Explore topic-wise InterviewSolutions in Current Affairs.

Economic geography is the branch of Human geography subject. 

Haryana has lowest sex ratio in India.

From population point of view India gets its rank in the world Second.

(a)Knoll 

(b) Spur 

(c) Col or Saddle 

(d) Ridge

1. the gulf of kambhat on wrest coast in Gujarat: 

2. sundarbans in the West Bengal on the East coast. 

3. lakshadweep and Andaman nicobar islands.

According to 2011 female literacy percentage in India is 65.46.

1. A rich hinter land of the Ganga and Brahmaputra plains. 

2. Availability of raw materials like jute, cotton, tea, minerals etc. 

3. Cheap labour from Bihar and Odisha. 

4. Availability of vast market in and around Kolkata.

The correct answer is Both 1 and 2.

• According to Article 293 of the Indian Constitution:
  1. Borrowing by States subject to the provisions of this article, the executive power of a State extends to borrowing within the territory of India.
  2. The Government of India may, subject to such conditions as may be laid down by or under any law made by Parliament, make loans to any State.
  3. A State may not without the consent of the Government of India raise any loan if there is still outstanding any part of a loan that has been made to the State by the Government of India.
• Hence, statements 1 and 2 both are correct.

The correct answer is Karan Singh.

• First Dronacharya Award Winner - Karan Singh, Bobby George (Athletics), D.E Azad (Cricket), Rajinder Singh (Hockey), Saeed Mohammuddin (Football), Sham Sunder Rao (Volleyball).

• Guru Dronacharya Award Winner from Rajasthan:
  • Shri Karna Singh
  • Mr Shyamsunder Rao
  • Mr Anup Kumar
  • Mr Maha Singh
  • Mr RD Singh
  • Mr Virendra Poonia
  • Shri Sagarmal Dhayal 

• Dronacharya award:
  • This award is given to those coaches who have successfully trained sportspersons or team and enable them to achieve outstanding results in international competitions.
  • This eminent award was started in the year 1985.
  • It is given to coaches for their hard work to produce top-level sportspersons.
  • This award is named after the legendary guru or teacher ‘Dronacharaya’.
  • In this award, the coach is given five lakh rupees cash, the scroll of honour, and a statue of guru Dronacharaya.

The Correct Answer is 1985.

• The Dronacharya Award was instituted in 1985.
• These awards are given by the Government of India for Excellency in the field of sports coaching.
• The award is given only to the disciplines included in the events like Olympic Games, Paralympic Games, Asian Games, Commonwealth Games, World Championship, and World Cup along with Cricket, Indigenous Games, and Parasports.

The correct answer is Uttarakhand.

• It is a high mountain pass located in the Himalayan Mountains of Uttarakhand.

• The Mana Pass which is also known as Chirbitya Pass is one of the highest motor vehicle-accessible passes in the world.

• Mana Pass is located within Nanda Devi Biosphere Reserve in Uttarakhand.
• Mana is the last village in India before the Mana Pass.

\(\frac{3}{12} -\frac{1}{3}\)

\(=\frac{3\times1-1\times4}{12}\)

\(=\frac{3-4}{12}\)

\(=\frac{3-4}{12}\)

\(=\frac{-1}{12}\)

\(\frac3{25}=\frac3{25}\times\frac{63}{63}=\frac{189}{1575}\)

\(\frac35 = \frac35\times\frac{315}{315}=\frac{945}{1575}\)

\(\frac3{15} = \frac3{15}\times\frac{105}{105}=\frac{315}{1575}\)

\(\frac3{35} = \frac3{35}\times\frac{45}{45}=\frac{135}{1575}\)

\(\frac3{45} = \frac3{45}\times\frac{35}{35}=\frac{105}{1575}\) 

\(\because\) \(\frac{105}{1576}<\frac{35}{1575}<\frac3{25}<\frac3{15}<\frac35\) 

Alternate method:

\(\because\) 5 < 15 < 25 < 35 < 45

⇒ 1/45 < 1/35 < 1/25 < 1/15 < 1/5

⇒ 3/45 < 3/35 < 3/25 < 3/15 < 3/5

Answer (a) Both the statements are true and Statement It is the correct explanation of statement I

Servomotor :

The servo system is the one, in which the output is some mechanical variable such as position, velocity or acceleration. The motors used in the servo systems are called servomotors. These motors are usually coupled to the output shaft for power matching. 

There are two types of servo motors. 

1. DC Servomotors 

2. AC Servomotors

D. parabolic

A. strikes the plane at the same time as the other body

D. a constantly increasing downward velocity

C. four times as great 

B. a frame attached to a particle on which there are no forces

Let y = tan^–1\(\left[\left(\frac{\sqrt{1+\mathrm x^2}}{\mathrm x}\right)^{-1}\right]\)

let x = tan z

⇒ \(\frac{d\mathrm x}{dz}=\sec^2z\)   (By differentiating w.r.t z)

⇒ \(\frac{dz}{d\mathrm x}\) \(=\frac{1}{\sec^2z}\) 

\(=\frac{1}{1+\tan^2z}=\frac{1}{1+\mathrm x^2}\) .................(i)

Then y = tan^–1\(\left[\left(\frac{\sqrt{1+\tan^2z}}{\tan z}\right)^{-1}\right]\)

\(=\tan^{-1}\left[\left(\frac{\sec z}{\tan z}\right)^{-1}\right]\)

\(=\tan^{-1}\left[\frac{\tan z}{\sec z}\right]\) \(=\tan^{-1}\left(\frac{\sin z}{\cos z}\times \cos z\right)\)

\(=\tan^{-1}(\sin z)\) \(=\tan^{-1}\left(\tan \frac{z}{\sqrt{1-z^2}}\right)\)

⇒ y = \(\frac{z}{\sqrt{1-z^2}}\) .........(ii)

Differentiate y w.r.t z, we get

\(\frac{dy}{dz}=\frac{\sqrt{1-z^2}\times 1-z\times \frac{-2z}{2\sqrt{1-z^2}}}{(1-z^2)}\)

\(=\frac{1-z^2+z^2}{(1-z^2)^{\frac{3}{2}}}\)

⇒ \(\frac{dy}{dz}=\frac{1}{(1-z^2)^{\frac{3}{2}}}\) ...........(iii)

Now, \(\frac{dy}{d\mathrm x}\) \(=\frac{dy}{dz}.\frac{dz}{d\mathrm x}\)

\(=\frac{1}{(1-z^2)^{\frac{3}{2}}}\times \frac{1}{1+\mathrm x^2}\)  (From equations (i) and (iii))

\(=\frac{1}{(1+\mathrm x^2)(1-(\tan^{-1}\mathrm x)^2)^{\frac{3}{2}}}\) (\(\because\) x = tan z ⇒ z = tan^-1x)

Alpha = -5 , Beta

(2x-3) (x+5) = 0

2x²+10x-3x-15 = 0

2x²+7x-15 = 0

Therefore, a = 2, b = 7, c = -15

We know that,

Alpha * Beta = c/a

-5 * Beta = -15/2

Beta = -15/2*-5

Beta = -15/-10 i.e Beta = 15/10

Therefore, Beta = 1.5 or 3/2

Given equation is x³ - 6x + 3 = 0

let f(x) = x³ - 6x + 3

Now, f(2) = 2³ - 6 x 2 + 3

= 8 - 12 + 3

= 11 - 12 

= -1<0

And f(3) = 3³ - 6 x 3 + 3

= 27 - 18 + 3

= 12 > 0

Thus, f(2) f(3) > 0

Therefore, the root of the equation x³ - 6x + 3 = 0 lies between 2 and 3

y = 2sin 2x – 5cos 2x

Differentiate y w.r.t x, we get

\(\frac{dy}{d\mathrm x}\) = 4cos 2x + 10sin 2x

Differentiate \(\frac{dy}{d\mathrm x}\) w.r.t x, we get

\(\frac{d^2y}{d\mathrm x^2}\) = –8sin 2x + 20 cos2x

= –4(2 sin2x – 5cos2x)

= –4y

⇒ \(\frac{d^2y}{d\mathrm x^2}\) + 4y = 0

Hence proved

The maximum value of the probability of an event will always be 1.

Shear stress, force tending to cause deformation of a material by slippage along a plane or planes parallel to the imposed stress. The resultant shear is of great importance in nature, being intimately related to the downslope movement of earth materials and to earthquakes.

C₁= 16 mF

V₁= 20V V₂=10V

C₂= C

Common potential V=14v

V = C₁V₁-C₂V₂/C₁+C₂

14= 16*20-C*10/16+C

14(16+C)= 16*20-C*10

224+14C= 320- 10C

320-224= 14C+10C

96/24 = C

C= 4 mF

Answer: 4 m/s

v=ds/dt

v=ds/dt at t=3

Slope=y/x=8/2

=4 m/s