This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 93151. |
What is the maximum pressure required in a compression molding process?(a) 35 MPa(b) 40 MPa(c) 45 MPa(d) 50 MPa |
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Answer» The correct option is (d) 50 MPa For explanation I would say: The maximum pressure that is required for the complete operation of compression molding is 50 MPa. |
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| 93152. |
Which of the following types of molecular structure present in thermosetting polymers?(a) Linear polymers(b) Branched polymers(c) Cross-linked polymers(d) Network polymers |
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Answer» The correct option is (c) Cross-linked polymers Best explanation: Cross-linked polymers are described by adjacent linear chains that are brought one to another at several locations by covalent bonds. Cross linking is completed by a non-reversible chemical reaction. Often, cross-linking is finished by additive atoms which are covalently bonded to the chains in the thermosetting polymers. |
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| 93153. |
Complex salt has two parts-one is ionisation sphere and another is coordination sphere. According to IUPAC nomenclature of complex, first we name positive ion then negative ion. According to VBT, metal ion should have vacent orbital equal to its coordination number. If ligand is strong field, pairing of electrons takes place. In the case of weak field ligand, pairing of electrons does not take place, generally. Crystal field splitting of d-orbitals of tetrahedral complex is just opposite to that octahedral complex.A. `[Ni(CO)_(4)]`B. `[Pd(NH_(3))_(4)]Cl_(2)`C. `[Fe(CO)_(5)]`D. `K_(2)[ZnCl_(4)]` |
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Answer» Correct Answer - B `Pd^(+2)` in Coordination number 4 is square planar. |
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| 93154. |
Complex salt has two parts-one is ionisation sphere and another is coordination sphere. According to IUPAC nomenclature of complex, first we name positive ion then negative ion. According to VBT, metal ion should have vacent orbital equal to its coordination number. If ligand is strong field, pairing of electrons takes place. In the case of weak field ligand, pairing of electrons does not take place, generally. Crystal field splitting of d-orbitals of tetrahedral complex is just opposite to that octahedral complex. If `Delta_(0)=45000` unit, find out the value of `Delta(t)`A. 2000 unitB. 20000 unitC. 45000 unitD. 11250 unit |
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Answer» Correct Answer - B `Delta_(t)=(4)/(9)Delta_(0)` `Delta_(t)=(4)/(9)xx45000=20,000" Unit"` |
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| 93155. |
For a two step reaction. `AhArrR+B" "R+Coverset(k_(2))toP` (where, R is a reactive intermediate whose concentration is maintained at some low steady state throughout the reaction). If the concentration of C is very high then the order of reaction for formation of "P" isA. 2B. 0C. 1D. `1//2` |
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Answer» Correct Answer - C Rate law `=(dp)/(dt)=K_(2)[R][C]` at steady state `(d[R])/(dt)=0` `(d[R])/(dt)=K_(1)[A]-K_(2)[R][B]-K_(2)[R][C]=0` `K_(1)[A]={K_(2)[B]+K_(2)[C]}[R]` `[R]=(K_(1)[A])/(K_(2){[B]+[C]})` Rate `=K_(2)xx(K_(1))/(K_(2))([A])/([B]+[C])xx[C]` `ul(K_(1)[A])` `=([B])/([C])+1` where C is very high Rate `=K_(1)[A]` `:.` order of reaction` = 1 " "]` |
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| 93156. |
What is the hybridisation of Fe in sodium thionitroprusside.A. `sp^(3)d^(2)`B. `d^(2)sp^(3)`C. `sp^(3)d`D. no hybridisation. |
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Answer» Correct Answer - B `Na4[Fe(CN)_(5)NOS]` `Fe^(+2)-d^(6)" sys "`. `:."Hybridisation of Fe in complex is" d^(2)sp^(3)" "]` |
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| 93157. |
Water rises to a height `h` in a capillary tube of cross-sectional area A. the height to which water will rise in a capillary tube of cross-sectional area `4A` will beA. hB. h/2C. h/4D. 4h |
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Answer» Correct Answer - B `h=(2Scostheta)/(rpg**)` Cross-sectional area inceases 4 times, which means radius gets doubled. Therefore, `h=(2S)/(2(rpg))=h/2` |
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| 93158. |
Figure shows a liquid flowing through a tube at the rate of `0.1 m^(3)//s`. The tube is branched into two semicircular tubes of cross-sectional area `A//3` and `2A//3`. The velocity of liquid at `Q` is (the cross section of the main tube is `A =10^(-2) m^(2)` and `v_(p) = 20 m//s`) A. 5 m/sB. 30 m/sC. 35 m/sD. None of these |
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Answer» Correct Answer - A `A_(1)v_(1)+A_(2)v_(2)=Av` |
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| 93159. |
A cylindrical vessel contains a liquid of density `rho` up to height `h`. The liquid is closed by a piston of mass `m` and area of cross section `A`. There is a small hole at the bottom of the vessel. The speed `v` with which the liquid comes out of the hole is A. `sqrt(2gh)`B. `sqrt(2(gh+(mg)/(pA)))`C. `sqrt(2(gh+(mg)/(A)))`D. `sqrt(2gh+(mg)/(A))` |
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Answer» Correct Answer - B `pgh+(mg)/(A)+0+0=1//2pv^(2)` |
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| 93160. |
If one equivalent of a strong acid is added to one equivalent of a weak base, the resulting solution will be. (A) neutral (B) acidic (C) alkaline (D) none of these |
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Answer» Correct option: (B) acidic Explanation: Since after neutralisation salt of (SA + WB) will form and its pH < 7. |
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| 93161. |
Two blocks of wood of masses `m_(1) and m_(2)` and each of specific givity 0.5 are submerged at a depth of `h_(1) and h_(2)` in v vessel `(h_(2)gth_(1))` filled with water, which is accelerated upwards with an acceleration g/2. The difference in time taken by the blocks to reach the surface, when frleased with zero velocity isA. zeroB. `2sqrt(((h_(2)-h_(1)))/(2g))`C. `sqrt(((h_(2)-h_(1)))/(g))`D. `2sqrt(((h_(2)-h_(1)))/(3g))` |
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Answer» Correct Answer - D `a_(1)=("upthrust-weight")/(m)=2g` similarly `a_(2) = 2g` Acceleration relative to water = 3g/2 `t_(l)=2sqrt((h_(1))/(3g))` `t_(2)=2sqrt((h_(2))/(3g))` `thereforet_(2)-t_(1)=2sqrt(((h_(2)-h_(1)))/(3g))` |
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| 93162. |
What are the differences between pigments and dyes ? |
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| 93163. |
Define law of limiting factor. Explain four external factors affecting the rate of photosynthesis. |
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Answer» Definition: If a chemical process is affected by more than one factor, then its rate will be determined by the factor which is nearest to its minimal value: it is the factor which directly affects the process if its quantity is changed.
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| 93164. |
Explain the pathway of water movement in root. |
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Answer» 1. Apoplast pathway 2. Symplast pathway. |
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| 93165. |
Who is camman |
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Answer» A famous youtuber
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| 93166. |
Explain the pathway of water movement in root |
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Answer» Pathways of Water Movement. Water can move through the roots by three separate pathways: apoplast, symplast, and transmembrane (transcellular). In the apoplast pathway (apoplastic route), water moves through the spaces between the cells and in the cells walls themselves.
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| 93167. |
In a group of 400 people, 250 can speak Hindi and 200 can speak English. How many people can speak both Hindi and English? |
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Answer» Let H be the set of people who speak Hindi, and E be the set of people who speak English ∴ n(H ∪ E) = 400, n(H) = 250, n(E) = 200 n(H ∩ E) = ? We know that: n(H ∪ E) = n(H) + n(E) – n(H ∩ E) ∴ 400 = 250 + 200 – n(H ∩ E) ⇒ 400 = 450 – n(H ∩ E) ⇒ n(H ∩ E) = 450 – 400 ∴ n(H ∩ E) = 50 Thus, 50 people can speak both Hindi and English. |
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| 93168. |
A=100 b=200 c=? perimeter=500 |
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Answer» a+b+c= Perimeter c=500-200-100 =500-300 =200 Thus c=200 |
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| 93169. |
Write all subset of the following1. {1, 2}2. {a, b, c}3. Φ (1 score each) |
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Answer» 1. Φ, {1}, {2}, {1, 2} 2. Φ, {a}, {b}, {c} ,{a, b}, {a, c}, {b, c}, {a, b, c} 3. Φ |
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| 93170. |
Find Set A, B and Universal set U |
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Answer» A = {e, f, d}; B = {a, b, c, d} and U = {a, b, c, d, e, f, g, h} |
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| 93171. |
Let A = {1, 2, {3, 4}, s, d, θ} , Which of the following statements are true/false and why?1. 3 ∈ A2. {1, {3, 4}} ∈ A3. {1, 2, 3} ⊂ A4. Φ ∈ A5. 1 ⊂ A |
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Answer» 1. 3 ∈ A - False 2. {1, {3, 4}} ∈ A - True 3. {1, 2, 3} ⊂ A - False 4. Φ ∈ A - False 5. 1 ⊂ A (1 score each) - False |
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| 93172. |
If A = {2, 4, 6, 7, 8, 12}; B = {2, 7, 9, 10} and C = {5, 9, 10, 12}. Find1. A – B2. B – C3. A – C4. B – A5. C – A6. (A ∪ B) – C7. A – {B ∩ C)8. (A ∩ B) – (C ∩ A) |
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Answer» 1. A – B = {4, 6, 8, 12} 2. B – C = {2, 7} 3. A – C = {2, 4, 6, 7, 8} 4. B – A = {9, 10} 5. C – A = {5, 9, 10} 6. (A ∪ B) – C = {2, 4, 6, 7, 8, 9, 10, 12} – {5, 9, 10, 12} = {2, 4, 6, 7, 8}. 7. A – (B ∩ C) = {2, 4, 6, 7, 8, 12} – {9, 10} = {2, 4, 6, 7, 8, 12} 8. (A ∩ B) – (C ∩ A) = {2, 7} – {12} = {2, 7} |
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| 93173. |
If U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}; A = {2, 7, 9, 10} B = {5, 9, 10, 12} and C = {1, 4, 5, 7, 11}. Find1. A’2. B’3. A’ – C4. (B – A)’5. B’ ∩ C’6. (A ∪ B)’7. A’ ∩ B’ |
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Answer» 1. A’ = { 1, 3, 4, 5, 6, 8, 11, 12} 2. B’ = { 1, 2, 3, 4, 6, 7, 8, 11} 3. A’ – C = {1, 3, 4, 5, 6, 8, 11, 12} – {2, 3, 6, 8, 9, 10, 12} = {1, 4, 5, 11} 4. (B – A)’ = {5, 12}’ = {1, 2, 3, 4, 6, 7, 8, 9, 10, 11} 5. B’ ∩ C’ = {1, 2, 3, 4, 6, 7, 8, 11} – {2, 3, 6, 8, 9, 10, 12} = {2, 3, 6, 8} 6. (A ∪ B)’ = {2, 5, 7, 9, 10, 12}’ = {1, 3, 4, 6, 8, 11} 7. A’ ∩ B’ = {1, 3, 4, 5, 6, 8, 11, 12} ∩ {1, 2, 3, 4, 6, 7, 8, 11} = {1, 3, 4, 6, 8, 11} |
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| 93174. |
If X and Y are two sets such that X ∪ Y has 50 elements, X has 28 elements and Y has 32 elements, how many elements does X ∩ Y have? |
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Answer» Given; n(X ∪ Y) = 50; n(X) = 28; n(Y) = 32 n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y) ⇒ 50 = 28 + 32 – n(X ∩ Y) ⇒ n(X ∩ Y) = 60 – 50 = 10 |
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| 93175. |
If A = {1, 2, 4, 6, 7, 8}; B = {2, 5, 7, 9, 10} and C = {4 , 5, 9, 10}. Find1. A ∪ B2. B ∪ C3. A ∪ C4. A ∩ B5.B ∩ C6. A∪ B ∪ C7. A ∩ B ∩ C8. (A ∩ B) ∪ (C ∩ A) |
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Answer» 1. A ∪ B = {1, 2, 4, 5, 6, 7, 8, 9, 10} 2. B ∪ C = {2, 4, 5, 7, 9, 10} 3. A ∪ C = {1, 2, 4, 5, 6, 7, 8, 9, 10} 4. A ∩ B = {2, 7} 5. B ∩ C = {5, 9, 10} 6. A ∪ B ∪ C = {1, 2, 4, 5, 6, 7, 8, 9, 10} 7. A ∩ B ∩ C = Φ 8. (A ∩ B) ∪ (C ∩ A) = {2, 7} u {4} = {2, 4, 7} |
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| 93176. |
What is the source of kinetic energy for falling rain drops? |
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Answer» Gravitational potential energy is a source of kinetic energy for falling rain drops. |
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| 93177. |
Raju dropped a rubber ball of mass m from a height h to the ground. He observed that the ball rebounds vertically and along the same line to a height h1, which is less than h.1. Is it an elastic or inelastic collision?2. Find the velocity with which it strikes the ground?3. If it is replaced by a solid aluminium ball, then what happens to the height of rebound?4. If the rubber ball is allowed to fall on a spring placed on the ground then what change will Raju notice in the height of rebound? |
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Answer» 1. Inelastic collision. 2. The velocity with which ball strikes the ground, v2 = u2 + 2as v2 = 0 + 2g × h v = \(\sqrt {2gh}\). 3. Height of rebound decreases. 4. Height of rebound depends on the state of potential energy stored in the spring. If ball falls on a compressed spring, the height of rebound increases due to potential energy given by the spring to bail. |
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| 93178. |
In a group of 65 people, 40 like cricket, 10 like both cricket and tennis, how many like tennis only and not cricket? How many like tennis? |
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Answer» Let C – Cricket; T – Tennis be the sets. Given; n(C’ ∪ T) = 65; n(C) = 40; n(C ∩ T) = 10 n(C ∪ T) = n(C) + n(T) – n(C ∩ T) ⇒ 65 = 40 + n(T) – 10 ⇒ n(T) = 35 n (tennis only and not cricket) = n(T ∪ C’) = n(T) – n(T ∩ C) = 35 – 10 = 25. |
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| 93179. |
Raju increased the speed of moving mass ‘50 kg’ from 2 m/s to 4m/s.1. How much force will be required, if velocity change takes place with in 0.2 sec?2. How much work is done by Raju? |
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Answer» 1. F = mass × acceleration = 50 × (4−2)/0.2 = 500N. 2. w = \(\frac{1}{2}\)mv2 – 12mu2. =\(\frac{1}{2}50\) (42 – 22) = 300 J. |
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| 93180. |
A body constrained to move along the Z-axis of a co-ordinate system is subjected to a constant force vectors F =(i +2ȷ +3k)N1. What is the magnitude of force along z direction.2. What is the work done by this force in moving the body over a distance of 4m along z-axis. |
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Answer» 1. 3N 2. Work done = Force × Displacement = 3 × 4 = 12J. |
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| 93181. |
Match the followingprocesscollisionphysical quantity conservedcollision of two ballsElasticKE, Total energy and momentumcollision of two moleculesInelasticKE and Momentum TE and Momentum |
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Answer» Collision of two balls – inelastic – TE and momentum Collision of two molecules – elastic – KE, TE, and momentum |
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| 93182. |
State if each of the following statements is true or false.1. In an elastic collision of two bodies, the momentum and energy of each body is conserved.2. Total energy of a system is always conserved, no matter what internal and external forces on the body are present.3. Work done in the motion of a body over a closed loop is zero for every force in nature.4. In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system. |
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Answer» 1. False 2. False 3. False 4. False (true usually but not always). |
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| 93183. |
A sphere of mass m is moving with a velocity u and makes a head on collision with another identical mass which is at rest. It is observed that the stationary mass starts moving with a lesser velocity than u, after the collision.1. Which physical quantity is conserved here?2. Define coefficient of restitution.3. Determine the ratio of the velocities of the two spheres after elastic collision if ‘e’ is the coefficient of restitution. |
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Answer» 1. conservation of linear momentum. 2. It is defined as the ratio of relative velocity of separation after collision to the relative velocity of approach before collision. 3. Coefficient of restitution, e = \(\frac{v_2}{u_1} - \frac{v_1}{u_2}\) in this cos u1 = u, u2 = 0, v1 = 0, v2 = u ∴ e =\(\frac{u - 0}{u - 0}\) e = 1. |
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| 93184. |
In atom, an electron is revolving around the nucleus. What is the work done? |
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Answer» Work done is zero because work done by centripetal force is zero. |
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| 93185. |
A man tries to lift a mass 200kg with a force 100N1. Is he doing work? Explain.2. If yes, find the amount of work done If No, find the force required to lift it.3. If it is lifted to 2m in 10 seconds, find his power. |
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Answer» 1. No work is done, as there is no displacement, 100N force is insufficient to raise 200kg. 2. Force required to lift 200 kg = 200 × 9.8 = 1960N 3. Power = \(\frac{mgh}{t}\) = \(\frac{200×9.8×2}{10}\) = 392W. |
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| 93186. |
12 Show that the oulation \( R \) on the set \( A \) of points on co-ordinate plane givem by \( R=\{(P, Q) \) : idistance \( O P=O Q \), where \( O \) is the origin ) is an equivalence velation. Furtier find the set of als points velated Uto apoint \( P \neq(0,0) \) is the circlepeissing throrgh \( p \) with the rigin as centre. |
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Answer» A is the set of points in a plane. R = {(P. Q): distance of the point P from the origin is same as the distance of the point Q from the origin} = {(PQ) |OP| = |OQ | where O is origin} Since | OP | = | OPI, (PP) ERVPE A. ... R is reflexive. Also (P. Q) ER ⇒|OP| = |OQ| ⇒ | OQ | = |OP| ⇒ (Q.P) ER⇒ R is symmetric. Next let (PQ) E R and (Q, T) ER⇒ |OP|=|OQ | and OQ | = |OT| ⇒ |OP| = |OT| →> (PT) ER .. R is transitive. ... R is an equivalence relation. Set of points related to P = 0 = {Q E A: (Q,P) E R} = {QEA: |OQ| = |OP|} = {Q E A :Q lies on a circle through P with centre O}.
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| 93187. |
What is the work done by the tension in the string of simple pendulum? |
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Answer» The work done by the tension in the string of simple pendulum is Zero. |
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| 93188. |
Let = {x ∈ Z ∶ 0 ≤ X ≤ 12}. Show that R = {(a,b):|a - b| is a multiple of 4} is (i) reflexive, (ii) symmetric and (iii) transitive. Find the set of elements related to 1. |
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Answer» Let = {x ∈ Z ∶ 0 ≤ X ≤ 12} and relation R on set A is defined as R = {(a, b): |a − b|is a multiple of 4}. Reflexivity : Let a ∈ A. Now, |a − b| = 0 which is a multiple of 4. Therefore, (a, a) ∊ R ∀ a ∈ A. Hence, the relation R is reflexive relation on set A. Symmetricity : Let a, b ∈ A such that (a, b) ∊ R. ⇒ |a − b| is a multiple of 4. ⇒ |b − a| is a multiple of 4. ( \(\because\) |a − b| = |−(b − a)| = |b − a|) ⇒ (b, a) ∊ R ∀ a, b ∈ A. Hence, if (a, b) ∊ R. Then, (b, a) ∊ R ∀ a, b ∈ A. Thus, the relation R is symmetric relation on set A. Transitivity : Let a,b,c ∈ A such that (a,b) ∊ R and (b,c) ∊ R. ⇒ |a - b| is a multiple of 4 and |b - c| is a multiple of 4. ⇒ a - b = 4m1 and b - c = 4m2, where m1 and m2 ∊ Z. ⇒ a - c = a - b + b - c = 4m1 − 4m2 = 4(m1 − m2 ) = 4m, where m = m1 − m2 ∈ Z. ⇒ |a - c| is a multiple of 4. ⇒ (a, c) ∊ R ∀ a,b,c ∈ A. Hence, if (a, b) ∊ R and (b, c) ∊ R. Then, (a, c) ∊ R ∀ a,b,c ∈ A. Thus, the relation R is transitive relation on set A. Let b ∈ A is image of 1 under the relation R. Therefore, |1 − b| is a multiple of 4 and b ∈ A. ⇒ 1 − b = 4n, where n ∊ z, 0 ≤ b ≤ 12 and b ∈ z. ⇒ b = 1 − 4n, where 0 ≤ b ≤ 12 and b, n ∈ Z. ( b lies in the range [0, 12] is possible only when n have values 0, −1, −2. ) ⇒ b ∈ {1, 5, 9}. Hence, the set of elements related to 1 is {1,5,9}. |
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| 93189. |
An urn contains 8 white and 4 red balls. Two balls are drawn from the urn one after the other without replacement. What is the probability that both drawn balls are white ? |
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Answer» Given that an urn contains 8 white and 4 red balls. Let experiment is drawn two balls from the urn one after the other without replacement. Therefore, total numbers of trials are n(S) = 12 × 11 = 132. Let the event is drawn two white balls from the urn. Therefore, the number of trials in which both drawn balls are white balls is n(A) = 8 × 7 = 56. Therefore, the probability that both drawn balls are white is \(\frac{n(A)}{n(s)}\) = \(\frac{56}{132}\) = \(\frac{14}{33}\) |
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| 93190. |
Let A and B be the events such that 2P(A) = P(B) = \(\frac{5}{13}\) and P(A|B) = \(\frac{2}{5}\) . Then, find P(A ∪ B) and P(A ∩ B). |
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Answer» We have 2P(A) = P(B) = \(\frac{5}{13}\) and P(A|B) = \(\frac{2}{5}\), therefore, P(A) = \(\frac{P(B)} {2}\) = \(\frac{5}{26}\) . By conditional probability, we know that P(A|B) = \(\frac{P(A∩B)}{P(B)}\). ⇒ P(A ∩ B) = P(A|B)P(B) = \(\frac{2}{5} \times \frac{5}{13} = \frac{2}{13}\). We know that P(A ∩ B)= P(A) + P(B) − P(A ∩ B) = \(\frac{5}{26} + \frac{5}{13} - \frac{2}{13} = \frac{5+10-4}{26} = \frac{11}{26}.\) Hence, P(A ∪ B) = \(\frac{11}{26}\) and P(A ∩ B) = \(\frac{2}{13}\). |
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| 93191. |
Given the relation `R={(1,2),(2,3)`on the set `A={1,2,3},`add a minimum number of ordered pairs so that the enlarged relation issymmetric, transitive and reflexive. |
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Answer» Correct Answer - 7 `R` is reflexive if it contains `(1,1),(2,2),(3,3)` `:.(1,2)epsilonR,(2,3)epsilonR`. Now `R={(1,2),(2,2),(3,3),(2,1),(3,2),(2,3),(1,2)}` `R` will be transitive if `(3,1),(1,3)epsilonR`. Thus `R` becomes an equivalence relation by adding `(1,1),(2,2),(3,3),(2,1),(3,2),(1,3),(3,1)` Hence the total no. of ordered pairs `7`. |
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| 93192. |
If you think your computer has a virus, what would be the first step in solving the problem? |
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Answer» If you think your computer has been infected, start by running a full system scan using an antivirus software. |
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| 93193. |
Write a note on any one Indiain political leader. |
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Answer» Dr. B.R. Ambedkar : Dr. B.R. Ambedkar is acknowledged as the leader of the untouchables and underprivileged in the Indian social strata. For his work in piloting the constitution of Independent India he is also hailed as the modem ‘Manu” Qr. Ambedkar was the 14th child of Ramojisakpal and Bhima bai of the Mahoba community in Maharastra. He was bom on 14th April 1891. He had his school education in Satara. He completed his graduation in Bombay with the support of Maharaja of Baroda. He did his MA and Ph.D degree from the Columbia University in 1951 and 1961 respectively. Later he got his law and D.Sc degrees also In 1924 he started an association for the welfare of the depressed classes. He started the News paper called “Mooka Nayaka” to motivate the people to fight for independence and also for the reform of depressed classes. He was the chairman of Drafting Committee for framing an constitution In the interim government he was the law minister in Nehru cabinet. He dedicated his whole life for the welfare of downtrodden people. He passed away on 16th December 1956. |
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| 93194. |
In what way advertisement in technology led to revolutionary changes in global communities? |
| Answer» The advertisements in technology led to Ievolutionary changes in global communities where it has created global platform for trade. Advertisements in newspapers and magazines have transformed following the change in technology. It has also affected the way consumers react to promotion of products. Give examples of INGOS. | |
| 93195. |
State any two reasons for farmers’ suicide. |
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Answer» 1. Event (crop loss, failure of a borewell) 2. Stressors (Illness, heavy borrowing). |
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| 93196. |
Write about disintegration of USSR and bilateral relations in IndoRussian relation. |
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Answer» In 1985 Mikhail Gorbachev, the President of USSR introduced economic and political reforms of ‘Perestroika’ (restructuring) and ‘Glasnost’(openness). That stopped the arms race with US, withdrew Soviet troops from Afghanistan, helped the unification of Germany, ended the cold war. Other weaknesses inherent in the Soviet Union led to the disintegration of USSR and formation of 15 new countries in 1991. India recognized all of them as sovereign states and established new diplomatic relations. Ten of them joined together to form new associations with Russia called CIS (Commonwealth of Independent States). Bilateral relations:- The new leadership in Russia and other Republics of erstwhile Soviet Union hold India in high regard due to India’s secular approach to politics, its stable democratic system assuring rights and equality to all its citizens, self-reliant industrial and economic base, and its genuine concern for vital global issues, e.g. peace disarmament, economic development, human rights and democratization of international organizations particularly of the UN and its agencies. It continues its support to India to become permanent member in UN Security Council. India and Russia both have multifaceted relationship involving strategic and high-level co-operation. The process of bilateral annual summits has given great impetus to bilateral relations. Indo-Russia co-operation has continued to move stronger on the basis mutual interest, faith, friendship and past relations. |
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| 93197. |
Mention any two business communities. |
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Answer» 1. Parsis 2. Nagarattars. |
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| 93198. |
Define International relations and its importance. |
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Answer» International relations is a dynamic discipline which tries to explain political activities across the state boundaries. According to Ola Joseph, “ International relations are the study of all forms of interactions that exist between members of separate entities or nations within the international system”. International relations is concerned with all the exchange transactions, contracts, flow of information and the resulting behavioural response between and among separate organised societies. International relations could encompass many different activities such as social, economic, religious and others. According to H.J. Morgenthau, Power is the key to international relations. He viewed that international relations are the subjects that deal with those relations among nations which involve power status. External developments constantly influence the domestic policies. Nations are compelled to enter into dialogues, form alliances with Other nations. This is to ensure the power and prestige of nations in the international system. It is of immense importance for the student of international relations to understand that the world of today is marked by two factors. One is to do with the nature of power in the nuclear age and the other concerned with the interdependence of mankind. |
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| 93199. |
Explain the importance of liberalisation. |
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Answer» Liberalization is the “willingness to respect or accept behaviour or opinion different from one’s own; open to new ideas”. Liberalization is the process of liberating the economy from various regulatory mechanisms and elimination of customs and tariffs. Economic liberalization is the policy of relaxation over economic and trade policies. Importance of liberalization are as follows: 1. Consumer-friendly: This leads to lower costs and prices for consumers to get the goods and services according to their wishes. There are many number of companies which bring lots of quality products to suit the consumer’s interests and demands. In liberalised economy, consumer gets more benefits. 2. Free from government regulations: Government provides free movement of ‘ trade and commerce where any private company can easily carry on their business activities without any restrictions. The companies need not undergo any procedural delay by the government. 3. Promotes competition: Liberalisation extends competition within different company’s trade firms. Basically, they maintain the. standards but offer lower prices for the consumers. Competition promotes efficiency and avoids wastage of resources. 4. Promotes world business class: Liberalization provides the business class and opportunity to share their knowledge and exchange technology with confidence at the international level. Business firms can learn and earn at global level. They can enrich their knowledge by equipping new machinery and tools for better performance as per international standards. 5. Provides for more private funding agencies: Liberalization allows financial markets to provide loans to companies which previously were not able to access, loans that they can pay off, and it allows more financial private funding agencies like ICICI, HDFC and HSBC. 6. Improve the economy: ‘ Liberalization is expected to improve nation’s GDP growth. It helps nation’s economic development and improves the standard of living in a shorter period. Most of the developing nations adopt liberalised economy. 7. Promotes technological advancement: Liberalisation makes new changes in an advanced technology and logistics for better services. That can be useful to save time, energy and money. It promotes for high quality of products and making the supplies in time. |
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| 93200. |
What are the challenges to free and fair elections in India? |
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Answer» Important issues which bring many limitations and challenges of Indian elections to our attention are following A. Candidates and parties with a lot of money may not be sure of their victory, but they do enjoy an advantage over smaller parties and independent candidates. B. In some parts of the country. candidates with criminal connection have been able to secure a ticket from major parties. C. Some families tend to dominate political parties. Tickets are distributed to members of these families. D. Very often elections offer little choice to ordinary citizens as both the major parties are similar to each other in their policies and practices. E. Smaller panics and independent candidates suffer a huge disadvantage as compared to the bigger parties. |
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