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(B)  CH₃C CH + (CH₃)₂C

1. Increasing order of nucelophilicity,

NH₃ < – OH^⊕ < CH₃O^⊖-

2. Higher electron density will increase the nucelophilicity.

3. Negatively charged species are almost always more nucelophiles than neutral species.

4. RO^⊖ has an alkyl group attached, allowing a greater amount of polarizability. This means oxygen’s lone pairs will be more readily available to reach in RO^⊖ than in OH^⊖ .

Hence CH₃O – is the better nucelophile for the nucleophilic substitution of alcohols. NH₃ cannot act as nucelophile for the nucleophilic substitution of alcohols.

Since egg shell is made of calcium carbonate. And we know that when calcium carbonate (CaCO₃) reacts with nitric acid (HNO₃) then carbon dioxide, calcium nitrate and water are formed. So same reaction happens when nitric acid is added to an eggshell. 

CaCO₃ + 2HNO₃→ Ca(NO₃)₂ + CO₂ + H₂O

(A)  CH₃CH₂C CNa + NH₃ 

(E)  CH₃CO₂H + CH₃ONa → CH₃CO₂Na 

 BF₃ is a Lewis acid.

According to Lewis theory, a base is a substance that can donate a lone pair of electrons

This species is a carbon-based Lewis acid CH₃

BF₃  is not a Lewis base

Addition reactions are characteristic of compounds with multiple   bonds

The four basic types of reactions are substitution, addition, elimination, rearrangement

C₄H₁₀ is not a Lewis acid

(B)  All Lewis acids contain hydrogen

(D)  CH₃NH₃ + and H₃O⁺ 

The process of bond-breaking where each fragment takes away one of the electrons from the bond is called homolysis.

(B)  Electron pair donor.

Heterolytic bond-breaking produces charged fragments/ions

(E)  HPO₄ ^-, H₂PO₄^-

 (C)  BF₃ + NH₃

According to Bronsted-Lowry theory, an acid is a substance that can  donate a proton

d) Parents’ property is inherited by their children

We know that AB || CD and t is a transversal

From the figure we know that ∠AEF and ∠EFD are alternate angles

So we get

∠AEF = ∠EFD

Dividing both the sides by 2 we get

(1/2) ∠AEF = (1/2) ∠EFD

So we get

∠PEF = ∠EFQ

The alternate interior angles are formed only when the transversal EF cuts both FQ and EP.

Therefore, it is proved that EP || FQ.

(d) supplementary

When the sum of the measures of two angles is 180^o, the angles are called supplementary angles.

x – 10^o + 190^o – x = 180^o

190^o – 10 = 180^o

180^o = 180^o

LHS = RHS

Correct option is  A) (∠D, ∠E)

Correct option is  D) 100°

1. ∠d, ∠f and ∠h coincide with part I. 

2. ∠c, ∠e and ∠g coincide with part II.

i. line a || line b and line l is a transversal. 

∴ m∠x = 105° …(i) [Corresponding angles]

ii. m∠y = m∠x … [Vertically opposite angles] 

∴ m∠y = 105° …[From (i)]

iii. m∠z + 105° = 180° …[Angles in a linear pair] 

∴ m∠z = 180°- 105°

∴ m∠z = 75° 

∴ m∠x = 105°, m∠y = 105°, m∠z = 75°

i. line p || line q and line l is a transversal. 

∴ m∠a + 80° = 180° …[Interior angles] 

∴ m∠a= 180° – 80° 

∴ m∠a= 100°

ii. line l || line m and line p is a transversal. 

∴ m∠c = 80° …(i) [Exterior alternate angles]

iii. line p || line q and line m is a transversal.

∴ m∠b = m∠c … [Corresponding angles]

m∠b = 80° …[From (i)]

∴ m∠a = 100°, m∠b = 80°, m∠c = 80°

Correct answer:

i. ∠w 

ii. ∠x 

iii. ∠y 

iv. ∠z 

v. ∠x 

vi. ∠r

1. ∠c and ∠e; ∠b and ∠h 

2. ∠a and ∠e; ∠b and ∠f; ∠c and ∠g; ∠d and ∠h 

3. ∠c and ∠h; ∠b and ∠e

i. line l|| line m and line p is a transversal. 

∴ m∠a = 78° …(i) [Corresponding angles] 

ii. line p || line q and line m is a transversal. 

∴ m∠d = m∠a …[Corresponding angles] 

∴ m∠d = 78° …(ii) [From (i)] 

iii. m∠b = m∠d …[Vertically opposite angles] 

∴ m∠b = 78° …[From (ii)] 

iv. line l|| line m and line q is a transversal. 

∴ m∠c + m∠d = 180° …[Interior angles] 

∴ m∠c + 78° = 180° … [From (ii)]

∴ m∠c =180° – 78° 

∴ m∠c = 102° 

∴ m∠a = 78°, m∠b = 78°, m∠c = 102°, m∠d = 78°

1. ∠d, ∠f and ∠h coincide with part I. 

2. ∠c, ∠e and ∠g coincide with part II.

i. line p || line q and line l is a transversal. 

∴ m∠a + 80° = 180° …[Interior angles] 

∴ m∠a= 180° – 80° 

∴ m∠a= 100° 

ii. line l || line m and line p is a transversal. 

∴ m∠c = 80° …(i) [Exterior alternate angles]

iii. line p || line q and line m is a transversal. 

∴ m∠b = m∠c … [Corresponding angles] 

m∠b = 80° …[From (i)] 

∴ m∠a = 100°, m∠b = 80°, m∠c = 80°

1. ∠c and ∠e; ∠b and ∠h 

2. ∠a and ∠e; ∠b and ∠f; ∠c and ∠g; ∠d and ∠h 

3. ∠c and ∠h; ∠b and ∠e

i. ∠w 

ii. ∠x 

iii. ∠y 

iv. ∠z 

v. ∠x 

vi. ∠r

Given, (fog)(x) = sin x² and (gof)(x) = sin² x

f(g(x)) = sin(x²) & g(f(x)) = (sin x)² ...(1)

Clearly, f(x) = sin x & g(x) = x² satisfies both conditions of (1)

So, f(x) = sin x and f(x) = x²

It is correct that a difference of 20 °C in temperature of water at two levels can be exploited to generate electricity. For this purpose, Ocean Thermal Energy Conversion (OTEC) power plants are used. To use this p1ant, a difference of 20°C or more between the temperature of surface waters and water at depths of 1000 meters is required. In one of Ocean Thermal Energy Conversion system, the warm surface water is used to boil low boiling liquid like ammonia, or a chlorofluorocarbon. The vapours of the liquid are then sent to move the turbines of generator. The cold water from the depths is used to cool the vapour escaped from the turbines and converted into liquid to be used again.

Use of renewable sources of energy-population control, Planting trees (afforestation)

Associated Value: The learners will be encouraged to play their role as a responsible citizen in the conservation of energy resources.

If in a fraction numerator is less than the denominator, then it is called a proper fraction. 

Proper fractions are \(\frac{3}{4},\) \(\frac{2}{3},\) \(\frac{1}{4},\) \(\frac{1}{3},\)

If in a fraction numerator is greater than the denominator, then it is called an improper fraction.

Improper fractions are \(\frac{6}{5},\) \(\frac{3}{2},\) \(\frac{4}{1},\) \(\frac{18}{13},\)

A combination of a whole number and a proper fraction is called a mixed fraction. 

Mixed fractions are \(1\frac{5}{7},\) \(11\frac{1}{2}\)

Correct option is  C) b/a

Circumference of a circle = 22 cm

That is, 2πr = 22

2 x 22/7 x r = 22

r = 7/2 cm

Area of quadrant of circle = 1/4 πr² = 1/4 x 22/7 x 7/2 x 7/2 = 77/8

Area of quadrant of circle is 77/8 cm²

Total area of rectangular park = 120 ×100 = 12000 m² 

Area of park excluding circular lawn = 8700 m² 

So,

Area of circular lawn = 1200 – 8700 = 3300 m² 

= πr² = 3300

r² = \(\frac{3300\times7}{22}\) = 1050 m

r = 32.40 m

Total area of the park = 120 x 100 = 12000

Area excluding the lawn = 12000 - πr^2 = 8700 (given)

So, πr^2 = 3300

\(\frac{22r^2}{7}\) = 3300

r^2 = 1050

So, r = root 1050

Hope it helps

Ask of any doubt

The correct answer is (C) 0.078

= 3578, 3758, 3785, 3587, 3857, 3875, 5378, 5387, 5837, 5873, 5738,5783,7358, 7385, 7538, 7583, 7835, 7853, 8357, 8375,8735,8753, 8537, 8573 

Numbers in ascending order are as follows : 

3578, 3587, 3758, 3785, 3857, 3875, 5378,5387, 5738, 5783, 5837, 5873, 7358, 7385,7538,7583, 7835, 7853, 8357, 8375, 8537, 8573, 8735, 8753 

Numbers in descending order are as follows : 

8753, 8735, 8573, 8537, 8375, 8357, 7853, 7835, 7583, 7538, 7385, 7358, 5873, 5837, 5783, 5738, 5387, 5378, 3375, 3857, 3785, 3758, 3587, 3578

3578 is the smallest number.

(i) The dimensions for a tin can with a rectangular base is

Length = 5cm

Breadth = 4cm

Height = 15cm

We know that

Volume of tin can = l × b × h

By substituting the values

Volume of tin can = 5 × 4 × 15

So we get

Volume of tin can = 300 cm³

(ii) The dimensions for cylinder with circular base

Diameter = 7cm

We know that radius = 7/2 = 3.5 cm

Height = 10cm

We know that

Volume of cylinder = πr²h

By substituting the values

Volume of cylinder = (22/7) × (3.5)² × 10

So we get

Volume of cylinder = 385 cm³

We know that the volume of plastic cylinder is greater than volume of tin can

So difference in volume = 385 – 300 = 85 cm³

Therefore, a plastic cylinder has greater capacity than a tin can by 85 cm³.

It is given that

Diameter of one pillar = 50cm = 0.5m

So the radius of one pillar = 0.5/2 = 0.25m

Height of one pillar = 4m

We know that

Lateral surface area of one pillar = 2 πrh

By substituting the values

Lateral surface area of one pillar = 2 × (22/7) × 0.25 × 4

So we get

Lateral surface area of one pillar = 6.285 m²

So the lateral surface area of 20 pillars = 20 × 6.285 = 125.714 m²

It is given that the cost of cleaning = ₹ 14 per m²

So the cost of cleaning 125.714 m² = ₹ (14 × 125.714)

We get

Cost of cleaning 125.714 m² = ₹ 1760

Therefore, the cost of cleaning 125.714 m² is ₹ 1760.

Even though GST will be collected by both central as well as state governments, but the taxpayer who is liable to be registered, has to make single application for online registration and to file only one return. GST computer system will automatically furnish the information of registration to central as well as state authorities. Any person who is presently registered with the state under VAT, will be issued GST registration automatically but before being issued registration number he will be issued the temporary registration number.

GST registration is based on Pan Card Number. GST registration number is of 15 digits. The structure of GSTIN will be as follows :

Registration work will be in the hands of the state governments and state GST departments will be doing the registration of tax payers.

Currents Status of Registered Persons : 

All the existing tax payers who are currently registered under VAT or Service Tax laws, the information about them will be passed by the GST common portal to the IT system of concerned state/central tax authorities and their GSTIN will will be generated. At present, some taxpayer are registered under Central Tax or State Tax or both. Now, under GST law, a person can be registered only under SGST. He may be exempled from single registration or separate registration for multiple businesses. NSDL and GSTN both will utilise the data of the registered person.

Those persons, who are not enrolled or whose complete data is not available with tax authorities, are informed through advertisement in newspaper so they can furnish their data to the department’s website within the specified time period. If the data is not submitted within the specified time period, his registration will be postponed till he furnishes the required data.

Registration of New Tax Payers : 

Every new person who wants to obtain registration, needs to apply for registration through GST Network Portal (GSTN). 

Following procedure needs to be followed for registration :

(1) To apply online for registration as per the rules and to enclose scanned copy of following documents :

1. Proof of constitution such as Partnership Deed in case of Partnership, Registration certificate in case of cooperative society MCA-21 in case of companies. 

2. Details and proof of place of business, like, municipal tax receipt, electricity bill copy, rent agreement, etc. 

3. Bank account details. 

4. Authorised signatory’s details. 

5. Photograph of Propreitor, Partners, Karta, MD, Managing Trustee, Person in charge in case other than the above category of person.

(2) GSTN system shall carry out preliminary verification of documents like CIN Number, PAN Number, etc. with various authorities through interportal connectivity.

(3) After preliminary verification, GSTN Portal shall carry forward such application to central/state authorities. If the details filed by the applicant are correct, registration certificate shall be granted, and if tax authorities refuse the registration, reason for refusal will be communicated to the concerned person by the state GST officer or central GST officer.

GST is a comprehensive tax levied on manufacture, sale and consumption of goods and services at a national level, under which no distinction is made between goods and services for levying the tax. Presently, tax system has 3 types of taxes excise duty, service tax and VAT. GST is a single tax replacing all the indirect taxes. But, the Constitution does not vest the power to the central or the state government to levy a single tax on goods and services. Therefore, India will adopt a dual GST, where the center and the states will simultaneously tax goods and services.

The GST replaces the following taxes : 

1. Central Excise Duty.

 2. Service Tax. 

3. Countervailing Duty. 

4. Special Countervailing Duty. 

5. Value Added Tax (VAT). 

6. Central Sales Tax (CST). 

7. Octroi. 

8. Entertainment Tax. 

9. Entry Tax. 

10. Purchase Tax. 

11. Luxury Tax. 

12. Advertisement Taxes.

 13. Taxes applicable on lotteries