InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The combined resistance of a galvanometer of resistance `500 Omega` and its shunt is `21 Omega` Calculated the value of shunt. |
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Answer» Here, `G = 500 Omega` and `R_(eq)= 21 Omega` `1/(R_(eq)) = 1/G +1/S` `:. 1/S = 1/(R_(eq)) - 1/G = (G-R_(eq))/(R_(eq)G)` `:. S = (R_(eq)G)/(G-R_(eq))` `rArr S = (500 xx 21)/(500 - 21) = (10500)/(479)` `:. S = 21.92 Omega`. |
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| 2. |
If the polarising angle for a given medium is ` 60^@`, then the refractive index of the medium isA. `1/(sqrt(3))`B. `sqrt((3)/(2))`C. `l`D. `sqrt(3)` |
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Answer» Correct Answer - d `sqrt(3)` Refractive index, `mu = tan i_(p)` `mu = tan 60^(@)` `:. mu = sqrt(3)` |
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| 3. |
The vapour pressure of pure benzene is 640 mm of Hg. `2.175 xx 10^(-3)` kg of non-volatile solute is added to 39 gram of benzene, the vapour pressure of solution is 600 mm of Hg. Calculate molar mass of solute (C = 12, H = 1). |
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Answer» Molar mass of benzene `= (6 xx 12 + 6 xx 1)` ` 78 xx 10^(-3) kg mol^(-1)` `P_(0) = 640 mm Hg,` P = 600 mm Hg `W_(1) = 39 xx 1-^(-13) kg` `W_(2) = 2.175 xx 10^(-3) kg` `M_(1) = 78 xx 10^(-3) kg, M_(2) = ?` `M_(2) = (p_(0) xx W_(2) xx M_(1))/(Delta P xx W_(1))` `M_(2) = (640 xx 2.175 xx 10^(-3) xx 78 xx 10^(-3))/((640 - 600) xx 39 xx 10^(-3))` `= 69.6 10^(-3) kg mol^(-1)` |
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| 4. |
The decay constant of radioactive substance is `4.33 xx 10^(-4)` per year. Calculate its half life period . |
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Answer» Here, `lambda = 4.33xx 10^(-4)` per year `t_(1//2) = (0.6931)/(lambda)` `:. t_(1//2) = (0.6931)/(4.33 xx 10^(-4))` `:. t_(1//2) = 1600.6928` years or `t_(1//2) = 1,600.6928 xx 365` days `:. t_(1//2) = 584252` days |
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| 5. |
Write mathematical equations of first law of thermodynamics for the following processes: (a) Adiabatic (b) Isochoric process |
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Answer» (a) In adiabatic process, there is no exchange of heat thus q = 0. So, first law becomes `Delta U = W`. (b) Isochoric process, as it carried in closed vessel `Delta V = 0` thus q = 0. So, first law becomes `Delta U = q` |
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| 6. |
Write the names and chemical formulae of any one are of iron and zinc each. |
| Answer» `{:("Element","ore","Name"),("Iron",Fe_(2)O_(3),"Haematite"),("Zinc",ZnS",Zinc blende"):}` | |
| 7. |
What is the action of (a) Sodium on arsenic (b) Magnesium on bismuth |
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Answer» (a) Sodium on arsenic : Arsenic reacts with sodium metal to form sodium arsenide. `2As + 3 Na to Na_(2) As_(3)` (not expected) (b) Magnesium on bismuth : Bismuth reacts with magnesium to form magnesium bismuthide. `2Bi + 3 Mg to Mg_(3) Bi_(2)` (not expected) |
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| 8. |
Define enthalpy of sublimation. How is it related to enthalpy of fusion and enthalpy of vaporization? |
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Answer» The enthalpy change that accompanies the conversion of one mole of solid directly into its vapour at constant temperature is called as enthalpy of sublimation. `Delta_(sub) H = Delta_(fus) H + Delta_(vsp) H` |
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| 9. |
The process of superimposing a low frequency signal on a high frequency wave is `"_________"`.A. detectionB. mixingC. modulutionD. attenuation |
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Answer» Correct Answer - c Modulation The process of superimposing a low frequency signal an a high frequency wave is known as modulution . |
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| 10. |
What are ketones? How are ketones classified? |
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Answer» First oxidation product of secondary alcohol or the organic compound containing keto of gt C = O group in which both valency of carbonyl carbon are satisfied by alkyl or any radical. simple ketones Ex. Acetone Mixed ketone Ex. Ethyl methyl ketone. |
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| 11. |
`Sc^(3+)` is colourless is aqueous solution whereas `Ti^(3+)` is coloured. |
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Answer» Electronic configuration of `._(21)Sc^(3+)` is [Ar `3d^(0)` and `._(22)Ti^(3+)` is [Ar] `3d^(1)`. Therefore due to absence of unpaired electron `Sc^(3+)` is colourless and due to presence of one unpaired electron d-d transtion takes place hence `Ti^(3+)` is coloured. |
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| 12. |
Double Salt and Coordination Compound |
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Answer» Double salts are those molecular or addition compounds which exist in a solid state but dissociate into constitunets ions when dissolved in water Ex. Mohr salt `FeSO_(4) (NH_(4))_(2) SO_(4). 6H_(2)O`. Coordination compound are those molecular or addition compounds which retain their identiy in aqueous solution and shows property entirely different from their constituent ions. Ex potassium ferrocyanide `K_(4) [Fe(CN)_(6)]` |
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| 13. |
Write the formula of Tetraminodichloroplatinum (IV) chloirde. How is propene converted into I-bromopropane and 2-bromopropane? |
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Answer» Tetraminodichlorplatinum (IV) chloride `[PtCl_(2) (NH_(3))_(4)]Cl_(2)` Propene converted into 1-bromopropane `CH_(3) CH = CH_(2) + HBr overset("Peroxide")(to) underset(1-bromopropane")(CH_(3)CH_()CH_(2)Br)` Proene converted into 2 bromopropane `CH_(3) CH = CH_(2) + HBr overset(MK "rule")(to) underset(2-"bromopropane")(CH_(3)CH BrCH_(3))` |
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| 14. |
Explain the terms: (a) Optical activity (b) Ligand (c ) Interstitial compounds. |
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Answer» (a) Optical activity : The phenomenon or property or organic substance to rotate the plane of PPL towards right or left is called as optical activity. (b) Ligand : The molecule or ion which are coordinated to the metal atom or ion in coordination compound are called as ligands (c ) Interstitial compounds : Those compounds which are formed when small amount of small atoms like H, C and N are trapped inside the interstitial space in crystal of metals. |
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| 15. |
A body of moment of inertia 5 `kgm^(2)` rotating with an angular velocity 6 rad/s has the same kinetic energy as a mass of 20 kg moving with a velocity of ……A. `5 m//s`B. `4 m//s`C. `3 m//s`D. `2 m//s` |
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Answer» Correct Answer - C `3 m//s` Given that `1/2 Iomega^(2) = 1/2 mv^(2)` `:. 1/2 xx 5kgm^(2) xx 6^(2)` rad/s= `1/2 xx 20 kg xx v^(2)` `:. v^(2) = 9` `:. v = 3` m/s. |
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| 16. |
What are neutral oxides? Explain the nature of zinc oxide with the help of reaction. Define Molar Conductivity and Zero order reaction. In a first order reaction x `to` 40% of the given sample of compound rate constant of the reaction. |
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Answer» The oxides which are neither acidic nor basic are called as neutral oxides. Ex. NO,CO,`N_(2)O` etc. Amphoteric natural of ZnO `ZnO_((s)) + 2HCI_((aq)) to ZnCl_(2(s)) + H_(2) O_((1))` `ZnO_((s)) + 2 NaOH_((aq)) to Na_(2) ZnO_(2(aq)) + H_(2) O_((1))` Molar conductivity : The conductance of a volume of a solution containing 1 mole of dissolved electrolyte when placed between two parallel electrode 1 cm apart. Zero order reaction : The reaction whose rate is independent of the reaction concentration adn remains constant throughout the course of the reaction. Solution : At t = 45 concentration `[A]_(0) = 100` final concentration `[A]_(r ) = 40` `K = (2.303)/(t) log_(10) ([A]_(0))/([A]_(t))` `= (2.303)/(45) log_(10) (100)/(40)` `= (2.303)/(45) log_(10) 2.5` `= (2.303 xx 0.3979)/(45)` `= 0.02036 "min"^(-1)` |
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| 17. |
Which of the following gates correspond to the truth table given below ? A. ANDB. NORC. ORD. NAND |
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Answer» Correct Answer - b NOR |
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| 18. |
Electric field intensity due to a charged sphere at a point outside the sphere decreases with `"……………….."`.A. increase in charge on sphereB. increase in dielectric constant.C. decrease in the distance of from the centre of sphere.D. decrease in the square of distance from the centre of sphere. |
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Answer» Correct Answer - b Increase in dielectric constant Electric field intensity at a point outside a charged conducting sphere is given as `E = 1/(4piepsi).(q)/(r^(2))` |
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| 19. |
Explain what is meant by diffraction of light. Describe a simple experiment to demonstrate diffraction at a single slit. |
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Answer» Bending of light near the edge of an obstacle or slit and spreading into the region of geometrical shadow is known as diffraction of light. The diffraction phenomenon is classified into two types : 1. Fraunhofer diffraction : The source of light and the screen on which the diffraction pattern is obtained are at infinite distance from the diffracting system. In this case, the wavefront due to diffraction is plance wavefront. The diffraction pattern is obtained by using a convex lens. 2. Fresnel diffraction : The source of light and the screen are kept at finite distances from the diffracting system. In this case, we obtain a cylindrical or spherical wavefront due to this diffraction. |
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| 20. |
The energy of a photon of wavelength `lambda` is given byA. `hclambda`B. `(hlambda)/(c )`C. `(lambda)/(hc)`D. `(hc)/(lambda)` |
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Answer» Correct Answer - d `(hc)/(lambda)` Energy of a photon, `E = hv = (hc)/(lambda)` |
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| 21. |
In potentiometer experiment, if `l_(1)` is the balancing length for e.m.f. of the cell of internal resistance r and `l_(2)` is the balancing length for its terminal potential difference when shunted with resistance R then :A. `l_(1) = l_(2) ((R + R)/(R ))`B. `l_(1) = l_(2) ((R )/(R - r))`C. `l_(1) = l_(2) ((R )/(R + r))`D. `l_(1) = l_(2) ((R - r)/(R ))` |
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Answer» Correct Answer - a `l_(1) = l_(2)((R + r)/(R ))` The internal resistance of a cell is given a `r = ((l_(1) - l_(2))/(l_(2)))R` `r/R = (l_(1) - l_(2))/(l_(2))` `:. rl_(2) = Rl_(1) - Rl_(2)` `:. l_(2) (R + r) = Rl_(1)` `:. l_(1) = l_(2) ((R + r))/(R)` |
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| 22. |
Which of the following amines yields foul smelling product with halofrom and alcoholic KOH?A. EthlyamineB. DiethylamineC. TriethylamineD. Ethyl methylamine |
| Answer» Correct Answer - Ethylamine (BONUS) | |
| 23. |
What are f-block elements? Distinguish between lanthanoid and actinoid. |
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Answer» f-block elements : The elements in which differentiating electron enters into (n - 2) f orbital or the penultimate shell or antepenultimate shell of the dorbital are called as f-block elements. Difference between lanthanoids and actinoids `{:("Lanthanoids","Actinoids"),(1."Differentiating electron enters in 4-f orbital",1. "Differentiating electron enters in 5-f orbital"),(2."Belongs to 6th period and form a part of third transition series",2."Belongs to 7th period and from a part of third transition series"),(3."Binding energy of 4-f orbital is higher",3."Binding energy of 4-f orbital is lower"),(4."only promethium is radioactive",4."All member are radioactive"),(5."Beside + oxidation state lanthanoids shows + 2 and + 4 oxidation state in few cases",5."Beside +3 oxidation state actinoids show +4, +5, + 7 higher oxidation state also"),(6."Lanthanoids show low tendency of form complexes",6."Actinoids show greater tendency to form complexes"),(7."Some of the ions of lanthanoids are fairely coloured",7."Most of the ions of actinoids are fairely coloured"),(8."Lanthanod hydroxides are less basic in nature",8."Actinoid hydroxides are more basic in nature"),(9."Contraction is relatively less",9."Contraction is greater"):}` |
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| 24. |
The molecular formula of `H_(2)S_(2)O_(2)` represents which oxoacid among the followingA. Hydrosulphurous acidB. Thiosulphurous acidC. Sulphuric acidD. Pyrosulphurous acid |
| Answer» Correct Answer - Thiosulphurous acid | |
| 25. |
Iodine exists of……..A. Polar molecular solidB. Ionic acidC. Nonpolor molecular solidD. Hydrogen bonded molecular solid |
| Answer» Non-polar molecular solid | |
| 26. |
Absolute entropies of solids, liquid and gases can be determined by ……..A. Measuring heat capacity of substance at various temperaturesB. Subtracting standard entropy of reactants fromC. Measuring vibrational motion of moleculesD. Using formula `DeltaS^(@) = S_(T)^(@) - S_(0)^(@)` |
| Answer» Measuring heat capacity of substance at various temperatures | |
| 27. |
On calculating the strength of current in amperes if a charge of 840 C (coulomb) passes through an electrolyte in 7 minutes, it will be……..A. 1B. 2C. 3D. 4 |
| Answer» Correct Answer - 2 | |
| 28. |
The determination of molar mass from elevation in boiling point is called as……..A. CryoscopyB. ColorimetryC. EbullioscopyD. Spectroscopy |
| Answer» Correct Answer - Ebullioscopy | |
| 29. |
A sonometer wire vibrates with frequency `n_1` in air under suitable load of specific gravity `sigma` . When the load is immersed in water , the frequency of vibration of wire `n_2` will be …..A. `n_(1) sqrt((sigma +1)/(sigma))`B. `n_(1)sqrt((sigma - 1)/(sigma))`C. `n_(1) sqrt((sigma)/(sigma + 1))`D. `n_(1) sqrt((sigma)/(sigma - 1))` |
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Answer» Correct Answer - B `n_(1) sqrt((sigma - 1)/(sigma))` Specific gravity or relative density is `(n_(1))/(n_(2)) = sqrt((sigma)/(sigma-1))` `:. n_(2) = n_(1) sqrt((sigma-1)/(sigma))` |
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