Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Choose the suitable answers of Section – B with Section – A.Section – ASection – B(i) Blue colour of sky(a) Dispersion of light(ii) Formation of rainbow(b) Scattering of light 

Answer»

i – b; ii – a.

2.

"No two electrons of the atom can have all the four quantum numbers same". Name the principal involved in this statement. (a) Hund's rule (b) Pauli's exclusion principle (c) Aufbau principle

Answer»

b (Pauli's exclusion principle)

3.

A sexual reproduction takes place through multiple fission in(a) Amoeba(b) Planaria(c) Hydra(d) Plasmodium

Answer»

(d) Plasmodium

4.

Which of the following Dam is built on Ganga?(a) Bhakra Nangal Dam(b) Sardar Sarovar(c) Tehri Dam(d) Krishna Sagar

Answer»

(c) Tehri Dam

5.

Correct bond energy order of following is-(1) C–Cl > C–Br > C–I > C–F (2) C–F < C–Cl < C–Br < C–I(3) C–F > C–Cl > C–Br > C–I  (4) C–I < C–Br < C–F < C–Cl 

Answer»

Answer: (3) C–F > C–Cl > C–Br > C–I 

Bond energy ∝ 1/Bond length

6.

A sample of red ink (a colloidal suspension) is prepared by mixing eosin dye, egg white, HCHO and water. The component which ensures stability of the ink sample is :- (1) HCHO (2) Eosin dye (3) Egg white (4) Water

Answer»

Answer is (3) Egg white

(3) Egg White.
7.

The following molecule acts as an:(1) Antiseptic (2) Anti-bacterial (3) Anti-histamine (4) Anti-depressant

Answer»

The correct option is (3) Anti-histamine.

8.

For a reaction 4M(s) + nO2(g)→ 2M2On(s) the free energy change is plotted as a function of temperature. The temperature below which the oxide is stable could be inferred from the plot as the point at which :(1) the slope changes from positive to zero (2) the free energy change shows a change from negative to positive value (3) the slope changes from negative to positive (4) the slope changes from positive to negative

Answer»

Correct answer is (2) The free energy change shows a change from negative to positive value

9.

Write 4 lines on chronology.

Answer»

The definition of chronological is arranged in the order it happened. An example of chronological is a biography that starts in 1920 and goes through 1997.

10.

If in the shown parallelogram `bar(AC) = -hat(i) + hat(j) - 3hat(k)` and `bar(BC) = 2 hat(i) + 5 hat(K)` then `bar(BD)` is A. `(5)/(2) hat(i) - (1)/(2) hat(j) + (13)/(2) hat(k)`B. `5hat(i) - hat(j) + 13hat(k)`C. `-5hat(i) + hat(j) - 13hat(k)`D. `-(5)/(2) hat(i) + (1)/(2) hat(j) - (13)/(2)hat(k)`

Answer» Correct Answer - B
The shown figure is a parallelogram. Then,
`bar(AB) + bar(BC) = bar(AC)` ……(i)
And `bar(BA) + bar(AD) + bar(AD) = bar(BD)` …..(ii)
Also, `bar(AB) = -bar(BA)` and `bar(BC) = bar(AD)` ….(iii)
so, from (ii) & (iii)
`-bar(AB) + bar(BC) = bar(BD)` ....(iv)
Adding (i) & (iv)
`2bar(BC) = bar(AC) + bar(BD)`
`bar(BD) = 2bar(BC) - bar(AC)`
11.

At `t=0`, a particle at `(1,0,0)` moves towards point `(4,4,12)` with a constant velocity of magnitude `65m//s`. The position of the particle is measured in metres and time in sec. Assuming constant velocity, the position of the particle at `t=2 sec` is `:`A. `(13hat(i)-120hat(j)+40hat(k))m`B. `(40hat(i)+31hat(j)-120hat(k))m`C. `(13hat(i)-40hat(j)+12hat(k))m`D. `(31hat(i)+40hat(j)+120hat(k))m`

Answer» Correct Answer - D
Unit vector in direction of `(1,0,0)` to `(4,4,12)` is `((4-1)hat(i)+(4,0)hat(j)+(12-0)hat(k))/(13)`
Hence position of particle at `t=2 sec` is `:`
`vec(r)_(f)=vec(r)_(i)+vec(v)xx2=31hat(i)+40hat(j)+120hat(k)`
12.

If a hyperbola has vertices (±6, 0) and P(10, 16) lies on it, then the equation of normal at P is(1) 2x + 5y = 100 (2) 2x + 5y = 10 (3) 2x – 5y = 100 (4) 5x + 2y = 100 

Answer»

Answer is (1) 2x + 5y = 100

Vertex is at (±6, 0)

∴ a = 6

Let the hyperbola is x2/a2 - y2/b2 = 1

Putting point P(10, 16) on the hyperbola

100/36 - 256/b2 = 1 ⇒  b2 = 144

∴ hyperbola is x2/36 - y2/144 = 1

∴ equation of normal is a2x/x1 + b2y/y1 = a2 + b2

∴ putting we get 2x + 5y = 100 

13.

At `t = 1` sec., a particle is at `(1, 2, 0)`. It moves towards `(, -8, 10)` with a constant speed of `50 m//s`. The position of the particle is measured in metres and the times in sec. Assuming constant velocity, the position of the particle at `t = 4s` is :A. `51hat(i) - 98 hat(j) + 100 hat(k)`B. `6 hat(i) - 8 hat(j) + 10 hat(k)`C. `5hat(i) - 10 hat(j) + 10 hat(k)`D. `50 hat(i) - 100 hat(j) + 100 hat(k)`

Answer» Correct Answer - A
`bar(S) = bar(V) xx t`
`bar(V) = |bar(V)| hat(V)`
`|bar(V)| = 50 m//s` and `hat(V) = (5 hat(i) - 10 hat(j) + 10 hat(k))/(15)`
`bar(S) = 50 ((5hat(i) - 10 hat(j) + 10 hat(k))/(15)) xx 3`
`= 50 hat(i) - 100 hat(j) 100 hat(k)`
`bar(S) = bar(r )_(f) - bar(r )_(1) = bar(r )_(f) - (hat(i) + 2 hat(j))`
`bar(r )_(f) = bar(S) + hat(i) + 2hat(j) = 51hat(i) - 98 hat(j) + 100 hat(k)`
14.

Which of the following statements about genes responsible for X-linked disease inheritance is/are TRUE? 1: They are located on the X chromosome. 2: They are passed on from mother to female child only. 3: They are passed to all male offsprings from male parent. 4: They are passed to all male offsprings from affected mother. A. only 1 B. only 1 and 4 C. only 2, 3 and 4 D. only 1, 2 and 3

Answer»

B. only 1 and 4 

15.

The negation of ‘ √5 is an integer or 5 is an irrational number’ is (1) √5 is an integer and 5 is not an irrational Number (2) √5 is not an integer and 5 is an irrational Number (3) √5 is not an integer or 5 is not an irrational Number (4) √5 is not an integer and 5 is not an irrational Number

Answer»

Answer is (4) 5 is not an integer and 5 is not an irrational Number

√5 is not an integer and 5 is not an irrational Number

(p ∨ q) = ~∧ ~ q

16.

The magnitude of the vector `X^(2)hat(i) + (X - 1) hat(j)` is same as that of the magnitude of vectore `-hat(j) + (X^(2) - 1) hat(k)`. The value of x isA. 1B. `-1`C. 0D. 2

Answer» Correct Answer - B
`sqrt((x^(2))^(2) + (x - 1)^(2)) = sqrt((1)^(2) + (x^(2) + 1)^(2))`
`x^(4) + x^(2) + 1 - 2x = 1 + x^(4) + 1 + 2x^(2)`
`x^(2) + 2x + 1 = 0`
`(x + 1)^(2) = 0`
`x = -1`
17.

An anther is made up of the following major parts: lobes, theca and sporangia. The theca are cavities in which the sporangia develop. Which of the following types of anther structure can develop into a tetrasporangiate anther? A. filamentous B. monothecous C. dithecous D. unlobed

Answer»

Correct option is C. dithecous 

18.

If a wrong type of pollen or pollen from a different species lands on the stigma, which of these in NOT formed? A. egg cell B. embryo C. embryo sac D. (all of the above will be formed)

Answer»

Correct option is B. embryo 

19.

Magnetic materials used for making permanent magnets (P) and magnets in a transformer (T) have different properties of the following, which property best matches for the type of magnet required? (1) T : Large retentivity, small coercivity (2) P : Large retentivity, large coercivity (3) P : Small retentivity, large coercivity (4) T : Large retentivity, large coercivity

Answer»

Answer (2) P : Large retentivity, large coercivity

Option (2) is correct as permanent magnet should have high coercivity & retentivity.

20.

PressureforceaccelerationVelocity

Answer»

Pressure Formula

Pressure is the force applied by one object on the another. It is symbolized by P.

Pressure is articulated as force per unit area articulated as

P=F/A

Where,

F = Force applied by the body,

A = Total area of the object.

Pressure Formula is given by

P=ρ x g x h

Where,

the height is h,

density is ρ,

gravity is g

Pressure Formula is made use of to compute pressure, force, area, density, height and gravity if some of these numerics are provided. Pressure is articulated in Pascal (Pa).

Force Formula

When one encounters the word Force they get an idea of getting energized. We continuously come across the term push and pull associated to it. 

In brief Force can be described as the exterior agency which makes the body change its state, size, position under strain. It is represented by F.

Commonly, the formula for force is articulated by

F = m × a

Where,

m = mass

a = acceleration.

It is articulated in Newton (N) or Kgm/s2.

Acceleration Formula

Acceleration is the rate of change in velocity to the change in time. It is denoted by symbol a and is articulated as- 

a=Change in velocity/Time taken

Meter per second squared or m/s2 is the S.I unit for Acceleration,

Velocity Formula

The speed of a body in a specific direction is the measure of Velocity.

It is represented by V and is articulated as

V=Displacement/Time Taken=s/t

Where,

the displacement is S  and

the time taken is t 

Since displacement is conveyed in meters and time taken in seconds. Velocity is articulated in meters/second or m/s.

21.

If electric field around a surface is given by |vectorE| = {Qin}/{ɛo|A|} where 'A' is the normal area of surface and Qin is the charge enclosed by the surface. This relation of gauss's law is valid when(1) Surface is equipotential (2) Magnitude of electric field is constant (3) Magnitude of electric field is constant & the surface is equipotential (4) For all Gaussian surfaces

Answer»

Answer is (3)

Magnitude of electric field is constant & the surface is equipotential

22.

Stopping potential depends on planks constant (h), current (I), universal gravitational constant (G) and speed of light (C) choose the correct option for the dimension of stopping potential (V)(1) hI–1G1C5 (2) h–1I1G–1C6 (3) h0I1G1C6 (4) h0I-1G–1C5

Answer»

Answer is (4)

V = K (h)a (I)b (G)c (C)d (V is voltage)

we know [h] = ML2T–1

[I] = A 

[G] = M–1 L3 T–2 

[C] = L T–1 

[V] = M L2 T–3 A–1

M L2 T–3 A–1 = (M L2 T–1)a (A)b (M–1L3T-2)c (LT–1)d

ML2T–3A–1 = Ma–c L2a+3c+d T–a–2c–d Ab

a – c = 1………………(1)

2a + 3c + d = 2………………(2)

–a –2c –d = –3 ………………(3)

b = –1………………(4)

on solving

c = –1 

a = 0 

d = 5, 

b = –1 

V = K (h)° (I)–1 (G)–1 (C) 5

23.

The value of vector[abc] is which of the following ?(A) 0 (B) 1

Answer»

Correct option:

(A) 0

24.

Which of the following is integrating factor of differential equation dy/dx + Py = Q, where P and Q are function of x. (A) e∫Pdx(B) e∫p.dx(C) e-∫Pdx(D) None of these

Answer»

Correct option:

(A) e∫Pdx

25.

The distance of the point (2, –3, –1) from the plane 2x – 3y + 6z + 7 = 0 is(A) 9 (B) 3 (C) 2 (D) 1/5

Answer»

Correct option:

(C) 2 

26.

the boiling temperatures from methane to propane increase because

Answer»

Methane, ethane, propane, and butane are gases at room temperature. As a result, it takes more energy to break these forces, and thus the melting or boiling points increase.

27.

.Which of the alkali metal is having least melting point?A. `Na`B. `K`C. `Rb`D. `Cs`

Answer» d. As the size of the metal increases, the strength of metallic bonding decreases and hence its melting point decreases. Since the size of `Cs` is the largest, therefore, its melting point is the lowest. Thus, option (d) is correct.
28.

Why `Be` generally form covalent compounds?

Answer» Due to small size and `+2` charge on `Be`, charge to radius ration of `Be` is high and thus beryllium has high polarising ability and form covalent compounds.
29.

Barium compounds are poisonous, even then `BaSO_(4)` is used in barium meal.Why?

Answer» The solubility of `BaSO_(4)` is extremely low and so it can be safely used for this purpose.
30.

Arrange hydroxides of group `2` elements in order of increasing basicity.

Answer» `Be(OH)_(2)ltMg(OH)_(2)ltCa(OH)_(2)ltSr(OH)_(2)ltBa(OH)_(2)`
31.

Arrange `Be,Mg,Ca,Sr` and `Ba` in increasing order of reactivity.

Answer» `BeltMgltCaltSrltBa`
32.

Which one of the following alkali metals gives hydrated salts?A. `Li`B. `Na`C. `K`D. `Cs`

Answer» a. Among alkali metal ions, `Li^(o+)` is the smallest.Therefore, it has the highest charge density and hence attracts the water molecules more strongly than any other alkali metal cation. Thus, option (a) is correct.
33.

Arrange the alkali metals in increasing order of their density.

Answer» Correct Answer - `LiltKltNaltRbltCs`
34.

What kind of metals can form superoxides?

Answer» Metals with very high electropositive character such as `K,Rb,Cs` etc. can form superoxides.
35.

Which one of the alkaline earth metal carbonates is thermally the most stable?A. `MgCO_(3)`B. `CaCO_(3)`C. `SrCO_(3)`D. `BaCO_(3)`

Answer» d. As the electropositive character of the metal increases or the basicity of their hydroxides increases down the group, their thermal stability increases. Thus, `BaCO_(3)` is the most stable and hence option (d) is correct.
36.

What is the order of reactivity of alkali metals towards hydrogen?

Answer» Correct Answer - `LiltNaltKltRbltCs`
37.

Name the alkali metal which can combine directly with `As,P,S` and halogens.

Answer» All alkali metals react directly with `As,P,S` and halogen.
38.

Name the alkali metals which do not combine directly with nitrogen.

Answer» Sodium, potassium, rubidium, caesium do not combine directly with nitrogen, whereas lithium combines directly.
39.

Dehydrobromination `(-HBr)` of the following in increasing order will be : A. `IltIIltIII`B. `IIIltIIltI`C. `I=IIltIII`D. `IIIltI=II`

Answer» Correct Answer - A
40.

The above trasformation proceeds through:A. electrophilic additionB. benzyne intermediateC. activated nucleophilic substitutionD. elimination

Answer» Correct Answer - C
41.

The intermediate during the addition of `HCl` to propene in the presence of peroxide is :A. `CH_(3)-overset(**)(C)H-CH_(2)Cl`B. `CH_(3)-overset(+)CH-CH_(3)`C. `CH_(3)-CH_(2)-overset(**)CH_(2)`D. `CH_(3)-CH_(2)-overset(+)CH_(2)`

Answer» Correct Answer - B
42.

Which of the following Group `15` elements do not show allotropy?A. NB. AsC. SbD. Bi

Answer» Correct Answer - D
All the elements of group 15 except Bi show allotropy as nitrogen exists in two solid forms namely `alpha`-nitrogen and `beta`-nitrogen. Phosphorus exists in a number of allotropic forms. As exists as grey, yellow and black arsenic and Sb exists as metallic, `alpha` and `beta`-antimony.
43.

The process of converting hydrated alumina into anhydrous alumina is calledA. roastingB. smeltingC. dressingD. calcination

Answer» Correct Answer - D
Calcination is a process in which ore is heated generally in the absence of air to expel water from a hydrated oxide or carbon dioxide from a carbonate .
44.

For a process, entropy change of a system is expressed asA. H- TSB. `(q_(rev))/T`C. `T/(q_(rev))`D. `q_(rev)xxT`

Answer» Correct Answer - B
For an isothermal reversible process, let the system absorbs q amount of heat from surroundings at temperature T. Thus, the entropy change of system will be `DeltaS_("System")=(q_(rev))/T`.
45.

Write the sum of lone pairs of electron on central atom of `SF_(4), CF_(4), XeF_(4), XeF_(2)` and `ClF_(3)`.

Answer» Correct Answer - 8
`SF_(4)(1)`
`CF_(4)(0)`
`XF_(4)(2)`
`XeF_(2)(3)`
`ClF_(3)(2)`
46.

A gaseous mixture contains `SO_(3)(g)` and `CH_(4)(g)` in `12.5 : 1` ratio by mass. Calculate `X ` where `X =` Ratio of total number of atoms present in `SO_(3)(g)` to total number of atoms presents in `CH_(4)(g)` in the mixure.

Answer» Correct Answer - `2`
`{:(,SO_(3),:,CH_(4)),("Mass ratio",12.5,:,1),("Mass ratio",12.5/80,:,1/16rarr2.5:1),("Atom ratio",2.5xx4:5xx1,,rArr2:1):}`
47.

For which orbit number of `He^(+)` value of radius equal to `1.058 Å` ?

Answer» Correct Answer - `2`
`r = 0.529(n^(2))/(Z)A`
48.

For `Be^(3+)` ion. Which of the following statement(s) is/are INCORRECT ?A. lonisation energy `= 122.4 eV`.B. The potential energy of electron in `1^(st)` excited satate is `-217.6 eV`.C. The frequency of revolution of electron in `2^(nd)` orbit of `Be^(3+)` is hall of the frequency of revoluation of electron in ground state of `H-"atom"`.D. `2^(nd)` excitation potential `= 193.4 V`.

Answer» Correct Answer - A::B::C
`(A)` lonisation energy `= 13.6 xx 16 eV = 217.6 eV`
`(B) PE = -27.2 xx (4^(2))/(2^(2)) = -108.8e V`
`(C) (f_(2))_(Be^(3+))/(f_(1))_(H) = ((4^(2))/(2^(3)))/(1^(2)/(1^(3))) = 2`
The frequency of revolution of electron in `2^(nd)` orbit is doble of the frequency of revolution of electron in ground state of `H -` atom.
`(D) 2^(nd)` excitation potential `= 12.09 xx 16 = 193.4 V`
49.

`10 dm^(3)` of `N_(2)` gas and `10 dm^(3)` of gas `X` contain the same number of molecules at the same temperature, the gas `(X)` may beA. `SO_(3)`B. `N_(2)O`C. `CO_(2)`D. `SO_(2)`

Answer» Correct Answer - A::B::C::D
Since `n, T, V` are same for both samples, so `P` should also be same. Further, `PV = nRT` is independent of nature of gas. So, `X` gas could be any gas.
50.

How many of the following have `sp^(3)` hydridisation around the central atom ? (a) `H_(2)O`, (b) `CH_(3)`, (c) `BCl_(3)`, (d) `BF_(4)^(-)`, (e) `BeCl_(2)(g)` (f) `PCl_(4)^(+)`, (g) `XeF_(2)`, (h) `CO_(2)`, (i) `NH_(4)^(+)`, (j) `PCl_(3)`

Answer» Correct Answer - 6
`{:((a)H_(2)O,(b)CH_(4),(d)BF_(4)^(-)),((f)PCl_(4)^(+),(i)NH_(4)^(+),(i)PCl_(3)):}`