This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the acute angle between the straight line x/1 = y/3 = z/0 and plane 2x + y = 5. |
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Answer» Given equation x/1 = y/3 = z/0 and plane eq. 2x + y = 5 line (x - x1)/l = (y - y1)/m = (z - z1)/n plane ax + by + cz + d = 0 here angle of them sin = (al + bm + cn)/√(a2 + b2 + c2) √(l2 + m2 + n2) Here, l = 1, m = 3, n = 0 a = 2, b = 1, c = 0 then, sin θ = (2 x 1 + 3 x 1 + 0 x 0)/√(22 + 12 + 02) x √(12 + 32) sin θ = (2 + 3 + 0)/√(4 + 1) √(1 + 9) sin θ = 5/(√5 x √10) sin θ = 5/√50 sin θ = 5/5√2 = 1√2 sin θ = sin π/4 θ = π/4 |
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| 2. |
If the straight line (x - 1)/k = (y - 2)/2 = (z - 3)/3 and (x - 2)/3 = (y - 3)/k = (z - 1)/2 intersect at a point, then find the value of integer k. |
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Answer» Given lines are (x - 1)/k = (y - 2)/2 = (z - 3)/3 = λ ...(i) and (x - 2)/3 = (y - 3)/k = (z - 1)/2 = μ ...(ii) Any point on line (i) is (kλ + 1,2λ + 2,3λ + 3) and any point on line (ii) (3μ + 2,μk + 3,2μ + 1) If these line interest, these points must coincide for some value of and . So, λk + 1 = 3μ + 2, 2λ + 2 = μk + 3, 3λ + 3 = 2μ + 1 λk - 3λ - 1 = 0, 2λ - μk - 1 = 0, 3λ - 2μ + 2 = 0 taking first two, we get λ/(3 - k) = μ/(-2 + k) = 1/(-k2 + 6) λ = (3 - k)/(6 - k2), μ = (k - 2)/(6 - k2) Putting these value of λ & μ in 3λ - 2μ + 2 = 0 3(3 - k)/(6 - k2) - 2(k - 2)/(6 - k2) + 2 = 0 9 - 3k - 2k + 4 + 12 - 2k2 = 0 2k2 + 5k - 25 = 0 2k(k + 5) - 5(k + 5) = 0 (2k - 5)(k - 5) = 0 k = 5/2, -5 k = -5 satisfy both the equation. Hence, k = - 5 is require value. |
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| 3. |
If tan-1 1/2 + tan-1 2/11 = tan-1 'a', then value of 'a' will be (a) 1/4(b) 1/2(c) 3/4(d) 1 |
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Answer» Answer is (c) 3/4 |
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| 4. |
sin(tan-1 x), (|x| < 1) = (a) x/√(1 - x2)(b) 1/√(1 - x2)(c) 1/√(1 + x2)(d) x/√(1 + x2) |
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Answer» Answer is (d) x/√(1 + x2) |
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| 5. |
A path length t in a glass plate of refractive index n is equivalent to..........path length in vacuum. A) (n-1) t B) nt C) (n/t-1) D) All of these |
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Answer» The correct option is B) nt. A path length t in a glass plate of refractive index n is equivalent to nt path length in vacuum. |
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| 6. |
Deviation of a thin prism of refractive index n and angle of prism A is - a) (1-n) A b) (n-1) A c) (n+1) A d) (1+n) A2 |
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Answer» The correct option is C) (n+1) A. The thin prism of refractive index n and angle of prism A is (n+1) A. |
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| 7. |
Light owes its colour to its A) Frequency B) Velocity C) Phase D) Amplitude |
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Answer» The correct option is A) Frequency. Of course, it is frequency that specifies the color of light or spectral radiation. For example, you can make the red light have the same wavelength as green light by passing red light through glass or air. |
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| 8. |
Which one of the following has maximum refractive (index)? A) Glass B) Water C) Iron D) Diamond |
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Answer» The correct option is D) Diamond. Diamond has a very high refractive index (about 2.42 compared to about 1.5 for glass). Diamonds are cut so that a light ray falling on the diamond is reflected multiple times inside the diamond and therefore sends light out in all direct. |
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| 9. |
A convex lens n = 1.5 is immersed in water n = 1.33 then it will behave as a A) Conversing lens B) Diverging lens C) Prism D) Concave lens |
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Answer» The correct option is A) Conversing lens. A convex lens n = 1.5 is immersed in water n = 1.33 then it will behave as a Conversing lens. |
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| 10. |
The relationship between de Broglie’s wavelength and momentum is A) λ = h + p B) λ = h/pC) λ = h x p2 D) λ = p/h |
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Answer» The correct option is (B) λ = h/p. The relationship between momentum and wavelength for matter waves is given by p = h/λ, and the relationship energy and frequency is E = hf. The wavelength λ = h/p is called the de Broglie wavelength, and the relations λ = h/p and f = E/h are called the de Broglie relations. |
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| 11. |
State the principle of homogeneity of dimensions? |
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Answer» It states that the dimensions of each term on both sides of an equation are same. |
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| 12. |
State the principle of homogeneity of dimensions. |
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Answer» The principle of homogeneity of dimensions states that the dimensional formula of all the terms in an equation must be the same. |
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| 13. |
State the Principle of homogeneity of dimensions. |
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Answer» This principle states that a physical equation will dimensionally correct if the dimensions of all the terms occurring on both sides of the equation are the same. |
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| 14. |
State "Principle of homogeneity". |
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Answer» According to this principle, the dimensions of the fundamental quantities of two sides of a physical relation must be the same. |
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| 15. |
When does a cyclist appear to be stationary with respect to another moving cyclist? |
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Answer» When both the cyclists are moving with equal velocities. That is, they move with equal speeds in the same direction. |
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| 16. |
1 stat -coulomb = ......... coulombA) 3 x 109B) 3 x 10-9C) 1/3 x 109D) 1/3 x 10-9 |
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Answer» Correct Answer is: B) 3 x 10-9 The stat coulomb is the unit of electric charge quantity in the cgs (centimetre/gram/second) system. It is approximately equal to the charge contained in 2.082 x 10⁹ electrons. When two objects, carrying like electrical charges of 1 stat coulomb each, are placed so their charge centers are one centimetre (1 cm) apart, the objects repel each other with a force of one dyne (1 dyne). |
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| 17. |
Diode is used as:A) An amplifierB) An oscillatorC) A modulatorD) A rectifier |
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Answer» Correct Answer is: D) A rectifier Diode is a device which allows passing a current only when it is forward biased. That's why if we use one alternating voltage source instead of a battery during the negative cycles the diode will be reverse biased and will not allow the current to flow. Hence it can be used as a rectifier. |
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| 18. |
The unit of ratio of magnetic field B and electric field E isA) ms-1B) sm-1C) msD) s-2 |
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Answer» Correct Answer is: B) sm-1 We know that unit of electric field is: Newton per coulomb or volt per meter…… (i) And for magnetic field: tesla which is equal to: Newton second per coulomb meter... (ii) Equation (ii) divided by eq (i): Ratio inverse of meter per second. |
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| 19. |
The energy of emitted photon electron depends uponA) Alpha particleB) Beta particleC) Photon D) Proton |
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Answer» Correct Answer is: C) Photon The energy in a hydrogen atom depends on the energy of the electron. When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level. |
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| 20. |
In producing a pure spectrum, the incident light is passed through a narrow slit placed in the focal plane of an achromatic lens because a narrow slit(a) produces less diffraction(b) increases intensity(c) allows only one colour at a time(d) allows a more parallel beam when it passes through the lens. |
| Answer» (d) allows a more parallel beam when it passes through the lens. | |
| 21. |
A convex lens is made of five different materials as shown in the figure. How many images does it form? Why? |
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Answer» The given convex lens is made up of five different materials. So they have different refractive indices / different focal lengths. Hence they form five different images. If a convex lens is made of five different materials then the lens will have five different refractive indices or different focal lengths. So, the lens will form five different images, one image each for every refractive. |
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| 22. |
Name one compound which is decomposed into hydrogen and oxygen by using the chemical effect of electric current. |
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Answer» Water is one compound which is decomposed into hydrogen and oxygen by using the chemical effect of electric current. |
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| 23. |
Name one chemical compound which is produced by using the chemical effect of electric current. |
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Answer» Copper sulphate is one chemical compound which is produced by using the chemical effect of electric current. |
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| 24. |
Name two metals which are purified by using the chemical effect of current (or electrolysis). |
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Answer» Copper and Gold are purified by using the chemical effect of current (or electrolysis). |
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| 25. |
Name two metals which are produced (or extracted) by using the chemical effect of electric current. |
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Answer» Carbon and hydrogen are extracted by using the chemical effect of electric current. |
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| 26. |
Which of the following metals are produced by the electrolysis of their molten compounds? A) Copper B) Silver C) Aluminium D) Sodium A. A and B B. Band C C. C and D D. only D |
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Answer» C. C and D Both Aluminum and Sodium metals are produced by the electrolysis of their molten compounds because they are not freely available. They need to be extracted from their sources. |
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| 27. |
What type of image is always made by a concave lens ? |
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Answer» Virtual type of image |
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| 28. |
In some seeds the nucellus may be persistent. Such nucellus is called ....a) Endosperm b) Scutellum c) Plumule d) Perisperm |
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Answer» d) Perisperm |
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| 29. |
Why do earthquakes originate in the Atlantic Ridge belt? |
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Answer» Formation of convergent faults, deviation of plates and vulcanicity are the major reasons for evolution of earthquakes in the Atlantic Ridge belt. |
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| 30. |
Which instrument is used to record the intensity of earthquakes? |
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Answer» Intensity of earthquakes is measured on the Richter scale. It contains numbers from 0 to 9. |
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| 31. |
Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3 (s) + 2HCl (aq) → CaCl2 (aq) + CO2 (g) + H2O (l). What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl ? |
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Answer» 1000 mL of.0.75 M HCl have 0.75 mol of HCl = 0.75 x 36.5 g = 24.375 g |
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| 32. |
Hydrochloric acid is 38% by mass. If the density of solution is 1.19 gm cm3, then what will be the molarity of solution? |
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Answer» 38% by mass = 38 g HCl in 100 g solution |
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| 33. |
In laboratory preparation of chlorine, manganese dioxide (MnO2) reacts with aqueous hydrochloric acid according to the reaction:4HCl (aq) + MnO2 (s) → 2H2O(l) + MnCl2 (aq) + Cl2 (g)How many grams of HCl react with 5.0 g of manganese dioxide? |
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Answer» 1 mol of MnO2 = (Atomic mass of Mn + 2 x atomic mass of oxygen) |
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| 34. |
Write balanced equations for reactions between Na2O2 and water. |
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Answer» Na2O2+2H2O → 2NaOH + H2O2 |
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| 35. |
Write balanced equations for reactions between KO2 and water. |
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Answer» 2 KO2+2H2O→ 2KOH + H2O2+O2 |
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| 36. |
Name the chief factor responsible for the anomalous behavior of lithium. |
| Answer» High polarizing power (charge/size ratio). | |
| 37. |
In fire works red colour flash is produced by ……(a) Ba(b) Ra (c) Sr (d) Rb |
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Answer» Answer: (c) Sr |
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| 38. |
The most common oxidation state of alkaline earth metals is ………(a) +4 (b) +2 (c) + 1 (d) +3 |
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Answer» Answer: (b) +2 |
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| 39. |
Consider the following statements. (i) Beryllium has small size and high polarizing power. (ii) Beryllium does not have d-orbitais in its valence shell. (iii) Beryllium has low electronegativity and very low ionization enthalpy as compared to other alkaline earth metals. Which of the above statements is/are not correct? (a) (i) only (b) (ii) only (c) (iii) only (d) (i) and (ii) |
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Answer» (c) (iii) only |
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| 40. |
Derive the ideal gas equation. |
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Answer» According to Boyle’s law, V ∝ \(\frac{1}{P}\) (at constant T and n) ………..(1) According to Charles’ law, V ∝ T (at constant P and n) …….(2) According to Avogadro’s law, V ∝ n (at constant P and T) …….(3) Combining relations (1), (2) and (3), we get V ∝ \(\frac{nT}P\) Converting this proportionality into an equation by introducing a constant of proportionality (‘R’ known as gas constant), we get ∴ V = \(\frac{nRT}P\) On rearranging the above equation, we get PV = nRT where, P = Pressure of gas, V = Volume of gas, n = number of moles of gas, R = Gas constant, T = Absolute temperature of gas. This is the ideal gas equation or equation of state. [Note: In the ideal gas equation, R is called gas constant or universal gas constant, whose value is same for all the gases. In this equation, if three variables are known, fourth can be calculated. The equation describes the state of an ideal gas. Hence, it is also called as equation of state.] |
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| 41. |
Which of the following expression at constant pressure represents Charles’s law? (A) V ∝ \(\frac{1}{T}\)(B) V ∝ \(\frac{1}{T^2}\)(C) V ∝ T(D) V ∝ d |
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Answer» Correct option is: (C) V ∝ T Charles's law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure V ∝ T Correct option is (C) V ∝ T |
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| 42. |
At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen at 4 bar. The molar mass of gaseous molecule is ……………. (A) 28 g mol-1(B) 56 g mol-1 (C) 112 g mol-1(D) 224 g mol-1 |
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Answer» Correct option is: (C) 112 g mol-1 PV = nRT = PV = \(\frac WM RT\) = PM = \(\frac WV RT\) = PM = \(\rho\)RT ....(i) Let say density of \(N_2\) at 4 bat = \(\rho\) then the density of unknown gas at 2 atm = 2\(\rho\) Using equation (i) For \(N_2\) gas 4 \(\times\) 28 = \(\rho\) \(\times\) R \(\times\) 300 ...(ii) for unknown gas 2 \(\times\) M = 2e \(\times\) R \(\times\) 300 ....(iii) iii ÷ ii, we got \(\frac {2M}{4\times28} = \frac {2\rho\times R\times300}{\rho\times r\times 300}\) M = \(\frac {2 \times 4\times 28}{2}\) M = 112 g/mol (C) 112 g mol-1 |
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| 43. |
The pressure of 2 mole of ideal gas at 546 K having volume 44.8 L is ……………. (A) 2 atm (B) 3 atm (C) 7 atm (D) 1 atm 1023 |
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Answer» Correct option is : (A) 2 atm Using ideal gas equation PV = nRT P = \(\frac {2\times0.082\times546}{44.8}\) = 2 atm Correct option is (A) 2 atm |
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| 44. |
If the volume of two moles of an ideal gas is at 546 K, then its pressure will be :(a) 2 atm(b) 1 atm(c) 4 atm(d) 3 atm |
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Answer» The answer is (a) 2 atm |
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| 45. |
What should we know in order to measure a physical quantity? |
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Answer» Its unit and the number of times the unit is contained in the physical quantity. |
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| 46. |
Is light year a unit of time? |
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Answer» No, it is a unit of distance. |
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| 47. |
Define one light year. |
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Answer» One light year is defined as the distance traveled by light in one year. 1 light year = 9.46 x 1015 m. |
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| 48. |
Give appropriate ratio of 1 A.U. and 1 light year. |
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Answer» 1 light year = 9.46 x 1015 m Hence 1 A.U./1 L.Y. = (1.496 x 1011/9.46 x 1015) = 10-5. |
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| 49. |
Define a metre. |
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Answer» The metre is the length of the path travelled by light in vacuum during a time interval of 1/299, 792, 458 of a second. |
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| 50. |
Calculate the number of light years in one metre. |
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Answer» 1 light year = 3 x 108 ms-1 x (365 x 24 x 60 x 60 ) s = 9.46 x 1015 m Thus 1 m = 1/(9.46 x 1015)1.y. = 1.057 x 10-16 light year. |
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