This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Define the term Isotope of an atom with a suitable example. |
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Answer» Atoms of an element with different mass number are called Isotopes. Ex : Hydrogen has three types of atoms, 1. 1H1 (protium) 2. 1H2 (deuterium) 3. 1H3 (tritium) |
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| 2. |
State the postulates of Dalton’s atomic theory. |
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Answer» In 1803 English chemist Dalton put forward his atomic theory. The main postulates of the theory are as follows. 1. Elements are made up of very small indivisible particles called atoms. 2. All atoms of a particular element are identical in shape, mass and other properties, but are different from the atom of other elements. 3. Atom of one element can not be converted into that of another element. 4. Atoms of an element combine in integral ratio with those of other elements to form a compound 5. An atom can neither be created nor destroyed. |
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| 3. |
List out the different characteristics of anode rays. |
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Answer» The characteristics of anode rays are: 1. They consists of positively charged particles. 2. They are deflected by electrical and magnetic fields. The deflection is very little when compared to the deflection of cathode rays because they consists of heavy particles 3. The deflection of the anode rays depends on the nature of the rays in the discharge tube. Heavier the gas lower the depletion. |
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| 4. |
Give the drawbacks of J.J. Thomson’s experiment. |
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Answer» (i) IT could not explain the origin of the spectral lines of hydrogen and other atoms, (ii) It failed to explain scattering of a - particles in Rutherford’s scattering experiment. |
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| 5. |
From the symbol 19k40 state (1) mass number of potassium (2) atomic number of potassium (3) write the distribution of electrons in an atom of potassium. |
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Answer» 1. The mass number of potassium (A)= 40 2. The atomic number of potassium (Z)=19 3. The electronic configuration of potassium = 1S2 , 2S22Ps 3S23P6, 4S1 |
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| 6. |
What are canal rays? |
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Answer» Canal rays are positively charged radiations that can pass through perforated cathode plate. These rays consist of positively charged particles known as protons. |
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| 7. |
What is an element? |
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Answer» Any Substance made up of same kind of atom is called element. 118 elements are known to us. |
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| 8. |
When the hydrogen gas is taken inside discharge tube the deflection will be maximum give season. |
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Answer» The positive particles of hydrogen atoms are the lightest hence the deflection will be maximum. |
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| 9. |
Why; e/m value is not constant for canal rays? |
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Answer» Mass of particles of cathode rays is not constant. |
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| 10. |
Why ; an electron cannot exist in the nucleus whose radius is 10-15 meter? |
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Answer» by using uncertainty principal calculated value of uncertainty in velocity is more than the velocity of light. |
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| 11. |
List out the characteristics of cathode rays. |
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Answer» The characteristics of cathode rays are: 1. They consists of negatively charged particles. 2. cathode rays are also called as electrons. 3. electrons are lighter than Hydrogen atom. 4. electrons mass is very small or less. |
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| 12. |
Calculate (a) wave number and (b) frequency of yellow radiation having wave length 5800 Å . |
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Answer» (a) Calculation of the wave number \(\lambda\) = 5800 Å = 5800 × 10-10 m \(\bar{v}\) = \(\frac{1}{\lambda}\) = \(\frac{1}{5800\times10^{-10}}\) = 1.724 × 106 m−1 = 1.724 × 104 cm1 (b) Calculation of frequency (v) v = \(\frac{c}{\lambda}\) = \(\frac{3\times10^8ms^{-1}}{5800\times10^{-10}m}\) = 5.172 × 10−14 s−1 |
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| 13. |
When would deBroglie wave length of a moving electron becomes equal to that of proton. |
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Answer» ʎ=h/mv derive from this equation for an electron and proton V1/v2 =m2/m1 =1.6725 x 10-27/9.1095 x 10-31 =1836 Velocity of electron= velocity of proton x 1836 |
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| 14. |
Write the draw back of Rutherford Atomic Model. |
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Answer» (1). He was unable to explain the stability of Atom. (2). He could not explain the line spectrum. |
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| 15. |
What is orbital? |
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Answer» The space around the nucleus where the probability of finding electrons is maximum is called orbital. |
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| 16. |
Types of atomic species . |
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Answer» Types of atomic species
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| 17. |
Write two properties which cannot be explain by wave nature of radiation. |
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Answer» 1.Photoelectric effect 2. Black Body radiation |
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| 18. |
Dual nature of light. |
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Answer» Some properties of light can be explained only by considering the wave nature (differaction and interference) while some could be explained by the particle nature (photoelectric effect). |
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| 19. |
Why atomic line spectra arise? |
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Answer» Atomic line spectra arise because of the absorption/emission of certain frequencies of light energy. |
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| 20. |
What do you mean by electromagnetic spectra? |
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Answer» The complete range of electromagnetic waves in the increasing order of wavelength (decreasing order of frequency) is known as electromagnetic spectra. |
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| 21. |
Write the electromagnetic spectra in the increasing order of wave length. (Decreasing order of frequency) |
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Answer» Increasing order of wave length > Cosmic rays > Gamma rays < X-rays < U.V. rays < Visible rays < IR rays < Microwave rays < Radio waves (i.e, decreasing order of frequency). |
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| 22. |
Explain the wave nature of light. |
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Answer» Wave nature of light: According to Newton, light is a stream of particles which are also known as corpuscles of light. This could not account for the phenomena of interference and deflection (as Rutherford’s model) but justified reflection and refraction. Hygen suggested in his wave theory that the fight travels in the form of waves, later James Maxwell proposed that fight and other radiations are transmitted, these waves are associated with oscillating electric and magnetic field. |
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| 23. |
Atomic radius is measured inA) m B) mmC) km D) pm |
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Answer» Correct option is D) pm |
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| 24. |
Deduce the de-Broglies matter wave equation. |
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Answer» Dual nature of electron – de Broglie's matter-wave equation According to Einstein’s mass-energy relation, E = mc2 … (1) Where m and c are the mass and velocity of an electron respectively. According to quantum theory, Energy E = hv = (he) / λ … (2) Where h is Plank’s constant = 6.626 × 10-34 Js, u is the frequency of moving electron. Comparing(1) and (2) me2 = (hc)/λ >me = h/λ > = λ = h /me … (3) Equation (3) is called de-Broglie’s equation. For an electron its velocity is given as V, So the de-Broglie’s equation for an electron is given by, λ = h / mv (mv = p = momentum of electron) λ = h / p is called de-Broglie’s matter – wave equation |
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| 25. |
Explain de Broglie’s equation. |
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Answer» de Broglie’s equation :
[Note : According to de Broglie’s equation, the wavelength of a moving particle is inversely proportional to its mass. Therefore, heavier particles have much smaller wavelength than lighter particles like electrons.] |
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| 26. |
Write the de Broglie’s equation. |
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Answer» λ = h/mV where λ – wavelength of wave, h = Plank’s constant, m = mass of the electron, V – velocity of the electron. |
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| 27. |
What are the basic requirements are to be present when a fuel undergoes combustion? |
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Answer» In order that a fuel undergoes combustion, three basic requirements are to be present • A combustible substance: All carbon compounds are combustible, but carbon as diamond is not. Petrol is a combustible substance. • A supporter of combustion: Atmospheric air or oxygen gas is a supporter of combustion. In their absence, combustion will not be supported. Carbon dioxide or nitrogen gases do not support combustion. • Heating to ignition temperature: A minimum amount of temperature or heat is required to enable a fuel to catch fire. Coal has a high ignition temperature; a matchstick cannot produce enough heat to ignite it. However, a matchstick can ignite paper or LPG gas as it has low ignition temperature. |
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| 28. |
What is mean life of nucleus? Give the expression. |
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Answer» The mean life time of the nucleus is the ratio of sum or integration of life times of all nuclei to the total number nuclei present initially. The expression for mean life time, \(\tau =\frac{1}{λ}\). |
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| 29. |
What is binding energy of a nucleus? Give its expression. |
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Answer» when Z protons and N neutrons combine to form a nucleus, mass equal to mass defect disappears and the corresponding energy is released. This is called the binding energy of the nucleus (BE) and is equal to (∆m) c2. BE = (Zmp + Nmn – M ) c2 |
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| 30. |
What is mass defect? |
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Answer» The mass of any nucleus is always less than the sum of the mass of its individual constituents. The difference in mass Am is called mass defect. ∆m = (Zmp + Nmn) – M. |
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| 31. |
Give the physical meaning of binding energy per nucleon. |
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Answer» The average binding energy per nucleon is the energy required to separate single nucleon from the particular nucleus. |
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| 32. |
What is Combustion? |
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Answer» Combustion Combustion means the burning of a substance. It is a process that is highly exothermic i.e., produces a lot of heat. The products of combustion of carbon and its compounds are heat energy, carbon dioxide and water (vapour). |
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| 33. |
Write the Chemical Properties of Carbon Compounds. |
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Answer» Chemical Properties of Carbon Compounds Most of the carbon-containing compounds associated with hydrogen i.e., hydrocarbons are fuels that produce heat on burning. Petroleum products like natural gas, petrol, diesel, kerosene, heavy oils etc., and in a larger sense, wood, biogas, charcoal and coke are all rich source of carbon compounds used as fuels. |
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| 34. |
Give the results of Rutherford alpha scattering experiment |
Answer»
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| 35. |
Write down the draw backs of Bohr atom model. |
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Answer» Limitations of Bohr atom model: The following are the drawbacks of Bohr atom model: 1. Bohr atom model is valid only for hydrogen atom or hydrogen like-atoms but not for complex atoms. 2. When the spectral lines are closely examined, individual lines of hydrogen spectrum is accompanied by a number of faint lines. These are often called fine structure. This is not explained by Bohr atom model. 3. Bohr atom model fails to explain the intensity variations in the spectral lines. 4. The distribution of electrons in atoms is not completely explained by Bohr atom model. |
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| 36. |
Define the ionization energy and ionization potential. |
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Answer» The ionization energy and ionization potential are: 1. Ionization energy: The minimum energy required to remove an electron from an atom in the ground state is known as binding energy or ionization energy. 2. Ionization potential: Ionization potential is defined as ionization energy per unit charge. |
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| 37. |
What is meant by excitation energy? |
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Answer» The energy required to excite an electron from lower energy state to any higher energy state is known as excitation energy. |
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| 38. |
The mass of a \(^7_3Li\) nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of \(^7_3Li\) nucleus is nearly(a) 46 MeV (b) 5.6 MeV (c) 3.9 MeV (d) 23 MeV |
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Answer» (b) 5.6 MeV If w = 1 u, C = 3 x 108 ms-1 then, E = 931 MeV 1 u = 931 Mev Binding energy = 0. 042 x 931 = 39. 10 MeV ∴ B.E 39.10 Binding energy per nucleon = \(\frac{B.E}{A}\) = \(\frac{39.10}{7}\) 5.58 = 5.6 MeV |
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| 39. |
Write the properties of cathode rays. |
Answer»
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| 40. |
Describe the following chemical properties of carbon compounds briefly and give one chemical reaction for each :(i) Combustion(ii) Addition(iii) Substitution(iv) Esterification(v) Oxidation |
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Answer» (i) Combustion: CH4+O2→ CO2+H2O+Energy+Light (ii) Addition CH2=CH2+H2+Ni →C2H6 (iii) Substitution CH4+Cl2+Sunlight → CH3Cl+HCl (iv) Esterification CH3COOH+C2H5OH+H+ →CH3COOC2H5+H2O (v) Oxidation C2H5OH+alk KMnO4 →CH3COOH. |
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| 41. |
The half-life period of a radioactive element A is same as the mean life time of another radioactive element B. Initially both have the same number of atoms. Then (a) A and B have the same decay rate initially (b) A and B decay at the same rate always (c) B will decay at faster rate than A (d) A will decay at faster rate than B. |
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Answer» (c) B will decay at faster rate than A (t 1/2)A = (t mean)B \(\frac{0.6931}{λ_A} = \frac{1}{λ_B}\) λA = 0.6931 λB λA < λB |
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| 42. |
What are cathode rays? |
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Answer» A cathode ray is a stream of electrons that are seen in vaccum tubes. It is called a “cathode ray” because the electrons are being emitted from the negative charged element in the vaccum tube called the cathode. |
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| 43. |
A radioactive nucleus (initial mass number A and atomic number Z) emits 2α and 2 positrons. The ratio of number of neutrons to that of proton in the final nucleus will be(a) \(\frac{A-Z-4}{Z-2}\)(b) \(\frac{A-Z-2}{Z-6}\)(c) \(\frac{A-Z-4}{Z-6}\)(d) \(\frac{A-Z-12}{Z-4}\) |
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Answer» (b) \(\frac{A-Z-2}{Z-6}\) |
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| 44. |
denotes the mass of the proton and Mn denotes mass of a neutron. A given nucleus of binding energy B, contains Z protons and N neutrons. The mass M (N, Z) of the nucleus is given by(where c is the speed of light)(a) M (N, Z) = NMn + ZMp – Bc2 (b) M (N, Z) = NMn + ZMp + Bc2 (c) M (N, Z) = NMn + ZMp – B / c2 (d) M (N, Z) = NMn + ZMp + B / c2 |
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Answer» (c) M (N, Z) = NMn + ZMp – B / c2 Binding energy, B = [ZMp + NMn – M (N, Z)] C2 M(N,Z) = ZMp + NMn - \(\frac{B}{C^2}\) |
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| 45. |
The process of conversion of starches and sugars to ethyl alcohol is called …………….. A) carbonisation B) esterification C) condensation D) fermentation |
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Answer» D) fermentation |
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| 46. |
In the banyan tree, the following is found (a) Prop roots (b) Stilt roots (c) Mycorrhiza root (d) Parasitic root |
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Answer» The answer is (a) Prop roots |
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| 47. |
2 – Methyl propane is also called A) Iso propaneB) n-butane C) n – propane D) Isobutane |
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Answer» D) Isobutane (D) Isobutane
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| 48. |
The isomeric pair is (a) ethane and propane (b) propane and butane (c) ethane and ethane (d) butane and 2-methyl propane |
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Answer» The isomeric pair is butane and 2-methyl propane. |
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| 49. |
Which one of the following resources cannot be shared? (a) printer (b) scanner (c) speakers (d) monitor |
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Answer» monitor resources cannot be shared. |
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| 50. |
In addition to some propane and ethane, LPG cylinders contain mainly two isomers of another alkane. Name the two isomers and write their condensed structural formulae. |
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Answer» n-butane and iso-butane. |
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