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94851.

The milk is delivered about 6 A.M so we have FRESH milk for breakfast. A) old B) sound C) specific D) dirty E) sour

Answer»

Correct option is E) sour

94852.

The alloy used in the construction of aircrafts is : (1) Mg-Zn (2) Mg-Al (3) Mg-Sn (4)Mg-Mn

Answer»

Correct option (2) Mg-Al

Explanation:

It is completely memory based question for air-craft construction aluminum and its alloy is used because these are lighter.

94853.

Which alloy is used in the manufacturing of Aeroplane?(1) Mg - Al(2) Mg - Sn(3) Mg - Pd(4) Mg - Sb

Answer»

The correct option (1) Mg - Al   

Explanation:

Mg - Al alloy is used in manufacturing of Aeroplane.

94854.

The ratio of translational and rotational kinetic energies at `100K` temperature is `3:2`. Then the internal energy of one mole gas at that temperature is `(R=8.3j//"mol"-K]`A. `1175J`B. `1037.5J`C. `2075J`D. `4150J`

Answer» Accordingly to law of equipartion of energy, energies equally distributed among its degree of freedom. Let transitional and rotaional degree of freedom be `f_(1)` and `f_(2)`
`therefore (K_(T))/(K_(R))=(3)/(2)` and `K_(T)+K_(R)=U`
Hence the ratio of transitional to rotational degrees of freedom is `3.2`. Since transiational degrees of freedom is `,`. the rotational degrees of freedom must be `2`
`therefore` Internal energy `(U)=1xx(f_(1)+rf_(2))=(1)/(2)RT`
`U=(1xx5xx8.3xx100)/(2)=U=2075J`
94855.

In each of the four situations of column-I , a stretched string or an organ pipe is given along with the required data. In case of strings the tension in string is T=102.4 N and the mass per unit length of string is 1g/m. Speed of sound in air is 320 m/s. Neglect end corrections.The frequencies of resonance are given in column-II.Match each situation in column-I with the possible resonance frequencies given in Column-II.A. `{:(,p,q,r,s),((A),1,3,2,4):}`B. `{:(,p,q,r,s),((B),1,4,3,2):}`C. `{:(,p,q,r,s),((C ),3,2,4,1):}`D. `{:(,p,q,r,s),((D ),2,4,1,3):}`

Answer» (A) The fundamental frequency in the string.
`f_0=sqrt(T//mu)/(2l)=sqrt(102.4/(1xx10^-3))xx1/(2xx0.5)Hz=320 Hz`.
Other possible resonance frequencies are `f_A and f_0=320 Hz, 640 Hz, 960 Hz`
(B)The fundamental frequency in the string.
`f_0=sqrt(T//mu)/(4l)=320/(4xx0.5)=160 Hz`.
Other possible resonance frequencies are
`f_B`=160 Hz, 480 Hz, 800 Hz.
(C )The fundamental frequency in both ends open organ pipe is
`f_0=v/(2l)=320/(2xx0.5)=320 Hz`
Other possible resonance frequencies are
`f_c=320 Hz,640 Hz, 960 Hz`
(D)The fundamental frequency in one end open organ pipe is
`f_0=v/(4l)=320/(4xx0.5)=160 Hz`
Other possible resonance frequencies are `f_D=160 Hz, 480 Hz, 800 Hz`
94856.

Which of the following alcohol will give immediate turbidity at room temperature when reacts with lucas reagent :-A. B. C. D.

Answer» Correct Answer - D
`3^@` alcohol react very fast with Lucas reagent
94857.

Where have you been? I’ve been looking for you _____ . A) everywhere B) all pieces C) anywhere D) some places

Answer»

Correct option is A) everywhere

94858.

There are so many cars ________ nowadays. A) for all places B) in all the place C) anywhere D) everywhere

Answer»

Correct option is D) everywhere

94859.

Let's study Linear Inequalities Formula and Notes Maths Class 11 here.

Answer»

Linear Inequalities:

Previously we read about equations which denote equality. We take an example of the number of student two classes. If the number of student in one class is same as that in another class then this involves equality. But in reality, we see that the number of students in each class varies in number. Thus, if the number of students is different in different classes we represent it by linear inequalities. The number of student in one class may be either greater than or less than another class.

We denote a greater symbol as ‘>’ and lesser symbol as ‘<’ when compared to other quantity.

Inequality:

Two real numbers or two algebraic expressions related by the symbol ‘<’, ‘>’, ‘≤’ or ‘≥’ this form an inequality.

Terminology related to Linear Inequalities:

Numerical inequalities: When only numerals are compared then it is numerical inequalities.
3 < 5; 7 > 5 are the examples of numerical inequalities.

Literal inequality: When literals or variables are compared with numerical or literals then it is Literal inequalities.
x < 5; y > 2; x ≥ 3, y ≤ 4 are some examples of literal inequalities.

Strict Inequalities: When two quantities are compared and one is either greater than or less than the other but not equal to other is strict inequality.
Example: ax + b < 0, ax + by > c etc.

Slack Inequalities: When two quantities are compared and one is either greater than and equal to or less than and equal to the other than it is slack inequality.
Example: ax + b ≤ 0, ax + by ≥ c

Linear inequality in one variable: Inequation containing only one variable is linear inequalities in one variable.
Example: ax + b < 0, ax + b ≤ 0, ax + b ≥ 0 etc.

Linear inequality in two variable: Inequation containing two variables is linear inequalities in two variable.
Example: ax + by < c, ax + by > c, ax + by ≥ c etc.

Rules of Linear Inequalities:

  1. Equal numbers may be added to (or subtracted from) both sides of an inequality.
  2. Both sides of an inequality can be multiplied (or divided) by the same positive number. But when both sides are multiplied (or divided) by a negative number, then the inequality is reversed.
  3. The values of x, which make an inequality a true statement, are called solutions of the inequality.
  4. To represent x < a (or x > a) on a number line, put a circle on the number a, and dark line to the left (or right) of the number a.
  5. To represent x < a (or x > a) on a number line, put a circle on the number a and dark line to the left (or right) of the number a.
  6. For Graphical representation of linear inequality having sign ≤ or ≥ then points on the line is also included in calculating its shading and graph of the inequality lies left (below) or right (above) of the graph.
  7. For Graphical representation of linear inequality having sign < or > graph of the inequality lies only left (below) or right (above) of the graph not on the line.
  8. The solution region of a system of inequalities is the region which satisfies all the given inequalities in the system simultaneously. 
94860.

`CH_4` gas is obtained in :- (a)Hydrolysis of `Al_4C_3` (b)Hydrolysis of `Be_2C` (c )Hydrolysis of `Mg_2C_3` (d) Hydrolysis of `CaC_2`A. only a, b, cB. only a, bC. only a, cD. only b, c, d

Answer» Correct Answer - B
`Al_2C_3 + 12H -OH to 4Al(OH)_3 + 3CH_4`
`Be_2C + 4H-OH to 2Be(OH)_2 +CH_4`
94861.

1. Solve 24x < 100, when(i) x is a natural number.(ii) x is an integer.2. Solve – 12x > 30, when(i) x is a natural number.(ii) x is an integer.3. 3 (1 – x) < 2 (x + 4)4. Ravi obtained 70 and 75 marks in first two unit test. Find the minimum marks he should get in the third test to have an average of at least 60 marks.5. To receive Grade ‘A’ in a course, one must obtain an average of 90 marks or more in five examinations (each of 100 marks). If Sunita’s marks in first four examinations are 87, 92, 94 and 95, find minimum marks that Sunita must obtain in fifth examination to get grade ‘A’ in the course.

Answer»

Q1. 

(i) \(24x < 100\)

\(⇒\) \(x < \frac{100}{24}\) (Dividing both sides by 24) 

\(⇒\) \(x < \frac{25}{6} \)

The natural numbers less than 4 are 1, 2, 3 

∴ The solution set is {1, 2, 3}

(ii) The integers less than 4 are … -3, -2, -1, 0, 1, 2, 3, 4

∴ The solution set is {… -3, -2, -1, 0, 1, 2, 3, 4}. 

Q2. 

(i) \(-12x > 30 \)

\(⇒\) \(​​x > \frac{-30}{12} \)

\(⇒\) \(x > \frac{-5}{2} \)

There is no natural number less than, \(\frac{-5}{2} \) thus there is no solution for this inequality. 

(ii) The integers less than \(\frac{-5}{2} \) are … -5, -4, -3

The solution set is {…-5, -4, -3}. 

Q3. 

Sol:- \( 3(1 – x)< 2 (x + 4)\)

\(⇒\) \(3 - 3x < 2x + 8\)

\(⇒\) \(3 < 5x + 8\)

\(⇒\) \(-5 < 5x\)

\(⇒\) \(x > - 1\)

\(∴ x ∈ (-1, ∞)\)

Q4. 

Let the minimum marks be x. Then, 

\(⇒\) \(\frac{70 + 75 + x}{3} ≥ 60 \)

\(⇒\) \(\frac{145 + x}{3} ≥ 60 \)

\(⇒\) \(145 + x ≥ 180\)

\(⇒\) \(x ≥ 35\)

Ravi should get minimum 35 marks in the third set to have an average of at least 60 marks. 

Q5. 

Let the minimum marks scored by Sunita be x. Then, 

\(⇒\) \(\frac{87 + 92 + 94 + 95 + x}{5} ≥ 90 \)

\(⇒\) \(\frac{368 + x}{5} ≥ 90 \)

\(⇒\) \(368 + x ≥ 450 \)

\(⇒\) \(x ≥ 82\)

The minimum marks scored by Sunita must be 82. 

94862.

I’ve been looking for you ________ . A) everywhere B) anywhere C) for all places D) in all places

Answer»

Correct option is A) everywhere

94863.

That’s the man ________ yesterday. A) which I was talking to B) what I was talking to C) I was talking to D) with who I was talking

Answer»

Correct option is C) I was talking to

94864.

She came ________ because her car has broken down. A) walking B) by foot C) with foot D) on foot

Answer»

Correct option is D) on foot

94865.

commercialisation of agriculture during British rule led to ?

Answer»

Commercialisation led to growth of national agriculture and agricultural problem acquired national form. 

94866.

12. Which of the following reactions is not correct?(a) \( 2 F _{2}+2 H _{2} O \rightarrow 4 H ^{+}+4 F ^{-}+ O _{2} \)(b) \( 2 I _{2}+2 H _{2} O \rightarrow 4 H ^{+}+4 I ^{-}+ O _{2} \)(c) \( Cl _{2}+ H _{2} O \rightarrow HCl + HOCl \)(d) \( Br _{2}+ H _{2} O \rightarrow HBr + HOBr \)

Answer»
And B from answer key
94867.

Milkman has a container filled with a mixture of milk and water which are in the ratio of 7 : 3. How many parts of the mixture needs to be removed and replaced from the water to obtain milk and water in ratio of 1 : 1?1. 2/32. 2/73. 2/54. 1/75. None of the above

Answer» Correct Answer - Option 2 : 2/7

Given:

Initial ratio of milk to water ratio = 7 : 3

Calculations:

Here, let milk in mixture be 7 liters and water be 3 liters

⇒ milk : water = 7 : 3

⇒ Let, X to be quantity of mixture withdrawn and replaced with water.

⇒ (7 - 7X/10)/(3 - 3X/10 + X) = 1/1

⇒ 7 - 7X/10 = 3 - 3X/10 + X

⇒ 7 - 3 = 7X/10 - 3X/10 + X

⇒ 4 = 14X/10

⇒ X = 20/7

⇒ Total quantity = 10 liters

⇒ Quantity withdrawn = 20/7 × 1/10

⇒ Quantity withdrawn = 2/7

∴ 2/7th of mixture needs to be replaced with water.

94868.

Write the IUPAC name of

Answer»

Ethony propane

94869.

You are General Manager, Hotel Dosa, Gurgaon. You need a lady Front Office Assistant with sound knowledge of computers. She must be a graduate and good in communication skills with pleasing manners. Draft an advertisement in not more than 50 words to be published in Gurgaon Times.

Answer»

Situation Vacant 

REQUIRED a female Front Office Assistant with sound knowledge of computers in Hotel Dosa, Gurgaon. The candidate must be a graduate and good in communication skills with pleasing manners. Experienced applicant preferred. Salary negotiable. Interested candidates may submit their Biodata before 10th March,2013 at Hotel Dosa Reception. For further details contact us at 0xx-xxxxxxxxxx

94870.

Write the IUPAC name of

Answer»

2-bromo-propanamide

94871.

Write the IUPAC name of

Answer»

Tertiary Amine or Ethyl-diemethyl amine

94872.

The first two-wheeler public transport service for all women started in Gurgaon was called _______.A. Bikxie BlueB. Bikxie PinkC. Bikxie GreenD. Bikxie Red1. B2. D3. A4. C

Answer» Correct Answer - Option 1 : B

The correct answer is Bikxie Pink.

  • The first two-wheeler public transport service for all women started in Gurgaon was called Bikxie Pink.

  • Bikxie - a bike taxi - is a service that has been playing on congested Gurgaon roads to get you to work and other engagements on time.
  • Bikxie, a two-wheeler taxi service provider, has announced the ‘soft launch’ of its women-only service Bikxie Pink in Delhi, on the occasion of International Women’s Day 2018. 
  • A first-of-its-kind service in the national capital, Bikxie Pink offers a fleet of electric scooters exclusively driven by women and for women.
  • The service was earlier launched in Gurugram in January 2016 and claims to have received immense popularity from women commuters in the city. 
  • Bikxie Pink will initially be rolled out with 10 women pilots, but the numbers shall increase to more than 100 female pilots in the next few months across Delhi NCR. 
  • On the Bikxie mobile app, female customers will be able to opt for Bikxie Pink pilots, or they may hail the scooties from key metro stations.
  • The app-based service is segmented into Bikxie Blue for men and Bikxie Pink for women - a safe solution where the driver is the same sex as the customer.
94873.

How will you distinguish between methanoic acid and ethanoic acid?

Answer»

Difference between Methanoic acid and Ethanoic acid

Methanoic acidEthanoic acid
(i) Simple name- Formic acid(i) Acetic acid
(ii) Formula- HCOOH(ii) CH3COOH
(iii) Melting point- 8°C(iii) 16.7°C
(iv) Boiling point- 100.5°C(iv) 118°C
(v) Density- 1.24(°C)(v) 1.05(°C)
94874.

How  many molecules of ATP are produced per molecule of glucose in glycolysis?

Answer»

38 molecules of ATP are produced per molecule of glucose in glycolysis.

94875.

Which one of the following is not a wildlife conservation projectA. Project Indian BastarB. Project TigerC. Project HangulD. Project Dodo

Answer» Correct Answer - D
(D) Project Dodo is not a wildlife conservation project.
94876.

Define Antibiotics with one example

Answer»

Antibiotics-

Antibiotics are defined as chemical substances  (produced wholly or partially by chemical synthesis), which in low concentration, either kill or inhibit the growth of microganism by intervening in their metabolic processes.

Example- Penicillin, Streptomycin, ofloxacin, etc

94877.

Pollen tube discharges its male gametes intoA. EggB. Healthy synergidC. Degenerating synergidD. Central cell

Answer» Correct Answer - C
(C) Pollen tube discharges its male gametes into degenerating synergid.
94878.

Define Analgesics with one example:

Answer»

Analgesics-

Drugs which reduce or abolish pain without causing impairment (reduction) of consciousnenss, mental confusion, in coordination or paralysis or some other disturbance or disorder of the nervous system are called analgesics. These are classified into the following two categories.

Non-narcotic (non-addictive) analgesics- Aspirin (2-acetaxybenzoic acid) and paracetamol (4-acetamidophenol).

Narcotic (addictive) analgesics- drugs which when administered in small doses relieve pain and produce sleep are called narcotics.

Example: Morphine, codeine, heroine

94879.

Name the vitamin whose deficiency is responsible for night blindness

Answer»

Deficiency of vitamin 'A' is responsible for night blindness.

94880.

Assertion (A) : H2S is less acidic than H2Te.Reason (R) : H-S bond has more Δbond H° than H-Te bond.(A) Both A and R are true and R is the correct explanation of A.(B) Both A and R are true but R is not the correct explanation of A.(C) A is true but R is false.(D) A is false but R is true.

Answer»

Option : (A) Both A and R are true and R is the correct explanation of A.

H2S is less acidic than H2Te. acidity depends on H-S and H-Te bond dissociation energy higher the bond dissociation energy. Less will be acidity.

On moving down the group the size of the atom increases and ionization enthalpy decreases. This helps to dissociate the bond easily. That's why H2Te is more acidic than H2S.

94881.

Define the Antiseptics with suitable examples:

Answer»

Antiseptics-

Antiseptics are the chemical substances which provent the growth of micro-organism and may even kill them.

They are safe to be applied to living tissues. Thus, they are generally applied on the wounds, cuts, ulcers and diseased skin surfaces in form of antiseptic cream like furacin, soframycin. Antiseptics are also added to face powder, breath purifiers, etc to reduce the odour produced as a result of bacterial decomposition of organic matter on the body or in the mouth.

94882.

Define colligative properties of solution and describe relative lowering of vapour pressure.

Answer»

The properties of solution which depends upon number of solute particles present in the solution irrespective of their nature is called colligative properties of solution.

The following conditions are satisfied for normal colligative properties of solution.

(i) Solution should be very dilute.

(ii) Solute should be non-volatile, does not dissociable or associable.

Example:–

(a) Lowering of vapour pressure.

(b) Elevation in the boiling point.

(c) Depression in the freezing point.

(d) Osmotic pressure.

Lowering of vapour pressure – When a non-volatile solute is added in a solvent. 

The vapour pressure is lowered due to the following reason.

(i) Surface area of solution decreases from solvent molecules. V. P.  surface area of solvent

(ii) Density of solution increases and rate of evaporation decreases.

Rate of Evaporation ∝ √1/density

Therefore V.P. of solution decreases from pure solvent.

V.P. of pure solvent = Po

V.P. of solution = Ps

Lowering of V. P. = Po – Ps 

Relative lowering of V.P.  = Po – Ps /Po

According to Raoult’s law

Po – Ps/Po = mole fraction of solute .

94883.

Give the reaction of 5% dilute HNO3 with copper metal

Answer»

When Zn reacts with HNO3 (50% concentration), then we get zinc nitrate, water and Nitric oxide.

3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O

94884.

Account for Fluorine shows only are oxidation state, but rest of the halogens show different oxidation states.

Answer»

Electronic configuration of flourine is 1s22s22px22py22pz2. It has only one orbital half filled and no d-orbital. The orbital cannot be on paired being highly electronegative. It shows only-1 oxidation state as it saturates its valences shell by accepting one electron.

94885.

Account for the of noble gases only xenon forms real chemical compounds.

Answer»

Only Xe (xenon) makes real chemical compound in the noble gases because of it converts into solid after cooling

94886.

Account for H2O is liquid but H2S is gas

Answer»

In vapour state (~100 K). Sulphur party exists as S2 molecule like O2 has two unpaired electrons in the anti-bonding π mole colour orbital and exhibits paramagnetism.

94887.

234.2 gm of sugar syrup contains 34.2 gm of sugar. What is the molal concentration of the solution?(a) 0.1(b) 0.5(c) 5.5(d) 55

Answer»

Answer (b) 0.5

94888.

Account for Noble gases are montomic in nature.

Answer»

Noble gases are monoatomic in nature. It is because noble gases make oxidation.

94889.

Account for bleaching of flowers by chlorine is permanent but that by sulphur dioxide is temporary.

Answer»

In presence of moisture, chlorine acts as an oxidizing agent and a bleaching agent.

Cl2 + H2O → HCl + HOCl(Unstable)

HOCl → HCl + O Nascent oxygen

Coloured matter to → Colourless matter.

The bleaching action is permanent due to Nascent oxygen. Bleaching action of SO2 in presence of moisture is due to Mascent hydrogen.

2SO4 + 2H2O → H2SO4 + 2H

Coloured matter + H → colours matter

So, bleaching action of SO2 is temporary

94890.

In the experiment it is found that 2.0769 gram of pure X produce 3. 6769 gram of pure x2O5 the number of mole of X is

Answer»

The balanced equation for the above reaction is 

2 X + 5/2 O→ X2O5

Now the mass of oxygen using law of conservation of mass = 3.6769 - 2.0769

Hence mass of Oxygen utilized in the reaction = 1.6 g 

number of moles of oxygen = given mass / molar mass 

Hence the number of moles of oxygen = 1.6/ 32 = 0.05 moles 

As 5/2 moles of O2 reacts with 2 moles of X

Hence 

5/2 mole of O2 → 2 moles of X

1 mole of O2 → 4/5 moles of X

0.05 moles of O2 reacts with → 4× 0.05/ 5 moles of X

Hence the number of moles of  X present in the system = 0.04. 

94891.

Bleaching of flowers by chlorine is permanent but that of sulphurdioxide is temporary, why ?

Answer»

Bleaching Nature of Cl2

In presence of moisture, chlorine acts as a bleaching agent. Chlorine reacts with water to form HCl and HCLO. HCLO is not stable. It decomposed to produce nascent oxygen.

Cl2 + H2→ HCl + HClO

 HClO → HCl  + O

Coloured flower + Nascent oxygen  colourless flower the bleaching action of chlorine is permanent. This is due to oxidizing nature of chlorine.

Bleaching action of CO2

In presence of moisture, SO2 produces nascent hydrogen.

SO2 2H2→ H2SO4 2[H]

Coloured flower + [H]  colourless flower the bleaching is temporary. This is due to reducing nature of SO2

94892.

Which type of extrinsic semiconductor is formed when silicon is doped with phosphorus? Mention the major charge carrier in it.

Answer»

n-type, Electron (s).

94893.

Which of the following bases is present in RNA only ?(a) Aderine(b) Guanine(c) Uracil(d) Thymine  

Answer»

 Uracil  is present in RNA only.

94894.

Why is phosphorus doped sizlicon is semiconductor ?

Answer»

When silicon is doped with small amount of phosphorus, its electrical conductivity increases. When silicon is doped with phosphorus, some of the positions in the lattice are substituted by phosphorus atoms. Phosphorus has five valence electrons. After forming four covalent bonds with silicon, one excess electron is left on phosphorus. This electron is not in volved in bonding and is delocolised. This contributes to electrical conductivity.

94895.

Penicillin is-(a) Harmone(b) Analgesics(c) Antibiotic(d) Antibody

Answer»

Penicillin is  Antibiotic

94896.

On warming an aqueous solution of benzene-diazonium chloride, the product obtained is-(a) Benzene(b) Aniline(c) Phenol(d) Amide

Answer»

On warming an aqueous solution of benzene-diazonium chloride, the product obtained is Phenol

94897.

What is a tropic movement? Explain with an example.

Answer»

The directional growth movements of plants due to external stimuli are called tropic movement. It can be either towards the stimulus, or away from it. For example, in case of phototropic movement, shoots respond by bending towards light while roots respond by bending away from it.

94898.

In Figure 7.4 (a), (b) and (c), which appears more accurate and why?

Answer» Figure (a) is more appropriate because in a plant shoots are
negatively geotropic hence, grow upwards and roots are positively
geotropic so grow downwards.
94899.

Column (A)Column (B)(a) Olfactory receptors(b) Thermo receptors (temperature receptors)(c) Gustatoreceptors(d) Photoreceptors  (i) Tongue (ii) Eye (iii) Nose(iv) Skin

Answer» (a) — (iii) (b) — (iv)
(c) — (i) (d) — (ii)
94900.

Label the parts of a neuron in Figure 7.5.

Answer» (a) Dendrite
(b) Cell body
(c) Axon
(d) Nerve ending