This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A ________ is solid bounded only by plane surfaces (faces).(a) square(b) rectangle(c) regular polyhedron(d) triangle |
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Answer» Correct answer is (c) regular polyhedron Explanation: In geometry, a polyhedron (plural polyhedra or polyhedrons) is a solid in 3 dimensions with flat polygonal faces, straight edges and sharp corners or vertices. The word polyhedron comes from the Classical Greek. A convex polyhedron is the convex hull of finitely many points, not all on the same plane. Cubes and pyramids are examples of convex polyhedra. A polyhedron is a 3-dimensional example of the more general polytope in any number of dimensions. |
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| 2. |
Which material property is shown by the 2nd figure?(a) Concrete(b) Earth(c) Electrical welding, electromagnets etc(d) Thermal insulation |
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Answer» The correct answer is (c) Electrical welding, electromagnets etc Easiest explanation: Electric resistance welded (ERW) pipe is manufactured by cold-forming a sheet of steel into a cylindrical shape. Current is then passed between the two edges of the steel to heat the steel to a point at which the edges are forced together to form a bond without the use of welding filler material. Initially this manufacturing process used low frequency A.C. current to heat the edges. This low frequency process was used from the 1920s until 1970. In 1970, the low frequency process was superseded by a high frequency ERW process which produced a higher quality weld. |
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| 3. |
Which types of prism does the 3rd figure represents?(a) Triangular(b) Square(c) Pentagon(d) Oblique |
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Answer» Correct option is (c) Pentagon For explanation I would say: A solid (3-dimensional) object which has six faces that are rectangles. It has the same cross-section along a length, which makes it a prism. It is also a “cuboid”. |
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| 4. |
For type 3rd what will be the pay range?(a) 251/- to 400/-(b) 500/- to 700/-(c) 350/- to 780/-(d) 290/- to 600/- |
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Answer» The correct choice is (a) 251/- to 400/- Explanation: Accommodation is two rooms, kitchen, store, verandah, bath and W.C. Floor area = 48.5 sq. m Plinth area = 58 sq. m S.S; 65 sq. m D.S. |
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| 5. |
Which material property is shown by the 3rd figure?(a) Concrete(b) Earth(c) Sound insulation(d) Thermal insulation |
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Answer» Correct answer is (a) Concrete Explanation: Concrete is a composite material composed of coarse aggregate bonded together with a fluid cement that hardens over time. Most concretes used are lime-based concretes such as Portland cement concrete or concretes made with other hydraulic cements, such as ciment fondu. However, asphalt concrete, which is frequently used for road surfaces, is also a type of concrete, where the cement material is bitumen, and polymer concretes are sometimes used where the cementing material is a polymer. |
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| 6. |
If 2nd plane shifts to the left of the object and 3rd plane shifts to the bottom of the object, then which angle of projection it will show?(a) Third – angle projection(b) Second – angle projection(c) First – angle projection(d) Fourth – angle projection |
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Answer» Right option is (c) First – angle projection To elaborate: When the object is situated in front of the V.P. and the H.P. i.e. in the first quadrant and then projected on these planes is called 1st angle projection. The object lies between the observer and the plane of projection. In this the top view comes below the front view. |
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| 7. |
All the following substances react with water. The pair that gives the same gaseous product isA. `Na and Na_(2)O_(2)`B. `K and KO_(2)`C. `Ba and BaO_(2)`D. `Ca and CaH_(2)` |
| Answer» Correct Answer - d | |
| 8. |
It is often found that learners at primary level experience difficulty in comprehending word problems. This problem can be best addressed by:1. introducing word problems in mother tongue as well2. giving a lot of word problems for practice3. eliminating word problems from the primary Mathematics Curriculum4. asking learners to look into dictionary for meanings |
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Answer» Correct Answer - Option 1 : introducing word problems in mother tongue as well Many second language learners may have difficulty reading and understanding the written content in a word problem. For example, if a student is learning English as a second language, he might not yet know key terminology needed to solve the equation. In other words, second language learners who have had formal education in their home countries generally do not have mathematical difficulties; hence, their struggles begin when they encounter word problems in a second language that they have not yet mastered. For this reason, it is recommended that students learn key terminology introducing word problems in mother tongue as well. And it is prior to attempting to solve mathematical word problems. Learners at primary level experience difficulty in comprehending word problems as they often pose a challenge because they require that:
Hence, it can be concluded that experiencing difficulty in comprehending word problems by the learners at the primary level can be best addressed by introducing word problems in mother tongue as well. |
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| 9. |
There are two inlets A and B connected to a tank. A and B can fill the tank in 16 hours and 10 hours respectively. If both taps are opened alternatively for 1h, starting from A then how much time will the tank take to be filled?1. 12 hours 12 minutes2. 11 hours 45 minutes3. 12 hours 24 minutes4. 12 hours 15 minutes5. None of these |
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Answer» Correct Answer - Option 3 : 12 hours 24 minutes Given: The inlet pipe A can fill a tank in 16 hours and pipe B can fill in 10 hours. Concept Used: If a pipe can fill a tank in x hour, then in 1 hour 1/x part of the tank will be filled by the pipe. Calculation: Pipe A can fill the tank in 16 hour Part of the tank filled by pipe A in 1 hour = 1/16 Pipe B can fill a tank in 10 hours Part of the tank filled by B in 1 hour = 1/10 The part filled by (A + B) in 2 hours = 1/16 + 1/10 ⇒ (5 + 8)/80 ⇒ 13/80 Now, 6 × (13/80) = 78/80 ⇒ In 6 × 2 = 12 hours tank filled by 78/80 part Remaining is (1 - 78/80) part ⇒ 2/80 = 1/40 part After complete of 12 hours pipe A will be open To fill 1/16 part pipe A takes time 1 hour ⇒ To fill 1/40 part pipe A will take time (16/40) hour ⇒ (2/5) hour ⇒ 24 minutes [∵ 1 hour = 60 min] Total time needed to fill the tank (12 hours + 24 minutes) ⇒ 12 hours 24 minutes ∴ Starting from A 12 hours 24 minutes will take to fill the tank. |
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| 10. |
Robert has sandy soil in his fields. The ideal crop for his field is:1. Cabbage2. Corn3. Wheat4. Gram |
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Answer» Correct Answer - Option 2 : Corn The correct answer is Corn.
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| 11. |
What concentration of `Ag^(+)` ions will be in equilibrium with a saturated solution containing a precipitate of `Ag_(2)CrO_(4) and CrO_(4)`-ion concentration of 0.40 moles per litre. Given `K_(SP)" of "Ag_(2)CrO_(4) = 1. 1 xx 10^(-11 )`A. `5.24xx10^(-6)` moles per litreB. `2.5xx10^(-6)` moles per litreC. `7.5xx10^(-6)` moles per litreD. `5.9xx10^(-6)` moles per litre |
| Answer» Correct Answer - a | |
| 12. |
Figure below represents a section (shaded) obtained due to intersection by a plane that is parallel to the axes of the cones, what it the section called?(a) Parabola(b) Hyperbola(c) Ellipse(d) Cycloid |
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Answer» The correct choice is (b) Hyperbola The best explanation: Hyperbola concept originated in Greek, can be defined as a set of points in a plane whose distances to two fixed points in the plane have a constant difference. It is formed by the intersection of a plane with a right circular cone. Equation of parabola: x^2/a^2 – y^2/b^2 = ±1. |
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| 13. |
The maximum number of electrons in an orbital having same spin quantum number will be:A. `l + 2`B. `2 l + 1`C. `l(l + 1)`D. `sqrt(l(l + 1))` |
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Answer» Correct Answer - B `p-"orbital" (l = 1)` can have three unpaired electrons , `d-"orbital" (l = 2)` can have five unpaired electrons. |
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| 14. |
Directions: Below question is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.Find the percentage savings of his savings.Statement I: Ajay has a monthly salary of Rs.45000. Statement II: He spends 70% of his salary. When his salary increased by 25%, he increases his spending by 10%.1. If the data in statement I alone is sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.2. If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.3. If the data either in statement I alone or in statement II alone is sufficient to answer the question.4. If the data even in both the statements I and II together are not sufficient to answer the question.5. If the data in both statements I and II together are needed to answer the question. |
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Answer» Correct Answer - Option 2 : If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question. Given: Statement I: Ajay’s salary = Rs.45000 Statement II: Ajay’s expenditure = 70% Ajay’s salary raise = 25% Ajay’s expenditure increase = 10% Concept used: Income = Expenditure + Savings Calculations: Statement I: Since the percentage change is required then salary is insignificant and the salary could also be assumed accordingly. Statement II: Let Ajay’s salary be Rs.100 Ajay’s savings = Salary – Expenditure = Rs.30 A’s salary after raise = 100 + 25 × 100/100 ⇒ Rs.125 Ajay’s expenditure after increase = 70 + 10 × 70/100 = Rs.77 Ajay’s new savings = 125 – 77 = Rs.48 Ajay’s savings % change = (48 – 30) × 100/30 ⇒ 60% The amount of salary was not used in calculation and the percentage change can easily be determined with the help of statement II. ∴ If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question. |
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| 15. |
In how many ways can we arrange ‘n’ things in a row?1. (n+1)!2. (n‐1)!3. 2n!4. n! |
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Answer» Correct Answer - Option 4 : n! Given In how many ways can we arrange 'n' things in a row Calculation : Number of ways of arrange n things(If n = 5!) ⇒ 5× 4 × 3 × 2× 1 = 120 ways to arrange fine objects . In general say that there are n! permutations of n objects . This quantity nCr is called the "combination" and represents the probability of picking r distinguishable outcomes out of n without regard to the order of picking each outcome. ∴ The required answer is n!. |
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| 16. |
The figure represents the intersection of two __________(a) concentric spheres(b) swimming flotation(c) tori(d) rings |
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Answer» Correct choice is (c) tori Explanation: The intersection curve of two polyhedrons is a polygon i.e. tori. The display of a parametrically defined surface is usually done by mapping a rectangular net into 3-space. The spatial quadrangles are nearly flat. So, for the intersection of two parametrically defined surfaces, the algorithm for the intersection of two polyhedrons can be used. |
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| 17. |
Which angle of projection does the figure resembles if it is lying in the 3rd coordinate?(a) Second – angle projection(b) Third – angle projection(c) Fourth – angle projection(d) First – angle projection |
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Answer» The correct option is (b) Third – angle projection The explanation is: Given in the question it lies in the 3rd quadrant. The plane of projection is assumed to be transparent. They lie between object and observer. When the observer views the object from the front, the rays of sight intersect the V.P, similarly when its top view is seen from bottom, the rays of sight intersect the H.P. The top view in this case comes above the front view and so it is third angle projection. |
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| 18. |
Directions: Below question is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.Find the age of the fourth friend.Statement I: Average age of nine friends is 15 years. Statement II: If the average age of the first five friends is 17 years and the average age of the last five friends is 14 years.1. If the data in statement I alone is sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.2. If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.3. If the data either in statement I alone or in statement II alone is sufficient to answer the question.4. If the data even in both the statements I and II together are not sufficient to answer the question.5. If the data in both statements I and II together are needed to answer the question. |
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Answer» Correct Answer - Option 4 : If the data even in both the statements I and II together are not sufficient to answer the question. Given: Statement I: The average age of nine friends = 15 Statement II: The average age of the first five friends = 17 The average age of the last five friends = 14 Formula used: Average age = Total sum of ages of all friends / Number of friends Calculations: Statement I: Let the sum of ages of nine friends be T Average age = 15 = T/9 ⇒ T = 135 Statement II: Let the age of the fifth friend be x ⇒ (17 × 5) + (14 × 5) – x = 135 ⇒ x = (85 + 70) – 135 ⇒ x = 20 years Together the two statements can help in determining the age of the fifth friend not the age of the fourth friend ∴ If the data even in both the statements I and II together are not sufficient to answer the question. |
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| 19. |
Which of the following correctly explains the nature of boric acid in aqueous medium :A. `H_3 BO_3 overset (H_2 O)rarr H_3^+ O + H_2 BO_3^-`B. `H_3 BO_3 overset (2 H_2O)rarr 2H_3^+ O + HBO_3^(2-)`C. `H_3 BO_3 overset (3H_2 O)rarr 3 H_3^+ O + HBO_3^(3-)`D. `H_3 BO_3 overset (H_2 O)rarr B(OH)_4^(-) + H^+`. |
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Answer» Correct Answer - D `H_3 BO_3` is weak, Lewis monobasic acid and shows the given equilibrium. |
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| 20. |
Directions: Below question is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.Find the sum of prices paid by A, B, and C to buy the article.Statement I: A sells his articles at 87.5% of the cost price to B. B sells it at a 10% profit to C. Statement II: C paid Rs. 1386 for the article.1. If the data in statement I alone is sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.2. If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.3. If the data either in statement I alone or in statement II alone is sufficient to answer the question.4. If the data even in both the statements I and II together are not sufficient to answer the question.5. If the data in both statements I and II together are needed to answer the question. |
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Answer» Correct Answer - Option 5 : If the data in both statements I and II together are needed to answer the question. Given: Statement I: A sold the article to B at = 87.5% of the cost price B sold the article to C at = 10% profit Statement II: Amount paid be C to purchase the article = Rs. 1386 Formula used: Profit % = [(SP – CP)/CP] × 100 Calculations: Statement I: Let A bought the cricket bat for Rs. x Then, B’s purchasing cost = (87.5/100) × x ⇒ 7x/8 Statement II: C’s purchasing cost = (110/100) × (7x/8) ⇒ (11/10) × (7x/8) = 1386 ⇒ 77x/80 = 1386 ⇒ x/80 = 18 ⇒ x = Rs. 1440 ∴ If the data in both statements I and II together are needed to answer the question. |
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| 21. |
Two Statements S1 and S2 are given below followed by a Question :S1 : n is a prime number.S2 : it leaves a remainder of 1 when divided by 4.Question :If it is a unique natural number between 10 and 20, then what is n?Which one of the following is correct in respect of the above Statements and the Question?1. S1 alone is sufficient to answer the Question.2. S2 alone is sufficient to answer the Question.3. S1 and S2 together are sufficient to answer the Question, but neither S1 alone nor S2 alone is sufficient to answer the Question. 4. S1 and S2 together are not sufficient to answer the Question. |
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Answer» Correct Answer - Option 4 : S1 and S2 together are not sufficient to answer the Question. Given: S1 : n is a prime number. S2 : it leaves a remainder of 1 when divided by 4. Calculation: Between 10 to 20 prime numbers are 11, 13, 17, 19. And 11/4 ,13/4, 17/4, 19/4 Remainder 11/4 ,13/4, 17/4, 19/4 are 3, 1, 1, 3 We could not find the given two statement. ∴ S1 and S2 together are not sufficient to answer the Question. |
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| 22. |
Directions: Below question is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.What is the age of C?Statement I: A, B, and C are three friends. The sum of the ages of the three is 58 years. As age is 5% more than B’s age. Statement II: C’s age is 15% lesser than that of B.1. If the data in statement I alone is sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.2. If the data in statement II alone is sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.3. If the data either in statement I alone or in statement II alone is sufficient to answer the question.4. If the data even in both the statements I and II together are not sufficient to answer the question.5. If the data in both statements I and II together are needed to answer the question. |
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Answer» Correct Answer - Option 5 : If the data in both statements I and II together are needed to answer the question. Given: Statement I: Sum of ages of all the friends = 58 A’s age = 5% more than B’s age Statement II: C’s age = 15% lesser than B's age Calculations: Statement I: Let A’s age, B’s age and C’s age be A, B, and C respectively. Total age = A + B + C = 58 ⇒ A = B + 5B/100 = 21B/20 Statement II: ⇒ C = B – 15B/100 = 17B/20 Sum of ages of all = 21B/20 + B + 17B/20 ⇒ 58B/20 = 58 ⇒ B = 20 ⇒ C = 17 ∴ If the data in both statements I and II together are needed to answer the question. |
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| 23. |
Consider the following compounds: Choose the correct statements(s) from the following:A. I,II and III are functional followingB. I and IV are position isomersC. II and III are chain isomersD. III and IV are metamers. |
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Answer» Correct Answer - A::D The formula for `CFSE` in octahedral field is `CFSE=-0.4xx("number of electrons in" t_(2g))` `+0.6Deltaxx` (number of electrons in `e_(g)`) `+Pxx`(number of extra pairings compared to normal filling of electrons) Where `Delta=` octahedral crystal field splitting and `P=` pairing energy (A). `K_(4)[Fe(CN)_(6)]` is `3d^(6)` strong field ligand `t_(2g)^(6)e_(g)^(0)` with two extra pairings (B). `[MnCl_(6)]^(4-)` is `3d^(5)` weak field ligand `t_(2g)^(3)e_(g)^(2)` with not extra pairing (C). `[Ni(H_(2)O)_(6)]SO_(4)` is `3d^(8)` weak field ligand `t_(2g)^(6)e_(g)^(2)` with no extra pairing |
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| 24. |
In the absence of external magnetic field, d-orbital isA. `3-`fold degenerateB. Non-degenerateC. `5-`fold degenerateD. `7-`fold degenerate |
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Answer» Correct Answer - C `d-`orbital is `5-` fold degenerate in absence of magnetic field. |
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| 25. |
A saturated solution of `CaF_(2)` is found to contain `2 xx 10^(-4) M` of `F^(-)` ions. `K_(sp)` of `CaF_(2)` is:A. `8 xx 10^(-12)`B. `4 xx 10^(-12)`C. `2 xx 10^(-12)`D. `10^(-12)` |
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Answer» Correct Answer - B `CaF_(2) hArr underset(s)Ca^(2+) + underset(2s)2F^(-)` `2s = 2 xx 10^(-4)` `s = 10^(-4)` `K_(sp) = 4s^(3) = 4 xx 10^(-12)` |
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| 26. |
Equal volume of the following `Ca^(+2)` and `F^(-)` solutions are mixed. In which case will percipitation occur? (`K_(sp)` of `CaF_(2) = 7 xx 10^(-10)`).A. `10^(-2) M Ca^(+2) + 10^(-5)MF^(-)`B. `10^(-3) M Ca^(+2) + 10^(-5)MF^(-)`C. `10^(-4) M Ca^(+2) + 10^(-2)MF^(-)`D. `10^(-2) M Ca^(+2) + 10^(-6)MF^(-)` |
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Answer» Correct Answer - C For precipitation `IP gt K_(sp)` |
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| 27. |
The reaction of (S)-2 bromobutane with `OH^(-)` to produce (R )-butane-2-ol will be -A. first order in 2-bromobutane onlyB. first order in `OH^(-)` onlyC. first order in 2-bromobutane and first order in `OH^(-)`D. second order in `OH^(-)` |
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Answer» Correct Answer - C Configuration invert, means `SN_(2)` reaction takes place Rate = K [Substrate][`OH^(-)`] |
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| 28. |
In which of the following processes energy is absorbed ?A. `Cl_((g))+e^(-)toCl_((g))^(-)`B. `F_((g))^(-)+e^(-)toF_((g))^(-2)`C. `Na_((g))^(+)+e^(-)toNa_((g))`D. `Mg_((g))^(+2)+e^(-)toMg_((g))^(+)` |
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Answer» Correct Answer - B `EA_(2)` process is always endothermic |
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| 29. |
Total charge required for the oxidation of two moles `Mn_3O_4 ` into `MnO_4^(2-)` in presence of alkaline medium isA. 5 FB. 10 FC. 20 FD. None of these |
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Answer» Correct Answer - C 1 mole `Mn_(3)O_(4)" lose"(6-(8)/(3))xx3=10` mole `e^(-)` , so total charge required = `2xx10`= 20F |
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| 30. |
Calculate standard free energy change for the reaction `2Ag+2H^(+)rarrH_(2)+2Ag^(+)` Given : `E_(Ag^(+)//Ag)^(@)=+0.80V`A. 308.08 kJB. 154.4 kJC. 77.2 kJD. `-154.4` kJ |
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Answer» Correct Answer - B `E_(cell)^(@)+E_(H_(2))^(@)-E_(Ag)^(@)` = 0-0.80 = 0.80 `DeltaG^(@)= -nFE_(cell)^(@)` = `-2xx96500xx(-1.80)` =+154.4kJ |
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| 31. |
Select incorrect order :A. `H_(2)OgtH_(2)SgtH_(2)SegtH_(2)Te` (Order of bond angle )B. `HFgtHClgtHBrgtHl` (Order of boiling point)C. `LiClltBeCl_(2)ltBCl_(3)lt C Cl_(4)` (Order of covalent character)D. `CaF_(2)gtCaCl_(2)gtCaBr_(2)ltCal_(2)` (Order of melting point) |
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Answer» Correct Answer - B correct order of boiling point is, `HFgtHIgtHBrgtHCl` |
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| 32. |
Which one of the following ionic species will impart colour to an aqueous solution ?A. `Ti^(+4)`B. `Cu^(+)`C. `Zn^(+2)`D. `Cr^(+3)` |
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Answer» Correct Answer - D `Ti^(4)=[Ar]4s^(0)3d^(0)(0" unpaired "e^(-))` `Cu^(+)=[Ar]4s^(0)3d^(10)(0" unpaired "e^(-))` `Zn^(+2)=[Ar]4s^(0)3d^(10)(0" unpaired "e^(-))` `Cr^(+3)=[Ar]4s^(0)3d^(3)(3" unpaired "e^(-))` |
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| 33. |
The soda extract of which of the following commpound gives the test of nitrogen?A. `NH_(2)NH_(2)`B. `HNO_(2)`C. `HCONH_(2)`D. all are correct |
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Answer» Correct Answer - C Carbon should be present in the compound for giving nitrogen test. |
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| 34. |
why magnesium ribbon be cleaned before burning |
| Answer» Due to deformed metal bonds of atoms at the surface of a fresh magnesium ribbon the metal ribbon exposed in air gets easily oxidised by oxygen forming a coating of magnesium oxide on it. This coating prevents it from further attack by oxygen when we try to burn it in flame. So it should be cleaned before burning. | |
| 35. |
Consider the following equation in a closed container:N2O4(g)⇄2NO2(g)At a fixed temprature, the volume of the reaction container is halved.For this change,Which of the following statements, holds true regarding the equilibrium constant (Kp) and degree of dissociation(α) |
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Answer» Correct option (D)KP does not change, but α changes Explanation: For the equilibria: N2O4(g) ⟺ 2NO2(g) KP = KC x (RT)Δn Since temperature is constant so Kc or KP will remain constant. Further since volume ishalved, the pressure will be doubled so α will decrease so as to maintain the constancy of KC or KP. |
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| 36. |
Which of the following reaction does not produce `H_(3)PO_(4)`?A. Reaction between `P_(4)O_(10)` and `H_(2)O`B. heating of `H_(3)PO_(3)`C. Heating of `H_(3)PO_(2)`D. Reaction between `Ca_(3)P_(2)` and `H_(2)O` |
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Answer» Correct Answer - D `Ca_(3)P_(2)+6H_(2)Oto3Ca(OH)_(2)+2PH_(3)` |
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| 37. |
2H2O ⇄ H3O+ + OH-,KW=1x10-14 at 25°C hence Ka is: |
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Answer» Molar mass of water = 18 gmol^-1 Mass of 1L water is 1000g Hence molarity of water [H2O]= 1000/18 molL^-1 Now dissociation constant of water Ka = [H+][OH-]/[H2O] = Kw/[H2O] = 10^-14×18/1000=18×10^-17 |
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| 38. |
Select the correct order for the strength of bases given below: |
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Answer» Correct option: (d) Explanation: The acidic character of conjugate acids is H2O > C2H2 > NH3 > C2H4 > C2H6 |
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| 39. |
Which of the folowing equations are dimensionally correct? (a) vf= vi + ax (b)y= (2 m) cos (kx), where k=2 m^-1 |
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Answer» (a) Equation vf= vi + ax is dimensionally incorrect. (b) Equation y= (2 m) cos (kx) is dimensionally correct. |
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| 40. |
The relation J = σ E is called |
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Answer» Ohm's law on the basis of drift velocity. |
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| 41. |
The figure shows P - V diagram of a thermodynamic cycle The work done in the cycle isA. `2P_(0)V_(0)`B. `3P_(0)V_(0)`C. `P_(0)V_(0)`D. `6P_(0)V_(0)` |
| Answer» Correct Answer - A | |
| 42. |
Differentiate between Diesel engine & petrol engine? |
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Answer»
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| 43. |
Densification of biomass |
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Answer» Densification essentially involves two parts; the compaction under pressure of loose material to reduce its volume and to agglomerate the material so that the product remains in the compressed state. This process of compaction is entirely related to the pressure exerted on the material and its physical characteristics. |
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| 44. |
What is the adiabatic process equation |
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Answer» The adiabatic process can be derived from the first law of thermodynamics relating to the change in internal energy dU to the work dW done by the system and the heat dQ added to it. |
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| 45. |
If \(\frac{{45}}{{53}} = \frac{1}{{a + \frac{1}{{b + \frac{1}{{c - \frac{2}{5}}}}}}},\) where a, b and c are positive integers, then what is the value of (4a - b + 3c)1. 62. 43. 74. 5 |
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Answer» Correct Answer - Option 4 : 5 Calculations: \(\frac{{45}}{{53}} = \frac{1}{{a + \frac{1}{{b + \frac{1}{{c - \frac{2}{5}}}}}}}\) \( \) \(⇒ \frac{1}{{1\; + \;\frac{1}{{5\; + \;\frac{5}{8}}}}} = \frac{1}{{a\; +\; \frac{1}{{b\;+ \;\frac{1}{{c\; -\; \frac{2}{5}}}}}}}\) \(⇒ \frac{1}{{1\; + \;\frac{1}{{5\; + \;\frac{1}{{2 \;- \;\frac{2}{5}}}}}}} = \frac{1}{{a\; +\; \frac{1}{{b\;+ \;\frac{1}{{c\; -\; \frac{2}{5}}}}}}}\) Compare both the sides ⇒ a = 1, b = 5 and c = 2 Value of (4a – b + 3c) = 4 × 1 – 5 + 3 × 2 ⇒ 10 – 5 = 5 ∴ The value of 4a – b + 3c is 5 |
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| 46. |
The square of 53 is:1. 2,8092. None of the above3. 2,8004. 2,806 |
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Answer» Correct Answer - Option 1 : 2,809 Concept used: Calculation: |
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| 47. |
Which of the following is the largest multiple of three digits of '12'.1. 9932. 9983. 9964. 992 |
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Answer» Correct Answer - Option 3 : 996 Given: Number is '12'. Concept used: We divide the smallest four digit number by '12', then subtract the remainder from the smallest four digit number to get desired result. Explanation: The smallest four digit number is '1000'. ⇒ On dividing it by 12, we get '4' as a remainder. ⇒ On subtracting 4 from 1000, we get ⇒ 996 ∴ The largest multiple of three digits of '12' is 996.
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| 48. |
Find the total number of factors of '900'.1. 82. 273. 184. 6 |
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Answer» Correct Answer - Option 2 : 27 Given: Number is 900 Concept used: First factorise the given number into its prime factors. N = 2a × 3b × 5c Number of factors of ‘N’ = (a + 1) × (b + 1) × (c + 1) Calculation: After factorising, we can write ⇒ 900 = 22 × 32 × 52. ⇒ Number of factors of '900' = (2 + 1) × (2 + 1) × (2 + 1) ⇒ 27 ∴ The total number of factors of 900 is 27.
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| 49. |
n is a natural number. Which number is to be added to n2 + 6n. So as to get a perfect square always. |
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Answer» n2 + 6n + 9 = n2 + 2 x n x 3 = 32 = (n + 3)2 which is a perfect square. Hence, we have to add 9 in n2 + 6n to gent a perfect square. |
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| 50. |
H.C.F and L.C.M of two numbers are 4 and 308 respectively. Find the sum of the digits of the number, lies between “30 – 50”.1. 22. 83. 64. 7 |
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Answer» Correct Answer - Option 2 : 8 Given: H.C.F of two numbers = 4 L.C.M of two numbers = 308 One of the numbers lies between “30 – 50” Concept used: If H.C.F of two natural numbers is H, then numbers should be Hx and Hy respectively. Where x and y should be relatively prime number. Formula used: The Product of H.C.F and L.C.M of any two numbers is equal to the product of that numbers. Calculation: H.C.F of two numbers = 4 Let, numbers = 4x and 4y respectively Using formula, 4x × 4y = 4 × 308 (Given) ⇒ x × y = 308/4 = 77 ⇒ x × y = 77 Possibilities of x and y are (1, 7) and (77, 11) [Both sets are co – prime] Taking x = 1 and y = 77 Numbers are 1 × 4 = 4 and 77 × 4 = 308 None of the numbers lie between 30 -50, therefore we can’t take these numbers. Now, taking x = 7 and y = 11 Numbers are 7 × 4 = 28 and 11 × 4 = 44 And 44 lies between “30- 50” ∴ Sum of the digits = 4 + 4 = 8 |
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