InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
V-I graph for the metallic wires X and Y at constant temperature are as shown in figure: Assuming that the two wires have same length and same diameter, explain as to which of the two wires has higher resistivity and why? |
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Answer» The slope I/V of the graph represents 1/R. Since the graph marked Y has a lesser slope, it represents higher resistance. |
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| 852. |
Name the material which is used for making the heating element of an electric iron. |
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Answer» Solution : The material which is used for making the heating element is Nichrome. |
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| 853. |
A hot plate of an electric oven connected to a `220 V` lines has two resistance coils `A and B`, each of `24 Omega` resistance, which may be used separately, in series or in parallel. What are the currents in the three cases ? |
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Answer» Here, potential difference, `V = 220 V` resistance of each coil, `r = 24 Omega` (i) When each of the coils `A or B` is connected separately, current through each coil, i.e., `I = (V)/( r) = (220 V)/(24 Omega) = 9.2 A` (ii) When coils `A and B` are connected in series, equivalent resistance in the circuit, `R_s = r + r = 2r = 48 Omega` Current through the series combination, i.e., `I_s = (V)/(R_s)=(220 V)/(48 Omega) = 4.6 A` (iii) When the coils `A and B` are connected in parallel, equivalent resistance in the circuit, `R_p = ( r)/(2) = (24 Omega)/(2) = 12 Omega` Current through the parallel combination, i.e., `I_p = (V)/(R_p) = (220 V)/(12 Omega) = 18.3 A`. |
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| 854. |
How is fuse wire made of? |
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Answer» It consists of a piece of wire made of a metal or an alloy of appropriate melting point, for example aluminium, copper, iron, lead etc. |
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| 855. |
What material is used for making wire to prepare heating coils? Give a reason. |
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Answer» Nichrome is used for making wire to prepare heating coils. The reason is that its melting point is high and its resistivity is also high. |
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| 856. |
State the effect of rise in temperature on the resistance of semi-conductors. |
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Answer» In the case of semi-conductors like carbon, silicon, germanium, etc., the resistance decreases with increase in temperature. |
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| 857. |
What is the S.I. Unit of resistivity? |
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Answer» ΩM is the S.I. Unit of resistivity |
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| 858. |
Why are thick copper wires used as connecting wires? |
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Answer» The resistance of connecting wires should be almost negligible. For this thick wires are used. since a thicker wire has a small resistance and the wires are made of copper because the resistivity of copper is low. |
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| 859. |
Give reason for the following :Why are copper and aluminium wires used as connecting wires ? |
| Answer» These are good conductors of electricity/low resistance, Iow resistivity. | |
| 860. |
Why are copper and aluminium wires usually employed for electricity transmission? |
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Answer» Copper and Aluminium are good conductors of electricity and they have less resistance. Hence they are used in electricity transmission. |
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| 861. |
Wastage of electricity can be reduced by using A) CFLS B) Motors C) Heaters D) Bulbs |
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Answer» Correct option is A) CFLS |
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| 862. |
An electric heater draws a current of `5 A` when connected to `220 V` mains. Calculate the resistance of its filament. |
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Answer» Correct Answer - `44 Omega` `R = V//I = 220 V//5 A = 44 Omega` |
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| 863. |
An electric iron draws a current of 0.5 A when the voltage is 220 volts. Calculate the amount of electric charge flowing through it in one hour. |
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Answer» I = \(\frac{Q}{t}\) Charge Q = ? Charge I = 0.5 A Time = 1 hour = 60 × 60 s Q = It = 0.5 × 3600 = 1800 C The amount of electric charge flowing = 1800 C |
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| 864. |
The atoms of copper contain electrons and the atoms of rubber also contain electrons. Then why does copper conduct electricity but rubber does not conduct electricity ? |
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Answer» Solution : Copper has free electrons that are loosely held by the nuclei of the atoms. These free electrons result in conduction of electricity. The electrons present in rubber are strongly held by the nuclei of its atoms. So, rubber does not have free electrons to conduct electricity. |
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| 865. |
What is the value of one kilo watt hour ? |
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Answer» One kilowatt hour = 1000 W hr 1 kWh = 3.6 × 106 J |
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| 866. |
The unit of resistance is _____. (a) volt (b) volt ampere-1 (c) ampere (d) Joule. |
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Answer» (b) Volt ampere -1 |
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| 867. |
1 kilo watt = A) 1000 watts B) 100 watts C) 1/1000 watts D) 1/100 watts |
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Answer» The correct option is A) 1000 watts. |
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| 868. |
An electric bulb is connected to a 220 V power supply line. If the bulb draws a current of 0.5 A, calculate the power of the bulb. |
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Answer» V = 220V, I = 0.5 amp, P = ? We know that P = VI = 220 X 0.5 P = 110 watt. |
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| 869. |
An electric bulb is connected to a 220 V power supply line. If the bulb draws a current of 0.5 A, calculate the power of the bulb. |
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Answer» V=220V, I=0.5amp, P=? We know that P=VI=220X0.5 P=110 watt. |
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| 870. |
The work done in moving a charge of 2 C across two points in a circuit is 2 J. What is the potential difference between the points?(a) 1 V (b) 10 V (c) 100 V (d) 0. |
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Answer» Correct answer is (a) 1 V |
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| 871. |
Assertion (A) : All the bulbs connected in parallel glow brightly. Reason (R) : All the bulbs are connected directly to a battery and derive the required electrcial energy.A. Both A and R are true and R is the correct explanation of A.B. Both A and R are true and R is not the correct explanation of A.C. A is true but R is false.D. Both A and R are false. |
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Answer» Correct Answer - A All the bulb connectedin parallel glow brightly because all the bulbs are connected directly to a bat-tery, and derive the required electrical energy. |
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| 872. |
The S.I. unit of electric current is _____. (a) Volt (b) Power (c) Ampere (d) newton. |
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Answer» Correct answer is (c) Ampere |
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| 873. |
A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason. |
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Answer» (1) Let R be the resistance of the electric lamp. In series total resistance = 5 + R I = v/r 1 = 10/5 + R R = 5 ohm 2) V across Lamp + conductor = 10 V V across Lamp = I × R = 1 x 5 = 5 Volt |
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| 874. |
The unit of electric current is: (a) ampere (b) volt (c) watt (d) kilo-watt |
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Answer» Correct answer is (a) ampere |
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| 875. |
An electric bulb of resistance 200Ω draws a current of 1 Ampere. Calculate the power of the bulb the potential difference at its ends and the energy in kWh consumed burning it for 5h. |
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Answer» Power of the bulb, P = l2R = (1)2 x 200 ⇒ P = 200 W Energy consumed by bulb in 5h in burning = Power x Time = 200 x 5 = 1000 Wh = 1 kWh |
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| 876. |
What actually travels through the wires when you switch on a light ? |
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Answer» Solution : Travels through the wires when you switch on a light is Electrons. |
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| 877. |
Which particles constitute the electric current in a metallic conductor ? |
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Answer» Solution : The particles constitute the electric current in a metallic conductor is Electrons |
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| 878. |
(a) What is an electric current ? What makes an electric current flow in a wire ? (b) Define the unit of electric current (or Define ampere). |
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Answer» Solution : (a) An electric currrent is a flow of electric charges (electrons) through a conductor. Potential difference between the ends of the wire makes electric current to flow in the wire. (b) When 1 coulomb of charge flows through any cross-section of a conductor in 1 second, the electric current flowing through it is said to be 1 ampere. |
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| 879. |
Explain the following : (a) Why is tungsten used almost exclusively for filament of incandescent lamp ? (b) Why are the conductors of electric heating devices, such as toaster and electric irons, made of an alloy rather than a pure metal ? ( c) Why is the series arrangement not used for domestic circuits ? (d) How does the resistance of a wire vary with its cross-sectional area ? (e ) Why are copper and aluminium wires usually employed for electricity transmission. |
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Answer» (a) The melting point and of Tungsten is an alloy which has very high melting point and very high resistivity so does not burn easily at a high temperature. (b) The conductors of electric heating divices such as bread toasters and electric irons are mode of alloy because resistivity of an alloy is more than that the metals which produces large amount of heat. ( c) In series circuits voltage is divided. Each component of a series receives a small voltage so the amount of currnet decreses and the device becomes hot and does not work properly. Hence, series arrangement is not used in domestic circuits. (d) Resistance (R) of a wire is inversely proportional to its area of cross-section (A), i.e. when area of cross section increases the resistance decreases or vice versa. (e) Copper and aluminium are good conductors of electricity also they have low resistivity. So they are usually used for electricity transmission. |
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| 880. |
An electric motor takes 5 A from a 220 V line. Determine the power of the motor and the energy consumed in 2 h. |
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Answer» P = VI |
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| 881. |
An electric motor takes `5 A` from a `220 V` line. Determine the power and energy consumed in `2 h`. |
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Answer» Here, `I = 5A, V = 220 V, t = 2 h = (2 xx 60 xx 60) s = 7200 s` Power, `P = VI = (220 V)(5 A) = 1100 W` Energy consumed, `W = VI t = (220 V)(5A)(7200 s) = 7920000 J`. |
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| 882. |
Electrical resistivity of a given metallic wire depends upon (a) its length (b) its thickness (c) its shape (d) nature of the material |
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Answer» The answer is (d) nature of the material |
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| 883. |
State difference between the wire used in the element of an electric heater and in a fuse wire. |
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| 884. |
ElectromagnetA. Electric motorB. Electric generatorC. Electric generatorD. Telegraph |
| Answer» Correct Answer - C | |
| 885. |
Choose the correct statement : - (A) In case of an electric cell, chemical energy is converted into electrical energy. (B) combination of electric cells is called battery.A. only A is trueB. only B is trueC. Both A and B are trueD. Both A and B are false |
| Answer» Correct Answer - C | |
| 886. |
Which of the following electrical appliances works on the principle of the magnetic effect of electric current ?A. electric heaterB. electric motorC. electric bellD. Both (b) and (c ) |
| Answer» Correct Answer - D | |
| 887. |
Which of the following electrical appliances work on the principal of the heating efect of electric current ?A. Electric ironB. Electric heaterC. Electric bulbD. All the above. |
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Answer» Correct Answer - D Electric iron, heater and electric bulb all work on the principle of the heating effect of elect-tric current. |
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| 888. |
Is drift speed of electrons in a conductor carrying current the same as the speed of current ? |
| Answer» No, drift speed of electrons is around `10^-4 m//s`, whereas speed of current is nearly equal to the speed of light in vacuum `(3 xx 10^8 m//s)`. | |
| 889. |
What sets the electrons into motion in an electric circuit ? |
| Answer» To set the electrons into motion in an electric circuit, a cell or a battery is used which provides pd across light terminals. | |
| 890. |
Two resistors of resistance 2Ω and 4Ω, when connected to a battery, will have (a) the same current flowing through them when connected in parallel (b) the same current flowing through them when connected in series (c) the same potential difference across them when connected in series (d) the different potential difference across them when connected in parallel |
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Answer» The answer is (b) same current flowing through them when connected in series In series combination current does not get divided into branches because resistor receives a common current. |
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| 891. |
Which of the following units could be used to measure electric charge?A. ampereB. jouleC. voltD. coulomb |
| Answer» Correct Answer - D | |
| 892. |
Which unit could be used to measure current?A. WattB. CoulombC. VolyD. Ampere |
| Answer» Correct Answer - D | |
| 893. |
If the current through a flood lamp is 5A, what charge passes in 10 seconds?A. `0.5C`B. `2C`C. `5C`D. `50C` |
| Answer» Correct Answer - D | |
| 894. |
When an electric lamp is connected to 12V battery, it draws a current of 0.5A. The power of the lamp is:A. 0.5WB. 6WC. 12WD. 24W |
| Answer» Correct Answer - B | |
| 895. |
Does a bulb glow when switch is in off position? Why? |
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Answer» When the switch is in off position, bulb does not glow. Because the circuit is opened. |
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| 896. |
If two resistors of `25 Omega` and `15 Omega` are joined together in series and then placed in parallel with a `40 Omega` resistor, the effective resistance of the combination is:A. `0.1 Omega`B. `10Omega`C. `20Omega`D. `40Omega` |
| Answer» Correct Answer - C | |
| 897. |
What are the material required to make a cell with lemons? |
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Answer» Zinc plate, copper plate, a small bulb, or LED, connecting wires, crocodile dips, and lemons. |
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| 898. |
A current of `0.5 A` is drawn by a filament of an electric bulb for `10` minutes. Find the amount of electric charge that flows through the electric circuit. |
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Answer» We are given, I=0.5 A: t=10 min=600 s. From Eq. (12.1), We have Q = it `= 0.5 A xx 600 s` = 300 C |
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| 899. |
Bulb is rated at 200 V, 100 W. Calculate its resistance. Five such bulbs are lighted for 4 hours daily. Calculate the units of electrical energy consumed per day. What would be the cost of using these bulbs per day at the rate of Rs. 4.00 per unit? |
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Answer» We know that for an electric appliance P = \(\frac{V^2}{R}\) Resistance will be given as R = \(\frac{V^2}{P}\) Now, here P = 100 W V = 200 volts So, R = \(\frac{200^2}{100}\) R = \(\frac{40000}{100}\) 400Ω Thus, resistance of the bulb is R = 400 Ω Now, electric energy consumed will be E = power of each unit × time. ⇒ E = p × t. Here P = 100 W t = 4 hours So, E = 100 x 4 = 400 Watt per hour Dividing by 1000 to convert into Kilo Watt per hour E = \(\frac{400}{1000}=0.4\) kWh Electrical energy consumed is 0.4 kWh The total cost of electricity = total unit of energy consumed x cost per unit = Cost = 0.4kWh x 4 Rs/kWh = Rs1.6 Thus, total cost (daily) = Rs. 1.6 |
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| 900. |
Two copper wires A and B of length 30 m and 10 m have radii `2 cm and 1 cm` respectively. Compare the resistances of the two wires. Which will have less resistance ? |
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Answer» Let the two resistances be labelled as `R_1 and R_2` Here, `l_1 = 30 m, A_1 = pi r_1^2 = pi (2 xx 10^-3) m^2` As `R = (rho l)/(A), R_1 = (rho l_1)/(A_1)` and `R_2 = (rho l_2)/(A_2)` Thus, `(R_1)/(R_2) = (rho l_1//A_1)/(rho l_2//A_2) = (l_1 A_2)/(l_2 A_1) = (30 xx pi(1 xx 10^-3)^2)/(10 xx pi(2 xx 10^-3)^2) = (3)/(4)` Clearly, `R_1 lt R_2`. |
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