This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What are the operations performed on linear data structures? |
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Answer» The various operations performed on linear data structures are: 1. Traversal: 2. Insertion: 3. Deletion: 4. Searching: 5. Sorting: 6. Merging: |
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| 2. |
Name any two characteristics of impact printers. |
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Answer» The two characteristics of impact printers are 1. Print quality is low in some types 2. Uses ink ribbon to print 3. Less expensive |
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| 3. |
What are pre-increment and post-increment operators? Give examples. |
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Answer» The pre-increment operator is a unary operator and is used to increment the value of variable before using in the expression i.e. value is first incremented and then used in the expression. Example: Y = 5; cout<< ++Y; output: 6. The post-increment operators is also unary operator and is used to increment the value of variable after the use of expression. For example; Y=5; cout<< Y++; output: 5. |
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| 4. |
Mention any two benefits of OOP. |
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Answer» The two benefits of OOP are 1. Follow bottom-up approach in program design. 2. Functions and data are coupled together. Data encapsulation and inheritance are the two features of OOP. |
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| 5. |
Write an algorithm to insert an element into the array. |
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Answer» A is an array |
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| 6. |
Define object code and source code. |
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Answer» 1. Object code: The object code is usually a machine code which can be understood directly by a specific type of CPU. 2. Source code: The source code is any collection of computer instructions written using some human-readable computer language. |
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| 7. |
What is an algorithm? Name any two characteristics of an algorithm. |
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Answer» An algorithm is defined as “step by step procedure to solve a given problem infinite number of steps”. Characteristics of algorithm: 1. Every step should perform a single task 2. There should not be any confusion at any stage. 3. It must involve a finite number of steps. |
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| 8. |
Explain the advantages of OOP. |
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Answer» The advantages of OOP are: 1. OOP provides a clear modular structure for programs. Large problems can be reduced to smaller and more manageable problems. 2. In OOP, data can be made private to a class such that only member functions of the class can access the data. This principle of data hiding helps the programmer to build a secure program. 3. Implementation details are hidden from other modules and other modules has a clearly defined interface. 4. It is easy to maintain and modify existing code as new objects can be created with small differences to existing ones. 5. With the help of polymorphism, the same function or same operator can be used different purposes. This helps to manage software complexity easily. 6. In OOP, programmer not only defines data types but also deals with operations applied for data structures. 7. It is easy to model a real system as real objects are represented by programming objects in OOP. 8. With the help of inheritance, we can reuse the existing class to derive a new class such that the repetition of code is eliminated and the use of existing class is extended. This saves time and cost of program. |
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| 9. |
Mention any five applications of OOP. |
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Answer» Some of the real-life applications of object-oriented programming are given below:
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| 10. |
Write the syntax and example for WHILE loop. |
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Answer» Syntax of while loop: while (condition) { statement (s); } Example: #include <iostream> void main() { int a = 10; while (a<15) { cout<<"value of a:"<<a<<end1; a++; } } |
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| 11. |
Write any three features of windows operating system. |
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Answer» General Features of windows operating system are 1. Fast start up and shutdown 2. Plug and play support for hardware devices 3. Supports all major networking protocols 4. Automatic update |
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| 12. |
Mention any two advantages of OOP. |
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Answer» Some of the advantages of object oriented programming are as follows: – 1. A clear modular structure can be obtained which can be used as a prototype and it will not reveal the details of the de sign. 2. Ease of maintenance and modification to the existing objects can be done with ease. 3. A good framework is provided which facilitates in creating rich GUI applications. |
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| 13. |
Write a note on ASCII code. |
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| 14. |
Give the examples of saturated & unsaturated fats. |
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Answer» Ghee and vegetable oils respectively. |
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| 15. |
Explain the different types of ROM. |
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Answer» 1. PROM: PROM stands for Programmable Read Only Memory and is initially blank. The manufacturer can write data/program on it by using special devices. However, once the program or data is written in PROM chip, it cannot be changed. 2. EPROM: EPROM stands for Erasable Programmable Read Only Memory and is also initially blank. Unlike PROM, the data written in EPROM chip can be erased by using special devices and ultraviolet rays. 3. EEPROM: EEPROM stands for Electrically Erasable Programmable Read Only Memory. This kind of ROM can be written or changed with the help of electrical devices. So data stored in this type of ROM chip can be easily modified. |
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| 16. |
What is type casting? Give one example. |
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Answer» Typecasting is making a variable of one type, such as an int, act like another type, a char, for one single operation. Example: void main () { int a=5, b=2; float c; c = (float) a / b; } |
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| 17. |
Mention any four string functions. |
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Answer» The four string functions are strupr(), strlwr(), strcpy() and strrev(). |
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| 18. |
What is a mail merge? Write the steps for mail merge. |
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Answer» The mail merge helps to generate form letters by combining content of one document with content of address. In a situation where a letter is to be sent to address of many persons then mail merge is used. The steps for mail merge is as follows; Step 1. Create a main document and type the letter. Step 2. Select data source document. Step 3. Insert merge field in the main document. Step 4. Select Finish and merge button. |
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| 19. |
calculate energetics of complete oxidation of one molecule of glucose |
Answer»
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| 20. |
classification of lipids with examples |
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Answer» Classification of Lipids Nonsaponifiable lipids, and Saponifiable Lipids Each of these categories can be further broken down into non-polar and polar lipids. Nonpolar lipids, such as triglycerides, are used for energy storage and fuel. Polar lipids, which can form a barrier with an external water environment, are used in membranes. Polar lipids include glycerophospholipids and sphingolipids. Fatty acids are important components of all of these lipids. |
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| 21. |
You cannot modify your document contents once the mail merge wizard has been started (True/False) |
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Answer» Answer: False |
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| 22. |
An increased melting temperature of duplex DNA results from a high constant of |
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Answer» Answer: Cytosine + Guanine |
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| 23. |
enzymes involved in joining together two substances is |
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Answer» Answer: Glutamine synthetase |
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| 24. |
the PH optima of most of the enzymes is |
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Answer» Answer: Between 5 and 9 |
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| 25. |
Define Glomerular Filtration Rate(GFR) |
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Answer» Glomerular Filtration Rate (GFR). The amount of the filtrate formed by the kidneys per minute is called glomercular filtration rate (GFR). GFR in a healthy individual is approximately 125ml/minute, i.e., 180 filitres per day. On an average, 1100 -1200 ml of blood pumped out by each ventricle of the heart in a minute. |
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| 26. |
About 125ml of glomerular filtrate is produced per minute in our kidney. However 1ml of urine is produced each minute. What happens to the other 124ml of the filtrate. |
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Answer» In man about 125ml of glomerular filtrate is formed per minute. But most of the substances are reabsorbed into tubular network of capillaries. This process is known as selective reabsorption. High threshold substances reabsorbed by active transport and low threshold substances reabsorbed by diffusion. |
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| 27. |
Fill in the gaps: 1. Ascending limb of Henle’s loop is .......(1) to water. Whereas the descending limb is ......(2) to it. 2. Reabsorption of water from distal parts of the tubules is facilitated by hormone ...........3. Dialysis fluid contain all the constituents as in plasma except ........... 4. A healthy adult human excretes (on an average) ......... gm of urea/day. |
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Answer» 1. (1) – Impermeable, (2) -Permeable 2. ADH 3. Nitrogenous wastes 4. 25-30 gm of urea/day |
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| 28. |
The steps involved in the treatment of a uremic patient is given below.1. Complete the missing steps (a) and (b) 2. Diagonise the treatment 3. Name the organ which is under failure |
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Answer» 1. The missing steps are
2. Hemodialysis 3. Kidney |
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| 29. |
Observe the diagram and answer the following questions.1. Label the parts (1) and (2). 2. Name the functional unit of the kidney. |
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Answer» 1. The parts are:
2. Nephron |
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| 30. |
Observe the diagram and answer the questions.1. Identify the labelled parts A, B, C, D. 2. What does the diagram represents? |
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Answer» 1. The labelled parts are
2. Glomerular Filtration |
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| 31. |
1. What does the diagram represent? 2. Name the parts A, B, C, D. 3. What is the physiological function taking place in part ‘B. |
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Answer» 1. Nephron 2. The parts are
3. Henle’s loop is the site of osmoregulation in human kidney. The descending limb of loop of Henle is permeable to water but almost impermeable to electrolytes. The ascending limb is impermeable to water but allows transport of electrolyte actively or passively. Therefore, as the concentrated filtrate pass upward, it gets diluted due to the passage of electrolytes to the medullary fluid. |
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| 32. |
Globozoospermia is a rare condition that affects only males. It is characterized by sperm cells having a round head and no acrosome. What would this condition lead to? A. inability of the sperms to fertilise the egg B. inability of the male to produce enough sperms C. formation of zygote that is haploid instead of diploid D. formation of zygotes with a missing sex chromosome |
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Answer» A. inability of the sperms to fertilise the egg |
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| 33. |
Two statements are given - one labeled Assertion (A) and the other labeled Reason (R). Assertion: INVO cell is a new cost-effective technology for in vitro fertilisation (IVF) in which the sperm and the egg are mixed in a lab, put in a small capsule which is inserted into the vagina for a five days incubation period, post which the capsule is removed, and the embryos are implanted inside the uterus as usual. Reason: Instead of growing the embryo in an incubator, allowing it to develop in the natural environment in woman’s vagina reduces the cost in case of INVO cell as compared to regular IVF technology. Which of the following is correct? A. Both A and R are true, and R is the correct explanation of the assertion. B. Both A and R are true, but R is not the correct explanation of the assertion. C. A is true, but R is false. D. A is false, but R is true. |
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Answer» A. Both A and R are true, and R is the correct explanation of the assertion. |
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| 34. |
Identify the correct sequence of processes that happen in an adult female leading to child birth. A. fertilisation → implantation → development of foetus → ovulation → birth B. ovulation → fertilisation → implantation → development of foetus → birth C. implantation → ovulation → development of foetus → fertilisation → birth D. menstruation → fertilisation → ovulation → development of foetus→ birth |
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Answer» B. ovulation → fertilisation → implantation → development of foetus → birth |
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| 35. |
State the differences between the following. 1. Tubular reabsorption and Tubular secretion. 2. ADH and RAAS. |
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Answer» 1. Tubular reabsorption: The process of selective reabsorption of most of the useful substances from the glomerular filtrate in the renal tubule. Tubular secretion: It is the process of active secretion of certain substances such as Hydrogen ions, ammonia etc. from the blood into the lumen of the urinary tubules by the tubular epithelium during urine formation. 2. ADH: ADH is the hormone from posterior pituitary gland, makes the wall of the distal convoluted tube and collecting tubule permeable to water so that more water is reabsorbed. RAAS: Renin – Angiotensin – Aldosterone system increases the blood pressure by constricting arterioles and increases the blood volume by stimulating proximal convoluted tubule. |
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| 36. |
The failure of removing toxic substances from the blood ultimately leads kidney failure. 1. How is it temporarily solved. 2. Name the machine is used. |
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Answer» 1. Hemodialysis is an artificial process of removing toxic substances from the blood 2. Artificial kidney or Hemodialysis machine. |
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| 37. |
Classify the following animals according to their type of excretion.Frog, Tadpole, birds, man, Turtle, shark, insect, camel |
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| 38. |
Distinguish between diabetis mellitus and diabetis insipedus. |
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Answer» Insulin deficiency causes large amounts of blood sugar to be lost in the urine. It leads to diabetis melitus while the deficiency of ADH leads to diabetes insipedus i.e dilute urine disease. |
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| 39. |
In alcoholic drinkers the urine is dilute. Why? |
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Answer» The process of reabsorption of water by the distal parts of the kidney tubules become low efficient. This occurs due to the deficiency of ADH. lt leads to diabetes insipedus. |
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| 40. |
‘Micturition is an involuntary as well as a voluntary process.’ Justify the statement. |
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Answer» The elimination of urine from the urinary bladder is called micturition. The gradual filling of the urinary bladder causes stretching. When the bladder is filled to its limit, the stretch receptors send impulses to the brain to excrete the urine. The initiation and inhibition of micturition is voluntary in adult but involuntary in children. Due to lack of nervous control the micturition in some humans become involuntary causing bed wetting. |
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| 41. |
Indicate whether the following statements are true or false: 1. Micturition is carried out by a reflex 2. ADH helps in water elimination, making the urine hypotonic.3. Protein-free fluid is filtered from blood plasma into the Bowman’s capsule. 4. Henle’s loop plays an important role in concentrating the urine. 5. Glucose is actively reabsorbed in the proximal convoluted tublue. |
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Answer» 1. True 2. False 3. True 4. True 5. True |
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| 42. |
Write about the accessory excretory organs and their excretory substances in human beings. |
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| 43. |
What is the name of the terminal portion of the axon? |
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Answer» The terminal portion of the axon is called presynaptic membrane. Through this membrane neurotransmitters are released into the synaptic junction. |
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| 44. |
What are the three main parts into which a neuron can be divided? What are their respective functions? |
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Answer» The three mains parts into which a neuron can be didactically divided are: dendrites, cell body and axon. Dendrites are projections of the plasma membrane that receive the neural impulse from other neurons. The cell body is where the nucleus and the main cellular organelles are located. Axon is the long membrane projection that transmits the neural impulse at distance to other neurons, to muscle cells and to other effector cells. |
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| 45. |
Write a short note on Modern English. |
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Answer» The modern age has emerged as an era of development of science and technology combined with a deeprening sense of globalization. It is also true that English is being spoken by a large number of the world population. As such being a common language being spoekn in almost all countries it has also emerged as the langauge of trade and commerce, consequently, an individual needs to learn to communicate himself to others in no other language than English which could assure him a livelihood. hence one cannot do without English in the modern age as it has become as essential for survival amidst cutting competition as oxygen in for existence. |
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| 46. |
Write a note on modern English |
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Answer» Modern English Period extends from the beginning of the 16th century to the present day. This long period can be subdivided in to early Modern English period and later Modern English period. The early period extends from 1601 to 1700 and the later from 1701 to the present day. The fall of Constantinople into the hands of the Turks and consequent spread of Greek scholars in the continent, the Renaissance, the Reformation, the invention of the printing press by Caxton in 1476, the discovery of America by Columbus had far-reaching effects and shook the very foundation of Middle English. By the End of the 16th century, it became universally accepted as the standard of the language. |
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| 47. |
Mrs. R opened a bank account in Patna, and later shifted her home to Delhi, describe how she can get her passbook updated by the means of the latest technology also explain the benefits of technology? |
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Answer» Mrs. R can avail the passbook updating facility from any CBS branch near her location or can use Technology driven sources like online banking or any ATM installed near her location Benefits of CBS are (explain any 3 points with complete explanation) 1. Improves operational efficiency -It improves the quality time of both bank and customer by providing 24/7/365 facility. 2. Reduces cost of operations like commuting cost paper cost etc 3. Improves customer service as satisfied with Timely and accurate information for management decision making 4. Integrates with electronic payment systems such as Anytime and Anywhere banking. |
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| 48. |
The capital of Mizoram is: a) Aizwal b) Imphal c) Shillong d) Kohima |
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Answer» Correct option: a) Aizwal |
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| 49. |
Which of the following is not an ingredient of Ferro cement a. A mixture of cement, sand, mortar, water b. Metal rods c. Skeleton of weld mesh and chicken mesh d. Plastic rod |
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Answer» Correct option: a. Plastic rod |
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| 50. |
Match List-I with List-II.List-IList-II(Ores)(Composition)(a) Haematite(i) Fe3O4(b) Magnetite(ii) ZnCO3(c) Calamine(iii) Fe2O3(d) Kaolinite(iv) [Al2(OH)4Si2O]Choose the correct answer from the options given below:(1) (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)(2) (a)-(iii), (b)-(i), (c)(iv), (d)-(ii)(3) (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)(4) (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv) |
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Answer» (1) (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv) Haematite Fe2O3 Magnetite Fe3O4 Calamine ZnCO3 Kaolinite [Al2(OH)4Si2O5] |
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