100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS Page 1879 InterviewSolution

93901.	-------- attack the whole grains both before and after harvest.a. Secondary Pestsb. Primary Pestc. Tertiary Pestd. None of All
Answer» b. Primary Pest

Discussion

93902.	Change or combine into a compound sentence1. As Rahim was sick, he could not attend the office.2. As he is wounded, he cannot walk fast.3. As he was poor, he could not lead a comfortable life.4. As Velu was sick, he could not attend class5. Mallika is very arrogant. She will not apologize
Answer» 1. Rahim was sick and so he could not attend the office. 2. He is wounded and so he cannot walk fast. 3. He was poor and so he could not lead a comfortable life . 4. Velu was sick and so he could not attend class. 5. Mallika is very arrogant and so she will not apologize.

93902.

Change or combine into a compound sentence1. As Rahim was sick, he could not attend the office.2. As he is wounded, he cannot walk fast.3. As he was poor, he could not lead a comfortable life.4. As Velu was sick, he could not attend class5. Mallika is very arrogant. She will not apologize

Answer»

1. Rahim was sick and so he could not attend the office.

2. He is wounded and so he cannot walk fast.

3. He was poor and so he could not lead a comfortable life .

4. Velu was sick and so he could not attend class.

5. Mallika is very arrogant and so she will not apologize.

Discussion

93903.	Something given away for no money is ______
Answer» Correct option is free

Discussion

93904.	Sometimes a bus ______ gets on the bus and checks the tickets. A) inspector B) agent C) conductor D) officer
Answer» Correct option is C) conductor

Discussion

93905.	Two weeks is also called a ______
Answer» Correct option is fortnight

Discussion

93906.	Light brown marks on the skin are called ______
Answer» Correct option is freckles

Discussion

93907.	After the battle, the ________ soldiers were helped by those who could walk. A) damaged B) wounded C) broken D) killed E) blessed
Answer» Correct option is B) wounded

Discussion

93908.	-------------attack the damaged or broken grain or flour a. Secondary Pests b. Primary Pest c. Tertiary Pest d. None of All
Answer» a. Secondary Pests

Discussion

93909.	The travel agent managed to ______ the problems about my ticket. A) stick to B) go with C) make out D) sort out
Answer» Correct option is D) sort out

Discussion

93910.	Something which is easily broken or damaged is ______
Answer» Correct option is fragile

Discussion

93911.	Where do you ______ the writing paper? In this desk. A) keep B) hold C) maintain D) guard
Answer» Correct option is A) keep

Discussion

93912.	While he was looking on at the football game he ______ an old classmate from high school days. A) ran over B) ran after C) ran across D) went into
Answer» Correct option is C) ran across

Discussion

93913.	Peggy wants to ______ ceramics when she retires. A) look after B) take up C) wear out D) do over
Answer» Correct option is B) take up B _ Take up there is a reason behind it

Discussion

93914.	PTO stands ______ “Please turn over”— the page, of course. A) as B) like C) for D) by
Answer» Correct option is C) for

Discussion

93915.	The gun ______ while he was cleaning it; it really frightened him. A) went off B) cut off C) ran overD) put up
Answer» Correct option is A) went off

Discussion

93916.	Susan works so hard that no one in the office can ______ her. A) put up with B) go without C) get along with D) keep up with
Answer» Correct option is D) keep up with

Discussion

93917.	Evaluate : ∫logx dx.
Answer» = ∫logx dx = ∫logx.1 dx = ∫uv dx = u∫v dx – ∫[d/dx x∫vdx] dx Iogx ∫1. dx ∫[d/dx(logx)x∫1.dx] dx = 1ogx(x)∫(1/x xx) dx = xlogx - ∫1. dx I = x logx – x + c

93917.

Evaluate : ∫logx dx.

Answer»

= ∫logx dx = ∫logx.1 dx

= ∫uv dx = u∫v dx – ∫[d/dx x∫vdx] dx

Iogx ∫1. dx ∫[d/dx(logx)x∫1.dx] dx

= 1ogx(x)∫(1/x xx) dx

= xlogx - ∫1. dx

I = x logx – x + c

Discussion

93918.	Why are those people ______ such a hurry? A) in B) on C) for D) of
Answer» Correct option is A) in

Discussion

93919.	Why didn't you go to the cinema with us, Susan? - _____. A) I couldn't continue writing. B) Thanks to you I've got into the theatre. C) I still believe him in spite of everything. D) I'll mend it within a week. E) I had to stay at home yesterday.
Answer» Correct option is E) I had to stay at home yesterday.

Discussion

93920.	My radio doesn’t work very well, but I don’t know what is wrong ______ it. A) for B) to C) on D) with
Answer» Correct option is D) with

Discussion

93921.	Susan will probably work ______ six. A) for B) under C) until D) by
Answer» Correct option is C) until

Discussion

93922.	There are a number of differences ______ the two theories.A) from B) among C) between D) than
Answer» Correct option is C) between

Discussion

93923.	Are there any objections ______ the committee’s plan of action? A) to B) for C) at D) of
Answer» Correct option is A) to

Discussion

93924.	I am going to ask a few questions ______ that old gentleman. A) up B) from C) to D) in
Answer» Correct option is C) to

Discussion

93925.	Partial derivative of x4 – x2y2 + y4 w.r.t. y at point (-1,1). a) -2 b) 2 c) -1 d) 1
Answer» Let f(x , y) = x⁴ - x²y² + y⁴ \(\frac{\partial f}{\partial y}\)= -2x² + 4y³ \(\frac{\partial f}{\partial y}(-1, 1)\)= -2(-1)² x 1 + 4 x 1³ = -2 + 4 = 2

93925.

Partial derivative of x4 – x2y2 + y4 w.r.t. y at point (-1,1). a) -2 b) 2 c) -1 d) 1

Answer»

Let f(x , y) = x⁴ - x²y² + y⁴

\(\frac{\partial f}{\partial y}\)= -2x² + 4y³

\(\frac{\partial f}{\partial y}(-1, 1)\)= -2(-1)² x 1 + 4 x 1³

= -2 + 4 = 2

Discussion

93926.	The angle between the lines vector r = (4 i - j) + 5(2i + j - 3k) and vector r = (i - j + 2k) + t(i - 3j + 2k) is (a) 3π/2(b) π/3(c) 2π/3 (d) π/6
Answer» Correct option: (b) π/3

93926.

The angle between the lines vector r = (4 i - j) + 5(2i + j - 3k) and vector r = (i - j + 2k) + t(i - 3j + 2k) is (a) 3π/2(b) π/3(c) 2π/3 (d) π/6

Answer»

Correct option:

(b) π/3

Discussion

93927.	The value of k x k = (a) 0 (b) 1 (c) \|k\|2 (d) None of these
Answer» Correct option: (a) 0

93927.

The value of k x k = (a) 0 (b) 1 (c) |k|2 (d) None of these

Answer»

Correct option:

(a) 0

Discussion

93928.	Let R = {(1, 3), (4, 2), (2, 4), (2, 3). (3, 1)} be a relation on the set A = {1, 2, 3, 4}. The relation will be :(a) A Function (b) Reflexive (c) Not Symmetric (d) Transitive
Answer» (c) Not Symmetric

Discussion

93929.	Write Java statement to extract selected item from a given listbox named “jList1.”
Answer» String X =(String)jList1.getSelectedValue(); OR String X=jList1.getSelectedValue().toString();

93929.

Write Java statement to extract selected item from a given listbox named “jList1.”

Answer»

String X =(String)jList1.getSelectedValue();

OR

String X=jList1.getSelectedValue().toString();

Discussion

93930.	Identify programming languages out of the following:HTML,C++, JAVA,MySQL
Answer» C + +, Java

Discussion

93931.	Write 5SQL queryclass 10 cbse
Answer» DDL queries - Create Drop Alter Truncate Rename DCL queries- Grant Revoke DML- insert update delete tcl- commit savepoint rollback dql-select

Discussion

93932.	4(sin4 30 + cos4 60) - 23 ( sin2 60 - cos2 45) + 12 tan2 60
Answer» = 4(sin⁴ 30 + cos⁴ 60) - 23 ( sin² 60 - cos² 45) + 12 tan² 60 = 4 ( (1/2)⁴ + (1/2)⁴ ) - 23 ( (√3/2)² - (1/√2)² ) + 12 (√3)² = 4 ( 1/16 + 1/16 ) - 23 ( 3/4 - 1/2 ) + 12 x 3 = 4 ( 2/16 ) - 23 ( 1/4 ) + 36 = 1/2 - 23/4 + 36 = (2-23+154)/ 4 = (156-23)/4 = 133/4

93932.

4(sin4 30 + cos4 60) - 23 ( sin2 60 - cos2 45) + 12 tan2 60

Answer»

= 4(sin⁴ 30 + cos⁴ 60) - 23 ( sin² 60 - cos² 45) + 12 tan² 60

= 4 ( (1/2)⁴ + (1/2)⁴ ) - 23 ( (√3/2)² - (1/√2)² ) + 12 (√3)²

= 4 ( 1/16 + 1/16 ) - 23 ( 3/4 - 1/2 ) + 12 x 3

= 4 ( 2/16 ) - 23 ( 1/4 ) + 36

= 1/2 - 23/4 + 36

= (2-23+154)/ 4

= (156-23)/4

= 133/4

Discussion

93933.	Compute the derivative of f(x) = cosx.
Answer» \(\frac d{dx}cosx=\lim\limits_{h \to 0}\frac{cos(x+h)-cos x}h\) \((\because f^1(x) = \lim\limits_{h \to 0}\frac{f(x+h)-f(x)}h)\) \(=\lim\limits_{h\to 0}\frac{cos xcos h-sin xsin h-cos x}h\) (\(\because\) cos (x + y) = cos x cos y - sin x sin y) \(=\lim\limits_{h\to 0}\frac{cosx(cos h-1)}h-\lim\limits_{h\to 0}sin x\frac{sin h}h\) \(=cos x\lim\limits_{h \to x}\cfrac{1-sin^2\frac h2-1}{\frac{h^2}4\times\frac 4h}-sin x\lim\limits_{h\to 0}\frac{sin h}h\) \(=-\frac24cos x\lim\limits_{h \to 0}h\left(\cfrac{sin\frac h2}{\frac h2}\right)^2\) - sin x \(\lim\limits_{h\to 0}\frac{sin h}h\) \(=-\frac12cos x\lim\limits_{h\to 0}h\left(\lim\limits_{h/2 \to 0}\cfrac{sin\frac h2}{\frac h2}\right)^2\) - sin x \(\lim\limits_{h\to 0}\frac{sin h}h\) \(=-\frac12 cos x\times0\times1^2-sin x\times1\) (\(\because\lim\limits_{h\to 0}\frac{sin h}h=1\)) = 0 - sin x = - sin x Hence, \(\frac d{dx} cos x=- sin x\)

93933.

Compute the derivative of f(x) = cosx.

Answer»

\(\frac d{dx}cosx=\lim\limits_{h \to 0}\frac{cos(x+h)-cos x}h\)

\((\because f^1(x) = \lim\limits_{h \to 0}\frac{f(x+h)-f(x)}h)\)

\(=\lim\limits_{h\to 0}\frac{cos xcos h-sin xsin h-cos x}h\)

(\(\because\) cos (x + y) = cos x cos y - sin x sin y)

\(=\lim\limits_{h\to 0}\frac{cosx(cos h-1)}h-\lim\limits_{h\to 0}sin x\frac{sin h}h\)

\(=cos x\lim\limits_{h \to x}\cfrac{1-sin^2\frac h2-1}{\frac{h^2}4\times\frac 4h}-sin x\lim\limits_{h\to 0}\frac{sin h}h\)

\(=-\frac24cos x\lim\limits_{h \to 0}h\left(\cfrac{sin\frac h2}{\frac h2}\right)^2\) - sin x \(\lim\limits_{h\to 0}\frac{sin h}h\)

\(=-\frac12cos x\lim\limits_{h\to 0}h\left(\lim\limits_{h/2 \to 0}\cfrac{sin\frac h2}{\frac h2}\right)^2\) - sin x \(\lim\limits_{h\to 0}\frac{sin h}h\)

\(=-\frac12 cos x\times0\times1^2-sin x\times1\) (\(\because\lim\limits_{h\to 0}\frac{sin h}h=1\))

= 0 - sin x = - sin x

Hence, \(\frac d{dx} cos x=- sin x\)

Discussion

93934.	If A and B are matrices of same order, then (AB1 – BA1) is Skew symmetric matrix Null matrix Symmetric matrix Unit matrix
Answer» We have matrices A and B of same order . Let P = (AB'- BA') = (AB')' - (BA')' = (B')'(A)'- (A')'B' = BA' - AB' = -(AB' - BA') = -P Hence, (AB' - BA') is a skew-symmetric matrix.

Discussion

93935.	If A = [(cos α,-sin α),(sin α,cos α)] and A + A' = I2, then α = (a) π(b) π/3(c) 3π/2(d) π/6
Answer» Answer is (b) π/3

Discussion

93936.	∫xex/(x + 1)2 dx =
Answer» Answer is (c) (e^x/(x + 1)) + c

Discussion

93937.	If A be a square matrix. Then A + A' will be a .............(a) Symmetric matrix (b) Skew symmetric matrix (c) Null matrix (d) Unit matrix
Answer» Answer is (b) Symmetric matrix

Discussion

93938.	If f(-x) = -f(x), then ∫f(x) dx for x ∈ [-a,a] = (a) 2 ∫f(x) dx for x ∈ [0,a](b) 0(c) 1(d) -1
Answer» Answer is (b) 0

Discussion

93939.	lt A is matrix of order 3 x 3, such that A2 = A, then (A + I3)3 - 7A is equal to?(a) I3(b) A (c) 3A (d) I3 - A
Answer» Answer is (a) I₃

Discussion

93940.	∫dx/(a2 + x2) =
Answer» Answer is (c) (1/a) tan^-1(x/a) + c

Discussion

93941.	Let A be a non-singular matrix of the order 2 x 2 then \|adj A\| = ------(a) 2\|A\| (b) \|A\| (c) \|A\|2(d) \|A\|3
Answer» Answer is (b) \|A\|

Discussion

93942.	(d/dx)([log(sec x + tan x)] = (a) 1/(sec x + tan x)(b) sec x (c) tan x(d) sec x + tan x
Answer» Answer is (b) sec x

Discussion

93943.	∫x2.ex^3 dx =
Answer» Answer is (b) ((1/3) e^{x^3}) + c

Discussion

93944.	If x2 y2 = (x + y)5, then dy/dx =(a) x/y(b) y/x(c) -y/x(d) -x/y
Answer» Answer is (b) y/x

Discussion

93945.	∫√(1 + cos 2x) dx =
Answer» Answer is (b) √2 sin x + c

Discussion

93946.	(d/dx) ([tan-1 √(1 + x2) - cot-1 (-√(1 + x2)] = (a) π(b) 1(c) 0(d) 2x/√(1 + x2)
Answer» Answer is (d) 2x/√(1 + x²)

Discussion

93947.	(d/dx)([limx → a ((x5 - a5)/(x - a)) = (a) 5a4(b) 5x4(c) 1(d) 0
Answer» Answer is (d) 0

Discussion

93948.	d(2x)/d(3x) =(a) (2/3)x(b) (2(x - 1)/(3(x - 1))(c) (2/3)x log3 2(d)(2/3)x log2 3
Answer» Answer is (c) (2/3)^x log₃ 2

Discussion

93949.	f(x) = √(3 sin x) + cos x is maximum then value of x = ..........(a) π/6(b) π/2(c) π/3(d) π/4
Answer» Answer is (c) π/3

Discussion

93950.	Equation of the tangent to the curve x2 + y2 = a2 is (x1, y1) is
Answer» Answer is (d) xx₁+ yy₁ = a²

Discussion

Explore topic-wise InterviewSolutions in .

-------- attack the whole grains both before and after harvest.a. Secondary Pestsb. Primary Pestc. Tertiary Pestd. None of All

Change or combine into a compound sentence1. As Rahim was sick, he could not attend the office.2. As he is wounded, he cannot walk fast.3. As he was poor, he could not lead a comfortable life.4. As Velu was sick, he could not attend class5. Mallika is very arrogant. She will not apologize

Something given away for no money is ______

Sometimes a bus ______ gets on the bus and checks the tickets. A) inspector B) agent C) conductor D) officer

Two weeks is also called a ______

Light brown marks on the skin are called ______

After the battle, the ________ soldiers were helped by those who could walk. A) damaged B) wounded C) broken D) killed E) blessed

-------------attack the damaged or broken grain or flour a. Secondary Pests b. Primary Pest c. Tertiary Pest d. None of All

The travel agent managed to ______ the problems about my ticket. A) stick to B) go with C) make out D) sort out

Something which is easily broken or damaged is ______

Where do you ______ the writing paper? In this desk. A) keep B) hold C) maintain D) guard

While he was looking on at the football game he ______ an old classmate from high school days. A) ran over B) ran after C) ran across D) went into

Peggy wants to ______ ceramics when she retires. A) look after B) take up C) wear out D) do over

PTO stands ______ “Please turn over”— the page, of course. A) as B) like C) for D) by

The gun ______ while he was cleaning it; it really frightened him. A) went off B) cut off C) ran overD) put up

Susan works so hard that no one in the office can ______ her. A) put up with B) go without C) get along with D) keep up with

Evaluate : ∫logx dx.

Why are those people ______ such a hurry? A) in B) on C) for D) of

Why didn't you go to the cinema with us, Susan? - _____. A) I couldn't continue writing. B) Thanks to you I've got into the theatre. C) I still believe him in spite of everything. D) I'll mend it within a week. E) I had to stay at home yesterday.

My radio doesn’t work very well, but I don’t know what is wrong ______ it. A) for B) to C) on D) with

Susan will probably work ______ six. A) for B) under C) until D) by

There are a number of differences ______ the two theories.A) from B) among C) between D) than

Are there any objections ______ the committee’s plan of action? A) to B) for C) at D) of

I am going to ask a few questions ______ that old gentleman. A) up B) from C) to D) in

Partial derivative of x4 – x2y2 + y4 w.r.t. y at point (-1,1). a) -2 b) 2 c) -1 d) 1

The angle between the lines vector r = (4 i - j) + 5(2i + j - 3k) and vector r = (i - j + 2k) + t(i - 3j + 2k) is (a) 3π/2(b) π/3(c) 2π/3 (d) π/6

The value of k x k = (a) 0 (b) 1 (c) |k|2 (d) None of these

Let R = {(1, 3), (4, 2), (2, 4), (2, 3). (3, 1)} be a relation on the set A = {1, 2, 3, 4}. The relation will be :(a) A Function (b) Reflexive (c) Not Symmetric (d) Transitive

Write Java statement to extract selected item from a given listbox named “jList1.”

Identify programming languages out of the following:HTML,C++, JAVA,MySQL

Write 5SQL queryclass 10 cbse

4(sin4 30 + cos4 60) - 23 ( sin2 60 - cos2 45) + 12 tan2 60

Compute the derivative of f(x) = cosx.

If A and B are matrices of same order, then (AB1 – BA1) is Skew symmetric matrix Null matrix Symmetric matrix Unit matrix

If A = [(cos α,-sin α),(sin α,cos α)] and A + A' = I2, then α = (a) π(b) π/3(c) 3π/2(d) π/6

∫xex/(x + 1)2 dx =

If A be a square matrix. Then A + A' will be a .............(a) Symmetric matrix (b) Skew symmetric matrix (c) Null matrix (d) Unit matrix

If f(-x) = -f(x), then ∫f(x) dx for x ∈ [-a,a] = (a) 2 ∫f(x) dx for x ∈ [0,a](b) 0(c) 1(d) -1

lt A is matrix of order 3 x 3, such that A2 = A, then (A + I3)3 - 7A is equal to?(a) I3(b) A (c) 3A (d) I3 - A

∫dx/(a2 + x2) =

Let A be a non-singular matrix of the order 2 x 2 then |adj A| = ------(a) 2|A| (b) |A| (c) |A|2(d) |A|3

(d/dx)([log(sec x + tan x)] = (a) 1/(sec x + tan x)(b) sec x (c) tan x(d) sec x + tan x

∫x2.ex^3 dx =

If x2 y2 = (x + y)5, then dy/dx =(a) x/y(b) y/x(c) -y/x(d) -x/y

∫√(1 + cos 2x) dx =

(d/dx) ([tan-1 √(1 + x2) - cot-1 (-√(1 + x2)] = (a) π(b) 1(c) 0(d) 2x/√(1 + x2)

(d/dx)([limx → a ((x5 - a5)/(x - a)) = (a) 5a4(b) 5x4(c) 1(d) 0

d(2x)/d(3x) =(a) (2/3)x(b) (2(x - 1)/(3(x - 1))(c) (2/3)x log3 2(d)(2/3)x log2 3

f(x) = √(3 sin x) + cos x is maximum then value of x = ..........(a) π/6(b) π/2(c) π/3(d) π/4

Equation of the tangent to the curve x2 + y2 = a2 is (x1, y1) is