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95501.

In the given figure AB, BC, BD cannot be in A. A.P.B. G.P.C. H.P.D. None of these

Answer» Correct Answer - A
95502.

Is 184 a term of the sequence 3,7,11, ... ?

Answer» Correct Answer - No
95503.

If `x in R ,`the numbers `2^(1+x)+2^(1-x), b//2,36^x+36^(-x)`form an A.P., then `b`may lie in theinterval`[12 ,oo)`b. `[6,oo)`c. `(-oo,6]`d. `[6, 12]`A. `[12, oo)`B. `[6, oo)`C. `(-oo, 6]`D. `[6, 12]`

Answer» Correct Answer - B
If `x in R`, the numbers ………….
`b = (2^(t+x)+2^(t-x))+(36^(x)+36^(-x))`
` = 2underset(ge2)underbrace((2^(x)+2^(-x))) + underset(ge2)underbrace((6^(2x)+6^(-2x)))`
`implies b ge 2(2)+2 = 6`
`i.e. b in [6, oo)`
95504.

If `x in R ,`the numbers `2^(1+x)+2^(1-x), b//2,36^x+36^(-x)`form an A.P., then `b`may lie in theinterval`[12 ,oo)`b. `[6,oo)`c. `(-oo,6]`d. `[6, 12]`A. `[12,oo)`B. `[6,oo)`C. `(-oo,6)`D. `[6,12]`

Answer» Correct Answer - A
95505.

If 13 tan θ= 12, then find the value of (2sinθ cosθ/cos2θ – sin2θ).

Answer»

Given : 13 tan θ = 12

Now given expression is,(2sinθ. cosθ/cos2θ– sin2θ)

Dividing numerator and denominator by cos2θ.

Given expression is = 312/25

95506.

A force `F=-K(yhati+xhatj)` (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point `(a, 0)`, and then parallel to the y-axis to the point `(a, a)`. The total work done by the force F on the particle isA. `-2ka^(2)`B. `2ka^(2)`C. `-ka^(2)`D. `ka^(2)`

Answer» Correct Answer - C
95507.

What is the solution of the pair of linear equations 37x+43y=123, 43x+37y=117?(a) x = 2,y = 1(b) x = -1,y = 2(c) x = -2,y = 1(d) x = 1,y = 2

Answer»

Correct answer is: (d) x = 1,y = 2

37x+43y=123 ........(1) 

43x+37y=117 ........(2) 

Adding (1) and (2)

X+ y=3 ........(3)

Subtracting (2) from (1)

-x + y=1......(4)

Adding (3) and (4),

2y=4

y=2

⇒ x=1

∴ solution is x=1 and y=2

95508.

A vertical stick 20m long casts a shadow 10m long on the ground. At the same time a tower casts a shadow 50m long. What is the height of the tower?(a) 30m(b) 50m(c) 80m(d) 100m

Answer»

Correct answer is: (d) 100m

Height of Vertical stick/Shadow of vertical stick=height of tower/shadow of tower

20/10=Height of tower/50

Height of tower=100 m

95509.

A particle is ejected from the tube at A with a velocity `V` at an angle `theta` with the verticle y-axis at a height h above the ground as shown. A strong horizontal wind gives the particle a constant horizontal acceleration a in the positive x-direction. If the particle strikes the ground at a point directly under its released position and the downward y-acceleration is taken as g then find h. A. `h= (2V^(2)sin theta cos theta)/(a)`B. `h =(2V^(2)sin theta cos theta)/(g)`C. `h =(2V^(2))/(g)sin theta[cos theta+(a)/(g)sin theta]`D. `h =(2V^(2))/(a)sin theta[cos theta+(g)/(a)sin theta]`

Answer» Correct Answer - D
A particle is …………
Since x - displecement is zero
`0 = Vsin theta t-(1)/(2)at^(2)`
`t = (2Vsin theta)/(a)`
`h = Vcos theta t+(1)/(2)"gt"^(2)`
`h = (2V^(2))/(a)sin theta [cos theta+(g)/(a)sin theta]`
95510.

The potential energy of a body is given by `U=9/x^(2)-2/x` The position at which its speed can be maximum is.A. `x=+3m`B. `x=-3m`C. `x=9m`D. `x=-9m`

Answer» Correct Answer - C
`U=-2/x+9/x^(2)`
`(du)/dx=+2/x^(2)-18/x^(3)`
` f=-(du)/dx=-2/x^(2)+18/x^(3)`
`f=0Rightarrowx=+9`
`(d^(2)U)/dx^(2)=-4/x^(3)+54/x^(4)`
`at x=9 (d^(2)U)/dx^(2)=(d^(2)U)/dx^(2)=[-4+6//27]ge=0Rightarrow potential energy is minimum`
95511.

A particle is moving with constant velocity `(6hati+8hatj)m//s`. It corosses x-axis at point `(2,0)`. The rate of separation from origin at this moment is :A. `6ms^(-1)`B. `8ms^(-1)`C. `10ms^(-1)`D. `7ms^(-1)`

Answer» Correct Answer - A
A particle is …………
Rate of seperation at any instant is determined by the component of velocity which is along the line joining the two refrence points. Here x-axis is the line of seperation and hance, rate of seperation `= v_(x) = 6 m//s`.
95512.

The conveyed belt is moving at `4m//s` the coefficient of static friction between the conveyed belt and the 10kg package Bis ` mu_(s)=0.2 determine the shortest time in which the belt can be stopped so the the package does not slide on the belt A. 1sB. 2sC. 4sD. 8s

Answer» Correct Answer - B
`a_(max)=mu,g=0.2xx10=2m//s^(2)`
`t_(min)=u/a_(max)=4/2=2sec`
95513.

A block of mass 10kg is placed on rough inclined plasne of variable angle `theta` and friction coefficient `mu_(s)=mu_(k)=3//4`. When `theta` is `37^(@)` net reaction force applied by inclined is `vecN_(1)` and when `theta = 53^(@)` net reaction force applied by inclined is `vecN_(2)` , then `|vecN_(1)|-|vecN_(2)|` is :A. `0`B. `25N`C. `-25N`D. `-37N`

Answer» Correct Answer - B
A block of …………..
`Mg - sqrt(1+mu^(2))Mg cos theta`
`= 25 N`.
95514.

In a parallel-plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is connected to a cell and the slab is taken out. ThenA. the potential difference across the capacitor reduces.B. the potential difference across the capacitor increases.C. the energy stored in the capacitor reduces.D. no work is done by an external agent in taking the slab out.

Answer» Analyse the situation gives qualitavely the charge on the plates can not change.
95515.

A particle is moving with a constant acceleration `veca = hati-2hatj+2hatk m//s^(2)` and instantaneous velocity `vecv = hati+2hatj+2hatk m//s`, then rate of change of speed of particle 2 second after this instant will be :A. `(19)/(3)m//s^(2)`B. `3m//s^(2)`C. `(19)/(7)m//s^(2)`D. None of these

Answer» Correct Answer - C
A particle is …………
`vecv=(hati+2hatj+2hatk)+2(hati-2hatj+2hatk)`
`= hati +2hatj+2hatk+2hati-4hatj+4hatk`
`= 3hati-2hatj+6hatk`
`(d|vecv|)/(dt)=((3hati-2hatj+6hatk))/(sqrt(9+4+36))(hati-2hatj+2hatk)`
`= (19)/(7)`
95516.

(a). Write the basic nuclear process involved in the emission of β+ in a symbolic form, by a radioactive nucleus. (b).In the reactions given below : (i). \(^{11}_6C\) → \(^{Z}_YB\) + x + v(ii). \(^{12}_6C\) + \(^{12}_6B\) → \(^{20}_aNe\) + \(^{c}_bHe\) Find the values of z, y and x and a, b& c.

Answer»

(a) For beta plus decay, 

A proton transforms into a neutron within the nucleus, according to :

P → n + e+ + v;

v = neutrino

Example of B+ decay :

\(_{11}Na^{22}\) → \(_{10}Ne^{22}\) + e+ + v 

Infect, 

Lighter radioactive isotopes with Z < 70 decay mostly by beta plus decay.

(b) (i). \(^{11}_6C\) → \(^{Z}_YB\) + x + v 

x : positron 

⇒ +1e0 

∴ Y = 5, Z = 1

(ii). \(^{12}_6C\) \(^{12}_6B\) → \(^{20}_aNe\) + \(^{c}_bHe\)

b = 2, c = 4 

a = 10

95517.

Assertion: In u235 fission reaction neutrons are required to be slowed down.Reason: The probability of capture of slow moving neutrons is high for u235. (1) If both assertion and reason are true and reason is the correct explanation of assertion. (2) If both assertion and reason are true but reason is not the correct explanation of assertion. (3) If assertion is true but reason is false. (4) If both assertion and reason are false.

Answer»

(1) If both assertion and reason are true and reason is the correct explanation of assertion.

95518.

In the nuclear raction `._1H^2 +._1H^2 rarr ._2He^3 +._0n^1` if the mass of the deuterium atom `=2.014741 am u`, mass of `._2He^3` atom `=3.016977 am u`, and mass of neutron `=1.008987 am u`, then the `Q` value of the reaction is nearly .A. 0.000352MeVB. 3.27 MeVC. 0.82 MeVD. 2.45 Me V

Answer» Correct Answer - B
`Q=[sum m_("reac tan ts")-summ_("products")]c^(2)`
`=2xx2.014741-(3.016977+1.008987)xx931MeV`
`=3.27Me V`
95519.

Statement-1:A mixture of p-Methylbenzoic acid and picric acid is separated by `NaHCO_3` solution. Statement-2:p-Methylbenzoic acid is soluble in `NaHCO_3` because it gives effervesence of `CO_2`A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - D
Both will give `CO_2` gas with `NaHCO_3` due to stronger acidic nature.
95520.

The degree of ionisation of a `0.1 M` bromoacetic acid solution is `0.13`. Calculate the `pH` of the solution and the `pK_(a)` of bromoacetic acid.

Answer» `{:(,BrCH_(2)COOH,hArr,CH_(2)(Br)COO^(Θ),+,H^(o+)),("Initial conc.",C,,0,,0),("Conc. at Eq.",C-Calpha,,Calpha,,Calpha):}`
`{:(Initial conc.,C,,0,0),(Conc. at Eq.,C-Calpha,,Calpha,Calpha):}`
`K_(a)=(Calpha.Calpha)/(C(1-alpha))=(Calpha^(2))/(1-alpha)~~Calpha^(2)`
`=0.1xx(0.132)^(2)=1.74xx10^(-3)`
`pK_(a)=-log(1.74xx10^(-3))=3-0.2405=2.76`
`[H^(o+)]=Calpha=0.1xx0.132=1.32xx10^(-2)M`
`pH=-log(1//32xx10^(-2))=2-0.1206=1.88`
95521.

The `pH` of `0.005 M` codine `(C_(18)H_(21)NO_(3))` solution is `9.95`. Calculate its ionisation constant and `pK_(b)`.

Answer» Codenine is `W_(B)`:
`BOH hArr B^(o+)+overset(Θ)(O)H`
`pH=9.95 :. pOH=14-9.95=4.05`
`pOH_(W_(B))=1/2(pK_(b)-logC)`
`4.05xx2=(pK_(b)-log 5xx10^(-3))`
`8.1=(pK_(b)-0.7+3), pK_(b)=8.1-2.3=5.8`
`K_(b)=Antilog (-5.8)=` Antilog `(-5-0.8+1-1)`
=Antilog `bar(6).2=1.588xx10^(-16)`
`:. K_(b)=1.588xx10^(-6)`
95522.

Which of the following thermodynamic properties must be associated with a reaction spontaneous at only high temperaturesA. `DeltaHlt0,DeltaSlt0`B. `DeltaHlt0,DeltaSgt0`C. `DeltaHgt0,DeltaSgt0`D. `DeltaHgt0,DeltaSlt0`

Answer» Correct Answer - C
`DeltaG=DeltaH-TDelta`
`(+ve)-(=ve)`
`DeltaG=-ve` only at high temp.
95523.

If the `DeltaG^(@)` of a cell reaction `AgCI+e^(-)` is `-21.20KJ` standard emf of cell isA. 0.329VB. 0.220VC. `-0.220V`D. `-0.110V`

Answer» Correct Answer - B
`DeltaG^(@)-nFE^(@)`
`-21.20=-1xx96500xxE^(@)`
`E^(@)(21.20xx1000)/(96500)`
`=0.22V`
95524.

Consider the following reactions: `C(s)+O_(2)(g)toCO_(2)(g)+x " kJ"` `CO(g)+(1)/(2)O_(2)(g)toCO_(2)(g)+y" kJ"` The heat formation of CO(g) is :A. `-(X+Y)kJ//mol`B. `(X-Y)kJ//mol`C. `(Y-X)kJ//mol`D. `(Y+X)kJ//mol`

Answer» Correct Answer - C
`T.R:C_(s)+(1)/(2)O_(2(g))toCO_((g)),DeltaH_(r)=DeltaH_(f)`
`T.R=(I)+(II)rev`
`=(-X)+(+Y)`
`DeltaH_(r)=Y-X`
95525.

The enthalpy change for the following reaction is 368 kJ. Calculate the average O-F bond energy. `OF_(2)(g)rarrO(g)+2F(g)`A. `184kJ//mol`B. `368kJ//mol`C. `536kJ//mol`D. `736kJ//mol`

Answer» Correct Answer - A
average` B.E=(368)/(2)=184kJ//mol^(-1)`
95526.

For a solution concetration can be expressed as 16% w/w well as 20 % w/v. what will be density of solution ?A. 1.5 gm/litB. 0.8 gm/litC. 1.25 gm/mlD. 0.8 gm/ml

Answer» Correct Answer - C
`((w_(B))/(w_(s))xx100=16)/((w_(B))/(v_(s))xx100=20)`
`(v_(s))/(w_(s))=16/20rArr d=5/4 =1.25 gm//ml`
95527.

Given `8Kl(aq)+5H_(2)SO_(4)(aq)rarr4K_(2)SO_(4)(aq)+4I_(2)(g)+H_(2)S(g)+4H_(2)O(g)` 16 mol of KI reacts with 12 mol of `H_(2)SO_(4)`. The total volume of gases collected at 1atm and 546 K isA. `18 xx 22.4 " Litre"`B. `14 xx 22.4 " Litre"`C. `10 xx 22.4 " Litre"`D. `36 xx 22.4 " Litre"`

Answer» Correct Answer - D
`8KI(aq.)+5H_(2)SO_(4)(aq.)rarr4K_(2)SO_(4)(aq.)+4I_(2)(g)+H_(2)S(g)+4H_(2)O(g)`
`{:("Given 16 mol",12" mol",,4//8xx16,1//8xx16,),("Limiting reagent "16//8=2,12//5=2.4,,=8" mol",=2" mol",8"mol"),(" ""L.R","excess",,,,),("After reaction",12-5//8xx16,,,,),(["Remaining mol"],=2" mol",,,,):}`
Total gaseous moles in container = ` 8 + 2 + 8 = 18 "mol"`
`V=18xx2xx22.4l`
95528.

If the density of methanol is `0.793 kg L^(-1)` what ia its volume needed for making 2.5 L of its `0.25 M` solution?

Answer» Molar mass of methanol `(CH_(3)OH)`
`=32 g mol^(-1)=0.032 kg mol^(-1)`
Molarity of the given solution
`=(W_(2) "in" kg)/(Mw_(2)xxV_(sol)(L))=(d_(sol)(kgL^(-1)))/(Mw_(2)(kg))`
`=(0.793 kg L^(-1))/(0.032 kg mol^(-1))=24.78 M`
Applying `underset(("Given solution"))(M_(1)xxV_(1))=underset("prepared)")underset("(Solution to be")(M_(2)V_(2)`
`24.78xxV_(1)=0.25xx2.5 L`
or `V_(1)=0.02522 L=25.22 mL`
95529.

Which type of graph plot is used to analyze the effect of temperature on the rates of chemical reactions?(a) Dot plot(b) Normal probability plot(c) Arrhenius plot(d) Line weaver-Burk plot

Answer» Correct option is (c) Arrhenius plot

Explanation: An Arrhenius plot displays the logarithm of kinetic constants (ln (k), ordinate axis) plotted against inverse temperature (1/T, abscissa). The Arrhenius equation can be written as:

ln (k) = ln (A) – (Ea/R) (1/T)

Where :

k = Rate constant

A = Pre-exponential factor

Ea = Activation energy

R = Gas constant

T = Absolute temperature, K

In the right, which represents the y-coordinate axis.
95530.

What useful information can be found from a Van Deemter plot?(a) Optimum column length(b) Optimum column temperature(c) Optimum mobile phase flow rate(d) The selectivity factor

Answer» The correct answer is (a) Optimum column length

Explanation: The Van Deemter equation is an empirical formula describing the relationship between plate height (H, the length needed for one theoretical plate) which is a measure of column efficiency, and linear velocity (µ) . Smaller plate height values correspond to greater peak efficiencies, as more plates, or analyte partitioning, can occur over a fixed length of a column. The Van Deemter equation is governed by three cumulative terms: (A) eddy diffusion, (B) longitudinal diffusion, and (C) mass transfer. A loss in peak efficiency can be observed as a wider analyte band, and therefore, these three terms can also be viewed as factors that contribute to band broadening.
95531.

On which plot the Best fit-line is represented?(a) Histogram plot(b) Scatter plot(c) Probability plot(d) Dot plot

Answer» Correct option is (b) Scatter plot

For explanation I would say: A line of best fit (or “trend” line) is a straight line that best represents the data on a scatter plot. This line may pass through some of the points, none of the points, or all of the points.
95532.

The plasma half life of penicillin-G is longer in the new born because their:A. Plasma protein level is low B. Drug metabolizing enzymes are immature C. Glomerular filtration rate is low D. Tubular transport mechanisms are not well developed

Answer»

D. Tubular transport mechanisms are not well developed

95533.

You are given a cube of pure copper. You measure the sides of the cube to find the volume and weigh it to find its mass. When you calculate the density using your measurements, you get 8.78 grams/cm^3. Coppers accepted density is 8.96 g/cm^3. What is your percent error?(a) 1%(b) 0.02%(c) 0.01%(d) 2%

Answer» Correct option is (d) 2%

Easy explanation: Experimental value = 8.78 g/cm^3

Accepted value = 8.96 g/cm^3

Step 1: Subtract the accepted value from the experimental value.

8.78 g/cm^3 – 8.96 g/cm^3 = -0.18 g/cm^3

Step 2: Take the absolute value of step 1

|-0.18 g/cm^3| = 0.18 g/cm^3

Step 3: Divide that answer by the accepted value, 0.18g/cm^3 ÷ 8.96g/cm^3 = 0.02

Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.

0.02 x 100 = 2

The percent error of your density calculation was 2%.
95534.

Which of the following is a type B (unpredictable) adverse drug reaction: A. Side effect B. Toxic effect C. Idiosyncrasy D. Physical dependence

Answer»

C. Idiosyncrasy

95535.

Monitoring of blood levels of diuretic drugs is not practised because: A. No sensitive methods for measuring blood levels of diuretics are available B. It is easier to measure the effect of these drugs C. Response to diuretics is not related to their blood levels D. Diuretics need activation in the body

Answer»

B. It is easier to measure the effect of these drugs

95536.

What shape does fillet pieces have?(a) Convex(b) Concave(c) Convex and concave(d) Plane

Answer» Correct answer is (b) Concave

To elaborate: Fillets have different construction for the straight and the corners which are not split. They are made up of milled concave pieces stuck in their position.
95537.

Which device is used to measure the amount of energy stored in foods?(a) Rheometer(b) Adiabatic calorimeter(c) Bomb calorimeter(d) Heat flow calorimeter

Answer» Right option is (c) Bomb calorimeter

To explain: Complex organic food molecules such as sugars, fats, and proteins are rich sources of energy for cells because much of the energy used to form these molecules is literally stored within the chemical bonds that hold them together. Scientists can measure the amount of energy stored in foods using a device called a bomb calorimeter. With this technique, food is placed inside the calorimeter and heated until it burns. The excess heat released by the reaction is directly proportional to the amount of energy contained in the food.
95538.

The loading dose of a drug is governed by its: A. Renal clearance B. Plasma half life C. Volume of distribution D. Elimination rate constant

Answer»

C. Volume of distribution

95539.

The type II, type III and type IV hypersensitivity reactions can be suppressed by: A. Adrenaline B. Antihistaminics C. Corticosteroids D. Sod. cromoglycate

Answer»

C. Corticosteroids

95540.

What should the radius of fillet be to allow fillet sharp angles?(a) More than 15mm(b) Less than 10mm(c) Between 10mm and 15mm(d) More than 20mm

Answer» The correct answer is (b) Less than 10mm

Explanation: Radius of the fillet in order to allow filleting sharp angles, must be less than 10mm, in all classes of pattern. If the radius exceeds this value or goes below it, there would be defects in the cast.
95541.

The most appropriate route of administration for adrenaline in a case of anaphylactic shock is: A. Intracardiac B. Intravenous C. Intramuscular D. Subcutaneous

Answer»

C. Intramuscular

95542.

When the same dose of a drug is repeated at half life intervals, the steady-state (plateau) plasma drug concentration is reached after: A. 2–3 half lives B. 4–5 half lives C. 6–7 half lives D. 8–10 half lives

Answer»

B. 4–5 half lives

95543.

A drug which produces qualitatively different actions when administered through different routes is: A. Phenytoin sodium B. Hydralazine C. Magnesium sulfate D. Nitroglycerine

Answer»

C. Magnesium sulfate

95544.

Intradermal drug sensitivity tests can detect the presence of following type of hypersensitivity: A. Type I (anaphylactic) B. Type II (cytolytic) C. Type III (retarded) D. All of the above

Answer»

A. Type I (anaphylactic)

95545.

Refer to Q6, and calculate the power dissipated per unit mass of fluid.(a) 0.050 m^2 s^-3(b) 0.042 m^2 s^-3(c) 0.040 m^2 s^-3(d) 0.052 m^2 s^-3

Answer» Right choice is (d) 0.052 m^2 s^-3

Explanation: (lambda^4 = frac{v^3}{varepsilon})

(varepsilon = frac{v^3}{λ^4})

Therefore,

(varepsilon = frac{(1.29×10^{-6})^3 ,m^6 ,s^{-3}}{(8×10^{-5})^4 m^4}) = 0.052 m^2 s^-3.
95546.

Tolerance is generally not acquired to: A. Antisecretory action of atropine B. Sedative action of chlorpromazine C. Emetic action of levodopa D. Vasodilator action of nitrates

Answer»

A. Antisecretory action of atropine

95547.

An addicting drug which produces little or no physical dependence is: A. Diazepam B. Phenobarbitone C. Amphetamine D. Methadone

Answer»

C. Amphetamine

95548.

Adaptive neurophysiological changes produced by repeated administration of a drug, which result in the appearance of characteristic withdrawal syndrome on discontinuation of the drug is called: A. Drug addiction B. Drug abuse C. Psychological dependence D. Physical dependence

Answer»

D. Physical dependence

95549.

Marked redistribution is a feature of: A. Highly lipid soluble drugs B. Poorly lipid soluble drugs C. Depot preparations D. Highly plasma protein bound drugs

Answer»

A. Highly lipid soluble drugs

95550.

Rectangular wooden workpiece of a pattern set is not used for making?(a) Shields(b) Boards(c) Boxes(d) Drum type elements

Answer» Correct option is (d) Drum type elements

The explanation is: Drum type elements are made using circular wooden workpiece of a pattern set, while the remaining ones are made out of the rectangular wooden workpiece.