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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
In `A=(x)/(360^(@))xxpir^(2),x=60^(@)`, and r=6cm , then A=_______ |
| Answer» Correct Answer - `6pi cm^(2)` | |
| 52. |
Thirty-six is divided into two parts such that one of the parts is twice the other. The two parts are |
| Answer» Correct Answer - 1 | |
| 53. |
Simple interest on a certain sum is given by `l=(PTR)/(100)`. Make T as the subject of the formula. Find T when P=rs1000, R=10% p.a., and l=rs 300.A. `T=(100l)/(PR),6` yearsB. `T=(100l)/(PR),3` yearsC. `T=(100P)/(IR),4` yearsD. `T=(100R)/(Pl):5` years. |
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Answer» Correct Answer - B `I=(PTR)/(100)` `rArr 100 I=PTRrArr(100I)/(PR)=TrArrT=(100I)/(PR)` Given `P=rs1000,R=10%` p.a, and `I=300` `therefore T=(100xx300)/(1000xx10)=3` years. |
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| 54. |
Write the relation between H and m from the given table. `{:("Number of hours"(H),1,3,5,6,10),("Number of minutes"(m),60,180,300,360,600):}`A. `H=60m`B. `m=60H`C. `H+m=1`D. `m=30H`. |
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Answer» Correct Answer - B We have `1h=60"min"rARrm=60H`. Hence, the correct option is (b). |
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| 55. |
There are b boys and g girls in a class and the average of number of boys and the number of girls is 18. Then b+g=_____ |
| Answer» Correct Answer - 36 | |
| 56. |
A man moevs with p km/h speed for 20 minutes and q km/h for next 30 minutes. Find the expression for this average speed in km/h. |
| Answer» Correct Answer - `(2p+3q)/(5)` | |
| 57. |
In the formula `k=sqrt((n^(2)-1)/(n^(2)+1))`, make n the subject and find n if k=0.5. |
| Answer» Correct Answer - `n=sqrt((1+k^(2))/(1-k^(2))),sqrt((5)/(3))` | |
| 58. |
In the formula, `x=(p+5q)/(sqrt(3)+2q)`, make q the subject. |
| Answer» Correct Answer - `q=(p-sqrt(3)x)/(2x-5)` | |
| 59. |
In the formula `S=sqrt((p^(2)+q)/(p-q))` make q the subject. |
| Answer» Correct Answer - `q=(s^(2)p-p^(2))/(1+s^(2))` | |
| 60. |
In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units and AC=2 units What is the relationship among AB,BC and CA? |
| Answer» Correct Answer - `AC=sqrt(BC^(2)+AB^(2))` | |
| 61. |
Frame the formula for the area (A) of a quadrilateral given by half the product of its diagonal (d) and sum of offsets drawn to the diagonal from its opposite vertices `(h_(1) and h_(2))`? |
| Answer» Correct Answer - `A=(1)/(2)d(h_(1)+h_(2))` | |
| 62. |
Which of the following is not an auxillary fromula for the area of a quadrilateral i.e., `A=(d)/(2)(h_(1)+h_(2))`?A. `h_(1)=(2A)/(d)-h_(2)`B. `h_(2)=(2A-h_(1)d)/(d)`C. `h_(1)=(2A)/(h_(2))-d`D. `d=(2A)/(h_(1)+h_(2))` |
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Answer» Correct Answer - C Make every variable other than A as theh subjects to get the auxiliary formulae and proceed. |
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| 63. |
If `(1)/(f)=(1)/(u)+(1)/(v)`, then make v as the subject o the foormula. Also find v, if u=12 units and f=3 unitsA. 4 unitsB. `(1)/(9)` unitsC. 9 unitsD. `(1)/(4)` units |
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Answer» Correct Answer - A (i) Apply transposition. (ii) First of all bring `(1)/(v)` to LHS and `(1)/(f)` to RHS. (iii) Simplify the RHS. (iv) Then write the reciprocal form. (v) substitute the values of u and f. |
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| 64. |
If `(1)/(f)=(1)/(u)+(1)/(v)`, then make v as the subject of the formula.A. `v=(u-f)/(uf)`B. `v=(f-u)/(fu)`C. `v=(uf)/(u-f)`D. `v=(uf)/(u+f)` |
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Answer» Correct Answer - C (i) Apply transposition. (ii) First make `(1)/(v)` as the subject and then write reciprocal form. |
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| 65. |
The perimeter of a polygon is the ttal length of its sides. In a regular polygon of n sids with x as the length of a side, the perimeter P is________ |
| Answer» Correct Answer - nx | |
| 66. |
If `A=2h(l+b`), then b=____A. `2Ah-1`B. `((A)/(2h))-1`C. `2A l-h`D. `(A)/(2l)-h` |
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Answer» Correct Answer - B Given `A=2h(l+b)` `rArr (A)/(2h)=l+b` `rArr (A)/(2h)-l=b` `rArr b=((A)/(2h))-1` |
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| 67. |
If `A=2h(l+b)`, then b=______A. `2Ah-l`B. `((A)/(2h))-l`C. `2Al-h`D. `(A)/(2l)-h` |
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Answer» Correct Answer - B Given `A=2h(l+b)` `rArr (A)/(2h)=l+b` `rArr(A)/(2h)-l=b` `rArr b=((A)/(2h))-l` Hence, the correct option is (b). |
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| 68. |
The subject of the formulae ,`A=2h(l+b)` is_____A. lB. bC. hD. A |
| Answer» Correct Answer - D | |
| 69. |
The sum of the interior angles in a 6-sided polygon is `720^(@)` and the six angles are x,y,z,z,y. and x. express the relation among x, y, and z by making z as the subject.A. `z=3606(@)-x+y`B. `z=360^(@)-(x+y)`C. `z=360^(@)+x-y`D. `z=36^(@)+x+y` |
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Answer» Correct Answer - B From the given data `x+y+z+z+y+x=720`. `2(x+y+z)=720` `rArr x+y+z=360^(@)` `rArr z=360^(@)-(x+y)` |
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| 70. |
In the formula `k=((a-b)/(a+b))^(2)`, find the value of b if `k=36` and a=3, making b the subject. |
| Answer» Correct Answer - `-70` | |
| 71. |
If `f=3cm` and v=4 cm, then find u. |
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Answer» `(1)/(f)=(1)/(u)+(1)/(v)rArru=(fv)/(v-f)` `=(3xx4)/(4-3)=12cm`. |
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| 72. |
The slant height (l) of a cone is the square root of the sum of the squares of its radius (r) and its vertical height (h). If for a cone, l=17cm and `r=15` cm, then find h. |
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Answer» `l=sqrt(r^(2)+h^(2))` Squaring on both sides, we get `l^(2)=r^(2)+h^(2)` `h^(2)=l l l^(2)-r^(2)=17^(2)-15^(2)=289-225=64` `hgt0` `therefore h=8cm` |
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| 73. |
The area of four walls of room is given by A=2h(l+b). Make l as the subject of the formula. Find l when `A=100m^(2)`, h=5m, and b=4m.A. `l=(A)/(2h)=b,6m`B. `l=(A)/(2h)-h,5m`C. `l=(A)/(2b)-h,4m`D. `l=(A)/(2b)-h,8m` |
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Answer» Correct Answer - A `A=2h(l+b)` `rArr (A)/(2h)=l+brArr(A)/(2h)-b=l` `rArr l=(A)/(2h)-b` Given `A=100m^(2), h=5m`, and `b=4m`. `rArr l=(100)/(2xx5)-4` `rArr I=6m` |
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| 74. |
The number of diagonals of a convex polygon of sides n is equal to `(n(n-3))/(2)`. Find the number of diagonals is hexagon.A. 9B. 6C. 10D. 8 |
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Answer» Correct Answer - A The number of diagonals `=(n(n-3))/(2)`. `=(6(6-3))/(2)`(given n=6)=9 |
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| 75. |
The following table shows the relation between the angles x and y. `{:(x,90^(@),100^(@),110^(@),120^(@),130^(@),140^(@)),(y,90^(@),80^(@),70^(@),60^(@),50^(@),40^(@)):}` Then which of the following is true?A. x=yB. `x+y=180^(@)`C. `x-y=20^(@)`D. `x=2y`. |
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Answer» Correct Answer - B From the given table, `x+y=180^(@)` Hence, the correct option is (b). |
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| 76. |
The following table shows the relation between the angles x and y. `{:(X,90^(@),100^(@),110^(@),120^(@),130^(@),140^(@)),(Y,90^(@),80^(@),70^(@),60^(@),50^(@),40^(@)):}` Express the relation between x and y with x as the subject.A. `y=180^(@)-x`B. `x=180^(@)-y`C. `y=180^(@)+x`D. `x=180^(@)+y` |
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Answer» Correct Answer - B From the given table. `x+y=180^(@)` `rArr x=180^(@)-y` |
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| 77. |
A is the area of the rectangle with length l units and breadth b units. Rewrite the formula for area making l as the subject. |
| Answer» Correct Answer - `l=(A)/(b)` | |
| 78. |
A is the area of the square with side S units. Write the formula of area making S as the subject. |
| Answer» Correct Answer - `S=sqrt(A)` | |
| 79. |
Frame the formula Hypotenuse (h) of right triangle is the square root of sum of the squares of perpendicular sides a and b. |
| Answer» `h=sqrt(a^(2)+b^(2))` | |
| 80. |
Write the relation between x and y from the given table. `{:(x,26^(@),34^(@),75^(@),30^(@),82^(@),10^(@)),(y,64^(@),56^(@),15^(@),60^(@),8^(@),80^(@)):}`A. `x=y-45^(@)`B. `x=y+54^(@)`C. `x=90^(@)-y`D. `x+y=100^(@)` |
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Answer» Correct Answer - C From the given data. `x+y=90^(@)rArr x=90^(@)-y`. Hence, the correct option is (c). |
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| 81. |
Frame the formula for the sentence given below. The sum of the cube of p and the product of 8 and q is equal to the sum of the product of 21, s and the product of 4 and the square of r.A. `p^(3)-4r^(2)=21s+8q`B. `p^(3)-4r^(2)=21s-8q`C. `p^(3)+4r^(2)=21s+8q`D. none of these |
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Answer» Correct Answer - B (i) `p^(3)+8q=21s+4r^(2)` Apply transposition to see the answer. (ii) Given, `p^(3)+8q=21s+4r^(2)` (iii) Then check te options. |
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| 82. |
The volume of a cone is `V=(1)/(3)pir^(2)h`. Make r as the subject of the formula.A. `r=sqrt((3V^(2))/(pih))`B. `r=sqrt((V)/(3pih))`C. `r=sqrt((3V)/(pih))`D. `r=sqrt((V)/(3pih))` |
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Answer» Correct Answer - C (i) apply transposition (ii) Cross multiply and make `r^(2)` as the subject. (iii) Apply square root on both sides. |
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| 83. |
Make y the subject in `(x+y)/(x-y)=(a+b)/(a-b)` |
| Answer» Correct Answer - `y=(bx)/(a)` | |
| 84. |
A wire of length a units is cut into two equal pieces and make a circle of radius r with one piece. Frame the formula by making r the subject. |
| Answer» Correct Answer - `r=(a)/(4pi)` | |
| 85. |
From the formula from the following table. Make a the subject of the formula. `{:(a,25^(@),34^(@),75^(@),4^(@),89^(@),85^(@)),(b,65^(@),56^(@),15^(@),86^(@),1^(@),5^(@)):}` |
| Answer» Correct Answer - `a=80^(@)-b` | |
| 86. |
Frame the formula for the volume (v) of a cylinder given by the product of `pi`, square of radius (r) and height (h). |
| Answer» Correct Answer - `V=pir^(2)h` | |
| 87. |
Frame the formula for the volume (v) of a hemisphere given by two-thirds o the product of `pi` and cube of radius (r). |
| Answer» Correct Answer - `V=(2)/(3)2pir^(3)` | |
| 88. |
Lateral surface area (A) of a cone is A=`pirl`, make l as the subject |
| Answer» Correct Answer - `l=(A)/(pir)` | |
| 89. |
Frame the formula: volume (v) of a cuboid is the product of its length (l), breadth (b), and height (h).A. `v=lbh`B. `v=l+b+h`C. `v=(lb)/(h)`D. `v=h(l+b)` |
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Answer» Correct Answer - A V=lbh. Hence, the correct option is (a). |
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| 90. |
Frame the formula from the following table. Make y the subject of the formula. `{:(X,1,2,5,7,8),(Y,1,4,25,49,64):}` |
| Answer» Correct Answer - `Y=X^(2)` | |
| 91. |
Frame the formula: The lateral surface area of a cylinder S is equal to twice the product of `pi`, radius (r) and height (h) of the cylinder.A. `S=pi^(2)r^(2)h^(2)`B. `S=pirh`C. `2S=pirh`D. `S=2pirh` |
| Answer» Correct Answer - D | |
| 92. |
The number of variables in the formula S=ut+`(at^(2))/(2)` is__.A. 4B. 3C. 2D. 1 |
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Answer» Correct Answer - A `S=ut+(at^(2))/(2)` `therefore` There are four different variables. Hence, the correct option is (a). |
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| 93. |
Frame the formula: final velocity (v) of a body in linear motion is equal to the sum of its initial velocity (u) and the product of acceleration (a) and time (t).A. v=-u+atB. v=u-atC. v=u+atD. v=-u-at |
| Answer» Correct Answer - C | |
| 94. |
If `d=ut+(1)/(2)at^(2),u=20,a=10`, and d=50t, then find t. |
| Answer» Correct Answer - 6 | |
| 95. |
The symbolic form of "area of a sector (A) is half of the product length of the are (l) and radius (r)" is _______A. A=lrB. `A=(r)/(l)`C. `A=(lr)/(2)`D. `A=(l+r)/(2)` |
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Answer» Correct Answer - C A=(Ir)/2 Hence, the correct option is (c). |
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| 96. |
If `A=(S)/(N)`, then N=________A. `(S)/(A)`B. `(A)/(S)`C. `SA`D. `S+A` |
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Answer» Correct Answer - A Given `A=(S)/(N)`. Multiplying with N on both the side, we get. `therefore N=(S)/(A)`. Hence, the correct option is (a). |
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| 97. |
The subject of the folulae, `s=ut+(at^(2))/(2)` is____A. sB. uC. tD. a |
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Answer» Correct Answer - A A variable standing along on the LHS of a formula is called the subject of the formula. Given `s=ut+(at^(2))/(2)`. `therefore` The subject is s. Hence, the correct option is (a). |
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| 98. |
The symbolic form of "6 less than twice p is equal to 3 more than q" is_______A. `2p+6=q-3`B. `6lt2p`C. `2p-6=q+3`D. `3gtq` |
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Answer» Correct Answer - C Twice p is 2p,6 less than twice p is 2p-6, and 3 more than q is q+3. `therefore` The symbolic form of "6 less than twice p is equal to 3 more than q" is `2p-6=q+3` . |
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| 99. |
The symbolic form of "area (A) of a trapezium is half of the product of distance between the paralel side (h) and sum of the lengths of parallel sides (a,b)" is____.A. `A=(h)/(2)(a+b)`B. `A=(h)/(2)(a-b)`C. `A=(hab)/(2)`D. `A=hab` |
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Answer» Correct Answer - A `A=(h)/(2)(a+b)` Hence, the correct option is (a). |
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| 100. |
Write the following sentence in symbolic form. Sum of cubes of p and q is equal to thrice the product of r and s.A. `p^(3)-q^(3)=3rs`B. `p^(3)+q^(3)=3rs`C. `p^(3)+q^(3)=r^(3)s^(3)`D. `p^(2)+q^(2)=3r^(3)s^(3)` |
| Answer» Correct Answer - B | |