This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which are the local bodies in Karnataka? |
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Answer» Zilla Panchayat, Taluk Panchayat and Gram Panchayat. |
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| 2. |
Two straight infinitely long wires are fixed in space so that the current in the left wire is 2 A and directed out of the plane of the page and the current in the right wire is 3 A and directed into the plane of the page. In which region(s) is/are there a point on the x-axis, at which the magnetic field is equal to zero due to these currents carrying wires? Justify your answer. |
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Answer» In region-I: Magnetic field due to 2A and 3A current wire is in opposite direction. In region-II:- Here, also magnetic field due to 2A and 3A currents wire is in opposite direction. But, it is highly probable, in region I, that we can have neutral points, because B1 = \(\frac{2\mu_o}{2\pi R_1}\) ; B2 = \(\frac{3\mu_o}{2\pi R_2}\) for region I, R2 > R1 and I2(3A) > I1(2A) and B1 and B2 are in opposite directions, so net magnetic intensity will become zero at existing neutral point.(highly probable). Explanation by showing magnetic field directions in all three regions Concluding left of region 1. |
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| 3. |
Sparking Brilliance of Diamond:The total internal reflection of the light is used in polishing diamonds to create a sparking brilliance. By polishing the diamond with specific cuts, it is adjusted the most of the light rays approaching the surface are incident with an angle of incidence more than critical angle. Hence, they suffer multiple reflections and ultimately come out of diamond from the top. This gives the diamond a sparking brilliance. 1. Light cannot easily escape a diamond without multiple internal reflections. This is because: a) Its critical angle with reference to air is too large b) Its critical angle with reference to air is too small c) The diamond is transparent d) Rays always enter at angle greater than critical angle2. The critical angle for a diamond is 24.4o . Then its refractive index isa) 2.42 b) 0.413 c) 1 d) 1.413 3. The basic reason for the extraordinary sparkle of suitably cut diamond is that a) It has low refractive index b) It has high transparency c) It has high refractive index d) It is very hard 4. A diamond is immersed in a liquid with a refractive index greater than water. Then the critical angle for total internal reflection will a) will depend on the nature of the liquid b) decrease c) remains the same d) increase5. The following diagram shows same diamond cut in two different shapes.The brilliance of diamond in the second diamond will be: a) less than the first b) greater than first c) same as first d) will depend on the intensity of light |
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Answer» 1. b) Its critical angle with reference to air is too small 2. a) 2.42 3. c) high refractive index 4. d) increase 5. d) less than first |
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| 4. |
What is the law of floating |
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Answer» Floating is a way to pause the hectic, saturated world and enter a state of deep mental and physical relaxation. Otherwise known as floatation-REST (restricted environmental stimulation technique) or sensory deprivation, floating is backed by research and offers immense potential for personal growth and healing. |
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| 5. |
Light cannot easily escape a diamond without multiple internal reflections because |
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Answer» Answer: Its critical angle with reference to air is too small |
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| 6. |
What’s at the bottom of a black hole? |
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Answer» Black holes don't have a bottom. A black hole is a region of infinitely warped space-time around what's called a singularity, which in turn is a collapsed star (among other options). A singularity is infinitely compressed. |
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| 7. |
An artery is a vessel that carries blood (A) with high concentrations of oxygen (B) with high concentrations of carbon dioxide (C) towards the heart'(D) away from the heart |
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Answer» An artery is a vessel that carries blood away from the heart. |
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| 8. |
Consider the following statements in connection with the functions of the blood vessels marked A and B in the diagram of a human heart as shown.(i) Blood vessel A - It carries Carbon dioxide rich blood to the lungs. (ii) Blood vessel B - It carries Oxygen rich blood from the lungs. (iii) Blood Vessel B - Left atrium relaxes as it receives blood from this blood vessel (iv) Blood Vessel A - Right atrium has thick muscular wall as it has to pump blood to this blood vessel. The Correct Statements are(a) (i) and (ii) only (b) (ii) and (iii) only(c) (ii), (iii) and (iv) (d) (i), (ii) and (iii) |
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Answer» Correct option is (a) (i) and (ii) only |
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| 9. |
What do you mean by magnetic properties of solid substance. |
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Answer» Magnetic properties of solid – The magnetic properties of a substance depend upon magnetic moment of the substance. The matter is made of atoms. In atom, there is nucleus and electrons are revolving round the nucleus. The moving electron is considered as small electrid loop. This small electric loop produces magnetic field. This is the reason that there creates magnetic properties in solid substances. |
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| 10. |
The total number of bonds in tetracyano ethylene |
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Answer» There are 4 single bonds, 1 double bond, 4 triple bonds in the molecule of tetracyanoethylene So, there is 4+1+4 = 9 sigma bonds & 0+1+(2×4) = 9 pi bonds |
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| 11. |
Which of the following contains three pairs of electron?A. CarbocationB. CarbanionC. Free radicalD. None of these |
| Answer» Correct Answer - A | |
| 12. |
The reaction between ethylene and bromine is an example of:A. electrophilic additonB. electrophilic substitutionC. nucleophilic additionD. nucleophilic substitution |
| Answer» Correct Answer - A | |
| 13. |
Which of the following compounds is not a Lewis acids?A. `BF_(3)`B. `SnCl_(4)`C. `R-OR`D. `P-MgX` |
| Answer» Correct Answer - C | |
| 14. |
Which is the increasing order of acidic strength in the following compounds ? `CH_(3)CH_(2)CH_(2)COOH(I), "NCCH"_(2)COOH(II), H_(2)C=CHCH_(2)COOH(III)`A. `IltIIltIII`B. `IltIIIltII`C. `IIIltIIltI`D. `IIltIltIII` |
| Answer» Correct Answer - B | |
| 15. |
The following reaction is an example of: A. nucleophilic substitutionB. electrophilic substitutionC. electrophilic additionD. nucleophilic addition |
| Answer» Correct Answer - D | |
| 16. |
Which of the following reactions is an example of `S_(N^(2))` reaction?A. `(CH_(3))_(3)C-Br+OH^(-)rarr(CH_(3))_(3)C-OH+Br^(-)`B. `(CH_(3))_(2)CH-Br+OH^(-)rarr(CH_(3))_(2)CH-OH+Br^(-)`C. `CH_(3)-Br+OH^(-)rarrCH_(3)-OH+Br^(-)`D. `CH_(3)CH_(2)OHunderset((-H_(2)O))rarrH_(2)C=CH_(2)` |
| Answer» Correct Answer - C | |
| 17. |
Arragne basicity of the following compounds in decreasing order: `CH_(3)CH_(2)NH_(2)(I)," "H_(2)C=CH-NH_(2)(II),` `HC-=C-NH_(2)(III)," "C_(6)H_(5)NH_(2)(IV)`A. `IgtIIgtIIIgtIV`B. `IVgtIIIgtIIgtI`C. `IIIgtIIgtIgtIV`D. `IgtIIIgtIIgtIV` |
| Answer» Correct Answer - A | |
| 18. |
The work function of Caesium metal is 2.14ev . A beam of light of frequency 6 ×1014 Hz easy incident on metal surface. Find a) energy of incident Photon.b) maximum kinetic energy of photoelectron. Given, h = 6.63 × 10-34 JS |
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Answer» Given, \(\phi=2.14\,ev\) v = 6 x 1014 h = 6.63 x 10-34 55 Js (a) Energy of photon E = hv E = 6.63 x 10-34 x 6 x 1014 E = \(\frac{39.78\times10^{-20}}{1.6\times10^{-19}}\) E = 24.86 x 10-1 E = 2.48 ev (b) Maximum kinetic energy of photo electron k = hv - \(\phi\) k = 2.48 - 2.14 k = 0.34 ev |
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| 19. |
Most stable radical isA. `CH_(2)=overset(.)CH`B. `CH_(2)=CH-overset(.)CH_(2)`C. D. |
| Answer» Correct Answer - B | |
| 20. |
Most stable carbocation is:A. B. C. D. |
| Answer» Correct Answer - C | |
| 21. |
The shape of carbanion, `[CH_(3)]^(-)` is :A. linearB. pyramidalC. planarD. tetrahedral |
| Answer» Correct Answer - B | |
| 22. |
Carbon atom in methyl carbocation and methyl carbanion is _____ and ______ hybridised :A. `sp,sp^(2)`B. `sp^(3),sp`C. `sp^(3),sp^(2)`D. `sp^(2),sp^(3)` |
| Answer» Correct Answer - D | |
| 23. |
English sample SA1 question papers |
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Answer» Please refer to NCERT or CBSE website for question papers of the latest pattern. |
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| 24. |
Explain the line"and stares with his brilliant eyes. at the brilliant stars |
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Answer» Stanza: He hears the last voice at night, /The patrolling cars, And stares with his brilliant eyes /At the brilliant stars. Word-meanings: Patrolling: moving about to check any danger Brilliant: shining Explanation: The poet again takes the reader to the cage where the tiger is sitting in the cage and feeling unpleasant and restless. He hears the sound created by the patrolling cars of the zoo authorities. He shows no interest in them. The poet shown him staring at the shining stars with his brilliant eyes. Thus the poem ends up at the point where it had started. The poet raises a moral issue here. He intends to present a strong case against the cruelty on animals, which are kept in cages. |
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| 25. |
760cm=?mtrs |
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Answer» 1m = 100 cms 760 cm = 7.6 metres hope it is helpful |
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| 26. |
Ampere's circuital theorem is best represented by |
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Answer» Amperes Circuital Law: The Ampere’s Circuital law is used to calculate the magnetic field due to distributed currents. It is analogous to Gauss law in Electrostatics, which calculates the electric field due to distributed charges. Ampere Circuital Law formula gives a method to calculate the magnetic field due to a given current distribution. We have studied the continuous distribution and discrete distribution of charges and masses. |
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| 27. |
the unit of luminous intensity is A.m B.kg C.cd D.mol |
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Answer» Answer: C.cd |
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| 28. |
A small steel ball of radius r is allowed to fall under gravity through a column of a viscous liquid of coefficient of viscosity `eta`. After some time the velocity of the ball attains a constant value known as terminal velocity `upsilon_T`. The terminal velocity depends on (i) the mass of the ball m (ii) `eta`, (iii) r and (iv) acceleration due to gravity g . Which of the following relations is dimensionally correct?A. `v_Tprop(mg)/(etar)`B. `v_Tprop(etar)/(mg)`C. `v_Tetarmg`D. `v_Tprop(mgr)/(eta)` |
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Answer» Correct Answer - A by subsituting dimension of each quantity is R.H.S of option (a) we get `[(mg)/(etar)]=[(MxxLT^-2)/(ML^-1T^-1xxL)]=[LT^-1]`. This option gives the dimension of velocity. |
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| 29. |
How is work done equal to Heat energy? |
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Answer» Work is a method of transferring energy and heat is a form at energy. Molecular work is the orderly transfer of energy in one direction while heat is the random molecular vibration work is accounted far in terms of change in the macroscopic physical variable of the system. Heat is vibrational molecules at microscopic thermal particles level. It was Joule who first discovered that work and heat are mutually convertible and gave an equation. where Q is heat raised of the system, W is work done on the system and j is a proportionality constant. Work is totally convertible into equal amount heat but total heat cannot be converted into an equal amount of work. |
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| 30. |
How can systematic errors be minimised (or) eliminated? |
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Answer» Systematic errors can be minimised by improving experimental techniques, selecting better instruments and removing personal bias as far as possible. For a given set up, these errors may be estimated to a certain extent and the necessary corrections may be applied to the readings. |
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| 31. |
Match the following :(i) Eka – boron (x) Scandium(ii) Eka – aluminium( y) Germanium(iii) Eka – silicon(z) Gallium(A) i – x, ii – y, iii – z (B) i – y, ii – x, iii – z (C) i – z, ii – x, iii – y (D) i – x, ii – z, iii – y |
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Answer» (D) i – x, ii – z, iii – y |
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| 32. |
Define work, power and energy. State their S.I units? |
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Answer» Work : The product of magnitude of displacement (S) and component of force (Fcosθ) along the direction of force is called work. i.e., W = vector F.S = F S cos θ. Unit → Joule; Power : The rate of doing work by a force is called power. P = w/t, Unit → watt (or) J/S Energy : The capacity to do work is called energy. Unit → Joule |
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| 33. |
What are the fundamental forces in nature? |
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Answer» (i) Gravitational force (ii) Electromagnetic force (iii) Strong nuclear force (iv) weak nuclear force. |
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| 34. |
By spinning eggs on a table top, how will you distinguish a hard boiled egg from a raw egg? |
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Answer» A raw egg has some fluid in it and a hard boiled egg is solid form inside. Both eggs are spinning on a table top, the fluid is thrown outwards. Therefore (Ir > Ib) That means M. I of raw egg is greater than boiled egg. As I ω = constant; ωr < ωb. That means Angular Velocity of raw egg is less than angular velocity of boiled egg. |
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| 35. |
What are polar satellites? |
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Answer» Polar satellites are low altitude satellites (500 to 800 km), but they go around the poles of the earth in a north-south direction. Its time period is around 100 minutes. |
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| 36. |
The least count of vernier callipers is `0.1 mm`. The main scale reading before the zero of the vernier scale is `10` and the zeroth division of the vernier scale coincides with the main scale division. Given that each main scale division is `1mm`. The measured value should be expressed asA. `1 cm`B. `2 cm`C. `0.5 cm`D. `0.1 cm` |
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Answer» Correct Answer - A Given, least count `(LC)=0.1mm` main scale reading `=0` vernier scale reading `=10` Length measured with the vernier callipers =reading before the zero of vernier scale+number of vernier divisions coinciding with any main division `X` least count `=10mm` `=1cm` |
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| 37. |
The total torque about pivot A provided by the forces shown in figure, for L=3.0m is |
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Answer» Moment of force about pivot A (80 N force) =80×3/2×sin30o = 60 N-m (anticlockwise) Moment of force about pivot A (70 N force) =70×3×sin30o=70×3×1/2 = 105 N-m (anticlockwise) Moment of force about pivot A (60 N force) =60×3/2×sin90o = 90 N-m (clockwise) Moment of force about pivot A (90 N force) =90×0×sin60o=0 Moment of force about pivot A (50 N) =50×3×sin180o=0 The total torque about pivot A T=(60+105−90) = 75 N-m |
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| 38. |
If a carved black utensil is heated to high temperature and then brought in dark then1) both utensil and its carving will Shine2) only utensil will shine3) only carving will shine4) none of the utensil and carving will Shine |
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Answer» Answer(1) If a carved black utensil is heated to high temperature and then brought in dark then: (1) Both utensil and its carving will shine (2) Only carving will shine (3) Only utensil will shine (4) None of the utensil and carving will shine. Both utensil and its carving will shine. The reason is that the thermal radiation are emitted spontaneously by many ordinary objects. Therefore this phenomenon can be called as black-body radiation. When a body absorbs so much heat then it emits thermal radiations according to its temperature. |
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| 39. |
Two cylinders A and B of equal capacity are connected to each other via a stop cock. A contains an ideal gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stop cock is suddenly opened. The process is :(1) isobaric(2) isothermal(3) adiabatic(4) isochoric |
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Answer» Correct answer is (3) adiabatic Free expansion i.e. expansion against vacuum is adiabatic in nature for all type of gases. It should be noted that temprature final temperature is equal to initial temperature for ideal gases. |
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| 40. |
The color code of a resistance is given belowThe values of resistance and tolerance, respectively, are :(1) 470 Ω, W, 5% (2) 470 kΩ, W, 5%(3) 47 kΩ, W, 10%(4) 4.7 kΩ, W, 5% |
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Answer» Correct answer is (1) 470 Ω, W, 5% R = 47 × 101 ± 5% R = 470 Ω, W, 5% |
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| 41. |
What is mean by P – V diagram? |
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Answer» PV diagram is a graph between pressure P and volume V of the system. The P-V diagram is used to calculate the amount of work done by the gas during expansion or on the gas during compression. |
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| 42. |
Write a note on reverberation? |
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Answer» The persistence of audible sound after the source has ceased to emit sound is called reverberation. |
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| 43. |
In the figure shown, current passing through the diode is A. `0.1 A`B. `0.02A`C. zeroD. `0.01A` |
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Answer» Correct Answer - C diode is reversely biased |
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| 44. |
What is Brownian motion? |
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Answer» The motion of the particles in a random and zig-zag mannar in a fluid is called Brownian motion. |
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| 45. |
Which of the following doesn't fit in the group? a. Conductorb. Semiconductor c. Four valence electrons d. Crystal structure |
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Answer» (a) Conductor |
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| 46. |
Which of the following is approximately equal to room temperature? a. 0 degrees C b. 25 degrees C c. 50 degrees C d. 75degrees C |
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Answer» (b) 25 degrees C |
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| 47. |
Silicon atoms combine into an orderly pattern called a a. Covalent bond b. Crystal c. Semiconductor d. Valence orbit |
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Answer» The correct answer is: (b) Crystal |
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| 48. |
The net charge of a neutral copper atom is a. 0 b. +1 c. -1 d. +4 |
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Answer» The correct answer is: (a) 0 |
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| 49. |
How many protons does the nucleus of a silicon atom contain? a. 4 b. 14 c. 29 d. 32 |
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Answer» The correct answer is: (b) 14 |
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| 50. |
Assume the valence electron is removed from a copper atom. The net charge of the atom becomes a. 0 b. + 1 c. -1 d. +4 |
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Answer» The correct answer is: (b) +1 b. +1Reason:- Configuration of copper is [Ar] 3d^10 4s^1, So if we remove one electron it will lose electron as it is a metal and therefore it will have +1 charge (anion). |
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