This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Form a new word by adding a suitable suffix to the root word “court”. (a) ________able (b) ________ship (c) ________less (d) ________age |
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Answer» Correct answer is (b) courtship |
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| 2. |
Form a new word by adding a prefix to the root word “circle”. (a) anti__________ (b) a__________ (c) semi__________ (d) co________ |
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Answer» Correct answer is (c) semicircle |
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| 3. |
Replace the underlined word with the appropriate phrasal verb. The ancestral jewelry has been handed down from generation to generation.(a) stored (b) delivered (c) hidden (d) distributed |
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Answer» Correct answer is (b) delivered |
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| 4. |
Form a new word by adding a prefix to the root word “cook”.(a) un__________ (b) over_________(c) im__________ (d) dis_________ |
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Answer» Correct answer is (b) overcook |
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| 5. |
What is the plural form of ‘military’? (a) military (b) militarys (c) militares (d) militaries |
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Answer» Correct answer is (d) militaries |
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| 6. |
Form a new word by adding a suitable prefix to the root word “estimate”. (a) under__________ (b) un__________ (c) dis_________ (d) de__________ |
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Answer» Correct answer is (a) underestimate |
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| 7. |
Form a new word by adding a suitable prefix to the root word ‘series”. (a) tele__________ (b) un__________ (c) dis__________ (d) re__________ |
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Answer» Correct answer is (a) teleseries |
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| 8. |
Form a new word by adding a suitable prefix to the root word “case”. (a) post__________ (b) un__________(c) dis__________ (d) en__________ |
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Answer» Correct answer is (a) encase |
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| 9. |
Form a new word by adding a suitable prefix to the root word “bug”.(a) ante__________ (b) anti__________ (c) un__________ (d) de_________ |
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Answer» Correct answer is (d) debug |
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| 10. |
Form a new word by adding a suitable suffix to the root word “defy”. (a) _______hood (b) _________ism (c) _______ance (d) ________ful |
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Answer» Correct answer is (c) defiance |
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| 11. |
Form a new word by adding a suitable prefix to the root word “contaminate”. (a) de__________ (b) un__________ (c) dis__________ (d) re__________ |
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Answer» Correct answer is (a) decontamin |
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| 12. |
Form a new word by adding a prefix to the root word “difference”. (a) un________ (b) in________ (c) im________ (d) dis________ |
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Answer» (b) indifference |
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| 13. |
Form a new word by adding a suitable prefix to the root word “important”. (a) in________ (b) un________ (c) dis________ (d) mis________ |
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Answer» (b) unimportant |
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| 14. |
Form a new word by adding a suitable suffix to the root word “poet”. (a) ________al (b) ________ic (c) ________ile (d) ________ion |
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Answer» Correct answer is (b) poetic |
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| 15. |
Form a new word by adding a suitable prefix to the root word “cast”. (a) de________ (b) in________ (c) en________ (d) fore________ |
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Answer» Correct answer is (d) forecast |
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| 16. |
Form a new word by adding a suitable prefix to the root word “sound”. (a) post__________ (b) un__________ (c) ultra__________ (d) re________ |
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Answer» Correct answer is (c) ultrasound |
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| 17. |
Form a new word by adding a suitable prefix to the root word “fortune”. (a) in________ (b) un________ (c) dis________ (d) mis________ |
| Answer» (d) misfortune | |
| 18. |
essay about if there were no doctors |
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Answer» With doctors, those with life-affecting diseases can prolong their life, which can lead to reproduction. The gene for the disease would then be passed on from generation to generation. If doctors weren't here to help them, they would most likely die off. Only the healthy would survive and reproduce. How do doctors help us? What is the purpose of a doctor? Who is a doctor in simple words? |
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| 19. |
All eyes turned in that direction. The figure of speech in the line is (A) Personification (B) Metaphor (C) Synecdoche (D) Alliteration |
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Answer» (C) Synecdoche |
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| 20. |
A: Do you mind if I ______ your dictionary? B: No, that’s all right. A) will use B) used C) use D) to use |
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Answer» Correct option is C) use |
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| 21. |
If z = (2+ 3i) ( 1+ 2i) find z-¹ |
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Answer» Z = (2 + 3i)(1 + 2i) = 2 + 4i + 3i + 6i2 = 2 – 6 + 7i \((\because i^2 =-1)\) = –4 + 7i Now, Z–1 \(=\frac{1}{z}=\frac{1}{-4+7i}\) \(=\frac{1}{-4+7i}\times \frac{4+7i}{4+7i}\) \(=\frac{4+7i}{49i^2-16}\) \(=\frac{4+7i}{-49-16}\) \((\because i^2=-1)\) \(=\frac{-1}{65}(4+7i)\) |
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| 22. |
........ with your work. You need not stand”, said the visiting minister to his staff. The correct phrasal verb to be filled in the blank is (A) Carry away (B) Carry out (C) Carry on (D) Carry off |
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Answer» (C) Carry on |
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| 23. |
Same meaning of sut violently |
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Answer» Answer: forcefully, forcibly, powerfully, overwhelmingly, destructively, furiously, strongly, fiercely, abruptly and mercilessly. |
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| 24. |
A geometric sequence has all positive terms. The sum of the first two terms is 15 and the sum to infinity is 27. Find the value of a)the common ratio |
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Answer» \(\because\) a + ar = 15 ⇒ a(1 + r) = 15 ⇒ a \(=\frac{15}{1+r}\) And sum of infinite term = 27 (Given) \(\therefore \frac{a}{1-r}=27\) \(\Rightarrow \frac{15}{(1+r)(1-r)}=27\) \(\Rightarrow 1-r^2 = \frac{15}{27}=\frac{5}{9}\) \(\Rightarrow r^2=1-\frac{5}{9}=\frac{4}{9}\) \(\Rightarrow r=\pm\frac{2}{3}\) \(\Rightarrow \) But r \(\ne \frac{-2}{3}\) \((\because \) all terms of g.p are positive) \(\therefore\) common ratio \(=r=\frac{2}{3}\) |
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| 25. |
Fill in the blank with appropriate ‘preposition’ : Madhuri was filled ...... surprise when her name was’ called out. |
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Answer» Madhuri was filled with surprise when her name was’ called out. |
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| 26. |
That’s the right answer, ..... The question tag to be added is (A) doesn’t it? (B) isn’t it? (C) is it? (D) wasn’t it? |
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Answer» (B) isn’t it? |
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| 27. |
He was suspected ...... having stolen the book. The appropriate preposition to be filled in the blank is . (A) to (B) for (C) of (D) with |
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Answer» He was suspected of having stolen the book. |
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| 28. |
The word in which ‘mis’ is a part of the word but not a prefix is (A) misjudge (B) mistake (C) misdeed (D) miscalculate |
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Answer» (B) mistake |
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| 29. |
Find out the unit normal to the surface xy3z2= 4 at (1,12) |
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Answer» Surface xy3z2 = 4 ∴ Normal vector to given surface is ∇(xy3z2) \(=\hat i\frac{\partial}{\partial\mathrm x}\mathrm xy^3z^2+\hat j \frac{\partial}{\partial y}\mathrm x y^3z^2+\hat k\frac{\partial}{\partial z}(\mathrm xy^3z^2)\) = y3z2\(\hat i\) + 3xy2z2\(\hat j\) + 2xy3z\(\hat k\) Normal vector to given surface at (1, 1, 2) is \(\mathrm{\left[\nabla(xy^3z^2)\right]}_{(1, 1, 2)}\) = 4\(\hat i\) + 12\(\hat j\) + 8\(\hat k\) (By putting x = 1, y = 1, z = 2) So, the vector normal to surface xy3z2 = 4 is 4\(\hat i\) + 12\(\hat j\) + 8\(\hat k\). |
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| 30. |
Which of the following used as a side mirror |
| Answer» Convex mirror is used as side mirror in vehicles. | |
| 31. |
If the lines(x - 1)/-3 = (y - 2)/2λ = (z - 3)/2and (x - 1)/3λ = (y - 5)/1 = (z - 6)/-5are at right angles to each other, then λ is equal to (A) 9/7 (B) -9/7 (C) -10/7 (D) 10/7 |
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Answer» Correct option is (C) -10/7 |
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| 32. |
Bihar board 12th result 2020 announced |
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Answer» BSEB has announced BSEB 12th result 2020 today, on biharboardonline.bihar.gov.in or can be checked from the direct link on this page.
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| 33. |
Physical science class 8 |
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Answer» what is vibration? Vibration is a to and from motion of the particles coming from the source.
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| 34. |
What is the amount of energy converted by a bulb of 60W In 30s |
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Answer» E = P x t E = Power x time E = 60 x 30 60×30 = 1,800 J E = P x t E = Power x time E = 60 x 30 E = 1800 Joule. |
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| 35. |
f(x) = {((sin(a + 2)x + sinx)/x; x < 0), (b; x = 0), ((x + 3x2)1/3 - x1/3)/x4/3; x > 0) Function is continuous at x = 0, find a + 2b. |
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Answer» LHL = a + 3 f(0) = b RHL = lim(h →0)((1 + 3h)1/3 - 1)/h) = 1 ∴ a = - 2 b = 1 ∴ a + 2b = 0 |
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| 36. |
The energy of emitted photoelectrons depends up on |
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Answer» The energy of the emitted photoelectrons are directly proportional to the frequency of the incident radiation. |
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| 37. |
If the area enclosed by `g(x),x=-3, x = 5` and x-axis where g(x) is the inverse `f(x) = x^3 + 3x + 1` is A, then [A] is |
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Answer» Correct Answer - 4 4 |
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| 38. |
If `m, n, r, in N` then `.^(m)C_(0).^(n)C_(r) + .^(m)C_(1).^(n)C_(r-1)+"…….."+.^(m)C_(r).^(n)C_(0)` `=` coefficient of `x^(r)` in `(1+x)^(m)(1+x)^(n)` `=` coefficient of `x^(f)` in `(1+x)^(m+n)` The value of r for which `S = .^(20)C_(r.).^(10)C_(0)+.^(20)C_(r-1).^(10)C_(1)+"........".^(20)C_(0).^(10)C_(r)` is maximum can not beA. `7`B. `8`C. `10`D. `15` |
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Answer» Correct Answer - A::B::C `S = .^(30)C_(r)`, which is maximum for `r = 15` |
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| 39. |
`f (x)= max |2 sin y-x|` where `y in R` then determine the minimum value of `f (x).` |
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Answer» Correct Answer - 2 2 |
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| 40. |
If `m, n, r, in N` then `.^(m)C_(0).^(n)C_(r) + .^(m)C_(1).^(n)C_(r-1)+"…….."+.^(m)C_(r).^(n)C_(0)` `=` coefficient of `x^(r)` in `(1+x)^(m)(1+x)^(n)` `=` coefficient of `x^(f)` in `(1+x)^(m+n)` The value of `r(0 le r le 30)` for which S = `.^(20)C_(r).^(10)C_(0) + .^(20)C_(r-1).^(10)C_(1) + ........ + .^(20)C_(0).^(10)C_(r)` is minimum can not beA. `0`B. `1`C. `30`D. `15` |
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Answer» Correct Answer - B::D `S = .^(30)C_(r)`, is least at `r = 0` and `r = 30` |
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| 41. |
Least positive inegral value of `x` satisfying `|4x + 3| + |3x - 4| = |7x - 1|` is |
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Answer» Correct Answer - 2 `|4x + 3| + |3x - 4| = |4x + 3 + 3x - 4|` `|a| + |b| = |a + b|` `ab ge 0` `(4x + 3)(3x - 4) ge 0` `x in (-oo, -(3)/(4))cup[(4)/(5), oo)` Least positibe integral value of `x` satisfying the equation is `2` |
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| 42. |
If `M & alpha` are twin prime `&alpha+M=7` then the greatest integral value of `N` isA. `64`B. `63`C. `125`D. `124` |
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Answer» Correct Answer - A::B If `alpha = 2m m = 65`, If `alpha = 5, m = 5` `log_(epsilon)N = (2 + beta), log_(2)N = 5 + beta` `N in [5^(2), 5^(3)) = [25, 125), N in [2^(5), 2^(6)) = [32, 64)` `:. N_(min) = 124, :. N_(max) = 63` |
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| 43. |
The sum `(2^(1))/(4^(1) - 1) + (2^(2))/(4^(2) - 1) + (2^(4))/(4^(4) - 1) + (2^(8))/(4^(8) - 1) +... oo` is equal to |
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Answer» Correct Answer - 1 sum `=sum_(k=0)^(oo)(2^(2^k))/(4^(2^(k))-1) = sum((2^(2^(k)) +1)/(4^(2^(k))-1)-(1)/(4^(2^(k))-1))` `sum((1)/(2^(2^(k))-1)-(1)/(4^(2^(k))-1))=sum((1)/(2^(2(2^(k-1))))-(1)/(4^(2^(k))-1))` `= sum_(k=0)^(oo)((1)/(4^(2^(k))-1)-(1)/(4^(2^(k))-1))` `= ((1)/(4^(2^(1))-1)-(1)/(4^(2^(0))-1))+((1)/(4^(2^(0))-1)-(1)/(4^(2^())-1))+((1)/(4^(2^(1))-1)-(1)/(4^(2^(2))-1))`.....{x}+{-x}={{:(0 if x in I), (1 if x !in I):}` `= (1)/(4^(-2^(1))-1) = (1)/(2-1) = 1` |
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| 44. |
Let p(x) = `a_0+a_1x+ a_2x^2+.............+a_n x^n` be a non zero polynomial with integer coefficient . if p(`sqrt(2)`+`sqrt(3)`+`sqrt(6)`)=0 , the smallest possible value of n . is |
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Answer» Correct Answer - 4 4 |
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| 45. |
If `M & alpha` are twin prime `&alpha+M=7` then the greatest integral value of `N` isA. `25`B. `32`C. `6`D. `81` |
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Answer» Correct Answer - A::B::D `alpha_(1), m in {3, 4}, {2, 5}, {1, 6}` `alpha = 3, m = 4 , log_(4)N = 3 + b , N in [4^(3), 4^(4)) = [64, 256)` `alpha = 4, m= 3 , N in [81, 243)` `alpha = 2, m = 5 , N in [25, 125)` `alpha = 5, m = 3 , N in [32, 64)` `alpha = 1, m = 6 , N in [6, 36)` `alpha = 6, m = 1 , m ne 1 :. N_(max) = 6` |
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| 46. |
d. \( \frac{x^{3}+5 x^{2}+4 x+3}{x^{3}} \) |
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Answer» Let f(x) =(x^3+5x^2+4x+3) /x^3 =1+5/x+4/x^2+3/x^3 d/dx(f(x)) =d/dx(1+5/x+4/x^2+3/x^3) = 0-5/x^2-8/x^3-9/x^4 = -5/x^2-8/x^3-9/x^4 therefore the derivative is -5/x^2 - 8/x^3 - 9/x^4
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| 47. |
Consider on equation with `x` as variable `7sin3x-2sin9x=sec^(2)theta+4cosec^(2)theta` then the value of `15/(2pi)`[minimum positive root-maximum negative root] is: |
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Answer» Correct Answer - 5 5 |
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| 48. |
In which of the following reactions correct major product is mentioned ?A. B. C. D. |
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Answer» Correct Answer - A,B,C,D All options are correct |
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| 49. |
Lagrange's theorem applicable for \( f(x)=x^{4 / 3} \) in \( [-1,1] \) |
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Answer» f(x) = x4/3, x ∈ [-1, 1] \(\because\) f(x) is continuous when x ∈[-1, 1]. and f-1(x) = d/dx(x4/3) = 4/3 x4/3 - 1 = 4/3 x1/3 \(\therefore\) f-1(x) is continuous when x ∈ [-1, 1]. \(\because\) Given function is satisfies both required conditions of Lagrange theorem. \(\therefore\) Lagrange theorem is applicable for f(x) = x4/3 in x ∈ [-1, 1]. |
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| 50. |
Lagrange's theorem applicable for \( f(x)=x^{4 / 3} \) in \( [-1,1] \). |
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Answer» f(x) = x4/3, x ∈ [-1, 1] \(\because\) f(x) is continuous when x ∈[-1, 1]. and f-1(x) = d/dx(x4/3) = 4/3 x4/3 - 1 = 4/3 x1/3 \(\therefore\) f-1(x) is continuous when x ∈ [-1, 1]. \(\because\) Given function is satisfies both required conditions of Lagrange theorem. \(\therefore\) Lagrange theorem is applicable for f(x) = x4/3 in x ∈ [-1, 1]. |
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