This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the weight of a football and what is its diameter? |
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Answer» The weight of a football is from 14 ounce to 16 ounce arid its diameter is 27 to 28 inches. |
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| 2. |
What is the weight of air in a football? |
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Answer» The weight of air in a football is 0.6007 or 9.01505 pound per square inch. |
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| 3. |
Tell the length and height of the goal posts? |
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Answer» The goal posts are 8 yards in length and 8 feet in breadth. |
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| 4. |
At what distance should the players of the opposite team stand when the jkick takes place? |
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Answer» This distance should be 10 yards. |
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| 5. |
What are the four General Purpose register ? |
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Answer» The AX, BX, CX and DX are the general purpose 16-bit register. (i) AX is used as 16-bit accumulator. AX ->AH (For higher 8-bit) AL (For lower 8-bit) (ii) BX-> Serve as base register for the computation of memory address. (iii) CX-> Used as counter in case of multi-iteration . (iv) DX-> used for memory addressing when the data are transferred between i/o port and memory using certain i/o instruction. |
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| 6. |
The standard font determines the width of the text lines in the __________(a) Function(b) Package(c) Library(d) Margin |
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Answer» Right option is (d) Margin Explanation: For any open graphics device there is a standard font which will be used for any characters if no other font is specified (font). The standard font determines the width of the text lines in the margins. |
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| 7. |
What is throw-in? |
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Answer» When the ball goes out of the ground and the player of the opposite team throws the ball in from that very placg it is called throw-in. |
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| 8. |
How does the game of football start? |
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Answer» The game of football starts with a pass of ball. |
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| 9. |
Tell the time for a football game? |
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Answer» The time for a football game is 45-5-45 minutes. |
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| 10. |
What are the two interfacing I/O device ? |
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Answer» There are two schemes for allocation of addresses memories and input and output device : a. I/O mapped I/O scheme b. Memory mapped I/O schem |
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| 11. |
Exercise which doubles the metabolic rate is likely to at least double the A. Oxygen consumption. B. Cardiac output. C. Stroke volume. D. Arterial PCO2. E. Minute volume. |
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Answer» A. True Oxygen consumption is directly related to metabolic rate. B. False This rises more slowly than metabolic rate because tissue O2 extraction increases. C. False Since heart rate rises, stroke volume does not rise in proportion to metabolic rate. D. False This is little changed. E. True This rises proportionately more than metabolic rate. |
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| 12. |
Jejunal mucosal cells are similar to proximal convoluted tubular cells in that both A. Absorb glucose by a process linked with sodium absorption. B. Absorb chloride ions actively. C. Absorb amino acids actively. D. Are rich in mitochondria. E. Possess microvilli on their luminal border. |
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Answer» A. True In both cases, glucose absorption is blocked by phlorhizin. B. False In both, these follow passively the absorption of sodium. C. True Again the process requires active absorption of sodium. D. True Both expend considerable energy. E. True The two types of cell have very similar functions. |
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| 13. |
What is the memory limit in R for 64 bit system?(a) 8 TB(b) 9TB(c) 10TB(d) 16TB |
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Answer» Right choice is (a) 8 TB Easy explanation: 8TB is the memory limit for 64-bit system memory and 3GB is the limit for 32-bit system memory. A solid understanding of R’s memory management will help you predict how much memory you’ll need for a given task. |
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| 14. |
The ________ number of your package increases with subsequent releases of a package.(a) Function(b) Studio(c) Version(d) Sequence |
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Answer» The correct choice is (c) Version Explanation: The version number of your package increases with subsequent releases of a package, but it’s more than just an incrementing the counter of the way the number changes with each release can convey information. |
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| 15. |
What are pointer and index registers ? |
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Answer» Pointer and index register:- (i) The Pointer IP,BP and SP usually contain in offset within the code and stack (Back SP and BP ) segment. (ii) The index register are used as general purpose register as well as for offset storage in case of indexed. (iii)The register SI is generally used to store the offset of source data segment while the register Di used to store the offset of destination in data or extra segment. The index register are particularly useful for string manipulation. SP- Stack Pointer BP-Back Pointer SI- Source Index DI-Destination Index IP- Index Pointer |
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| 16. |
How many flags are put in a football game? |
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Answer» Six flags are fixed in a football game. Four of them are fixed at the corners of the ground and two are fixed at the end of the centre line at a distance of one yard each. |
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| 17. |
Point out the correct statement?(a) Empty vectors can be created with the vector() function(b) A sequence is represented as a vector but can contain objects of different classes(c) “raw” objects are commonly used directly in data analysis(d) The value NaN represents undefined value |
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Answer» Right answer is (a) Empty vectors can be created with the vector() function Explanation: A vector can only contain objects of the same class. |
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| 18. |
____________ function can be used to select the random sample of size ‘n’ from a huge dataset.(a) Simple()(b) Sample()(c) While()(d) Signal() |
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Answer» The correct answer is (b) Sample() Best explanation: Sample () function can be used to select a random sample of size ‘n’ from the huge dataset. R has a large number of in-built functions and also the user can create their own functions. |
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| 19. |
One mole of calcium ion A. Is equivalent to two osmoles of calcium. B. Has the same mass as two equivalents of calcium ion. C. Is present in one litre of a normal solution of calcium ions. D. Weighs 40 grams. E. Depresses the freezing point of water to the same extent as one mole of sodium ion. |
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Answer» A. False One mole of any ion in solution exerts one osmole of osmotic pressure. B. True Because calcium is divalent. C. False A normal solution has one equivalent weight of ion per litre. D. True This is the atomic weight in grams. E. True 1 osmole of a substance in 1 litre of water depresses the freezing point by 1.86°C. |
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| 20. |
On lying down there is a decrease in the A. Central venous volume. B. Total systemic peripheral resistance. C. Ventilation/perfusion ratio in lung apices. D. Vital capacity. E. Rate of formation of urine. |
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Answer» A. False Volume expands as blood shifts from veins in the lower extremities to the chest. B. True A reflex response to an increased central blood volume. C. True Apical perfusion increases during recumbency. D. True Due to vascular distension in the lungs and pushing up of the diaphragm. E. False An increase in central blood volume results in increased urine formation. |
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| 21. |
What types Segment register ? |
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Answer» Segment register:- CODE SEGMENT:- It is used for addressing a memory location in the code segment of the memory ,where the executable programmable is stored. DATA SEGMENT:- Data segment register points the data segment memory ,Where the data is reside. EXTRA SEGMENT:- It also refers to a segment which essentially is another data segment of the memory. So extra segment also contains data. STACK SEGMENT:- It is used for addressing stack segment of Memory i.e. memory which is used to store stacks data. It may be noted that all these segments are the logical segment .They may or may not be physically separated. |
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| 22. |
How many flags are in the Status Flags ? |
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Answer» Status Flags:- The 8086 has a 16 bit flag register (a) Condition code or status flags:-
(b) Machine cycle:-
(1) Carry Flag:- The flag register is set to 1 when there is unsigned overflow. When there is no overflow this flag is set 0. (2) Parity Flag:- The flag is set to be 1 when there is even no. of one bits in result and it 0 when there is odd no. of one bits. (3) Auxiliary Flag:- Set to be 1 when there is an unsigned overflow for low nibble (4 bits). (4) Zero Flag:- Set to be 1 when result is zero, for non-zero results this flag is set to 0. (5) Sign Flag:- Set to 1 when result is negative, when result is positive it is set to 0. (6) Trap Flag:- It is set; the processor enters the single step execution mode or a trap interrupt generated after execution of each instruction. (7) Direction Flag:- This is used string manipulation instruction D=0, then the string is processed beginning from lower address to the higher address. D=1, then the string is processed beginning higher address to the lower address. (8) Interrupt Flag:- This flag is set, the mask able interrupt recognized by the CPU otherwise they are ignored. (9) Overflow Flag:- This flag is set, if an overflow occurs i.e. if the result signed operation is large enough to accommodate in a destination register. |
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| 23. |
Attributes of an object (if any) can be accessed using the ______ function.(a) objects()(b) attrib()(c) attributes()(d) obj() |
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Answer» The correct choice is (c) attributes() Explanation: Not all R objects contain attributes, in which case the attributes() function returns NULL. |
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| 24. |
What is the use of instruction register ? |
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Answer» (i) The instruction pointer in 8086 acts as Program counter. (ii) It points to the address of the next instruction to be executed .it’s content is automatically incremented when the execution of program proceed further. |
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| 25. |
What is addressing mode and types ? |
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Answer» Addressing Modes : Addressing modes are an asset of the instruction set architecture in most CPU designs. The various addressing modes that are defined in a given instruction set architecture define how machine language instructions in that architecture identity the operand of each instruction. An addressing mode specifies how to calculate the effective memory address of an operand by using information held in register and/or constants contained within machine instruction or elsewhere. For 8085 there are five addressing modes. They are: (i) DIRECT ADDRESSING MODE In type of addressing mode the address of the operand or the data is given to the instruction itself. This type of mode is used to accept data from outside devices to store the data in the accumulator and send the data stored in the accumulator to the output devices. E.g. IN 02 (to accept the data from the port 02h and store the same in the accumulator) OUT 01H (send the data from the accumulator to the output port) LHLD address (load H-L pair direct.) (ii) REGISTER ADDRESSING MODE In type of addressing mode the address is provided through the registers. Here the operand is GPR. E.g. MOV Rd,Rs (move a copy of data from the source register to the destination register) ADD B (add the content of b to the accumulator and the value is stored in the accumulator) INR C (Increment the value of the register c by 1) (iii) REGISTER INDIRECT ADDRESSING MODE In type of addressing mode the address of the operand or the data is specified by a pair of register before the execution of the instruction itself. Here the address of the memory is not directly given in the instruction. The address of the memory resides in H-L pair and this has been already specified in an earlier instruction. E.g. LXI H, 8175; MOV B, M (move the data from memory specified by H-l pair to the register b) LXI H, 8763; ADD M (Add the content of memory specified of the H-L pair to the accumulator) (iv) IMMEDIATE ADDRESSING MODE in type of addressing mode the data is directly associated in the instruction itself. It loads immediate data to the destination provided in the instruction. E.g. MVI r. D8 (move an 8 it data directly to the register) ADI 62H (add 62 to the accumulator content and store the result in the accumulator) JMP address, JC address, CPI D8. (v) IMPLICIT ADDRESSING MODE There are certain instruction which are operated on the content of the accumulator. These types of construction don’t require any address of the operand. Eg. CMA (it finds the 1’s compliment of the data present in the accumulator and stores in accumulator) RAL (rotate the content of accumulator left through carry) RRC (rotate the content of accumulator right without carry) |
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| 26. |
The membrane potential of the neuron has a negative resting or equilibrium value is called ____________(a) Hyperpolarization(b) polarization(c) Hypolarization(d) Hypopolarization |
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Answer» Correct option is (a) Hyperpolarization To elaborate: The membrane potential of the neuron has a negative resting or equilibrium value. Making this more negative leads to a hyperpolarization which are trying to depolarize the membrane. |
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| 27. |
Which of the following merges two variables into one?(a) spread()(b) gather()(c) separate()(d) unite() |
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Answer» The correct option is (b) gather() Best explanation: The unite() function is a convenience function to paste together multiple variable values into one. |
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| 28. |
What are the 3 types of Instruction ?Explain with example ? |
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Answer» Instruction can be categorized in 3 parts: 1) One-byte instruction/ one word instruction 2) Two-byte instruction/two word instruction 3) Three-byte instruction/three word instruction ONE BYTE INSTRUCTION: This type of instruction requires one memory location. The 8 bit or 1 byte instruction code is called as opcodes that uniquely identifies the instruction. If the instruction is one byte then the timing diagram has only one machine cycle i.e. opcode fetch cycle. it has only one opcode. EX- CMA; MOV A,B; ADD C; SUB D; RLC . TWO BYTE INSTRUCTION: In this kind of instruction, the first byte is for the opcode and the second byte is for the operand or the code associated with the memory address. such instructions are stored in two consecutive memory locations. if the instruction is two byte, then it requires two machine cycle. The first machine cycle is for opcode fetch and the second machine cycle is either for memory read/memory write i/o read or i/o write. EX: MVI B,62; ADI 58; ORI 43; IN 89. THREE BYTE INSTRUCTION: In this type of instruction, the first byte is for opcode and the second and third byte is for an operand code associated with the memory address. Such instructions are stored in 3 consecutive memory locations. If the instruction is of three bytes, then it requires three machine cycles. The first machine cycle is for opcode fetch and the second and third machine cycle is either for memory read/memory write I/O read or I/O write. EX: LDA 8062; LXI H, 8057; JMP 7809. |
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| 29. |
Instruction format |
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Answer» Intel 8085 handles 8 bit of data as it is an 8 bit microprocessor. It is designed to process 8 bit of data at a time. If a 16 bit data has to be stored then they are stored in consecutive memory locations. There are various ways to specify data for an instruction:
E.g. ADI 07H, LXI 7051H etc.
Ex LDA 8582H, IN 02H etc.
Ex ADD B
Ex MOV D,E
Ex CMA, RRC, RAL. |
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| 30. |
What is instruction data format ? |
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Answer» 1. Every microprocessor has a different of instruction data format. The instruction format of each microprocessor depends upon its address, data and control bus. 2. Every instruction contains an operand and an opcode. 3. In typical microprocessor is organized in 8 bits, each of which has unique memory location in the physical memory. Each memory is specified by a 16 bit hexadecimal address. 4. Data is stored in the memory as 8 bit binary number arrangement of 8 bits of a stored data s shown below: 5. Instruction stored in first byte must be the opcode. |
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| 31. |
What is a checkpoint and When does it occur? |
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Answer» A Checkpoint is like a snapshot of the DBMS state. By taking checkpoints, the DBMS can reduce the amount of work to be done during restart in the event of subsequent crashes. |
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| 32. |
Write an SQL SELECT statement to display all the columns of the STUDENT table but only those rows where the Grade column is greater than or equal to 90. |
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Answer» SELECT * FROM STUDENT WHERE Grade >= 90; |
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| 33. |
What is instruction execution ? |
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Answer» The microprocessor performs operations by accepting instructions from the user. Every program consists of a sequence of instructions. The commands of n instruction set are called ‘mnemonics’. A command is understood by the CPU only when it is converted into equivalent single byte hexadecimal opcodes with or without one-byte or two byte data or address. An instruction consists of:- 1. Opcode (operational code) 2. Operand(Operational End) |
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| 34. |
Which of the following companies stopped making personal computers in 2005?1. Dell2. Acer3. IBM4. Asus |
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Answer» Correct Answer - Option 3 : IBM The correct answer is IBM.
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| 35. |
What is psychoneuroimmunology? |
Answer»
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| 36. |
What are life skills? List any two life skills. |
Answer»
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| 37. |
Operating System is1.System Software2.Application Software3. Generalised package4. Utility tool |
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Answer» Correct Answer - Option 1 : System Software The correct answer is System Software.
Some of the major types of Operating System-
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| 38. |
Differentiate between hostile aggression and proactive aggression. |
Answer»
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| 39. |
Which of the following is not a cybercrime?1. Spoofing2. Phishing3. Cyber Stalking4. Online gaming |
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Answer» Correct Answer - Option 4 : Online gaming The correct answer is Online gaming. Online gaming is not a cybercrime.
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| 40. |
What is the difference between arithmetic and logic unit (ALU) ? |
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Answer» ARITHMETIC AND LOGIC UNIT (ALU) • An ALU is a combinational circuit that performs arithmetic and logical operation on the data stored in accumulator. • Results of operation by ALU are placed back in the accumulator. • Typical operations performed by ALU includes add, shift/rotate, compare, increment, decrement, AND, OR, XOR, complement, clear, pre-set etc. • Apart from performing these operation, ALU also contains important information about certain conditions that occur during these mathematical operation. • These conditions i.e. occurrence of carry, borrow, zero, negative or even parity results are stored in register called flag register and the individual bits are called flag bits. • The number of bits is the most important factor determining the capabilities of the processor. Hence the size of ALU defines the size of the microprocessor. |
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| 41. |
What is SQL, and why is it important? |
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Answer» SQL stands for Structured Query Language, and is the most important data processing language in use today. It is not a complete programming language like Java or C#, but a data sublanguage used for creating and processing database data and metadata. All DBMS products today use SQL. |
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| 42. |
You have been given a set of tables with data and asked to create a new database to store them. When you examine the data values in the tables, what are you looking for? |
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Answer» (1) Multivalued dependencies, (2) Functional dependencies, (3) Candidate keys, (4) Primary keys and (5) Foreign keys. |
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| 43. |
Who is E.F. Codd, and why is he significant in the development of modern database systems? |
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Answer» While working at IBM, E.F. Codd created the relational database model. A paper he published in 1970 presented his ideas to the world at large. His work is the foundation for most of the DBMSs currently in use, and thus forms the basis for database systems as we know and use them today. |
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| 44. |
The indiscriminate exploitation of natural resources of a country is due to A. Industrialization B. Population explotion C. Globalization D. Consumerism |
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Answer» C. Globalization |
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| 45. |
Why do normalized tables require more complex SQL when SQL statements are used in application programs? |
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Answer» Tables that are normalized contain data that has been distributed among the tables, but which may need to be recombined to answer queries from an application. To recombine the data, the programmer will have to use subqueries and/or joins. These SQL structures are more complex to write than a simple SELECT statement. |
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| 46. |
Why is a database considered to be "self-describing"? |
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Answer» In addition to the users' data, a database contains a description of its own structure. This descriptive data is called "metadata." |
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| 47. |
Which industry is the basis of all other industries. |
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Answer» Iron and steel industry. |
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| 48. |
According to which land tax system of the British, the farmer was directly linked to East India Company? |
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Answer» Ryotwari system |
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| 49. |
What is the multivalue, multicolumn problem? Include an example not used in the text. |
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Answer» The multivalue, multicolumn problem occurs when a table is designed to include multiple columns that hold variations of one type of attribute data. One example is where boat owners have the names of their boats stored as BOAT_01, BOAT_02 and BOAT_03. |
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| 50. |
What is a DBMS? |
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Answer» DBMS stands for Database Management System. A DBMS receives requests from applications and translates those requests into actions on a specific database. A DBMS processes SQL statements or uses other functionality to create, process and administer databases. |
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