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201.

The first machine cycle of an instruction is always

Answer» Fetch cycle is always first machine cycle.
202.

A counter has N flip flops. The total number of states are

Answer» One flip-flop means 2 states and N flip-flops means 2N states.
203.

Out of S, R, J, K, Preset, Clear inputs to flip flops, the synchronous inputs are

Answer» Preset and clear inputs are not applied in any fixed sequence.
204.

In a mod-12 counter the input clock frequency is 10 kHz. The output frequency is

Answer» Mod-12 counter is divide by 12 counter. Output frequency = = 0.833 kHz.
205.

Inputs A and B of the given figure are applied to a NAND gate. The output is LOW

Answer» NAND gate gives Low output if all inputs are High. For other combinations of inputs, output is High.
206.

AECF1 + 15ACD = __________ .

Answer» Convert to decimal, add and change the result to hexadecimal.
207.

A XOR gate has inputs A and B and output Y. Then the output equation is

Answer» XOR gate recognises odd number of 1's.
208.

Wired AND connection can be used in TTL with totem pole output.

Answer» F, No it cannot be used.
209.

A X 2 __________ .

Answer» A16 = 10, 216 = 2, 10 x 2 = 20 in decimal = 14 in hexadecimal.
210.

For the binary number 11101000, the equivalent hexadecimal number is

Answer» 11 01000 = 128 + 64 + 32 + 8 = 232 in decimal = E 8 in hexadecimal.
211.

Boolean expression for the output of XNOR (Equivalent) logic gate with inputs A and B is

Answer» (A + B) (A + B) = A ⊕ B.
212.

An SR flip flop can be built using NOR gates or NAND gates.

Answer»
213.

In the given figure R = R = 1 kΩ, then V =

Answer» Transistor is off. .
214.

A 14 pin NOT gate 1C has __________ NOT gates.

Answer» 6 Input pins, 6 output pins, 1 supply pin and 1 ground pin. Hence 6 NOT gates.
215.

F's complement of (2BFD) is

Answer»
216.

A Karnaugh map with 4 variables has

Answer» 24= 16.
217.

An 8 bit data is to be entered into a parallel in register. The number of clock pulses required is

Answer» In a parallel in register only one pulse is needed to enter data.
218.

The total number of input words for 4 input OR gate is

Answer» 24 = 16.
219.

In digital circuits Schottky transistors are preferred over normal transistors because of their

Answer» Schottky transistors have low switching time and hence low propagation delay.
220.

A flip flop is a

Answer» It is a memory element used in digital circuits.
221.

A 4 bit parallel type A/D converter uses a 6 volt reference. How many comparators are required and what is the resolution in volts?

Answer» No. of comparators = 2n - 1 = 24 - 1 = 15 .
222.

Quantization error occurs in

Answer» Analog input can have any value but digital value can have only 2N discrete levels (for N bits). Hence quantization error in A/D conversion.
223.

A universal shift register can shift

Answer» Both left to right and right to left operations are possible in universal shift register.
224.

Available multiplexer IC package can have a maximum of 8 inputs.

Answer» 16 : 1 1C multiplexer is also available.
225.

For the logic circuit of the given figure the simplified Boolean equation

Answer» = (A + B) (C + D) (E + F).
226.

A combination circuit is one in which the output depends on

Answer» Combinational circuit does not have memory.
227.

71 = __________ .

Answer» 71 in octal = 7 x 8 + 1= 57 in decimal = 111001 in binary.
228.

1011 x 101 = __________

Answer» 1011 = 11 in decimal and 101 = 5 in decimal, 11 X 5 = 55.
229.

A mod 4 counter will count

Answer» Mod 4 counter has 4 states, 0 to 3.
230.

In the given figure shows a 4 bit serial in parallel out right shift register. The initial contents as shown are 0110. After 3 clock pulses the contents will be

Answer» Output of XOR gate is input to register.
231.

It is desired to display the digit 7 using a seven segment display. The LEDs to be turned on are

Answer»
232.

For a MOD-12 counter, the FF has a = 60 ns The NAND gate has a of 25 n sec. The clock frequency is

Answer» For a proper working, the clock period should be equal to or greater than tpd = Mod 12 - 4FFs = 4 x 60 = 240 nsec. Total tpd = 240 + 25 = 265 nsec. = fc and fc = 3.774 MHz.
233.

100101 is equal to decimal number

Answer» 32 + 4 + 1 = 37 in decimal.
234.

In the figure, the LED

Answer» To emit the light, it is necessary NAND gate output is zero, for NAND O/P zero. Both the I/O must be height. And it is not possible in any case.
235.

A 4 bit ripple counter uses flip flops with propagation delay of 50 ns each. The maximum clock frequency which can be used is

Answer» Time delay = 50 x 4 x 10-9s, .
236.

An AND gate has two inputs A and B and one inhibit input S. Out of total 8 input states, output is 1 in

Answer» Only one input, i.e., A = 1, B = 1 and S = 0 gives output 1.
237.

268 = __________ .

Answer» 10C in hexadecimal = 1 x 162 + 12 = 268 in decimal.
238.

In a JK Master slave flip flop

Answer»
239.

In a 7 segment display the segments are lit. The decimal number displayed will be

Answer»
240.

The minimum number of comparators required to build an 8 bit flash ADC is

Answer» 2n - 1 = 28 - 1 = 255.
241.

For a Mod-64 synchronous counter the number of flip flops and AND gates needed is

Answer» 26 = 64 Hence 6 flip-flops. The number of AND gates is 6 - 2 = 4 see in the given figure
242.

A 4 bit DAC gives an output of 4.5 V for input of 1001. If input is 0110, the output is

Answer»
243.

In 2's complement form, - 2 is

Answer» A = 1110, A = 0001, A + 1 = 0001 + 1 = 0010 = 2 Therefore A = -2.
244.

The Boolean function/implemented in the figure using two I/P multiplexers is

Answer» when B = 1, f1 = ABC B = 0, f2 = ABC f = f1 + f2 = ABC + ABC.
245.

Am equivalent 2's complement representation of the 2's complement number 1101 is

Answer» 2's complement of (1101)2 = 0011
246.

The number of digits in hexadecimal system

Answer» It has 16 digits 0 to 15.
247.

Which of these is the most recent display device?

Answer» VF display can operate at very low voltages, has low power consumption and very long life.
248.

A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH

Answer» NOR gate gives High output when all inputs are Low.
249.

9's complement of 56 is

Answer» 99 - 56 = 43.
250.

4 bit 2's complement representation of a decimal number is 1000. The number is

Answer» (a) and (d) both are option, But there is meaning to represent a positive number in 2's complement form, we take complement representation for negative number only. Therefore most appropriate number is "-8".