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51.

____________ is used to prevent deep fade for rapidly varying channel.(a) Modulation(b) Demodulation(c) Macroscopic diversity technique(d) Microscopic diversity techniqueThe question was posed to me by my college professor while I was bunking the class.The query is from Diversity Techniques in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» RIGHT choice is (d) Microscopic DIVERSITY technique

Explanation: In order to PREVENT deep fades from occurring, microscopic diversity techniques can exploit the rapidly changing signal. By selecting the best signal at all times, a receiver can MITIGATE SMALL scale fading effects.
52.

MLSE decodes each received signal by itself.(a) True(b) FalseI had been asked this question in my homework.I need to ask this question from Equalization Techniques topic in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (b) False

The explanation: Rather than decoding each received SIGNAL by itself, MLSE tests all possible data sequences by USING a channel IMPULSE RESPONSE simulator within the algorithm. It chooses the data sequence with maximum PROBABILITY as the output.

53.

Which of the following linear codes achieve largest possible minimum distance?(a) Hamming code(b) Hadamard code(c) Golay code(d) Reed Solomon codesThis question was posed to me by my school principal while I was bunking the class.This interesting question is from Block Codes and Finite Fields in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Correct choice is (d) REED Solomon codes

The best explanation: RS codes achieve the largest possible minimum distance, dmin of any linear code. They are non-binary codes which are CAPABLE of correcting ERRORS that APPEARS in bursts.

54.

For (n,k) block codes, rate of the code is defined as __________(a) n^2/k(b) k^2/n(c) n/k(d) k/nThis question was posed to me in final exam.This key question is from Block Codes and Finite Fields topic in division Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» CORRECT choice is (C) n/k

To elaborate: The BLOCK CODE is referred to as an (n,k) code, and the rate of the code is DEFINED as R=n/k. It is equal to the rate of information divided by the raw channel rate.
55.

Choice of equalizer structure and its algorithm is not dependent on ________(a) Cost of computing platform(b) Power budget(c) Radio propagation characteristics(d) Statistical distribution of transmitted powerThe question was posed to me during an interview.Origin of the question is Algorithms for Adaptive Equalization topic in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right option is (d) STATISTICAL distribution of transmitted power

The explanation is: The cost of the computing platform, the power budget and the radio propagation characteristics dominate the choice of an equalizer STRUCTURE and its ALGORITHM. Battery drain at the subscriber unit is ALSO a paramount consideration.

56.

For N symbol inputs, LMS algorithm requires ______ operations per iterations.(a) 2N(b) N+1(c) 2N+1(d) N^2The question was posed to me in a national level competition.This key question is from Algorithms for Adaptive Equalization topic in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» RIGHT CHOICE is (c) 2N+1

Easy explanation: The LMS algorithm is the simplest algorithm. For N symbol inputs, it requires only 2N+1 operations PER iteration.
57.

Rate of convergence is defined by __________ of algorithm.(a) Time span(b) Number of iterations(c) Accuracy(d) ComplexityThe question was asked in exam.The origin of the question is Algorithms for Adaptive Equalization in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right ANSWER is (b) Number of iterations

Explanation: Rate of convergence is required as number of iterations required for the algorithm to CONVERGE close ENOUGH to the OPTIMUM solution. It enables the algorithm to track statistical VARIATIONS when operating in non stationary environment.

58.

Which of the following is not an advantage of lattice equalizer?(a) Simple structure(b) Numerical stability(c) Faster convergence(d) Dynamic assignmentI got this question in class test.The question is from Equalization Techniques in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct option is (a) Simple structure

The explanation is: The structure of LATTICE equalizer is more complicated than a linear transversal equalizer. But, NUMERICAL stability and FASTER convergence are TWO advantage of laatic equalizer. Also, its unique structure allows dynamic assignment of the most EFFECTIVE length of lattice equalizer.

59.

Time for convergence of an equalizer is not a function of _______(a) Equalizer algorithm(b) Equalizer structure(c) Time rate of change of multipath radio channel(d) Transmitter characteristicsI have been asked this question during a job interview.This intriguing question originated from Fundamentals of Equalization topic in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct option is (d) Transmitter characteristics

The explanation is: The timespan over which an equalizer CONVERGES is a function of the equalizer ALGORITHM, the equalizer STRUCTURE and the time RATE of change of the multipath radio channel. Equalizers require proper retraining in order to maintain EFFECTIVE ISI cancellation.

60.

Which of the following indicates the number of input bits that the current output is dependent upon?(a) Constraint length(b) Code length(c) Search window(d) Information rateThe question was asked in examination.Origin of the question is Convolutional Codes topic in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct choice is (a) CONSTRAINT length

Best EXPLANATION: Constraint length determines the number of input data BITS that the current output is dependent UPON. The constraint length determines how powerful and complex the code is.

61.

Which of the following is not a property of block code?(a) Linearity(b) Systematic(c) Cyclic(d) Non linearityI got this question during an interview.I need to ask this question from Block Codes and Finite Fields in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct answer is (d) Non linearity

The best I can explain: Block CODES are linear, systematic and cyclic in nature. Encoding and decoding techniques make USE of mathematical constructs KNOWN as FINITE fields.

62.

In systematic codes, parity bits are appended at the __________(a) Beginning(b) End(c) End(d) Odd placesThe question was posed to me in examination.I want to ask this question from Block Codes and Finite Fields topic in division Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct answer is (B) END

The explanation is: A systematic code is one in which the parity bits are appended to the end of the information bits. For an (n,k) code, the FIRST k bits are identical to the information bits, and the REMAINING (n-k) bits of each code word are linear COMBINATIONS of k information bits.

63.

Which of the following is not a category of space diversity technique?(a) Selection diversity(b) Time diversity(c) Feedback diversity(d) Equal gain diversityThis question was addressed to me in an online interview.Origin of the question is Diversity Techniques topic in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (b) Time diversity

The best I can explain: SPACE diversity RECEPTION METHODS can be classified into four categories. They are selection diversity, feedback diversity, maximal ratio COMBINING and equal gain diversity.

64.

LMS equalizer minimizes __________(a) Computational complexity(b) Cost(c) Mean square error(d) Power density of output signalI had been asked this question by my college professor while I was bunking the class.Origin of the question is Algorithms for Adaptive Equalization in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (C) Mean square error

The best I can EXPLAIN: LMS equalizer is a robust equalizer. It is used to minimize mean square error (MSE) between the desired equalizer output and the actual equalizer output.

65.

Coherence time is dependent on the choice of the algorithm and corresponding rate of convergence.(a) True(b) FalseI got this question in quiz.My enquiry is from Algorithms for Adaptive Equalization topic in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The CORRECT answer is (a) True

Explanation: The choice of ALGORITHM and its corresponding rate of convergence depends on the channel data rate and coherence time. The speed of the mobile unit DETERMINES the channel FADING rate and the Doppler spread, which is directly related to coherence time of the channel.

66.

For a distorted channel, LTE performance is superior to DFE.(a) True(b) FalseThe question was posed to me in an interview.Query is from Equalization Techniques in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Correct answer is (b) False

Explanation: LTE is well behaved when the channel SPECTRUM is comparatively FLAT. But if the channel is severely DISTORTED or exhibits null in the spectrum, the performance of LTE deteriorates and MSE of DFE is better than LTE.

67.

Non-linear equalizers are used in applications where channel distortion is not severe.(a) True(b) FalseThis question was addressed to me by my college director while I was bunking the class.The question is from Equalization Techniques topic in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right OPTION is (B) False

The explanation is: Non-LINEAR EQUALIZERS are used in applications where the channel distortion is too severe for a linear equalizer to handle. They are most COMMONLY used in practical wireless communication.

68.

An equalizer is said to be converged when it is properly _______(a) Trained(b) Tracked(c) Installed(d) UsedI got this question in an online quiz.I'd like to ask this question from Fundamentals of Equalization in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Correct CHOICE is (a) Trained

Explanation: When an EQUALIZER has been properly trained, it is said to have converged. Equalizers are commonly used in digital communication systems where user DATA is segmented into SHORT time blocks or time slots.

69.

Equalizer is ________ of the channel.(a) Opposite(b) Same characteristics(c) Inverse filter(d) Add onI had been asked this question during a job interview.I want to ask this question from Fundamentals of Equalization in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct option is (C) Inverse filter

Easy explanation: An equalizer is ACTUALLY an inverse filter of the channel. The goal of EQUALIZATION is to satisfy that the combination of the transmitter, channel and receiver be an all pass channel.

70.

Viterbi algorithm performs ____________ decoding of convolutional codes.(a) Maximum likelihood(b) Maximum a posteriori(c) Minimum square(d) Minimum mean squareThe question was asked in an online quiz.The doubt is from Convolutional Codes topic in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct ANSWER is (a) MAXIMUM likelihood

The best explanation: VITERBI ALGORITHM performs maximum likelihood decoding of convolutional codes. The algorithm was first DEVELOPED by A.J. Viterbi. It is one of the most important algorithm used for decoding convolutional codes.

71.

Which of the following code is a class of non-binary BCH?(a) Hamming code(b) Hadamard code(c) Golay code(d) Reed Solomon codesI got this question during an online exam.This interesting question is from Block Codes and Finite Fields in division Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The CORRECT answer is (d) REED Solomon codes

The best I can explain: The most important and most COMMON CLASS of non binary is the family of codes known as Reed Solomon codes. BCH codes are among the most popular BLOCK codes that exist for a wide range of rates, achieve significant coding gains.

72.

A RAKE receiver uses __________ to separately detect the M strongest signals.(a) Single correlator(b) Multiple correlator(c) Single IF receiver(d) Multiple IF receiversThe question was asked in an internship interview.I'd like to ask this question from Rake Receiver topic in division Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» CORRECT answer is (b) Multiple correlator

To explain I WOULD say: A RAKE receiver uses multiple correlators to separately detect the M strongest multipath components. Demodulation and bit decisions are then BASED on the weighted ouputs of the M correlators.
73.

Large scale fading can be mitigated with the help of _________(a) Modulation(b) Demodulation(c) Macroscopic diversity technique(d) Microscopic diversity techniqueI have been asked this question during an internship interview.The above asked question is from Diversity Techniques in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (c) Macroscopic DIVERSITY technique

For EXPLANATION: Large scale fading is mitigated with macroscopic diversity techniques. It is done by selecting a base station which is not shadowed when others are, the mobile can IMPROVE substantially the AVERAGE signal to noise ratio.

74.

Polarization diversity uses the ________ as the diversity element.(a) Modulation index(b) Carrier frequency(c) Reflection coefficient(d) Coherence timeThe question was posed to me by my school teacher while I was bunking the class.This key question is from Diversity Techniques topic in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (C) Reflection coefficient

Easiest EXPLANATION: Decorrelation of the signal in each polarization is caused by multiple reflections in the channel between MOBILE and base station antenna. Reflection coefficient for each polarization is different, which RESULTS in different amplitudes and phases for each reflection.

75.

Each correlation receiver in RAKE receiver is adjusted in ____________(a) Frequency shift(b) Amplitude change(c) Phase shift(d) Time delayI had been asked this question in an internship interview.My question is taken from Rake Receiver in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» RIGHT ANSWER is (d) Time delay

To explain: Each CORRELATION receiver MAY be adjusted in time delay, so that a MICROPROCESSOR controller can cause different correlation receivers to search in different time windows for significant multipath.
76.

Which of the following is not an error correction and detection code?(a) Block code(b) Convolutional codes(c) Passive codes(d) Turbo codesI got this question during an interview.My question comes from Convolutional Codes in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right choice is (C) Passive codes

For EXPLANATION: There are three BASIC types of error correction and DETECTION codes. They are block codes, convolutional codes and turbo codes. A channel coder operates on digital message data by encoding the source information into a code sequence.

77.

Which of the following does not hold true for MLSE?(a) Minimizes probability of sequence error(b) Require knowledge of channel characteristics(c) Requires the statistical distribution of noise(d) Operates on continuous time signalI got this question during an interview.My question comes from Equalization Techniques in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Correct choice is (d) OPERATES on continuous TIME signal

For explanation: Matched filter operates on the continuous time signal, whereas maximum likelihood sequence estimation (MLSE) equalizer and channel ESTIMATOR rely on discretized samples. MLSE is optimal in the sense that it minimizes the probability of sequence error.

78.

The weight of code is given by number of _______(a) Non-zero elements in the codeword(b) Zero elements in the codeword(c) Total elements in the codeword(d) Elements in parity bitsI have been asked this question in an internship interview.I need to ask this question from Block Codes and Finite Fields topic in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

Right answer is (a) Non-zero ELEMENTS in the codeword

Easy EXPLANATION: The weight of a CODE is GIVEN by number of non-zero elements in the codeword. For a binary code, the weight is BASICALLY the number of ones in the codeword.

79.

Frequency diversity is good for low traffic conditions.(a) True(b) FalseThe question was posed to me in an international level competition.I'd like to ask this question from Diversity Techniques topic in section Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer»

The correct option is (b) False

For explanation: Frequency diversity is not good for LOW traffic conditions. This TECHNIQUE has a disadvantage that it not only requires spare bandwidth but ALSO requires that there be as many RECEIVERS as there are channels used for frequency diversity. HOWEVER, for critical traffic, the expense may be justified.

80.

Which of the following is not a characteristic of FIR filter?(a) Many zeroes(b) Poles only at z=0(c) Transfer function is a polynomial of z-1(d) Many polesThe question was posed to me during an interview.My doubt stems from Equalization Techniques topic in chapter Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» RIGHT option is (d) Many poles

Explanation: Finite IMPULSE response FILTER (FIR) has many zeroes but poles only at z=0. The transfer FUNCTION of the filter is a polynomial of z-1. It is also referred to as transversal filter.
81.

Which of the following is a blind algorithm?(a) Linear adaptive algorithms(b) Constant modulus algorithm(c) Non-linear adaptive algorithms(d) Spatially adaptive algorithmsThe question was asked in examination.My question is taken from Fundamentals of Equalization in portion Equalization, Diversity and Channel Coding of Wireless/Mobile

Answer» RIGHT answer is (b) Constant MODULUS algorithm

The explanation is: Blind algorithm technique uses algorithms such as the constant modulus algorithm (CMA) and the spectral coherence restoral algorithm (SCORE). CMA is used for constant ENVELOPE MODULATION and FORCES the equalizer weights to maintain a constant envelope on the received signal.