

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
1. |
Name a substance of which the resistance remains almost unchanged by the increase in temperature. |
Answer» (Managanin). |
|
2. |
The graph shown here shows the variation of terminal potential difference V, across a combination of three cells in series to a resistor, versus current i:(i) Calculate the emf of each cell.(ii) For what current i, will the power dissipation of the circuit be maximum? |
Answer» (i) Let ε be emf and r the internal resistance of each cell. The equation of terminal potential difference V = εeff – i rint becomes V = 3ε –i rint …(i) Where rint is effective (total) internal resistance. From fig., when i = 0, V = 6.0 V ∴ From (i), 6 = 3ε - 0 \(\Rightarrow \epsilon=\frac{6}{3}=2V\) i.e., emf of each cell, ε = 2 V Thus, emf of each cell, ε = 2V |
|
3. |
The plot of the variation of potential difference across a combination of three identical cells in series, versus current is shown below. What is the emf and internal resistance of each cell? |
Answer» Potential difference, E = 6/3 = 2 V Internal resistance, r = \(\frac{E}{I} = \frac{6}{1}\) = 6 ohm Given, three cells are connected in series, r' = r/3 = 6/3 = 2 ohm |
|
4. |
The plot of the variation of potential difference across a combination of three identical cells in series, versus current is shown alongside. What is the emf and internal resistance of each cell? |
Answer» We know that for a circuit V = Eeq - Ireq ....(i) From graph, when I = 0 A, then V = 6 V and when I = 1 A then V = 0 V Putting V = 6 V and I = 0 A in eq (i) 6 = Eeq - 0.req \(\Rightarrow\) Eeq = 6 V Eeq = ε1 + ε2 + ε3 \(\Rightarrow\) ε1 = ε2 = ε3 = ε = \(\frac{E}{3}\) = 2 V And, when I = 1 A, and V = 0 V 0 = 6 - 1. req \(\Rightarrow\) req = 6 Ω req = r1 + r2 + r3 \(\Rightarrow\) r1 = r2 = r3 = r = \(\frac{R}{3}\) = 2 ohm |
|
5. |
Nichrome and copper wires of same length and same radius are connected in series. Current I is passed through them. Which wire gets heated up more? Justify your answer. |
Answer» Nichrome wire gets heated up more. Heat dissipated in a wire is given by \(H=I^2Rt\) \(H=I^2 \,\frac{pl}{A}t\) \((\because\,R=\frac{pl}{A})\) Here, radius is same, hence area (A) is same. Also, current (I) and length (l) are same. \(\therefore \,H\infty\,r\) But Pnichorme > Pcopper ∴ Hnichrome > Hcopper |
|
6. |
What will be the equilibrium resistance between points A & D(A) 10 Ω(B) 20 Ω(C) 30 Ω(D) 40Ω |
Answer» The answer is (C) 30 Ω |
|
7. |
Two heater wires of equal lengths are first connected in series and then in parallel. The ratio of heat produced in two cases is(A) 2:1(B) 1:2(C) 4:1(D) 1:4 |
Answer» The answer is (C) 4:1 |
|
8. |
What is the net resistance between A and B?(A) R(B) 5R(C) 3R(D) 6R |
Answer» The answer is (A) R |
|
9. |
The rate of flow of charge through any wire is called ………… |
Answer» The rate of flow of charge through any wire is called Current. |
|
10. |
The net flow of charge at any point in the conductor is ……… |
Answer» The net flow of charge at any point in the conductor is Zero. |
|
11. |
Calculate the value of the shunt which when connected across a galvanometer of resistance 38 Ω will allow 1/20th of the current to pass through the galvanometer |
Answer» Data : G = 38 Ω, \(\cfrac{I_g}I\) = \(\cfrac1{20}\) Ig = \(\left(\cfrac{S}{S+G}\right)I\) ∴ \(\cfrac{I_g}I\) = \(\cfrac{S}{S+G}\) ∴ \(\cfrac1{20}\) = \(\cfrac{S}{S+38}\) ∴ S + 38 = 20 S ∴ 19 S = 38 ∴ S = 2 Ω This is the required value of the shunt. |
|
12. |
Define relaxation time or mean free time. |
Answer» The average time that elapses between two successive collisions of an electron with fixed atoms or ions in the conductor is called relaxation time. |
|
13. |
Define electron mobility. |
Answer» Mobility (μ) is defined as the magnitude of drift velocity (vd) per unit electric field (E). i.e. μ = (vd/E) |
|
14. |
What is the effect of relaxation time of electrons in a metal? |
Answer» Relaxation time decreases with increase in temperature. |
|
15. |
Define the term ‘Mobility’ of charge carries in a conductor. Write its SI unit. |
Answer» Mobility is defined as the magnitude of the drift velocity per unit electric field. μ = Vd/E = lτ/m where τ is the average collision time for electrons. The SI unit of mobility is m2 /Vs or m2 V–1 s–1 |
|
16. |
Write the mathematical relation for the resistivity of a material in terms of relaxation time, number density, mass and charge of charge carriers in it. Explain using this relation, why the resistivity of a metal increases and that of a semiconductor decreases with rise in temperature. |
Answer» Resistivity of a material, \(p=\frac{m}{ne^2r}\) Where m is mass, e is charge on charge carrier, n is number density and τ is relaxation time. For a metallic conductor: When temperature of a metal increases, the number of collisions of electrons with ion-lattice increases, so relaxation time decreases, as resistivity \(P\,\infty \frac{1}{T},\) so resistivity of material increases with rise of temperature. For a semiconductor: When temperature increases, the covalent bonds between valence electrons of atoms of semiconductor break, so more charge carriers (electrons and holes) becomes free. In other words the number density of charge carriers increases \(P\,\infty \frac{1}{n},\) so resistivity of semiconductor decreases with the rise of temperature. |
|
17. |
Derive an expression for the current density of a conductor in terms of the drift speed of electrons. |
Answer» Current density vector J is the current flowing through a conductor per unit are of cross section, it is a vector quantity and has the direction same as current. l = vector J.A Magnitude of current density J = l/A = nevd |
|
18. |
The flow of …………… constitutes the electric current in a wire. (a) Protons (b) Neutrons (c) Electrons (d) Gravitons |
Answer» Correct option is: (c) electrons |
|
19. |
Current stops flowing when potential difference between two ends of a wire becomes ………….. .(a) Zero (b) Positive (c) Negative (d) Higher |
Answer» Correct option is: (a) zero |
|
20. |
What is the unit of resistivity. |
Answer» The unit of resistivity is ohm metre (Qm). |
|
21. |
What is Earth wire? |
Answer» Earth wire is generally yellow or green colour, it is connected to a metal plate buried deep underground near the house and is for safety purpose. |
|
22. |
The conventional direction of flow of current is from …………… terminal to …………… terminal.(a) Negative to positive (b) Neutral to positive (c) Positive to negative (d) Positive to neutral |
Answer» Correct option is: (c) positive, negative |
|
23. |
Which substances are called conductors of electricity? |
Answer» Those substances which have very low electrical resistance are called conductors of electricity. |
|
24. |
What is the direction of conventional current ? |
Answer» From positive terminal of battery to negative terminal of battery through the external circuit. It is opposite to electron flow direction. |
|
25. |
Define the term (1) drift velocity (2) relaxation time. |
Answer» (1) drift velocity : It is defined as the average velocity gained by the free electrons of a conductor in the opposite of the externally applied electric field. (2) relaxation time : The average time that elapses between two successive collisions of an electron with fixed atoms or ions in the conductor is called relaxation time. |
|
26. |
A cell or battery maintained a dierence in potential between its two electrodes by the : A. mechanical processes B. electrical processes C. chemical processes D. None of the above |
Answer» C. chemical processes |
|
27. |
State Joule’s law of heating. |
Answer» It states that the heat developed in an electrical circuit due to the flow of current varies directly as: 1. the square of the current 2. the resistance of the circuit and 3. the time of flow. H = I2 R? |
|
28. |
In Joule’s heating law, when I and t are constant, if the H is taken along the y axis and I along the x axis, the graph is(a) straight line (b) parabola (c) circle(d) ellipse |
Answer» Correct answer is (a) straight line |
|
29. |
How is the current conducted in metals ? explain. |
Answer» Every metal conductor has large number of free electrons which move randomly at room temperature. Their average thermal velocity at any instant is zero. When a potential difference is applied across the ends of a conductor, an electric field is set up. Due to it, the free electrons of the conductor experience force due to electric field and drift towards the positive end of the conductor, causing electric current. |
|
30. |
A current of 2A ows through a 12V bulb then calculate the resistance ?A. 6 ohm B. 0.16 ohm C. 32 ohm D. ohm |
Answer» 6 ohm 12V bulb is calculate the resistance. |
|
31. |
What is Joule’s heating effect? |
Answer» When current flows through a resistor, some of the electrical energy delivered to the resistor is converted into heat energy and it is dissipated. This heating effect of current is known as Joule’s heating effect. |
|
32. |
A current of 3A ows through a conductor whose ends are at a p.d of 6V. Calculate the resistance of the conductor ?A. ohm B. 0.5 ohm C. 2 ohm D. 12 ohm |
Answer» V= IR, R= V/I, R= 6/3 =2 ohm |
|
33. |
What is meant by thermoelectric effect? |
Answer» Conversion of temperature differences into electrical voltage and vice versa is known as thermoelectric effect. |
|
34. |
Distinguish between:Conductors and Insulators |
||||||||||
Answer»
|
|||||||||||
35. |
Connect a 6V bulb to a 6V source. Using a multimeter, measure the resistance of the bulb when the circuit is switched off. Switch on the bulb for a short time, then switch it off and immediately measure its resistance.(i) Is the resistance the same in both the situations?(ii) When the circuit was switched on, was the temperature of the bulb low or high?(iii) Did the resistance increase or decrease when the temperature was increased?(iv) List the factors affecting the resistance of a conductor? |
Answer» (i) No (ii) High (iii) Resistance increased when the temperature was increased (iv)
|
|
36. |
Distinguish between:Resistance in Series and Resistance in Parallel |
||||||||||
Answer»
|
|||||||||||
37. |
What is a thermopile? On what principle does it work? |
Answer» Thermopile is a device used to detect thermal radiation. It works on the principle of seebeck effect. |
|
38. |
State whether the following statements are true or false. Correct the false statements:(1) The SI unit of charge is volt. (2) Voltmeter is always connected in series with the device. (3) The conventional direction of flow of current is from positive terminal to negative terminal. (4) Silver and copper are good conductors. (5) Resistivity of pure metals is more than alloys. (6) Resistance in series arrangement is used to decrease resistance of circuit. (7) A conducting wire offers less resistance to flow of electrons. (8) Charges are measured in ampere. (9) The unit of potential difference is ampere. (10) Resistance of a conductor is inversely proportional to the length of the conductor. (11) Ammeter is connected in parallel to the cell to measure current. (12) Fuse is made of wire having high melting point. |
Answer» (1) False. The SI unit of charge is coulomb. (2) False. Voltmeter is ahvays connected in parallel with the device. (3) True (4) True (5) False. Resistivity of pure metals is less than alloys. (6) False. Resistance in series arrangement is used to increase resistance of circuit. (7) True (8) False. Charges are measured in coulomb. (9) False. The unit of potential difference is volt. (10) False. Resistance of a conductor is directly proportional to the length of the conductor. (11) False. Ammeter is connected in series to the cell to measure current. (12) False. Fuse is made of wire having low melting point. |
|
39. |
What is a thermistor? |
Answer» A material with a negative temperature coefficient is called a thermistor. Eg: 1. Insulator 2. Semiconductor. |
|
40. |
Make pair:(i) Copper : Conductor :: Rubber : ……………….(ii) Aluminium : ………………. :: Indium oxide : Super Insulator(iii) Parallel Connection : \(\cfrac{1}{R_p}\)= \(\cfrac{1}{R_1}\)+ \(\cfrac{1}{R_2}\):: Series Connection : ……………….(iv) Electric Current : ………………. :: Electric charge : Coulomb(v) Electric resistance : Ohm :: Potential difference : ………………. |
Answer» (i) Insulator (ii) Super conductor (iii) Rs = R1 + R2 (iv) Ampere (v) Volt |
|
41. |
A potentiometer wire, having a resistance of 5 Ω and length 10 m, is connected in series a cell of emf 5 V and an external resistance of 495 Ω. A potential difference of 1.5 mV will balance against a length of (A) 3 cm (B) 30 cm (C) 3 m (D) none of these. |
Answer» Correct option is (B) 30 cm |
|
42. |
The open-circuit potential difference across the terminals of a cell balances on 150 cm of a potentiometer wire. When the cell is shunted by a 4.9 Ω resistor, the balancing length reduces to 147 cm. The internal resistance of the cell is(A) 0.01 Ω (B) 0.05 Ω (C) 0.1 Ω (D) 1 Ω |
Answer» Correct option is (C) 0.1 Ω |
|
43. |
A 10 m long potentiometer wire has a resistance of 20 Ω. If it is connected in series with a resistance of 55 Ω and a cell of emf 4 V and internal resistance 5 Ω, the potential gradient along the wire is (A) 0.1 V/m (B) 0.08 V/m (C) 0.01 V/m (D) none of these. |
Answer» Correct option is (A) 0.1 V/m |
|
44. |
State the uses of a potentiometer. |
Answer» The applications (uses) of the potentiometer : 1. Voltage divider : The potentiometer can be used as a voltage divider to change the output voltage of a voltage supply. 2. Audio control: Sliding potentiometers are commonly used in modern low-power audio systems as audio control devices. Both sliding (faders) and rotary potentiometers (knobs) are regularly used for frequency attenuation, loudness control and for controlling different characteristics of audio signals. 3. Potentiometer as a sensor: If the slider of the potentiometer is connected to the moving part of a machine, it can work as a motion sensor. A small displacement of the moving part causes a change in potential which is further amplified using an amplifier circuit. The potential difference is calibrated in terms of displacement of the moving part. 4. To measure the emf (for this, the emf of the standard cell and potential gradient must be known). 5. To compare the emf’s of two cells. 6. To determine the internal resistance of a cell. |
|
45. |
Why is potentiometer preferred over a voltmeter for measuring emf? |
Answer» A voltmeter should ideally have an infinite resistance so that it does not draw any current from the circuit. However a voltmeter cannot be designed to have infinite resistance. A potentiometer does not draw any current from the circuit at the null point. Therefore, it gives more accurate measurement. Thus, it acts as an ideal voltmeter. |
|
46. |
State the potentiometer principle. |
Answer» Potential difference between two points of a current carrying conductor is directly proportional to the length of the wire between two points. |
|
47. |
“When electric current is passed through a resistance wire, it get heated up”.1. Name the law associated with this phenomenon.2. What happens to the heat energy developed, if the current through the wire is doubled. |
Answer» 1. Joules law of heating 2. Heat developed in the conductor H = I2 R If current is doubled, Heat developed becomes 4 times. |
|
48. |
1. State whether the following statement is true or false “The value of resistance of a metal increase with the rise of temperature”.2. Explain the reason.3. With the help of the graph, match the following4. Alloys like manganin, eureka, constantan, etc. are used in making standard resistance coils. Why? |
Answer» 1. True. 2. When temperature increases, the amplitude of vibration of atom increases. Hence relaxation time decreases. Hence resistivity of metal increases according to the equation \(ρ=\frac{m}{ne^2\tau}\) 3. A ....... Carbon B ....... Manganin C ............. Iron. 4. The temperature coefficient of resistance of manganin, eureka and constantan, etc are zero. Hence they are used in making standard resistance coils. |
|
49. |
1. Potentiometer is better than voltmeter for measuring emf becauseIt is cheapEasy to handleIts measurement uses null method2. Give the basic principle of potentiometer,3. If K2 is open balancing length is 600 cm, if K2 is closed 350 cm is balancing length. Calculate the internal resistance. |
Answer» 1. Its measurement uses null method. 2. Principle: Potential difference between two points of a current carrying conductor (having uniform thickness) is directly proportional to the length of the wire between two points. 3. I = 600 cm, I = 350 cm \(r=R\Big(\frac{I-I_1}{I_1}\Big)\) r = 3 \(\Big(\frac{600-350}{350}\Big)\) = \(\frac{3\times250}{350}\) = 2.1 Ω |
|
50. |
Match the following. A B CDrift speedTemperature104Relaxation timeMagnetic field10-6Electron mobility in metalElectric field10-7Proportionally constant10-3 |
||||||||||||
Answer»
|
|||||||||||||