Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Explain the terms ‘depletion layer’and ‘potential barrier’, in a p-n junction diode. How are the (a) width of depletion layer, and (b) value of potential barrier, affected when the p-n junction is forward biased?

Answer»

Depletion layer is a region created around the p-n junction which is devoid of free charge carriers and has immobile ions. It is created due to diffusion of majority carriers across the junction when p-n junction is formed. 

Potential barrier is a potential difference or junction voltage developed across the junction due to migration of majority carriers across it when p-n junction is formed. It opposes the further migration of majority carriers across the p-n junction. It appears as if a fictitious battery is connected across the p-n junction, with its positive terminal to n-region and negative terminal to p- region of p-n junction. The value of potential barrier is 0.3V for Ge and 0.7V for Si semiconductor diode. The forward bias voltage opposes the potential barrier. Due to it, the potential barrier is reduced and hence, the width of depletion layer decreases.

2.

The plates of a parallel plate capacitor have an area of 100 cm2 each of 100 cm2 each and are separated by 3 mm. The capacitor is charged by connecting it to a 400 V supply. a) Calculate the electrostatic energy stored in the capacitor. b) If a dielectric of dielectric constant 2.5 is introduced between the plates of the capacitor, then find the electrostatic.

Answer»

energy stored and also change in the energy stored. 

Given A = 100 cm2 = 100 x 10–4m2,

d = 3 mm = 3 x 10–3m, V = 400 V, U1 = ? 

K = 2.5, U2 = ? also U2 – U1 = ? 

U = \(\frac{1}{2}CV^2\) C = \(\frac{\varepsilon_0 A}{d}\)

Calculating 

U1 = 23.608 x 10–7

U2 = 59.02 x 10–7

U2 ∼ U1 = 35.412 x 10–7J

3.

Two wire are made of the same material and same volume .Cross-sectional area of wire 1 is A and wire 2 is 3A. If the length of the wire 1 increase by dx on applying force F, how much force needed to stretch wire 2 by the same amount?

Answer» Let the length of first wire be Land that of 2nd wire be l. As the volumes of two wires are same then

L×A=l×3A

So L/l=3

Let Young's modulus of the material be Y

Then for elongation of dx length of first wire we can write

Y=(F1/A)/(dx/L), where F1 is the force required.

For similar elongation of second wire if force required be F2 then

Y=(F2/3A)/(dx/l)

So (F2/3A)/(dx/l)=(F1/A)/(dx/L)

=>F2/F1=L/l×3=3×3=9

=>F2=9×F1

Hence 9 times force is required in 2nd case to cause similar elongation.
4.

What is the meaning of the term 'attenuation' used in communication system ?

Answer»

Attenuation is refererred to as the reduction in the strength of a signal while propagating through a medium. Attenuation is possible for both digital and analog signals as a result of long distance transmission.

5.

. A person can “ walk on water “ if she has the proper shoes. Assume that you use expanded polystyrene (ρ = 0.40 g/cm3 ) to construct two blocks that you will strap to your feet, with a cross section of 850 cm2 . How long will each block need to be in order to support a 65 kg person?

Answer» F=mg = (65)(9.8)= 637

F = (0.4 g/cm3)(850 cm2)(9.8)(h)

F = 3332 (h)

637 = 3332(h)

0.19 = h
6.

Let a, b ∈ R and f : R → R be defined by f(x) = a cos(|x3 – x|) + b|x| sin(|x3 + x|). Then f is (A) differentiable at x = 0 if a = 0 and b = 1 (B) differentiable at x = 1 if a = 1 and b = 0 (C) NOT differentiable at x = 0 if a = 1 and b = 0 (D) NOT differentiable at x = 1 if a = 1 and b = 1

Answer»

(A) differentiable at x = 0 if a = 0 and b = 1 

(B) differentiable at x = 1 if a = 1 and b = 0 

f(x) = a cos(x3 – x) + bx sin(x(x2 + 1)) 

It is a differentiable function ∀ x∈R

7.

Mohandas Karamchand Gandhi returned to India in the year ______ after two decades of residence abroad.1. 18692. 19053. 18934. 1915

Answer» Correct Answer - Option 4 : 1915

The correct answer is 1915.

  • Mohandas Karamchand Gandhi landed on January 9, 1915, at the Apollo Bunder in Bombay after two decades of residence abroad.
  • He received a "Kaiser-i-Hind" gold medal in the King’s birthday honors list of 1915.
  • His political mentor on the Indian scene was Gopal Krishna Gokhale.
  • Lord Hardinge’s open support of the Satyagraha movement had in any case removed the stigma of rebellion from South Africa’s Indian movement.

  • As a 19-year-old, Mohandas Karamchand Gandhi had left India for the first time on September 4, 1888, to get enrolled in the centuries-old law institute Inner Temple in London.
  • In 1894 Gandhi tried his first criminal cases in South Africa.
  • From 1893 till 1913 Gandhiji practiced in South Africa.
  • On March 12, 1930, Indian independence leader Mohandas Gandhi begins a defiant march to the sea in protest of the British salt monopoly.
  • Gandhi set out from Sabarmati Ashram, Ahmadabad with 78 followers on a 241-mile march to the coastal town of Dandi on the Arabian Sea.
    • They reached Dandi on April 5, Gandhi was at the head of a crowd of tens of thousands. Gandhi spoke and led prayers and early the next morning walked down to the sea to make salt.
8.

Semilogarithmic paper means a. One axis is linear, and the other is logarithmic b. One axis is linear, and the other is semilogarithmic c. Both axes are semilogarithmic d. Neither axis is linear

Answer»

(a) One axis is linear, and the other is logarithmic

9.

If f = 1 MHz, and f2 = 10 Hz, the ratio \(\frac{f}{f_2}\) represents how many decades? a. 2 b. 3 c. 4 d. 5

Answer»

The correct answer is:  (d) 5

10.

At the lower or upper cutoff frequency, the voltage gain is a. 0.35Amid b. 0.5Amid c. 0.707Amid d. 0.995Amid

Answer»

The correct answer is: (c) 0.707Amid

11.

One frequency is 8 times another frequency. How many octaves apart are the two frequencies? a. 1 b. 2 c. 3 d. 4

Answer»

The correct answer is: (c) 3

12.

If the power gain doubles, the decibel power gain increases by a. A factor of 2 b. 3 dB c. 6 dB d. 10 dB

Answer»

The correct answer is: (b) 3 dB

13.

If the voltage gain is 10, the decibel voltage gain is a. 6 dB b. 20 dB c. 40 dB d. 60 dB

Answer»

The correct answer is: (b) 20 dB

14.

Two stages have voltage gains of 100 and 200. The total decibel voltage gain is a. 46 dB b. 66 dB c. 86 dB d. 106 dB

Answer»

The correct answer is: (c) 86 dB

15.

Two stages have decibel voltage gains of 20 and 40 dB. The total ordinary voltage gain is a.1 b. 10 c. 100 d. 1000

Answer»

The correct answer is: (d) 1000

16.

If the voltage gain is 2000, the decibel voltage gain is a. 40 dB b. 46 dB c. 66 dB d. 86 dB

Answer»

The correct answer is: (c) 66 dB

17.

If the voltage gain is 100, the decibel voltage gain is a. 6 dB b. 20 dB c. 40 dB d. 60 dB

Answer»

The correct answer is: (c) 40 dB

18.

If the voltage gain doubles, the decibel voltage gain increases by a. A factor of 2 b. 3 dB c. 6 dB d. 10 dB

Answer»

The correct answer is: (c) 6 dB

19.

A ray of light incident perpendicularly (⊥r) on plane mirror. What will be measure of angle of reflection ?(A) 0º (B) 45º(C) 90º (D) 135º

Answer»

A ray of light incident perpendicularly (⊥x) on plane mirror. 90º will be measure of angle of reflection. 

20.

The real absolute refractive index of air is —(A) equal to 1 (B) less than 1(C) greater than 1 (D) zero

Answer»

The real absolute refractive index of air is greater than 1.

21.

Define the principal focus of a concave mirror. 

Answer»

A parallel beam of light after reflection from a concave mirror converges at a point in front of the mirror. This point (F) is the focus of a concave mirror and it is real. 

22.

Minimum distance for clear picture is—(A) 25 cm (B) 25 m(C) 2.5 cm (D) ∝

Answer»

Minimum distance for clear picture is 25 cm. 

23.

Who inverted “Magnetic effect of electric current”(A) Farad (B) Oersted(C) Ampere (D) Bohr

Answer»

Oersted inverted “Magnetic effect of electric current”

24.

Define the centre of curvature of the spherical mirror? 

Answer»

Centre of curvature (C) : The centre of the sphere of which the mirror is a part is called centre of curvature. 

25.

Define homologous organ.

Answer»

–Homology refers to the traits inherited by two different organisms from a common ancestry. 

–Homologous organs are those organs which are similar in structure and different in function. 

–These organs have similar origin & different function. e.g.

(i) Forelimbs of vertebrates having pentadactyl limbs of similar origin and similar arrangement of bones. Muscles etc.  

26.

What is fossils? 

Answer»

–Fossils are the remains or impression of a pre-historic plant or animal embedded in rock and preserved in petrified from. 

–The study of fossils of some of the organisms show similarity between the two groups. 

27.

How does binary fission differ from multiple fission ?

Answer»
Binary fission Multiple fission 
–Asexual reproduction where each nuclear division is followed by cytoplasmic division.–Asexual reproduction where the nucleus divided several times before the cytoplasmic division. 
–Two daughter cells are formed
e.g. Amoeba
Many daughter cells are formed
e.g. Plasmodium
28.

What is pollination? 

Answer»

The transfer and deposition of pollen grains from the anther to the stigma of a flower is called as pollination.  

Pollination is of two types :- 

(i)  Self pollination :-  The transfer of the pollen grains from the anther to the stigma of either the same or genetically similar flower.

(ii)  Cross pollination : The transfer of the pollen grains from the anther of one flower to the stigma of another flower on a different plant of the same species. 

29.

The embryo gets nutrition from the mother’s blood with the help of a special tissue called A) Zygote B) Utreus only C) PlacentaD) None of these

Answer»

C)  Placenta

30.

Which of the following terms does not represent electrical power in a circuit? A) I2R B) IR2 C) VI D) V2 /R

Answer»

IR2 terms does not represent electrical power in a circuit.

31.

Write the two limitations of Newland's law of octaves.

Answer»

Limitations of law of octaves :

(A)  The law of octaves was found to be applicable only upto calcium. It was not applicable to elements of higher atomic masses.

(B)  Position of hydrogen along with fluorine and chlorine was not justified on the basis of chemical properties.

32.

Write the set {x : x ∈ R and -4< x ≤ 6) as an interval.

Answer»

{-3, -2, -1, 0, 1, 2, 3, 4, 5, 6} ∴ x ∈ (-3, 6)]

33.

By which reaction metal is obtained from metal oxide A) Liquification B) Reduction C) Calcination D) Roasting

Answer»

B)  Reduction

34.

One of the main aim of conservation is to try and preserve the ______ we have inherited. A) Ecosystem B) BiodiversityC) Environment D) Universal

Answer»

B)  Biodiversity

35.

If (x + 1, y – 2) = (3,1), find the value of x and y.

Answer»

x + 1 = 3, 

∴ x = 2 

y – 2 = 1, 

∴ y = 3.

36.

Define valency

Answer»

Valency of an element is the combining capacity of the atoms of the element with atoms of the same or different elements. The combining capacity is explained in terms of their tendency to attain a fully - filled outermost shell 

37.

Conversion of electrical signal to chemical signal occurs at: A) Dendrite of a neuron B) Axon of a neuron C) Nerve ending of a neuron D) Cell body of a neuron

Answer»

C) Nerve ending of a neuron

38.

Which of the following reaction will never occur A) Cu + H2SO4 → CuSO4 + H2 B) Mg + H2SO4 → MgSO4 + H2 C) 2Al + 6HCl → 2AlCl3 + 3H2 D) Fe + 2HCl → FeCl + H2

Answer»

A) Cu + H2SO4 → CuSO4 + H2

39.

Define rancidity 

Answer»

Rancidity: When the food materials prepared in fats and oils are kept for a long time, they start giving unpleasant smell and taste, this is called rancidity.

This happens as follows : When the fats and oils present in food materials get oxidised by the oxygen (of air), their oxidation products have unpleasant smell and taste.The condition produced by aerial oxidation of fats and oils in foods marked by unpleasant smell and taste is called rancidity

40.

Convert 2π/3 radians  into degree measue.

Answer»

2π/3 = (2 x 180)/3 = 120°

41.

One of the main aim of conservation is to try and preserve the ______ we have inherited.A) EcosystemB) BiodiversityC) EnvironmentD) Universal

Answer»

One of the main aim of conservation is to try and preserve the Biodiversity we have inherited.

42.

Sodium carbonate is a basic salt because it is a salt of A) Strong acid and strong base B) Weak acid and weak base C) Strong acid and weak baseD) Weak acid and strong base

Answer»

D) Weak acid and strong base

43.

Why do we apply paint on iron articles?

Answer»

When an iron article remains exposed to moist air for a long time, its surface is covered with a brown, flaky (non-sticky) substance called rust.

To prevent rusting. iron articles are not allowed to come in contact with the damp air. This can be done by painting the iron articles. 

44.

What are autosomes and sex chromosomes?

Answer»

Human cell contain 23 pairs of chromosomes out of 23 pairs, 22 pairs are called autosomes, rest of 1 pair, which determine the sex of child is called sex chromosomes.

45.

(i) The main thinking part of brain is hind brain(ii) Centres of hearing, smell, memory, sight etc are located in forebrain.(iii) Involuntary actions like salivation, vomiting, blood pressureare controlled by the medulla in the hind brain(iv) Cerebellum does not control posture and balance of the body(a) (i) and (ii) (b) (i), (ii) and (iii)(c) (ii) and (iii) (d) (iii) and (iv)

Answer» (c) (ii) and (iii)
46.

Which of the following terms does not represent electrical power in a circuit?A) I2RB) IR2C) VID) V2/R

Answer»

The answer is B) IR2

47.

Write mirror formula

Answer»

Mirror formula 

1/v + 1/u = 1/f

48.

Sodium carbonate is a basic salt because it is a salt ofA) Strong acid and strong baseB) Weak acid and weak baseC) Strong acid and weak baseD) Weak acid and strong base

Answer»

D) Weak acid and strong base

49.

(i) Sudden action in response to something in the environment iscalled reflex action(ii) Sensory neurons carry signals from spinal cord to muscles(iii) Motor neurons carry signals from receptors to spinal cord(iv) The path through which signals are transmitted from a receptorto a muscle or a gland is called reflex arc(a) (i) and (ii) (b) (i) and (iii)(c) (i) and (iv) (d) (i) , (ii) and (iii)

Answer» (c) (i) and (iv)
50.

Write the names of two fossil fuels

Answer»

Coal and petroleum, are two fossil fuels.