Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Consider a long cylindrical wire carrying current along the axis of wire. The current distributed non-uniformly on cross section. The magnetic field B inside the wire varies with distance `r` from the axis as `B=kr^(4)` where k is a cosntant. The current density `J` varies with distance `r` as `J=cr^(n)` then the value of `n` is (where c is another constant).

Answer» Correct Answer - 3
`int bar(B).bar(dl)=u_(0)i_("ene")`
`implies B(2pir)=mu_(0)int_(0)^(R) 2pirdr=mu_(0)int_(0)^(r)2piCr^(n-1)dr`
`kr^(4)xx2pir=mu_(0)2piC (r^(n+2))/(n+2)impliesn+2=5impliesn=3`
2.

In which gas, hydrogen and oxygen will the sound have greater velocity?

Answer»

As velocity, v α\(\sqrt{1}/{ρ}\) , velocity of sound will be greater in hydrogen gas.

3.

What king of waves help the  bats to find their  way in dark?

Answer»

ultrasonic wave helps to find the ways of bats in dark.

4.

A chinese fire cracker when busted creates 100 dB sound at a distance of 10 cm. this level of sound is dangerous and can create deafness. To reduce the sound to a safer level, we need to stand far from it. At what minimum destance from the fire cracker a person should stand so that sound level heard by him is 40 dB? (Assume that sound energy spread equally in all directions)A. 100 mB. 6.63 cmC. 10 mD. 1 m

Answer» Correct Answer - A
Intensity at 10 cm
`100=10log(I_(1))/(I_(0))`
`impliesI_(1)=10^(-2)=W//m^(2)`
Intensity at `r` distance
`40=10log(I_(2))/(I_(0))`
`impliesI_(2)=10^(-8)W//m^(2)`
Since firecracker is a point source:
`(I_(1))/(I_(2))=(r_(2)^(2))/(r_(1)^(2))=(r^(2))/((0.1)^(2))`
`r=0.1xxsqrt((10^(-2))/(10^(-8)))=100m`
5.

Why does sound travel faster in iron than in air?

Answer»

Because solids are more elastic compared to air.

6.

Velocity of sound in vacuum is(a) 330ms-1(b) 165ms-1(c) zero(d) 660ms-1

Answer»

Correct answer is (c) zero

Sound requires a material medium for propation. Hence, velocity of sound in vacuum is zero.

7.

What is the range of frequency of audible sound?

Answer»

20Hz to 20KHz.

8.

Find the cube root of 941192.1. 982. 883. 944. 785. None of these.

Answer» Correct Answer - Option 1 : 98

Concept used:-

Trick to find cube root of a number.

Method and Calculation:-

 • Find the unit digit of cube root by looking at unit digit of given number.

For cube root of 941192, unit digit must be 8 (83 is 512)

 • Find other digit(s) by ignoring the last three digits of number and looking at remaining digits.

729 < 941 < 1000 (729 and 1000 are cubes of 9 and 10, so remaining part of cube root will be 9)

Hence, 98 is our answer

9.

Find the cube root of 50653.1. 372. 473. 334. 275. None of these.

Answer» Correct Answer - Option 1 : 37

Concept used:-

Trick to find cube root of a number.

Method and Calculation:-

 • Find the unit digit of cube root by looking at unit digit of given number.

For cube root of 50653, unit digit must be 7 (73 is 343)

 • Find other digit(s) by ignoring the last three digits of number and looking at remaining digits.

27 < 50 < 64 (27 and 64 are cubes of 3 and 4, so remaining part of cube root will be 3)

Hence, 37 is our answer

10.

Who among the following cannot be removed from office except in the manner prescribed in the Constitution of India?(a) The Deputy Chairman, Planning Commission (b) The Governor of a State (c) The Chief Election Commissioner (d) The Chairman, Finance Commission 

Answer»

(c) The Chief Election Commissioner

11.

Consider the following statements:1. f(x) = |x - 3| is continuous at x = 02. f(x) = |x - 3| is differentiable at x = 0Which of the statements given above is/are correct?1. 1 only2. 2 only3. Both 1 and 24. Neither 1 nor 2

Answer» Correct Answer - Option 3 : Both 1 and 2

Concept:

|x| = x if x ≥  0 and |x| = -x , if x < 0

We say f(x) is continuous at x = a if \(\rm\lim _{x \rightarrow a^{-}} f(x)=\lim _{x \rightarrow a^{+}} f(x)=lim _{x \rightarrow a} f(x)\)

We say f(x) is differentiable at x = a if \(\rm\lim _{x \rightarrow a^{-}} f'(x)=\lim _{x \rightarrow a^{+}} f'(x)\)

 

Calculation:

Here,  f(x) = |x - 3|

f(x) = x - 3 when x - 3 ≥  0 ⇒ x ≥ 3

And f(x) = 3 - x when x - 3 < 0 ⇒ x < 3

For, x = 0, f(x) = 3 - x

Function is not changing at x = 0   (∵ function is linear)

So, f(x) is continuous at x = 0

Now, x = 0, f(x) = 3 - x

⇒ f'(x) = -1

f'(0-) = -1 and f'(0+) = -1

So, f(x) is differentiable at x = 0

Hence, option (3) is correct.
12.

The smallest perfect square number divisible by each of 6 and 12 is:1. 1082. 363. 1964. 144

Answer» Correct Answer - Option 2 : 36

Given:

Smallest perfect number divisible by 6 and 12

Concept used:

LCM of the numbers

Calculation:

LCM of 6 and 12 is 12.

⇒ 12 × 1 = 12, 12 is not a perfect square

⇒ 12 × 2 = 24, 24 is not a perfect square

⇒ 12 × 3 = 36, 36 is a perfect square

∴ The smallest perfect square number divisible by 6 and 12 is 36.

13.

Find the LCM of 8, 10, 15, 16 and 20?1. 2402. 2603. 2204. 250

Answer» Correct Answer - Option 1 : 240

Calculation:

8 = 2 × 2 × 2

10 = 2 × 5

15 = 3 × 5

16 = 2 × 2 × 2 × 2

20 = 2 × 2 × 5

L.C.M = 2 × 2 × 2 × 2 × 3 × 5

⇒ 240

∴ The required LCM is 240

14.

Express the following numbers as the sum of odd numbers using the above pattern?(a) 63 (b) 83 (c) 73Consider the following pattern.23-13 =1+ 2 x 1 x 333-23 =1+ 3 x 2 x 343-33 =1+ 4 x 3 x 3Using the above pattern, find the value of the following.(i) 73-63 (ii) 123-113 (iii)203-193 (iv) 513-503 

Answer»

(a) n=6 and (n-1) = 5
∴ We start with (6 x 5) + 1 = 31
we have
63= 31 + 33 + 35 + 37 + 39 + 41=216
(b) n=8 and (n-1)=7
∴ we start with (8 x 7)+1=57
we have
83= 57 + 59 + 61 + 63 + 65 + 67 + 69 + 71 = 512
(c) n = 7 and (n-1) =6
∴ we start with (7 x 6) + 1 = 43
We have
73= 43+ 45+ 47 + 49 + 51 + 53 + 55 = 343

(i) 73-6= 1 + 7 x 6 x 3 = 127
(ii) 123-11= 1 + 12 x 11 x 3 = 397
(iii) 203-19= 1 + 20 x 19 x 3 = 1141
(iv) 513-50= 1 + 51 x 50 x 3 = 7651

15.

What is the product of √3 + √2 and √3 - √2.

Answer»

We know that a- b= (a + b)(a - b)

(√3 + √2) (√3 - √2)

= (√3)2 - (√2)2

= 3 - 2

= 1

16.

Aravalli mountain ranges are an example of1. Block Mountain2. Folded Mountain3. Residual Mountain4. Bolkanic Mountain

Answer» Correct Answer - Option 3 : Residual Mountain

Aravalli mountain ranges are an example of Residual Mountain

  • Since it is the residual part of an earlier mountain or plateau it is called residual mountains and is made up of relatively hard rocks.
  • The erosion of soft rocks in an area is rapid whereas erosion of resistant rocks is low thus a degraded and flat area with hard and resistant rocks is formed.
  • Aravalli is the oldest mountain range in the world and is very rich in natural resources.
  • Aravalli is an example of residual mountains.
  • It is located in the western part of India, Rajasthan.
  • It is also known as Adavala Parvat in Rajasthan.

Hence, it is a mountain or landform that has been cut down by denudation becomes low and flat.

17.

Where is the maximum onion production in India?1. Uttar Pradesh2. Madhya Pradesh3. Maharashtra4. Andhra Pradesh

Answer» Correct Answer - Option 3 : Maharashtra

Maximum onion production takes place in Maharashtra.

Onion production in India:

  • Maximum onion production takes place in Maharashtra (4905.0 thousand tons) state followed by Karnataka (2592.2 thousand tons), Gujarat (1514.1 thousand tons.), Bihar (1082.0 thousand tons.), Madhya Pradesh (1021.5 thousand tons.) and Andhra Pradesh (812.6 thousand tons).
  • In Rajasthan, Haryana and Uttar Pradesh it is grown to some extent i.e. 494.2, 453.9 and 368.6 thousand tons respectively.

 Onion production statistics, 2017-18

RankStateAreaProduction
1Maharashtra507.965,355.39
2Madhya Pradesh150.873,859.83
3Karnataka195.283,197.40
4Gujarat22.491,303.07
5Rajasthan64.761,292.20
6Bihar53.771,248.96
7Haryana29.93905.80
8AndhraPradesh42.00695.12
9Tamil Nadu28.36687.50
10West Bengal35.20560.65
18.

Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnefied images of biological molecules and other type of material. If the velocity of the electron in this microcope is `1.6xx10^(6) m s^(-1)`. Calculate de Broglie wavelength associated with this electron.

Answer» `lambda=h/(mv)=(6.626xx10^(-34) kgm^(2) s^(-1))/((9.11xx10^(-31)kg)(1.6xx10^(6) ms^(-1)))`
`=4.55xx10^(-10)m=455 p m`
Mass of neutron `=1.675xx10^(-27)kg`
19.

Number of the α-particle deflected in Rutherford's α-scattering experiment varies with the angle of deflection. Then the graph between the two is best represented by.

Answer»

Answer is (2)

N ∝ {1}/{sin4(θ/2)}

20.

Women saint Daya Bai was a disciple of?1. Saint Charandas2. Saint Nimbarkacharya3. Saint Raidas4. Saint Ramcharan

Answer» Correct Answer - Option 1 : Saint Charandas

The correct answer is Saint Charandas.

  • Women saint Daya Bai was a disciple of Saint Charandas.

  • Saint Charandas
    • ​Charandas was born in Derha, near Alwar in 1706.
    • His family belonged to the Dhusar caste (merchant class).
    • He was succeeded to his spiritual seat by his cousin sisters of his Dhusar community of Alwar.
    • Two of his major disciples, Sahjo Bai and Daya Bai, both women.

  • Saint Nimbarkacharya
    • ​The Nimbarka Sampradaya also known as the Hamsa Sampradāya, and Sanakādi Sampradāya, is one of the four Vaiṣṇava Sampradāyas.
    • It was founded by Nimbarka, a Telugu Brahman.
    • He was a follower of Dvaitadvaita.
    • Dvaitadvaita states that humans are both different and non-different from Isvara, God, or Supreme Being.
  • Saint Raidas
    • Ravidas was an Indian poet-saint of the Bhakti movement during the 15th to 16th century CE.
    • Venerated as a guru (teacher) in the region of Uttar Pradesh, Rajasthan, Maharashtra, Madhya Pradesh, and mainly Punjab.
    • He was a poet-saint, social reformer, and spiritual figure.
  • Saint Ramcharan
    • Ramcharan was born in Sodha, a village in the Tonk district of Rajasthan.
    • Charan's childhood name was "Ram Kishan".
    • Charan married Gulab Kanwar and became Patwari after marriage.
    • After some time the king of Jaipur (Amber, India) Jai Singh II of Amber offered him the post of Divan of Jaipur of Malpura branch.
    • He became a disciple of Kripa Ram Maharaj and followed him.
21.

The singing tradition with which Gavari Devi was associated:1. Langa2. Mand3. Talabandi4. Thumari

Answer» Correct Answer - Option 2 : Mand

The correct answer is Mand.

  • The singing tradition with which Gavari Devi was associated is Mand.

 

  • Mand
    • ​Mand is a style of singing in Rajasthan, used in folk songs.
    • It is similar to the thumri and the ghazal.
    • Mand singers include:
      • Allah Jilai Bai from Bikaner (awarded Padma Shri-1982 and Sangeet Natak Akademi Award-1988 in Folk Music),
      • Mangi Bai Arya from Udaipur (awarded Sangeet Natak Akademi Award-2008 in Folk Music), and
      • Gavari Bai from Jodhpur (awarded by Sangeet Natak Akademi Award-1975-76 and 1986 in Folk Music).

  • Langa
    • Singing style sang by Langa singers on Mangalik occasions and celebrations like Manganiyar in Bikaner, Barmer, Jodhpur and Jaisalmer district is called Langa.
    • Gayaki Sarangi and Kamayacha are the main instruments of the Rajputs.
    • The major Langa artists are Fuse Khau, Mahradin Langa, Alauddin Langa, Karim Khan Langa.
  • Talabandi
    • In Rajasthan's eastern region Bharatpur, Dhaulpur, Karauli and Sawai Madhopur etc.
    • There is a classical tradition of folk singing style in which the poems of ancient poets associated with raga raganis are sung collectively, this is called talbandi singing.
    • There are sarangi, harmonium, dholak, tabla and jhoj and also play the nagada (bomb) in between.
22.

Which of the following species are Isoelectronic with Ne?(Atomic no. of Ne = 10). N3-, Na+, Al3+, Ar, Rb+ &amp; F-

Answer»

All elements contains total 10 electrons.

23.

Mention the type of Hydrogen bond in the following compounds.(i) Water (ii) ortho-Nitrophenol

Answer»

(i) Inter molecular hydrogen bonding 

(ii) Intra molecular hydrogen bonding

24.

Which of the following is first IPS lady of Punjab?1. Ms. Surinder Kaur2. Bibi Jagir Kaur3. Ms. Rajinder Kaur4. Ms. Kiran Bedi

Answer» Correct Answer - Option 4 : Ms. Kiran Bedi

The Correct Answer is Kiran Bedi.

  • Kiran Bedi is an Indian police officer and is the first woman to join the Indian Police Service (IPS) in 1972.
  • She was born on 9th June 1949 in Amritsar, Punjab, and is one of the most celebrated and widely known police officers who ever served the Indian Police Force.
  • Until taking voluntary retirement in 2007, she stayed in service for 35 years as Director-General, Bureau of Police Research and Development. 
  • Bedi was crowned the national junior tennis champion as a teenager in 1966. She won multiple titles at different national and state-level competitions between 1965 and 1978.
  • Bedi worked in Delhi, Goa, Chandigarh, and Mizoram after entering the IPS.
  • She began her career in Delhi's Chanakyapuri district as an Assistant Superintendent of Police (ASP) and received the President's Police Medal in 1979.
  • Then she moved to West Delhi, where she instituted a reduction in the number of crimes against women
  • Subsequently, she supervised traffic arrangements for the 1982 Asian Games in Delhi and the 1983 CHOGM meeting in Goa as a traffic police officer.
25.

Who among the following Sociologist has studies Indian National Movement by using Marxian Perspective ?(a) Ram Krishna Mukherjee(b) A.R. Desai(c) Bipin Chandra(d) D.N. Dhangare

Answer»

A.R. Desai Sociologist has studies Indian National Movement by using Marxian Perspective.

26.

Who is the author of "Bharat main Jativad Aur Harijan Saamasya" ?(a) K. Bharti(b) Jagjeevan Ram(c) S.C. Dubey(d) K. Nath. 

Answer»

Jagjeevan Ram is the author of "Bharat main Jativad Aur Harijan Saamasya".

27.

Which one of the following factors Contributes to regional disparities in India ?(a) Population Growth(b) Sex Ratio(c) Economic development(d) None of these. 

Answer»

Economic development factors Contributes to regional disparities in India.

28.

Indus Mega Food Park Private Limited is the first ever mega food park in Madhya Pradesh situated in ________ district of the state. 1. Bhopal2. Jabalpur 3. Indore 4. Khargone

Answer» Correct Answer - Option 4 : Khargone
  • The first ever mega food park of Madhya Pradesh came up in Khargone District of the state and is named as the Indus Mega Food Park Private Limited. 
  • Another mega food park is going to come up in Dewas district in the state as the second mega food park of the state. 
  • The Indus Mega Food Park Private Limited has been established with a cost of Rs 127.70 crores and it is expected to benefit around 30000 farmers in the state. 
29.

The first ever mega food park of the country was set up in which among the following states in India?1. Andhra Pradesh 2. Karnataka3. Maharashtra4. Madhya Pradesh

Answer» Correct Answer - Option 1 : Andhra Pradesh 
  • Andhra Pradesh became the first state in the country to have a mega food park. 
  • It came up in Chittoor District of the state and is mainly focused on providing global standards to the food processing infrastructure in the country. 
30.

What is the approximate fraction of genetic variation in the nuclear genome that is expected to have a harmful effect on gene function?(a) 50%(b) 25%(c) 10%(d) 1%

Answer» Correct choice is (d) 1%

Explanation: Genetic variation due to mutation causes harmful effects on gene function. Ad low as 1% genetic variation can cause noticeable harmful changes the expression and function of genes. It may lead to congenital diseases or may be fatal.
31.

Which phenomena are made use of in the technique FRAP?(a) electrostatic(b) photothermal(c) hybridization(d) fluorescence

Answer» Correct choice is (d) fluorescence

To explain I would say: Fluorescence recovery after photobleaching (FRAP) is a technique in which integral membrane proteins are labeled with a fluorescent dye, after which they are irradiated by a laser beam.
32.

In every cell, the number of tRNA molecules is at least (A) 10 (B) 20 (C) 30 (D) 40

Answer»

Correct option (B) 20

33.

Which of the following statement(s) is/are incorrectA. Number of sub-shell presentin M-shell = 3B. `Cu^(+)` (Z=29) is paramagnetic.C. Zeeman effect explains splitting of special lines in magnetic fieldD. Orbital angular momentum of an `e^(-)` is `(h)/(2pi) sqrt(l(l+1))`

Answer» Correct Answer - A
`v = 2lambda`
`lambda=(h)/(mv)`
`lambda^(2)=(h)/(2m)`
34.

In tRNA molecule D arm is named for the presence of the base: (A) Uridine (B) Pseudouridine (C) Dihydrouridine (D) Thymidine

Answer»

Correct option (A) Uridine

35.

Which of following wil show positional isomerismA. 1-chloroetheneB. 2,2-dimethylpropaneC. 2,2-dimethylbutaneD. None of these

Answer» Correct Answer - D
Angular node = 0
Radial node = 2
`6-(4r)/(a_(0))+(4)/(9)(r^(2))/(a_(0)^(2))=0`
Distance of radial node from nucleous = `(9)/(8) (4+(4)/sqrt(3))a_(0)" & "(9)/(8)(4-(4)/(sqrt(3)))a_(0)`
Distance between radial node `=sqrt(27)a_(0)`
This equation represent 3s orbital.
36.

Transfer RNAs are classified on the basis of the number of base pairs in (A) Acceptor arm(B) Anticodon arm(C) D arm(D) Extra arm

Answer»

(D) Extra arm

37.

Select the correct statementA. `C_(6)H_(14)` has 6 structural isomer possibleB. positional isomersC. Ethylcyclohexane and 1, 1-dimethylcyclohexane are chain isomersD. All of these

Answer» Correct Answer - B
`Mvr=(nh)/(2pi)`
38.

Due to which of the following phenomenon, an object such as tree appears to be inverted and appears to be on the bank of a pond?1. Scattering of light2. Tyndall effect3. Refraction4. Mirage

Answer» Correct Answer - Option 4 : Mirage

The correct answer is Mirage.

  • A mirage is a naturally occurring phenomenon in which light rays bend because of refraction to produce a displaced image of distant objects or the sky.

  • It mostly occurs in the desert or at sea, by which the image of the object appears displaced above, below, or to one side of its true position as a result of variations in the refractive index of air.
  • Thus, an object such as a tree appears to be inverted and appears to be on the bank of a pond because of Mirage.
39.

Which process involves maximum release of energy?A. `O(g)+e^(-) rarr O^(-)(g)`B. `S(g)+e^(-) rarr S^(-)(g)`C. `F(g)+e^(-) rarr F^(-)(g)`D. `Cl(g)+e^(-) rarr Cl^(-)(g)`

Answer» Correct Answer - C
The tendency to lose electron is higher with elements having lower ionisation potential.
40.

Find out the number of benzene containing functional isomers of

Answer» Correct Answer - 2
`Li lt Na`
`Li^(+) (aq) gt Na^(+) (aq)`
41.

An `e^(-)` having wavelength `(18sqrt(pi)pmDeltalambda)Å`, if its uncertainty in position and wavelength are equal, then what is the minimum value of uncertainty in wavelength of `e^(-)` in `Å`? (where `Delta lambda` = uncertainty in wavelength)

Answer» Correct Answer - 5
`2NaOH+H_(2)SO_(4)rarrNa_(2)SO_(4)+2H_(2)O`
`0.04 "mol "0.02 "mol" `
mol of `H_(2)SO_(4)` consumed = 0.02
`therefore M_("dilute ")20//1000 =0.02`
Molartiy of dilute `H_(2)SO_(4)` solution = 1
`100 xx 5 = 1 xxV`
V = 500 ml diluted solution
`therefore x = 400ml H_(2)O` added.
`therefore (400)/(80) = 5`
42.

Calculate sum of maximum & minimum number of electrons present in Mn having `n + l ge 4, |m| = 1, s = + 1//2`

Answer» Correct Answer - 9
`(Deltax)=(Deltalambda)`
`Deltax xx (h)/(lambda^(2))Deltalambda=(h)/(4pi)`
`Deltalambda=(lambda^(2))/(4pi)=(lambda)/(2sqrt(pi))=(18sqrt(pi))/(2sqrt(pi))Å=9Å`
43.

`{:(("One to one matching"),,,,"Numer of structural isomers"),("Column-I",,,,"Column-II"),((A)C_(5)H_(10),,,,(P)3),((B)C_(5)H_(12),,,,(Q)9),((C)C_(4)H_(6),,,,(R)10),((D)C_(4)H_(8)O("Cyclic ether only"),,,,(S)6),(,,,,(T)5):}`

Answer» Correct Answer - A (R ), B (Q), C (P,R), D(P,R,S)
(A) `Li gt Na`
`1s^(2)2s^(1)" "1s^(2)2s^(2)2p^(6)3s^(1)" "(l.E_(1))`
(B) `underset(Z_("eff")uarr)overset(LigtBegtBgtC)rarr` (order of size)
(C ) `underset(Z_("eff")uarrE.Nuarr)overset(Mg gt Al gt Si)rarr`
`Li gt Na`
(D) `{:(Mg " "lt " "Al " "lt " "Si),(3s^(2)" "3s^(2)3p^(1)" "3s^(2)3p^(2)),(Li gt Na),(2s^(1) " "3s^(1)),(Cl gt F gt Br gt l):}}" (Order of E.A)"`
44.

Which of the following statement is/are correct for photoelectric effectA. Photo current is depends upon intensity of lightB. Maximum kinetic energy of photo electron depends upon frequency of light incident on metal surfaceC. If frequency of light incident on metal surface is equal to threshold frequency then photo electron must be ejected metal surface.D. If-value of maximum K.E of photo `s^(-)` is `4.8xx10^(-10)J` then stopping potential is 3 volt.

Answer» Correct Answer - A::B::D
Chemical properties may be same
45.

Which of the following is/are incorrect statementsA. First ionisation energy of `e^(-)` in He(g) atom is `+54.4 eV`B. If `e^(-)` makes a transition from n = 3 to n = 1 then maximum line obtained in te spectrum of H-atom sample is 2C. Ratio of radius of `2^(nd)` orbit and `4^(th)` orbit of H-atom is propotional to `n^(3)`D. Time period of `e^(-)` in `n^(th)` orbit of H-atom is propotional to `n^(3)`

Answer» Correct Answer - A::B::C::D
`1M " "H_(2)O_(2)" "+" "2M" "H_(2)O_(2)`
`200 mL" "300 ml`
`M =(1xx2+2xx3)/(5)=1.6M`
volume strength `= 1.6 xx 11.35 = 18.16 V`
Strength = `54.4 g//L`
`% (w)/(v) = 5.44%`
46.

The correct order among the following is/areA. `P lt Cl lt S (l.E_(2))`B. `HClO gt HBrO gt HIO` (Decreasing order of acidic nature)C. `Ti^(2+) lt Ti^(3+)` (Magnetic moment)D. `F gt O gt N gt C` (order of E.A)

Answer» Correct Answer - C::D
`(A) B lt C (E.A)`
`B^(+) gt C^(+)(l.E)`
`2s^(2) 2s^(2) 2p^(1)`
`(B) S lt Cl (E.A)`
`S^(+) gt Cl^(+)(l.E)`
`3p^(3) 3p^(4)`
(C ) `Li gt Na (E.A)`
`Li^(+) gt Na^(+)(E.A)`
`1s^(2) 2s^(2) 2p^(6)`
(D) `Na gt Mg (E.A)`
`Na^(+) gt Mg^(+) (l.E.)`
`2p^(6) 2p^(8) 3s^(1)`
47.

If 2/5 of a number is equal to 2/3 of another number, what is the ratio between these two numbers?1. 5 : 32. 3 : 43. 15 : 44. 4 : 3

Answer» Correct Answer - Option 1 : 5 : 3

Let the one number be 'x' and other number be y

According to question

2/5 of x = 2/3 of y

⇒ 2 × 3 × x = 5 × 2 × y

⇒ x/y = 5/3

∴ Required ratio = 5 : 3

48.

200ml of 11.35V `H_(2)O_(2)` solution is mixed with 300 ml of 22.7 V `H_(2)O_(2)` solution then which of the following is/are are correct for Resulting solution.A. 250ml of `H_(2)O` solution gives 4.54 L of `O_(2)(g)` at STP on complete decomposition.B. `%(w)/(v)` of `H_(2)O_(2)` solution is 5.44%C. Sum of number of moles of O-atom and H-atom in resulting `H_(2)O_(2)` solution is 3.2 moles.D. Molartiy of `H_(2)O_(2)` solution = 1.6 M

Answer» Correct Answer - A::B
Second ionisation energy of He(g) `=+54.4 V`
Maximum lines `=(n(n-1))/(2)" "," Radius"=0.529 (n^(2))/(z)A^(@)" , Time period"prop(n^(3))/(z)`
49.

“Some flowers are called perigynous”. What do you mean by it?

Answer»

Ovary half inferior or half superior.

50.

The following diagrams show different types of placentation.1. Name the type of placentations. 2. write one example for each placentation.

Answer»

1. Marginal, Basal 

2. Pea & Sunflower