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601.

Identify the circuit, (Fig.) in which the electrical components have been properly connected. A. (i)B. (ii)C. (iii)D. (iv)

Answer» Correct Answer - B
(i) Positive terminals of `V and A` should be joined to positive terminal of the cell and their negative terminals should be joined to the negative terminal of the cell. (ii) The voltmeter (V) should be connected in parallel and the ammeter (A) should be connected in series. These conditions are satisfied in (Fig.3) (ii).
602.

What is the maximum resistance which can be made using five resistors each of `(1//5) Omega` ?A. `(1//5) Omega`B. `10 Omega`C. `5 Omega`D. `1 Omega`

Answer» Correct Answer - D
Maximum resistance is obtained in series combination. Thus, `R_s = 5((1)/(5) Omega) = 1 Omega`.
603.

Disha was given two thin wires A and B in science laboratory. The teacher asked her to find out which wire was “fuse wire” and which one was “nichrome wire”. Disha was given batteries of 3 V and 12 V and some connecting wires. The teachers also advised her to switch off fan while performing the activities and take necessary precautions to avoid burns. Disha performed the activities for testing and concluded that wire A is nichrome wire, whereas wire B is fuse wire. On the basis of above information, answer the following questions (i) Describe the activity which Disha performed to conclude that wire A is nichrome wire. (ii) Describe the activity which Disha performed to conclude that wire B is fuse wire.

Answer»

i) • Disha connected wire A with both the batteries. 

• When wire A was connected with 3v battery, Disha found that the wire started heating. 

• When the wire A was connected with 12V battery, she found that the wire is emitting a large amount of heat. 

• Thus, she concluded that wire A is a nichrome wire as nichrome wire has a very large resistance and it produces a large amount of heat. 

ii) • Disha connected wire B with both the batteries. 

• When wire B was connected with 3v battery, did not find anything. 

• When the wire B was connected with 12V battery, she found that the wire has started melting and. 

• Thus, she concluded that wire B is a fuse wire as fuse wire has a very low melting point and it melts as a large amount of current is made to pass through it.

604.

What current will be taken by a 920 W appliance if the supply voltage is 230 V ?

Answer»

P=920W, V=230V, I=? 

We know that 

P = V x I, 

920 = 230 x I

I = 920/230 = 4amp

605.

Why is silver wire not used for electricity transmission?

Answer»

Though silver is a very good conductor of electricity but still that is not used in electric wiring primarily due to its cost. It's very expensive compared to the widely used wiring material copper. Another reason for not using silver is that , it oxidizes easily and tarnishes when it comes in contact with air.

606.

An electric iron has a rating of `750 W, 220 V`. Calculate : (i) current passing through it and (ii) its resistance, when in use.

Answer» Here, `P = 750 W, V = 220 V`
(i) As `P = VI, I = (P)/(V) = (750 W)/(220 V) = 3.4 A`
(ii) `R = (V)/(I) = (220 V)/(3.4 A) = 64.7 Omega`.
607.

What is meant by saying that the potential difference between two points is 1 volt ?

Answer»

Solution :

The potential difference between two points is 1 volt means 1 joule of work is done in moving 1 coulomb of electric charge from one point to the other.

608.

Three 2 V cells are connected in series and used as a battery in a circuit.(a) What is the p.d. at the terminals of the battery ?(b) How many joules of electrical energy does 1 C gain on passing through (i) one cell (ii) all three cells ?

Answer»

Solution : 

(a) If three cells of 2 volt each are connected in series to make a battery, then the total potential difference between terminals of the battery will be 6V. 

(b) (i) Given: p.d. = 2V, Charge moved = 1C 

We know that 

Work done = p.d. x charge moved = 2 x 1 

Work done = 2 joules 

(ii) Given: p.d. = 6V, 

Charge moved = 1C 

Work done = p.d. x charge moved = 6 x1 

Work done = 6 joule. 

609.

State whether a voltmeter has a high resistance or a low resistance. Give reason for your answer.

Answer»

Solution : 

Voltmeter has a high resistance so that it takes a negligible current from the circuit.

610.

When a high resistance voltmeter is connected directly across a resister its reading is 2 V. An electric cell is sending the current of 0.4A, (measured by an ammeter) in the electric circuit in which a rheostat is also connected to vary the current.Find the resistance of the resister.

Answer»

Since the voltmeter reading shows 2V. Thus V = 2.

Also, Current send by electric cell = 0.4A 

Thus I = 0.4A 

By Ohm’s law V = IR 

⇒ 2 = 0.4 × R 

⇒ R = \(\frac{2}{0.4}=\frac{20}{4}\) = 5Ω

The resistance of the resistor is 5Ω.

611.

Name the electrical property of a material whose symbol is “omega

Answer»

Solution : 

The electrical property of a material is known as Resistance

612.

Gasoline (explosive) transport trucks generally carry long chains of metal hanging down and touching the ground. Why?

Answer» What happens to the charge on a body when it is connected to the ground?
What is the consequence if a gasoline transport truck is charged by friction?
613.

Give reasons for the following : Fuse wire is placed in series with the device.

Answer» It melts and stops the flow of any unduly high electric current and breaks the circuit.
614.

Calculate the equivalent resistance between the points `A and B` in the combination of resistors shown in (Fig. 3.56). .

Answer» Since `CD(= 20 Omega), DE (=10 Omega) and EF(= 20 Omega)` are in parallel combination, their effective resistance `(R_P) is 5 Omega`. Now `R_P and FB (=6 Omega)` are in series and as such resistance between `A and B = 5 Omega + 6 Omega = 11 Omega`.
615.

A simple circuit consists of a resistor, a battery, and connecting wires. How must an ammeter be connected in a circuit to correctly read the current?

Answer»

The ammeter must be connected in the series to read the current correctly. Ammeter has very low resistance If it is connected in parallel across any load then all current in circuit will choose lower resistive path (i.e ammeter) which will cause the circuit to be damaged. Hence it is used in series. Also the current in the series is always same

616.

A wire of given material having length l and area of cross-section A, has a resistance of 2 Ω. Find the resistance of another wire of same material having length 2l and are of cross-section A/2.

Answer»

Given 

Resistance (R) = 2Ω 

Area of cross-section = A 

Length = l 

We know that R = \(ρ\frac{1}A\)

⇒ 2 = \(ρ\frac{1}A\) 

New Area = A/2 

New Length = 2l 

New Resistance = R’

⇒ R' = \(ρ\frac{2l}{\frac{A}{2}}\)

⇒ R' = \(ρ\frac{4l}{A}\)

 ⇒ R' = \(4ρ\frac{l}{A}\)

⇒ R' = 4 x 2 = 8, from (1)

Hence the new resistance will be four times the previous resistance i.e. 8Ω.

617.

Write short note on Electrical Energy.

Answer»

Because of the existence of resistance to the flow of current work has to be done in order to maintain the flow of current.

Since the potential difference V is the work done to carry unit positive charge from infinity to a point, the work done to carry a charge q is given by:

W= qV

But I = q/t

So W = ItV

Since V = I R

W = I2Rt = V2t/R

This work done is stored as energy.

SI unit of electrical energy is Joule.

618.

Fuse of 3A, 5A and 10A are available. Calculate and select the fuse for operating electric iron of 1 kW power at 220 V line.

Answer»

Power rating of electric iron = 1 kW = 1000 W

V=220 V

P=VI

I=P/V=1000/220

=4.55 A

Hence, a fuse of rating 5A can be used because it can bear the current.

619.

Write the full form of M.C.B.

Answer»

Miniature Circuit Breaker.

620.

Which fuse wire is thick : 5 A or 15 A ?

Answer»

∴ R α l/a

More the area, lesser is the resistance and more is the current flowing.

∴ 15 A fuse wire is thick

621.

How does a fuse protect the electric wiring (or an appliance) from being damaged ?

Answer»

Due to voltage fluctuations or insulation on the wire of cable gets worn and tom (breaks), the live wire comes in contact with the neutral wire and results in SHORT CIRCUIT. To prevent this damage, a fuse is used in the LIVE WIRE. The fuse wire gets heated up to the extent that it melts, a gap is produced in the live wire and the circuit becomes incomplete, no current flows and the appliance is saved.

622.

How does fuse wire protect electrical appliances ?

Answer»

The fuse breaks the circuit if a fault in an appliance causes too much current flow. This protects the wiring and the appliance if something goes wrong. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great, the wire heats up until it melts and breaks the circuit.

623.

How does use of a fuse-wire protect electrical appliances ?

Answer» A fuse is a circuit connection that will be destroyed by excessive current flow, creating an open circuit, to protect electrical appliances from receiving to high current. It is designed to be the weakest link in the circuit, which will fail before the other components are damaged.
The simplest fuses contain thin wire strips that melts when heated by excessive current flow. A fuse wire consists of low melting point and high resistivity and it is always connected in live wire.
624.

Can we use copper wire as a fuse wire ? Give reason.

Answer»

Copper wire cannot be used as a fuse wire since the melting point of Cu is higher and resistance is very low and current can flow through it without melting it and without breaking the circuit.

625.

Name the material of a fuse wire.

Answer»

MATERIAL used is an ALLOY of LEAD (50%) and TIN 50% having low M.P. of 200°C

626.

State one property of the material of a fuse wire.

Answer»

Two CHARACTERISTICS OF FUSE WIRE are:

(i) Has LOW MELTING POINT.

(ii) Has HIGH RESISTANCE.

627.

What is an electric fuse ? State its purpose in the household electrical circuit.

Answer»

FUSE: “Is a safety device which is used to limit the current in an electric circuit.

PURPOSE OF FUSE IN HOUSEHOLD CIRCUIT: It safeguards the circuit and the appliances connected in the circuit from being damaged if the current in the circuit exceeds the specified value due to voltage fluctuation or short-circuiting.

628.

Write true or false for the following statements: A conducting wire offers resistance to the flow of electrons because electrons repel each other in the wire.

Answer»

False 

A conducting wire offers resistance to the flow of electrons due to the random collision between the electrons and the stationery atoms.

629.

Define the term series.

Answer»

Series : If the second terminal of the first device is connected to the first end of the second device such type of connection is called series connection.

630.

What is fluorescent tube ?

Answer»

Fluorescent tube : Fluorescent tube light is a light source, which is commonly known as tube light.

631.

Write the required materials to do an activity to know about heating effect of electric current.

Answer»

1. Electric cell, 

2. Iron nails – 2, 

3. Wooden board, 

4. Connecting wires, 

5. 10 cm of Nichrome wire etc.

632.

What is parallel  ?

Answer»

Parallel : If all the first terminals of all the devices are connected to one point and all the second terminals are connected to another point such type of connection is called parallel connection.

633.

What is heating effect ?

Answer»

Heating effect : The production of heat due to the flow of electricity through a wire is called heating effect of electricity.

634.

What is electric shock.

Answer»

Electric shock : An electric shock occurs when a person comes into contact with an electrical source and electricity flows through his body.

635.

What is magnetic effect ?

Answer»

Magnetic effect : The production of magnetic force due to the flow of electricity through a wire is called magnetic effect of electricity

636.

What is Fuse ?

Answer»

Fuse : The safety device which is used in electrical appliances to protect from damages when excess of electricity flows through them is called a electric fuse.

637.

What is CFL ?

Answer»

CFL : Compact Fluorescent Lamp is a light source.

638.

Define the term MCB.

Answer»

MCB : Miniature Circuit Breaker is Na type of fuse which automatically turns off when electricity in a circuit exceeds the safe limit.

639.

Which of the following is the symbol of a battery ?A. B. C. D.

Answer» Correct Answer - B
640.

The bluish white streak of light seen during lightning is due toA. a change of colour of the clouds, as charge passes between the clouds.B. burning of clouds producing an intense white light.C. air becoming white hot as charge passes between the clouds.D. None of the above

Answer» Correct Answer - C
The bluish white streak of light seen during lighting is due to air becoming white hot as charge passes between the clouds.
641.

Which of the following is the symbol of a battery ?A. B. C. D.

Answer» Correct Answer - B
642.

Which among the following has carbon as the positive electrode?A. LechancheB. Bichromate cellC. Dry cellD. All of the above

Answer» Correct Answer - D
643.

During lightning, thunder is produced due toA. a sudden expansion of air due to intense heat.B. a collision among clouds.C. a sudden expansion of clouds due to intense heat.D. None of the above

Answer» Correct Answer - A
A sudden expansion expansion of air due to intense heat produced during lightning causes thunder.
644.

When charges are moving from one end to the other end of a conductor, we say there is `"_______"` in the conductor.

Answer» Correct Answer - electric current
645.

It which of the following cells, carbon is not used as positive electrode ?A. Leclanche cellB. Lead-acid storage battery.C. Dry cellD. None of the above

Answer» Correct Answer - B
Carbon is not used as positive electrode in lead acid battery.
646.

A current of 4A flows through a 12V car headlight bulb for 10 minutes. How much energy transfer occurs during this time?

Answer» Energy = Power `xx` Time
or `E = P xx t` .......(1)
First of all we should calculate power P by using the current of 4A and voltage of 12 V.
Now, `P = V xx I`
So, `P = 12 xx 4`
or, Power, `P = 48` watts
`= (48)/(1000)` kilowatts
Thus, Power, `P = 0.048 kW`
And, Time, `t = 10` minutes
`= (10)/(60)` hours
`= (1)/(6)` hours
Now, putting `P = 0.048 kW` and, `t = (1)/(6)` hours in equation (1), we get:
`E = 0.048 xx (1)/(6)`
`= 0.008 kWh`
Thus, the energy transferred is 0.008 kilowatt-hour.
647.

An electric current of 2A flows through a circuit consisting of a bulb. Find the number of electrons that would pass through the bulb in 8 minutes.

Answer» We are given,
`I=2A` and `t=8` minutes `=8xx60 s = 480 s `
`:. Q = It`
`=(2A)xx(480 s)=960 C`
1 C charge corresponds to `6.25xx10^(18)` electrons
`:. 960 C` charge corresponding to `960 xx 6.25 xx 10^(18)` electrons `=6000xx10^(18)` electrons
`=6xx10^(21)` electrons.
648.

Two bulbs each of 60 W and 80 W power are used for (1/4)th a day and (1/2) a day, respectively. Write the following steps in a sequential order to find the total number of units consumed by them when they are used for 30 days. (a) Now, multiply E with 30, to get the energy consumed by them in 30 days. (b) Find the electric energy consumed by each bulb in a day using `E_(1)=P_(1)t_(1)` and `E_(2)=P_(2)t_(2)`. (c) Note down the powers of the bulbs and the time for which they are used per day as `P_(1), P_(2)` and `t_(1)`, `t_(2)` , respectively. (d) Convert the time into hours. (e) Find the total energy (E) consumed by them in one day, i.e., `E=E_(1)+E_(2)`. (f) Write the energy in terms of units, i.e., commercial unit of electric energy.A. c d b e a fB. c d e a b fC. c d a d e fD. c e a b d f

Answer» Correct Answer - A
(i) Note down the powers of the bulbs and the time for which they are used per day as `P_(1), P_(2)` and `t_(1),t_(2)` respectively.
(ii) Convert the time into hours.
(iii) Find the electric energy consumed by each bulb in a day using `E_(1)=P_(1)t_(1)` and `E_(2)=P_(2)t_(2)`
(iv) Find the total energy (E) consumed by them in one day, i.e., `E=E_(1)+E_(2)`.
(v) Now, multiply E with 30, to get the energy consumed by them in 30 days.
(vi) Write the energy in terms of units i.e. commercial unit of electric energy.
649.

An electric current of 6 A flows through a circuit for 10 minutes. Write the following steps in sequential order to find the electrons that would pass through the circuit in 10 minutes. Note the given data about current (i) and time (t). The number of electrons (n) flowing through the circuit can be found using, Q = ne (2) (c) Find the charge (Q) that flows through the circuit using , Q = it (1) (d) Equate (1) and (2), to find n.A. a d b cB. a b c dC. b c a dD. a c b d

Answer» Correct Answer - D
(i) Note the given data about current (i) and time (t).
(ii) Find the charge (Q) that flows through the circuit using,
Q = it (1)
(iii) The number of electrons (n) flowing through the circuit can be found using,
Q = ne (2)
(iv) Equate (1) and (2), to find n.
650.

`"_______"` is a used to protect builiding from lightning.

Answer» Correct Answer - lightning conductor