Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The correct order of basic nature isA. `B_(2)O_(3) lt Al_(2)O_(3) lt In_(2)O_(3) lt Tl_(2)O`B. `B_(2)O_(3) gt Al_(2)O_(3) gt In_(2)O_(3) gt Tl_(2)O`C. `B_(2)O_(3) lt Tl_(2)O lt Al_(2)O_(3) lt ln_(2)O_(3)`D. `B_(2)O_(3) lt In_(2)O_(3) lt Tl_(2)O lt Al_(2)O_(3)`

Answer» Correct Answer - A
`B_(2)O_(3) lt A_(2)O_(3) lt Imn_(2)O_(3) lt Tl_(2)O` =basci nature order
`to` size of atom increases
`to` Tendency to loose of electron increases
`to ` Basic nature decreases
`to` Acidic nature increases
2.

A container with a volume of 20.0 L holds `N_(2(g))` and `H_(2)O_((l))` at 300 K and 1.0 atm. The liquid water is then decomposed completely into `H_(2(g))` and `O_(2(g))` by any means, at constant temperature, if the final pressure becomes 1.86 atm, what was the mass of water (jn gm) present initially. Neglect the initial volume of water: [Given : vapour pressure of water at 300 K=0.04 atm L-atm / K -mol]

Answer» Correct Answer - 2
`P_(gas)=1-0.04 =0.96 gm`
`{:(H_(2)O_((l)) hArr,H_(2(g)),+,1/2 O_(2(g))),("x=0.5 mole",x,,x/2" "=3/2 x =1.86 -0.96 =0.9),(=9gm,,,),(0.9xx20=3/2x xx24,,,x=0.6),(0.5=12/24 =x,,,):}`
3.

Which of the following are linear ?A. `(CN)_(2)`B. `(SCN)_(2)`C. `O_(3)`D. `HgCl_(2)`

Answer» Correct Answer - BCD
`ddot(N)-=C-C-=ddot(N)to "linear" " " O_(3)` = Bent
Cl-Hg-Cl`to ` linear `" " ` SCN=Bent
4.

When electrons are de-exciting from nth orbit of hydrogen atoms to ground state, 15 spectral lines are formed. The shortest wavelength among these will beA. `11/900R`B. `36/(35R)`C. `35/36R`D. `35/(36R)`

Answer» Correct Answer - B
`(n(n-1))/2=15 rArr n=6`
`1/(lambda)=Rxx1^(2)[1/(1^(2))-1/(6^(2))]=Rxx35/36`
`lambda=36/(35R)`
5.

Which of the following resonating structure is most stable ?A. `CH_(3) -underset(..)(ddotO)-CH=CH-overset(o+)(C)H_(2)`B. `CH_(3) -underset(..)(ddotO)-overset(o+)(C)H_(2)-CH=CH_(2)`C. `CH_(3) -underset(..)(ddotO)-overset(o+)(C)H_(2)-overset(Theta)(C)H-overset(o+)(C)H_(2)`D. `CH_(3)-overset(o+)underset(..)(O)=CH-CH=CH_(2)`

Answer» Correct Answer - B
Polar complete octet
6.

Which of the following has the highest lattice energy ?A. NaFB. `MgF_(2)`C. `AlF_(3)`D. `CaF_(2)`

Answer» Correct Answer - C
`L.E. alpha (q_(1)q_(1))/(r^(2)), Al^(3+)` ion has maximum positive charge, hence `AlF_(3)` has maximum L.E.
7.

A hydrogen like specie is in a spherical symmetrical orbital `S_(1)` having 3 radial node. It gets dexcited to another level `S_(2)` having no radial node. Energy of `S_(2)` orbital is 2.25 times energy of 1st bohr orbit of hydrogen atom. Based on this information answer the questions that follow. Identify the specie involvedA. `He^(+)`B. `Be^(+3)`C. `Li^(+2)`D. `B^(+4)`

Answer» Correct Answer - D
`S_(2)=2.25 (S_(1))_(H)`
`13.6xx(Z^(2))/(n^(2)) =9/4 xx 13.6`
`Z=3 rArr Li^(2+)`
8.

A hydrogen like specie is in a spherical symmetrical orbital `S_(1)` having 3 radial node. It gets dexcited to another level `S_(2)` having no radial node. Energy of `S_(2)` orbital is 2.25 times energy of 1st bohr orbit of hydrogen atom. Based on this information answer the questions that follow. What is the orbital angular momentum quantum number of `S_(2)` ?A. 1B. 0C. 2D. `h/(2pi)`

Answer» Correct Answer - C
`2s to 2 -0 -1 =1 `radial node
`2p to 2-1-1=0` radial node
9.

A hydrogen like specie is in a spherical symmetrical orbital `S_(1)` having 3 radial node. It gets dexcited to another level `S_(2)` having no radial node. Energy of `S_(2)` orbital is 2.25 times energy of 1st bohr orbit of hydrogen atom. Based on this information answer the questions that follow. What is the combined total number of nodes (radial+angular) in `S_(1)` and `S_(2)` ?A. 4B. 3C. 5D. 6

Answer» Correct Answer - B
`{:(S_(1)=4s,,S_(2)=2p),.("Total node=4-1",+,2-1=4):}`
10.

A fiber of length `10`cm is illuminated with light from an light emitting diode (LED) which is turned on and off repeatedely for equal amount of time. The speed of the pulse of light are `2.00xx10^(8)m//s` and `2.1xx10^(8)m//s` in fiber. Maximum frequency of LED os that pulse arrive without overlapping is `60X(KHz)`. Calculate `X`.

Answer» Correct Answer - 7
`Deltat=(10km)/(2xx10^(8))-(10km)/(2.1xx10^(8))`
`=(10xx10^(3))/(10^(8))[(2.1-2)/4.2]=1/(10^(4))xx1/((42))`
`f=42xx10^(4)=420Khz=60xxKhzimpliesX=7`
11.

Figure shows two coherent sources `S_(1)-S_(2)` vibrating in same phase. `AB` is an irregular wire lying at a far distance from the sources `S_(1)` and `S_(2)`. Let `(lamda)/d=10^(-3)m,/_BOA=0.12^(@)`. How many bright spots will be seen on the wire, including points `A` and `B`

Answer» Correct Answer - 3
Angular width `=(lamda)/d=10^(-3)` (given)
`:.` No. of fringes within `0.12^(@)` will be
`n=(0.12xx2pi)/(360xx10^(-3))~=[2.09]`
`:.` The number of bright spots will be three.
Hence (B).
12.

On a disc of radius `R` a concentric circle of radius `R//2` is drawn. The disc is free to rotate about a frictionless fixed axis through its center and perpendicular to plane of the disc. All three forces `(` in plane of the disc `)` shown in figure are exerted tangent to their respective circular periphery. The magnitude of the net torque `(` about centre of disc `)` acting on the disc is `:` A. `1.5 FR`B. `1.9 FR`C. `2.3 FR`D. `2.5 FR`

Answer» Correct Answer - A
Toreque `tau = (2f)R + F((R)/(2)) + FR(-1) = (3FR)/(2)`
13.

The area of region between `y=sinx` and `x-` axis in the interval `[0,(pi)/(2)]` will be `:`A. 1B. 0C. 2D. `(1)/(2)`

Answer» Correct Answer - A
`underset(0)overset(pi//2)intsinxdx=[-cosx]_(0)^(pi//2)=1`
14.

On a disc of radius `R` a concentric circle of radius `R//2` is drawn. The disc is free to rotate about a frictionless fixed axis through its center and perpendicular to plane of the disc. All three forces `(` in plane of the disc `)` shown in figure are exerted tangent to their respective circular periphery. The magnitude of the net torque `(` about centre of disc `)` acting on the disc is `:` A. `1.5FR`B. `1.9FR`C. `2.3FR`D. `2.5FR`

Answer» Correct Answer - A
Torque `tau=(2F)R+F((R)/(2))+FR(-1)`
`=(3FR)/(2)`
15.

A particle starts moving from rest the origin `&` moves along positive `x-` direction . Its rate of change of kinetic energy with time shown on `y-` axis veries with time `t` as shown in the graph. If position, velocity , acceleration `&` kinetic energy of the particle at any time `t` are `x,v,a,& k` respectively then which of the option `(s)` may be correct ? A. B. C. D.

Answer» Correct Answer - A::B::D
`(dk)/(dt)prop t`
`rArr k prop t^(2) .....(i)`
`rArr v prop t ...(ii)`
`rArr v vs t:st. ` line
`rArr x propt^(2) ....(iii)`
`rArr x vs t :` parabola
`(i) & (iii)`
`rArr k prop x :` st. line
`(ii)rArra=` constant
`(ii) & (iii) rArr v^(2) prop x .....(v) v^(2)vs x: st. `line
16.

A radioactive isotope `._(Z)X^(A)` is converting into `._(Z-8)Y^(A-16)` by `alpha`-decay. If g-atoms `._(Z)X^(A)` produced 3 mole of He atoms in 20 hours, then calculate the half life of `._(Z)X^(A)` (in hours).A. 10B. 5C. 2D. 1

Answer» Correct Answer - A
`{:(._(Z)X^(A)to,Y+,4_(2)^(4)He,),("1 mole",,"4 mol",),(1-x,,4x,),(,,4x=3,),(,,x=(3)/(4),):}`
`K=(1)/(20)ln4`
`t_(1//2)=(ln2)/((1)/(10)ln2)`
`t_(1//2)=10" hrs. "]`
17.

Select the correct statement(s)A. Calamine and siderite and carbonatesB. Argentite and cuprites are oxides.C. Zinc blende andiron-pyrite are sulphidesD. Malachite and azurite are ores of Cu.

Answer» Correct Answer - A::C::D
Argentite is `Ag_(2)S`.
18.

Which of the following alkyl halides would be most likely to give a rearranged product under `S_(N)1` conditions ?A. B. C. D.

Answer» Correct Answer - C
In C there will be a carbocation rearrangment from `1^(@)" to "3^(@)" "]`
19.

Following is the graph between `(a-x)^(-1)` and time for second order reaction `Ato2B,Q=tan^(-1)(0.5),OA=2Lmol^(-1)`. Here is the initial concentration of reactant and x is its amount reactedc at any time t. Hence rate at the start of the reaction is:A. `0.125Lmol^(-1)mol^(-1)`B. `0.25molL^(-1)min^(-1)`C. `0.125molL^(-1)min^(-1)`D. `0.25Lmol^(-1)min^(-1)`

Answer» Correct Answer - C
For second order reaction,
`because(a-x)^(-1)=(1)/(Kt)+(I)/(a)`
`becausek=tantheta(becausetantheta=0.5` from question)
`becauseK=0.5` lit `mol^(-1)min^(-1)`
and `(I)/(a)=2` or `a=0.5M`
`r=Ka^(2)`
`=0.5xx0.5^(2)`
`=0.125molL^(-1)min^(-1)`
20.

End-product of which of following reaction give positive Iodoform test.A. `H-overset(O)overset(||)C-Clunderset((ii)H^(o+))overset((i)CH_(3)MgBr("excess"))to`B. `Ph-overset(O)overset(||)C-O-Etunderset((ii)H^(o+))overset((i)CH_(3)MgBr("excess"))to`C. `H-overset(O)overset(||)C-O-Etunderset((ii)H^(o+))overset((i)CH_(3)MgBr("excess"))to`D. `H-overset(O)overset(||)C-Hunderset((ii)H^(o+))overset((i)CH_(3)MgBr("excess"))to`

Answer» Correct Answer - A::B::C::D
`H-overset(O)overset(||)C-Clunderset((ii)H^(o+))overset((i)MeMgBr("excess"))toH-underset(Me)underset(|)overset(OH)overset(|)C-Meto+ve" Iodoform test"`
`H-overset(O)overset(||)C-Etunderset((ii)H^(o+))overset((i)MeMgBr("excess"))toH-underset(Me)underset(|)overset(OH)overset(|)C-Meto+ve" Iodoform test"`
`CH_(3)-overset(O)overset(||)C-Hunderset((ii)H^(o+))overset((i)CH_(3)MgBr("excess"))toCH_(3)-overset(OH)overset(|)CH-CH_(3)to+ve" Iodoform test"`
21.

Explain Hoffmann’s bromamide degradation reaction for the preparation of methanamine.

Answer»

When an amide is treated with bromine in aqueous or alcoholic solution of NaOH, primary amine is formed. 

Ex: CH3CONH2 + 4NaOH + Br2 → CH3NH2 + Na2CO3 + 2NaBr + H2O

22.

What is the minimum pressure required in a transfer molding process?(a) 20 MPa(b) 40 MPa(c) 50 MPa(d) 70 MPa

Answer» The correct option is (a) 20 MPa

Easiest explanation: The maximum pressure that is required for the complete operation of transfer molding is 20 MPa.
23.

What is the maximum pressure required in a transfer molding process?(a) 80 MPa(b) 90 MPa(c) 100 MPa(d) 120 MPa

Answer» Right choice is (c) 100 MPa

Best explanation: Processing of thermosetting plastics is classified as, compression molding and transfer molding. The maximum pressure that is required for the complete operation of transfer molding is 100 MPa.
24.

What is the minimum curing time required in a compression molding process?(a) 0.4 minutes(b) 0.5 minutes(c) 0.6 minutes(d) 0.7 minutes

Answer» Right choice is (b) 0.5 minutes

Explanation: The minimum curing time that is required for the complete operation of compression molding is 0.5 minutes.
25.

What is the minimum temperature required in a compression molding process?(a) 120°C(b) 125°C(c) 130°C(d) 135°C

Answer» The correct choice is (b) 125°C

The explanation: None.
26.

What is the minimum pressure required in a compression molding process?(a) 0.5 MPa(b) 1 MPa(c) 1.5 MPa(d) 2 MPa

Answer» Right answer is (a) 0.5 MPa

To explain: Processing of thermosetting plastics is classified as, compression molding and transfer molding. The minimum pressure that is required for the complete operation of compression molding is 0.5 MPa.
27.

Write four points of distinction between lanthanoids and actinoids.

Answer»
LanthanoidsActinoids
a.In lanthanoids, last differentiating electron occupies 4f orbital.In actinoids, last differentiating electron occupies 5f orbital.
b.They are the elements of first inner transition series.Theyare the elements of second inner transition series.
c.They are present in period 6.They are present in period 7.
d.Most of lanthanoids (with exception of promethium) occur in nature.Most of actinoids (with exception of uranium and thorium) are prepared in laboratory.
e.Most of lanthanoids (with exception of promethium) are non-radioactive.All the actinoids are radioactive.
f.Lanthanoids do not form oxo cation.Actinoids form oxo cation such as \(UO^{2+}_2\) , PuO2+, UO+ .
g.4f orbitalsin lanthanoids have higher binding energy.5f orbitals in actinoids have lower binding energy.
h.Contraction in atomic and ionic radii is relatively less in lanthanoids.Contraction in atomic and ionic radii is relatively greater in actinoids due to poor shielding of 5f electrons.
i.Lanthanoids show +2, +3 and +4 oxidation states.Actinoids show +3, +4, +5, +6, +7 oxidation states.
j.Lanthanoids have less tendency to form complexes.Actinoids have greater tendency to form complexes.
k.Some ions of lanthanoids are coloured.Most of the ions of actinoids are deeply coloured.
l.Lanthanoid hydroxides are less basic in nature.Actinoid hydroxides are more basic in nature.

28.

What is the name of the surface-to-surface nuclear-capable inter-continental ballistic missile developed by the Defence Research and Development Organization (DRDO)?1. Prithvi II2. Trishul3. Agni 54. Barak-8

Answer» Correct Answer - Option 3 : Agni 5

The correct answer is Agni 5.

  • Agni 5 is the name of the surface-to-surface nuclear-capable inter-continental ballistic missile developed by the Defence Research and Development Organization (DRDO).
  • The missile is believed to have a range of around 5,000 to 8,000 km.
  • Its first flight was conducted in 2012.

About DRDO:

  • Present chief Secretary - Dr G Satheesh Reddy.
  • Headquarters - New Delhi.
  • DRDO was founded in 1958.
29.

State and explain Hund’s rule of maximum multiplicity?

Answer» It states that pairing of e in the degenerate orbital is not possible until there is one e in each orbital.A ball is thrown horizontally from the top of the tower a speed of 50m/s. Find the velocity and position the end of 3 sec.
30.

If screening does not split the subshell(l) of a given shell(n), how many elements would occur in 5th period.A. 50B. 32C. 18D. 64

Answer» then no of electrons in 5th shell=no. of electron in 5th pd=2xxn^(2)=2xx5^(2)=50`
31.

Maximum number of electron that can exist in completely filled n=4 enrgy level.A. 18B. 32C. 50D. 8

Answer» `2n^(2)=2xx4^(2)=32`
32.

Which of the following statement is correct for an element having atomic number (z)=98?A. It is s-block element.B. It is p-block element.C. It is transition element.D. It is inner transition element.

Answer» z=98
configuration `=[Ra]_(86)7s^(2)5f^(10)`
fblock element=inner transition element
33.

Successive ionization enthalpies (in eV/atom) of on element are 5,8,9,90,100. The number of valence electrons are:A. 1B. 2C. 3D. 4

Answer» Number of valence electron =3 as difference between `IE_(3) & IE_(4)` is very high.
34.

Orbital angular momentum associated with 2p-electron is:A. `sqrt(2)h)/(pi)`B. `0`C. `sqrt(6)xx(h)/(pi)`D. `(h)/sqrt(2pi)`

Answer» Orbital angular momentum `=sqrt(l(l+1))(h)/(2pi)` for p subshell, l=1
`=sqrt(2)(h)/(2pi)=(h)/sqrt(2pi)`
35.

Mrs. Simpson ________ £1000 to the Dogs’ Home when she died. A) remained B) left C) presented D) offered E) permitted

Answer»

Correct option is B) left

36.

Mrs. Simpson will visit ________ Spain or Greece. A) both B) either C) neither D) between

Answer»

Correct option is B) either

37.

On what parameter do the Elements are classified in the modern periodic table?

Answer» Atomic number
38.

What type of Van der waals force exists between HCI molecules? 

Answer»

Dipole – dipole interaction

39.

Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 x 1024 per second, calculate the power of this laser.

Answer»

Energy of photos emitted in 1 s =Nhu = Nh\(\frac{C}{\lambda}\) 

\(\frac{5.6\times10^{24}s^{-1}\times 6.626\times10^{-34}Js\times 3\times 10^3ms^{-1}}{337.1\times 10^{-9}m}\) 

= 33Js-1

40.

What is meant by compressibility factor of gases? How does its value deviate from that of an ideal gas in case of real gases and what does it indicate?

Answer»

It is the ratio of the product PV to nRT. 

Z = PV/nRT. For ideal gas its value is unity. Z < 1 indicates negative deviation i.e. gas is more compressible due predominance of attractive forces. Z > 1 indicates positive deviation i.e. gas is less compressible due predominance of repulsive forces.

41.

What is Active Mass?

Answer»

Active mass is represented by [ ] and expressed as

Active Mass = activity coefficient × Concentration.

For dilute liquid solution and gases behaving ideally activity coefficient is taken as unity. Thus active mass is equal to concentration for dilute liquid solutions and ideal gases. Active mass of liquids and solids is taken as unity.

42.

What is Chemical equilibrium?

Answer»

As reaction proceeds concentration of reactants decrease and concentration of products increase, thus rate of forward reaction decreases and rate of backward reaction increases with time and after some time rate of forward reaction equals to rate of backward reaction.

Rateforward = Ratebackward  

That means that amount of products formed by forward reaction is equal to amount of products consumed in backward reaction, similarly amount of reactants consumed in forward reaction is equal to amount of it formed by backward reaction, thus net concentration of reaction species remain constant and rate of two reactions also get constant. Thus is termed as state of chemical equilibrium.

43.

Compare the stability of carbocations(a) A &gt; B &gt; C (b) B &gt; C &gt; A (c) A &gt; C &gt; B (d) C &gt; A &gt; B

Answer»

(a) A > B > C 

In A lone pairs of oxygen causes extra stability of carbocation through resonance In B +I effect of two alkyl groups increase the stability of carbocation In C-I effect of OH decreases the stability of carbocation

44.

A vessel contains air and vapor H2O, if the partial pressure of vapor H2O is 4 atm and pressure of air is 1 atm, what is the fraction of vapor H2O in vessel?(a) 0.25(b) 0.5(c) 0.75(d) 0.8

Answer» Correct option is (c) 0.75

The best explanation: yH2O = 15/(15 + 5) = 0.75.
45.

I’m afraid I took your umbrella by ________. A) fault B) error C) misdeed D) mistake E) misjudgment

Answer»

Correct option is D) mistake

46.

Find the antonym of words:Shove A) press B) drag C) move D) thrust

Answer»

Correct option is B) drag

47.

Crazy A) cruel B) chubby C) wild D) mad

Answer»

Correct option is D) mad

48.

Find the word which is out of the logic list:A) acquittal B) accusation C) allegation D) charge

Answer»

Correct option is A) acquittal

49.

Find the word which is out of the logic list:A) innocent B) lawbreaker C) criminal D) culprit

Answer»

Correct option is A) innocent

50.

I can’t understand why you are so BUSY at home. A) engaged B) sleepy C) afraid D) free E) angry

Answer»

Correct option is D) free