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By referring to the mammoth’s extinction, the poet teaches that those who harm others suffer the same fate one day.

विशाल हाथी के लुप्त होने के संकेत द्वारा कवि यह सिखाना चाहता है कि वे लोग जो दूसरों को हानि पहुँचाते हैं एक दिन वे भी वैसा ही भुगतते हैं।

There is duality in Nature and creation. Brute, bloody and cruel tiger co-exists with the deer who is splendid, mild and serene. But the serene gets throttled and killed by the ferocious. The poet points to the process of dominance and destruction of the meek by the strong in the world.

प्रकृति और सृष्टि में दोहरापन है। निर्दयी, खूनी और क्रूर चीता सुन्दर, सौम्य ओर शान्त हिरन साथ-साथ हैं। लेकिन जो शान्त है उसका गला घोटा जाता है और जो खूखाँर है उसके द्वारा उसे मार दिया जाता है। कवि संसार में शक्तिशाली द्वारा कमजोर को दबाने और उसका बिनाश करने की प्रक्रिया की और संकेत करता है।

The poet has used in the poem the symbols of the deer and the tiger to refer to good and evil, life and death, innocence and cruelty. The poet teaches that the two opposites co-exist in nature and creation and are equally essential for the existence of life.

कवि ने कविता में हिरन और चीते के प्रतीकों का प्रयोग अच्छे और बुरे, जीवन और मरण, निर्दोषता और क्रूरता की ओर संकेत करने के लिये किया है। कवि यह सिखाता है कि प्रकृति और सृष्टि में ये दो विरोधी साथ-साथ रहते हैं और जीवन के अस्तित्व के लिये बराबर आश्वयक हैं।

The poet has made in the poem a reference to the mammoth which used to shake the plains of Asia once but is now extinct. The poet does so to teach that those who harm others are destroyed like the mammoth. The evil comes to an end while the good lives on.

कवि ने कविता में उस विशाल हाथी का जिक्र किया है जो कभी एशिया के मैदानों को हिला देता था लेकिन अब लुप्त हो चुका है। कवि ने ऐसा यह सिखाने के लिये किया है कि जो दूसरों को हानि पहुँचाते हैं विशाल हाथी के समान नष्ट हो जाते हैं। बुराई का अन्त होता है और अच्छाई चलती रहती है।

The poem “The Tiger and the Deer” teaches that those who harm others will be destroyed like the mammoth which shook the plains of Asia but is now extinct. The poet wants to say that the bloody will meet their end in blood while the mild shall remain appreciated till the end.

कविता “The Tiger and The Deer” यह सिखाती है कि वे लोग जो दूसरों को हानि पहुँचाते हैं उस विशाल हाथी के समान नष्ट हो जायेंगे जो कभी एशिया के मैदानों को झकझोरता था लेकिन अब लुप्त हो गया है। कवि कहना चाहता है कि खूनी लोगों का अन्त खून में ही होगा जबकि जो सौम्य हैं उनकी अन्त तक प्रशंसा होगी।

The tiger crouched and crept again and again slowly and noiselessly towards the deer. It crouched one last time and then made a sudden fatal leap for the deer which was drinking water from the pool unaware of the danger. The tiger killed the deer and tore him apart.

चीता’बार-बार झुका और रेंगकर धीरे-धीरे और बिना आवाज किये हिरन की ओर बढ़ा। वह एक आखिरी बार झुका और फिर इस हिरन पर अचानक घातक आक्रमण किया जो खतरे से अनजान तालाब से पानी पी रहा था। चीते ने हिरन को मार दिया और उसके चिथड़े कर डाले।

In the expression “Hardly daring to breathe”, the poet refers to the tiger moving stealthily towards the deer drinking water from the pool. The deer was unaware of the impending danger. There was perfect stillness. The tiger dared not breathe lest it should alert the deer and spoil it’s scheme.

इस अभिव्यक्ति ‘‘साँस लेने का भी सहास नहीं में कवि तालाब में पानी पीते हुये हिरन की तरह चुपचाप बढ़ते हुये चीते की ओर संकेत किया है। हिरन अति हुये खतरे से अनजान था। पूर्ण शान्ति थी। चीता साँस लेने का साहस भी नहीं कर पा रहा था कि कहीं हिरन को वह सचेत न कर दे और अपनी योजना को बिगाड़ दे।

The answer is (d) All of the above

A botanical garden or botanic garden is a garden dedicated to the collection, cultivation and display of a wide range of plants labeled with their botanical names. A botanical garden is a controlled and staffed institution for the maintenance of a living collection of plants under scientific management for purposes of education and research, together with such libraries, herbaria, laboratories, and museums as are essential to its particular undertakings.

The mounted specimens are sprayed with fungicides like 2% solution of mercuric chloride for preservation.

A herbarium (plural: herbaria) is a systematically arranged collection of’preserve (dried) plant specimens and associated data used for scientific study.

• Useful for accurate morphological and anatomical scientific research of plants.
• Useful for comparative and taxonomical studies of plants.
• Useful for classification and nomenclature of plants.

A class having one attribute is known as the class of the first order, class of the combination two attributes as class of the second order. The total number of observations is denoted by N. Here, N is frequency of zero order, because it has no attribute to indicate. 

(A), (B), (α), (β) are called frequencies of the first order, and (AB), (αB), (Aβ), (αβ) are called frequencies of the second order.

• The value of this coefficient lies between ±1 (i.e., – 1 < Q < 1). 
• If Q = +1 there is perfect positive association between the attributes. 
• If Q = -1 there is perfect negative association (perfect dissociation) between the attributes and, 
• If Q = zero the two attributes are independent.

Let x = 3k and y = k 

Then, \(\frac{x^3-y^3}{x^3+y^3}\) = \(\frac{(3k)^3-k^3}{(3k)^3+k^3}\) = \(\frac{27k^3-k^3}{27k^3+k^3}\) = \(\frac{26k^3}{28k^3}\) = \(\frac{13}{14}\) = 13 : 14.

S = { 1, 2, 3, ---- , 25} |S|= 25 

And E = { 2, 3, 5, 7, 11, 13, 17, 19, 23 } |E|= 9 

Hence P(E) = |E| / |S| = 9 / 25.

Let A = x, B = 2x and C = 3x

Given, \(\frac{x+2x+3x}{3}\) = 600 ⇒ 6x = 1800 ⇒ x = 300

∴ The numbers are A = 300, B = 600, C = 900 

New average = 105% of 600 = \(\frac{105}{100}\times600\) = 630 

New value of A = \(\frac{110}{100}\times300\) = 330 

New value of B = \(\frac{80}{100}\times600\) = 480 

Let new value of C = y

Then, \(\frac{330+480+y}{3}\) = 630 ⇒ 810 + y = 1890

⇒ y = 1080 ∴ Increase in C = 1080 – 900 = 180.

(a) 12 years

Let the man’s age = 4x years. 

Then, Wife’s age = 3x years 

Given, \(\frac{4x+9}{3x+4}=\frac97\)

⇒ 28x + 28 = 27x + 36 ⇒ x = 8 

∴ Man’s age = 32 years, wife’s age = 24 years

Suppose they were married x years ago.

Then, \(\frac{32-x}{24-x}=\frac53\)

⇒ 96 – 3x = 120 – 5x ⇒ 2x = 24 ⇒ x = 12

Correct answer is

(B) \(\frac{49}{50}\)

Let the third proportional to (x² – y²) and (x + y) be A. Then 

(x² – y²) : (x + y) : : (x + y) : A 

⇒ (x² – y²) x A = (x + y)² ⇒ A = \(\frac{(x+y)^2}{x^2-y^2}\)

⇒ A = \(\frac{(x+y)^2}{(x+y)(x-y)}\) = \(\frac{x+y}{x-y}.\)

Let the third proportional to 16 and 36 be x then 16:36:36:x 

⇒ 16*x=36×36 

∴ x=81. 

Correct answer is

(A) Rs. 1,200

Correct answer is

(B) \(\frac{x - y}{x + y}\)

Let monthly income of A is 3x and expenditure is 3x – 1000 and monthly income of B is 4x and 

Given \(\frac{3x - 1000}{4x - 1000}\) = \(\frac{1}{2}\)

6x – 2000 = 4x – 1000 

⇒ 2x = 2000 ⇒ x = 1000

∴ The monthly income of A = 3x = 3 × 1000 = 3000

∴ The monthly income of B is 3(500) = 1500.

Correct answer is

(B) 5 : 7

The photocurrent is directly proportional to the number of photoelectrons emitted per second. This implies that the number of photoelectrons emitted per second is directly proportional to the intensity of incident radiation. 

(D) varies directly with the intensity of radiation.

Given α_steel = 1.20 x 10^-5 K^-1 (coefficient of lin. exp. of steel)

T₁ = 27°C = 27 + 273 K = 300 K

Length at temperature, T₁K = l_T1 = 8.70 cm

Length at temperature, T₂K = l_T2 = 8.69 cm

Change in length = l_T2 - l_T1 = l_T1 α(T₂ - T₁)

⇒ 8.69 - 8.70 = 8.70 x (1.20 x 10^-5) x (T₂ - 300)

⇒ T₂ - 300 = {0.01}/{8.70 x 1.2 x 10⁵} = -95.8

T₂ = 300 - 95.8 = 204.2 K

= -68.8°C

For first stone,

x(0) = 200 m, v(0) = 15 ms^-1

a = -10 ms-2

x₁(t) = x(0) + v(0)t +1/2 at²

x₁(t) = 200 + 15t - 5t²

When the first stone hits the ground, x1 (t) = 0

or, -5t² +15 t² + 200 = 0

On simplification, we get t = 8s.

For second stone, x(0) = 200 m, v(0) = 30 ms^-1,

a= -10 ms^-2

x₂(t) = 200 +30t -5t²

When this stone hits the ground x₂ (t) = 0

or, -5t² + 30t +200 = 0

Relative position of second stone w.r.t, first is given by

x₂(t) -x₁(t) = 15t.

Since, there is a linear relationship between x₂(t) x₁ (t) and t, the graph is a straight line.

For maximum separation, t = 8t

so. maximum separation is 120 m.

After 8 second, only the second stone would be in motion. so, the graph is in accordance with the quadratic equation.

Alkali metals like Li, Na, K, caesium and rubidium. 

Wilhelm Hallwachs and Philipp Lenard 

Zinc, cadmium, magnesium etc. 

Here, L = diameter of hole = 4.24 cm

ΔT = 227 - 27 = 200°C

and α = 1.70 x 10^-5°C^-1

∴ Change in diameter, ΔL = α x ΔT x L

= 1.70 x 10^-5 x 4.24 x 200

= 1.44 x 10^-2 cm

P₁ = Atmospheric pressure = 75 × ƒg
V₁ = 100 × A
P₂ = Atmospheric pressure + Mercury pessue = 75ƒg + hgƒg (if h = height of mercury)
V₂ = (100 – h) A
P₁V₁ = P₂V₂
=>75ƒg(100A) = (75 + h)ƒg(100 – h)A
=> 75 × 100 = (74 + h) (100 – h) => 7500 = 7500 – 75 h + 100 h – h₂
=> h₂ – 25 h => 0 => h₂ = 25 h => h = 25 cm

Height of mercury that can be poured = 25 cm​

Answer is (C) 20,000

The average K.E per molecule \(\overline {KE}\) = ε = \(\frac{3}{2} kT\)

The equation implies that the temperature of a gas is a measure of the average translational K.E. per molecule of the gas.

Moon has no atmosphere. The escape speed of gases on the surface of Moon is much less than the root mean square speeds of gases due to low gravity. Due to this all the gases escape from the surface of the Moon.

(b) high pressure and low temperature

The farmer told his wife that she needn’t be afraid as the mongoose as it was a friendly animal. It was as sweet as their baby and they were the best of friends.

Within five to six month the mongoose grown into full size but the baby was still a kid.The farmer’s wife was afraid of the mongoose may harm her child and so she didn’t want to leave her baby alone with the mongoose.

Mohair : The wool derived from Angora goat.

The farmer brought a baby mongoose into his house because they needed a pet so that their son had a companion when he grew up. The baby mongoose would be a friend to their son in the future.

This episode describes the silly behaviour of a rich woman who is foolishly indulgent. This may be because of her loneliness. They are ignorant about results of their actions. They show their excessive love and affection for someone without knowing the consequences. There is no doubt that their intentions are good, and don’t have any sort of ill will, but they are not aware their action can cause harm to others.

The process of removal of shrinkage from silk clothes is called Rolling.

(c) velocity

Correct Answer is: (c) Samudragupta

(D) A 200 g weight after falling through one kilometre.

Correct option is: (A) move in direction of motion of lighter mass.

It is the ratio of refractive index of second medium to refractive index of first medium.

Relative refractive index (n₂₁) = \(\frac{Refractive\, index\, of\, second\, medium (n_2)}{Refractive\, index\, of\, first\, medium (n_1)}\)