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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

Which of the following is an example of an Ohmic conductor?(a) Nichrome(b) Water voltameter(c) Gallium Arsenide(d) ThyristorI have been asked this question in homework.I would like to ask this question from Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

Correct answer is (a) Nichrome

For explanation: Most of the metals obey Ohm’s LAW and they are called ohmic conductors. WHEREAS semiconductors are non-ohmic. Nichrome METAL is an ohmic conductor in which the V-I CHARACTERISTIC has a STRAIGHT line passing through the origin.

52.

A potential difference of 100 V is applied across a conductor of length 50cm. Calculate the drift velocity of electrons if the electron mobility is 9 × 10^-5 m^2V^-1s^-1.(a) 0.001 ms^-1(b) 1.800 ms^-1(c) 0.018 ms^-1(d) 0.180 ms^-1The question was posed to me during an interview.Question is from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

Correct answer is (c) 0.018 ms^-1

Easiest explanation: Drift velocity = Mobility × ELECTRIC field.

It can be REARRANGED as,

Drift velocity = \(\frac {(mobility \, \TIMES \, Potential \, DIFFERENCE)}{LENGTH}\).

Drift velocity = \(\frac {(9 × 10^{-5} \times 100)}{0.5}\) = 0.018 ms^-1.

53.

Give the SI unit of resistivity.(a) ohm/metre^2(b) ohm metre^2(c) ohm metre(d) ohm/metreI got this question in class test.I'm obligated to ask this question of Ohm’s Law in portion Current Electricity of Physics – Class 12

Answer»

Right answer is (c) ohm METRE

Best EXPLANATION: Resistivity = \(\FRAC {(Resistance \, \TIMES \, Area)}{LENGTH}\)

SI unit of resistivity=\(\frac {(ohm \, \times \, metre^2)}{metre}\)

 = ohm metre.

54.

Give the number of electrons passing through a wire per minute. The current flowing through it is 500mA.(a) 1.875 × 10^20(b) 6.875 × 10^20(c) 1.875 × 10^-20(d) 6.875 × 10^-20The question was asked in quiz.My question comes from Electric Current in chapter Current Electricity of Physics – Class 12

Answer» CORRECT choice is (a) 1.875 × 10^20

For explanation I would SAY: Number of electrons, n = \(\frac {It}{E}\).

= \(\frac {(500 \times 10^{-3} \times 60)}{(1.6 \times 10^{-19})}\)

= 1.875 × 10^20.
55.

The emf of a cell depends upon concentration of the electrolyte.(a) True(b) FalseI have been asked this question during an interview.Enquiry is from Current Electricity in chapter Current Electricity of Physics – Class 12

Answer»

The CORRECT option is (a) True

Explanation: The emf of a CELL depends upon the NATURE of ELECTRODES, nature and concentration of ELECTROLYTE used in the cell and its temperature as well. Emf of a cell is inversely proportional to the concentration of the electrolyte.

56.

Which is the factor that internal resistance does not depend on?(a) Distance between the electrodes(b) Temperature of the electrolyte(c) Nature of electrode and electrolyte(d) Area of the electrode, immersed in the electrolyteThis question was addressed to me in quiz.My question comes from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

The correct choice is (b) Temperature of the electrolyte

The best explanation: Internal RESISTANCE is defined as the resistance OFFERED by the electrolyte and electrodes of a CELL when the current flows through it. Internal resistance DEPENDS on distance between the electrodes, the nature of electrodes and electrolyte, and area of the electrode immersed in the electrolyte. So, that leaves temperature of the electrolyte out, which is the answer.

57.

The power consumed by a 300 V bulb, having a resistance of 100 ohms, is 3 Watts.(a) True(b) FalseI have been asked this question by my school teacher while I was bunking the class.My query is from Current Electricity in portion Current Electricity of Physics – Class 12

Answer»

Correct answer is (b) False

To explain I would SAY: Electric power can ALSO be calculated or represented in other ways, such as: Power = voltage × CURRENT; Power = current^2 × resistance; Power = \(\frac {voltage^2}{resistance}\). In this case, we can use the EQUATION – Power = \(\frac {voltage^2}{resistance}\). Voltage = 300 V; Resistance = 100 ohms

Power = \(\frac {300 \times 300}{100}\)

= 900 Watts

Therefore, the power consumed by a 300 V BULB, having a resistance of 100 ohms, is 900 Watts.

58.

Identify the type of materials which have resistivities in the range of 10^-8 Ωm to 10^-6 Ωm.(a) Semiconductors(b) Insulators(c) Conductors(d) ThyristorsThe question was asked in an international level competition.This intriguing question originated from Current Electricity in division Current Electricity of Physics – Class 12

Answer»

Right choice is (c) Conductors

To explain I would SAY: Conductors have low resistivities in the range of 10^-8 Ωm to 10^-6 Ωm. Metals are GOOD conductors. Conductors are objects or types of material that allows the flow of charge in ONE or more directions, and a result, the resistance offered against the flow of charge will be less.

59.

Identify the dimensional formula of electric current.(a) [M L T^-2](b) [M^0 L^0 T^0 A^1](c) [M L^3 T^0](d) [M L^2 T^-3]This question was posed to me in semester exam.Question is from Electric Current in portion Current Electricity of Physics – Class 12

Answer»

The CORRECT answer is (b) [M^0 L^0 T^0 A^1]

EXPLANATION: The flow of charge per unit time is defined as current. The FUNDAMENTAL unit of current is Ampere (named after ANDRE Marie Ampere).

Hence the DIMENSIONAL formula of electric current is [M^0 L^0 T^0 A^1].

60.

Pick out the correct statement from the following about parallel combination of resistors.(a) The current across the resistors are the same(b) The resistance offered by all resistors are the same(c) The potential difference is same across each resistor(d) The equivalent overall resistance is larger than the largest resistorThe question was asked by my college director while I was bunking the class.The above asked question is from Combination of Resistors topic in chapter Current Electricity of Physics – Class 12

Answer» RIGHT CHOICE is (c) The potential difference is same across each resistor

The best I can explain: In parallel combination, the resistors are connected TOGETHER at one end, and are ALSO all connected together at the other end. So, the potential difference across the resistors will not change and THUS, remains the same.
61.

Which of the following is not a valid reason for using alloys to make standard resistors?(a) Alloys have a high value of resistivity(b) They are least affected by air and moisture(c) Alloys have a large temperature coefficient(d) Their contact potential with copper is smallI got this question in an internship interview.The query is from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

Right ANSWER is (C) Alloys have a large temperature coefficient

To explain: Alloys have a HIGH value of resistivity. They have a very small temperature coefficient. So their resistance does not CHANGE appreciably even for several DEGREES rise of temperature. That leaves the answer – alloys have a large temperature coefficient.

62.

The resistivity of semiconductors and insulators decreases linearly with the increase of temperature.(a) True(b) FalseI had been asked this question by my college professor while I was bunking the class.Origin of the question is Current Electricity in chapter Current Electricity of Physics – Class 12

Answer»

Right option is (b) False

For EXPLANATION: The resistivity of semiconductors and INSULATORS DECREASES exponentially with the increase in TEMPERATURE. This is because the number density of FREE electrons increases exponentially with the increase in temperature.

63.

What is the study of electric charges in motion called?(a) Charge mobility(b) Electronic mobility(c) Static electricity(d) Current electricityThe question was posed to me during an online exam.This interesting question is from Electric Current topic in section Current Electricity of Physics – Class 12

Answer»

Correct option is (d) CURRENT ELECTRICITY

The explanation: The study of MOTION or dynamics of charges constitute an electric current. Therefore, the study of electric charges in motion is called current electricity.

64.

What is the reciprocal of resistivity of a material called? Give its unit.(a) Conductance, ohm^-1(b) Conductivity, ohm^-1 m^-1(c) Conductance, ohm^-1 m^-1(d) Conductivity, ohm^-1I have been asked this question in homework.Query is from Ohm’s Law topic in portion Current Electricity of Physics – Class 12

Answer»

Right choice is (b) Conductivity, ohm^-1 m^-1

The best EXPLANATION: Conductivity = \(\frac {1}{Resistivity}\)

SI unit of conductivity = \(\frac {1}{ohm \, meter}\)

= ohm^-1 m^-1.

65.

Calculate the number of units of electricity used if a bulb of 100 W is kept on for 5 hours.(a) 1 unit(b) 0.1 unit(c) 5 unit(d) 0.5 unitThe question was asked in an internship interview.This key question is from Current Electricity in chapter Current Electricity of Physics – Class 12

Answer»

Correct answer is (d) 0.5 unit

The best I can explain: The NUMBER of units of electricity consumed is

n = \(\frac {(TOTAL \, wattage \, \TIMES \, TIME \, in \, hour)}{1000}\)

Total wattage = 100 WTime in hour = 5 hours

Therefore,n = \(\frac {100 \times 5}{1000}\)

= 0.5 units

So, the number of units of electricity consumed is 0.5 units.

66.

Which type of current is flowing through a circuit?(a) Static current(b) Conventional current(c) Electronic current(d) Potential currentThe question was asked by my college director while I was bunking the class.The question is from Electric Current in division Current Electricity of Physics – Class 12

Answer»

The correct answer is (c) ELECTRONIC current

Best explanation: The carriers of electric current are electrons. The current in a circuit is DUE to the flow of electrons. THEREFORE, the direction of the CONVENTIONAL current is OPPOSITE to the direction of flow of electrons.

67.

A cell has an emf of 6V, internal resistance of 1 ohms and a current of 0.5 A passing through it. This cell is connected to a resistor. Find out the resistance of the resistor.(a) 10 ohms(b) 11 ohms(c) 12 ohms(d) 13 ohmsThis question was posed to me during an online exam.My doubt is from Current Electricity in chapter Current Electricity of Physics – Class 12

Answer»

The correct CHOICE is (b) 11 ohms

The EXPLANATION is: Emf (e) = 6V; Internal RESISTANCE (r) = 1 ohms; Current (I) = 0.5A

Required equation: I = \(\frac {e}{R}\) + r

0.5 = \(\frac {6}{R}\) + 1

R = \(\frac {(6 – 0.5)}{0.5}\)

R = 11 ohms

Therefore, the resistance of the resistor is 11 ohms.

68.

One watt is equal to __________(a) one kilowatt per second(b) one kilo joule per second(c) one joule per second(d) one joule per minuteThe question was asked during an online exam.This interesting question is from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

Correct choice is (C) one JOULE per second

The BEST explanation: WATT is the SI unit of power. Power = \(\FRAC { work \, done}{time}\). The SI unit of work done is the same as energy, that is, joule and that of time is seconds. Therefore, one watt is equal to one joule per second.

69.

Which of the following relation is significant for metals when the temperature increases?(a) Resistivity increases and conductivity decreases(b) Resistivity decreases and conductivity decreases(c) Resistivity and conductivity do not change with temperature(d) Temperature dependence is non-linearI had been asked this question during a job interview.My enquiry is from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

Right answer is (a) Resistivity increases and conductivity decreases

The best I can explain: The resistivity of a metal increases and the conductivity decreases with the INCREASE in TEMPERATURE. With an increase in temperature, the free electrons COLLIDE more frequently with the metal IONS. The mean collision time also decreases.

70.

Which type of a physical quantity is electric current?(a) Scalar quantity(b) Vector quantity(c) Bipolar quantity(d) Thermodynamic quantityThe question was asked in examination.This intriguing question comes from Electric Current topic in portion Current Electricity of Physics – Class 12

Answer»

The correct choice is (a) Scalar quantity

For explanation: The electric CURRENT is a scalar quantity. Laws of ordinary algebra are used to ADD electric CURRENTS and the law of VECTOR algebra are not applicable.

71.

Two resistors are connected in parallel, whose resistance values are in the ratio 3:1. Find the ratio of power dissipated.(a) 1:3(b) 3:1(c) 1:2(d) 2:1I got this question in a national level competition.Query is from Combination of Resistors topic in chapter Current Electricity of Physics – Class 12

Answer»

Right CHOICE is (a) 1:3

For explanation: We can consider the relation that INCLUDES power and RESISTANCE, i.e.Power = \(\frac {voltage^2}{resistance}\). SINCE, the resistors are connected in parallel, the voltage across them will be the same. From this relation, power and resistance are inversely proportional to each other.

Thus, \(\frac {P1}{P2} = \frac {R2}{R1} = \frac {1}{3}\)

So, the power dissipated is in the RATIO is 1:3.

72.

Identify the correct statement from the following about discharging of a cell.(a) The direction of current in the cell is from positive to negative terminal(b) Terminal potential difference is greater than emf of the cell(c) Terminal potential difference is lesser than emf of the cell(d) The current increases and decreases frequentlyI had been asked this question by my school teacher while I was bunking the class.I need to ask this question from Current Electricity topic in division Current Electricity of Physics – Class 12

Answer»

The correct ANSWER is (c) TERMINAL potential DIFFERENCE is LESSER than emf of the cell

For EXPLANATION I would say: During discharging of a cell terminal potential difference, the terminal potential difference is lesser than the emf of the cell. The direction of current inside the cell is from negative terminal to positive terminal.

73.

In parallel grouping of cells, we obtain more current.(a) True(b) FalseThis question was addressed to me in semester exam.My question comes from Current Electricity in division Current Electricity of Physics – Class 12

Answer»

Correct answer is (a) True

The explanation: Yes, in parallel GROUPING of cells, we obtain more current. In parallel combination, the voltage remains the same and the RESISTANCE OFFERED is minimum. As more cells are added parallel to each other, then the resistance will keep reducing. As a RESULT, more current can be obtained.

74.

Which among the following has weak temperature dependence values with resistivity?(a) Silver(b) Copper(c) Nichrome(d) GermaniumThis question was addressed to me in exam.I need to ask this question from Current Electricity in portion Current Electricity of Physics – Class 12

Answer»

Correct choice is (c) Nichrome

To explain I would say: ALLOYS have high RESISTIVITY. The resistivity of nichrome has WEAK temperature dependence. At absolute zero, a PURE metal has negligibly small resistivity while an alloy like nichrome has some RESIDUAL resistivity.

75.

What is the unit of the temperature coefficient of resistance (α)?(a) ^oC(b) ^oC^-1(c) \(\frac {\Omega}{ ^{\circ} C}\)(d) \(\frac { ^{\circ} C}{\Omega}\)This question was addressed to me in semester exam.I would like to ask this question from Current Electricity in portion Current Electricity of Physics – Class 12

Answer» RIGHT choice is (b) ^oC^-1

The best I can explain: The temperature COEFFICIENT of resistivity is defined as the increase in resistivity PER UNIT resistivity per degree RISE in temperature.

The unit of the temperature coefficient of resistance is ^oC^-1.
76.

Identify the material whose resistivity is more than 10^14 Ωm.(a) Bakelite(b) Copper(c) Aluminum(d) SiliconI got this question by my college director while I was bunking the class.I'd like to ask this question from Current Electricity topic in division Current Electricity of Physics – Class 12

Answer»

Correct answer is (a) Bakelite

To EXPLAIN I would say: INSULATORS are materials which do not conduct electric current, and thereby, offer high resistance to the FLOW of charges. Insulators LIKE bakelite and hard rubber have very high resistivities in the RANGE of 10^14 to 10^16 Ωm.

77.

Ohm’s law is a fundamental law of nature. State true or false.(a) True(b) FalseI had been asked this question in class test.This intriguing question originated from Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

Right option is (b) False

The best I can explain: OHM’s LAW is not a fundamental law of nature. Some reasons for the failure of ohm’s law are: Potential DIFFERENCE MAY vary non-linearly with the current ; The V-I relationship may be non-unique; The VARIATION of current with potential difference may depend upon the sign of the potential difference applied.

78.

In series connection of resistors, what happens to the current across each resistor?(a) Increases(b) Decreases(c) Remain the same(d) Initially increases and then decreasesI got this question in semester exam.My doubt stems from Combination of Resistors in division Current Electricity of Physics – Class 12

Answer» CORRECT choice is (C) Remain the same

The EXPLANATION is: When the resistors are connected in series, and CURRENT is PASSED through them, the current passing through each of the resistor is the same. This is because, the resistors are connected end to the end and, therefore, there is only one path for the current to flow through.
79.

Calculate the number of dry cells, each of emf 2V and internal resistance 1V that is joined in series with a resistance of 30 ohms so that a current of 0.8A passes through it.(a) 20(b) 10(c) 30(d) 40The question was posed to me in class test.This interesting question is from Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer» CORRECT answer is (a) 20

The explanation is: Emf = 2V; r = 1 ohm; I = 0.8A; R = 30 ohms

The REQUIRED equation: I = \(\frac {(n \times e)}{ [(n \times r) + R] }\)

0.8 = \(\frac {(n \times 2)}{ [(n \times 1) + 30] }\)

0.8n + 24 = 2n

1.2n = 24

n = \(\frac {24}{1.2}\) = 20

Therefore, the number of DRY cells required are 20.
80.

The equivalent overall resistance is smaller than the smallest parallel resistor.(a) True(b) FalseI had been asked this question in my homework.My enquiry is from Combination of Resistors topic in portion Current Electricity of Physics – Class 12

Answer»

Right choice is (a) True

The explanation: Yes, the equivalent overall resistance is SMALLER than the smallest resistor connected in parallel. This is because, the overall equivalent resistance of parallel COMBINATION is: Rp = \(\frac {1}{R_1} + \frac {1}{R_2} + \frac {1}{R_3}\). When the inverse of a resistance value is taken, the value obtained is lesser than the original value. THUS, the sum of inverse values will only provide a lesser value than the initial RESISTANCES.

81.

Which one of the following is the practical unit of power?(a) Watt (W)(b) Kilowatt hour (kWh)(c) Horse power (hp)(d) Kilojoule (kJ)I got this question in class test.Question is from Current Electricity in portion Current Electricity of Physics – Class 12

Answer» RIGHT choice is (c) Horse POWER (HP)

Best explanation: The practical unit of power is horse power (hp). KILO watt is also another practical unit of power. 1 kilowatt = 1000 watt; 1 hp = 746 watt. It is usually used in REFERENCE to the output of engines or motors.
82.

Kabir bought 5 new light bulbs of 50 W each in addition to the 7 bulbs he already had in his house which were also 50 W each. Calculate his electricity bill, if he keeps the new bulbs on for 5 hours and the older bulbs on only for 3 hours, and the cost of one unit of electricity is Rs. 60.(a) Rs.136(b) Rs.137(c) Rs.138(d) Rs.139The question was asked in final exam.My question is based upon Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

Correct option is (c) Rs.138

To explain: NEW bulbs = 5; OLD bulbs = 7; Total WATTAGE of new bulbs = 5 × 50;

Total wattage of old bulbs = 7 × 50; TIME the new bulbs are kept on = 5 hours;

Time the old bulbs are kept on = 3 hours

The number of units of electricity consumed by new bulbs (n1) = \(\frac {(total \, wattage \, \times \, time \, in \, hours)}{1000}\)

= \(\frac {50 \times 5 \times 5}{1000}\) = 1.25

The number of units of electricity consumed by old bulbs (n2) = \(\frac {50 \times 7 \times 3}{1000}\) = 1.05Total BILL of electricity = number of units of electricity consumed × amount for one unit of electricity

= (n1 + n2) × 60

= (1.25 + 1.05) × 60

= 138

Therefore, his electricity bill will be Rs. 138.

83.

What is the SI unit of current?(a) Coulomb (C)(b) Ampere (A)(c) Farad (F)(d) Newton (N)The question was asked in homework.Asked question is from Electric Current in section Current Electricity of Physics – Class 12

Answer» RIGHT CHOICE is (b) Ampere (A)

The best EXPLANATION: The SI unit of current is Ampere (A). The current through a wire is called one ampere if one COULOMB of charge flows through the wire per second.

1 Ampere= \(\frac {1 \, Coulomb}{1 \, Second}\) or 1A = 1Cs^-1.
84.

Which of the following is the correct statement regarding electrochemical cell?(a) It converts chemical energy to electrical energy(b) It converts electric energy to chemical energy(c) It converts chemical energy to thermal energy(d) It does not maintain the flow of charge in a circuitI got this question during an interview for a job.Asked question is from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

Right choice is (a) It converts chemical energy to electrical energy

Best explanation: An electrochemical cell is a device which converts chemical energy to ELECTRIC energy, and maintains the flow of charge in a circuit. There are 2 types of electrochemical cells – GALVANIC cell and ELECTROLYTIC cell.

85.

1 kWh = ___________(a) 3.6 × 10^6 J(b) 3.6 × 10^5 J(c) 0.36 × 10^6 J(d) 0.36 × 10^5 JI got this question in an interview for job.My query is from Current Electricity topic in division Current Electricity of Physics – Class 12

Answer»

The CORRECT answer is (a) 3.6 × 10^6 J

The explanation: The COMMERCIAL unit of electric energy is kilowatt-hour (kWh).

1 kWh = 1000 Wh = 3.6 × 10^6J = one unit of electricity CONSUMED. The electric energy used in factories, industries and houses are measured in kWh.

86.

Which of the following is a widely used variety of commercial resistor?(a) Bio amplification resistor(b) Wire-bound resistor(c) Ultrasonic resistor(d) Copper resistorThe question was posed to me by my college professor while I was bunking the class.My enquiry is from Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

Correct choice is (b) Wire-bound resistor

The best EXPLANATION: A wire bound resistor is an electrical passive component that limits current. Wire-bound RESISTORS are MADE by winding the wires of an ALLOY like manganin on an insulating base. They are relatively insensitive to temperature.

87.

The SI unit of electrical energy is ____________(a) kilojoule (KJ)(b) joules (J)(c) watt (W)(d) kilowatt (KW)The question was posed to me in my homework.My question is based upon Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer» CORRECT choice is (b) joules (J)

To explain I would say: Electric ENERGY is defined as the total electric work done or energy supplied by the SOURCE of emf in maintaining the current in an electric circuit for a given time. The SI unit of electrical energy is joule (J). The commercial unit of electric energy is kilowatt-hour (KWH).
88.

Which of the following is an example of a non-ohmic conductor?(a) Copper(b) Silver(c) Silicon(d) NichromeI have been asked this question during an interview.My question is from Current Electricity topic in division Current Electricity of Physics – Class 12

Answer»

The correct choice is (C) SILICON

To explain I would say: Silicon is an example of a non-ohmic conductor. It EXHIBITS non-linear behaviour. After a certain voltage, the current decreases as the voltage INCREASES. The V-I PLOT for silicon is non-linear.

89.

In nature, free charged particles exist in the upper strata of the environment called the stratosphere. State true or false.(a) True(b) FalseI got this question in an online interview.This interesting question is from Electric Currents in Conductors in portion Current Electricity of Physics – Class 12

Answer»

Right CHOICE is (B) False

Explanation: Free CHARGED particles exist in the upper strata of environment called the ionosphere. It is a region which is IONIZED by solar radiation and includes PARTS of thermosphere, mesosphere and exosphere.

90.

What is the equivalent resistance of series combination of 3 resistors?(a) Rs = R1 + R2 + R3(b) Rs = \(\frac {1}{(R_1 + R_2 + R_3 )}\)(c) Rs = \(\frac {1}{R_1} + \frac {1}{R_2} + \frac {1}{R_3}\)(d) Rs = \(\frac {(R_1 + R_2)}{R_3}\)I got this question in unit test.Enquiry is from Combination of Resistors topic in portion Current Electricity of Physics – Class 12

Answer»

Correct choice is (a) RS = R1 + R2 + R3

For explanation I would say: When three resistors are CONNECTED in series, then the equivalent RESISTANCE of this combination is Rs = R1 + R2 + R3. So, if 3 resistors having resistances 10, 15, and 20 ohms, are connected in series, then equivalent resistance of this combination is Rs = 10+15+20 = 45 ohms.

91.

Identify the correct formula of electric power.(a) Electric power = \(\frac {time \, taken}{electric \, work \, done}\)(b) Electric power = \(\frac {electric \, work \, done}{time \, taken}\)(c) Electric power = electric work done × time taken(d) Electric power = \(\frac {1}{electric \, work \, done}\)The question was posed to me in an interview for job.Enquiry is from Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

The correct choice is (b) Electric power = \(\frac {electric \, WORK \, done}{time \, TAKEN}\)

To explain I would say: Electric power is defined as the rate at which work is done by the SOURCE of EMF in maintaining the CURRENT in the electric circuit. So, the formula of electric power is:

Electric power (P) = \(\frac {electric \, work \, done}{time \, taken}\)

92.

If the fourth band of the carbon resistor is absent, it implies there is no tolerance.(a) True(b) FalseI have been asked this question in my homework.My question comes from Current Electricity in section Current Electricity of Physics – Class 12

Answer»

The correct option is (b) False

For explanation: The fourth band INDICATES the tolerance or POSSIBLE VARIATION in the percent of the INDICATED value. If the fourth band is absent, it implies the tolerance of the resistor is ±20%.

93.

What is the SI unit of mobility?(a) Vm^-1(b) m^2V^-1s^-1(c) mV^-2(d) m^2V^-2s^-1The question was asked by my school teacher while I was bunking the class.The origin of the question is Current Electricity in chapter Current Electricity of Physics – Class 12

Answer»

Right choice is (b) m^2V^-1s^-1

The explanation is: The SI UNIT of MOBILITY is m^2V^-1s^-1.

Mobility = \(\FRAC {Drift \, velocity}{Electric \, field}\)

SI unit = \(\frac {ms^{-1}}{Vm^{-1}}\) = m^2V^-1s^-1.

94.

What will be the grouping of cells when the current in the circuit is \(\frac {ne}{(R + nr)}\)?(a) Parallel grouping(b) Series grouping(c) Mixed grouping(d) When there is no groupingI had been asked this question by my school teacher while I was bunking the class.The query is from Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer»

The correct CHOICE is (B) Series grouping

For explanation: When n identical cells, each of emf ‘E’ and internal resistance ‘r’ are connected to the external resistance ‘R’ in series, its called series grouping. In series grouping eeq = ne and REQ = nr Therefore, current in the circuit (I) = \(\frac {ne}{(R + nr)}\).

95.

Find the resistance value of the carbon resistor if the colors of the four bands are red, red, red and silver respectively.(a) 33 × 10^2Ω ± 20%(b) 22 × 10^2Ω ± 5%(c) 22 × 10^2Ω ± 10%(d) 33 × 10^3Ω ± 10%I got this question in an online interview.Query is from Current Electricity in portion Current Electricity of Physics – Class 12

Answer» CORRECT choice is (c) 22 × 10^2Ω ± 10%

To explain: A color CODE is used to indicate the resistance VALUE of a carbon RESISTOR and its percentage accuracy. The CORRESPONDING value of resistance for the given color code is 22 × 10^2 Ω ± 10% (Red-2; Red-2; Red-2; Silver-10%).
96.

Identify the material which is suitable for making standard resistors.(a) Silver(b) Copper(c) Constantan(d) GermaniumThis question was addressed to me in my homework.This intriguing question originated from Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer»

Correct CHOICE is (C) Constantan

For explanation: Alloys like constantan or manganin are used for making standard RESISTANCE coils due to their high resistivity values and very small TEMPERATURE coefficient.

97.

Identify the type of conductor in which the variation of current with potential difference may depend upon the sign of the potential difference applied.(a) Metallic conductor(b) Thyristor(c) Water voltameter(d) p-n junction diodeThe question was posed to me during an internship interview.Question is taken from Current Electricity in portion Current Electricity of Physics – Class 12

Answer»

The CORRECT option is (d) p-n junction diode

Easiest explanation: p-n junction diode consists of p-type and n-type semiconductors. The V-I relationship is non-linear. When a VOLTAGE is APPLIED across junction, very little current flows for the fairly high NEGATIVE voltage and a current begins to flow for much smaller positive (forward) bias. The magnitude of variation DEPENDS upon the sign of potential difference applied across it.

98.

For small currents, ‘X’ obeys Ohm’s law. But when large currents are passed through the same conductor, it deviates from ohmic behaviour. Identify X.(a) Metallic conductor(b) Gallium arsenide(c) Thyristor(d) p-n junction diodeThe question was asked in an interview.The origin of the question is Current Electricity in portion Current Electricity of Physics – Class 12

Answer»

Right answer is (a) METALLIC conductor

The explanation is: ‘X’ is a metallic conductor. For small currents, it obeys OHMS’s law and its V-I GRAPH is a straight line. But when large currents are passed through the same conductor, it gets heated up and its resistance increases. It no longer obeys OHM’s law at higher currents.

99.

Which of these relation holds good for an Ohmic conductor?(a) V-I relationship is non-linear(b) The straight-line V-I graph pass through the origin(c) V-I relationship is non-unique(d) V-I relationship depends on the sign of V for the same absolute value of VI got this question during an online interview.The doubt is from Current Electricity topic in section Current Electricity of Physics – Class 12

Answer»

Correct option is (b) The straight-LINE V-I graph PASS through the origin

To explain: The conductors which obey Ohm’s LAW are called Ohmic conductors. The linear relationship between voltage and current for these conductors hold good. The resistance (R=\(\FRAC {V}{I}\)) is independent of the current through the conductor. The magnitude of current changes linearly with voltage. Hence the V-I graph for ohmic conductors is a straight line PASSING through the origin.

100.

Calculate the drift velocity of free electrons if a current of 200 A is maintained in a conductor of cross-section 10^-3m^2. The number density of free electrons is 96 × 10^20 m^-3.(a) 130.20 ms^-1(b) 13.020 ms^-1(c) 1.3020 ms^-1(d) 0.1302 ms^-1I have been asked this question by my college director while I was bunking the class.Query is from Current Electricity topic in portion Current Electricity of Physics – Class 12

Answer»

Right OPTION is (a) 130.20 ms^-1

Explanation: DRIFT velocity = \(\frac {Current}{(number \, DENSITY \, of \, electrons \, \times \, charge \, on \, electron \, \times \, Area)}\).

=\(\frac {200}{(96 \times 10^{20} \times 1.6 \times 10^{-19} \times 10^{-3})}\)

= 130.20 ms^-1.