(4)),n=3" "(ii)[Co(NH_(3))_(6)]^(2+)Co^(2+)(3d^(7)),n=3` `(iii)Fe(H_(2)O)_(6)]^(2+)Fe^(2+)(3d^(7)),n=4" "(iv)[Mn(H_(2)O)_(6)]^(2+)Mn^(2+)(3d^(5)),n=5` `(v)[Co(H_(2)O)_(6)]^(3+)Co^(3+)(3d^(6)),n=0(d^(2)sp^(3))` Thus, `Cr^(3+)` and `Co^(2+)` have same number of unpaired electrons. Hence in pair `(C )` , both species will have same magnetic moment. |
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| 121. |
Which of the following is not an ambidentate ligand ?A. `CN^(-)`B. `SCN^(-)`C. `CO`D. `NO_(2)^(-)` |
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Answer» Correct Answer - 3 Ligands which can ligate through two different atoms present in it are called ambidentate ligands. Examples of such ligands are the `CN^(-),NO_(2)^(-)` and `SCN^(-)` ions. CO is not an ambidentate ligand. |
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| 122. |
Indicate the complex ion which shows geometrical isomerism.A. `[Cr(H_(2)O)_(4) Cl_(2)]^(+)`B. `[Pt(NH_(3))_(3)Cl]`C. `[Co(NH_(3))_(6)]^(3+)`D. `[Co(CN)_(5) (NC)]^(3-)` |
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Answer» Correct Answer - A Complexes of type `MA_(4) B_(2)` show geometrical isomerism . |
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| 123. |
Magnetic moment of `[MnCl_(4)]^(2-)` is 5.92 BM. Explain giving reason present. |
| Answer» The magnetic moment 5.92 BM shows that there are five unpaired electrons present in the d-orbitals of `Mn^(2+)` ion. As a result, the hydridisation involved is `sp^(3)` rather than `dsp^(2)`. Thus tetrahedral structure of `[MnCl_(4)]^(2-)` complex will show 5.92 BM magnetic moment value. | |
| 124. |
The number of ions produced by the complex `[Cr(NH_(3))_(4)CI_(2)]CIO_(3)` is .A. 2B. 3C. 4D. 6 |
| Answer» Correct Answer - A | |
| 125. |
Magnesium is an important component of which biomolecule occuring extensively in living world?A. HaeomoglobinB. Chlorophy11C. FlorigenD. `ATP` |
| Answer» Correct Answer - B | |
| 126. |
Hardness of water is estimated by simple complex formation titration Complex formed by cation in hard water during estimation of hardness is .A. `Na_(2)[Ca(PO_(3))_(6)]`B. `Na_(2)[Mg(EDTA)]`C. `[Ca(So_(4))_(2)]^(2-)`D. `Na[Pb(EDTA)]` |
| Answer» Correct Answer - B | |
| 127. |
Among `[Ni(CO)_(4)], [NiCl_(4)]^(2-), [Co (NH_(3))_(4) Cl_(2)] Cl, Na_(3) [CoF_(6)], Na_(2)O_(2)` and `CsO_(2)`, the total number of paramagnetic compounds isA. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - B |
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| 128. |
The complex `[]Ni(CN)_(4)]^(2-)` is diamagnetic and the complex `[NiCl_(4)]^(2-)` is paramagnetic . What can you conclude about their molecular geometries ?A. Both complexes have square planar geometriesB. Both complexes have tetrahedral geometriesC. `[NiCl_(4)]^(2-)` has a square planar geometry while `[Ni(CN)_(4)]^(2-)` has a tetrahedral geometry .D. `[NiCl_(4)]^(2-)` has a tetrahedral geometry while `[Ni(CN)_(4)]^(2-)` has a square planar geometry . |
| Answer» Correct Answer - D | |
| 129. |
`[Co(NH_3)_5Br]SO_4` and `[CO(NH_3)_5SO_4]Br` are examples of which type of isomerismA. (a) LinkageB. (b) GeometricalC. (c) IonizationD. (d) Optical |
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Answer» Correct Answer - C The two given compounds have same composition but in solution both will give different ions. The isomerism is known as ionisation isomerism. |
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| 130. |
The number of isomers possible for square planar complex `K_2[PdClBr_2SCN]` is:A. (a) `2`B. (b) `4`C. (c) `3`D. (d) `6` |
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Answer» Correct Answer - B Geometrical isomers (cis and trans) and linkage isomers `(-SCN- and -CNS-)`. |
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| 131. |
`[Co(NH_3)_5Br]SO_4` and `[Co(NH_3)_5SO_4]Br` are the examples of:A. (a) linkage isomerismB. (b) geometrical isomerismC. (c) optical isomerismD. (d) ionization isomerism |
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Answer» Correct Answer - D Both produce different ions in solution state: `[CO(NH)_3]_5BrSO_4hArr[CO(NH_3)_5Br]^(2+)+SO_4^(2-)` `[CO(NH_3)_5SO_4]BrhArr[CO(NH_3)_5SO_4]^+ + Br^(-)` |
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| 132. |
An example of coordination isomerism isA. `[Cr(H_(2)O)_(6)]Cl_(3) and [Cr(H_(2)O)_(5)Cl]Cl_(2),H_(2)O`B. `[Co(NH_(3))_(6)][Cr(CN)_(6)] and [Cr(NH_(3))_(6)][Co(CN)_(6)]`C. `[Pt(NH_(3))_(4)Cl_(2)] and [Pt(NH_(3))_(2)Cl_(4)]`D. `[Co(NH_(3))_(5)Br]SO_(4) and [Co(NH_(3))_(5)SO_(4)]Br` |
| Answer» Correct Answer - B | |
| 133. |
Which of the following octahedral complexes do not show geometrical isomerism ?A. `[Co(NH_(3))_(3)Cl_(3)]`B. `[PtCl_(2)(NH_(3))_(4)]`C. `[Cr(H_(2)O)_(5)Cl]^(2+)`D. `[Co(en)_(3)]^(3+)` |
| Answer» Correct Answer - C | |
| 134. |
Geometrical isomerism is found in coordination compounds having coordination number:A. (a) `6`B. (b) `3`C. (c) `4`(tetrahedral)D. (d) `2` |
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Answer» Correct Answer - A Geometrical isomerism is found is compound having coordination no. 4 (square planar and not tetrahedral shape) as well as coordination no. 6 Coordination no. 4(square planar) `M_(A_2BC),M_(A_2B_2)` Showing geometrical isomerism `M_(ABCD)` Coordination no. 6 (octahedral) `M_(A_4B_2), M_(A_4BC)` Showing geometrical isomerism `M_(A_3B_3), M_(( A A)_2B_2)` |
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| 135. |
Which complexes show geometrical isomerism ?A. TetrahedralB. OctahedralC. Square planarD. Linear |
| Answer» Correct Answer - B::C | |
| 136. |
Geometrical isomerism is found in coordination compounds having coordination number:A. 2B. 3C. 4(tetrahedral)D. 6 |
| Answer» Correct Answer - D | |
| 137. |
In which structure crystal field splitting energey `(CFSE)` for octahedral complex will be zero when `DeltaltP` .A. `d^(5)`B. `d^(6)`C. `d^(8)`D. `d^(10)` |
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Answer» Correct Answer - d If `Delta lt P` weak field no pairing `d^(5) = (t_(2g)^3e_(g)2)` CFSE = -` 0 .4 xx 3 + 2 xx 1.6 = 0` If `DeltagtP` strong field pairing `d^(5) = t_(2g) 5 e_(g)^(0)` CFSE = `- 0 .4 xx 5 = - 2Delta` For `d^(10) , implies t_(2g) 6 e_(g)^(4) = - 0.4 xx 6 + 0.6 xx 4 =0` . |
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| 138. |
In which structure crystal field splitting energey `(CFSE)` for octahedral complex will be zero when `DeltaltP` .A. `-1.0Delta_(t)`B. `1.0Delta_(t)`C. 0D. `-1.8Delta_(t)` |
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Answer» Correct Answer - c Tetrahedral complex , `CN =4` `(Delta lt P "weak ligand no pairing high spin")` `Fe = 3d^(6) 4s^(2), Fe^(+3) = 3d^(5)` Structure is `(e^(2) t_(2)^(3))` `CFSE = - 0.6 xx 2 + 0.4 xx 3 = 0` . |
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| 139. |
Corystal field splitting energy `(CFSE)` for the complex `[Cr(H_(2)O)_(6)]^(2+)` is when `(DeltaltP)` .A. ` 1.2Delat_(0)`B. `-0.6Delta_(0)`C. `0.6Delta_(0)`D. `1.2Delta_(0)` |
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Answer» Correct Answer - b Octahedral complex `CN=6,Delta lt P` (Weak ligand no pairing high spin state) `Cr = 3d^(5) 4s^(1),Cr^(+2) = 3d^(4)` ,Structure is `(t_(2g)^(3)` e_(g)^(0))` `CFSE `=(-0.4 xx 3 + 0.6)Delta_(0)=-0.6Delta_(0)` . |
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| 140. |
Crystal field splitting energy `(CFSE)` for the complex `[Cr(H_(2)O)_(6)]^(2+)` is when `P =20925cm^(-1)` and `Delta_(0) = 10462.5cm^(-1)(1kJmo1^(-1) = 83.7 cm^(-1))` .A. `a.-75kJmo1^(-1)`B. `b.75kJmo1^(-1)`C. `c.750kJmo1^(-1)`D. `d.-750 kJ mo1^(-1)` |
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Answer» Correct Answer - a `Delta ltP` weak field no pairing high spin state Octahedral complex `CN =6` `Cr = 3d^(5) 4s^(1) ,Cr^(+2) = 3d^(4)` ,Structure `3(t_(2g)^(2) e_(g)^(1))` `P = (20925 cm^(1-))/(83. 7) =250 kJmo1^(-1)` `Delta_(0) = (10462.5 cm^(1))/(83 .7) = 125 kJ mol e^(-1)` `CFSE = ( 0.4 xx 3 +0.6)Delta_(0) = - 0.6Delta_(0) = -0.6 xx 125` `=- 75kJmo1^(-1)` . |
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| 141. |
The enthalpy of hydration of `Cr^(+2)` is `-460` kcal `mo1^(-1)` In the absence of `CFSE` the value for `DeltaH=-424` kcal `mo1^(-1)` What is the value of `Delta_(0)` for `[Cr(H_(2)O)_(6))]^(2+)` .A. `60kcal "mole"^(-1)`B. `-60kcal "mole"^(-1)`C. `25.7 kcal "mole"^(-1)`D. `-25.7kcal "mole"^(-1)` |
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Answer» Correct Answer - a `Cr = 3d^(5)4s^(1) , Cr^(+2) = 3d^(4)` Structure is `(t_(2g)3e_(g)1)` `CFSE (-0.4 xx 3 + 0.6)Delta_(0) = - 0.6 Delta_(0))` `- 0.6 Delta_(0) = (- 460) - (-424) = - 36k cal mo1^(-1)` `Delta_(0) = (-36)/(-0.6) = 60 kcal "mole"^(-1)` ` 60 xx 350cm^(-1) = 21000cm^(1-)` `(1 kcal mo1^(-1) = 350cm^(-1))` . |
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| 142. |
Crystal field splitting energey `(CFSE)` for the complex `[Fe(CN)_(4)]^(Θ)` is when `DeltagtP` .A. `a)-2.0`B. `b)Delta+P`C. `c)2+P`D. `d)0` |
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Answer» Correct Answer - d Tetrahedral complex `CN = 4 DeltagtP` Strong ligand but pairing does not take place tetrahedral complexes `Fe = 3d^(6) 4s^(2), Fe^(+6) = 3d^(2) implies (e^(2) t_(2)_(0)` `CFSE = ( -0.6 xx 2 + 0.4 xx 3)Deta_(t) = 0.0` . |
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| 143. |
Crystal field splitting energey `(CFSE)` for the complex `[Fe(O)_(4)]^(2-)` is when `Delta =125` and ` P =250kJmo1^(-1)` .A. `-1.2Delta_(t)`B. `1.2Delta_(t)`C. `-8`D. 8 |
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Answer» Correct Answer - a Tetrahedral complex `CN =4, Delta ltP` Weak ligand no pairing high spin `Fe = 3d^(6)4s^(2)` , `Fe^(+6) = 3d^(2)implies (e^(2) t_(2)^(0))` `CFSE = ( -0.6 xx 2)Delta_(t) = - 1.2Delta_(t)` . |
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| 144. |
Arrange the following complexes in the increasing order of conductivity of their solution `[Co(NH_(3))_(3)Cl_(3)], [Co(NH_(3))_(4)Cl_(2)]Cl, [Co(NH_(3))_(6)]Cl_(3), [Cr(NH_(3))_(5)Cl] Cl_(2)`A. `(i) lt (ii) lt (iv) lt (iii)`B. `(ii) lt (i) lt (iii) lt (iv)`C. `(i) lt (iii) lt (ii) lt (iv)`D. `(iv) lt (i) lt (ii) lt (iii)` |
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Answer» Correct Answer - A Higher the number of ions in the solution , higher is the conductivity . No. of ions : `[Co(NH_(3))_(3) Cl_(3)] = 0 , [Co(NH_(3))_(4)Cl_(2)]Cl = 2` `[Co(NH_(3))_(5) Cl]Cl_(2) = 3 , [Co(NH_(3))_(6)]Cl_(3) = 4` |
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| 145. |
Assertion : Inner orbital complexes are low spin complexes . Reason : In low spin complexes , inner d-orbital (3d) is used in hybridisation .A. If both Assertion and reason are true and reason is the correct explanation of assertionB. If both assertion and reason are true but reason is not the correct explanation of assertionC. If assertion is true but reason is falseD. if both assertion and reason are false |
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Answer» Correct Answer - A Because inner d-orbitals is involved in hybridisation , pairing of electrons occur and hence due to less or no unpaired electrons the complexes are low spin complexes . |
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| 146. |
If excess of `AgNO_(3)` solution is added to 100 mL of a 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride, how many mol of AgCl be precipitated:A. `0.0012`B. `0.0016`C. `0.0024`D. `0.0048` |
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Answer» Correct Answer - C 100 mL of 0.024 M = 0.0024 mole of the complex , complex is ` [Co(en)_(2)Cl_(2)]Cl` and thus ,One `Cl^(-)` is formed per mol of the complex which gives 1 mole of AgCl. hence ,Ag Cl formed = 0.0024 mol |
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| 147. |
If excess of `AgNO_(3)` solution is added to 100mL of a 0.024 M solution of dichlorobis (ethylenediamine) cobalt (III) chloride . How many mole of AgCl be precipitated ?A. 0.0012B. 0.0016C. 0.0024D. 0.0048 |
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Answer» Correct Answer - C `[CoCl_(2)(en)_(2)]Cl`. One mole complex contain, one mole of ionisation `Cl^(-)`. One mole of complex = one mole of `Cl^(-)` `:.` One mole of `AgCl`= One mole of complex`=(100xx0.024)/(1000)=0.0024`. |
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| 148. |
Which one of the following statements is not correct?A. Merpury (II) iodide dissolves in excess of potassium iodide solutionB. Tin (IV) chloride is made by dissolving tin solution in concentrated hydrochloric acidC. Zinc dissolves in sodium hydroxide solutionD. Carbon monoxide reduces iron (III) oxide to iron |
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Answer» Correct Answer - B `SnCl_(4)` is obtained by passmg chlorme over tin So Sn (IV) chloride is made by dissolving tin solution in concentrated solution statement is incorrect and answer is (b). |
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| 149. |
The complex ion `[Co(NH_(3))_(6)]^(3+)` is formed by `sp^(3) d^(2)` hybridiration. Hence, the ion should possesA. octahedral geometryB. tetrahedral geometryC. square planar geometryD. tetragonal geometry |
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Answer» Correct Answer - A Since the hybridisation of central metal tin`[Co(NH_(3))_(6)]^(+)` complex ion is `sp^(3)d^(2)` and coordination number of `Co^(3+)` is 6. So its geometry is octahedral. |
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| 150. |
The co-ordination number of Co in `[Co(C_(2)O_(4))_(2)Cl_(2)]` isA. 4B. 6C. 8D. 12 |
| Answer» Correct Answer - B | |