This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The solution of LPP, maximize z = 3x + 2y, x + 2y ≤ 0; 3x + y ≤ 15; x,y ≥ 0 lies in which quadrant.(a) first(b) second(c) third(d) fourth |
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Answer» Answer is (a) first |
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| 2. |
The Probabilities of solving a problem by three students are 1/2,1/3,1/4. Find the probability that the problem will be solved. |
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Answer» From the equation, P(E1) = 1/2, P(E2) = 1/3, P(E3) = 1/4 P(bar E1) = 1/2, P(bar E2) = 2/3, P(bar E3) = 3/4 ∴ P (not solving the Problem) = 1/2 x 2/3 x 3/4 = 1/4 P (solving the Problem) = 1 - (1/4) = 3/4 |
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| 3. |
Explain the similarities and differences of centripetal and centrifugal forces. |
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Answer» Salient features of centripetal and centrifugal forces. Centripetal Force:
\(|\vec F_{CP}|\) = mω2r = \(\frac{mv^2}{r}\)
Centrifugal Force:
\(|\vec I_{Cf}|\) = mω2 r = \(\frac{mv^2}{r}\)
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| 4. |
S.I unit of momentum is ………………A) kg.m/s2 B) kg-m/s C) N.Sec D) Both B & C |
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Answer» D) Both B & C |
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| 5. |
Give an example of a non-renewable resource that is non- recyclable also. |
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Answer» A non-renewable resource is a finite resource. It cannot renew itself completely, making it a valuable and limited in quantity. An example of a renewable resource is coal. Coal is a fossil fuel which is derived from the remains of plants and animals that lie buried in the earth. It takes billions of years to form naturally, so it is considered to be a non-renewable resource. |
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| 6. |
Observe the figure and answer the questions1. What will be the effect on the velocity of the motorcycle if its speed increases or decreases, but its direction remains unchanged?2. In case of a turning on the road, will the velocity and speed be same?3. If, on a turning, we change the direction as well as the speed of the motorcycle, what will be the effect on its velocity? |
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Answer» 1. If the speed is increased the velocity of the motorcycle will increase and if the speed is decreased the velocity of the motorcycle will decrease. 2. As speed is scalar quantity while velocity is vector quantity so by turning velocity will change while speed remains same. 3. Its velocity will change because velocity depends on speed as well as direction and here both speed and direction are changed. |
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| 7. |
If a person moving from pole to equator, the centrifugal force acting on him – (a) increases (b) decreases (c) remains the same (d) increases and then decreases |
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Answer» (a) increases |
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| 8. |
Acceleration increases with increase of ……………. A) mass B) pressure C) volume D) net force |
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Answer» D) net force |
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| 9. |
Acceleration decreases with increases of ……………A) mass B) volume C) density D) pressure |
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Answer» Correct option is A) mass |
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| 10. |
The unit of force is …………… A) Newton B) N.S C) N/s D) N.m |
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Answer» Correct option is A) Newton |
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| 11. |
1 kg. m/s2 = A) 1 Dyne B) 1 Hertz C) 1 Newton D) 1 Volt |
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Answer» Correct option is C) 1 Newton |
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| 12. |
……………. is the unit of force. (a) Both B and C (b) Newton (c) Dyne (d) Volts |
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Answer» Correct option is: (a) Both B and C |
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| 13. |
By stretching the rubber strings of a we store ………………. energy in it.(a) Potential (b) Chemical (c) Electric (d) Kinetic |
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Answer» Correct option is: (a) potential |
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| 14. |
Flowing water has ……… energy. (a) Potential (b) Chemical (c) Solar (d) Kinetic |
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Answer» Correct option is: (d) kinetic |
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| 15. |
Write the value of tan-1{2 sin(2 cos-1 \(\frac{\sqrt3}2\))}. |
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Answer» Given tan-1 {2 sin (2 cos-1 √3/2)} = tan-1 {2 sin (2 cos-1 cos π/6)} = tan-1 {2 sin (2 × π/6)} = tan-1 {2 sin (π/3)} = tan-1 {2 × √3/2} = tan-1 {√3} = π/3 ∴ tan-1 {2 sin (2 cos-1 √3/2)} = π/3 |
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| 16. |
Write the value of\(tan^{-1}\{2sin(2cos^{-1}\frac{\sqrt{3}}{2})\}\) |
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Answer» Given tan-1 {2 sin (2 cos-1 √3/2)} = tan-1 {2 sin (2 cos-1 cos π/6)} = tan-1 {2 sin (2 × π/6)} = tan-1 {2 sin (π/3)} = tan-1 {2 × √3/2} = tan-1 {√3} = π/3 ∴ tan-1 {2 sin (2 cos-1 √3/2)} = π/3 |
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| 17. |
Write the value of\(tan(2tan^{-1}\frac{1}{5})\). |
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Answer» Let tan θ = 1/5 Given tan (2 tan-1 1/5) = tan 2θ We know that \(tan2\theta=\frac{2tan\theta}{1-tan^2\theta}\) \(=\frac{2\times\frac{1}{5}}{1-\frac{1}{25}}\) \(=\frac{\frac{2}{5}}{\frac{24}{25}}\) \(=\therefore tan(2tan^{-1}\frac{1}{5})=\frac{5}{12}\) |
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| 18. |
For the principal values, evaluate each of the following:\(sin^{-1}(-\frac{\sqrt3}2)+cos^{-1}(\frac{\sqrt3}2)\) |
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Answer» \(sin^{-1}(-\frac{\sqrt3}2)+cos^{-1}(\frac{\sqrt3}2)\) \(=-\frac{\pi}3+\frac{\pi}6\) {Since sin-1x = An angle in\([-\frac{\pi}2,\frac{\pi}2]\) whose sine is x, Similarly, cos-1 = An angle in [0, π ] whose cosine is x} \(=-\frac{\pi}6\) Hence, \(sin^{-1}(-\frac{\sqrt3}2)+cos^{-1}(\frac{\sqrt3}2)\) = \(-\frac{\pi}6\) \(\therefore\) Principal value of \(sin^{-1}(-\frac{\sqrt3}2)+cos^{-1}(\frac{\sqrt3}2)\) is \(-\frac{\pi}6\) |
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| 19. |
Write the principal value of\(tan^{-1}(1)+cos^{-1}(-\frac{1}{2})\). |
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Answer» Given tan-1(1) + cos-1 (-1/2) We know that cos-1 (-θ) = π – cos-1 θ \(=\frac{\pi}{4}+[\pi-\frac{\pi}{3}]\) \(=\frac{\pi}{4}+\frac{2\pi}{3}\) \(=\frac{3\pi+8\pi}{12}\) \(=\frac{11\pi}{12}\) \(\therefore tan^{-1}(1)+cos^{-1}(-\frac{1}{2})=\frac{11\pi}{12}\) |
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| 20. |
Find the principal value of the following :\(\tan^{-1}1+\cos^{-1}\left(-\frac{1}{2}\right)+ \sin^{-1}\left(-\frac{1}{2}\right)\) |
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Answer» [Formula: cos -1(-x)=π – cos(x) and sin -1(-x)= -sin(x) ] \(\tan^{-1}1+\left(\pi-\cos^{-1}\left(\frac{1}{2}\right)\right)+\left(-\sin^{-1}\left(\frac{1}{2}\right)\right)\) Putting the values for each of the inverse trigonometric terms \(=\frac{\pi}{4}+\left(\pi-\frac{\pi}{3}\right)-\frac{\pi}{6}\) \(=\frac{\pi}{12}+\frac{2\pi}{3}\) \(=\frac{9\pi}{12}=\frac{3\pi}{4}\) |
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| 21. |
Find the principal value of the following :\(\cos^{-1}\frac{1}{2}+2\sin^{-1}\frac{1}{2}\) |
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Answer» Putting the values of the inverse trigonometric terms \(\frac{\pi}{3}+2\times \frac{\pi}{6}\) \(=\frac{\pi}{3}+\frac{\pi}{3}\) \(=\frac{2\pi}{3}\) |
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| 22. |
Evaluate: ∫x/(x2 + 1)(x + 1) dx |
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Answer» Let I = ∫x/(x2 + 1)(x + 1) dx Now, x/(x2 + 1)(x + 1) = (1/2)[(x + 1)/(x2 + 1) - (1/x + 1)] (partial function) So, I = (1/2)∫x/(x2 + 1) dx + ∫dx/(x2 + 1) - ∫dx/(x + 1) = (1/4) log(x2 + 1) + 1/2) tan-1 x - (1/2) log|x + 1| + k |
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| 23. |
Which reagent is used to convert ethylene glycol to ethylene?(a) HI (b) I2(c) PI3 (d) Conc. H2SO4 |
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Answer» PI3 is used to convert ethylene glycol to ethylene. |
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| 24. |
What is the product formed when ethylene glycol is heated at 773 K?(a) Ethanal (b) Ethene (c) Ethane (d) Oxirane |
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Answer» Oxirane is the product formed when ethylene glycol is heated at 773 K. |
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| 25. |
Name the product formed when ethan- 1, 2-diol is treated with anhydrous ZnCl2(a) Ethanol (b) Ethene (c) Ethane (d) Ethana |
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Answer» (d) Ethanal |
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| 26. |
Which reagent is used to convert ethan – 1, 2 – diol into Ethanal?(a) Anhydrous ZnCI2(b) Dilute. H2SO4 (c) Either (a) or (b) (d) Conc. H2SO4 |
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Answer» (c) Either (a) or (b) |
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| 27. |
Which one of the following is formed when ethan – 1, 2 – diol is treated with PI3 ? (a) Ethane (b) Ethyne (c) Ethene (d) Ethanol |
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Answer» Ethene is formed when ethan – 1, 2 – diol is treated with PI3 |
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| 28. |
Expenses of a business for the first year were Rs. 80,000. In the second year, it was increased to Rs. 88,000. What is the trend percentage in the second year? (a) 10% (b) 110%(c) 90% (d) 11% |
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Answer» The correct answer is : (b) 110 % |
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| 29. |
Given below is a diagram of two system together in the human body(a) Name the systems(b) Name the parts numbers 1-10(c) Describe the functions of the parts 3, 4, 5 & 6. |
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Answer» (a) Excretory system and Female Reproductive system (b) 1. Kidney 2. Ureter 3. Fallopian Tube 4.Infundibulum 5. Ovary 6. Uterus 7. Urinary Bladder 8.Cervix 9. Vagina 10. Valva (c) Function of Fallopian Tube (part 3): The fallopian tubes carry the ovum released from the ovary to the uterus. Function of Infundibulum (part 4): Infundibulum is the funnel shaped distal end of the ovary which picks up the released ovum and pushes it further on its passage into the fallopian tube. Function of Ovary (part 5): Ovary produces female gametes i.e. ova. Function of Uterus (part 6): Uterus allows the growth and development of the embryo. |
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| 30. |
Which part of the human body :(a) produces sperms ?(b) produces ova ?(c) passes Sperms from a man to a woman ? |
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Answer» (a) Testes. (b) Ovaries. (c) Penis. |
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| 31. |
A loan backed by collateral is called a: a. line of credit.b. dividend. c. secured loan. d. trade credit. |
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Answer» c. secured loan. |
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| 32. |
The most widely used source of short-term funding is: a. factoring. b. trade credit.c. family and friends. d. commercial banks. |
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Answer» d. commercial banks. |
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| 33. |
What is a commercial paper? What are its advantages and limitations? |
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Answer» Commercial paper is an unsecured promissory note issued by a firm to raise funds for a short period, varying from 90 days to 364 days. It is issued by one firm to other business firms, insurance companies, pension funds and banks. The amount raised by CP is generally very large. The CP can be issued only by firms having good credit rating as this debt is totally unsecured. Issue of CP is regulated by the Reserve Bank of India. Merits of Commercial Paper 1. A commercial paper does not contain any restrictive conditions as it is sold on an unsecured basis. 2. It has high liquidity as it is a freely transferable instrument. 3. It provides more funds compared to other source. 4. The cost of CP to the issuing firm is generally lower than the cost of commercial bank lo Answer: 5. A commercial paper provides a continuous source of fund because their maturity can be tailored to suit the requirements of the issuing firm. 6. Companies can invest their excess funds in commercial paper and can earn good return on them. Limitations of Commercial Paper 1. Only firms which are financially sound and have high credit ratings can raise money through commercial papers. New and moderately rated firms are not in a position to raise funds by this method as these are unsecured. 2. The amount of money that can be raised through commercial paper is limited. 3. Commercial paper is an impersonal method of financing and if a firm is not in a position to redeem its paper due to financial difficulties, extending the maturity of a CP is not possible. |
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| 34. |
A statement that projects management’s expectations for revenues and, based on those financial expectations, allocates the use of specific resources throughout the firm is called: a. a cash flow. b. a budget. c. a resource plan. d. a resource allocation. |
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Answer» b. a budget. |
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| 35. |
Debt capital refers to: a. money raised through the sale of shares. b. funds raised by borrowing that must be repaid. c. factoring accounts receivable. d. inventory loans. |
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Answer» b. funds raised by borrowing that must be repaid. |
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| 36. |
The most common cause (s) of financial problems are: a. under capitalization. b. inadequate expense control. c. credit terms. d. all of the above. |
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Answer» d. all of the above. |
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| 37. |
The steps in financial planning are:a. forecasting financial needs and developing budgets to meet those needs. b. identifying sources of financing. c. establishing financial controls to ensure the company is following the financial plans. d. A&C. |
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Answer» Correct Answer is: d. A&C. |
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| 38. |
(a) Give chemical tests to detect the presence of (i) Ethanol (ii) Ethanoic acid (b) Why ethanoic acid is called glacial acetic acid? |
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Answer» (a) Add sodium hydrogen carbonate. Ethanol will not react. Ethanoic acid will give brisk effervescence due to carbon dioxide. (b) Pure ethanoic acid exist as solid like glaciers at 291 K, therefore, called glacial acetic acid. |
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| 39. |
Na, Mg, Al and P belong to 3rd period but are placed in first, second, thirteenth and fifteenth group. Number of shells occupied in Mg is three. What is the number of occupied shells in Na, Al and P Give reasons for your answer. |
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Answer» It is three in Na, Al and P. Elements with the same number of occupied shells are placed in the same period |
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| 40. |
Distinguish between renewable and non-renewable sources of energy. Also give an example of each of these sources. |
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Answer»
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| 41. |
Distinguish between renewable and non-renewable sources of energy. |
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Answer»
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| 42. |
Explain debentures in detail. |
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Answer» Debentures:
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| 43. |
What is debenture? State its characteristics. |
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Answer» Debentures:
Characteristics:
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| 44. |
Who has the first right to receive dividend from company’s profit? |
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Answer» Preference share holders. |
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| 45. |
How retaining profit leads to evil of monopoly? |
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Answer» Encourages monopoly: When a company retains its profit too much it becomes economically quite strong. If can then dominate the market by over stocking very large amount of raw material, forcing vendors and suppliers to follow company’s policies, ask them to create artificial scarcity etc. and hence create monopoly. |
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| 46. |
Which forecast gives management some sense of the profit potential possible of different strategic plans? a. short-term forecast. b. cash flow forecast. c. long-term forecast. d. none of the above. |
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Answer» c. long-term forecast. |
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| 47. |
A budget is the plan of the various costs and expenses needed to operate the business, based on the short-term forecast.a. capital budget b. operating budget c. cash budget d. resource budget. |
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Answer» b. operating budget |
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| 48. |
Distinguish between Anamorph and Telomorph. |
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Answer» The asexual phase of fungi is called anamorph. The sexual phase of fungi is called telomorph. |
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| 49. |
What is plectenchyma? Mention its types. |
Answer»
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| 50. |
Give any two examples of chemicals that are added to denature the alcohol. |
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Answer» Methanol and acetone are added to denature the alcohol to prevent the misuse of alcohol. |
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