Explore topic-wise InterviewSolutions in Current Affairs.

Correct option is E) to tidy up

Correct option is B) ticket

Correct option is E) athlete

Correct option is E) sensitive

Correct option is C) bride / bridegroom

Correct option is A) who

Given:

M₁ = 10, D₁ = 20 days

D₂ = 4 days

Here M is number of men, and D is number of days

Formula used:

M₁ × D₁ = M₂ × D₂ 

Calculation:

M1 × D1 = M2 × D2 

⇒ 10 × 20 = M2 × 4

⇒ M2 = 200/4 = 50

∴ 50 men can complete the same work in 4 days

Given:

Number is multiplied by 12 instead of 21

Resultant = Actual value – 198

Formula Used:

Actual value = Resultant + difference between actual value and resultant value

Calculation:

Let the number be n

Actual value = 21 × n = 21n

⇒ Resultant =  n × 12 

⇒ Resultant = 12n

21n = 12n + 198

⇒ 21n – 12n = 198

⇒ 9n = 198

⇒ n = 198/9

⇒ n = 22

∴ The number is 22

Given 

Vessel A, sugar = 30 g, water = 180 ml

Vessel B, sugar = 40 g, Water = 280 ml 

Vessel C, Sugar = 20g , water = 100 ml 

Calculation 

⇒ Concentration of sugar in vessel A = 30/180 = 1/6 g/ml

⇒  Concentration of sugar in vessel B = 40/280 = 1/7 g/ml 

⇒  Concentration of sugar in vessel C = 20/100 = 1/5 g/ml

⇒ the more concentration of sugar means more sweetness of solution 

 ⇒ vessel C > vessel A > vessel B

∴ the solution of B is less sweet than solution C

Given:

30 persons can do a piece of work in 24 days

Formula Used:

\(\frac{{m1.d1.t1.e1}}{{w1.c1}} = \frac{{m2.d2.c2.e2}}{{w2.c2}}\) ,

m = number of men required to complete the work

d = number of days required to complete the work

t = time used for work in a single day

e = efficiency of man

w = amount of work

c = consumption of a man 

Calculation:

\(\frac{{m1.d1.t1.e1}}{{w1.c1}} = \frac{{m2.d2.c2.e2}}{{w2.c2}}\)

Here we have compared only the number of men required

And the number of days required to complete the work

⇒  30 × 24 = m2 × 20

⇒ 36

∴ 6 more men will be required

Given:

Cost price of rice = 20/kg

Percent profit at which 40 kg rice was sold = 10%

Percent profit on the total deal = 20%

Concept used:

Per kg selling price of remaining rice = (Total selling price of remaining rice)/(Quantity of remaining rice)

Calculation:

Total cost price of 120 kg rice = 120 × 20

⇒ 2400

Selling price of 120 kg rice = 2400 × {(100 + 20)/100}

⇒ 2400 × {120/100}

⇒ 24 × 120

⇒ 2880

Selling price of 40 kg rice at 10% profit = (40 × 20) × {(100 + 10)/100}

⇒ 800 × {110/100}

⇒ 8 × 110

⇒ 880

Then, Selling price of remaining 80 kg rice = 2880 – 880

⇒ 2000

Selling price of per kg of 80 kg rice = 2000/80

⇒ 25

Given:

Multiply by a number = 3/2.

But he divide the number = 3/2.

Concept used:

Using linear equation.

Calculation:

Let the number be 'x'.

Number when multiply by 3/2 = (3x)/2

Number when divide by 3/2 = x/(3/2) = (2x)/3

According to the question,

((3x)/2) – ((2x)/3) = 10

⇒ (9x – 4x)/6 = 10

⇒ 5x = 60

⇒ x = 12

∴ The number was 12.

Given:

f(x) = 2x² – 5x + 2

Calculation:

f(x) = 2x2 – 5x + 2

⇒ f(x) = 2x² – 4x – x + 2

⇒ f(x) = 2x(x – 2) – 1(x – 2)

⇒ f(x) = (2x – 1)(x – 2)

∴ One factor is (x – 2)

Given:

103 × 104

Calculation:

⇒ (100 + 3) (100 + 4)

⇒ 100 × 100 + 100 × 4 + 3 × 100 + 3 × 4

⇒ 10,000 + 400 + 300 + 12

⇒ 10,712

∴ The required answer is 10,712

Given:

Dividend is 919K

Divisor is 418

Quotient is 22

Formula used:

Dividend = Divisor × Quotient + Remainder

Calculation:

Here, Remainder is zero,

Dividend = 418 × 22

⇒ Dividend = 9196 

∴ K is  6 a number.

Given:

The price of the 1^st type of price is Rs. 50 /kg, and of the 2^nd type = Rs. 70 /kg

Calculation:

The total price of 1^st type of rice will be 50 × 5 = Rs. 250

The total price of the 2^nd type of rice will be 70 × 10 = Rs. 700

The total price of rice = 250 + 700 = Rs. 950 per kg

⇒  950/15 = Rs. 190/3

∴ The price of rice per kg = Rs. 190/3

Among those who was most critical of the existing social order and made a strong plea for Hindu-Muslim Unity, the name of Kabir stands out. Kabir was a Champion of the Bhakti Cult. Of course there is a good deal of uncertainty about the dates and early life of Kabir. According to a legend, Kabir was the son of a brahmana widow who due to certain reasons left him after his birth in a helpless condition on the bank of a tank at Banaras in 1440 A.D.

Fortunately a Muslim weaver Niru by name saw the baby and took him home. He was brought up in the house of a Muslim Weaver. But he was not given proper education. He learnt weaving from his adopted father and made it his profession. Kabir from his very childhood developed a love for religion. While living at Kashi he came in contact with a great saint named Ramananda who accepted him as his disciple.

He also met a number of Hindu and Muslim Saints. Though he was married and later become the father of two children his love for God could not be wiped out amidst worldly cares. He did not leave home. He spent his life as a family man. He at the same time started preaching his faith in Hindi Language. He attracted thousands of people by his simple spell bounding speech. His followers were both the Hindus and the Muslims. He breathed his last in 1510.

It is said there happened a miracle after his death. His dead body was claimed by both the Hindu and the Muslim followers. Even a quarrel took place over this issue. After some time a follower out of curiosity lifted the cloth which had covered Kabir’s dead body. To the utter surprise of everybody present there, it was found a heap of flowers at the place of the body. Where did the body go? Realizing its implication both Hindu and Muslim followers distributed flowers among themselves.

Teachings:
The teachings of Kabir were very simple. He first of all emphasized on the unity of God. He said, we may call the God by any name such as Rama, Hari, Govinda, Allah, Sahib etc., it makes no difference. They are one and the same. Kabir said God is formless. He strongly denounced idol-worship. He also did not believe in incarnations (Avatara) of God. He disregarded formal worships and practices like idol-worship, Pilgrimages, bathing in holy rivers.

He advised people not to give up the life of a normal house holder for the sake of a saintly life. He said that neither asceticism nor book knowledge could give us true knowledge. Dr. Tara Chand says “The mission of Kabir was to preach a religion of love which would unite all castes and creeds. He disregarded the outer form and formalities of both Hindu and Islamic religion.

Kabir strongly denounced the caste system. He gave emphasis on the unity of men and opposed all kinds of discrimination between human beings. His sympathizers were with the poor man, with whom he identified himself. The teachings of Kabir appealed both Hindus and Muslims. His followers were called as Kabir panthis or the followers of Kabir. His poems were called as dohas. After his death, his followers collected his poems and named it Bijak.”

Given:

A shopkeeper bought 10 kg of rice at the rate of Rs. 25 per kg. He sold forty percent of the total quantity at the rate of Rs. 50 per kg.

Calculation:

Cost price of rice = 10 × 25 = Rs. 250

40% of total quantity = 10 × 0.4 = 4 kg 

Selling price of 4 kg = 50 × 4 = Rs. 200 

For overall 40% profit, total Selling price = 250 × 1.4 = Rs. 350

Remaining quantity = (10 - 4)kg = 6 Kg

Selling price per kg of remaining quantity = (350 - 200)/6 = Rs. 25

∴ The selling price for remaining quantity is Rs. 25.

Given:

P can fill the tank in = 16 h

Q can fill the tank in = 10 h

Concept Used:

Total work is LCM of work done by each pipe.

Calculation:

Part filled by P in 1 h = 1 / 16

Part filled by Q in 1 h = 1 / 10

Both are opened alternately,

Part filled by (P + Q) in 2 h = 1 / 16 + 1 / 10

⇒ 13/80

Part filled by (P + Q) in 12 h = 6 × 13 / 80

⇒ 39/40

Remaining part = 1 – 39 / 40

⇒ 1 / 40

Now, it is P’s turn

Time taken by P to fill 1 / 40 part of the tank = 1 / 40 × 16

⇒ 2 / 5 h

Total time taken = 12 + 2 / 5

⇒ 62 / 5 h

Follow this link for answer:

https://www.sarthaks.com/33703/explain-the-principles-involved-in-the-estimation-of-halogens-by-carious-method​

(i) Halogens: Halogens reacts with silver nitrate to for precipitate of silver halides. 

X + Ag⁺ → AgX . 

X represents a halogen -Cl, -Br or -1

(ii) Sulphur 

S⁺ + [Fe(CN)₅NO]₂ → [Fe(CN)₅NOS]^4- 

Sulphur reacts with nitropresside to form a violet colour complex.

Carbon exhibits many allotropic forms: both crystallins as well as amorphous. Diamond and graphite are two well known crystalline forms of carbon, third form of carbon known as fullerences. 

Fullerences are made by heating of graphite in an electric are in the presence of inert gases such as helium or argon. The sooty material formed by condensation of vapourised Ca small molecular consists of-mainly C₆₀ with smaller quantity of C₇₀ and traces of fallerences consiting of even number of carbon atoms upto 350 or above.

Ice is a solid substance when ice kept at room temp ice will melt and change into water (liquid) form. Conclusion – When temperature increase the ice (solid) change into water (liquid).

Given:

Pipe X can fill an empty pool in 6 hours and pipe Y in 8 hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Part of pool filled by pipes X and Y in 2 hours

⇒ \(2{\rm{\;}}\left( {\frac{1}{6}{\rm{}} + {\rm{}}\frac{1}{8}} \right)\)

⇒ \(2{\rm{}}\left( {\frac{{4{\rm{\;}} + {\rm{\;}}3}}{{24}}} \right){\rm{}} = {\rm{}}\frac{7}{{12}}\)

Remaining part = \(1 - \frac{7}{{12}}{\rm{}} = {\rm{}}\frac{5}{{12}}\)

This part is filled by pipe Y.

Required time = \(\frac{5}{{12}} \times 8\)

⇒ 10/3 hours

= \(3\frac{1}{3}\) hours

∴ Y will take \(3\frac{1}{3}\) hours to fill the remaining tank.