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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
Geomerical isomerism is not observed in complexes of coordination number 4 of____________geometry . |
Answer» Correct Answer - Tetrahedral | |
202. |
Give the number of ligands which are monodentate as well as ambidentate `overset(Θ)(CN),C_(2)O_(4)^(2-),S_(2)^(2-),NO_(2)^(Θ), overset(Θ)OCN,SCN^(Θ` . |
Answer» Correct Answer - 4 `CN^(Θ) ,NO_(2) Θ , overset(Θ)(OCN) ,SCN^(Θ)` . |
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203. |
The correct formula for hexaaminecobalt(III) nitrate isA. `[Co_(3)(NH_(3))](NO_(3))_(3)`B. `[Co_(3)(NH_(3))_(6)](NO_(3))_(3)`C. `[Co(NO_(3))_(3)].6NH_(3)`D. `[Co(NH_(3))_(6)](NO_(3))_(3)` |
Answer» Correct Answer - D | |
204. |
Type of isomerism which is shown by `[PtCl_2Br_2]^(2-)` is also observed in:A. (a) `[CoCl_2Br_2]^(2-)`B. (b) `[Co(en)_3]^(3+)`C. (c) `[PtCl_4Br_2]^(2-)`D. (d) `[PtCl_3(NO)_2]^(2-)` |
Answer» Correct Answer - C Square planar `[PtCl_2Br_2]^(2-)=Show GI` (a) Tetrahedral `[CoCl_2Br_2]^(2-)=` Does not show GI (c) Octahedral `[PtCl_4Br_2]^(2-)=Show GI` (d) `[PtCl_3(NO_2)]^(2-)=` This belongs to `MA_3B`, so does not show GI |
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205. |
Which of the following types of octahedral complexes does not show optical isomerism?A. (a) `MA_2X_2Y_2`B. (b) `[Pt(NH)_3)_4]^(2+)`C. (c) `[M(A A)_3]^(n+)`D. (d) `[M(A A)_2X_2]^(n+)` |
Answer» Correct Answer - B `[Pt(NH_3)_4]^(2+)` is a square planar complex having four similar ligands. |
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206. |
Which of the following is not optically active?A. (a) `[Co(en)_3]^(3+)`B. (b) `[Cr(o x)_3]^(3-)`C. (c) `cis-[CoCl_2(en)_2]^(+)`D. (d) `trans-[CoCl_2(en)_2]^(+)` |
Answer» Correct Answer - D Trans complex is symmetrical and is optically inactive. |
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207. |
The IUPAC name of complex `[Cu(en)_(2)(H_(2)O)_(2)]^(22+)`A. ethylene dimineCu(II) dihydrateB. diaquobis(ethylenediamine)copper(II)ionC. diaquobisdietyleamineCU(II)ionD. diaquobis(ethylenediamine)cuprate(II) |
Answer» Correct Answer - B | |
208. |
Which of the following complexes are heteroleptic ?A. `[Cr(NH_(3))_(6)]^(3+)`B. `[Fe(NH_(3))_(4) Cl_(2)]^(+)`C. `[Mn(CN)_(6)]^(4-)`D. `[Co(NH_(3))_(4)Cl_(2)]` |
Answer» Correct Answer - B::D Heteropleptic complexes Coordination complexes which contain more than one type of ligands are known as heteropletic complexes. e.g., `[Fe(NH_(3))_(4)Cl_(2)]^(+)` contain `NH_(3)` and `Cl` as a ligand is as heteroleptic complex. Similarly `[Co(NH_(3))_(4)Cl_(2)]` contain `NH_(3)` and `Cl` as ligand is also a heteroleptic complex. Hence, options (b) and (d) are correct choices. |
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209. |
The electronic spectrum of `[Ni(H_(2)O)_(6)]^(++)` shows as band at `8500cm^(-1)` due to d-d transiton . `[Ph_(4)As]_(2)[NiCl_(4)]` will have such a transition in `cm^(-1)` atA. 3778B. 8500C. 7250D. 850 |
Answer» Correct Answer - A | |
210. |
A complex of the type `[M(A A)_(2)X_(2)]` is known to the optically active. What does this indicate about the structure of the complex? Give one example of such complex .A. It has an octahedral geometryB. It is tetrahedral complexC. It is trans complexD. none of the above |
Answer» Correct Answer - A An optically active complex of the type ` [M (AA) _(2) X_(2)]^(n+)` indicates cis -octahedral structure e .g Cis `[Pt(en)_(2) Cl_(2)]` of Cis `[Cr(en)_(2)Cl_(2)]^(+)` |
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211. |
The IUPAC name of `[Ni (P Ph_(3))_(2) Cl_(2) ]^(2+)` isA. bis- dichlorido (triphenylphosphine ) nikel (II )B. dichloride bis ( triphenylphoshine ) nikel (IV )C. dischlorido triphenylphospine nickel (II )D. triphenylphosphine nickel (II ) dichloride |
Answer» Correct Answer - B The IUPAC name of `[Ni(PPh_(3))_(2)Cl_(2)]^(2+)` is dichlorido bis (triphenylphosphine nickel (IV ) |
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212. |
`[Co(HN_(3))_(6)][Cr(CN)_(6)]` and `[Cr(NH_(3))_(6)][Co(CN)_(6)]` are .A. Geometrical isomerismB. Linkage isomerismC. Ionization isomerismD. coordination isomerism |
Answer» Correct Answer - D Coordination isomerism is shown by those ionic coordination copmpounds in which both cation as well as anion are complexes (coordination entites) and ligands interchange their positions between the two complex ions. |
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213. |
The d-electron configurations of `Cr^(2+), Mn^(2+), Fe^(2+)` and `Co^(2+)` are `d^4, d^5, d^6` and `d^7` respectively. Which one of the following will exhibit minimum paramagnetic behavious?A. (a) `[Cr(H_2O)_6]^(2+)`B. (b) `[Mn(H_2O)_6]^(2+)`C. (c) `[Fe(H_2O)_6]^(2+)`D. (d) `[Co(H_2O)_6]^(2+)` |
Answer» Correct Answer - D `H_2O` is weak field ligand, thus `CO^(2+)` has only 3 unpaired electrons. |
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214. |
`[Co(HN_(3))_(6)][Cr(CN)_(6)]` and `[Cr(NH_(3))_(6)][Co(CN)_(6)]` are .A. Coordination position isomerismB. Polymerization isomerismC. Coordination isomerismD. Ionization isomerism |
Answer» Correct Answer - C When both the positive and negative ions of a corrdination compound are complex ions, coordination isomerism is possible and is caused by the interchange of ligands between the anion and cation: `[Co(NH_(3))_(6)][Cr(CN)_(6)]` `[Co(NH_(3))_(5)CN][Cr(NH_(3))CN)_(5)]` `[Co(NH_(3))_(4)(Cr)_(2)][Cr(NH_(3))_(2)(CN)_(4)]` `[Co(NH_(3))_(3)(CN)_(3) [Cr(NH_(3))_(3)(CN)_(3)]` is not possible as both units are neutral species `[Cr(NH_(3))_(4)(CN)_(2)][Co(NH_(3))_(2)(CN)_(4)]` `[Cr(NH_(3))_(5)CN][Co(NH_(3))(CN)_(5)]` `[Cr(NH_(3))_(6)][Co(CN)_(6)]` |
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215. |
`[Co(HN_(3))_(6)][Cr(CN)_(6)]` and `[Cr(NH_(3))_(6)][Co(CN)_(6)]` are .A. (a) Geometrical isomerismB. (b) Linkage isomerismC. (c) Ionization isomerismD. (d) Coordination isomerism |
Answer» Correct Answer - D Coordination sphere is interchanged. |
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216. |
Other theories explaining the bonding in coordination compounds areA. Ligand field theoryB. Molecular orbital theoryC. VSEPR theoryD. Atomic orbital theory |
Answer» Correct Answer - A::B | |
217. |
`[Cr(CN)_(6)][Co(NH_(3))_(6)]` containsA. Cationic complexB. Anionic complexC. Neutral ligandsD. Anionic ligands |
Answer» Correct Answer - A::B::C::D | |
218. |
Two compounds have the empirical formula `Cr(NH_(3))_(3)(NO_(2))_(3)` In aqueous solution one of these conducts electricity while the other does not Deduce their probable structures . |
Answer» The complex which conducts electricity can be one of the following (a) `[Cr(NH_(3))_(3)(NO_(2))_(2)H_(2)O]^(o+)NO_(2)^(o+)` (b) `[Cr(NH_(3))_(3)(NO_(2))(H_(2)O)_(2)]^(2+)2NO_(2)^(Θ)` (c ) `[Cr(NH_(3))_(3)(H_(2)O)_(3)]^(3+)3NO_(2)^(Θ)` Which does not conduct electricity is `[Cr(NH_(3))_(3)(NO_(2))_(3)]` . |
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219. |
Indicate the oxidation state of the central metal ion in each of the following complex (a) `[Cu(NH_(3))_(4)]^(2+)` (b) `[Cu(Br_(4))]^(2-)` (c ) `[Cu(CN)_(2)]^(Θ)` (d) `[Cu(NH_(3))_(4)CO_(3)]^(o+)` (e) `[PtCI_(4)]^(2-)` (f) `[Co(NH_(3))_(2)(NO_(2))_(4)]^(Θ)` (g) `Fe(CO)_(5))` (h) `[ZnCI_(4)]^(2-)` (i) `[Fe(en)_(3)]^(2+)` . |
Answer» (a) `+2` , (b) `+2` , (c ) `+1` (d) `+3` , (e) `+2` , (f) `+3` (g) `0` `(h) `+2` , (i) `+2` . |
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220. |
The oxidation numbe of Co in the complex ion is :A. `+2`B. `+3`C. `+4`D. `+6` |
Answer» Correct Answer - B `2X+1(-2)+1(-1)=+3,x=(6)/(2)=+3` |
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221. |
Mark the incorrect match .A. Insulin - ZincB. Haemoglobin - IronC. Vitamin `B_(12)` - CobaltD. Chlorophyll - Chromium |
Answer» Correct Answer - A Chlorophyll contains magnesium . |
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222. |
Mark the incorrect statement .A. Inner orbital (low spin) complexes involve `d^(2) sp^(3)` hybridisation .B. Outer orbital (high spin) complexes involve `sp^(3) d^(2)` hybridisation .C. Tetrahedral complexes generally involve `dsp^(2)` hybridisation .D. Stereoisomerism involves geometrical and optical isomerism . |
Answer» Correct Answer - C Tetrahedral complexes generally involve `sp^(3)` hybridisation . |
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223. |
Which of the following sets of examples and geometry of the compounds is not correct ?A. Octahedral - `[Co(NH_(3))_(6)]^(3+) , [Fe(CN)_(6)]^(3-)`B. Square planar - `[Ni(CN)_(4)]^(2-) , [Cu(NH_(3))_(4)]^(2+)`C. Tetrahedral - `[Ni(CO)_(4)] , [ZnCl_(4)]^(2-)`D. Trigonal bipyramidal - `[Fe(NH_(3))_(6)]^(2+) , [CuCl_(4)]^(2-)` |
Answer» Correct Answer - D `[CuCl_(4)]^(2-) ` : Tetrahedral `[Fe(NH_(3))_(6)]^(2+) ` : Octahedral |
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224. |
The oxidation number of `Co ` in ` [Co(NH_(3))_(3)(NO_(2))_(3)]` isA. `+3`B. `0`C. `-3`D. `6` |
Answer» Correct Answer - A Oxidation state of `NH_(3) =0 and NO_(2)=-1` So `[Co (NH_(3))_(3) (NO_(2))_(3)]` Let , x be the charge on co ` x+(0) 3 +(-1) 3=0 implies x-3=0` ` implies x=+3` |
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225. |
`AgCl` dissolved in excess of `NH_(3), KCN` and `Na_(2)S_(2)O_(3)` solutions the complex produces ionsA. `[Ag(NH_(3))_(2)]^(2+),[Ag(CN)_(2)]^(+)and [Ag(S_(2)O_(3))_(2)]^(3-)`B. `[Ag(NH_(3))_(2)]^(2+),[Ag(CN)_(2)]^(3-)and [Ag(S_(2)O_(3))_(2)]^(2-)`C. `[Ag(NH_(4))_(2)]^(2+),[Ag(CN)_(2)]^(3-)and [Ag(S_(2)O_(3))_(2)]^(2-)`D. `[Ag(NH_(3))_(2)]^(+),[Ag(CN)_(2)]^(-)and [Ag(S_(2)O_(3))_(2)]^(3-)` |
Answer» Correct Answer - A `AgCl + 2NH_(3) to [Ag(NH_(3))_(2)] Cl` ` AgCl +2KCN to K[Ag(CN)_(2)]+KCI` `AgCl +Na_(2) S_(2) O_(3) to [Ag (S_(2)O_(3))_(2)]^(3-)` |
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226. |
The extraction of ----- by the formation of cyanide complex is a typical example of the use of coordination compounds in metallurgical processes.A. AgB. AuC. CuD. Both 1 and 2 |
Answer» Correct Answer - D Some important extraction processe of metals, like those of Ag and Au, make use of complex formation. Gold, for example, combines with cyanide in the presence of oxygen and water to form the coordination entity `[Au(Cu)_(2)]^(-)` in aqueous solution. Gold can be separated in metallic form this solution by the addition of zinc. `4Au(s)+8CN^(-)(aq)+O_(2)(g)+2H_(2)O(1) rarr 4[Au(CN)_(2)]^(-)(aq)+ 4OH^(-)(aq)` `Zn(s)+2[Au(CN)_(2)]^(-) (aq) rarr [Zn(CN)_(4)]^(2-)+2Au(s)` |
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227. |
Which of the following system has maximum number of unpaired electrons ?A. `d^(4)`(octahedral , low spin )B. `d^(6)`(tetrahedral , high spin )C. `d^(6)`(octahedral , low spin )D. `d^(9)`(octahedral) |
Answer» Correct Answer - B | |
228. |
Which of the following pairs is not correctly matched?A. (a) Effective atomic number of `Pt` in `[PtCl_6]^(2-)=84`B. (b) Absorption peak for `[Cr^(III)(NH_3)_6]^(+3)=21680 cm^(-1)`C. (c) Crystal field stabilization energy of `d^2` in weak ligand field `=(-)0.8 Delta_o`D. (d) Example of weak ligand field for `d^5` configuration `=[Mn^(II)F_6]^(-4)` |
Answer» Correct Answer - A EAN of Pt in `[PtCl_6]^(2-)=80` |
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229. |
Which ion produces a small crystal field splitting (a weak ligand field)?A. (a) `I^(-)`B. (b) `Cl^(-)`C. (c) `F^(-)`D. (d) All |
Answer» Correct Answer - D Strong ligand produces more crystal field splitting. Weak ligand produces small crystal field splitting, thereby increasing strength of ligands `I^(-)ltBr^(-)ltS^(2-)ltSCN^(-)ltCl^(-)ltN^(3-)ltF^(-)` Weak field ligand `ltOH^(-)ltC_2 O_4^(-2)ltH_2OltNCS^(-)` `~H^(-)ltNH_3lten=CO_3^(2-)ltNO_2^(-)ltCN^(-)ltCO^(-)` increasing order of strong field ligands |
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230. |
In tetrahedral crystal field, three is splitting of d orbitals. Which of the following d orbitals constitute the higher energy set of orbirals.A. `d_(xy), d_(x^(2)-y^(2))`B. `d_(z^(2)), d_(x^(2)-y^(2))`C. `d_(xy), d_(yz), d_(xz)`D. `d_(z^(2)), d_(xz), d_(yz)` |
Answer» Correct Answer - C The second most common stereochemistry is tetrahedral. In the tetrahedral arrangement of four ligands around the metal ion, the `t_(2g)` orbitals `(d_(xy), d_(xz), d_(yz))` are more in line with the approaching ligands than the `e_(g)` orbitals `(d_(x^(2)-y^(2))` and `d_(z^(2)))` . As a result, it is the `(d_(x^(2)-y^(2))` and `d_(z^(2)))` orbitals that are lower in energy, and the tetrahedral energy diagram is inverted relative to the octahedral diagram. |
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231. |
Which of the following relations is correctA. `Delta_(t) = (9//4)Delta_(@)`B. `Delta_(t) = (2//3)Delta_(@)`C. `Delta_(t) = (3//2)Delta_(@)`D. `Delta_(t) = (4//9)Delta_(@)` |
Answer» Correct Answer - D With only four ligands instead of six and the ligands not quite pointing directly at the three d orbitals, the tetrahedral crystal field splitting is much less than in the octahedral case, in fact, it is about four-ninths of `Delta_(o)` As a result of the small orbital splitting, the tetrahedral complexes are almost all high spin. Tetrahedral complexes are most commonly found for halogen complexes such as the tetrachloridocobalate (II) ion `[CoC1_(4)]^(2-)` and for the oxyanions such as the tetraoxomolybdate (VI) ion, `MoO_(4)^(2-)` (commonly called molydate). |
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232. |
Nearly all tetrahedral complexes areA. high spinB. low spinC. intermediate spinD. complex spin |
Answer» Correct Answer - A Different geometric arrangements of the ligands give different energy splitting for the d orbitals. The splitting pattern in tetrahedral complexes is just the opposite of that in octahedral complexes , that is the `t_(2g)` orbitals have higher energy than the `e_(g)` orbitals. As with octahedral complexes, the energy ordering follows form the relative orientation of the orbital obes and the ligands. Because none of the orbitals points directly at the ligands in terahedral geometry and because there are only four ligands instead of six, the crystal field splitting in tetrahedral complexes in only about half `(4//9)` of that in octahedral complexes. Consequently, `Delta_(t)` is almost always smaller than the spin pairing energy P, and nearly all tetrahedral complexes are high spin. |
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233. |
Which of the following is not an organometallic compounds ?A. Sodium ethoxideB. Trimethoxytitanium chlorideC. trimethylorthoborateD. All of these |
Answer» Correct Answer - D The oranganometallic copmpounds must contain at lest one direct metal-to-carbon covalent bond. The metal can be transition, main group or f-group metal, and the term 'metal' is often stretched to include B, Si, Ge, As, Sb, Se and Te. The carbon containing group (s) may be a carbonyl, alkene, alkyne aromatic, cyclic or hetroctclic copmpound. Thus, sodium ethoxide `(Na^(+)barO C_(2)H_(5))` , trimethoxytitanium chloride `[(CH_(3)O)_(3)TiC1]` and trimethylorthoborate `[(CH_(3))_(3)BO_(3)]` are not organometallic compounds. |
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234. |
Which of the following d orbitals has highest energy in square planer complexes ?A. `d_(xy)`B. `d_(xy)`C. `d_(x^(2)-y^(2))`D. `d_(yz)` |
Answer» Correct Answer - C The crystal field splitting energy `Delta` is small in tetrahedral complexes but much larger in square planar complexes. Square palner complexes look loke octahedral ones except that the two trans ligands along the z axis are missing. In square planer complexes, the `d_(x^(2)-y^(2))` is highest in energy because it points directly at all four ligands, which lie along the x and y axes. The splitting pattern is more complicated here than for the octahedral and tetrahedral case, but the main point to remember is that a larger energy gap exists between the `d_(x^(2)-y^(2))` orbital and the four lower-energy orbitals. Square planar geomertry is mopst common for metal ions with electron configuration `d^(8)` because this configuration favours low spin complexes in which alll four lower energy orbitals are filled and the higher energy `d_(x^(2)-y^(2))` orbital is vacant. Common examples are `[Ni(CN)_(4)]^(2-)` , `[PdC1_(4)]^(2-)` `[PrC1_(4)]^(2-)` and `[Pt(NH_(3))_(2)C1_(2)]`. |
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235. |
Which of the following has largest paramagnetism ?A. `[Cr(H_(2)O)_(6)]^(3+)`B. `[Fe(H_(2)O)_(6)]^(2+)`C. `[Cu(H_(2)O)_(6)]^(2+)`D. `[Zn(H_(2)O)_(2)]^(2+)` |
Answer» Correct Answer - B More the number of unpaired electrons , higher is its paramagnetism . `Cr^(3+) : 3d^(3) , Fe^(2+) : 3d^(6) , Cu^(2+) : 3d^(9) , Zn^(2+) : 3d^(10)` `Fe^(2+)` has four unpaired electrons hence it shows highest paramagnetism . |
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236. |
Which of the following is a high spin complex ?A. `[Co(NH_(3))_(6)]^(3+)`B. `[Fe(CN)_(6)]^(4-)`C. `[Ni(CN)_(4)]^(2-)`D. `[FeF_(6)]^(3-)` |
Answer» Correct Answer - D | |
237. |
`[Co(NH_(3))_(5)SO_(4)]Br` and `[Co(NH_(3))_(5)Br]SO_(4)` shown _________isomerism . |
Answer» Correct Answer - Ionisation | |
238. |
`0.02` mole of `[Co(NH_(3))_(5)Br]Cl_(2)` and 0.02 mole of `[Co(NH_(3))_(5) Cl] SO_(4)` are present in 200 cc of a solution X . The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectivelyA. 0.02 , 0.02B. 0.01 , 0.02C. 0.02 , 0.04D. 0.04 , 0.02 |
Answer» Correct Answer - D `[Counderset(0.02 "mole") underset(1"mole") ((NH_(3))_(5))Br]Cl_(2) + 2 underset(2 "moles")(AgNO_(3)) to [Co(NH_(3))_(5)underset(1 "mole")(Br)](NO_(3))_(2) + 2 Agunderset(2 "moles")(Cl)_((ppt)) (Y)` `0.02 xx 2 = 0.04 ` mole `[Co(NH_(3))_(5)underset(1 "mole")(Cl)]SO_(4) + underset(0.02 "moles")(BaCl_(2)) to [Co(NH_(3))_(5)underset(1 "mole")(Cl)] Cl_(2) + BaSO_(4)_("(ppt.)") underset(0.02 "moles")((Z))` |
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239. |
Which has maximum paramagnetic nature ?A. `[Cu(H_(2)O)_(4)]^(2+)`B. `[Cu(NH_(3))_(4)]^(2+)`C. `[Mn(H_(2)O)_(6)]^(2+)`D. `[Fe(CN)_(6)]^(4-)` |
Answer» Correct Answer - C | |
240. |
Which one of the following is paramagnetic in nature ?A. `Ni(CO)_(4)`B. `[Ni(CN)_(4)]^(2-)`C. `K_(4)[Fe(CN)_(6)]`D. `[FeF_(6)]^(4-)` |
Answer» Correct Answer - D | |
241. |
The type of isomerism that `Co(NH_(3))_(4)Br_(2)Cl_(2)` can exhibit is/areA. geometric and ionisationB. ionisationC. Optical and ionisationD. Optical, ionisation and geometric |
Answer» Correct Answer - A | |
242. |
Prove that the lowering of the stabilised orbitals is `0.4Delta_(0)` while raising of the destabilised orbitalsw is `0.6Delta_(0)` . |
Answer» The total energy of separation is `Delta_(0)` Let `x=` energy of stabilisation and `y=` energy of destabilisation Then `y-x=Delta_(0)` Since the orbitals yield no net increase in energy when they are equally occupied `3x +2y =0` `implies 3x +2 (Delta_(0)) =0` `:. 5x = -2Delta_(0) x = - 0.4 Delta_(0)` and `y = +0.6 Delta_(0)` . |
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243. |
The spin-only magnetic moment of `[Fe(NH_(3))_(6)]^(3+) and [FeF_(6)]^(3-)` (in units of BM ) respectively areA. 1.73 and 1.73B. 5.92 and 1.73C. 1.73 and 5.92D. 5.92 and 5.92 |
Answer» Correct Answer - C | |
244. |
Optical isomerism is exhibited byA. `[Cr(NH_(3))_(5)Br]^(3+)`B. `[Cr(en)(H_(2)O)_(4)]^(3+)`C. trans `-[Cr(en)_(2)CI_(2)]^(2+)`D. `[Cr(en)_(3)]^(3+)` |
Answer» (d) Optical isomerism is exhibited by `[Cr(En)_(3)]^(3+)` | |
245. |
Give the number of unpaired electron(s) in the complex ion`[CoCI_(6)]^(3-)` . |
Answer» Correct Answer - 4 `Co^(3+) =3d^(6)` (weak field ligand , no pairing) `(n =4)` . |
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246. |
The number of somers of `[Cu(NH_(3))_(4)][PtCI_(4)]` areA. 6B. 3C. 4D. 5 |
Answer» (a) The possible number of isomerss are, (i) `[Cu(NH_(3))_(4)][PtCI_(4)]` (ii) `[Cu(NH_(3))_(2)CI_(2)].[PtCI_(2)(NH_(3))_(2)]` cis (iii) `[Cu(NH_(3))_(2)CL_(2)].[PtCI_(2)(NH_(3))_(2)]` trans (iv) `[Cu(NH_(3))_(3)CI][PtCI_(3)(NH_(3))]` (v) `[Cu(NH_(3)CL_(3)][PtCI(NH_(3))_(3)]` and (vi) `[CuCi_(4)][Pt(NH_(3))_(4)]` |
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247. |
The equation which is balanced and represents the correct product(s) is .A. `[Mg(H_(2)O)_(6)]^(2+)+(EDTA)^(4-)overset(ExcessNaOH)rarr[Mg(EDTA)]^(2+) +6H_(2)O`B. `CuSO_(4)+4KCNrarrK_(2)[Cu(CN)_(4)]+K_(2)SO_(4)`C. `Li_(2)O+2KCIrarr2LiCI +K_(2)O`D. `[CuCI(NH_(3))_(5)]^(o+)+5H^(o+)rarrCo^(2+) +5NH_(4)^(o+) +CI^(Θ)` |
Answer» Correct Answer - d Equation 1 is is not balanced w.r.t charge Equation `2givesK_(3)[Cu(CN)_(4)]` as product Equation 3 reaction is unfavourable in the forward direction `(K_(2)O` is unstable while `Li_(2)O` is stable `Equation 4 is correct and balanced . |
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248. |
Which of the following compound may be optical active ?A. `Co(en)_(2)Cl_(2)`B. `[Rh Cl Br NH_(3) PH_(3)]^(-)`C. `Cu(en)_(2)Cl_(2)`D. All of these |
Answer» Correct Answer - A | |
249. |
The number of ions formed when hexammine copper (II ) sulphate is dissolved in water isA. 1B. 2C. 4D. 6 |
Answer» Correct Answer - B The formula of hexammine copper (II ) sulphate is `[Cu(NH_(3))_(6)]SO_(4).` It dissolves in water as , `[Cu (NH_(3))_(6) ]SO_(4) hArr ubrace([Cu(NH_(3))_(6)]^(2+)+SO_(4)^(2-))_("2 ions")` |
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250. |
Which of the following factors does tends to increase the stability of metal ion complexes ?A. Higher ionic radius of the metal ionB. Higher charge / size ratio of the metal ionC. Lower ionisation potential of the metal ionD. Lower basicity of the ligands. |
Answer» Correct Answer - B | |