This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Describe plant ash analysis. |
Answer»
Requirements for Detection of Ash: (a) Preparation of Ash Extract: For detection of various elements in plant ash viz., Ca, Mg, Fe, S, P, CI etc. ash material is dissolved in 50% HC1 (v/v) or 50% HNO3 (v/v) for an hour or more, then filtered through filter paper. Finally selective tests are made for detection of the elements. (b) Reagents: 1. HCl (50%). 2. HNO3 (50%). 3. Barium chloride (5%).4. NH4OH solution (dilute). 5. Ammonium oxalate (saturated). 6. Na2HPO4 solution (10%). 7. Potassium ferrocyanide solution (2%). 8. Ammonium thiocyanate solution (5%). 9. Potassium thiocyanate solution (5%). 10. Ammonium molybdate solution (10%). 11. Silver nitrate solution (10%). 12. Disodium hydrogen phosphate solution (10%). Tests for Detection of Ash: (a) Tests Using HC1 Extract of Plant Ash: Experiment: Test 1: To about 5-10 ml of filtrate, a few drops of 5% Barium chloride solution is added. Test 2: About 20 ml of filtrate is taken in a test tube and made alkaline by addition of a drop of dil. NH4OH. Finally saturated ammonium oxalate solution is added. Test 3: After removal of Calcium oxalate ppt. by filtration, the solution is heated to concentrate and then cooled. Finally 10% disodium hydrogen phosphate solution is added to it. Test 4 : To about 10 ml of ash extract 2% potassium ferrocyanide solution is added. Test 5: To about 10 ml of extract, 5% ammonium thiocyanate or 5% potassium thiocyanate solution is added. Observations: A white crystalline precipitate is formed (ppt. of BaSO4). A white precipitate of Calcium oxalate is formed. A white precipitate of ammonium magnesium phosphate is formed. A dark blue coloration (Prussian blue) is formed. The solution turns blood red. Inference: Presence of sulphur in the ash extract. Presence of Calcium in the ash extract. Presence of Magnesium in the ash extract. Presence of Iron in the ash extract. Presence of Iron in the ash extract. (b) Tests using HNO3 extract of Plant Ash: Experiment: Test 6: To about 10 ml of extract, a few drops of ammonium molybdate soln. added, then heated for 10 min. and cooled. Test 7: To a small quantity of extract a few drops of 10% silver nitrate solution are added. Observation: A yellowish crystalline precipitate is formed (ppt. of ammonium phosphomolybdate). A white precipitate is formed. Inference: Presence of Phosphorus in the ash extract. Presence of Chlorine in the ash extract. |
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| 2. |
In which form Fe and Cl are absorbed from the soil? |
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Answer» He is absorbed in the form of Ferric (Fe3+) ion and chlorine are absorbed in the form of Chloride (Cl-) |
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| 3. |
Explain the term hydroponics and Vermiculite? |
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Answer» Hydroponics: The technique of culturing plants in a nutrient solution in place of soil is called liquid culture or hydroponics. This technique is used to determine the requirement of mineral nutrients of plants. Vermiculite: Vermiculite is a mineral substance found in soil in nature. This is lightweight, chemically inert, heat resistant, the sterile substance having water holding capacity more than soil. This substance is heated in a furnace at 2000°F and the product is used in culturing plants. This technique is called Vermiculoponics. |
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| 4. |
Write the name of primary macronutrients? |
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Answer» Nitrogen (N), Phosphorus (P), and Potassium (K) |
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| 5. |
Plants absorb nitrogen in the form of? |
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Answer» Plants absorb nitrogen in the form of nitrate and nitrite and as an exception as NH4+ |
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| 6. |
Which element is most important for the transportation of carbohydrates in plants? (a) Fe (b) Mo (c) B (d) Zn |
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Answer» The answer is (c) B |
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| 7. |
Immobile nutrient elements are – (a) Cu, S, Fe, Mn (b) Ca, B, Cu, S (c) N, P, Fe, Mn (d) P, K, Zn, Mo |
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Answer» The answer is (a) Cu, S, Fe, Mn |
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| 8. |
The number of essential elements for normal growth and completion of the life cycle of plants is? (a) 105 (b) 60 (c) 27 (d) 17 |
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Answer» The answer is (d) 17 |
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| 9. |
Little leaf disease is caused by a deficiency of which element? (a) Zn (b) Mg (c) B (d) S |
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Answer» The answer is (a) Zn
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| 10. |
The main function of Mo is in which of the following? (a) Flowering (b) Nitrogen fixation (c) Water absorption (d) Photosynthesis |
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Answer» The answer is (b) Nitrogen fixation Nitrogen fixation is a process by which molecular nitrogen in the air is converted into ammonia (NH3) or related nitrogenous compounds in soil |
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| 11. |
The element found in chlorophyll is?(a) Fe (b) Mn (c) Mg (d) K |
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Answer» The answer is (c) Mg Chlorophylls have a cyclic tetrapyrrole porphyrin head to which a long phytol tail is attached. The cyclic tetrapyrrole has an atom of magnesium coordinated in the centre. The chlorophyll is synthesized from protochlorophyllide on exposure to light. The synthesis of protochlorophyllide requires iron. Hence, the correct answer is the Mg |
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| 12. |
Which of the following elements are called micronutrients? (a) Mo, Cu, Zn, Ca (b) Mg, S, K, P (c) Mn, Zn, Cu, Mg (d) Mn, Mo, Cu, Zn |
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Answer» The answer is (d) Mn, Mo, Cu, Zn |
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| 13. |
Differentiate between active and passive absorption of minerals. |
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Answer» Active Absorption of the mineral is absorbed when the cell sap in plant put large quantities of minerals ion against the concentration gradient like as in a plant the cell sap of the root cells have potassium ions and phosphate ions who is thousand or hundred times greater than in the soil where the plant was growing. It is called active absorption because it require disbursement of metabolic energy. Whereas passive absorption of minerals occurs when the concentration of minerals is higher in the outer solution than the cell sap of the root cells. The minerals absorbed according to the concentration gradient by the simple process of diffusion, this is called passive absorption of minerals because it does not require disbursement of metabolic energy. The whole process of absorption of minerals may be two types -(i) Active Absorption of minerals (ii) Passive Absorption of minerals Active Absorption of the mineral is absorbed when the cell sap in plant put large quantities of minerals ion against the concentration gradient like as in a plant the cell sap of the root cells have potassium ions and phosphate ions who is thousand or hundred times greater than in the soil where the plant was growing. It is called active absorption because it require disbursement of metabolic energy. Whereas passive absorption of minerals occurs when the concentration of minerals is higher in the outer solution than the cell sap of the root cells. The minerals absorbed according to the concentration gradient by the simple process of diffusion, this is called passive absorption of minerals because it does not require disbursement of metabolic energy. |
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| 14. |
Controlling plays an important role in helping:(a) increase the costs, (b) fixing standards, (c) identify opportunities, (d) time management |
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Answer» Correct option is (c) identify opportunities, |
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| 15. |
Deviation is a term used in: (a) controlling (b) motivation (c) directing (d) staffing |
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Answer» Correct option is (a) controlling |
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| 16. |
Changes in environment can be (a) Economic (b) Sociological(c) Technological (d) All of the above |
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Answer» Correct option is (d) All of the above |
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| 17. |
Directing the employees includes (a) Supervising employees (b) Leading employees (c) Both a and b (d) None of the above |
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Answer» Correct option is (c) Both a and b |
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| 18. |
Resistance to change is due to (a) Status quo (b) Fear of unknown (c) Both a and b (d) None of the above |
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Answer» Correct option is (c) Both a and b |
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| 19. |
Need for planned change arises due to (a) Market situation (b) Technology (c) Deficiency in existing system (d) All of the above |
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Answer» Correct option is (d) All of the above |
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| 20. |
Describe the Hershey−Chase experiment. Write the conclusion they arrived at after the experiment. OR How did Hershey and Chase established that DNA is transferred from virus to bacteria? |
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Answer» Proof for DNA as the Genetic Material ▪ Hershey and Chase conducted experiments on bacteriophage to prove that DNA is the genetic material. Procedure: i. Some bacteriophage virus were grown on a medium that contained radioactive phosphorus (32P) and some in another medium with radioactive sulphur (35S). ii. Viruses grown in the presence of radioactive phosphorus (32P) contained radioactive DNA. iii. Similar viruses grown in presence of radioactive sulphur (35S) contained radioactive protein. iv. Both the radioactive virus types were allowed to infect E. coli separately. v. Soon after infection, the bacterial cells were gently agitated in blender to remove viral coats from the bacteria. vi. The culture was also centrifuged to separate the viral particle from the bacterial cell. Observations and Conclusions: i. Only radioactive 32P was found to be associated with the bacterial cell, whereas radioactive 35S was only found in surrounding medium and not in the bacterial cell. ii. This indicates that only DNA and not protein coat entered the bacterial cell. iii. This proves that DNA is the genetic material which is passed from virus to bacteria and not protein. |
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| 21. |
What are the factors responsible for colour of transition metal ions? |
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Answer» Factors responsible for colour of transition metal ions are as follows: i. The presence of incompletely filled d-orbitals in metal ions. ii. The presence of unpaired electrons in d-orbitals. iii. d-d transitions of electrons due to absorption of radiation in the visible region. iv. Nature of groups (anions or ligands) linked to the metal ion in the compound or a complex. v. Type of hybridisation in metal ion in the complex. vi. Geometry of the complex containing transition metal ion. Note: Colour of 3d transition metal ions:
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| 22. |
Explain the colour of MnO4- ion. |
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Answer» i. MnO-4 ion is intense purple coloured in solution. ii. The colour is due to charge transfer. An electron is temporarily transferred from O-2 to Mn7+ in MnO-4. iii. Due to this, there is a temporary change in the oxidation state of oxygen from -2 to -1 and manganese from +7 to +6. iv. Charge transfer is possible when the energy levels on the two different atoms involved are appreciably close. Note: Cr2O72- , Cr2O4- , MnO4- , Cu2O and Ni-DMG complex are coloured due to charge transfer transitions. |
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| 23. |
Explain why copper sulphate is blue in colour when dissolved in water but turns yellow when treated with concentrated HCl. |
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Answer» i. The electronic configuration of Cu: [Ar] 3d104s1 and Cu2+: [Ar] 3d9 ii. In the aqueous solution of copper sulphate, Cu2+ forms blue hydrated complex [Cu(H2O)6]2+ because it has one unpaired electron in 3d subshell. The complex has octahedral geometry. iii. When CuSO4 solution is treated with concentrated HCl solution, it forms a new complex [CuCl4]2- . [Cu(H2O)6]2+ + 4Cl- → [CuCl4]2- + 6H2O iv. The complex [CuCl4]2- has a tetrahedral geometry. Due to the change in geometry and hybridisation of the complex, the colour of the solution changes from blue to yellow. |
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| 24. |
An employee in a textile manufacturing firm was given the freedom to opt for the start and quit time for a week. What is the type of flex time being following by the firm A. Glidingtime B. Flexi tour C. Variable day D. Maniflex |
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Answer» Correct option is B. Flexi tour |
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| 25. |
What is binomial nomenclature? |
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Answer» Binomial nomenclature: The binomial nomenclature is made up of two words a generic name and a specific name. |
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| 26. |
What is the body features of annelids? |
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Answer» Annelids’ body is bilaterally symmetrical, triploblastic segmented, and has a true body cavity. Eg: Earthworm, Leech, Nereis. |
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| 27. |
In Drosophila, the genotype of normal wings(A) vgni(B) Vg+(C) vgno(D) vg |
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Answer» Correct answer is B. vgni = Nicked wings vgno = Notched wings vg = Vestigial wings |
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| 28. |
How is the variability in oxidation states of transition metals different from that of the non‐ transition metals? Illustrate with examples. |
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Answer» The transition elements use its (n‐1)d, ns and np orbital and the successive oxidation states differ by unity. For example, Mn shows all the oxidation states from +2 to +7. On other hand non transition elements use its ns, np and nd orbitals and the successive oxidation states differ by two units e.g. Sn2+, Sn4+ etc. |
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| 29. |
Account for the following :(a) Cu+ is unstable in an aqueous solution.(b) Transition metals form complex compounds. |
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Answer» (a) Because Cu+ undergoes disproportionation as 2Cu+ → Cu + Cu2+ Hydiation enthalpy of Cu2+ is higher than that of Cu+ which Compensates the I.E.2 of cu involved in the formation of Cu2+ ions. (b)Because of small size of metal, high ionic charge and availability of vacant d-orbital. |
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| 30. |
What are d-block elements? Give their general electronic configuration. |
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Answer» Definition : d-block elements are defined as the elements in which the differentiating electron enters d-orbital of the penultimate shell i.e. (n – 1) d-orbital where n is the last shell. The general electronic configuration can be represented as, (n – n) dn-10, nsn-2 |
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| 31. |
Some d-block elements are given below.(Cr, Mn, Fe, Co, Ni)(a) Identify the element which shows maximum paramagnetic behaviour.(b) Give reason for the highest paramagnetic property of that element.(c) When two electrons are lost from each atom, is there any change in magnetic properties of each ? Explain? |
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Answer» (a) Cr (b) Cr- 4s1 3d5 Since there are six unpaired electrons in Cr, it has the maximum paramagnetic behaviour. when two electrons are lost, Mn2+ contains maximum number of unpaired electrons ie., Mn2+ is the ion with maximum paramagnetic behaviour. Cr2+ and Fe2+ show similar paramagnetism and so on. |
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| 32. |
In which block of the modern periodic table are the transition elements placed? |
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Answer» Transition elements are placed in d-block of the modern periodic table. |
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| 33. |
What is the position of the transition elements in the periodic table? |
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Answer» The transition elements are placed in periods 4 to 7 and groups 3 to 12 of the periodic table. |
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| 34. |
Why are most of the d-block elements called transition elements? |
Answer»
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| 35. |
Which elements in the 4d and 5d-series will show maximum number of oxidation states? |
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Answer» In 4d-series maximum number of oxidation states are for Ruthenium Ru (+ 2, + 3, + 4„ + 6, + 7, + 8). In 5d-series, maximum number of oxidation states are for Osmium, Os ( + 2 to + 8). |
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| 36. |
Predict which of the following will be coloured aqueous solution?Ti3+, V3+ cu+, Sc3+, Mn2+, Fe3+ and CO2+ and MnO4- . Give reasons for each. |
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Answer» Any ion that has partially filled d-orbitals is coloured due to d-d transition in visible light. MnO has purpule colour due to charge-transfer. Cu+(d10) and Sc3+(d0) are white since there is no d-d transition. |
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| 37. |
Give the similarities and differences in elements of 3d, 4d and 5d series. |
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Answer» Similarity :
Differences :
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| 38. |
Why Li and Mg show resemblance in chemical behaivour? |
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Answer» Due to diagonal relationship, since their atomic size, electro negativity and ionisation potential are almost the same. |
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| 39. |
Why noble gases have low boiling point? |
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Answer» Noble gases being monoatomic have no inter atomic forces except weak dispersion forces. Hence they have low boiling points. |
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| 40. |
Write the formula of the first noble gas compound prepared by N. Bartlett. What inspired N Bartlett to prepare this compound ? |
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Answer» Xe+ [PtF6]- . Neil Bartlett,observed the reaction of a noble gas. First, he prepared a red compound which is formulated as O2 + [PtF6] -. He, then realised that the first ionization enthalpy of molecular oxygen (1175 kJmol–1) was almost identical with that of xenon (1170 kJ mol–1). He made efforts to prepare same type of compound with Xe and was successful in preparing another red colour compound Xe+ [PtF6] - by mixing PtF6 and xenon. |
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| 41. |
In which period of the periodic table, will an element, be found whose differentiating electron is a 4d-electron? |
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Answer» An element whose differentiating electron is a 4d-electron will be present in fifth period of the periodic table. |
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| 42. |
Why Li and Mg although belonging to different groups show resemblance in chemical behaviour? |
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Answer» Due to diagonal relationship, since their atomic size, electronegativity and ionization potential are almost the same. |
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| 43. |
In which period of the periodic table, will an element, be found whose differentiating electron is a 4d electron? |
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Answer» Fifth period of the periodic table consist of elements in which the differentiating electron is a 4d electron. |
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| 44. |
What are the conditions for ‘something’ to be called ‘matter’? |
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Answer» The condition for something to be called as matter is that it should occupy space and have mass. |
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| 45. |
Cr, Mo, W are hard & highly metallic. Why? |
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Answer» These metals have maximum number of unpaired electrons in their (n-1) d orbitals. |
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| 46. |
Explain the metallic characters of the d-block elements. |
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Answer» i. All the transition elements are metallic in nature. They either have hexagonal close pack (hcp), cubic close pack (ccp) or body centred cubic lattices which is a characteristic of true metal. ii. They are hard, lustrous, malleable and ductile with high melting and boiling points, and having good thermal and electrical conductivities. iii. Low ionization enthalpies and presence of vacant orbitals in the outermost shell results in metallic character due to formation of metallic bonds. iv. In addition to the electrons from outermost energy level, the unpaired d-electrons also contribute for the bond formation. So, greater the number of unpaired d-electrons, stronger is the bonding. This is due to the formation of covalent bonds by the overlapping of the d-orbitals containing unpaired electrons. |
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| 47. |
Which element of the first transition series shows the highest number of oxidation states? |
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Answer» Mn element is the highest number of oxidation states. |
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| 48. |
Why are Cd2+ salts white? |
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Answer» Cd2+ ion has no unpaired electron. |
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| 49. |
What are d-block elements? |
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Answer» The elements in which the last electron enters the d-orbital of the penultimate shell i.e.,(n-1)d-orbital where ‘n’ is the outermost shell, are called d-block elements Their general valence or outer electronic configuration is (n - 1)d1-10 ns1-2. |
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| 50. |
Define transition elements? Which group of d- block elements is not considered as transition element and why? |
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Answer» Transition elements have partly filled d sub shell in its ground state or any of its oxidation. Group 12 elements are not considered as transition elements due to completely filled d- orbital in ground state as well as oxidation states. |
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