This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Voltmeter measures |
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Answer» voltmeter, instrument that measures voltages of either direct or alternating electric current on a scale usually graduated in volts, millivolts (0.001 volt), or kilovolts (1,000 volts). |
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| 2. |
S. I. unit of surface density of charge is -(A) Coulomb x metre(B) Coulomb x (metre)2 (C) Coulomb x \(\frac{1}{\text{metre}}\)(D) Coulomb x \(\left(\frac{1}{\text{(metre)}}\right)^2\) |
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Answer» Correct answer is (D) Coulomb x \(\left(\frac{1}{\text{(metre)}}\right)^2\) |
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| 3. |
Shall we request the committee ____ our suggestion again? A) consider B) considering C) to consider D) considerd |
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Answer» Correct option is C) to consider |
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| 4. |
The value of ∈0 is -(A) 8.85 x 10-12 F/m(B) 8.85 x 10-13 F/m(C) 8.85 x 10-16 F/m(D) 8.85 x 10-20 F/m |
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Answer» Correct answer is (A) 8.85 x 10-12 F/m |
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| 5. |
Which of the following is correct for electric intensity at a distance ‘r’ from charge q ?(A) \(E=\frac{1}{4\pi \in_0}.\frac{q}{r}\)(B) \(E=\frac{1}{4\pi \in_0}.\frac{q}{r^2}\)(C) \(E=\frac{1}{4\pi \in_0}.\frac{q^2}{r}\)(D) \(E=\frac{1}{4\pi \in_0}.\frac{q}{r^3}\) |
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Answer» Correct answer is (B) \(E=\frac{1}{4\pi \in_0}.\frac{q}{r^2}\) |
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| 6. |
Which series comes in visible region of hydrogen spectrum? (a) Lyman series(b) Balmer series(c) Paschen series(d) Brackett series |
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Answer» Correct answer is (b) Balmer series |
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| 7. |
Write the decimal number 25 in binary.(a) (1100)2(b) (1001)2(c) (11001)2(d) (11101)2 |
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Answer» Correct answer is (c) (11001)2 |
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| 8. |
Statement -I: Photon cannot be deflected by magnetic and electric field.Statement II: Rest mass of photon is zero. Of these statements: (a) Both the Statements are true and Statement-II is the correct explantion of Statement -I(b) Both the statements are true,but Statement -II is not the correct explanation of Statement -I(c) Statement -I is true, but Statement -II is false.(d) Statement I is false, but Statement -II is true. |
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Answer» (b) Both the statements are true,but Statement -II is not the correct explanation of Statement -I |
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| 9. |
The equivalent capacity between A and B is(a) (20/9)μF(b) 9μF(c) 1 μF(d) (1/9)μF |
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Answer» Correct answer is (a) (20/9)μF |
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| 10. |
The electric flux over the surface of a spere if it is charged with 10μC is-(a) 36π x 104 Nm2/C (b) 36π x 10-4 Nm2/C (c) 36π x 106 Nm2/C (d) 36π x 106 Nm2/C |
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Answer» Correct answer is (a) 36π x 104 Nm2/C |
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| 11. |
Brewster's law is(a) μ = sin ip(b) μ = cos ip(c) μ = tan ip(d) μ = tan2 ip. |
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Answer» Correct answer is (c) μ = tan ip |
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| 12. |
Figure shows an electrical calorimeter to determine specific heat capacity of an unknown liquid, First of all, the mass of empty calorimeter (a copper container) is measured and suppose it is `m_(1)`. Then the unknown liquid is poured in it. Now the combined mass of calorimeter+liquid system is measured and let it be `m_(2)`. So the mass of liquid is `(m_(2)-m_(1))`. Initially both were at room temperature (`theta_(0)`). Now a heater is immeresed in if for time interval `t`. The voltage drop across the heater is `V` and current passing through it is `I`. Due to heat supplied, the temperature of both the liquid and calorimeter will rise simultaneously. After `t sec`, heater was switched off, and final temperature is `theta_(r)`. If there is no heat loss to surroundings. Heat supplied by the heater=Heat absorbed by the liquid+heat absorbed by the calorimeter `(VI)t=(m_(2)-m_(1))S_(1)(theta_(f)-theta_(0))+m_(1)S_(c)(theta_(f)-theta_(0))` The specific heat of the liquid `S_(1)=(((VI)t)/(theta_(f)-theta_(0))-m_(1)S_(c))/((m_(2)-m_(1)))` Radiation correction: There can be heat loss to environment. To compensate this loss, a correction is introduced. Let the heater was on for `t sec`, and then it is switched off. Now the temperature of the mixture falls due to heat loss to environment. The temperature of the mixture is measured `t//2 sec`. after switching off. Let the fall in temperature during this time is `varepsilon` Now the corrected final temperature is taken as `theta_(f)=theta_(f)+varepsilon` If mass and specific heat capacity of calorimeter is negligible, what would be maximum permissible error in `S_(l)`. Use the date mentioned below. `m_(1)to`, `S_(l)to0`, `m_(2)=1.00kg`, `V=10.0V`, `I=10.0A`, `t=1.00xx10^(2)sec`, `theta_(0)=15^(@)C`, Corrected `theta_(1)=65^(@)C`A. `4%`B. `5%`C. `8%`D. `12%` |
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Answer» Correct Answer - C If `m_(1) to 0`, `S_(l) to 0`, `S_(l)=(VIt)/(m_(2)(theta_(f)-theta_(0)))` `(dS_(l))/(S_(l))=(DeltaV)/(V)+(DeltaI)/(I)+(Deltat)/(t)+(Deltam_(2))/(m_(2))+(Deltatheta_(r)+Deltatheta_(0))/(theta_(r)-theta_(0))` `=(0.1)/(10.0)+(0.1)/(10.0)+(0.01xx10^(2))/(1.00xx10^(2))+(0.01)/(1.00)+(1+1)/(50)=8%` |
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| 13. |
Diamagnetic substances have relative permeability_____________(a) Greater than 1(b) Less than 1(c) Equal to 1(d) Zero |
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Answer» Correct choice is (b) Less than 1 For explanation: A diamagnetic material creates a magnetic field opposing that of the external magnetic field and it repels the external magnetic field. Hence it has relative permeability less than 1. |
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| 14. |
Which of the following is correct ?(A) (4)10 = (100)2 (B) (4)10 = (10)2 (C) (4)10 = (1001)2 (D) (4)10 = (111)2 |
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Answer» Correct answer is (A) (4)10 = (100)2 |
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| 15. |
Number of neutrons in \(^{238}_{92}U\) will be -23892U(A) 92 (B) 238 (C) 146 (D) 330 |
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Answer» Correct answer is (C) 146 |
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| 16. |
In `u-v` method, we require the distance between object or image from the pole (vertex) of the mirror (actual distance). But practically we measure the distance between the indices `A` and `B`. (Observed distance). Which need not exactly co-inside with object and pole, there can be a slight mismatch called index error, which will be constant for every observation. Index error=Observed distance-Actual distance(Just like zero error in screw guage, it is the excess reading). To determine index error, mirror and object needle and placed at arbitary position. For measuring actual distance, a knitting needle is just fitted between the pole of mirror and object needle `O`. The length of knitting needle will give the actual object distance while the seperation between indices `A` and `B` at that instant is the observed distance. So index error is- `e=`Observed distance-Actual distance `=` Separation between indices `A` and `B`- Length of knitting neddle once we get `e`, in every observation, we get Actual distance=Observed distance (separation between the indices)- Excess reading(e) There is an another term, Index corraction which is invert of index error. Index correction=-index error In some observation, the observed object distance (Separation between indices of object needle and mirror) is `30.2cm`, and the observed image distance is `19.9cm`. Using index correction from previous two equations, estimate the focal distance of the concave mirror!A. `36cm`B. `20cm`C. `12cm`D. `8cm` |
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Answer» Correct Answer - C `u=30.2-0.2` (excess reading) `=30.0 cm` `v=19.9-(-0.1)` (excess reading) `=20.0 cm` `(1)/(f)+(1)/(v)+(1)/(u)impliesf=12.0cm` |
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| 17. |
In `u-v` method, we require the distance between object or image from the pole (vertex) of the mirror (actual distance). But practically we measure the distance between the indices `A` and `B`. (Observed distance). Which need not exactly co-inside with object and pole, there can be a slight mismatch called index error, which will be constant for every observation. Index error=Observed distance-Actual distance(Just like zero error in screw guage, it is the excess reading). To determine index error, mirror and object needle and placed at arbitary position. For measuring actual distance, a knitting needle is just fitted between the pole of mirror and object needle `O`. The length of knitting needle will give the actual object distance while the seperation between indices `A` and `B` at that instant is the observed distance. So index error is- `e=`Observed distance-Actual distance `=` Separation between indices `A` and `B`- Length of knitting neddle once we get `e`, in every observation, we get Actual distance=Observed distance (separation between the indices)- Excess reading(e) There is an another term, Index corraction which is invert of index error. Index correction=-index error To find index error for `v`, when the same knitting needle is adjusted between the pole and the image needle, the separation between the indices of image needle and mirror was found to be `19.9cm`. Index error for `v` isA. `0.1cm`B. `-0.1cm`C. `0.2cm`D. `-0.2cm` |
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Answer» Correct Answer - B `e=19.9cm-20.0cm=-0.1cm` |
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| 18. |
In `u-v` method, we require the distance between object or image from the pole (vertex) of the mirror (actual distance). But practically we measure the distance between the indices `A` and `B`. (Observed distance). Which need not exactly co-inside with object and pole, there can be a slight mismatch called index error, which will be constant for every observation. Index error=Observed distance-Actual distance(Just like zero error in screw guage, it is the excess reading). To determine index error, mirror and object needle and placed at arbitary position. For measuring actual distance, a knitting needle is just fitted between the pole of mirror and object needle `O`. The length of knitting needle will give the actual object distance while the seperation between indices `A` and `B` at that instant is the observed distance. So index error is- `e=`Observed distance-Actual distance `=` Separation between indices `A` and `B`- Length of knitting neddle once we get `e`, in every observation, we get Actual distance=Observed distance (separation between the indices)- Excess reading(e) There is an another term, Index corraction which is invert of index error. Index correction=-index error To find index error for `u`, when a knitting needle of length `20.0cm` is adjusted between pole and object needle, the sepertion between the indices of object needle and mirror was observed to be `20.2cm`. Index corraction for u isA. `-0.2cm`B. `0.2cm`C. `-0.1cm`D. `0.1cm` |
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Answer» Correct Answer - B Index error(excess reading)=Observed reading-Actual reading `=20.2-20.0=0.2cm` |
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| 19. |
Bulk modules of elasticity for isobaric process isA. equal to that of isochoric process.B. equal to that of isothermal process.C. zeroD. infinite |
| Answer» Correct Answer - C | |
| 20. |
Equal temperature difference exists between the ends of two metallic rods 1 and 2of equal length. Their thermal conduetivities are `K_(1)` and `K_(2)` and cross sectional areas are respectively `A_(1)` and `A_(2)`. The condition for equal rate of heat transfer will be-A. `K_(1)A_(2) =K_(2)A_(1)`B. `k_(1)^(2)A_(2)=k_(2)^(2)A_(1)`C. `K_(1)A_(1) =K_(2)A_(2)`D. `K_(1)A_(1)^(2)=K_(2)A_(2)` |
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Answer» Correct Answer - C `(K_(1)A_(1)Delta0)/(l)=(K_(2)A_(2)Delta0)/(l)` `rArr K_(1)A_(1)=K_(2)A_(2)` |
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| 21. |
Current through the ideal diode is - |
| Answer» Correct Answer - A | |
| 22. |
The output characteristics of a transistor are shown in the figure. When \( V_{C E} \) is \( 10 V \) and \( I_{C}=4.0 mA \), the value of \( \beta_{d c} \) is:1. 2002. 2503. 3004. 150 |
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Answer» β = ΔIC / ΔIB ΔIB = 30 – 20 IC = 4mA (reference value given) = 10 μA ΔIC = = 4.5 – 3 = 1.5mA β = [1.5 × 10-3] / [10 × 10-6] = 150 |
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| 23. |
What is the base resistance `R_(B)` in the circuit as shown in figure , if `beta_(d.c.) = 90, V_(BE) = 0.7 V, V_(CE) =4V?` A. `29 K Omega`B. `82 K Omega`C. `108 K Omega`D. `55 K Omega` |
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Answer» Correct Answer - B `V_(CE)=I_(c)xx2 xx10^(3)+9=4` `I_(c)(5xx10^(-3))/(2) rArr2.5 xx 10^(-3)` `beta=90 (I_(C))/(I_(B))` `I_(beta)=(2.5 xx10^(-3))/(90)` `V_(BE)=-I_(B)R_(B) +3` `0.7 + (2.5 xx 10^(-3))/(50) R_(B) =3` `R_(B)=(2.3xx90)/(2.5xx10^(-3))` `=(2.3 xx 10^(-3))/(25) xx 10^(4)` `rArr (2070)/(25) xx 10^(3)rArr 82 K Omega` |
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| 24. |
From the given figure, name all pairs of parallel lines? |
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Answer» The pairs of parallel lines are l||m, m||n and n||l |
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| 25. |
To get maximum current through a resistance of `2.5Omega,` one can use m rows of cells, each row having n cells. The internal resistance of each cell is `0.5 Omega` what are the values of n and m, if the total number of cells is 45.A. 3, 15B. 5, 9C. 9,5D. 15,3 |
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Answer» Correct Answer - D d. For maximum current, net resistance of cells must be equal to `2.5 Omega` i.e., `(n(0.5))/m = 25`………….(i) and `m xx n = 45` …………..(ii) Solving we get n = 15, m= 3 . |
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| 26. |
Consider the situation shown in . The wire PQ has a negligible resistance and is made to slide on the three rails with a constant speed of `5 cm s^(-1)` . Find the current in the `10 Omega` resistor when the switch S is thrown to (a) the middle rail (b) the bottom rail. A. zeroB. 2 mAC. 3 mAD. None of these |
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Answer» Correct Answer - D Here `B=1T, v=5 xx 10^(-2) m//s, R=1 Omega` When the switch is thrown to the middle rail `E=Bvl` `=1 xx 5 xx 10^(-2) V` `=10 xx 10^(-4) =10^(-3)V` Current in the `10 Omega` resistor =`E//R` `(10^(-3))/(10) =10^(-4) = 0.1 mA` The switch is thrown to the lower rail `E=Bvl` `=1 xx 5 xx 10^(-2) xx 4 xx 10^(2) = 20 xx 10^(-4)V` Current `=(20 xx 10^(-4))/(10) = 2 xx 10^(-4) = 0.2 mA`. |
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| 27. |
Any charge given to the battery when taken off the vehicle is called : (a) bench charge (b) step charge (c) float charge (d) trickle charge |
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Answer» (a) bench charge |
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| 28. |
Floating battery systems are widely used for : (a) power stations (b) emergency lighting (c) telephone exchange installation (d) all of the above |
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Answer» (d) all of the above |
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| 29. |
The sediment which accumulates at the bottom of a lead-acid battery consists largely of : (a) lead-peroxide (b) lead-sulphate (c) antimony-lead alloy (d) graphite |
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Answer» (c) antimony-lead alloy |
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| 30. |
The reduction of battery capacity at high rates of discharge is primarily due to : (a) increase in its internal resistance (b) decrease in its terminal voltage (c) rapid formation of PbSO4 on the plates (d) non-diffusion of acid to the inside active materials. |
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Answer» (c) rapid formation of PbSO4 on the plates |
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| 31. |
A dead storage battery can be revived by : (a) a dose of H2SO4 (b) adding so-called battery restorer (c) adding distilled water (d) none of the above |
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Answer» (d) none of the above |
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| 32. |
As compared to a lead-acid cell, the efficiency of a nickel-iron cell is less due to its : (a) lower e.m.f. (b) smaller quantity of electrolyte used (c) higher internal resistance (d) compactness. |
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Answer» (c) higher internal resistance |
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| 33. |
During the charging and discharging of a nickel iron cell :(a) its e.m.f. remains constant (b) water is neither formed nor absorbed (c) corrosive fumes are produced(d) nickel hydroxide remains unsplit |
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Answer» (b) water is neither formed nor absorbed |
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| 34. |
Sulphation in a lead-acid battery occurs due to: (a) trickle charging (b) incomplete charging (c) heavy discharging (d) fast charging |
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Answer» (b) incomplete charging |
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| 35. |
As compared to constant-current system, the constant-voltage system of charging a lead-acid cell has the advantage of :(a) avoiding excessive gassing (b) reducing time of charging (c) increasing cell capacity (d) both (b) and (c). |
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Answer» (d) both (b) and (c). |
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| 36. |
The active materials of a nickel-iron battery are. (a) nickel hydroxide (b) powdered iron and its oxides (c) 21% solution of caustic potash (d) all of the above. |
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Answer» (d) all of the above. |
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| 37. |
The capacity of a lead-acid cell does NOT depend on its : (a) rate of charge (b) rate of discharge (c) temperature (d) quantity of active material |
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Answer» (a) rate of charge |
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| 38. |
The capacity of a cell is measured in : (a) watt-hours (b) watts (c) amperes (d) ampere-hours |
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Answer» (d) ampere-hours |
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| 39. |
In an isosceles right angled triangle, the perimeter is 20 metre. Find its area. (a) 9,320m2 (b) 8,750m2 (c) 7,980m2 (d) 8,000m2 (e) None of these |
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Answer» (a) In an isosceles right angled triangle, |
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| 40. |
√(x-1/x-2 |
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Answer» (-infinty,1]U(2, infinity) |
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| 41. |
If \( f(x)=x^{2} \) and \( g(x)=4 x+1 \) be two real functions then find \( b(i)(f+g)(x) \) (ii) \( (f-g)(x) \), (iii) \( (f \cdot g)(x) \) |
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Answer» \(f(x) = x^2\) \(g(x) = 4x + 1\) (i) \((f + g) (x) = f(x) + g(x) = x^2 + 4x +1\) (ii) \((f - g)(x) = f(x) - g(x) = x^2 - (4x + 1) = x^2 - 4x - 1\) (iii) \((f.g)(x) = f(x). g(x) = x^2 (4x + 1)\) |
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| 42. |
Grandmother lets the children do anything they like, so they are completely ________. A) spoilt B) damaged C) hurt D) injured E) destroyed |
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Answer» Correct option is A) spoilt |
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| 43. |
The order Orthoptera contains: a. Bed bugs and stink bugs b. Chewing and sucking lice c. Roaches and mantids d. Crickets and grasshoppers |
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Answer» The order Orthoptera contains Crickets and grasshoppers. |
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| 44. |
Q5. Assertion (A): Change in Profit-sharing Ratio is not a reconstitution of partnership.Reason (R): Winding-up of the firm is reconstitution of business. |
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Answer» please answer this |
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| 45. |
The living world MCQ pdf |
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Answer» 1. In majority of higher animals and plants, _____ and _____ are mutually exclusive events. A. growth; nutrition 2. A group of plants and animals with similar traits of any rank is A. Taxon 3. Energy flow and energy transformation in a living system follow A. Biogenetic law 4. The defining characteristic of living beings is A. They reproduce 5. In multicellular organisms, _____ refers to the production of progeny possessing features more or less similar to those of parents. A. growth 6. Families are characterized on which of the following features of plant species? A. External morphology 7. The sum total of all the chemical reactions occurring in our body is known as A. metabolism 8. Nicotiana is a ————- A. Species 9. The scientific name of mango is A. Mangifera indica 10. Cell division occurs _______ in plants and _______ in animals. A. continuously, only upto a certain age Answer: 1. Correct Answer : (C) growth; reproduction 2. Answer: A. Taxon 3. Answer: B. Law of thermodynamics 4. Answer: C. They respond to external stimuli 5. Answer: B. reproduction 6. Answer: C. Vegetative and reproductive parts Explanation: A family is a subdivision of an order consisting of a group of related genera which in turn are composed of groups of related species. Families are characterized on the basis of vegetative and reproductive parts of the plants species. 7. Answer: A. metabolism Explanation: All living organisms are continuously making or breaking biomolecules, such conversions are due to chemical reactions, and sum total of all such chemical reactions, occurring in the body is called metabolism. Each metabolic pathway in the cell is tightly regulated by enzymes. 8. Answer: C. Genus 9. Answer: C. Mangifera indica 10. Answer: A. continuously, only upto a certain age |
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| 46. |
The length of the perpendicular from the origin to the plane \(\vec {r} .(3\vec{i}+4\vec{j}+12\vec{k}) = 26\) is _______. (a) 26 (b) 26/163(c) 2 (d) 1/2 |
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Answer» The correct answer is : (c) 2 |
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| 47. |
The asymptote to the curve y2 (1 + x) = x2 (1 – x) is _______. (a) x = 1 (b) y = 1 (c) y = -1 (d) x = -1 |
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Answer» The correct answer is : (d) x = -1 |
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| 48. |
If `f(x) = { 3 + |x-k|, x leq k; a^2 -2 + sin(x-k)/(x-k), xgtk}` has minimum at x =k, then show that `|a| >2`.A. `aepsilonR`B. `|a|lt2`C. `|a|gt2`D. `1lt|a|lt2` |
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Answer» Correct Answer - C `f(k)=3` `f(k+h)=a^(2)-2+(sinh)/himplieslim_(hrarro) f(k+h)=a^(2)-1` `lim_(xrarr0) f(k-h)=lim_(hrarr0)(3+|k-h-k|)=lim_(hrarr0)(3+|-h|)=3` `impliesa^(2)-1gt3` `a^(2)gt4rarr|a|gt2` |
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| 49. |
Find the middle term in the expansion \(\rm \left ( 4x-\frac{x^3}{2} \right ) ^9\)1. \({}^9C_{4}\ 4^3\ x^{17}\)2. \(- {}^9C_{5}\ 2^3\ x^{19}\)3. Both 1 and 24. None of these |
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Answer» Correct Answer - Option 3 : Both 1 and 2 Formula Used: General Term in the expansion (x - y)n = Tr+1 = (-1)r × nCr × xn-r × yr Concept: The middle term of the expansion of (x + a)n depends upon the value of n. (i) When n is even the total number of terms in the expansion of (x + a)n is n+1(odd). So, there is only one middle term, i.e \(\rm\left ( \frac{n+1}{2} \right)\)th term is the middle term. (ii) When n is odd The total number of terms in the expansion of (x + a)n is n+1(even). So, there is two middle term, i.e., \(\rm\left ( \frac{n+1}{2} \right )\)th and \(\rm\left ( \frac{n+3}{2} \right )\)th term are two middle terms. Calculation: The number of terms in the expansion of \(\rm \left ( 4x-\frac{x^3}{2} \right ) ^9\) is 10(even). So there are two middle terms. i.e. \(\rm\left ( \frac{9+1}{2} \right )\)th and \(\rm\left ( \frac{9+3}{2} \right )\) th terms. They are given by T5 and T6. Tr+1 = nCrxn-rar Required term T5 = T4+1 = 9C4(4x)5(-x3/2)4 \(\Rightarrow \rm T_{5}= {}^9C_{4}4^5x^5\left ( \frac{1}{2^4} \right )x^{12}\) \(\Rightarrow \rm T_{5}= {}^9C_{4}4^3x^{17}\) T6 = T5+1 = 9C5(4x)4(-x3/2)5 \(\Rightarrow \rm T_{6}= -{}^9C_{5}4^4x^4\left ( \frac{1}{2^5} \right )x^{15}\) \(\Rightarrow \rm T_{6}=- {}^9C_{5}\left ( \frac{2^8}{2^5} \right )x^{19}\) \(\Rightarrow \rm T_{6}=- {}^9C_{5}\ 2^3\ x^{19}\) ∴ The 3rd option is correct option. |
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| 50. |
Rajdhani Express covers a distance of \( 540 km \) between New Delhi and Kanpur in 4 hours 30 minutes. Its speed was ......1) \( 120 km \) / hour 2; \( 142 m / sec \)3) \( i 26 km / \) hour4) \( 124 km / hol r \) |
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Answer» Answer : a)120km/hr Explanation : GIven, Distance covered by Rajdhani Express = 540km Time taken = 4.5hrs Speed = Distance/Time = 540/4.5 = 120km/hr |
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